Please help.

For math class

Answer:

The last one

Step-by-step explanation:

Answer:

I think its two eqautions

Answer:

b

[tex]\int\limits^a_b {x} \, dx[/tex]

Step-by-step explanation:

Answer:

#1 is Geometric

its common ratio is 2

#2 is Arithmetic

its common difference is 6

Answer:

a = 146

Step-by-step explanation:

0 . 1 5 + 2 8 . 1 = 5 0  

3 / 2 0 + 2 8 . 1 = 5 0

3 /2 0 = 2 1 . 9

Answer:

B

Step-by-step explanation:

put in order from least to greatest

2,3,4,5,6,10,12

median is just another word for middle

Answer:

Step-by-step explanation:

It all depends on how many people are in your class.

To calculate probability

Determine a single event with a single outcome.

Identify the total number of outcomes that can occur.

Divide the number of events by the number of possible outcomes.

To determine the probability, Use the formula

What is the formula of probability?

P(A) is the probability of an event “A” n(A) is the number of favourable outcomes. n(S) is the total number of events in the sample space.

P(A | B) = P(A∩B) / P(B)

Answer:

$1,250

Step-by-step explanation:

Mr. Stewart will spend $750

Mrs. Steward wants $250 less than twice that

750 * 2 is 1500

1500 - 250 is 1250, our final answer

brainliest? please and thank you.

Answer: Area: 5808 Primiter: 308

Answer:

Answer: A-Area: 5808 Primiter: 308

B-Area is needed

Step-by-step explanation:

Answer:

Median - 15.5

Lower Quartile - 13

Upper Quartile - 22.5

Steps to calculate Median:

1. Orchestrate your numbers in mathematical request.  

2. Check the number of numbers you have.  

3. On the off chance that you have an odd number, partition by 2 and gather together to get the situation of the middle number.  

4. On the off chance that you have a considerably number, partition by 2. Go to the number around there and normal it with the number in the following higher situation to get the middle.

Steps to calculate Upper and Lower Quartile:

1. Request your informational index from most minimal to most elevated qualities.  

2. Track down the middle. This is the second quartile Q2.  

3. At Q2 split the arranged informational collection into equal parts.  

4. The lower quartile Q1 is the middle of the lower half of the information.  

5. The upper quartile Q3 is the middle of the upper portion of the information.

Answer:

B

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

The measure of the angle CBD = 180° - 30° = 150°.

Answer:

y ≥ 62

Step-by-step explanation:

Give Me Brainllest plz T - T

Answer:

2 : 3 is the correct answer

Step-by-step explanation:

happy to help :)

Answer:

z=7

Step-by-step explanation:

If z represents 1/2 of 14, then z=14*1/2=14/2=7

Answer:

233445.54 gallons

Step-by-step explanation:

Given data

Diameter= 15m

Radius= 7.5m

Height= 5m

Let us first find the volume

the volume of a cylinder is given as

V= πr^2h

substitute

V= 3.142*7.5^2*5

V= 3.142*56.25*5

V=883.6875 m^3

Hence the volume in gallons is

233445.54 gallons  (from conversion tables)

9514 1404 393

Answer:

  17 7/9 yd³

Step-by-step explanation:

The volume is the product of the dimensions.

  V = LWH

  V = (3 1/3 yd)(2 2/3 yd)(2 yd) = (10/3)(8/3)(2) yd³ = 160/9 yd³ = 17 7/9 yd³

__

Additional comment

You can guess the correct answer with a couple of estimates.

  volume is greater than (3)(2)(2) = 12 . . . . rounding down to integer

  volume is less than (3 1/3)(3)(2) = 20 . . . . rounding 2 2/3 up to 3

Based on the way these numbers are rounded, the volume is closer to 20 than to 12. This strongly suggests that 17 7/9 is the correct answer.

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required data to answer the question are missing.

However, the interpretation of the question is to determine the interquartile range (IQR) of a certain dataset.

Then get the difference between the calculated IQR & Joe's data and also the difference between the calculated IQR & Sam's data

Then, make comparison

To do this, I will use the following assumed datasets.

[tex]Data: 62, 63, 64, 64, 70, 72, 76, 77, 81, 81[/tex]

IQR is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]Q_3[/tex] is [tex]the\ median[/tex] of the upper half

[tex]Q_1[/tex] is [tex]the\ median[/tex] of the lower half

For Joe, we have:

[tex]Lower\ half: 62, 63, 64, 64, 70[/tex]

[tex]Upper\ half: 72, 76, 77, 81, 81[/tex]

The median is then calculated as:

[tex]M = \frac{N + 1}{2}[/tex]

For, the lower half:

[tex]Q_1 = \frac{5 + 1}{2} = \frac{6}{2} = 3rd[/tex]

So:

[tex]Q_1 = 64[/tex]

For the upper half:

[tex]Q_3 = \frac{5 + 1}{2} = \frac{6}{2} = 3rd[/tex]

So:

[tex]Q_3 = 77[/tex]

When the same process is applied to Sam's data,

[tex]Q_1 = 52[/tex]

[tex]Q_3 = 58[/tex]

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 77 - 64[/tex]

[tex]IQR = 13[/tex]

Assume that:

[tex]Joe = 60[/tex]

[tex]Sam = 65[/tex]

[tex]Joe - IQR = 60 - 13 = 47[/tex]

[tex]Sam- IQR = 65- 13 = 52[/tex]

Hence, the IQR is 47 points less for Joe's data than Sam's

Answer:

170 divided by 30 or calories divided by minutes

Step-by-step explanation:

the answer could be either but they both mean the same thing just in different words

Answer:

              [tex]\bold{a_n =32\left(\frac32\right)^{n-1}}[/tex]

Step-by-step explanation:

[tex]a_1=32\\a_2=48\\a_3=72\\\\\dfrac{a_2}{a_1}=\dfrac{48}{32}=\dfrac32\\\\ \dfrac{a_3}{a_2}=\dfrac{72}{48}=\dfrac32\\\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac32=r[/tex]

Therefore the formula:

                                     [tex]a_n=a_1\cdot q^{n-1}\\\\a_n =32\left(\frac32\right)^{n-1}[/tex]

The solution of the equation x³ = 16 will be;

⇒ x = 2.519

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The equation is,

⇒ x³ = 16

Now,

Since, The equation is,

⇒ x³ = 16

Solve for x as;

⇒ x = ∛ 16

⇒ x = 2.519

Thus, The solution of the equation is,

⇒ x = 2.519

Learn more about the mathematical expression visit:

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Answer: 65

Step-by-step explanation:

Measure of ∠M to the nearest degree is [tex]65^{0}[/tex].

The law of cosine states that the square of any one side of a triangle is equal to the difference between the sum of squares of the other two sides and double the product of other sides and cosine angle included between them.

Given

k = 76 inches

l = 30 inches

m = 69 inches

From the law of cosines

Cos <M = [tex]\frac{k^{2} +l^{2} -m^{2} }{2.k.l}[/tex]

Cos <M = [tex]\frac{76^{2} +30^{2} -69^{2} }{2.76.30}[/tex]

Cos <M = [tex]\frac{1915}{4560}[/tex]

Cos <M = 0.42

<M  = [tex]cos^{-1} (0.42)[/tex]

<M ≈ [tex]65^{0}[/tex]

Hence, measure of ∠M to the nearest degree is [tex]65^{0}[/tex].

Find out more information about law of cosines here

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Answer:

6 pounds

Step-by-step explanation:

every 16 ounces =1 pound

so 96/16 = 6

6 *1 = 6

therefour 6 pounds

Answer:

f(2)=67

Step-by-step explanation:

In order to evaluate the function you must switch all of the x for 2

so it would be f(2)=2^4+6(2)^3+3