Please see attached photo for problem from my homework set.

Answer:

See below ~

Step-by-step explanation:

Given

Solving

Take Equation 1 and rewrite it so that it is equal to x.

Take Equation 2 and rewrite it so that it is equal to z.

Now, substitute these values in Equation 3.

Substitute the value of y in Equation 1.

Substitute the value of y in Equation 2.

Add the values of x, y, and z together.

Answer:

Use   SOH  CAH TOA  to rember how the trig function fit on the triangle

Step-by-step explanation:

we are given  the Hypotenuse and the Opposite  or   H and O   look for the trig function with each of those,  SOH is good

Sin Ф =  Opp /  Hyp,    or   SOH

now plug in what you are given

Sin Ф = 5 / 8

use inverse trig fuction to find the angle

arcSin ( Sin Ф) = arcSin ( 5/8)

trig functions cancel out

Ф = arcSin(5/8)

I'm using my calculator to find the arcSin(5/8)

Ф=38.6821...°

also make sure you know if your calculator is in degrees or radians.  

Ф=38.68°   to the nearest hundredth  :)

Answer:

∠A = 38.68°

Step-by-step explanation:

The side opposing ∠A and the hypotenuse are given.

Therefore, take the inverse sin function of ∠A.

Answer:

$18.60

Step-by-step explanation:

The total amount spent is $372, and this can be divided by 20. Each costume would cost $18.60.

Answer:

$3096

Step-by-step explanation:

There are 12 months in 1 year.

3 × 12 = 36

There are 36 months in 3 years.

$86 × 36 = $3096

Answer:

3096

Step-by-step explanation:

I just completed the quiz.

Answer: 3

Step-by-step explanation:

3x8 = 24

24x2= 48!

8x12= 96!

Answers must be divisible by both numbers, and achievable by both inputs.

Hope This Helped

The linear function that gives the candle's height, y, after x hours, is defined by:

y = -0.25x + 11.

A linear function is modeled by:

y = mx + b

In which:

In this problem, in 12 hours, the height decayed 3 inches, hence the slope is given by:

m = -3/12 = -0.25.

So:

y = -0.25x + b.

After 4 hours, the height was of 10 inches, hence we use this to find b:

10 = -0.25(4) + b

b = 11

Thus the equation is given by:

y = -0.25x + 11.

More can be learned about linear functions at https://brainly.com/question/24808124

#SPJ1

Answer:

umm 9?

Step-by-step explanation:

Step-by-step explanation:

4x−5y=6

−8x+10y=−12

Isolate x for 4x –5y = 6: x=6-5y/4

Substitute x= 6+5y/4

[-8 (6-5y/4) +10y=-12]

Simplify

[-12= -12 ]

The solutions to the system of equations are:

x=6+5y/4

Answer:

Equation:

C = 1.75x + 5 25

A 22-mile ride costs $43.75.

Step-by-step explanation:

Because there is a flat fee of 5.25, only the first two equations could possibly be correct.

Then check with the examples given. If a 7 mile ride costs 17.50, the second equation cannot possibly be right. 7 miles times over $5 per mile will cost more than $35 not even including the flat fee.

Check:

1.75(7) + 5.25 = 17.50

and

12(1.75) + 5.25 = 26.25

So, the correct equation is

C = 1.75x + 5.25

Next use this equation to find the cost of the 22 mile ride.

1.75(22) + 5.25

= 43.75

Answer:

A. r = 6 sin theta

Step-by-step explanation:

Given equation is: [tex]x^2+y^2-6y=0[/tex]....(1)

Using the formulae that link Cartesian to Polar coordinates.

[tex]x=r\cos\theta \: and \: y = r\sin\theta[/tex]

Plugging the values of x and y in equation (1), we find:

[tex](r\cos\theta)^2+(r\sin\theta)^2-6(r\sin\theta)=0[/tex]

[tex]\implies r^2\cos^2\theta+r^2\sin^2\theta-6r\sin\theta=0[/tex]

[tex]\implies r^2(\cos^2\theta+\sin^2\theta)=6r\sin\theta[/tex]

[tex]\implies r^2(1)=6r\sin\theta[/tex]

[tex](\because \cos^2\theta+\sin^2\theta=1)[/tex]

[tex]\implies\frac{ r^2}{r}=6\sin\theta[/tex]

[tex]\implies\huge{\purple{ {r}=6\sin\theta}}[/tex]

Answernone

none

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Step-by-step explanation:

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: [tex]y=b^x[/tex]

Our equation: [tex]y=6^x[/tex]

Add alterations:

Final equation: y=6^x+0.612 - 4

Answer:

0.05km

Step-by-step explanation:

There are 1000 meters in a single kilometer. Using some dimensional analysis, we get set up the following expression:

[tex]\frac{50}{1} \frac{meters}{1}\frac{1}{1000} \frac{kilometers}{meters}[/tex]

The meters will cancel leaving the units of kilometers:

[tex]\frac{50}{1000} km=0.05km[/tex]

Answer:

10 and 30

Step-by-step explanation:

The sum of 10 and 30 is 40.

30 is three times ten (10 x 3 = 30).

hope this helps!

The answer is 10 and 30

10 times 3 is 30, meaning 10 will be the number times 3 they wanted. 10 + 30 is 40, therefore the answer is 10 and 30

Answer:

The length of the arc is 8*pi cm. An arc that subtends a central angle of 120 degrees has a length of 120/360 = 1/3 the length of the total circumference of the circle. We know the entire circumference of the circle is 2πr, which in this case is 2π*12 = 24π.

Step-by-step explanation:

sorry I only have the 8

Answer:

r = 50 degrees.

Step-by-step explanation:

r = 50 degrees ( vertical angles are congruent).

Answer:

0.825 bags of oranges

Step-by-step explanation:

1/3 is 0.33 and 2/5 is 0.4 so 0.33/0.4 is 0.825

Answer:

6 hours

Step-by-step explanation:

2 2/3 +3 1/3= 5+1=6

Answer:

2 2/3+ 3 1/3 = 6. Multiply 6 by 4 weeks. 24 as your whole number.

Step-by-step explanation:

hope this helps

Answer:

x = -2 and 6

Step-by-step explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

[tex]y=\frac{x-5}{x^{2} -4x-12}[/tex]

[tex]x^{2} -4x-12=0[/tex]

[tex]x^{2} -6x+2x-12=0[/tex]

[tex]x(x-6)+2(x-6)=0[/tex]

[tex](x+2)(x-6)=0[/tex]

[tex]x=-2,6[/tex]

Hope this helps and God bless!

The base of a solid is the region in the first quadrant bounded by the y-axis, the x-axis, the graph of y=ex, and the vertical line x=1. For this solid, each cross section perpendicular to the x-axis is a square. What is the volume of the solid?

Step-by-step explanation:

Answer: Sometimes I dont want to be happy.

Answer:

1. Triangle: B = 47.0° , C = 103.05° , c = 2.53 cm

2. Lake: c = 1105.31 ft

Step-by-step explanation:

Law of Sine Formula:[tex]\frac{sin(A)}{A} = \frac{sin(B)}{B} = \frac{sin(C)}{C}[/tex]

Given: A = 30° , a = 1.3 cm , b = 1.9 cm

[tex]\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9} = \frac{sin(C)}{C}[/tex]

Solving for sin(B). Cross Multiply.

[tex]\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9}\\1.3*sin(B)=1.9*sin(30)\\sin(B)=\frac{1.9*sin(30)}{1.3} \\[/tex]

B = sin^-1( [tex]\frac{1.9*sin(30)}{1.3}[/tex] )

B ≈ 46.9509202

B = 47.0°

Solve for C°

A° + B° + C° = 180°

30° + 46.95° + C° = 180°

C° = 180° - 30° - 46.95°

C° = 103.05°

Solve for sin(C)

[tex]\frac{sin(30)}{1.3} = \frac{sin(103.05)}{C}\\[/tex]

Cross Multiply

[tex]C*sin(30)=1.3*sin(103.05)\\C=\frac{1.3*sin(103.05)}{sin(30)}[/tex]

C ≈ 2.532850806

C = 2.53 cm

Law of Cosine Formula: [tex]c^2=a^2+b^2-2*a*b*cos(C)[/tex]

Given: a = 850 ft , b = 960 ft ,  C=75°

Solve for c.

[tex]c^2=a^2+b^2-2*a*b*cos(C)\\c^2=(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\\\c=\sqrt{(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\} \\[/tex]

c ≈ 1105.308698

c = 1105.31 ft

Use logarithms to solve for a.

[tex]3^a = 2 \implies \log_3(3^a) = a\log_3(3) = \log_3(2) \implies a = \log_3(2)[/tex]

Similarly, for b and x.

[tex]3^b = 5 \implies b = \log_3(5)[/tex]

[tex]3^x = 150 \implies x = \log_3(150)[/tex]

Factorize 150:

150 = 2 • 3 • 5²

Then we can expand log₃(150) using the product-to-sum and exponent property,

[tex]\log_3(150) = \log_3(2\times3\times5^2) = \log_3(2) + \log_3(3) + \log_3(5^2)[/tex]

[tex]\implies \log_3(15) = \log_3(2) + 1 + 2 \log_3(5) \iff \boxed{x = 1 + a + 2b}[/tex]

Answer:

  30 mL

Step-by-step explanation:

You are being asked to solve the given equation for the value of x.

__

  0.10x +0.15(50 -x) = 0.12(50) . . . . given

  -0.05x = -0.03(50) . . . . . subtract 0.15(50), combine terms

  x = 30 . . . . . . . . . . . divide by -0.05

Bruce should use 30 mL of the 10% alcohol solution.

Substitute [tex]x\mapsto\sqrt{1-x^2}[/tex], which transforms the integral to

[tex]\displaystyle \int_0^1 \ln^{2k} \left(\frac{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}\right) \, dx = \int_0^1 \ln^{2k}\left(\frac{\ln\left(\frac{1-x}{\sqrt{1-x^2}}\right)}{\ln\left(\frac{1+x}{\sqrt{1-x^2}}\right)}\right) \frac{x}{\sqrt{1-x^2}} \, dx[/tex]

and factoring [tex]\sqrt{1-x^2}=\sqrt{(1-x)(1+x)}[/tex] reduces this to

[tex]\displaystyle = \int_0^1 \ln^{2k}\left(\frac{\ln\left(\sqrt{\frac{1-x}{1+x}}\right)}{\ln\left(\sqrt{\frac{1+x}{1-x}}\right)}\right) \frac x{\sqrt{1-x^2}} \, dx[/tex]

The inner logarithms differ only by a sign, so that

[tex]\displaystyle = \int_0^1 \ln^{2k}(-1) \frac x{\sqrt{1-x^2}} \, dx[/tex]

Using the principal branch of the complex logarithm, we have

[tex]\ln(-1) = \ln|-1| + i\arg(-1) = i\pi[/tex]

and hence

[tex]\displaystyle \int_0^1 \ln^{2k} \left(\frac{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}{\ln\left(\frac{1-\sqrt{1-x^2}}x\right)}\right) \, dx = (i\pi)^{2k} \underbrace{\int_0^1 \frac x{\sqrt{1-x^2}} \, dx}_{=1} = \boxed{(-\pi^2)^k}[/tex]

where I assume k is an integer.

Answer:

$77

Step-by-step explanation:

The answer is $77 because first you need to find how much money was discounted by doing 70-49 to get 21. Then you need to find how much percent 21 is of 70 by doing 21/70, then you would get 0.3 which is 30% since you have to multiply it by 100. This means that there is a 30% discount. Then you would do 0.3*110=33. This means that the 30% discount takes away $33. So 110-33=77. The answer is $77.

Answer:

3/4_2/3 find the LCM= 1/12