Periodic motion
This question is about the stretching of springs
The diagram below shows an unblocked spring of length 100 mm
hanging suspended from a clamp. When an object of mass 50g is
hung on the spring, it becomes 180 mm long.
The spring constant K=50N/m
100 mm
50g
1- Calculate x in (mm) then convert it to meter
X is the distance that the spring is stretched from its
equilibrium position.
2- Use Hooke's law to calculate the restoring force of the spring
Hooke's law :
F=-K.X

Based on the image shown, the numbers that correspond to the term or phrase assuming that the electrons flow counterclockwise from 3 to 2 to 1, from 5 to 4 to 5, and to 3 are:

Electrochemical cells are cells that convert chemical energy to electrical energy.

The components of an electrochemical cell are:

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Answer:

Explanation:

b)  Fg = W = mg = (104 kg)(9.8 m/s²) = 1019.2 N  (weight of the box)

Ff = (coeff. friction)(N)

N = normal force = Fg = 1019.2 N

c)  coeff. friction = Ff/N = 45 N/1019.2 N = 0.044

d)  Fnet = 245 N - 45 N = 200 N

It's hard to draw a free body diagram with the available symbols, but here's a try at it.  Just add a box between the arrows!

                            W

                            ↓

     Ff  →                                 ←  Fapplied

                             ↑

                             N

Answer:

the answer is static electricity

Answer: 1477.14 should be right

Explanation:

trust

The time needed for 1.00 [tex]m^{3}[/tex] of water to flow through the pipe is 1,478.16 sec  .

The volume of a cylinder is the capacity of the cylinder which calculates the amount of material quantity it can hold.

Formula of volume of a cylinder:

V = πr²h

Here,

'r' is the radius of the base (circle) of the cylinder

'h' is the height of the cylinder

According to the question

Water enters a shower head through a pipe of radius 0.00712 m at 4.25 m/s.

As pipe is a cylinder  

Therefore

r = 0.00712 m

Speed = height filed by pipe in a second  =  4.25 m/s

Now,

Time it take for 1.00 m³ of water to flow through the pipe

Let time needed = t

By using volume of a cylinder

V = πr²h

1 m³  =   3.14 * (0.00712)² * 4.25 * t

1 m³  = 0.000676516768 *  t

t = 1,478.16 sec

Hence, The time needed for 1.00 [tex]m^{3}[/tex] of water to flow through the pipe is 1,478.16 sec  .

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Time required to film something in HD to collect 1 PB of data is all day for about 3.5 years.

A petabyte, or 2 to the 50th power of a byte, is a unit of measurement for memory or data storage. One exabyte is equal to about 1,024 petabytes (PB), or 1,024 terabytes (TB).

Although traditional network-attached storage (NAS) can handle petabytes of data and is expandable, it might be resource-intensive to traverse the system's ordered storage index.

A common laptop or desktop computer has 16 GB of random access memory for storage (RAM).

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When two objects collide in two dimensions (for example, x and y), the momentum will be conserved separately in each direction (as long as there isn't an external impulse in that direction).

The momentum before and after a direct impact between two pieces of clay is maintained. The amount of initial kinetic energy lost during the impact as a fraction is 0.961.

The total momentum of the two objects prior to the collision equals the total momentum of the two following the collision when object 1 and object 2 collide in an isolated system. The momentum obtained by object 2 equals the momentum lost by object 1, and vice versa.

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Answer:

204kW

Explanation:

P = t x ω = 500 x (2πx3900/60) = 204203W = 204kW

The power developed by the engine is equal to 204.1 KW.

Torque can be defined as the rotational equivalence of linear force while power is defined as the rate of doing work. The relation between torque and power scalar product of torque and angular velocity.

The relation between power and torque can be expressed mathematically as:

[tex]{\displaystyle {P = \tau \times \omega[/tex]

Where P is the power which is work done per unit of time, τ is the torque, and ω is the angular velocity.

Given, the torque that the engine develops, τ = 500 Nm

The angular velocity, ω =  3900 rev/min

ω =  3900 × 2×3.14/60

ω =  408.2 rad/s

The power developed by the engine can be calculated as:

P = 500 Nm ×  408.2 rad/s

P = 2041100 W

P = 204.1 KW

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Answer:

[tex]\text{Remember: Power is given by:}\frac{Work}{Time}\\\therefore \frac{600J}{10sec}=60\text{ Watts of Power-D}[/tex]

Answer:

Sound waves are not transverse wave

Answer:

Sound waves are longitudinal

The true statement is " this situation does not show a closed system" because the linear momentum is not conserved.

option A is the correct answer.

The principle of conservation of linear momentum states in a closed or isolated system, the total momentum of the system is always conserved.

Mathematically, the formula for the conservation of linear momentum is given as;

Pi = Pf

where;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The given momentum of the toy cars before and after collision;

                 Momentum Before                     Momentum After

Car 1                9 g m/s                                              -2 g m/s

Car 2              -6 gm/s                                               4 g m/s

Sum of the momentum before the collision = 9 gm/s - 6 g m/s = 3 g m/s

Sum of the momentum after the collision = -2 gm/s + 4 gm/s = 2 g m/s.

The above does not show conservation of linear momentum, hence the system is closed because of the momentum is lost.

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In the figure below, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

Periodic or oscillatory motion is defined as a motion that repeats itself. Due to a restoring force or torque, an object in such motion oscillates around an equilibrium position.

Energy is conserved in oscillation.

So, the maximum loss in Potential Energy = Maximum gain in Kinetic energy

5 J - 1 J = Maximum gain in Kinetic energy

Maximum gain in Kinetic energy = 4 J

[tex]0.5 \times m \times vmax^2 = 4\\0.5 \times 2.0 \times 10^-3\; Kg \times vmax^2 = 4 J\\vmax^2 = 4 \times 10^3 m^2/s^2\\vmax = 63.2 m/s[/tex]

Therefore, the maximum speed of a 2.0 g particle that oscillates between x = 2.0 mm and x = 8.0 mm is 63 m/s.

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Answer:

a unit of length effectively equal to the average, or mean, distance between Earth and the Sun

Explanation:

Answer: False

Explanation:

The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.

Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.

Answer:

B the force would be weaker

The full load primary current of a 230/115V, 2kVA transformer can be calculated using the formula:

I_primary = (2kVA * 1000 VA/kVA) / (230V)

I_primary = 8.7V

The full load secondary current of the transformer can be calculated using the formula:

I_secondary = (2kVA * 1000 VA/kVA) / (115V)

I_secondary = 17.4V

Therefore, the full-load primary current of the transformer is approximately 8.7V, and the full-load secondary current is approximately 17.4V. It is important to note that these values are based on the assumption that the transformer is operating at its full load capacity. If the transformer is operating at a lower load, the primary and secondary currents will be correspondingly lower.

The mass of the girl is 30 kg  in order for the seesaw to be in equilibrium.

A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.

As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.

Let the  mass of the girl = m kg

In equilibrium;

40 kg × 300 cm = m × 400 cm

⇒ m = 30 kg.

Hence,  the mass of the girl is 30 kg.

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Answer:

50 cubic cm

Explanation:

As the water displaces 50 cubic centimeters the amount of water that must leave the container for it to be able to be dropped into it is also 50 cubic as the water which was in its place must have gone somewhere.

Answer:

Explanation:

Given that gravity on the Moon has approximately 1/6th of the strength of gravity on Earth, a man who weighs 60kg on Earth would weigh approximately 10kg on the Moon. His mass, however, remains constant.

Answer:

ratio variables

Ratio scale of measurement

Weight, height and distance are all examples of ratio variables. Data in the ratio scale can be added, subtracted, divided and multiplied. Ratio scales also differ from interval scales in that the scale has a 'true zero'. The number zero means that the data has no value point

Neutrons and protons in an atom are acted upon by the strong force.

Strong force or strong nuclear force, a fundamental interaction of nature that acts between subatomic particles of matter. The strong force binds quarks together in clusters to make more-familiar subatomic particles such as protons and electrons.

Quarks are fundamental building blocks of matter. They are most commonly found inside protons and neutrons.

So being only option in which electrons are not present , option D is the correct answer.

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Answer:

normal force and gravitational force

Explanation:

I hope this helps :D

Answer:

the weight of the object decreases when it is taken from the Earth to the Moon

Explanation:

The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.

[tex]W =mg[/tex]

where,

W = weight of the object

m = mass of the object

g = acceleration due to gravity on the planet

The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.

The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.

Hence, the weight of the object decreases when it is taken from the Earth to the Moon

Answer:Un tren de engranajes es un sistema mecánico formado por el montaje de engranajes en un marco para que los dientes de los engranajes se acoplen.

Explanation:

La relación de los círculos de paso de los engranajes acoplados define la relación de velocidad y la ventaja mecánica del conjunto de engranajes. Un tren de engranajes planetarios proporciona una alta reducción de engranajes en un paquete compacto.

Answer:

uhh that is a hard question

Explanation:

cathcing or throwing

When you perform the skill of catching, you must track the object before receiving it. Therefore, option (C) is correct.

Manipulative skills can be described as those skills which require the ability to handle an object or piece of equipment with control. They involve skills such as striking, kicking, dribbling, or catching a ball.

Manipulative skills involve moving an object with the hands or feet to get a goal or fulfill a task. The objects might be used as equipment or toys such as balls, bats, racquets, or jump ropes. Manipulative skills are also called object-control skills.

Types of Manipulative Skills are Bouncing, Catching, Dribbling (moving a ball with the feet), Kicking or rolling, Lifting, Pushing and pulling (the object might be a wheeled toy), Striking (such as swinging a baseball bat), Throwing, and Volleying.

Therefore, we track the object before receiving during catching,

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The conditions that determine which process occurs in a cell are largely based on the environment and the needs of the cell.

A cell is the basic unit of life. It is the smallest unit of an organism that is capable of independent functioning. Cells are composed of a variety of molecules, including proteins, lipids, carbohydrates, and nucleic acids. Cells are able to carry out functions such as energy production, metabolism, growth and division, movement, and communication.

These conditions include the availability of nutrients, the presence or absence of specific signaling molecules, the amount of oxygen, and the temperature. In addition, the genetic makeup of the cell and its response to internal and external cues can also determine which processes occur.

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