please help me figure out how many significant figures are in there

The Dilution of a buffer solution with a small amount of water will raise the PH of the solution. Dilution is the process of "reducing the concentration of a solute in a solution by simply adding more solvent to the solution, such as water." Dilution involves increasing the amount of solvent in a solution without increasing the amount of solute.

When a solvent is added, the concentration of the solute in the solution is diluted. By removing the solvent, concentration raises the solute concentration in the solution. Dilution is the process of lowering a given solute's concentration in its solution.

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N-Pentane has a higher boiling point than the other three elements

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n-Pentane and 2,2-Dimethylpropane are isomers of one another and have the same chemical formula. Only London dispersion forces (LDFs), the smallest intermolecular forces, exist between the two molecules. The connectedness of the carbon skeleton accounts for the variation in their boiling points. While 2,2-dimethylpropane is a branching hydrocarbon, n-pentane is a straight hydrocarbon. Because of the n-linear pentane's shape, which results in greater surface areas between molecules, there are more LDFs between the molecules. N-Pentane has a higher boiling point as a result.

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Complete Question

Rank the following compounds in terms by increasing boiling point, starting with the lowest boiling point first. I. 1-pentanol II. n-pentane III. 2,2-dimethylpropane IV. (R)-4-hydroxypentanoic acid.

Answer:

the number in front of the chemical

Explanation:

example: 4c is 4 carbon 4 os the coefficient of c

Answer:

D

Explanation:

this is because the number of protons is always equal to the number of electrons of an atom

Answer:

control variable

Explanation:

hope this helps :)

If copper (ii) chloride solution splashes on your skin while preparing the answer, you ought totell your teacher about the accident right away and use water to rinse the part of your skin that came in contact with the chemical.

 Copper Chloride (CuCl₂) is light brown solid which forms a blue green dihydrate solution on absorbing moisture.

From the above conclusion we can say that, If copper (ii) chloride solution splashes on your skin while preparing the solution, you should tell your teacher about the accident right away and use water to rinse the part of your skin that came in contact with the chemical.

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Answer: milliliter

Explanation: Generally, the unit used to measure liquid are liter (L) and milliliter (mL). But the volume of liquid in a can of Coca-Cola is commonly measured in mL. Therefore, the correct answer is option b.

Answer:MILLMETER

Explanation:

While Separating sand and salt by filtration and evaporation, the observation is during the filtration the sand gets accumulated in the filter paper while separating it from the salt solution, while in evaporation the salt gets accumulated.

When we tried to separate the individual components from the mixture of the salt and sand the first step is dissolving the mixture in water as the salt gets dissolved so it is easy for us to filter the sand from the solution, it is followed by the method of evaporation, in which the filtered salt solution is boiled until the water gets evaporated and we are left with the salt,  that's how salt and sand are separated from a mixture.

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Wavelength of (nm) of photon emitted is 438nm

Wavelength is the distance between identical points means adjacent crest in the adjacent cycles of a waveform signal propagated in space or along a wire

Here in the given data is photon emitted when electron drop at 7th orbital means n = 7 and n = 1 for hydrogen atom and redberg constant is also given = 1.097×10⁷m⁻¹

we have to find wavelength = ?

Expression of wavelength of radiation is

1/λ = R (1/n₁² - 1/n₂²)

1/λ = 109677×(1/7²- 1/1²)

1/λ =  109677×48/49

λ = 438.69cm = 43869m

λ = 438nm

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A system of two atoms, each having only 3 quantum states of energies 0, e and 2s. The system is in contact with a heat reservoir at temperature T.

The quantum state of a particle is defined by the values of its quantum numbers, so what this implies is that no two electrons within the same atom can have the identical set of quantum numbers.

In natural philosophy, a quantum state may be a mathematical entity that gives a probability distribution for the outcomes of every possible measurement on a system. Knowledge of the quantum state along with the foundations for the system's evolution in time exhausts all which will be predicted about the system's behavior.

For example, the spin of an isolated electron can tackle one amongst only two values; there aren't any other quantum states available for the electron and no intermediate values, since spin is quantized . As a physical parameter is varied, quantum fluctuations can drive a natural action into a special phase of matter.

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Assuming histidine residues as uncharged, the total charge of the Histone octamer at pH 7 is +146.

Histone H2A has a total of 26 positively charged residues (Arg + Lys) and 9 negatively charged residues (Asp + Glu).

The net charge is 26 – 9 = + 17

Histone H2B has a total of 28 positively charged residues (Arg + Lys) and 10 negatively charged residues (Asp + Glu).

The net charge is 28 – 10 = + 18

Histone H3 has a total of 31 positively charged residues (Arg + Lys) and 11 negatively charged residues (Asp + Glu).

The net charge is 31 – 11 = + 20

Histone H4 has a total of 25 positively charged residues (Arg + Lys) and 7 negatively charged residues (Asp + Glu).

The net charge is 25 – 7 = + 18

The histone octamer's overall charge is equal to 2 x (17 + 18 + 20 + 18) = +146.

The complete question is:

Based on the amino acid sequences of each histone, estimate the charge of a histone octamer at pH 7. Assume that histidine residues are uncharged at this pH.

Histone H2A

M S G R G K Q G G K A R A K A K T R S S R A G L Q F P V G R V H R L L R K G N Y S E R V G A G A P V Y L A A V L E Y L T A E I L E L A G N A A R D N K K T R I I P R H L Q L A I R N D E E L N K L L G R V T I A Q G G V L P N I Q A V L L P K K T E S H H K A K G K

Histone H2B

M P E P A K S A P A P K K G S K K A V T K A Q K K D G K K R K R S R K E S Y S V Y V Y K V L K Q V H P D T G I S S K A M G I M N S F V N D I F E R I A G E A S R L A H Y N K R S T I T S R E I Q T A V R L L L P G E L A K H A V S E G T K A V T K Y T S S K

Histone H3

M A R T K Q T A R K S T G G K A P R K Q L A T K A A R K S A P S T G G V K K P H R Y R P G T V A L R E I R R Y Q K S T E L L I R K L P F Q R L V R E I A Q D F K T D L R F Q S A A I G A L Q E A S E A Y L V G L F E D T N L C A I H A K R V T I M P K D I Q L A R R I R G E R A

Histone H4

M S G R G K G G K G L G K G G A K R H R K V L R D N I Q G I T K P A I R R L A R R G G V K R I S G L I Y E E T R G V L K V F L E N V I R D A V T Y T E H A K R K T V T A M D V V Y A L K R Q G R T L Y G F G G

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The relationship between the volume and the mass of the object is shown by option A.

Density gives the ratio of the mass to the volume of an object. We know that volume is an intrinsic property. This implies that it does not change with the amount of the substance. It can be used to identify a given substance because it does not change with the mass or the quantity of the substance present.

It is possible to see that the relationship between the volume and the mass of the object. This relationship is based on the density of the object that is under consideration. The first question that we would have to ask is if the volume changes with the mass of the object.

Given the fact that we have established that the ratio of the mass to the volume of a body is always a constant, we can conclude that the mass does not undergo any change with the volume of the object.

We can conclude that the relationship between the volume and the mass of the object is shown by option A.

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The earliest nebulae to form in the universe were made almost of Hydrogen and Helium.

The first atmosphere on Earth, 4.6 billion years ago, was most likely made up of Hydrogen and Helium. These are the two most prevalent gases in the universe. Several other gases were infused into the atmosphere as a result of outgassing or the upsurge of vapors from the Earth's core.

Planetary outgassing, comet collisions, and volcanic eruptions formed the Earth's first atmosphere. Helium and Hydrogen in the early Earth's crust were heated up and managed to escape the gravity of the Earth, only for the solar wind to blow them away.

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Answer:

Alpha radiation/ alpha decay

Answer:

P= [tex]\frac{M}{V}[/tex]

Explanation:

Answer:

1 Answer. fruity · Stefan V. The answer is 2.5 g/cm3 .

Explanation:

The liquid poured into the graduated cylinder has a specific weight, density, and specific gravity of 22,222.22 N/m3, 2,265.26 kg/m3, and 2.26526, respectively.

Given: weight = 10 N  and volume = 450 mL or 0.450 L

The specific weight of a substance is defined as its weight per unit volume or density of a substance multiplied to the acceleration of gravity. To obtain a specific weight with units of N/m3, we will be converting the volume from L to m3.

Specific weight = 10 N / 0.450 L = 22.22 N/L

Specific weight = (22.22 N/L) * (1000 L/ 1 m3) = 22,222.22 N/m3

The density can be determined by dividing specific weight by the acceleration of gravity.

Density = Specific Weight / gravity

Density = 22,222.22 N/m3 / 9.81 m/s2

Density = 2,265.26 kg/m3

Specific gravity is a dimensionless quantity of the ratio of the density of a substance to the density of water. The density of water that will be used is 1000 kg/m3.

Specific gravity = Density of substance / Density of water

Specific gravity = 2,265.26 kg/m3 / 1000 kg/m3

Specific gravity = 2.26526

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Answer:

ANSWER :: (DENSITY OF OIL IS --0.8/CM²) .

(DENSITY OF MERCURY IS --- 13.69/CM²) .

The atomic mass of Indium obtained is 60.544 g

For every 1g of Oxygen  4.784 g of Indium Oxide

Atomic mass of oxygen, O2 = 16.00 g

Now,

For Indium Oxide,

Mass of oxygen present = 3*16.00 = 48.00 g

Mass of Indium Oxide = 4.784 g * 48.00 g = 229.632 g

Let atomic mass of Indium

Mass of Indium Oxide = 2*M  + 3* 16.00 g

229.632 g = 2 * M + 48.00 g

2 M = 181.632 g

M = 181.632 g / 2

M = 90.816 g

For InO

Mass of oxygen present = 1* 16.00 g = 16.00 g

Mass of InO = 4.784 g * 16.00 g = 76.544 g

Let the atomic mass of Indium = M

Mass of InO = M * 1 g + 1*16.00 g

76.544 g = M + 16.00 g

M = 60.544 g

Hence the value obtained is 60.544 g

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Answer:

BaS

Explanation:

The chemical formula of Barium sulfide is BaS. It's molar mass is 169.39 g/mol.

The given chemical reaction between acetic acid and sodium hydroxide has sodium acetate and water as its products.

The balanced equation of a chemical reaction between acetic acid and sodium hydroxide is:

[tex]CH_3COOH (aq) + NaOH (aq) \rightarrow CH_3COONa (aq) + H_2O (l)[/tex]

This reaction is a neutralization reaction between a weak acid (acetic acid) and a strong base (sodium hydroxide).

In a neutralization reaction, an acid and a base mix chemically to provide salt and water as the final products. [tex]H^+[/tex] ions and [tex]OH^-[/tex] ions combine to generate water during a neutralization process. Because acid and base balance each other out to create a neutral chemical, this reaction is therefore known as a neutralization reaction.

In a balanced equation, the number of atoms of each element remains the same before and after the reaction. Therefore, in this reaction, on the products side, the number of atoms of Carbon (C) is 2, Hydrogen (H) is 5, Oxygen (O) is 3 and Sodium (Na) is 1.

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The concentration of a solution that has 3 moles of c6h12o6 dissolved in 9 liters of water is 0.33M

Concentration is defined as the ratio of number of moles of solute to the volume of the solution.

Concentration = number of moles of solute/ Volume of solution

It is defined as the ratio of given mass of substance to the molar mass of substance.

Given,

given mole of solution = 3 mol

Volume of the solution = 9L.

C = 3/9

C = 1/3

C = 0.33M

Thus, we calculated that the concentration of a solution that has 3 moles of c6h12o6 dissolved in 9 liters of water is 0.33M.

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Various criteria can be used to categorize chemical substances. One such approach is based on the distinct components present.

All other chemicals are categorized as inorganic, and organic compounds are defined as those possessing a carbon atom backbone. Organometallic compounds are organic molecules bound to metal atoms, as their name suggests.

The sorts of bonds that a compound has served as the basis for another classification system for chemical compounds. Ions are present in ionic compounds, which are held together by the attraction interactions between the ions with opposing charges. One of the most well-known ionic compounds is table salt or sodium chloride.

Reactivity, or more specifically, the kinds of chemical reactions that the compounds are most likely to experience, is the basis of a third classification system.

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The mass of dinitrogen tetroxide the number of Nitrogen atoms are 46 x 10^9 gram

Given:

number of nitrogen atoms = 1 x 10^12 atoms

To Find:

mass of dinitrogen tetroxide

Solution:

From the molecular formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

92 g of dinitrogen tetraoxide contains 2 atoms of nitrogen

x g of dinitrogen tetraoxide will contain 1 * 10^12 atoms of nitrogen

x = 92*1* 10^ 9/2

x = 46 x 10^9 gram

Hence, the number of Nitrogen atoms are

Hence, the number of Nitrogen atoms are 46 x 10^9 gram

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Answer:

The mass of dinitrogen tetroxide the quantity of Nitrogen particles are 46 x 10^9 gram

Number of nitrogen atoms = 1 x 10^12 atoms

Explanation:

From the atomic Formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

92 g of dinitrogen tetraoxide contains 2 molecules of nitrogen

x g of dinitrogen tetraoxide will contain 1 * 10^12 molecules of nitrogen

x = 92*1* 10^ 9/2

x = 46 x 10^9 gram

the quantity of Nitrogen molecules are 46 x 10^9 gram

A histogram is a chart that shows the spread of data, which allows us to see outliers and the best number that fits with the data (Option D).

A histogram is a diagram used to show the relationships between two different variables, which is represented by rectangles that indicate a specified amount of a given parameter in the representation.

In conclusion, a histogram is a chart that shows the spread of data, which allows us to see outliers and the best number that fits with the data (Option D).

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The answer of the calculations above in scientific notation are a=8.3 ×10³, b= 3.9 × 10^¹um, c= 1.4 × 10³gmol, d= 5.6× 10²km

In calculation of various expressions, the results can be expressed in a scientific notation which is a way to compress cumbersome figures.

4.2 × 104 = 436.8

7.9 × 10³ = 7900

436.8 + 7900 = 8,336.8

The scientific notation= 8.3 ×10³kg

5.23 x 106 um = 554.38um

554.38 × 7.1 = 3,936.1

3,936.1 × 10^-²

3.9 × 10³ × 10^-²= 3.9 × 10^¹um

The scientific notation= 3.9 × 10^¹um

5.44 x 107 g = 582.08g

8.1 x 104 mol = 842.4 mol

582.08g+ 842.4 mol = 1,424.48

The scientific notation = 1.4 × 10³gmol

8.40 x 105 km = 882km

3.1 × 105 = 325.5km

882km - 325.5km = 556.5

The scientific notation = 5.6× 10²km

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The initial weight of mercury oxide in the sample was 59.1 g HgO.

chemical reaction

2HgO ⟶ 2Hg + O₂

the moles of O₂

pV = nRT

n = (pV)/(RT)

Data:

p = 0.970 atm

V = 4.50 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 390.0 K

Calculation:

n = (0.970 × 4.500)/(0.082 06 × 390.0)

n = 0.1364 mol O₂

the moles of HgO

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

the mass of HgO

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = 59.1 g HgO

For the creation of various organic mercury compounds and specific inorganic mercury salts, mercury(II) oxide, or HgO, serves as a source of elemental mercury.

This red or yellow crystalline substance is also utilised in mercury batteries and zinc-mercuric oxide electric cells as an electrode (combined with graphite).

Mercuric oxide is a colourless, crystalline powder that ranges from yellow to orange-yellow.

It serves as a seed protectant, a pigment, a preservative, and an ingredient in alkaline batteries and cosmetics.

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Answer:

When an acid reacts with a base, they undergo neutralization and their opposite pH levels cancel each other out. This happens through the double displacement of ions or, put simply, the ions switch partners.

Explanation:

When an acid and a base are placed together, they react to neutralize the acid and base properties, producing a salt. The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt.

An example of neutralization reaction is: HCL + NaOH ⇆ NaCl +

acid + base ⟶ water + salt.

HCl(aq) + KOH(aq) ⟶ H 2O(ℓ) + KCl(aq)

2 HCl(aq) + Mg(OH) 2(aq) ⟶ 2 H 2O(ℓ) + MgCl 2(aq)

HCl(aq) + NH3(aq) ⟶ NH4Cl(aq)

Answer:

neutralize one another and produce salts

Explanation:

When mixed, acids and bases neutralize one another and produce salts, substances with a salty taste and none of the characteristic properties of either acids or bases.

An element is any naturally occurring substance found on Earth that is normally identified by the atomic number (option D).

An element is the simplest chemical substances that cannot be decomposed in a chemical reaction or by any chemical means and made up of atoms all having the same number of protons.

Chemical elements are arranged in accordance with their atomic numbers on the periodic table.

Each element has its own unique symbol but are usually identified by its atomic number. All elements possess its own atomic number.

Therefore, an element is any naturally occurring substance found on Earth that is normally identified by the atomic number.

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Uranium is the element which could not form in the sun and would have to be formed in a supernova

With an atomic number of 92, uranium is a metallic chemical element in the periodic table that is silvery-white. The chemical symbol for it is U. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons. The atomic weight of uranium is the greatest among all naturally occurring elements.

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