The magnitude of an applied torque depends on the following:
the distance between the point of force application and the axis of rotation of the object.the magnitude of the force.
The applied torque magnitude is an essential quantity to consider when considering rotational motion. Torque is defined as the action of a force on an object that creates a rotational motion around an axis of rotation.
Therefore, the magnitude of an applied torque depends on the distance between the point of force application and the axis of rotation of the object, and the magnitude of the force.
When it comes to torque, the perpendicular component of the force creates torque. The perpendicular distance from the axis of rotation to the force is the torque arm (r).
Therefore, we can write,
Torque = force x torque arm.
The magnitude of torque,
F × r
is proportional to the force applied and the perpendicular distance from the axis of rotation to the line of action of the force.
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a 63 kg k g person starts traveling from rest down a waterslide 4.0 m m above the ground. at the bottom of the waterslide, it then curves upwards by 1.0 m m above the ground such that the person is consequently launched into the air. ignoring friction, how fast is the person moving upon leaving the waterslide? express your answer with the appropriate units.
Person is moving at most at a speed of 11.8 m/s
We can use the principle of conservation of energy. In this scenario, the person starts at a height of 4.0 m and ends at a height of 5.0 m. Using the formula for gravitational potential energy, we can calculate that the initial potential energy is
[tex]63 kg * 9.81 m/s^2 * 4.0 m = 2474.04 J.[/tex]
At the top of the curve, all of this energy is converted into potential energy again, so the kinetic energy is zero.
[tex]63 kg * 9.81 m/s^2 * 5.0 m = 3085.05 J.[/tex]
Equating these energies, we get[tex]1/2 mv^2 = 3085.05 J[/tex],
where m is the mass of the person and v is the velocity. Solving for v, we get [tex]v = \sqrt{(2 * 3085.05 J / 63 kg)} = 11.8 m/s[/tex].
Therefore, the person is moving at a speed of 11.8 m/s upon leaving the waterslide.
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a 2.80 kg grinding wheel is in the form of a solid cylinder of radius 0.100 m .what constant torque will bring it from rest to an angular speed of 1200 rev/min in 2.5 s ?
A constant torque of 0.703 N·m will bring the grinding wheel from rest to an angular speed of 1200 rev/min in 2.5 s.
First, we need to convert the final angular speed to radians per second:
ω = (1200 rev/min) x (2π rad/rev) x (1/60 min/s) = 125.66 rad/s
The moment of inertia of the grinding wheel can be calculated using the formula for a solid cylinder:
I = (1/2)mr² = (1/2)(2.80 kg)(0.100 m)² = 0.014 J·s²
The angular acceleration can be found using the formula:
α = ω/t = (125.66 rad/s) / (2.5 s) = 50.264 rad/s²
The torque required to produce this angular acceleration can be found using the formula:
τ = Iα = (0.014 J·s²)(50.264 rad/s²) = 0.703 N·m
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a certain wire has resistance r. another wire, of the same material, has half the length and half the diameter of the first wire. the resistance of the second wire is:
The cross-sectional area of the second wire is 1/16th that of the first wire. The resistance of the second wire is four times that of the first wire.
The resistance of a wire is given by the formula:
R = ρ × L / A
where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
Since both wires are made of the same material, their resistivities are the same. Let's denote the length and diameter of the first wire by L1 and D1, respectively, and the length and diameter of the second wire by L2 and D2, respectively. We are given that:
L2 = L1 / 2
D2 = D1 / 2
The cross-sectional area of a wire is given by the formula:
A = π × (D/2)^2
Substituting the given values, we have:
A1 = π × (D1/2)^2
A2 = π × (D2/2)^2
= π × (D1/4)^2
= (1/16) × A1
Therefore, the cross-sectional area of the second wire is 1/16th that of the first wire.
Now we can use the formula for resistance to find the resistance of the second wire:
R2 = ρ × L2 / A2
= ρ × (L1/2) / (1/16 × A1)
= (ρ × L1 × 16) / (2 × A1)
Since the first wire has a resistance of R1, we can substitute its value:
R2 = (ρ × L1 × 16) / (2 × A1)
= (ρ × L1 × 16) / (2 × π × (D1/2)^2)
= 4 × R1
Therefore, the resistance of the second wire is four times that of the first wire.
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what factor, more than any other, do you think led to jupiter having so many moons compared to the inner terrestrial planets?
The main factor that led to Jupiter having so many moons compared to the inner terrestrial planets is its size and mass.
Jupiter is the largest planet in our solar system, and its strong gravitational force allows it to capture and hold onto many objects in its orbit. Jupiter's location in the outer solar system, beyond the asteroid belt, means that there are more objects available for it to capture compared to inner planets. This combination of size, mass, and location provides Jupiter with the ideal conditions to accumulate and retain a large number of moons. The gravitational force of Jupiter is strong enough to capture asteroids and comets that pass near its orbit, resulting in formation of many moons.
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Which is a property of every heterogeneous mixture?
a.the mixture is made up of at least two different states.
b.the mixture is made up of something dissolved in a liquid.
c.the composition of the mixture is the same throughout.
d.the characteristics of the mixture change within a sample.
hana fills a cup with sandy ocean water. she pours the mixture through a filter. what does she collect that passes through the filter?
a.a sample of pure water
b.a solution of salt in water
c.a suspension of sand in water
d.a colloid of salt in water
which describe colloids? check all that apply.
1.heterogeneous mixtures
2.homogeneous mixtures
3.may have a uniform appearance
4.are made up of at least two substances
5.will settle out over time
when mixed, which states of matter form only a homogeneous mixture?
a.two liquids
b.two gases
c.a solid and
Answer: C for all of them
Explanation:
Because I'm smart
Jk
So basically its beacuse all of them have the same mixture since science can be interrelated and interchangebale in terms of formulas ok bye now
Thanks
Hope this helped you
Or not
Sorry if it didn't ig
an undersea research chamber is spherical with an external diameter of 5.20 m. the mass of the chamber, when occupied, is 74,400 kg. it is anchored to the sea bottom by a cable. what is (a) the buoyant force on the chamber, and (b) the tension in the cable?
The buoyant force on the chamber will be 750,775N and tension in the cable will be -21,031N
(a) The buoyant force on the chamber is equal to the weight of the water that displaced by the chamber.
So if we have to find the volume of water displaced by the chamber, we need to find its volume first.
External diameter of the chamber ⇒ 5.20 m
Radius ⇒ 2.60 m.
Formula for the volume of a sphere is,
V = (4/3) × π × r³
Substituting,
V = (4/3) × π × (2.60 m)³ = 74.63 m³
Mass of the chamber ⇒ 74,400 kg
Weight, W = mg = 74,400 kg × 9.81 m/s² = 729,744 N
Density of seawater ⇒ 1025 kg/m³.
The mass of water displaced by the chamber,
[tex]m_{displaced}[/tex] = V × ρ = 74.63 m³ × 1025 kg/m³ = 76,469 kg
The weight of the displaced water is,
[tex]W_{displaced} = m_{displaced}*g = 76,469 * 9.81 m/s^2 = 750,775 N[/tex]
So we can say the buoyant force on the chamber is equal to the weight of the displaced water,
[tex]F_{buoyant}=W_{displaced}=750,775 N[/tex]
(b) The tension in the cable is equal to the weight of the chamber minus the buoyant force on the chamber. In other words, the tension makes the chamber from floating to the surface.
Tension = Weight of the chamber - Buoyant force
[tex]T=W-F_{buoyant}[/tex] [tex]= 729,744 N - 750,775 N = -21,031 N[/tex]
Tension in the cable is downward. That is the cable is under compression. That is why there is a negative sign here. Chamber is heavy enough to sink to the seafloor and negative value states that. The cable is under tension due to the weight of the chamber
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in what fundamental respect does electromagnetism break away from the form of materialism associated with the physics of newton and democritus? group of answer choices the electromagnetic force can be felt across a vacuum. newton had thought that the only force in the universe was gravity. the electromagnetic field is physically real, even though it is not made of atoms. nonsense--electromagnetism agrees quite well with newtonian materialism. electromagnetism implies that the future cannot be precisely determined.
Electromagnetism fundamentally breaks away from the materialism associated with the physics of Newton and Democritus in that the electromagnetic field is physically real, even though it is not made of atoms.
This distinction is significant because both Newtonian physics and Democritus atomism rely on the idea that matter, made up of atoms or other particles, is the primary building block of the universe. Newtonian physics, based on the concept of gravity as the only force in the universe, focuses on the interaction of massive objects and their motion.
Democritus, an ancient Greek philosopher, proposed that the universe was made up of indivisible particles called atoms, which form various materials through their combinations. On the other hand, electromagnetism introduces the concept of electric and magnetic fields, which are not made of material particles or atoms.
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30 In an electric circuit, a current of 5A is flowing. If the potential difference across two points of the wire is 220V, calculate the resistance. Calculate the total voltage in the given electric circuit. (A) (Ans: 4452, 24V) FOT
The total resistance across the circuit is 44 ohms
What is the resistance in the circuit?According to Ohm's Law, the resistance (R) of a wire is equal to the potential difference (V) across the wire divided by the current (I) flowing through it. Using this formula:
R = V/I = 220V / 5A = 44 ohms
So the resistance of the wire is 44 ohms.
To calculate the total voltage in the circuit, we need to know the voltage across all the components in the circuit. If there are no other components in the circuit, then the total voltage would simply be the voltage across the wire, which is 220V.
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in a drum-buffer-rope system, the lot size that moves from one work center to another for additional processing is a(n)
In a drum-buffer-rope system, the lot size that moves from one work center to another for additional processing is a "batch" size.
The drum-buffer-rope (DBR) system is a manufacturing scheduling method that aims to maximize throughput while minimizing inventory and operating expenses. In this system, the "drum" represents the bottleneck work center that determines the production rate for the entire system, and the "buffer" is a quantity of inventory strategically placed before the bottleneck to prevent downtime.
The "rope" refers to the mechanism used to synchronize production with demand, typically through a pull-based system that only allows material to be released to the next work center when the previous work center has completed its processing. This approach ensures that production is driven by actual demand and that inventory is minimized throughout the system, resulting in improved efficiency and profitability.
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--The complete question is, in a drum-buffer-rope system, the lot size that moves from one work center to another for additional processing is ______.--
naphthalene is diffusing from a spherical particle via forced convection into its surroundings. what is the first step in determining its mass flux?
In finding the mass flux of naphthalene after diffusing with a spherical particle, we need to calculate the mass transfer coefficient that can be measured to find out how much better the mass spreads to the surrounding.
The formula for mass transfer is
[tex]Kg/m^{2s} = ( Sh *D)/r[/tex]
Where,
Sh = Sherwood number, D = diffusion coefficient
After calculating the mass transfer using the given formula it is easy to calculate the mass flux using Fick's Law
Fick's Law can be used in forming a formula that can help in finding the mass flux. Therefore,
The formula for Fick's Law is
[tex]J = -Kg/m^{2s} * (C1 - C2)[/tex]
Where
J = mass flux
C1 = presence of naphthalene on the surface of the particle
C2 = presence of naphthalene in the bulk fluid
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g what are the dimensions (height and width) of the smallest plane mirror that you can buy so that you can still see all of yourself without having to move your head?
The smallest plane mirror that one can buy to see their entire reflection without moving their head would have a height of 3.4 meters and a width of 1.1 meters, assuming an average height of 1.7 meters
To see all of oneself in a plane mirror, the mirror must be tall enough to reflect the entire height of the person and wide enough to reflect the entire width. Let's assume an average height of 1.7 meters for a person.
The minimum height of the mirror should be twice the person's height so that the person can see their full reflection, including the head and feet. Therefore, the minimum height of the mirror would be 2 x 1.7 = 3.4 meters.
To determine the minimum width of the mirror, we need to consider the distance between the person and the mirror. Let's assume this distance to be about 1 meter. The minimum width of the mirror would then need to be twice the person's shoulder width plus the distance between the person and the mirror.
Assuming an average shoulder width of 50 cm, the minimum width of the mirror would be 2 x 50 cm + 1 m = 1.1 meters. An average shoulder width of 50 cm, and a distance of 1 meter between the person and the mirror.
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Which of the following best describes statistics?
1. a way to organize data
2. a way to analyze data
3. all are correct
4. a way to interpret data
The following best describes statistics : 2.) a way to analyze data.
What is statistics?Statistics can be described as a way to analyze data. It includes the collection, organization, analysis, interpretation and presentation of data. Statistics deals with gathering, presenting and also arranging of information to make any decision.
Study and manipulation of data, including ways to gather, review, analyze, and draw conclusions from data is called statistics and two major areas of statistics are descriptive and inferential statistics.
Statistics are important as they help people make informed decisions. Governments, organizations and businesses collect statistics that helps them to track the progress, measure performance and then analyze problems.
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a 80 kg man lying on a surface of negligible friction shoves a 53 g stone away from himself, giving it a speed of 4.6 m/s. what speed does the man acquire as a result?
When an 80 kg man moving at 120.75 m/s pushes a 53 g stone away from him while lying on a surface with little friction, the stone moves at a speed of 4.6 m/s.
Let the man acquire the speed v in the opposite direction.Let the momentum be conserved here.The momentum of the stone before the push is: p₁ = 0The momentum of the stone after the push is: p₂ = m × vWhere m is the mass of the stoneThe impulse is given as: J = p₂ - p₁Now, we know that the impulse (J) = Force (F) × time (t).
We also know that force is mass × acceleration. Therefore, the impulse can be written as: J = m × a × tUsing these equations we can solve for the acceleration (a).a = J/(m × t)Now, the acceleration is the same for the man and the stone, but the masses are different.
Therefore, the man acquires a speed v that is much smaller than the velocity of the stone. Substituting the given values we get,a = (m₂v₂ - m₁v₁)/(m₂t₂) = (0.053 × 4.6)/(80 × t) = 0.00109/t m/s². After equating the forces acting on both the stone and the man, we have;Fman = - Fstone.
This is because the man's speed is in the opposite direction to the stone.Let u be the initial speed of the man before he shoves the stone away from himself.
Using the momentum formula, m1u1 + m2u2 = m1v1 + m2v2.The mass of the stone is 0.053 kg while the man's mass is 80 kg.So,80u + 0.053 × 0 = 80v + 0.053 × 4.6v = (80u) / 0.053+4.6v = (80u) / 0.053v = 120.75u.
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suppose you moved two objects farther apart. how would this affect the force of gravity between those objects?
The moving objects farther apart will result in a weaker gravitational attraction between them.
When two objects are moved farther apart, the force of gravity between them decreases. This relationship is described by Newton's Law of Universal Gravitation,
which states that the gravitational force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Mathematically, this can be represented as F
= G * (m1 * m2) / r^2, where F is the gravitational force,
G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.
As the distance (r) increases, the denominator (r^2) becomes larger, causing the overall force of gravity (F) to decrease.
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the velocity vector of a particle moving in the xy-plane has components given by and . at time , the position of the particle is . what is the y-coordinate of the position vector at time ?
The y-coordinate of the position vector at time t is (5/2)t² - 8t - 1/2.
It is given the velocity vector components as:
v(t) = (4t - 6) i + (5t - 8) j
To find the position vector at time t, we need to integrate the velocity vector with respect to time. integrate each component separately:
x(t) = ∫ (4t - 6) dt = 2t² - 6t + C1
y(t) = ∫ (5t - 8) dt = (5/2)t² - 8t + C2
where C1 and C2 are constants of integration. We can determine these constants by using the initial position of the particle given as:
r(0) = (2, -1)
At time t=0, we have:
x(0) = 2, y(0) = -1
Substituting these values in the expressions for x(t) and y(t), may get:
C1 = 2, C2 = -1/2
So, the position vector at time t is:
r(t) = (2t² - 6t + 2) i + ((5/2)t² - 8t - 1/2) j
To find the y-coordinate of the position vector at time t, may simply need to substitute t into the expression for y(t):
y(t) = (5/2)t² - 8t - 1/2
Therefore, the y-coordinate of the position vector at time t would be (5/2)t² - 8t - 1/2.
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the amplitude of a 3.00-kg object in simple harmonic motion is 6.00 m. the maximum acceleration of the object is 5.00 m/s2. what is the period of simple harmonic motion?
The period of simple harmonic motion for this 3.00-kg object is approximately 6.87 seconds.
To find the period of simple harmonic motion for a 3.00-kg object with an amplitude of 6.00 m and a maximum acceleration of 5.00 m/s², we first need to find the angular frequency (ω).
We know the formula for the maximum acceleration in simple harmonic motion is given by:
amax = ω² * A
where amax is the maximum acceleration, A is the amplitude, and ω is the angular frequency.
Rearranging the formula to solve for ω, we get:
ω = sqrt(amax / A)
Plugging in the given values:
ω = sqrt(5.00 m/s² / 6.00 m)
ω ≈ 0.912 m^(-1/2) s^(-1)
Now that we have the angular frequency, we can find the period (T) using the relationship between angular frequency and period:
ω = 2π / T
Rearranging the formula to solve for T, we get:
T = 2π / ω
Plugging in the value of ω we found earlier:
T ≈ 2π / 0.912 m^(-1/2) s^(-1)
T ≈ 6.87 s
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a merry-go-round rotates at the rate of 0.30 rad/s with a(n) 80.0 kg man standing at a point 2.0 m from the axis of rotation. what is the new angular speed when the man walks to a point 1.0 m from the center? assume that the merry-go-round is a solid 6.50 x 102 kg cylinder with a radius of 2.00 m.
The new angular speed of the merry-go-round after the man walks to a point 1.0 m from the center is approximately 1.80 rad/s.
Let's denote the initial angular speed of the merry-go-round as ω₁, and the new angular speed after the man walks to a point 1.0 m from the center as ω₂.
Given:
Initial angular speed ω₁ = 0.30 rad/s
Mass of the man m = 80.0 kg
Initial distance of the man from the axis of rotation r₁ = 2.0 m
New distance of the man from the axis of rotation r₂ = 1.0 m
Mass of the merry-go-round (cylinder) M = 6.50 * 10² kg
Radius of the merry-go-round (cylinder) R = 2.00 m
The conservation of angular momentum can be applied in this scenario, where the initial angular momentum of the system is equal to the final angular momentum of the system.
The initial angular momentum of the system is given by:
Initial angular momentum L₁ = Moment of inertia of the man about the axis of rotation x initial angular speed of the merry-go-round
The moment of inertia of the man about the axis of rotation can be calculated using the formula for the moment of inertia of a point mass rotating about an axis at a distance r from the axis of rotation:
Moment of inertia of the man about the axis of rotation I₁ = m x r₁²
The final angular momentum of the system is given by:
Final angular momentum L₂ = Moment of inertia of the man about the new axis of rotation x new angular speed of the merry-go-round
The moment of inertia of the man about the new axis of rotation can be calculated using the same formula as above, but with the new distance r₂:
Moment of inertia of the man about the new axis of rotation I₂ = m x r₂²
Setting the initial and final angular momenta equal to each other, we can solve for the new angular speed ω₂:
L₁ = L₂
I₁ * ω₁ = I₁ * ω₂
Substituting the expressions for I₁, I₂, and the given values:
m * r₁² * ω₁ = m * r₂² * ω₂
Simplifying:
r₁² * ω₁ = r₂² * ω₂
Plugging in the given values for r₁, r₂, and ω₁, and solving for ω₂:
2.0² * 0.30 = 1.0² * ω₂
[tex]\omega_2 = \frac{(2.0^2*0.30)}{1.0^2}[/tex]
ω₂ ≈ 1.80 rad/s.
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flywheel in form of a solid cylinder of mass 60.00 kg and radius 1.80 m is rotated to an angular velocity 26.0 rad/s. what is the energy stored in the flywheel?
The energy stored in the flywheel is approximately 32,949.6 Joules.
The energy stored in the flywheel can be calculated using the formula for rotational kinetic energy: KE = 0.5 * I * ω², where KE is the kinetic energy, I is the moment of inertia, and ω is the angular velocity.
For a solid cylinder, the moment of inertia (I) is given by the formula: I = 0.5 * M * R², where M is the mass and R is the radius.
Substituting the given values: I = 0.5 * 60 kg * (1.8 m)² = 97.2 kg m².
Now, we can find the kinetic energy: KE = 0.5 * 97.2 kg m² * (26.0 rad/s)² ≈ 32949.6 J.
So, the energy stored in the flywheel is approximately 32,949.6 Joules.
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a fire hose exerts a force on the person holding it due to the water accelerating as it goes from the thicker hose out through the narrow nozzle. how much force is required to hold a 7.0-cm-diameter hose delivering through a 0.75-cm-diameter nozzle?
When the water goes from the thicker hose out through the narrow nozzle, a fire hose exerts a force on the person holding it. To hold a 7.0-cm-diameter hose delivering through a 0.75-cm-diameter nozzle, the force required is 34.8 N.
How much force is required to hold a 7.0-cm-diameter hose delivering through a 0.75-cm-diameter nozzle, As per Bernoulli's equation, the pressure P of a fluid (liquid or gas) at any point along its path is equal to the sum of its static pressure (p0),
the kinetic energy per unit volume of the fluid (0.5ρv2),
and its potential energy per unit volume (ρgh),
where ρ is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height relative to a reference point of the fluid point in question. 0.5ρv1^2 + P1 + ρgh1 = 0.5ρv2^2 + P2 + ρgh2
The Bernoulli principle can be simplified to: F1/A1 = F2/A2
Where: F1 and F2 are the forces exerted by the fluid on the hose A1 and A2 are the areas of the hose and nozzle, respectively.
Substituting the values:F1 = (F2A1)/A2 = (A2/A1)ρv2^2A1 = (7/2)2π = 38.48 cm2A2 = (0.75/2)2π = 0.44 cm2v1 = v2 (since the water is incompressible)ρ = 1000 kg/m3Thus:F2 = 0.5ρv2^2A2F1 = 0.5ρv2^2A2 (A1/A2) = (0.5 × 1000 × v2^2 × 0.44) × (38.48/0.44)F1 = 34.8 N
Therefore, the force required to hold a 7.0-cm-diameter hose delivering through a 0.75-cm-diameter nozzle is 34.8 N.
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open the charge-in-magnetic-field simulation and first run it with the default values. why is the trajectory of the positively charged particle curving down, to the bottom of the screen, when moving in the magnetic field?
In a magnetic field, a charged particle's trajectory is curving because of the effect of the magnetic field on the charged particle.
A magnetic field is a vector field that arises from electric currents and magnetized materials. The magnetic field is a vector field that has both magnitude and direction. A magnetic field exists in the vicinity of a magnetic material or a moving electric charge in the form of a flux of force-carrying particles known as virtual photons.
The magnetic field, like the electric field, is a fundamental entity of nature that is used in a variety of applications. In a magnetic field, charged particles follow a helical path that is nearly circular. The magnitude of the charged particle's velocity and the magnetic field's strength both influence the radius of the circle.
A charged particle's velocity vector and the magnetic field's direction are perpendicular to each other in the plane that is perpendicular to the magnetic field. The magnitude of the charged particle's velocity vector is constant throughout the motion because there is no force parallel to the velocity vector in the magnetic field.
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given an average particle diameter of 70mm for the bed of the geography river, what would be the critical tractive force necessary to dislodge that particle?
With the river bed. Assuming the contact area is proportional to the square of the particle's diameter:
F = τc × A
A ≈ D²
To calculate the critical tractive force necessary to dislodge a particle with an average Diameter of 70mm in a river bed, you can follow these steps:
1. Determine the particle's size (D) and convert it to meters: D = 70mm = 0.07m.
2. Calculate the submerged weight (Ws) of the particle. You'll need to know the specific gravity (G) of the particle material and the density of water (ρw). Assuming a typical specific gravity of 2.65 for sediment particles and water density of 1000 kg/m³:
Ws = (G - 1) × ρw × V × g
where V = (4/3)π(D/2)³ is the particle volume and g = 9.81 m/s² is the gravitational acceleration.
3. Calculate the critical shear stress (τc) using the Shields equation:
τc = ρw × g × R × (D/2)
where R is the submerged specific gravity, R = G - 1.
4. Determine the critical tractive force (F) by multiplying the critical shear stress by the particle's contact area (A) with the river bed. Assuming the contact area is proportional to the square of the particle's diameter:
F = τc × A
A ≈ D²
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The resistance produced by a current of 120 amps from a 6V battery is??
[tex]Answer[/tex]
To find the resistance produced by a current of 120 amps from a 6V battery, we can use Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) flowing through the resistor multiplied by the resistance (R) of the resistor:
V = IR
In this case, we know that the current is 120 amps and the voltage is 6V, so we can rearrange the equation to solve for the resistance:
R = V/I
Substituting the given values, we get:
R = 6V / 120A = 0.05 ohms
Therefore, the resistance produced by a current of 120 amps from a 6V battery is 0.05 ohms.
starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply.
Angular velocity depends upon the radius of the sphere and the height of the incline when a solid sphere rolls without slipping down an incline plane. The correct options are b and c.
A sphere is a three-dimensional shape that is circular and completely round, like a ball or globe. Solid spheres, also known as balls, are objects with a radius and a center point that are fully enclosed by a curved surface in three dimensions.
The angular velocity of a solid sphere rolling down an incline plane without sliding depends on the radius of the sphere and the height of the inclination.
The angular velocity is unaffected by the length of the slope or the mass of the sphere. This is due to the fact that the angular velocity is governed by the sphere's moment of inertia and rotational kinetic energy, both of which are dictated by the sphere's form (radius) and the height of the incline.
Therefore, options are b and c are correct.
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The probable question may be:
Starting from rest, a solid sphere rolls without slipping down an incline plane. at the bottom of the incline, what does the angular velocity of the sphere depend upon? check all that apply.
a. The angular velocity depends upon the length of the incline b. The angular velocity depends upon the radius of the sphere c. The angular velocity depends upon the height of the incline d. The angular velocity depends upon the mass of the sphere
a hollow spherical shell has mass 7.90 kg and radius 0.230 m . it is initially at rest and then rotates about a stationary axis that lies along a diameter with a constant acceleration of 0.895 rad/s2 . part a what is the kinetic energy of the shell after it has turned through 5.00 rev ?
The hollow spherical shell has a mass of 7.90 kg and a radius of 0.230 m. It initially rests and then rotates with a constant acceleration of 0.895 rad/s2 around a stationary axis that lies along a diameter. The kinetic energy of the hollow spherical shell is 2.12 J.
The first step is to calculate the angular displacement using the formulaθ = n × 2π = 5.00 rev × 2π/rev = 31.4 rad[The angular displacement here is a positive value, as the spherical shell is rotating in a counterclockwise direction]. The next step is to calculate the angular velocity after 5.00 rev, using the formula
ωf = ωi + αt, where ωi = 0 [initial angular velocity]α = 0.895 rad/s2 [angular acceleration n]t = 2.22 s [time taken to complete 5.00 revolutions]Therefore,ωf = 0 + 0.895 × 2.22 = 1.987 rad/s Kinetic energy of the shell, K = 1/2 I ω²where I is the moment of inertia of the shell.
The moment of inertia of a hollow spherical shell is given by
I = 2/3 M R² where M is the mass of the shell and R is the radius of the shellSubstituting values, K = 1/2 × 2/3 × 7.90 × (0.230)² × (1.987)²= 2.12 J [to 2 significant figures]
Therefore, the kinetic energy of the hollow spherical shell is 2.12 J after it has turned through 5.00 revolutions.
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how wide should a 20 m long conductor of square cross section be if it is to carry a current of 1.0 a with a uniform current density of 400 a/m2 ?
The width of the 20 m long conductor should be approximately 0.05 meters.
To determine the width of the conductor, we first need to find its cross-sectional area (A) using the given uniform current density (J) and current (I). The formula for this is:
A = I / J
Plugging in the given values:
A = 1.0 A / 400 A/m² = 0.0025 m²
Since the conductor has a square cross-section, its width (w) will be the square root of the cross-sectional area:
w = √A = √0.0025 m² ≈ 0.05 m
So, the width of the 20 m long conductor should be approximately 0.05 meters.
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which one of the following quantities remains constant for a given lc circuit? group of answer choices the energy dissipated in the circuit. the sum of the energy stored in the capacitor and that in the inductor. the energy stored in the inductor. the energy stored in the current flowing in the circuit. the energy stored in the capacitor.
For the given LC circuit (inductor-capacitor) , the sum of the energy stored in the capacitor and that in the inductor remains constant.
Energy transferred between the inductor and capacitor. So the total energy oscillating between the two components at a resonant frequency.
The energy stored in the capacitor and inductor individually varies over time as the energy oscillates between them.
When voltage changes the energy stored in the capacitor also changes. This is caused by the change in current flowing.
So we can say both the energy stored in the capacitor and the energy stored in the inductor remains constant in a given LC circuit.
The energy dissipated in the circuit can vary over time. Like that the energy stored in the current flowing in the circuit and the energy stored in the capacitor can also vary over time in an LC circuit.
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a ball traveling in a circle with a constant speed of 15 m/s has a centripetal acceleration of 20 m/s2. what is the radius of the circle?
The radius of the circle can be calculated using the formula; Centripetal acceleration = v^2/r, where v is the speed and r is the radius of the circle.
Substitute the given values; Centripetal acceleration = 20 m/s^2Speed = 15 m/s Using the formula above, we have;20 = (15)^2/rr = (15)^2/20r = 11.25mTherefore, the radius of the circle is 11.25 m.
The radius of the circle can be calculated using the formula for centripetal acceleration: a_c = v^2 / r, where a_c is the centripetal acceleration, v is the speed, and r is the radius. In this case, a_c = 20 m/s^2 and v = 15 m/s. Rearranging the formula to find r, we get:
r = v^2 / a_c = (15 m/s)^2 / (20 m/s^2) = 225 m^2 / 20 m/s^2 = 11.25 m
The radius of the circle is 11.25 meters.
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What is the approximate time difference between the first P-wave and the first S-wave recorded at a seismic station located 8000 kilometers from an earthquake’s epicenter?
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5 points
8 minutes 40 seconds
9 minutes 20 seconds
11 minutes 20 seconds
20 minutes 40 seconds
The approximate time difference between the first P-wave and the first S-wave recorded at a seismic station located 8000 kilometers from the earthquake’s epicenter would be 11 minutes 20 seconds.
Given the distance from earthquake’s epicenter (d) = 8000km
The approximate time difference between a P-wave and an S-wave can be calculated using the following formula:
From the diagram given we can see that the speed of P-wave (v1)= 8km/s
The speed of S-wave (v2) = 4.75km/s
We know that the time is calculated as distance per speed.
Then time taken for P-wave (t1) = d/v1
Time taken for S-wave (t2) = d/v2
Time Difference (t) = t1 - t2
Then, [tex]t = d/v1 - d/v2 = d((v2 - v1)/v1*v2)[/tex]
[tex]t = 8000 * (8 - 4.75/8 * 4.75)[/tex]
t = 680.4 seconds
So, for an earthquake epicenter located 8000 km away, the time difference would be:
Time Difference = 11 minutes 20 seconds
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A 3kg crab was moving at 1 m/s in the shore before the ride pushed him for 5 seconds. If his final speed was 3 m/s, what force did the tide push him with?
Answer:
[tex]1.2\; {\rm N}[/tex], assuming that all other forces on this crab were balanced.
Explanation:
The impulse [tex]J[/tex] on an object is equal to the change in momentum [tex]\Delta p[/tex]. In other words:
[tex]J = \Delta p[/tex].
If the mass [tex]m[/tex] of the object stays the same (as in the case of this question), the change in momentum can be rewritten as:
[tex]J = \Delta p = m\, \Delta v[/tex], where [tex]\Delta v[/tex] is the change in velocity.
Impulse is also equal to the net force on the object [tex]F_{\text{net}}[/tex] times the duration [tex]\Delta t[/tex] over which the force is applied:
[tex]J = F_{\text{net}}\, \Delta t[/tex].
Equate the two expressions for [tex]J[/tex] to obtain:
[tex]F_{\text{net}}\, \Delta t = m\, \Delta v[/tex].
In this question:
[tex]\Delta t = 5\; {\rm s}[/tex] is the duration over which the force was applied,[tex]m = 3\; {\rm kg}[/tex] is the mass of the crab, and[tex]\Delta v = (3 - 1)\; {\rm m\cdot s^{-1}} = 2\; {\rm m\cdot s^{-1}}[/tex] is the change in the velocity of the crab.Rearrange [tex]F_{\text{net}}\, \Delta t = m\, \Delta v[/tex] and solve for the net force [tex]F_{\text{net}}[/tex]:
[tex]\begin{aligned}F_{\text{net}} &= \frac{m\, \Delta v}{\Delta t} \\ &= \frac{(3\; {\rm kg})\, (2\; {\rm m\cdot s^{-1}})}{5\; {\rm s}} \\ &= 1.2\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 1.2\; {\rm N}\end{aligned}[/tex].
Assuming that all other forces on this crab are balanced, the net force on the crab would be equal to the force from the tide. Hence, the tide would have pushed the crab with a force of [tex]1.2\; {\rm N}[/tex].
a 180-lb (i.e.,5.59 slug) player can accelerate from rest to 15 ft/s in 2 second. if her center of mass accelerates only horizontally, what is the magnitude of the minimum static friction needed so she won't slip? (hint: find her acceleration first)
If her center of mass accelerates only horizontally, the magnitude of the minimum static friction needed so she won't slip is 52 lb.
To find the speed increase of the player, we can utilize the equation a = Δv/Δt, where Δv = 15 ft/s (last speed) and Δt = 2 s (time taken to arrive at that speed). In this way, a = 7.5 ft/s².
To work out the base static erosion expected to forestall slipping, we want to consider the powers following up on the player. The player's weight acts descending (W = mg = 5.59 slug x 32.2 ft/s² = 180 lb), and the power of static erosion acts on a level plane the other way to the course of movement. The greatest power of static grinding is equivalent to the coefficient of static contact (μs) increased by the ordinary power (N = W).
Since the player isn't slipping, the power of static erosion should be equivalent to or more noteworthy than the power expected to evenly speed up her. Accordingly, we can set the power of static contact equivalent to ma*ma (mass x speed increase), which gives:
μsN = ma*ma
μs(W) = ma*ma
μs(180 lb) = (5.59 slug)(7.5 ft/s²)
μs = 0.29
In this manner, the extent of the base static grating required so she won't slip is 0.29 times the heaviness of the player, or around 52 lb.
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