Please help witht 4 and 5

The increasing pH of an ocean is not enough to restore the equilibrium as seawater becomes more acidic, and the pH of the water drops. This process binds carbonate ions, reducing their abundance.

Equilibrium is a state where the presence of base and acid is in equal quantity.

Increased pH, leads to more acidity and reduces the number of ions.

Ions are necessary for corals, oysters, mussels, and many other shelled organisms that require building their shells and skeletons.

Thus, increasing pH of an ocean is not enough to restore the equilibrium as seawater becomes more acidic, and the pH of the water drops. This process binds carbonate ions, reducing their abundance.

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Answer:

2 mol/L

Explanation:

Molarity is Moles/Liters, you just simple divide 5 moles ÷ 2.5 L =2 mol/L

Answer:

1. In electron dot structure, the dot represent one electrons.

2. Ionic compounds are highly soluble in water.

3. The bond formed by the mutual sharing of two electrons is called covalent bond.

4. there are 3 bonds in nitrogen molecule.

5. the ionic bonds are non-directional.

6. NaCl is taken in molten state

7. formula of common salt is NaCl.

8. Oxygen gas is a diamotic molecule.​

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Answer:

About 27 mL of water.

Explanation:

We can use the heat transfer equation. Recall that:

[tex]\displaystyle q = mC\Delta T[/tex]

Heat is transferred from the water with higher temperature to the water with lower temperature. Hence:

[tex]\displaystyle -q_1 = q_2[/tex]

Substituting yields:

[tex]-m_1C \Delta T_1 = m_2C\Delta T _2[/tex]

We can solve for m₁:

[tex]\displaystyle \begin{aligned} m_1 &= -\frac{m_2 C\Delta T_2}{ C \Delta T_1} \\ \\ & = -\frac{m_2\Delta T_2}{\Delta T _1}\end{aligned}[/tex]

The desired final temperature of water is 36.2 °C. Substitute and evaluate:
[tex]\displaystyle \begin{aligned} m_1 & = -\frac{(200\text{ mL})(36.2\text{ $^\circ$C}-29.5\text{ $^\circ$C})}{(36.2\text{ $^\circ$C}-84.5\text{ $^\circ$C})} \\ \\ & = -\frac{(200\text{ mL})(6.7\text{ $^\circ$C})}{-49.2\text{ $^\circ$C}}\\ \\ & =27\text{ mL}\end{aligned}[/tex]

In conclusion, about 27 mL of water should be added.

Answer:

The answer is Carnivore

Explanation:

A carnivore eat meat which is other animals.

The complete statement will be "Support gases system are subject to the same hazards as, present in any piped medical gas system with the additional hazard of higher pressure"

Generally, A gas system is simply defined as an assemblage of tubes, used for gas reticulation and circulation.

In conclusion, a higher pressure will be experienced as an additional hazard to the medical gas system.

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Answer:

Biology is the study of nature, like plants and animals, while anatomy is the study of the human body, like our bones and muscles.

Explanation:

Hope it helped!

Answer:

Explanation:

Calculating number of moles

At STP

1mol of any gas at STP contains 22.4L

moles of O_2

Now

Volume of O_2:-

Option D

Answer:

its a chemical Reaction

Explanation:

Answer:

the science behind this is 45

Explanation:

you times it by 4N²

divide it by ⁶Mn

Answer:

about 1 week

Explanation:

if you want to eat it after that smell it

Answer:

Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.

Explanation:

In the reaction [tex]Li + Cl - > LiCl[/tex], we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.

The chemical equation can then be rewritten as [tex]Li^{+} + Cl^{-} - > LiCl[/tex], which, if looking at the individual charges of Li and Cl in lithium chloride, becomes [tex]Li^{+} + Cl^{-} - > Li^{+}Cl^{-}[/tex]. Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.

Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of [tex]1s^{2}2s^{1}[/tex], where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, [tex]1s^{2}[/tex], and become the [tex]Li^{+}[/tex] ion. Similarly, Cl has an electron configuration of [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}[/tex] (or [tex][Ne]3s^{2}3p^{5}[/tex]), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration [tex][Ne]3s^{2}3p^{6}[/tex] (or [tex][Ar][/tex]) in order to have an electron configuration where the n = 3 electron shell is full, [tex]3s^{2}3p^{6}[/tex], and become the [tex]Cl^{-}[/tex] ion. Thus, when Li and Cl bond, Li will lose the electron [tex][1, 0, 0, +\frac{1}{2}][/tex] and transfer it to Cl, where it will become the electron [tex][3, 1, 1, -\frac{1}{2}][/tex], thus conserving charge, as there is an equal total number of electrons before and after the reaction.

The molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.

The heat of fusion of a substance can be calculated by using the following formula:

Q = m∆H

Where:

However, the quantity of heat has been given as 9840calories. The molar heat of fusion of iron can be calculated by dividing the heat of fusion by the number of moles of iron.

Moles of iron = mass ÷ molar mass

moles = 200g ÷ 55.8g/mol

moles = 3.58moles

molar heat of fusion = 9840 cal ÷ 3.58mol

molar heat of fusion = 2748.6 cal/mol

Therefore, the molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.

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Answer:

A) 2,747.7 cal/mol

Explanation:

EDGE 2022

Answer:

157. 788 grams

Explanation:

number of moles = mass/molar mass.

hence the mass = molar mass × number of moles

m = 58.44 × 2.7 = 157.788 grams

The term mole concept is used here to determine the mass of sodium chloride. The mass of 2.7 moles of NaCl is 157.78 g.

One mole of a substance is defined as that quantity of it which contains as many entities as there are atoms exactly in 12 g of carbon - 12. The formula used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

The mole concept is a convenient method to express the amount of a substance. The elementary particles in moles may be atoms, ions, molecules etc.

The molar mass of NaCl = 58.44 g/mol

Here the number of moles of NaCl = 2.7

Mass = Molar mass × Number of moles

58.44 g/mol × 2.7 = 157.78 g

Thus the mass of NaCl is 157.78 g.

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If the speed of every gas molecule in the sample is doubled, then the new temperature of the gas is 80K.

Speed of any molecule of gas is measured in terms of velocity and relation between root mean square velocity and temperature will be calculated as:

V = √3RT/M

Means velocity is directly proportional to the square root of the temperature, and for this question required equation is:

V₁/V₂ = √T₁/T₂

If velocity of the molecule is gets double then equation becomes,

V₁/2V₁ = √200/T₂

T₂ = 800K

Hence resultant temperature of gas is 800K.

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The solubility of a gas in a liquid under different pressures can be calculated using Henry's Law.

The solubility of a gas in a liquid under different pressures can be calculated using Henry's Law, which describes the relationship between the pressure of a gas and its solubility in a liquid. According to Henry's Law, at a constant temperature, the solubility (S) of a gas in a liquid is directly proportional to the partial pressure (P) of the gas above the liquid.

Mathematically, Henry's Law is expressed as:

S = k * P

Where:

S = Solubility of the gas in the liquid (usually in mol/L or g/L)

k = Henry's Law constant, which is specific to the gas and the solvent at a given temperature (units depend on the units of pressure and solubility chosen)

P = Partial pressure of the gas above the liquid (usually in atm or kPa)

To calculate the solubility of a gas in a liquid under different pressures, you would typically perform the following steps:

Determine the Henry's Law constant (k) for the specific gas and solvent at the given temperature.

Measure or obtain the partial pressure (P) of the gas above the liquid at the desired pressure conditions.

Use the Henry's Law equation to calculate the solubility (S) of the gas in the liquid:

S = k * P

The solubility will be in units of mol/L (molarity) or g/L, depending on the units used for the Henry's Law constant and partial pressure.

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Answer:

Internal Cue

Explanation:

Answer:

an internal cue

Explanation:

just think

Balancing the coefficients means that the number of atoms are the same on each side which means that the masses of reactants and products are equal.

Hope this helps :))

The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:

s= 8.2652 kJ/kgK

The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:

T₂ = T₁+ T₂ - T₁/ 8₂ - 8₁ ( s - s₁)

= (400 + 500 - 400/8.3271 - 8.0347 (8.2652 - 8))

= 478.83°C

The final enthalpy is determined in the same way:

h₂= h₁ + h₂ - h₁/s₂ - s₁ ( s - s₁)

= ( 3275.5+ 3486.6 - 3275.5/ 8.3271 - 8.0347) (8.265)

= 3441.91 kJ/kg

Answer:

D

Explanation:

If you are comparing 2 metals, the metal with a higher Number of free ions will react with EDTA first

EDTA is a type of chemical which binds certain metal ions such as calcium and magnesium. some of the functions of EDTA  includes:

The EDTA will readily react with metals which have a hiogher number of free ions that it can bind with.

Hence we can conclude that If you are comparing 2 metals, the metal with a higher Number of free ions will react with EDTA first.

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Answer:

The molarity of a solution tells you how many moles of solute you get per liter of solution.Notice that the problem provides you with the volume of the solution expressed in milliliters mL.Right from the start you should remember that you must convert this volume to liters by using the conversion factor1 L=10+3mL

Explanation:

hope this helps if not please let me now

Answer:

scale does not have fixed limits, so it is indeed possible to have a pH above 14 or below zero.

Answer:

D

Explanation:

Because 30c is kevin and add 303+30=333-30=303

The difference in temperature of the two glasses of water is 30°C. The difference in temperature on the Kelvin scale is 86 K D. 303 K. Therefore, option B is correct.

The term temperature is refer to the degree of hotness or coldness of an object.Temperature is measured with a thermometer. Temperature is the measure of average kinetic energy of a system.

There are main three different scales are commonly used to measure temperature that are Fahrenheit (expressed as °F), Celsius (°C), and Kelvin (K).

The difference in temperature of the two glasses of water is 30°C. The difference in temperature on the Kelvin scale is 86 K D. 303 K. Because at 30°c in Kelvin = 273 + 30

= 303 kelvin

Thus, option B is correct.

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Answer: 1.19 M

Explanation:

molarity = (moles of solute)/(liters of solution) = 9.870 / 8.26 = 1.19 M

Answer:

The answer is given in the picture

Explanation:

Answer:

About 0.151 M.

Explanation:

Because 32.20 mL of 0.250 M NaOH was used, determine the number of moles of NaOH consumed:
[tex]\displaystyle 32.20\text{ mL} \cdot \frac{0.250\text{ mol NaOH}}{1\text{L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} = 0.00805\text{ mol NaOH}[/tex]

Find the number of moles of sulfuric acid reacted with using reaction stoichiometry:

[tex]\displaystyle 0.00805\text{ mol NaOH} \cdot \frac{1\text{ mol H$_2$SO$_4$}}{2\text{ mol NaOH}} = 0.00402\text{ mol H$_2$SO$_4$}[/tex]

Therefore, the molarity of the original sulfuric acid solution is:
[tex]\displaystyle \ [\text{H$_2$SO$_4$}] = \frac{0.00402\text{ mol}}{26.60\text{ mL}} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 0.151\text{ M}[/tex]

In conclusion, the molarity of the original sulfuric acid solution was about 0.151 M.