options:

Reflection across the y-axis
Translation to the left
Reflection across the x-axis
90° counter clockwise Rotation

The volume of a sphere with radius [tex]r[/tex] is [tex]\frac{4}{3}\pi r^3[/tex]. If the radius is multiplied by a constant [tex]k[/tex], then the new volume is [tex]\frac{4}{3} \pi (kr)^3[/tex], which is equal to [tex]k^3 \cdot \frac{4}{3} \pi r^3[/tex]. This means that the volume of the sphere is multiplied by [tex]k^3[/tex].

a. If the radius is doubled, the volume is multiplied by 8

b. If the radius is tripled, the volume is multiplied by 27

c. if the radius is quadrupled, the volume is multiplied by 64

Answer:

I think it's 0.18 in decimal

Answer:

If you want the improper fraction 43/8

If you want it in a decimal 5.375

Step-by-step explanation:

Answer:

5 3/8 or 5.375

Step-by-step explanation:

Assuming that your "and" means addition, 5 and 3/8 is

5 3/8 or 5.375

Step-by-step explanation:

No problem,

The first steps we take is we will subtract 11 from the equation and subtract it from the total so it is easier for us.

Its one of the basic rules of Algebra.

2x + 11 = 25

2x + 11 - 11 = 25 -11 (We subtracted from both sides.)

2x = 14 (Now we are going to divide.)

2x / 2 = x

14 / 2 = 7

Now if we put this equation together we get x = 7.

Hope this helps.

Comment down if you have any questions

Answer:

14

Step-by-step explanation:

You can determine the common ratio by dividing each number in the sequence from the number preceding it.

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

Triangles must have equal corresponding sides and equal corresponding angles in order to be congruent.

According to the RHS congruence theorem, two right-angled triangles are congruent if their respective hypotenuses and sides are the same as those of another right-angled triangle.

Here we have

AOC and BOD are diameters of a circle and have a center O.

It is given that AOC and BOD are diameters of a circle.

From the triangles Δ AOC and ΔBOD

⇒ BD = CA  [ Diameters of the circle i.e Hypotenuse of triangles ]    

⇒ ∠BAD = ∠CDA [ Right angles in a semicircle is 90°]

⇒ AD = AD [ Common in both triangles i.e sides of triangles ]

Thus, Using RHS congruence criteria

⇒ ΔABD ≅ ΔDCA

Hence,

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

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Answer: h = 15 yards

Volume = 475.17 cubic yards

Diameter = 5.5*2 = 11.0 = 11 yards

HOPE THIS HELPS

There are 90 ways to arrange 6 beads of distinct colors in a 2*3 grid if reflections and rotations are considered the same.

In order to reach this result, we may use Burnside's Lemma, which states that the average number of arrangements of a symmetric object's symmetric parts, is taken throughout the set of all possible symmetry operations of the object.

You may fix one element and position the rest around it because of the rotation. You now have a total of 90 configurations available.

Thus, If reflections and rotations are treated equally, there are 90 ways to arrange 6 beads of different colors on a 2*3 grid.

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Answer:

4

[tex]4 \sqrt{2(2) + 8} = 4 \sqrt{4 + 8 } = 4 \sqrt{12} = 4(6) = 24[/tex]

If  sin (A + B) = 1

and tan (A - B) = 1/√3

value of:

We know that,

So,

A + B + A - B = 90 + 30

(A + A) + (B - B) = 120

2A = 120

A = 120/2

By putting value of A in 2

A - B = 30

60 - B = 30

-B = 30 - 60

-B = -30

tan 60 + tan 30

We know that

√3 + 1/√3

√3 × √3 + 1/√3

3 + 1/√3

[tex]4/√3[/tex]

sec A- cosec B

sec 60 - cosec 30

We know that

2 - 2 = [tex]0[/tex]

tan A+ tan B=4/√3

sec A- cosec B=0

Answer:

I believe its C xd, have a good day hun <3

Step-by-step explanation:

The correct pair of ratios which form proportion is,

⇒ 4/3.2, 22/17.6

Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.

Given that;

The ratios are;

A) 7/12, 21/24

B) 12/39, 8/36

C) 4/3.2, 22/17.6

Now,

For A;

⇒ 7 / 12 = 0.583

⇒ 21/24 = 0.875

Thus, It is not form a proportion.

For B;

⇒ 12/39 = 0.307

⇒ 8/36 = 0.222

Thus, It is not form a proportion.

For C;

⇒ 4/3.2 = 1.25

⇒ 22/17.6 = 1.25

Thus, It is form a proportion, because both the ratio are same.

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The required true statements for the given lines are 1 and 4.

An element or portion of a line with two endpoints is called a line segment. A line segment, in contrast to a line, has a known length. A line segment's length can be calculated using either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches.

Statement A: E and C are co-linear.

It is true, E and C are lie in same line

statement 2: Lines I and m intersect at point D.

It is false, I and m intersect at point E.

statement 3: AE and DC are line segments on line I

It is false,because AE and DC are line segments placed in different line.

statement 4: EA and EC are rays on the line m.​

It is true, as EA and EC are in same line m.

Thus, required true statements are 1 and 4.

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Answer:

1 and 4

Step-by-step explanation:

The graph indicates that the line segment's domain and range are [-5, 1] and [-4, 7, respectively.

The range of values a function may accept is referred to as its domain. These numbers represent the x-values of a function like f. (x). The range of values that a function may operate on is referred to as its domain. The value that the function returns following the insertion of the x value is this set. A function containing the independent variable x and the dependent variable y is said to be y = f(x). A value of x is said to be in the domain of a function f if it can be used to successfully create a single value y utilizing the value of x for that purpose.

The range refers to all potential values of y, while the domain refers to all conceivable values of x.

The graph indicates that the line segment's domain and range are [-5, 1] and [-4, 7, respectively.

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The approximate value of ㏒(b) to the nearest hundredth is 1.23.

The other method to write exponents in mathematics is using logarithms. A number's base-based logarithm is equal to some other number. A logarithm performs exponentiation's exact opposite function. 

In Logarithms, ㏒ₐ(b) = ㏒(b)/ ㏒(a)

Given that

The two expressions below have the same value when rounded to the nearest hundredth

=> ㏒₅ (b) = ㏒₉ (48)  

As we know  ㏒ₐ(b) = ㏒(b)/ ㏒(a)

=> ㏒₅ (b) = ㏒(b)/㏒(5)

=> ㏒(b)/㏒(5) = ㏒₉ (48)  

=> ㏒(b) = ㏒₉ (48) ㏒(5)

=> ㏒(b) =  (1.7618)(0.6989)  

=> ㏒(b) = 1.23132202  

=> ㏒(b) = 1.23  

Therefore,

The approximate value of ㏒(b) to the nearest hundredth is 1.23.

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Answer: The probability of a random student to have either ginger or blonde hair is 19/28.

Step-by-step explanation: Before anything is done, let's look and see what information the problem gives us and what we need to find out. We know that there's a 5/14 chance for a student to be ginger, and a 9/28 chance for them to be blonde. We need to find out the combined chance, as we want to know what the chances are for a student to have either hair color.

In order to do this, all we need to find is the sum of both fractions. Because the fractions have different denominators, we need to change one of them to match the other. 14 multiplied by 2 is equal to 28.

If we multiply both the numerator and denominator of 5/14 by 2, we get 10/28. Now, all we have to do is add that to 9/28. When we do that, we get 19/28.

19/28 cannot be simplified, so it is our final answer. Hope this helps!

The length of the rectangle's shorter side is 6cm and the of the rectangle's longer side is 12cm.

What is perimeter?

The total length of a shape's boundary, as used in geometry, is referred to as the shape's perimeter. Adding the lengths of all the sides and edges that surround a shape yields its perimeter. It is calculated using linear length units like centimeters, meters, inches, and feet.

Given:

A rectangle has a perimeter of 36 cm and an area of 72 cm^2.

Let the length of the rectangle's shorter side is 'a' and

the length of the rectangle's longer side 'b'.

As the perimeter is 36 cm.

⇒ Perimeter = 2(a + b)

               36 = 2(a + b)

                18 = a+ b

                 a = 18 - b

Now the area of rectangle is 72cm^2.

⇒                   Area = ab

                         72 = (18 - b)*b

                         72 = 18b - b^2

      b^2 - 18b + 72 = 0

b^2 - 12b - 6x + 72 = 0

b(b - 12) - 6(b - 12) = 0

         (b - 12)(b - 6) = 0

(b - 12) = 0,    (b - 6) = 0

b = 12,   b = 6

When  b = 12   ⇒  a = 18 - 12 = 6

When  b = 6   ⇒  a = 18 - 6 = 12

Hence, the length of the rectangle's shorter side is 6cm and the of the rectangle's longer side is 12cm.

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We would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.

The first equation is: 3x + 4y = 5

To eliminate the y variable when solving the system of equations by elimination, we need to multiply the first equation by -4. This is because when two equations are multiplied by the same number, any terms that have the same variable will be eliminated when the equations are added together.

Formula:

3x + 4y = 5

-4(3x + 4y = 5)

3x + 4y = 5

-12x - 16y = -20

Thus, we would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.

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Which of these is the algebraic expression for "5 times the sum of 2 and y?" (1 point)

A. 5 ⋅ 2 + y

B. 2 + 5 ⋅ y

C. 2(5 + y)

D. 5(2 + y) ✔

______________

Answer:

D 5(2+y)

Step-by-step explanation:

"5 times (so moltepli by 5) the sum (the answer of a addition equation) of 2 and y?".

hope this helps, pleas give Brainliest. :)

The required simplified solution of the given expression is 8√3.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

here,
Given expression,
=  2 √ 3 + 2 √ 27

Since √27 = 3√3
= 2√3 + 2× 3√3
= √3 [2 + 6]
= √3[8]
= 8√3

Thus, the required simplified solution of the given expression is 8√3.

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Given:

The quadratic function is:

[tex]f(x)=(x+2)^2+1[/tex]

To find:

The graph of the given quadratic function.

Solution:

The vertex form of a quadratic function is:

[tex]f(x)=a(x-h)^2+k[/tex]              ...(i)

Where, a is a constant and (h,k) is the vertex of the graph of the quadratic function.

We have,

[tex]f(x)=(x+2)^2+1[/tex]           ...(ii)

On comparing (i) and (ii), we get

[tex]a=1[/tex]

[tex]h=-2[/tex]

[tex]k=1[/tex]

Now,

[tex](h,k)=(-2,1)[/tex]

It means the vertex of the graph of the given function is at point (-2,1).

Only in graph C, the vertex of the parabola is at (-2,1).

Therefore, the correct option is C.

Answer:

2. k = -24

3. y = 50

4. m = -13

5. b = 8/7

6. x = -1/2

7. a = -4

8. k = 7.8

Step-by-step explanation:

2. -20 ÷ 5/6

3. 18 ÷ 0.36

4. -1/2 * 26

5. 6/7 + 2/7

6. 1/8 - 5/8

7. -2.3 - 1.7

8. 3.4 + 4.7

Those should be good. Good luck

Answer:  The resulting expression is 8+9y+4, which simplifies to 12+9y.

Step-by-step explanation: To combine like terms, we add the coefficients of the terms that are the same. In this expression, the like terms are 2y and 7y. Their coefficients are 2 and 7, respectively, so when we add them we get 2+7=9. The resulting expression is 8+9y+4, which simplifies to 12+9y.

I would choose both I and II for accomplishing the task of "When you want to Add or Remove Filters, you select Data in the ribbon, and then Filter. You would prefer to do this with one click, so you decide to add Filters to the Quick Access Toolbar."

Click the Commands Not in the Ribbon option in the Customize Quick Access Toolbar dialog box. Click Filter in the list of commands. Select the Add option. Press the OK button. You may use the FILTER function to filter a set of data depending on criteria you provide. The Filter option makes it simple to narrow down your search field.

Here,

I would choose both I and II to complete the task of "When you wish to Add or Remove Filters, go to the Data ribbon, then Filter. You'd prefer to do this with a single click, so you add Filters to the Quick Access Toolbar."

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Answer:

its 28

Step-by-step explanation:

Answer:

The top second one :))

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0

The average value of both f(x) and g(x) on 0≤x≤2 is 1/4. The average value of (f.g) on 0≤x≤2 is 0 and the statement avg(f) . avg(g) = avg(f . g) is false.

avg value of a function = 1/(b - a) ∫f(x) with limts a and b. Here a and b are the constraints under which the average has to be calculated.

a)

Hence average value of f(x) on 0≤x≤2

= 1/2 ∫f(x)  with 0 and 2 as intervals

Since integration is basically the area under the curve we get

avg of f(x) = 1/2[area under curve from 0 to 1 + Area under the curve from 1 to 2]

Since from 0 to 1, the figure is a triangle and beyond that a straight line we get

1/2[1/2 X 1 X 1 + 0]

= 1/4 sq units

b)

Similarly, the average value of g(x) on 0 ≤ x ≤ 2

1/2[area from 0 to 1 + area from 1 to 2]

= 1/2[0 + 1/2]

= 1/4 sq units

c) here we need to find the average of f(x) . g(x)

Here we see that f(x) is 0 from x = 1 to x = 1 while g(x) id 0 from x = 0 from x = 1

Hence we see that on multiplying the functions, the resultant has to be a 0 function.

Hence its average value will be 0.

d)

Average(f) . Average(g) = 1/4 X 1/4

= 1/16

Average of (f.g) = 0

Hence the statement is false

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Complete Question

The figure attached to the left is a graph of f(x), and below to the right is g(x).

The figure below to the left is a graph of f(x), a

(a) What is the average value of f(x) on 0≤x≤2? avg value = __________

(b) What is the average value of g(x) on 0≤x≤2? avg value = __________

(c) What is the average value of f(x) . g(x) on 0≤x≤2? avg value = _________

(d) Is the following statement true?

Average(f) . Average(g)=Average(f.g)

A. Yes

B. No