PLEASE HELP!! WORTH A TOTAL OF 100 POINTS!!
The three blocks shown are released from rest and are observed to move at a distance of 0.5m with an acceleration of magnitude of 1.5 m/s^2. answer the following assuming M=2.0kg and ignoring the pulley masses and any friction in the pulleys.

Formulas:
T₁ - m*g = m₁*a --- (1)
T₂ - T₁ - F = m₂*a --- (2)
m₃*g - T₂ = m₃*a --- (3)
m₁ = M
m₂ = 2M
m₃ = 2M

Questions solved:
The magnitude of the friction force: 4.6 N
The coefficient of friction: 0.12
The tension in the left string: 22.6 N
The work done by gravity: 9.8 J
The work done by friction: -2.3 J
The velocity of the blocks after they moved the 0.5 m distance from rest: 1.22 m/s

Needed:
What is the tension in the string on the left?

Answer:

it is a push or pull

Explanation:

short and best description

Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

or

 push or pull.

Explanation:

From the change in the kinetic energy of the particle, the force that acted on the particle from an inertial frame is proved as F(dr) = dK.

The kinetic energy of the particle is given as;

K.E = ¹/₂mv²

dK/dv = mv

m = dK/vdv

The force on the particle is given by Newton's second law of motion;

F = ma

a = dv/dt

F = m(dv/dt)

F = (dK/vdv) (dv/dt)

F = dK/vdt

F(vdt) = dK

v = dr/dt

F (dr/dt) x (dt) = dK

F(dr) = dK, proved

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The rate of radiation into surrounding space of the box shaped wooden stove at a temperature of 205 degrees Celsius is 8,453.82 J/s.

The rate of radiation of the wooden stove is calculated as follows;

P =  εAσT4

Where:  

A = 2(Lw + Lh + Wh)

A = 2(0.75 x 1.2  +   0.75 x 0.4   + 1.2 x 0.4)

A = 3.36 m²

P = 0.85 x 3.36 x (5.67 x 10⁻⁸) x (478)⁴

P = 8,453.82 J/s

Thus, the rate of radiation into surrounding space of the box shaped wooden stove at a temperature of 205 degrees Celsius is 8,453.82 J/s.

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Explanation:

Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects. And decreasing the separation distance between objects increases the force of attraction or repulsion between the objects.

Answer:

Explanation:

The total amount of mass and energy in the universe is constant.....energy may change to mass and mass may change to energy, but the total is a constant.

Answer: 4.4m/s

Explanation:

Answer:

The numerical limits imposed on imported goods through quotas ultimately leads to higher prices paid by consumers. Essentially, the import quota prevents or limits domestic consumers from buying imported goods. The import quota reduces the supply of imports.

Explanation:

The resistance of the electric space heater dissipating the given amount of power is 10.9Ω.

Ohm's law states that "the voltage across the cross-section of a conductor is directly proportional to the current passing through it.

It is expressed as;

V = I × R

Where V is voltage, I is current and R is resistance.

Also, electrical power is the product of current and voltage.

P = I × V meaning I = P/V

Hence,

V = (P/V) × R

R = V² / P

Given the data in the question;

To determine the resistance of the heater, we substitute our given values into the derived expression above.

R = V² / P

R = (120V)² / 1320W

R = 14400V² / 1320W

R = 10.9Ω

Therefore, the resistance of the electric space heater dissipating the given amount of power is 10.9Ω.

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Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.

The confidence Interval of the survey above is calculated using the formula:

[tex] x ± z( σ/√n)[/tex]

where

From the data provided;

x = 2.0

σ = 5.1

n = 200

z = 2.576 for 99% confidence

Therefore, the confidence Interval is:

[tex] 2.0 ± 2.576( 5.1/√200)[/tex]

Confidence interval = 2.0 ± 0.93.

Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

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The following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

To answer the question, we have to know what mathematical operations are.

Mathematical operations are operations which are performed to change the value of a variable. The arithmetic mathematical operations we have are

Now, for two quantities with different unit dimensions, addition, subtraction and equality are not allowed because these mathematical operations require the quantities to be in the same unit dimensions

Also, for two different quantities with differnt unit dimensions, multiplication and division are allowed because these mathematical operations do not require the quantities to be in the same unit dimensions.

So, the mathematical operations that are allowed are multiplication and division while the mathematical operations that are not allowed are addition, subtraction and equality.

So, the following mathematical operations are and are not allowed on two quantities with different unit dimensions are C) Allowed : Multiplication, Division , Not Allowed : Addition, Subtraction, Equality

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The temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

The relationship between resistance and temperature is given as;

R = R₀( 1 + αΔθ)

From the first resistance, we will have the following equation,

R₁ = R₀( 1 + αΔθ)

50 = R₀(1 + 15α) ------ (1)

From the second resistance, we will have the following equation,

58 = R₀(1 + αT) ------ (2)

Divide (1) by (2)

[tex]\frac{50}{58} = \frac{R_0(1 + 15\alpha)}{R_0(1 + T\alpha)} \\\\\frac{50}{58} = \frac{(1 + 15\alpha)}{(1 + T\alpha)} \\\\50(1 + T\alpha) = 58(1 + 15\alpha)\\\\50 + 50T\alpha = 58 + 870\alpha \\\\50(0.0425)T = (58- 50) + 870(0.0425)\\\\2.125T = 44.975\\\\T = 21.2\ ^0C[/tex]

Thus, the temperature of the transformer after the transformer has been in operation for several hours at the given resistance is 21.2 degrees Celsius.

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Answer:

The angular momentum depends on both the angular velocity and the mass distribution of the object. You can change this angular momentum by exerting a torque (a twisting force)—but with no external torque, the angular momentum is conserved. Now getting back to the ice skater.

Speed of second car  will be 15.35 m/s

The Doppler effect is the apparent change in frequency of a wave when the observer and the source of the wave move relative to each other.

f0= observed frequency = 1920 Hz

v = speed of source = 343 m/s

v0 = speed of observer = ?

fs = frequency of source = 2010 Hz

from Doppler effect

f0 = (v -v0 / v) * fs

1920 / 2010 = (343 - v0)/ 343

(192/ 201) * 343 = 343 - v0

v0 = (343 * 9) / 201 = 15.35 m/s

Speed of second car  will be 15.35 m/s

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Answer:    Let the speed of sound equal 331 m/s

f = f0 ( (V ± Vo) / V)      observer moving

f = 482 (331 + 25.6) / 331 = 519 /s    (observer moving towards source)

f = 519 (331 / (331 - 25.6) = 563 / s    (source moving towards observer)

Check: For both moving:

f = f0 ((331 + 25.6) / (331 - 25.6)) = 1.17 f0 = 482 * 1.17 = 563 / s

Answer:

b

Explanation:

Source is parallel to the propagation.

Answer:

input force is force applied to overcome the load and the output force is the force overcome by the effort

Explanation:

effort is equal to input and load is equal to the output

Answer:

Explanation:

Formula (Force)

We have the values of :

Substitution

Answer:

my friend give options .............

The work done by the electric force of the charge is equal to the change in kinetic energy, equal to 5x [tex]10^{-4}[/tex] J.

The work done by the body in motion is equal to the change in kinetic energy or the difference between the final and initial kinetic energy.

[tex]W=[/tex]Δ[tex]K.E=K.E_{f} -K.E_{i}[/tex]

Given, the kinetic energy found when the charge has moved 3 cm is  5x [tex]10^{-4}[/tex] J.

Therefore, work done by the electric force, [tex]W=[/tex]  5x [tex]10^{-4}[/tex] J.

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The turn signal belongs to the control subsystem of an automobile.

Turn signals serves as the control that help motorists to react and plan for road user making a turn in front of them.

This is part of the subsystem of an automobile. which help to maintain the best driving experience on the road.

Learn more about turn signal at;

Answer:

liquid to a gas and doesn't change T

Explanation:

that part of the line has no slope

Answer:

A. At segment T-U, the substance changes from a liquid to a gas and does not change temperature.

Explanation:

The atoms of these noble gases have stable arrangements of electrons, the elements are all inert.

The term inert gases has to do with those gases that are not reactive. The atoms of these elements have a complete octet of electrons hence they are unreactive.

As such,  the atoms of these noble gases have stable arrangements of electrons, the elements are all inert.

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[tex]\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2\\\\~~~~~=\dfrac 12 \cdot 110 \times 10^{-3} \cdot 50^2\\\\~~~~~=137.5~ \text{J}[/tex]

Answer: 137.5 Joules

Explanation:

The SI units for kinetic energy is Joules, the SI units for mass is kilograms, and the SI units for velocity is meters per second. We are given the mass in grams, so we must convert it to kilograms. There are 1,000 grams in 1 kilogram:

[tex]110g*\frac{1kg}{1000g} =0.11kg[/tex]

Kinetic energy is the energy the system has due to its motion. It is defined to be:

[tex]KE=\frac{1}{2} mv^2[/tex]

Plug everything in:

[tex]KE=\frac{1}{2} (0.11kg)(50m/s)^2[/tex]

[tex]KE=137.5J[/tex]

Answer:

735 J

Explanation:

Formula

Gravitational Potential Energy (GPE) = mgh

Given

Solving

The density of the unknown liquid is 650.67 kg/m³

First step : determine the mass in air

The Tension in air = mg

therefore Mass in air ( m ) = Tension in air / g

                                           = 3.78 kg

Considering Tension in water

T = 29.6 N

29.6 = 4/3 * πR³ * ( р - б ) g   ----- ( 1 )

where : р = mass density, б = water density

Considering Tension in other liquid

T = 19.1 N

19.1 = 4/3 * πR³ * ( р - б' ) g  ------ ( 2 )

Final step : Determine the density of the unknown liquid

Divide equation ( 1 ) by equation ( 2 )

1.54 = ( р - б ) / ( р - б' )

0.54 р + б = 1.54 * б'

therefore ( б' ) density of uknown liquid

= 650.67 Kg/m³

Hence we can conclude that The density of the unknown liquid is 650.67 kg/m³

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Answer:

The answer is Model the charge distribution as the sum of infinitesimal point charges, dq, and add together the electric potentials, dV, from all charges, dq. ...

Calculate the electric field (either as a integral or from Gauss' Law), and use: ΔV=V(→rB)−V(→rA)=−∫BA→E⋅d→r.

Explanation:

Answer:

yes

Explanation:

tissues and organs are made of cells therefore cells have to be smaller and simpler