One of the scientists suggests that he can build a
cooling system for the theoretical photovoltaic cells
Experiment 2, which will keep the cells 1°C cooler
dan normal but decrease their efficiency by 1%. The
teoretical photovoltaic cells capturing which frequency
ranges
, if any, would benefit from this cooling system?

Explanation:

Given that,

Mass, m = 1.8 kg

Compression, x = 2.6 cm

We know that,

Force on spring = weight

So,

[tex]mg=kx[/tex]

Where

k is spring constant

[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{1.8\times 9.8}{2.6\times 10^{-2}}\\\\k=678.46\ N/m[/tex]

(2) If m = 5.2 kg

[tex]x=\dfrac{mg}{k}\\\\x=\dfrac{1.8\times 9.8}{678.46}\\\\x=2.6 \ cm[/tex]

Hence, this is the required solution.

Answer:

   [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           [tex]c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }[/tex]

Answer:

m = 95000 kg

Explanation:

Given that,

Net force acting on the house, F = 2850 N

Initial speed, u = 0

Final speed, v = 15 cm/s = 0.15 m/s

We need to find the mass of the house. Let the mass be m. We know that the net force is given by :

F = ma

Where

a is the acceleration of the house.

So,

[tex]F=m\dfrac{v-u}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2850\times 5}{(0.15-0)}\\\\m=95000\ kg[/tex]

So, the mass of the house is equal to 95000 kg.

(a) The length of the pendulum is 3.96 m.

(b) The amplitude is 7.89 m.

(c) The frequency is 0.25 Hz.

(d) The maximum velocity is 12.38 m/s.

(e) The total energy is 9.67 J.

(f) The maximum height is 3.94 m.

The length of the pendulum at the given parameters is determined using the following formula.

[tex]T = 2\pi \sqrt{\frac{l}{gcos(\theta)} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{gcos(\theta)} }\\\\\frac{T^2}{4\pi ^2 } =\frac{l}{gcos(\theta)}\\\\l = \frac{gcos(\theta)T^2}{4\pi^2} \\\\l = \frac{(9.8)cos(5)\times (4)^2}{4\pi^2} \\\\l = 3.96 \ m[/tex]

The amplitude of the pendulum is calculated as follows;

mgLcosθ = ¹/₂FA

mgLcosθ = ¹/₂(mg)A

Lcosθ = ¹/₂A

A = 2Lcosθ

A = 2 x 3.96 x cos(5)

A = 7.89 m

[tex]\omega = \sqrt{\frac{g}{l} } \\\\\omega = \sqrt{\frac{9.8}{3.96} } \\\\\omega = 1.57 \ rad/s[/tex]

ω = 2πf

f = ω/2π

f = (1.57) / (2π)

f = 0.25 Hz

The maximum velocity is calculated as follows;

v = Aω

v = 7.89 x 1.57

v = 12.38 m/s

E = mgLcosθ

E = 0.25 x 9.8 x 3.96 x cos(5)

E = 9.67 J

h = Lcosθ

h = 3.96 x cos(5)

h = 3.94 m

Learn more about length of pendulum here: https://brainly.com/question/8168512

[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]

We have ―

We have been asked to calculate the mass of the car, m.

[tex]\qquad\implies\boxed{\red{\sf{ P = mv}}}\\[/tex]

[tex] \quad \twoheadrightarrow\sf { 20000 = 25m} \\ [/tex]

[tex] \quad \twoheadrightarrow\sf { \cancel{\dfrac{20000}{25}} = m} \\ [/tex]

[tex]\quad\twoheadrightarrow\boxed{\red{\sf{ m = 800 \; kg}}}\\[/tex]

Therefore, mass of the car is 800 kg.

Answer: C. 20J

Explanation:  im pretty sure sorry if im wrong :(

Answer:

F = 64800 N

Explanation:

Given that,

Initial speed of a car, u = 70 km/h = 19.44 m/s

Finally it comes to a stop, v = 0

Time,t = 450 ms

The mass of the car is 1500 kg

We need to find the force exerted on the car. The force exerted on an object is given by :

F = ma

So,

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1500\times (19.44-0)}{450\times 10^{-3}}\\\\F=64800\ N[/tex]

So, the required force is equal to 64800 N.

Answer:

750 Hz

Explanation:

speed = freq * wl

 1500 =  f  * 2

    f = 750 Hz