Plot the point whose polar coordinates are given. Then find two other pairs of polar coordinates of this point, one with r > 0, and one with r < 0.
(a) (2, 5pi/6)
(b) (1, -2pi/3)
(c) (-1, 5pi/4)

Answer:

The other pairs are:

[tex](a)\ (2, \frac{5\pi}{6}) \to[/tex]  [tex](2, \frac{17\pi}{6})[/tex] and [tex](-2, \frac{23\pi}{6})[/tex]

[tex](b)\ (1, -\frac{2\pi}{3}) \to[/tex] [tex](1, \frac{4\pi}{3})[/tex] and [tex](-1, \frac{7\pi}{3})[/tex]

[tex](c)\ (-1, \frac{5\pi}{4}) \to[/tex] [tex](-1, \frac{3\pi}{4} )[/tex] and [tex](1, \frac{7\pi}{4})[/tex]

See attachment for plots

Step-by-step explanation:

Given

[tex](a)\ (2, \frac{5\pi}{6})[/tex]

[tex](b)\ (1, -\frac{2\pi}{3})[/tex]

[tex](c)\ (-1, \frac{5\pi}{4})[/tex]

Solving (a): Plot a, b and c

See attachment for plots

Solving (b): Find other pairs for [tex]r > 0[/tex] and [tex]r < 0[/tex]

The general rule is that:

The other points can be derived using

[tex](r, \theta) = (r, \theta + 2n\pi)[/tex]

and

[tex](r, \theta) = (-r, \theta + (2n + 1)\pi)[/tex]

Let [tex]n =1[/tex] ---- You can assume any value of n

So, we have:

[tex](r, \theta) = (r, \theta + 2n\pi)[/tex]

[tex](r, \theta) = (r, \theta + 2*1*\pi)[/tex]

[tex](r, \theta) = (r, \theta + 2\pi)[/tex]

[tex](r, \theta) = (-r, \theta + (2n + 1)\pi)[/tex]

[tex](r, \theta) = (-r, \theta + (2*1 + 1)\pi)[/tex]

[tex](r, \theta) = (-r, \theta + (2 + 1)\pi)[/tex]

[tex](r, \theta) = (-r, \theta + 3\pi)[/tex]

[tex](a)\ (2, \frac{5\pi}{6})[/tex]

[tex]r = 2\ \ \ \ \theta = \frac{5\pi}{6}[/tex]      

So, the pairs are:

[tex](r, \theta) = (r, \theta + 2\pi)[/tex]

[tex](2, \frac{5\pi}{6}) = (2, \frac{5\pi}{6} + 2\pi)[/tex]

Take LCM

[tex](2, \frac{5\pi}{6}) = (2, \frac{5\pi+12\pi}{6})[/tex]

[tex](2, \frac{5\pi}{6}) = (2, \frac{17\pi}{6})[/tex]

And

[tex](r, \theta) = (-r, \theta + 3\pi)[/tex]

[tex](2, \frac{5\pi}{6}) = (-2, \frac{5\pi}{6} + 3\pi)[/tex]

Take LCM

[tex](2, \frac{5\pi}{6}) = (-2, \frac{5\pi+18\pi}{6})[/tex]

[tex](2, \frac{5\pi}{6}) = (-2, \frac{23\pi}{6})[/tex]

The other pairs are:

[tex](2, \frac{17\pi}{6})[/tex] and [tex](-2, \frac{23\pi}{6})[/tex]

[tex](b)\ (1, -\frac{2\pi}{3})[/tex]

[tex]r = 1\ \ \ \theta = -\frac{2\pi}{3}[/tex]      

So, the pairs are:

[tex](r, \theta) = (r, \theta + 2\pi)[/tex]

[tex](1, -\frac{2\pi}{3}) = (1, -\frac{2\pi}{3} + 2\pi)[/tex]

Take LCM

[tex](1, -\frac{2\pi}{3}) = (1, \frac{-2\pi+6\pi}{3})[/tex]

[tex](1, -\frac{2\pi}{3}) = (1, \frac{4\pi}{3})[/tex]

And

[tex](r, \theta) = (-r, \theta + 3\pi)[/tex]

[tex](1, -\frac{2\pi}{3}) = (-1, -\frac{2\pi}{3} + 3\pi)[/tex]

Take LCM

[tex](1, -\frac{2\pi}{3}) = (-1, \frac{-2\pi+9\pi}{3})[/tex]

[tex](1, -\frac{2\pi}{3}) = (-1, \frac{7\pi}{3})[/tex]

The other pairs are:

[tex](1, \frac{4\pi}{3})[/tex] and [tex](-1, \frac{7\pi}{3})[/tex]

[tex](c)\ (-1, \frac{5\pi}{4})[/tex]

[tex]r = -1 \ \ \ \ \theta = \frac{-5\pi}{4}[/tex]

So, the pairs are

[tex](r, \theta) = (r, \theta + 2\pi)[/tex]

[tex](-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi}{4} + 2\pi)[/tex]

Take LCM

[tex](-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi+8\pi}{4} )[/tex]

[tex](-1, \frac{-5\pi}{4}) = (-1, \frac{3\pi}{4} )[/tex]

And

[tex](r, \theta) = (-r, \theta + 3\pi)[/tex]

[tex](-1, \frac{-5\pi}{4}) = (-(-1), \frac{-5\pi}{4}+ 3\pi)[/tex]

Take LCM

[tex](-1, \frac{-5\pi}{4}) = (1, \frac{-5\pi+12\pi}{4})[/tex]

[tex](-1, \frac{-5\pi}{4}) = (1, \frac{7\pi}{4})[/tex]

So, the other pairs are:

[tex](-1, \frac{3\pi}{4} )[/tex] and [tex](1, \frac{7\pi}{4})[/tex]

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