Oxygen gas consists of individual oxygen atoms.
True or False

Answer:

hi, I haven't done this in a while, but I think this is it!

Explanation:

20

8 Iron Atoms

12 Oxygen Atoms

Answer: The volume of the solution formed will be 32.5 L. Explanation: Molarity is defined as the amount of solute present in 1 L of solution. The equation used to determine molarity of the solution follows: We are given: Molarity of the solution = 0.02 mol/L Mass of NaCl = 38 grams Molar mass of NaCl = 58.5 g/mol Putting values in above equation, we get: Hence, the volume of the solution formed will be 32.5 L.

The total volume of the solution will be 21.66 L

A solution is a uniformly dispersed mixture of more than one solute in a solvent. The type of substance under which a solute is dissolved to form a homogenous mixture is called a solvent. The substance that dissolves in a solvent to generate a homogenous mixture is referred to as a solute.

Calculation of volume of the solution with the aid of molarity is shown as:

Molarity = moles of solute / volume of solution in L.

Moles = mass / molar mass.

It is given that, molarity of NaCl = 0.0200 M

Mass of NaCl = 38 g

Molar mass of NaCl = 58.44 g/mol.

Moles of NaCl can be calculated as:

Moles of NaCl = mass of NaCl / molar mass of NaCl

= 38 g/ 58. 44 g/mol

= 0.650 mols.

Volume of NaCl solution can be calculated as:

Molarity = moles of solute / volume of solution in L.

0.0200 M = 0.650 moles/ Volume

Volume = 0.650 moles/ 0.0300 M

Volume = 21.66 L

Therefore, the volume of the solution will be 21.66 L.

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A measuring stick called meterstick or yardstick.

A meterstick or yardstick is either a foldable ruler or straightedge which is used to measure the length and it is specially common in the construction industry. Meterstick are made up of plastic or A measuring stick called meterstick or yardstick.  

A meterstick or yardstick is either a foldable ruler or straightedge which is used to measure the length and it is specially common in the construction industry. Meterstick are made up of plastic or wood and they often have a metal or plastic joints so that they can be folded together. Metersticks are often rectangular and thin. Metersticks are divided with lines for each millimeter and numerical markings per centimeter. Whereas, yardsticks are often marked with a scale in inches. Measuring stick is also known as ruler. For example: We measure the diameter of a circle with a ruler, and also draw a perfectly straight line using its edge.

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In quartz, silicon has a mass percent of 46.7% while oxygen has a mass percent of 53.3%.

Given the total mass of a sample of quartz (SiO2) (m1) = 5.05g

Mass of silicon (m2) = 2.36g

The percent composition of an element in a chemical compound is referred to as mass percent. Mass percent may be expressed as follows:

mass percent  = mass of element/mass of sample x 100

The percent mass of silicon (p1)  =  2.36/5.05 x100 = 46.7%

The substance was made of silicon and oxygen.

Thus, 100% Quartz =%Silicon +%Oxygen can be used to express the mass percentage of quartz.

100% Quartz = 46.7% + % Oxygen

% Oxygen = 53.3%

Hence the percentages of silicon and oxygen in quartz are 46.7% and 53.3%.

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0.167 is the molarity of the solution. Hence, option B is correct.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass of NaOH = 40

40 g of NaOH = 1 mole

5 g of NaOH = 0.125 moles

1000 ml = 1 L

750 ml = 0.75 L

Molarity = 0.125 ÷ 0.75 = 0.1666

Approximately = 0.167

Hence, option B is correct.

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If the molar mass of NaOH is 39.9969 g/mol, the molarity of a 750.0 mL solution containing 5.00 g of NaOH solution is 0.167. Hence Option (B) is correct

Molarity is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.

In chemistry, the most commonly used unit for molarity is the number of moles per liter, having the unit symbol mol/L or mol/dm³ in SI unit.

Given ;

       If, 40 g of NaOH = 1 mole

 Then, 5 g of NaOH = 0.125 moles

       If, 1000 ml = 1 L

  Then, 750 ml = 0.75 L

Molarity = 0.125 / 0.75

               = 0.1666

               = 0.167 Approximately

Therefore, If the molar mass of NaOH is 39.9969 g/mol, the molarity of the a 750.0 mL solution containing 5.00 g of NaOH solution is 0.167. Hence Option (B) is correct

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No, a mole doesn't equal a molecule. Despite the fact that the terms "moles" and "molecules" are separate, the idea of "moles" can be used to quantify the number of molecules in a sample.

The primary distinction between a mole and a molecule is that a mole is a unit of measurement for amount whereas a molecule is an atomized chemical species.

A mole of a substance is the same number of molecules of that substance as there are carbon-12 atoms in precisely 12 g of the element. This indicates that the molecular weight of any material, stated in terms of atomic mass units, is equivalent to 1 mole of that substance's weight in grams.

Thus, a mole is an amount of 6.02210²³ particles, whereas a molecule has several atoms of different elements that are chemically connected to one another.

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Answer:

Explanation:

A) bubbles show hydrogen gas escaping

B) the water reacted with sodium to form an alkaline solution

Answer: -162,120J

Explanation:

Okay, so q stands for work, given by the formula q = -P∆V,

For the first round, we have 2atm (for P) and a volume change of 3.2 (6.4-3.2) for the first experiment.

Find the work: q = -2 • (3.2 - 6.4) = 6.4L/atm

For the second experiment, it is now 2.5atm, with the change in volume going from 3.2 to 2.56.

So, work is q = -2.5(2.5 - 3.20) = 1.6L/atm

Add the total work: 1.6 + 6.4 = 8L/atm

To find the Joules per L/atm, recall that a mol of gas in K is 8.31447J, while the gas constant where a liter of gas per mol in K is 0.08206L/atmK. Divide these two values, which leaves us with 101,325J

So, for the first round, multiply 8 x 101,325, which leaves us with 810,600J.

Second round: The pressure is 2.5atm, with the volume change from 6.40 to 2.56

Solve for work: q = -2.5(2.56-6.4) = 9.6L/atm

Multiply with the Joule unit found earlier: 9.6 x 101,325 = 972,720J.

To find the difference, subtract the value of the single-step process (second round) from the first round (multistep)

810600 - 972720 = -162,120J. Therefore, it takes more heat to do the single step than the multistep process.

Answer:

i think is true..

Answer:

[tex]V_2=28.6L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to solve this problem via the Avogadro's gas law as a way to understand the volume-moles behavior as a directly proportional relationship:

[tex]\frac{V_2}{n_2}=\frac{V_1}{n_1}[/tex]

In such a way, we solve for the final volume as shown below:

[tex]V_2=\frac{V_1n_2}{n_1} \\\\V_2=\frac{40.0L*50.0mol}{70.0mol}\\\\V_2=28.6L[/tex]

Regards!

The peptides amino acids form peptide linkages between -COOH and -NH2 groups in protein.

What do you mean by peptides?

Peptides are short chains of amino acids that are linked together by peptide bonds. They are found in all living organisms and play important roles in many biological processes, such as cell signaling, hormone production, and metabolism. Peptides can range in size from two to hundreds of amino acids and can be made up of different combinations of amino acids.

Peptide bonds are formed when the carboxyl group (COOH) of one amino acid reacts with the amino group (NH2) of another amino acid. This creates a peptide bond, which is a covalent bond between the two amino acids. As proteins are made up of many amino acids, this process of forming peptide bonds is what links the amino acids together to form a protein.

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In scientific notation, the result of multiplying an integer between 1 and 10 by a power of 10 is written.For instance, 650,000,000 can be represented as 6.5 108 in scientific notation.

Always set the base to 10. The exponent must be an integer that is non-zero, therefore it can either be positive or negative. The absolute value of the coefficient must be less than ten and more than one.

a system of symbols for designating unique items. Example: In mathematics, the symbol "" stands for "infinity." There are many notations in mathematics.

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The triple point of a substance is the temperature and pressure at which all three phases of the substance (solid, liquid, and gas) can coexist in equilibrium.

Point B on the phase diagram is the triple point for Bogusium, represented by the intersection of three lines, which indicates that all three phases can coexist in equilibrium at this point.

1. A triple point of a substance is the temperature and pressure at which all three phases of the substance can coexist in equilibrium.

2. Point B on the phase diagram is the triple point for Bogusium, represented by the intersection of three lines.

3. This indicates that all three phases can coexist in equilibrium at this point.

4. Therefore, the correct statement is that Point B represents the triple point for Bo.

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Answer:

Pressure = 29.0 psi

Explanation:

Step 1: Given data

Required pressure in the tires (P): 200 kiloPascal

Step 2: Convert the required pressure in the tires to pounds per square inch (psi)

To convert kPa to psi, we need a conversion factor. In this case, we will use the conversion factor 1 psi = 6.89 kPa.

200 kPa × (1 psi/6.89 kPa) = 29.0 psi

200 kPa is equal to 29.0 psi.

The theoretical yield of a reaction is 5.00 moles of potassium permanganate . If the reaction actually produces 616.2 g KMnO₄ ,  the percent yield of the reaction is 78 %.

given that :

the theoretical yield of the reaction = 5 mol

mass of the potassium permanganate = 616.2 g

molar mass of the potassium permanganate = 158 g /mol

moles of the  KMnO₄ = mass / molar mass

                                   = 616.2 / 158

                                   = 3.9 moles

the percent yield = ( experimental yield / theoretical yield ) × 100 %

                              = ( 3.9 / 5 ) ×100 %

                              = 78 %

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Answer:2.5M

Explanation:

let the number of moles = x

x/0.025L =15

x= 15*0.025 = 0.375 moles

the concentration of the new solution = moles / volume =

0.375 / (0.025+0.125) = 2.5M

Answer:

hggggggggggggggggggggggggggggggggggggsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Explanation:

jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

Explanation:

The advantage of the universal indicator is that it displays a variety of colors over the whole pH scale. This makes it possible to determine an approximate pH of a solution over a range from 1-14. whereas, A commonly used acid-base indicator is litmus.

In a first-order breakdown reaction, 81.8% of the molecule takes 19.0 min to break down. A compound breaks down in 7.3 minutes by 33%. The human race started to scratch right away.

A means of climbing the food chain. People snatched what they needed from those who were unsuccessful in the same race without regard for anyone else (the producers and the rest of the consumers). First order in both surfactant and acid concentrations, decomposition is a dislocation process of reaction. The process is autocatalytic since acid is produced during the degradation. Reservoir rock, on the other hand, has a sizable absorbing impact.

x = (81.8*7.3)/33 x = 19.0 min

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Equation I cannot be divided by another factor as it will introduce errors in the equation.

Errors in chemical analysis result when there is a difference between observed value and the true value.If the magnitude of errors is large , it results in decrease in accuracy, reproducibility, and precision.

There are three types of errors:1) random error 2) systematic error 3) human error.The cause of random errors are difficult to quantify while the human errors can be minimized by taking a range of readings to reduce the error.

Errors while measuring boiling point may be human errors while noting down the boiling temperature or instrumental or systematic error if there is a fault in the thermometer.

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Answer:   Y  21.38 % , Al  32.44 % and O 46.16 %

Explanation: Molar mass of YAl5O12 is 88.91 + 5·26.98+12·16

= 415.81 g/mol

  m-% ( Y) = 88.91 / 415.81 = 21.38 % ,     m-% (Al) = 5·26.98 / 415.81 =

  32.44 %  , rest is Oxygen

i) No reactant will be left as all of them have been converted to product after completion of this reaction.

ii) Final percentage of each reactant remaining if each reaction went to completion is about 99.9%.

The difference between the moles (or molecules) of reactants consumed and the moles (or molecules) of products produced in a chemical reaction is known as the molar ratio.

i) Now given the molar ratio of CV : NaOH is 1:1 . That means Equal moles of CV and NaOH are present in the solution. That means all the CV and NaOH molecules will react to form equal number of products.

So in this case, no reactant will be left as all of them have been converted to product after completion of reaction.

ii) In this case, the given NaOH : CV = 1000 : 1. That means per 1000 moles of NaOH, we have only 1 mole of CV. Now since 1 mole of CV can react with only 1 mole of NaOH, then after the reaction of this 1 mole CV, there will be no CV left . And only 999 NaOH molecules will be left in the solution

So here % CV left = 0%

% of NaOH left = 999 / 1000 × 100

% of NaOH left = 99.9 %

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Complete question is attached below

One of the lab groups unintentionally left a beaker with 1.00 M1.00 M of NaOH solution out on the lab table over night. The molarity of the solution is 3.00 M after evaporation.

The total moles of solute contained in a given volume of solution is referred to as a solution's molarity. In this case, "M" stands for molarity, "n" is the number of moles of solute present in the solution, and "V" is the volume of solution present in a container. A unique kind of homogenous mixture made up of two or more components is known as a solution in chemistry. A solute, or substance that is dissolved in a solvent, is one of the components of such a mixture.

Moles = 1.00/1/3 Moles = 3.00 M

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The empirical formula of the compound is BF3.

The empirical formula of a compound is the simplest whole-number ratio of atoms that represents the compound's composition. To determine the empirical formula of a compound, we need to determine the number of moles of each element present and then simplify the ratio of moles to the smallest whole-number ratio.

First, we can use the percentages of boron and fluorine to find the number of grams of each element present in 100 grams of the compound:

15.94 g boron / 100 g compound

84.06 g fluorine / 100 g compound

Next, we can convert the number of grams of each element to moles using the molar masses of boron and fluorine:

15.94 g B / (10.81 g/mol) = 1.48 mol B

84.06 g F / (18.99 g/mol) = 4.44 mol F

To find the empirical formula, we divide the number of moles of each element by the lowest number of moles:

1.48 mol B / 1.48 mol B = 1.00

4.44 mol F / 1.48 mol B = 3.00

So the empirical formula of the compound is BF3.

It's important to note that this is the empirical formula, and the actual formula of the compound could be a multiple of this depending on the chemical structure of the compound.

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A gas law known as Gay-law Lussac's asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature

A gas law known as Gay-law Lussac's asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. In other words, while the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas.

In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-law Lussac's can be expressed mathematically as follows:

P ∝ T ; P/T = k

Where:

P is the pressure that the gas is applying.

T is the gas's actual temperature, while k is a fixed value.

The tire pressure of a car increases after driving. This is due to the air inside the tires heating up as a result of friction (a contact force) between the tires and the road. Gay-Law Lussac's states that because the air cannot expand because the tires are effectively fixed-volume containers, the pressure rises.

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The student is to weigh out 94.5g of glycerol in accordance with the provided statement.

Glycerin is a kind of carbohydrate known as a polyol, along with other sugar alcohols including sorbitol and erythritol. Glycerin has a complex taste, but unlike sugar I've already discussed—it is not absorbed by the body as sugar and does not raise blood sugar levels. Glycerol may be safe for short-term treatment when taken orally. Headaches, lightheadedness, bloat, nausea, and diarrhea are possible side effects. Glycerol appears to be safe when used topically. It might result in burning, itching, and redness.

1mL = 1cm³

Quantity = 75mL = 75cm³

1.26 g/cm³ is the density.

Mass = ?

Mass is equal to the product of volume and density.

Mass = 1.26 * 75 = 94.5g

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The complete question is-

A chemistry student needs 75.0 mL of glycerol for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of glycerol is 1.26 g.cm⁻³. Calculate the mass of glycerol the student should weigh out. Be sure your answer has the correct number of significant digits.

The elements with the highest ionization energy are the noble gases, which are located in the upper right corner of the periodic table. These elements include helium, neon, argon, krypton, xenon, and radon. These elements have a full valence electron shell, meaning that they have the maximum number of electrons possible in their outermost energy level. This makes them very stable and resistant to chemical reactions, as they do not have any electrons that can be easily removed or added.

As a result, they have very high ionization energy, meaning that a large amount of energy is required to remove an electron and form an ion. Due to these properties, these elements are not readily reactive with other elements and tend to exist as diatomic molecules or as individual atoms. These elements are used in a variety of industrial, medical, and everyday applications such as in lighting, refrigeration, and as inert gases in medical equipment and in the manufacturing of semiconductors.

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