Pk runs a restaurant two workers who prepare food for 50 heads every day.he received an order to prepare food for 200 heads. with the help of graph, explain how it will affect the demand for labour?​

Answers

Answer 1

Note that where the above ocndition exists, as the demand for labor increases due to the increased order, the demand curve shifts to the right, indicating that Pk will be willing to hire more workers at a higher wage rate to meet the new demand for food preparation.

What is the explanation for the above response?

Assuming that the two workers can prepare food for 50 heads per day, it means they can prepare food for 250 heads in five days (50 heads/day x 5 days = 250 heads).

However, with the new order of preparing food for 200 heads, Pk will need to increase the demand for labor to meet the new demand. One way to show this on a graph is by using a labor demand curve, which illustrates the relationship between the quantity of labor demanded and the wage rate.

As the demand for labor increases due to the increased order, the demand curve shifts to the right, indicating that Pk will be willing to hire more workers at a higher wage rate to meet the new demand for food preparation.

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Related Questions

For a thrust of 130,000 N and a thrust time of 100 S, what is the rockets mass that makes the rocket reach 220 KM

Answers

The rocket mass that would make a rocket with a thrust of 130,000 N reach 220 Km would be 2,954.55 kg.

How to find the rocket mass ?

To solve this problem, we need to apply the basic equations of motion. We will assume that the only force acting on the rocket is the thrust force, and we will ignore the effects of air resistance and gravity.

Calculate acceleration (a) using thrust (F) and mass (m):

Given the thrust F = 130,000 N, we have:

a = 130,000 / m

Apply the equation of motion:

Given y = 220,000 m (220 km), y0 = 0 m (initial position), v0 = 0 m/s (initial velocity), and t = 100 s, we can write the equation as:

220,000 = 0 + 0 * 100 + 0.5 * (130,000 / m) * (100)^2

Solve for mass (m):

220,000 = 0.5 * (130,000 / m) * 10,000

440,000 = 130,000 * 10,000 / m

m = 130,000 * 10,000 / 440,000

m = 2, 954.55 kg

In conclusion, the mass of the rocket that makes it reach 220 km with a thrust of 130,000 N and a thrust time of 100 s is approximately 2, 954.55 kg.

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Hello can Someone PLEASE HELP ME with this
Pascal’s Law
1. Are fluids only liquids, only gases, or both?
2. Hydraulics involve pushing/pulling ?
3. Pneumatics involve pushing/pulling ?
4. How can water make your car go up and down?
5. Does increased pressure in the pneumatic tube make the chair go up or down?
6. Holding down the pump lets air out, which decreases pressure, making the chair do what?
7. What happens when you push all the water from a little syringe into a big syringe? Does the big syringe pop out the same distance as the little syringe was pushed in? Why or why not?
8. Should the car move up as far as the thinner “small force” moves down? Why or why not? _
9. The pressure under piston 1 is ___________________ the pressure under piston ?

Answers

Answer:

1. Fluids can be both liquids and gases.

2. Hydraulics involve pushing.

3. Pneumatics involve pulling.

4. Water can be used in hydraulic systems to lift and lower a car using a hydraulic lift. The water is pumped into a hydraulic cylinder which then pushes a piston up to lift the car.

5. Increased pressure in the pneumatic tube makes the chair go up.

6. Holding down the pump lets air out, which decreases pressure, making the chair go down.

7. When you push all the water from a little syringe into a big syringe, the big syringe does not pop out the same distance as the little syringe was pushed in. This is because the pressure under the larger piston is less than the pressure under the smaller piston due to the difference in the size of the pistons.

8. Yes, the car should move up as far as the thinner "small force" moves down according to Pascal's Law, which states that pressure applied to a confined fluid is transmitted equally in all directions and acts with equal force on equal areas.

9. The pressure under piston 1 is equal to the pressure under piston 2 according to Pascal's Law.

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