Please help I beg of you

The volume of a sphere with radius [tex]r[/tex] is [tex]\frac{4}{3}\pi r^3[/tex]. If the radius is multiplied by a constant [tex]k[/tex], then the new volume is [tex]\frac{4}{3} \pi (kr)^3[/tex], which is equal to [tex]k^3 \cdot \frac{4}{3} \pi r^3[/tex]. This means that the volume of the sphere is multiplied by [tex]k^3[/tex].

a. If the radius is doubled, the volume is multiplied by 8

b. If the radius is tripled, the volume is multiplied by 27

c. if the radius is quadrupled, the volume is multiplied by 64

Answer:

2. k = -24

3. y = 50

4. m = -13

5. b = 8/7

6. x = -1/2

7. a = -4

8. k = 7.8

Step-by-step explanation:

2. -20 ÷ 5/6

3. 18 ÷ 0.36

4. -1/2 * 26

5. 6/7 + 2/7

6. 1/8 - 5/8

7. -2.3 - 1.7

8. 3.4 + 4.7

Those should be good. Good luck

I would choose both I and II for accomplishing the task of "When you want to Add or Remove Filters, you select Data in the ribbon, and then Filter. You would prefer to do this with one click, so you decide to add Filters to the Quick Access Toolbar."

Click the Commands Not in the Ribbon option in the Customize Quick Access Toolbar dialog box. Click Filter in the list of commands. Select the Add option. Press the OK button. You may use the FILTER function to filter a set of data depending on criteria you provide. The Filter option makes it simple to narrow down your search field.

Here,

I would choose both I and II to complete the task of "When you wish to Add or Remove Filters, go to the Data ribbon, then Filter. You'd prefer to do this with a single click, so you add Filters to the Quick Access Toolbar."

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If  sin (A + B) = 1

and tan (A - B) = 1/√3

value of:

We know that,

So,

A + B + A - B = 90 + 30

(A + A) + (B - B) = 120

2A = 120

A = 120/2

By putting value of A in 2

A - B = 30

60 - B = 30

-B = 30 - 60

-B = -30

tan 60 + tan 30

We know that

√3 + 1/√3

√3 × √3 + 1/√3

3 + 1/√3

[tex]4/√3[/tex]

sec A- cosec B

sec 60 - cosec 30

We know that

2 - 2 = [tex]0[/tex]

tan A+ tan B=4/√3

sec A- cosec B=0

Answer:  The resulting expression is 8+9y+4, which simplifies to 12+9y.

Step-by-step explanation: To combine like terms, we add the coefficients of the terms that are the same. In this expression, the like terms are 2y and 7y. Their coefficients are 2 and 7, respectively, so when we add them we get 2+7=9. The resulting expression is 8+9y+4, which simplifies to 12+9y.

The average value of both f(x) and g(x) on 0≤x≤2 is 1/4. The average value of (f.g) on 0≤x≤2 is 0 and the statement avg(f) . avg(g) = avg(f . g) is false.

avg value of a function = 1/(b - a) ∫f(x) with limts a and b. Here a and b are the constraints under which the average has to be calculated.

a)

Hence average value of f(x) on 0≤x≤2

= 1/2 ∫f(x)  with 0 and 2 as intervals

Since integration is basically the area under the curve we get

avg of f(x) = 1/2[area under curve from 0 to 1 + Area under the curve from 1 to 2]

Since from 0 to 1, the figure is a triangle and beyond that a straight line we get

1/2[1/2 X 1 X 1 + 0]

= 1/4 sq units

b)

Similarly, the average value of g(x) on 0 ≤ x ≤ 2

1/2[area from 0 to 1 + area from 1 to 2]

= 1/2[0 + 1/2]

= 1/4 sq units

c) here we need to find the average of f(x) . g(x)

Here we see that f(x) is 0 from x = 1 to x = 1 while g(x) id 0 from x = 0 from x = 1

Hence we see that on multiplying the functions, the resultant has to be a 0 function.

Hence its average value will be 0.

d)

Average(f) . Average(g) = 1/4 X 1/4

= 1/16

Average of (f.g) = 0

Hence the statement is false

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Complete Question

The figure attached to the left is a graph of f(x), and below to the right is g(x).

The figure below to the left is a graph of f(x), a

(a) What is the average value of f(x) on 0≤x≤2? avg value = __________

(b) What is the average value of g(x) on 0≤x≤2? avg value = __________

(c) What is the average value of f(x) . g(x) on 0≤x≤2? avg value = _________

(d) Is the following statement true?

Average(f) . Average(g)=Average(f.g)

A. Yes

B. No

The graph indicates that the line segment's domain and range are [-5, 1] and [-4, 7, respectively.

The range of values a function may accept is referred to as its domain. These numbers represent the x-values of a function like f. (x). The range of values that a function may operate on is referred to as its domain. The value that the function returns following the insertion of the x value is this set. A function containing the independent variable x and the dependent variable y is said to be y = f(x). A value of x is said to be in the domain of a function f if it can be used to successfully create a single value y utilizing the value of x for that purpose.

The range refers to all potential values of y, while the domain refers to all conceivable values of x.

The graph indicates that the line segment's domain and range are [-5, 1] and [-4, 7, respectively.

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Given:

Number of pink bows = 6

Number of blue bows = 1

Number of purple bows = 3

Nataly will randomly choose 1 bow from the box.

To find:

The probability that the Nataly will choose a pink bow.

Solution:

The total number of bows is:

[tex]6+1+3=10[/tex]

The  total number of bows is the total outcomes.

Total outcomes = 10

The number of pink bows is the favorable outcomes.

Favorable outcomes = 6

We know that, the probability that the Nataly will choose a pink bow is

[tex]\text{Probability}=\dfrac{\text{Number of pink bows}}{\text{Total number of bows}}[/tex]

[tex]\text{Probability}=\dfrac{6}{10}[/tex]

[tex]\text{Probability}=0.6[/tex]

Therefore, the probability that Nataly will choose a pink bow is 0.6.

There are 90 ways to arrange 6 beads of distinct colors in a 2*3 grid if reflections and rotations are considered the same.

In order to reach this result, we may use Burnside's Lemma, which states that the average number of arrangements of a symmetric object's symmetric parts, is taken throughout the set of all possible symmetry operations of the object.

You may fix one element and position the rest around it because of the rotation. You now have a total of 90 configurations available.

Thus, If reflections and rotations are treated equally, there are 90 ways to arrange 6 beads of different colors on a 2*3 grid.

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Answer:

its 28

Step-by-step explanation:

Answer:

The top second one :))

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0

The approximate value of ㏒(b) to the nearest hundredth is 1.23.

The other method to write exponents in mathematics is using logarithms. A number's base-based logarithm is equal to some other number. A logarithm performs exponentiation's exact opposite function. 

In Logarithms, ㏒ₐ(b) = ㏒(b)/ ㏒(a)

Given that

The two expressions below have the same value when rounded to the nearest hundredth

=> ㏒₅ (b) = ㏒₉ (48)  

As we know  ㏒ₐ(b) = ㏒(b)/ ㏒(a)

=> ㏒₅ (b) = ㏒(b)/㏒(5)

=> ㏒(b)/㏒(5) = ㏒₉ (48)  

=> ㏒(b) = ㏒₉ (48) ㏒(5)

=> ㏒(b) =  (1.7618)(0.6989)  

=> ㏒(b) = 1.23132202  

=> ㏒(b) = 1.23  

Therefore,

The approximate value of ㏒(b) to the nearest hundredth is 1.23.

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Answer: h = 15 yards

Volume = 475.17 cubic yards

Diameter = 5.5*2 = 11.0 = 11 yards

HOPE THIS HELPS

Answer:

If you want the improper fraction 43/8

If you want it in a decimal 5.375

Step-by-step explanation:

Answer:

5 3/8 or 5.375

Step-by-step explanation:

Assuming that your "and" means addition, 5 and 3/8 is

5 3/8 or 5.375

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

Triangles must have equal corresponding sides and equal corresponding angles in order to be congruent.

According to the RHS congruence theorem, two right-angled triangles are congruent if their respective hypotenuses and sides are the same as those of another right-angled triangle.

Here we have

AOC and BOD are diameters of a circle and have a center O.

It is given that AOC and BOD are diameters of a circle.

From the triangles Δ AOC and ΔBOD

⇒ BD = CA  [ Diameters of the circle i.e Hypotenuse of triangles ]    

⇒ ∠BAD = ∠CDA [ Right angles in a semicircle is 90°]

⇒ AD = AD [ Common in both triangles i.e sides of triangles ]

Thus, Using RHS congruence criteria

⇒ ΔABD ≅ ΔDCA

Hence,

It is proven that ΔABD ≅ ΔDCA by RHS congruency criteria.

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Answer:

41235

Step-by-step explanation:

There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,

The total number of times where each number will occur or be at first place is calculated as:

4! = 4 × 3 × 2 × 1

= 24

Hence,

24th number = The last number where 1 is at first place

We can write this out as:

12345

12354

12435

12453

12534

12543

13245

13254

13425

13452

13524

13542 e.t.c.

48th number = The last number where 2 is at first place

72nd place = The last number where 3 is at first place.

This means, the 73rd number is the first number where 4 is at first place.

Therefore, the 73rd number based on pattern is 41235

Answer:

I believe its C xd, have a good day hun <3

Step-by-step explanation:

The correct pair of ratios which form proportion is,

⇒ 4/3.2, 22/17.6

Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.

Given that;

The ratios are;

A) 7/12, 21/24

B) 12/39, 8/36

C) 4/3.2, 22/17.6

Now,

For A;

⇒ 7 / 12 = 0.583

⇒ 21/24 = 0.875

Thus, It is not form a proportion.

For B;

⇒ 12/39 = 0.307

⇒ 8/36 = 0.222

Thus, It is not form a proportion.

For C;

⇒ 4/3.2 = 1.25

⇒ 22/17.6 = 1.25

Thus, It is form a proportion, because both the ratio are same.

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The required simplified solution of the given expression is 8√3.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

here,
Given expression,
=  2 √ 3 + 2 √ 27

Since √27 = 3√3
= 2√3 + 2× 3√3
= √3 [2 + 6]
= √3[8]
= 8√3

Thus, the required simplified solution of the given expression is 8√3.

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Answer:

The first one

Step-by-step explanation:

The figure shown is a rectangular pyramid

The volume of a rectangular pyramid can be calculated using the formula

[tex]V=\frac{1}{3} lwh[/tex]

where l = length of base, w = width of base and h = height

We have a given length of 6 in, a given width of 4 in and a given height of 8 in

That being said, we plug in the given values into the formula

[tex]V=\frac{1}{3} (6)(4)(8)[/tex]

This equation matches A therefore A is the answer

Answer:

4

[tex]4 \sqrt{2(2) + 8} = 4 \sqrt{4 + 8 } = 4 \sqrt{12} = 4(6) = 24[/tex]

The required true statements for the given lines are 1 and 4.

An element or portion of a line with two endpoints is called a line segment. A line segment, in contrast to a line, has a known length. A line segment's length can be calculated using either metric measurements like millimeters or centimeters, or conventional measurements like feet or inches.

Statement A: E and C are co-linear.

It is true, E and C are lie in same line

statement 2: Lines I and m intersect at point D.

It is false, I and m intersect at point E.

statement 3: AE and DC are line segments on line I

It is false,because AE and DC are line segments placed in different line.

statement 4: EA and EC are rays on the line m.​

It is true, as EA and EC are in same line m.

Thus, required true statements are 1 and 4.

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Answer:

1 and 4

Step-by-step explanation:

Which of these is the algebraic expression for "5 times the sum of 2 and y?" (1 point)

A. 5 ⋅ 2 + y

B. 2 + 5 ⋅ y

C. 2(5 + y)

D. 5(2 + y) ✔

______________

Answer:

D 5(2+y)

Step-by-step explanation:

"5 times (so moltepli by 5) the sum (the answer of a addition equation) of 2 and y?".

hope this helps, pleas give Brainliest. :)

Given:

The quadratic function is:

[tex]f(x)=(x+2)^2+1[/tex]

To find:

The graph of the given quadratic function.

Solution:

The vertex form of a quadratic function is:

[tex]f(x)=a(x-h)^2+k[/tex]              ...(i)

Where, a is a constant and (h,k) is the vertex of the graph of the quadratic function.

We have,

[tex]f(x)=(x+2)^2+1[/tex]           ...(ii)

On comparing (i) and (ii), we get

[tex]a=1[/tex]

[tex]h=-2[/tex]

[tex]k=1[/tex]

Now,

[tex](h,k)=(-2,1)[/tex]

It means the vertex of the graph of the given function is at point (-2,1).

Only in graph C, the vertex of the parabola is at (-2,1).

Therefore, the correct option is C.

By using the area of circle formula, the solution of the given problem of circle comes out to be 6 + π cm

Every location in the plane of a circle is equally separated from the center and is a closed, as double object. Each line tracing the circle contributes to the formation of a line of reflection symmetry. Additionally, each angle has axis of symmetry around the center.

Here,

A 9 Pi square centimeter circle's sector has a 60 degree center angle. The sector's exterior border is

Circle area is equal to. πR² = 9π

Circumference =2πR

=> 2π*3 = 6π cm

Arc length equals (60/360)*6 to cm

Arc's perimeter is calculated as follows: Radius + Length of Arc + Radius = π +3 + 3 = 6 +  π cm

Therefore , the solution of the given problem of circle comes out to be

6 + π cm.

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By using the area of circle formula and circumference of a circle formula, the solution of the given problem of circle comes out to be 12π cm

Every location in the plane of a circle is equally separated from the center and is a closed, as double object. Each line tracing the circle contributes to the formation of a line of reflection symmetry. Additionally, each angle has axis of symmetry around the center.

Here,

sector area of circle = 9π

arc measure = 90°

Area of sector  = (arc/360°)*πr²

⇒ 9π = (90°/360°)πr²

⇒ 9π = (1/4)πr²

⇒ 4*9π = πr²

⇒ 36 = r²

⇒ 6² = r²

r = 6

and Circumference of circle = 2πr

=> 2π*6 = 12π cm

Therefore , the solution of the given problem of circle comes out to be

12π cm.

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We would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.

The first equation is: 3x + 4y = 5

To eliminate the y variable when solving the system of equations by elimination, we need to multiply the first equation by -4. This is because when two equations are multiplied by the same number, any terms that have the same variable will be eliminated when the equations are added together.

Formula:

3x + 4y = 5

-4(3x + 4y = 5)

3x + 4y = 5

-12x - 16y = -20

Thus, we would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.

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Answer:

14

Step-by-step explanation:

You can determine the common ratio by dividing each number in the sequence from the number preceding it.

Answer:

I think it's 0.18 in decimal