ou throw a rock from the upper edge of a 87.0 m vertical dam with a speed of 21.0 m/s at 58.0∘ above the horizon. Neglect any effects due to air resistance. How much time 1 after throwing the rock will it return to its initial height?

Answers

Answer 1

You throw a rock from the upper edge of a 75.0 -m vertical dam with a speed of 25.0 m/s at 65.0∘ above the horizon.

What is horizon?

The horizon is the line that, when seen from a position on or near the surface of a celestial body, appears to separate the surface from the sky of that body. All viewing directions are split according to whether it crosses the surface of the relevant body or not.

Since the true horizon is an imaginary line, it can only be seen with any degree of accuracy when it is situated along a generally flat surface, such as the oceans of the Earth. On Earth, the geography may also cause biological objects like trees and/or man-made objects like buildings to obstruct this line in some locations. The location where these obstructions overlap the sky is known as the visible horizon.

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Related Questions

Not sure if it’s right can someone make sure

Answers

Explanation:

stones a and b will hit the ground at the same time because they are of identical weight I think your right

One group of nursing home patients drinks orange juice before watching an
informative film. A similar group drinks water before watching the same film.
After the film, both groups are tested for their memory of the film's contents.
Here, the independent variable is:

Answers

The Independent variable here in this sentence is the type of drink each group was subjected to intake.

Independent variable in a experiment is the one which stands independent and acts as a control which influences the experiment's outcome. Independent variables are employed in a experiment to test whether the dependent variable changes accordingly.

Here, in this experiment the dependent variable, i.e., the theory to be tested is the memory of the patients. The independent variable here is the type of juice given to the patients, which acts as a control of the experiment's outcome. Any variable which alters the final result of the experiment and which can be controlled through out the experiment is termed as Independent variable.

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Two football players hit each other head on in a football game. One football
player had an acceleration of 4 m/s² and a mass of 150 kg. The second football
player had an acceleration of 2 m/s² and a mass of 200 kg. Calculate the force
each player had when they hit. What will be the net force of both players and who
knocked who back.

Answers

Answer:

200N in Player 1's direction

Player 2 is knocked back

Explanation:

Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.

Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]

Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]

They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]

Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.

Hope this helped!

World should shift its energy dependence from nonrenewable sources to renewable sources. Write your opinion​

Answers

Answer:

•Renewable energy, often referred to as clean energy, comes from natural sources or processes that are constantly replenished. For example, sunlight or wind keep shining and blowing, even if their availability depends on time and weather.

• Renewable sources of energy are better than nonrenewable sources because they refill themselves over a short period of time.

The pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C. The pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C.

Determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level.

________ times more frequently.

Answers

It takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.

What is Pressure ?

Pressure is force per unit area. Pressure in fluid is the product of fluid density, acceleration due to gravity and the height. Pressure is measured in  N/m²

Given that the pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C.

From Ideal gas law, PV = nRT

Where

P = 31000 N/m²

T = - 30 + 273 = 243 K

n/V =  ?

R = 8.314 1/K/Mol

n/V = P / RT

n/V = 31000 / (8.314 × 243)

n/V = 31000 / 2020.302

n/V = 15.34

When the pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C, then

T = 20 + 273 = 293 K

n/V = 100000 / (8.314 × 293)

n/V = 100000 / 2436.002

n/V = 41.05

To determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level, you divide the two values. That is,

41.05 / 15.34 = 2.67

Therefore, it takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.

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a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W

Answers

Answer:

W = 15 N

Explanation:

The moments from the center mus be equal for balance to occur

 center is at 25 cm  ( for a 1/2 meter stick)

moment one :   15 cm * 20 N

moment two :   20 cm * W         these must be equal

   15 * 20 = 20 * W        W = 15 N

A car was moving at 14 m/s. After 30 s, its speed increased to 20 m/s. What was the acceleration during this time?

Answers

Answer: 0.2 m/s²

Explanation:

Acceleration= (20-14)/30 = 0.2 m/s²

1. A 10kg ball moving at a speed of 6 m/s strikes another 5kg ball at rest with a contact time of 0.5 seconds. The 10kg comes to a complete stop. (a) What average force was exerted on the 10kg ball? (b) What average force was exerted on the 5kg ball? (c) What is the final momentum of the 5kg ball? (d) What is the initial momentum of the 10kg ball?

Answers

a)average force was exerted on the 10kg ball= -120 N

b)average force was exerted on the 5kg ball= 60N

c)What is the final momentum of the 5kg ball= 2.5 kg m/s

d) the initial momentum of the 10kg ball=60 kg m/s

The average force can be calculated by formula F=m(vf–vi)/ Δt so, 10 (0-6)/0.5 = -120 N the minus is representing opposite direction

the average force on the 5 kg ball = 5(6-0)/0.5= 60 N

The final momentum of 5 kg ball is 5 X 0.5 =2.5 kg m/s and initial momentum of 10 kg ball = 10 X 6 = 60 Kg m/s.

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At the snail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [fwd] for 140 s. Determine the winning snail’s displacement during this time interval.​

Answers

Answer: 1.2 mm

Explanation:

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement=  0.5* (2.4/140) *140 = 1.2 mm

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Temperature is a vector quantity because it can go down as well as up. True or false?

Answers

Answer:

Explanation:

temperature is a scalar quantity

A boat travels west at a speed of 20 m/s across a river that is flowing south at 9 m/s. What is the
resultant velocity of the boat?

Answers

Answer:

22m/s

Explanation:

This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula [tex]\sqrt{20^2+9^2\\[/tex] =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.

After 30s, a runner is sprinting at 3 m/s. But 10 s later, the runner is sprinting at 3.8 m/s. What is the runners acceleration during this time? Need to show step by step work please. Content is from physical science, 8th grade.

Need to show step by step - I need to check please

Answers

The acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

What is Average acceleration?

Average acceleration is defined as the average rate of change of velocity with time. Mathematically -

a = Δv/Δt

Given is a runner sprinting at 3 m/s and after 10 s the same runner is sprinting at 3.8 m/s. Therefore, we can write -

Initial velocity [u] = 3 m/s

Final velocity [v] = 3.8 m/s

time taken [Δt] = 10 s

The average acceleration of the sprinter can be calculated as follows -

a = Δv/Δt

Δv = v - u

Δv = 3.8 - 3 = 0.8 m/s

Δt = 10 s

Therefore -

a = 0.8/10 = 0.08 m/s².

Therefore, the acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

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When will you say a body is in Uniform acceleration and Non Uniform acceleration?

Answers

Answer:

(i) A body has a uniform acceleration if its velocity changes by equal amounts in equal intervals of time. The motion of a freely falling body is an example of uniform acceleraion.

(ii) A body has a non-uniform acceleration if its velocity changes by unequal intervals of time. The motion of a car on a crowded city road is an example of non-uniform acceleration.

A proton is moving in a circular orbit of radius 14 cm in a uniform magnetic field of
magnitude 0.35 T directed perpendicular to the velocity of the proton. Find the orbital speed
of the proton.

Answers

The orbital speed of the proton is 4.7 x 10⁶ m/s.

What is the orbital speed of the proton?

The orbital speed of the proton is calculated by applying the following equations as shown below.

Centripetal force of the proton = magnetic force of the proton

Fc = qVB

mv²/r = qvB

mv² = qvBr

v² = qvBr/m

v = qBr/m

where;

v is the speed of the protonB is the magnetic field strengthr is the radius of the circular pathm is mass of the proton

The orbital speed of the proton is calculated as follows;

v = (1.6 x 10⁻¹⁹ x 0.35 x 0.14) / (1.67 x 10⁻²⁷)

v = 4.7 x 10⁶ m/s

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A car travels at a speed of 55 km/h for 2.4 h. How far has the car traveled during this journey?

Answers

20.63km/h hope this helped

I went driving the other day and I covered 100 miles in the first 2 hours. Then I had a picnic for an hourThen continue driving to my friends house and traveled 50 miles in 2 hoursWhat was my average speed?

Answers

100 miles in 2 hours = 50mph

0 miles in 1 hour = 0mph

50 miles in 2 hours = 25mph

50 + 25 = 75/2 = 37.5mph

Question is down here
⬇️​

Answers

The property that the wire must have to be used in the game is high conductivity.

What is a wire?

A wire is a material that is used to carry electric current from one point to another. Thus, we know that when we connect wire to a source, there is a movement of electrons. We can thus see that the wire is able to conduct electricity.

Having said that, the game as shown in the image attached has to do with the formation of a circuit and the flow of electricity in that circuit that is formed.

We can see that the property that the wire must have to be used in the game is high conductivity.

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Expert help me

When firing a rifle, the bullet is shot at a high speed as the rifle recoils in the opposite directo How do you compare the force which they impart on each other? • How do you then explain the big difference in the velocities of two? Would you care to fire a rifle whose bullet is ten times as massive as the rifle? Why or why not?​

Answers

Answer:

See below

Explanation:

The forces are equal but opposite directions

the velocities of the two differ because of the different masses of the two objects....the bullet is light compared to the rifle/shooter.

I would not want to fire a heavy projectile...the 'kick' or 'recoil' of the rifle would be quite large.....and painful!

You drop a 20 Ton object and a
10 Ton object at the same time.
How does the acceleration
compare through the fall
assuming minimal air resistance.

Answers

Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

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Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.

Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.

In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.

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Two ropes are attached to a heavy object. The ropes are given to two strong physics students (is there any other kind?) with instructions for each to pull with 1000 N of force. Determine the resultant force if the two students pull: a) in the same direction east.

Answers

Resultant force is 2000N in east direction

What are the reasons Flat Earther's use to prove their claim?

Answers

Answer:

The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.

Explanation:

HELPPP

Is the density of an object always the same as its mass?


Yes


No

How would you calculate the density of an object?


mass/area


mass/volume

After completing the liquids portion of the lab, which liquid was the least dense?

oil


water


syrup
In a density column experiment (like the one explained in the lesson), the density of the liquids depends on the order in which they are added to the column.


True


False


Would a golf ball or a ping pong ball (of the same volume) have more density?

golf ball


ping pong ball

Answers

The correct responses are;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

What is density?

The term density refers to the mass per unit volume of an object. This implies that if measure the mass of the object and divide this value by the volume of the object then we obtain the density of the object. The density is an empirical property hence it does not change.

Let us now answer the questions individually;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

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A ball dropped from a window strikes the ground at 4.00 s later. How high is the window above the ground?

Answers

Answer:

15

Explanation:

Explain why sound connot travel in a vaccum

Answers

Sound cannot travel through a vacuum because there are no particles to carry the vibrations.

Explanation:

When travelling through air, the speed of sound is about 330 metres per second (m/s).

Which of the following best describes a position versus time graph foran accelerating object?

Answers

Answer: I don't really see the answer choices.

Explanation:

A rescue helicopter lifts a 50kg rock climber. If he accelerates at 5m/s what is the tension of the rope

Answers

The tension of the rope is 750 N.

According to Newton's second law of motion, the mass of a rock climber, m = 50 kg, while lifting a thing upwards with an acceleration, the upward force must be larger than the weight of the object in order to have a net force in upward direction to induce acceleration in upward direction.

accelerating a rock climber upward with a rope,

a= 5 m/s

determining the rope's tension (T)

The following two forces are at work on the rock climber as it is raised:

Rope tension acting upward. The rock climber's weight acting downward. Using Newton's second rule of motion, we may now:

Mass times climber's acceleration equals net upward force.

T−m×g=m×aT

=m×(g+a)T

=50× (10+5) T

=750 N

The complete question is -A rescue helicopter lifts a 50 kg rock climber by a rope from a cliff face. The rock climber is accelerated vertically a 5m/s−² What is the tension in the rope?

a) 350N

b) 500N

c) 750N

d) 1500 N

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What is the ratio of the nuclear densities of two nuclie having mass numbers in ratio 1:4

Answers

Answer:

[tex]1:1[/tex]

Explanation:

As the nuclear density is independent of mass number, so the ratio of nuclear densities of the two given nuclei is 1:1.

Given:-

Two nuclei have mass number in the ratio of 1:4.

To find:-

The ratio of nuclear densities of the two nuclei.

Answer:-

The nuclear densities for all atoms is same and it doesn't depends on mass number.

So the ratio of the nuclear densities will be 1:1 .

[tex]\implies \underline{\underline{\green{ \rm Ratio= 1:1}}}[/tex]

_________________________________________

Additional information:-

Here I would be providing you the proof for the same .

Firstly we know that the volume of nucleus is directly proportional to its mass number ( Why ? because as the mass number increases , nucleons increases so volume increases) . Therefore;

[tex]\implies V = \dfrac{4}{3}\pi r^3 \\[/tex]

And ,

[tex]\implies V \propto A \\[/tex]

So ,

[tex]\implies \dfrac{4}{3}\pi r^3 \propto A \\[/tex]

[tex]\implies r^3 \propto A \\[/tex]

[tex]\implies r\propto A^{\dfrac{1}{3}} \\[/tex]

[tex]\implies r = r_0 A^{\dfrac{1}{3}} \dots\rm{(1)} \\[/tex]

where,

[tex]r_0[/tex] is a constant and its value is 1.2 fm .[tex] A[/tex] = Mass number[tex] r[/tex] = radius of nucleus.

Now in order to find out the nuclear density , say [tex]\rho[/tex] ; we have ;

[tex]\implies \rho =\dfrac{Mass_{\rm nucleus}}{Volume_{\rm nucleus}} \\[/tex]

Now let's assume that there are m nucleons and their average mass number is A . So the average mass of m nucleons would be mA .

[tex]\implies \rho = \dfrac{mA}{ \dfrac{4}{3}\pi r^3}\\[/tex]

From equation (1) , we have ;

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi (r_0 A^{\dfrac{1}{3}})^3} \\[/tex]

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi r_0^3 A} \\[/tex]

[tex]\implies \underline{\underline{\green{\rho = \dfrac{3m}{4\pi r_0^3}}}} \\[/tex]

Now we can see that all the terms in the RHS of the equation are constants. This implies that nuclear density is also constant for all atoms independent of their mass numbers .

And we are done!

What is the condition for block b to move downwards
A) mb/ma > sin theta - mew cos theta

B) mb/ma > cos theta + mew sin theta

C) mb/ma > sin theta + mew cos theta

D) mb/ma > cos theta - mew sin theta

And what would the condition for the block to move upwards

A) mb/ma < sin theta - mew cos theta

B) mb/ma < cos theta + mew sin theta

C) mb/ma < sin theta + mew cos theta

D) mb/ma < cos theta - mew sin theta

Answers

Answer:

Solution in Photo

Explanation:

To solve this question, draw the Free Body Diagram (FBD) for the whole system such that

theta < 90, it will be more clearer that way.

A speedboat moves west at 108 km/h for 22.0 min. It then moves at 60.0° south of west at 90.0 km/h for 10.0 min.

What is the average speed for the trip?


What is the magnitude of average velocity for the trip?


What is the direction of average velocity for the trip? Enter the angle in degrees where negative indicates north of west and positive indicates south of west.

Answers

Answer:

108 km/hr = 1.8 km/min

90 km/hr = 1.5 km/min

V1 = (-39.6, 0)

V2 = (-10.6, -10.6)         (10.6^2 + 10.6^2)^1/2 = 15    1.5 km/min * 10 min

V = (-50.2, -10.6)       final displacement vector

Total time = 22 + 10 = 32 min

S = (50.2^2 + 10.6^2)^1/2 = 51.3 km

Average speed = (1.8 * 22 + 1.5 * 10) / 32 = 1.71 km / min

Displacement = 51.3 km

Average velocity = 51.3 / 32 = 1.60 km/min

Direction = 10.6 / 50.2 = .211 or 11.9 deg S of W

story problem questions for newtons 3rd law

Answers

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