Please procedure and solution

2 x |-6|-3 x |2|+|-14|=​

Answer:

1.5(x+4) is the answer of this question.

[tex]increasing ( \infty \: to \: 1) and \: increasing(3 \: to \: 4) \\ \\ decreasing(1 \: to \: 3) \: and \: (4 \: to - \infty )[/tex]

Step-by-step explanation:

by increasing it means the gradient is positive, so coming positive infinity gradient is positive but once it reaches (1;0) it becomes 0 (=0). from (1;0) it starts to decrease approaching the asymptote of 3

The shorter piece of wire is 8 cm long when the total length of the wire is 19 cm long.

We are given that:

a wire's length is 19 cm.

We have to cut the wire into two pieces.

We are also given that the longer piece of wire is 3 cm longer than the shorter piece.

Let the shorter piece of wire be x cm

Longer piece = x + 3 cm.

So, the equation formed will be:

x + x + 3 cm = 19 m

2 x + 3 cm = 19 cm

2 x cm = 19 cm - 3 cm

2 x cm = 16 cm

x = 16 / 2 cm

x = 8 cm.

Therefore, the shorter piece of wire is 8 cm long.

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Answer:

Step-by-step explanation:

Comment

For this particular problem, the 10^6 will not be affected. All you have to do is divide 9.45 by 2. When you do that, you get

9.45/2 = 4.725

Now add on the 10^6

The answer is 4.725 * 10^6

Personally, I would likely round this to 4.73 because you were given 3 digits of accuracy, so you should give your answer as 3 digits.

The required solution is ∠X'≅∠X, ∠Y'≅∠Y and  ∠Z'≅∠Z.

It is required to find the corresponding angles.

In Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle and corner whether constituting a projecting part or a partially enclosed space.

Given :

Corresponding angles are

∠X'≅∠X,

∠Y'≅∠Y

∠Z'≅∠Z

Therefore, the required solution is ∠X'≅∠X, ∠Y'≅∠Y and  ∠Z'≅∠Z.

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The complete statement is that if the equation of the function f(x + 3) = x^2 + 4x − 7, the value of the function f(2) is -10

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, we have

f(x + 3) = x^2 + 4x − 7

To find f(2), we make use of the following comparison

f(2) = f(x + 3)

This means that

2 = x  + 3

Evaluate

x = -1

Substitute x = -1 in f(x + 3) = x^2 + 4x − 7

f(-1 + 3) = (-1)^2 + 4(-1) − 7

This gives

f(2) = -10

Hence, the complete statement is that if the equation of the function f(x + 3) = x^2 + 4x − 7, the value of the function f(2) is -10

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Considering the given probability distribution, we have that there is a 0.349 = 34.9% probability that the left tire has a pressure of at least 25 psi.

The probability distribution for the air pressure of the tires of the car(X right, Y left) is given as follows:

The pressure in the right tire is found to be 22 psi, hence y = 22 and:

The value of K is found considering that the sum of all probabilities has to be 1, hence:

[tex]\int_{18}^{28} K(x^2 + 484) dx = 1[/tex]

[tex]\frac{Kx^3}{3} + 484Kx\lbracket|_{x = 18}^{x = 28} = 1[/tex]

Applying the Fundamental Theorem of Calculus:

7317.33K + 13552K - 8712K - 1944K = 1

10213.33K = 1

K = 1/10213.33

K = 0.000098.

The probability that the left tire has a pressure of at least 25 psi is:

[tex]P(X \geq 25) = \int_{25}^{28} 0.000098(x^2 + 484) dx[/tex]

[tex]P(X \geq 25) = 0.000098\int_{25}^{28} (x^2 + 484) dx[/tex]

[tex]P(X \geq 25) = 0.000098\left(\frac{x^3}{3} + 484x\right)_{x = 25}^{x = 28}[/tex]

[tex]P(X \geq 25) = 0.000098(7317.33 + 13552 - 5208.33 - 12100)[/tex]

[tex]P(X \geq 25) = 0.349[/tex]

0.349 = 34.9% probability that the left tire has a pressure of at least 25 psi.

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Answer:

8 months

Step-by-step explanation:

5x6 is 30

30 books per 6 month

40 books is 1 month and a bit

the bit is 10 left

5x2 is 10 so 2 more months

6plus 2 is 8

so he has been with his book club for 8 months

Answer:9

Step-by-step explanation:

I'm assuming the equation is : [tex]9^{6}[/tex]=[tex]x^{3}[/tex]*[tex]9^{3}[/tex]

1) [tex]9^{6}[/tex]=531441

  [tex]9^{3}[/tex]    =729

2) 531441=729  [tex]x^{3}[/tex]

3) [tex]\frac{531441}{729}[/tex]= [tex]x^{3}[/tex]

4)729=[tex]x^{3}[/tex]

5) [tex]\sqrt[3]{729}[/tex] =[tex]\sqrt{x}[/tex]^3    

6) 9=x

The area of the cardboard in Pedro's model is 190 sq inches.

The only difference between lateral surface area and total surface area is in lateral surface area we only consider the side views and neglect the top and bottom on the other hand for total surface area we consider all sides.

As a sphere has no side it has only total surface area which is 4πr².

According to the given question Pedro uses cardboard to make a model of a square pyramid.

Also given that the edges of the of the model is 5 in. long and the height of the triangular face is 4 in.

As to make the base of the pyramid with is square we need to form a cube which has sides = height = 5 inches.

We know the total surface area of a cube is 6(side)² which is

= 6(5)² sq inches.

= 6(25) sq inches.

= 150 sq inches.

Now for the upper triangular part we need 4 triangles with height 4 inches and as the base of the cube is 5 inches therefore the base of the triangle will also be of 5 inches.

We know area of a triangles with given height and base is

= (1/2)×base×height.

So for four such triangles the area will be 4 times of this.

= 4[(1/2)×5×4] sq inches.

= 4[10] sq inches.

= 40 sq inches.

So, the total area of the square pyramid model will be (150 + 40) = 190 sq inches.

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The number 0.00006 is greater than 0.000002 by 30 times.

Two numbers , 0.00006 and 0.000002 are given.

We have to find out that by how many times 1st is greater by the 2nd.

What is algebra ?

Algebra is the branch that deals with various symbols and the arithmetic operations such as multiplication , division , etc.

As per the question ;

Numbers are 0.00006 and 0.000002.

Let's divide them to find how many times 1st is greater by the 2nd.

So ;

0.00006 ÷ 0.000002

Multiply by 10^6 and divide by 10^6

We get ;

[tex]\frac{0.00006 * 10^6}{0.000002*10^6}[/tex]

or

60 / 2

= 30 times

Thus , the number 0.00006 is greater than 0.000002 by 30 times.

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Answer:

5.6 =5610=28×25×2=285 in simplest form.

Step-by-step explanation:

Answer:

5 3/5

(heres a picture that will show you, i really hope this helps!!)

Answer:

x = 1 and y = 1

Step-by-step explanation:

Let's solve your system by elimination.

2x − y = 1 and x − 2y = −1

Multiply the second equation by -2, then add the equations together.

(2x−y=1)

−2(x−2y=−1)

Becomes:

2x−y=1

−2x+4y=2

Add these equations to eliminate x:

3y=3

Then solve3y=3for y:

3y=3

3y3=33(Divide both sides by 3)

y=1

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

2x−y=1

Substitute1foryin2x−y=1:

2x−1=1

2x−1+1=1+1(Add 1 to both sides)

2x=2

2x2=22(Divide both sides by 2)

x=1

Answer:

x=1 and y=1

Answer:x=1, y=1 point (1,1)

Step-by-step explanation:

Answer:

The time she would arrive in London is 1:20 pm

Step-by-step explanation:

Recall

Speed= Distance/Time

But we want to find the time taken, so:

We cross multiply:

Speed *Time = Distance

Make time the subject of formula

Time= Distance/Speed

195/52

= 3.75 hours

Therefore, 9:45 am + 3.75 hours

= 13.20 pm

Which is equivalent to 1:20 pm

Answer:

x=11.1

Step-by-step explanation:

6x-4x-20=2.2

2x-20=2.2

2x=22.2

x=11.1

The correct answer is option A

• In mathematics, comparison of numbers if the process that defines similar properties between two numbers and identifies that the number if smaller or greater than or equal to the other number.

• In maths there are three special symbols used in comparison of numbers. The basic symbols are

1. Greater than (>)

2. Less than (<)

3. Equals to (=)

According to the question

Option A :

4.13 = 4.130

As we know the value of 0 after all the numbers and after the decimal is insignificant,

So , 4.13 = 4.130

This is correct comparison.

Option B :

5.16<5.06

Bigger number can’t be less than the smaller number, comparison is wrong.

Option C :

6.28<6.08

Bigger number can’t be less than the smaller number, comparison is wrong.

Option D:

7.09>7.19

Smaller number can’t be greater than the bigger number, comparison is wrong.

Option A is correct

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Answer:

Y = ×+ 4 a 75 VBC

I HOPE ITS HELP

63+ (2x+8)+(x + 7) = 180

63+3x+15=180

78+3x=180

3x=102

x=34

Hey there!

63 + (2x + 8) + (x + 7) = 180

DROP the PARENTHESES:

63 + 2x + 8 + x + 7 = 180

CONVERT TO:

63 + 2x + 8 + 1x + 7 = 180

COMBINE the LIKE TERMS 1:

71 + 3x + 7 = 180

COMBINE the LIKE TERMS 2:

78 + 3x = 180

3x + 78 = 180

SUBTRACT 78 to BOTH SIDES:

3x + 78 - 78 = 180 - 78

SIMPLIFY IT:

3x = 180 - 78

3x = 102

DIVIDE 3 to BOTH SIDES:

3x/3 = 102/3

SIMPLIFY IT:

x = 102/3

x = 34

Therefore, your answer should be:

x = 34

Good luck on your assignment & enjoy your day day!

~Amphitrite1040:)

Answer:

x=5 and y = 0 coordinate = (5,0)

Step-by-step explanation:

solve the simultaneous equation

hope this works :)

Answer:

30

Step-by-step explanation:

to find 10%, find 100% first

because we know what 25% is, the easiest way we can work this out is multiply 25% by 4

so:

[tex] 4 \times 25\% = 100\%\\\\ 75 \times 4 = 300[/tex]

this means that 100% is 300.

now to find 10% all we have to do is divide the number by 10.

[tex]300 \div 10 = 30[/tex]

so 10% is 30

to check we're right, we make sure that 25% and 10% = 35%

75 + 30 = 105, meaning our percentages are correct

Answer:

3

Step-by-step explanation:

6n = 3/5 x 5 (n+3)

6n = 3 (n+3)

6n = 3n + 9

6n - 3n = 9

3n = 9

=3

Answer:

6n=3/5(5n+15)

6n=3n+9

6n-3n=9

3n=9

3n/3=9/3

n=3

The 13th term in the following arithmetic sequence 2,10,18,26 is 114

Arithmetic progression is the series of numbers that have common differences between adjacent values

Now the given sequence is,

2,10,18,26

So, common difference, d = 10 -2 = 8

and 1st term, a1 = 2

Thus, nth term of an arithmetic sequence is given as,

Tn = a1 + (n - 1)d

For 13th term put n =  13

⇒ T13 = 2 + (15 - 1)8

⇒ T13 = 2 + 14*8

⇒ T13 = 2 + 112

⇒ T13 = 114

Thus, the 13th term in the following arithmetic sequence 2,10,18,26 is 114

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The correct question is-

find the 13th term in the following arithmetic sequence 2,10,18,26.

The x and y coordinates of the endpoint F are (6,-5)

The midpoint of a line segment is a point that is situated exactly at the middle from the  two ends of the line segment

The coordinate of the mid-point or any other point can be found using the section formula.

For a point P with coordinates, the section formula is as follows: (x,y)

which divides the line segment A(x1,y1), B(x2,y2) in the ratio m:n, is given by the equation

Px=mx2+nx1/m+n               Py=my2+ny1/m+n

Because the midpoint divides the line segment equally, m and n are both 1 in the midpoint case.

Thus the formula becomes

Px=1*x2+1*x1/1+1       Py = 1*y2+1*y1/1+1

where Px and Py are x and y co-ordinates of the point x and y

It is now assumed that midpoint M has coordinates (4,-1)

Point E is given by (2,3)

We are required to find F

Thus using section formula,

Mx=2+x/2            My=-3+y/2

4=2+x/2                 -1=1+y/2

8-2=x                        -2-3=y

x=6                         -5=y

Therefore, the coordinates of x and y of the endpoint F are(6,-5)

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Answer:

Blank 1: -5
Blank 2: -4

Blank 3:-4

Blank 4: 0

Blank 5: 1

Blank 6: -2

Blank 7: 0

Blank 8: -2

Step-by-step explanation:

Blank 1 and 2 were already done.

We can fill in the x value of A into blank 3, which makes it 0/2, or for blank 4: 0

We can fill in the y value of B into blank 5, which makes it -4/2, or for blank 6: -2

Then we can put the values from 4 and 6 together into 7 and 8, so 7 is 0 and 8 is -2. (0, -2)

Answer:

Step-by-step explanation:

2 1/3 because I learned this exact question at school

Linear inequality of the given graph is given by option (A) and (C) .

(A) y > x /6 +2   ..(1) this line is represented by upper line .

and y ≤ x /4 + 1   ....(2) this line is represented by lower line .

  Let consider a point (2, 3)

Put in equation (1) , we get

  3 > 0.33 +2

  3 > 2.33

which is true so shading will be in lower part of this line .

Put in equation (2) , we get

 3 ≤  0.5 +1

 3 ≤  1.5

which is false so shading will be in opposite direction in upper part of this line.

Hence , there is a common shading area between the lines which is required area .

(b) y <  x /6 +2   ..(1) this line is represented by upper line  and y ≥ x /4 + 1   ....(2) this line is represented by lower line . Let consider a point (2, 3)

Put in equation (1) , we get

  3 < 0.33 +2

  3 < 2.33

which is false so shading will be in opposite direction to the point in upper part of this line .

Put in equation (2) , we get

 3  ≥ 0.5 +1

 3 ≥  1.5

which is true so shading will be in lower part of this line.

Hence , there is no common shading area between the lines .

(C)  y ≥  x /6 +2   ..(1) this line is represented by upper line  and y < x /4 + 1   ....(2) this line is represented by lower line . Let consider a point (2, 3)

Put in equation (1) , we get

  3 ≥  0.33 +2

  3 ≥  2.33

which is true so shading will be in direction to the point in lower part of this line .

Put in equation (2) , we get

 3  <  0.5 +1

 3 <  1.5

which is is false so shading will be in opposite direction to the point in upper part of this line

Hence , there is a common shading area between the lines which is required area .

(D)  y ≤  x /6 +2   ..(1) this line is represented by upper line  and y > x /4 + 1   ....(2) this line is represented by lower line . Let consider a point (2, 3)

Put in equation (1) , we get

  3 ≤ 0.33 +2

  3 ≤ 2.33

which is false so shading will be in opposite direction to the point in upper part of this line .

Put in equation (2) , we get

 3  > 0.5 +1

 3 >  1.5

which is true so shading will be in lower part of this line.

Hence , there is no common shading area between the lines .

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According to the given statement the area of the right angle triangle:

= 18 cm².

A right triangle, sometimes known as a right-angled triangle, or perhaps more formally called an orthogonal triangle, formerly known as a rectangle triangle, is a triangle with one right angle or two perpendicular sides. Trigonometry is founded on the relationship between the sides and some other angles of a right triangle.

Given value

A = 6cm

B = 6cm

Using the right angle triangle area formula:

Area = (a*b)/2

       = (6 *6)/2

       = 18 cm²

According to the given statement the area of the right angle triangle:

= 18 cm²

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