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20-27 show ur work

Answer:

tanC

Step-by-step explanation:

tanC = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{6}{10}[/tex]

Answer:

E) quadrilateral

Step-by-step explanation:

Quadrilateral LMNO has 4 sides, but only two seem to parallel each other and that is why it is only a quadrilateral.

Requirements for each shape:

Square = 4 equal sides, 2 pairs of parallel ones, all right angles

Rectangle = 2 sets of equal and parallel sides, all right angles

Rhombus = 4 equal sides, 2 pairs of parallel ones

Parallelogram = 2 pairs of parallel sides

Quadrilateral = 4 sided polygon with 4 corners

Hope this helps!

The volume of the cylindrical tank is the amount of space in it

The volume of the larger tank is 800 gallons

The volume of the small tank is given as:

v = 100

The volume of a cylinder is:

v = πr²h

For the bigger tank, we have:

V = πR²H

The dimensions are twice the smaller tank. This gives

V = π(2r)² * (2h)

Expand

V = 8πr²h

Substitute v = πr²h in V = 8πr²h

V = 8v

Substitute v = 100 in V = 8v

V = 8 * 100

V = 800

Hence, the volume of the larger tank is 800 gallons

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The new volume after the edges of the box are increased by 1 unit = 266,491 units^3

The volume of a rectangle= l×w×h

The surface area of the box = (side)^2

The sum of the edges of the box = 216 units

If area of the box x^² = 2002

X = √2002

X = 44.7units

But the sum of the edges = 216 units

44.7 + 44.7 + y = 216

make y the subject of formula,

y = 216 - 89.4

y= 126.6 units

Therefore the length, width and height of the rectangular box = 44.7, 44.7 and 126.6 units respectively.

When additional 1 unit is added to each edge it becomes,

44.7 +1 =45.7,

44.7 + 1 = 45.7and

126.6 + 1 = 127.6 units.

Therefore the new volume = 45.7×45.7 × 127.6 = 266,491 units^3.

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Question:

Please tell me what the answer is

Answer:

The people with the membership take seven classes

The people without the membership take five classes

Step-by-step explanation:

As it says in the picture:

"A local gym has two different fees for their yoga classes. Members of the gym are charged a one-time membership fee of $25 and pay $5 per yoga class. Nonmembers do not pay a membership fee, but they pay $7 per class. How many yoga classes do nonmembers and members have to attend for their cost to be the same?"

First, what you would do is look for your key words in the sentence. What you'd take from the sentence is everything that I highlighted.

If the membership fee is $25 and yoga classes are $5 and nonmembers cost for yoga classes is $7 then you have your problem right there.

Next, what you would look for is your Greatest common divisor. (GCD) The GCD of 5 and 7 is 5 of course. So now what you would do is find out how many times 5 and 7 goes into five.

7 x 5 = 35

5 x 5 = 25

Now what you do is ask yourself the question, "How many times does the nonmembers and members have to go to class to have the same amount of money spent?"

Now I will answer this question for you.

five dollars for members.

seven dollars for nonmembers.

Your answer is: 7 x 5 (30)

Answer:

2. 3520 yds

3. 15840 ft

8. 27 in

Step-by-step explanation:

2. There are 1760 yards in a mile. Since we're looking for the number of yards in 2 miles, we just have to multiply this number by 2.

2 · 1760 = 3520 yds

5. There are 5280 feet in a mile. Since we're looking for the number of feet in 3 miles, we just have to multiply this number by 3.

3 · 5280 = 15840 ft

8. There are 12 inches in a foot. This means that 2 feet equals 24 inches [2 · 12 = 24]. Since we have to find the number of inches in 2 feet and 3 inches, we just have to add 3 to 24. This equals 27 inches.

Answer:

1.900 miles / 2 = 950 miles per day.

2700 miles / 3 = 900 miles per day.

Therefore, the other family travelled faster.

The rate of the change of the volume of the pile, in cubic feet per hour, when the circumference of the base is 8x feet, for this case, is 40x²/π³ cubic ft/ hour.

Suppose that a function is defined as;

[tex]y = f(x)[/tex]

Then, suppose that we want to know the instantaneous rate of the change of the function with respect to the change in x, then its instantaneous rate is given as:

[tex]\dfrac{dy}{dx} = \dfrac{d(f(x))}{dx}[/tex]

If a variable z depends on the variable y, which itself depends on the variable x, then we have:

[tex]\dfrac{dz}{dx} = \dfrac{dz}{dy} \times \dfrac{dy}{dx}[/tex]

(assuming all these derivatives exist).

For this case, we're given that:

[tex]V = \dfrac{r^3}{3}[/tex]    (in cubic ft)

Assuming the cross section being circular, expressing radius 'r' in terms of circumference, we get:
[tex]C = 2\pi r\\\\r = \dfrac{C}{2\pi}\\\\V = r^3/3\\\\V = \dfrac{C^3}{24\pi^2} \: \rm ft^3[/tex]

It is given that rate of change of circumference with respect to time is 5.

Thus, symbolically, we get:
[tex]\dfrac{dC}{dt} = 5[/tex]

Finding rate of change of volume with respect to time:

[tex]\dfrac{dV}{dt} = \dfrac{d\left (\dfrac{C^3}{24\pi^2}\right) }{dC} \times \dfrac{dC}{dt} = \dfrac{3C^2}{24\pi^3} \dfrac{dC}{dt} = \dfrac{5C^2}{8\pi ^3} \: \rm ft^3/hour[/tex]

(using chain rule of differenciation).

At C = 8x ft, we get:
[tex]\dfrac{dV}{dt} = \dfrac{5C^2}{8\pi ^3} \: \text{ft}^3\text{/hour}\\\\\dfrac{dV}{dt} |_{C = 8x} = \dfrac{5(8x)^2}{8 \pi^3} = \dfrac{40x^2}{\pi^3} \: \rm ft^3/hour[/tex]

Thus, the rate of the change of the volume of the pile, in cubic feet per hour, when the circumference of the base is 8x feet, for this case, is 40x²/π³ cubic ft/ hour.

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Answer:

B

Step-by-step explanation:

it goes 8 6 3 2

none of the other ones go this order

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

n=5, -5

Answer:

[tex]n=\frac{3i\sqrt{22}-2}{-8}[/tex]

Step-by-step explanation:

[tex](2-8n)^2=-198[/tex]

[tex]\sqrt{(2-8n)^2} =\sqrt{-198}[/tex]

[tex]2-8n=i\sqrt{198}[/tex]

[tex]2-8n=3i\sqrt{22}[/tex]

[tex]-8n=3i\sqrt{22} -2[/tex]

[tex]n=\frac{3i\sqrt{22}-2}{-8}[/tex]

I hope this helps!

The correct statenments are:

The circumference of a circle is the sum of the external part of the circle.

The formula for calculating the area of a circle is expressed as:

A = πr²

The formula for calculating the circumference is given as:

C = 2πr

r is the radius of the circle

If radius is 2 units

A = π(2)² = 4π

C= 2π(2) = 4π

The numerical values of the area and circumference are equal when r = 2.

If radius is 1 units  < 2 units

A = π(1)² = π

C= 2π(1) = 2π

The numerical value of the area is less than the numerical value of the circumference when r less-than 2.

If radius is 3 units  > 2 units

A = π(3)² = 9π

C= 2π(3) = 6π

The numerical value of the area is less than the numerical value of the circumference when r greater-than 2.

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Answer:

ABD

Step-by-step explanation:

Answer:

x = 146°

Step-by-step explanation:

The 34° angle and the angle marked x are same side interior angles. They are supplementary which means the angles should add up to 180°

34 + x = 180

Subtract 34.

x = 146

Answer:

-3 x 10

Step-by-step explanation:

Because there are 10 questions, all wrong taking away 3 points

Answer:

____________________________________

[tex] \large{ \tt{ \star \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \boxed{ \tt{♡ \: VOLUME \: = l \: \times b \: \times h}}}[/tex]

[tex] \longrightarrow \: 4 \frac{1}{3} \times 3 \frac{1}{3} \times 4[/tex]

[tex] \longrightarrow \: \frac{13}{3} \times \frac{10}{3} \times 4[/tex]

[tex] \longrightarrow \: \frac{540}{9} [/tex]

[tex] \longrightarrow \tt \: 57 \frac{7}{9} \: ft ^{3} [/tex]

- HappY LearninG ^_________^

Answer: 57 7/9 is the answer

Step-by-step explanation: 4 times 4 1/3 times 3 1/3 is 57 7/9

The theoretical probability that Chandra will be chosen as one of the science fair participants is 0.8 or 80%.

Theoretical probability of an event is the ratio of number of favourable outcome to the total expected number of outcome of that event.

Five students, Adriana, Ben, Chandra, Diana, and Ernesto, would each like one of the four spots at the regional science fair.

Their names are placed in a hat, and four names are chosen at random to decide who attends the fair.

The total number of ways 4 names can be taken out from 5 names is,

[tex]^5C_4[/tex].

Here one spot needs to be fixed for Chandra. Now the total number of outcome remain 4 and favourable outcome remain 3.

Thus, the number of ways 4 names can be taken out such that it contains the name Chandra is

[tex]^4C_3[/tex].

The theoretical probability that Chandra will be chosen as one of the science fair participants is,

[tex]P=\dfrac{^4C3}{^5C4}\\P=\dfrac{4}{5}\\P=0.8\\P=80\%[/tex]

Thus, the theoretical probability that Chandra will be chosen as one of the science fair participants is 0.8 or 80%.

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Answer:

[C] 4x - 19 < 318

Step-by-step explanation:

For [C] I think you meant: [C] 4x - 19 < 318

Since, x = -8

then we can plug it in to each answer choice to find the answer:

[A] -3x - 2 = 24

⇒ -3(-8) - 2 = 24

-3(-8) = 24

24 -2 = 22 not 24

False.

[B]  12 + 2x > 9

⇒  12 + 2(-8) > 9

 12 -16 > 9

-4 > 9

False.

[C] 4x -19 < 318

⇒ 4(-8) -19= 318

-51 < 318

True.

[D] 17 + x>10​

⇒ 17 + (-8) >10​

-25 > 10

False.

Hence, the answer is [C] 4x - 19 < 318

Kavinsky

The answer of this question is √17 units

Answer:

Ok, but what is the question or data?

Answer:

2 units.

Step-by-step explanation:

8 - 6 = 2 units.

There is no need to use the distance formula as both points are on the y-axis. Its just a simple subtraction.

[tex] \huge \mathfrak \red{hey \: there}[/tex]

[tex]\mathfrak \orange{answer}[/tex]

[tex] \mathfrak \orange{ explanation}[/tex]

[tex] x_1[/tex] = 0 [tex] x_2[/tex] = 0

[tex] y_1[/tex] = 6 [tex] y_2[/tex] = 8

[tex] \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } // \sqrt{ {(0 - 0)}^{2} + {(8 - 6)}^{2} } //[tex] \sqrt{ {(0)}^{2} + {(2)}^{2} } // [tex] \sqrt{ {(0 + 4} [/tex]

Step-by-step explanation:

khan academy

The formulas that give the standard deviation will be given below.

[tex]\sigma = \sqrt{\dfrac{(67 - 70) ^2 + (67 - 70) ^2 + ( 68 - 70) ^2 + ....+ (73 - 70) ^2}{12}}[/tex]

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The mean is the straightforward meaning of the normal of a lot of numbers. In measurements, one of the markers of focal propensity is the mean. The normal is alluded to as the number-crunching mean. It's the proportion of the number of genuine perceptions to the absolute number of perceptions.

[tex]\rm \sigma = \sqrt{\dfrac{\Sigma (x_i - \mu)^2}{n}}[/tex]

Juana weighed a sample of 12 jumbo eggs. Here are their weights (in grams): 67, 67, 68, 69, 69, 70, 71, 71, 71, 72, 72, 73

The mean is μ =70 grams.

Then the standard deviation is given as,

[tex]\sigma = \sqrt{\dfrac{(67 - 70) ^2 + (67 - 70) ^2 + ( 68 - 70) ^2 + ....+ (73 - 70) ^2}{12}}[/tex]

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288 ft

first off you will want to find the area of the garden, which is 1120 ft squared, we’ll come back to this

Since the path is 4 ft wide and surrounding the garden, its area is 28+4 by 40+4, minus the area of the garden.

32*44 = 1408 - 1120 = 288 ft

you may or may not need to write it as feet squared

To find f(-8) and f(6), all that we need to do is plug in each of the numbers for x.

f(-8) = -8 - 1 = -9

f(-8) = -9

f(6) = 6 - 1 = 5

f(6) = 5

Hope this helps!

If f(-x) = x - 1, then f(x) = - x - 1. So

f(-8) = 8 - 1 = 7

and

f(6) = - 6 - 1 = -7

Answer:

10      if the other it is 20

Step-by-step explanation:

she can get 10 foil balloons that cost $3 becasue 30 / 3 = 10 out of 30  if she usees all the money on foil balloons

she can get 20 plain balloons cost that cost $1.50 because 30 / 1.50 = 20 if she usees all the money on plain balloons

Answer:

Mean : 31.6
Mode : 46
Median : 32
Range: 34

Step-by-step explanation:

Answer: Mean 31.57 Mode 46 Median 32

Range34

Step-by-step explanation: Mean is average. Add all the numbers and divide by 7

Mode is highest occurring

Median is middle number

Range is highest- lowest 46 - 34

Step-by-step explanation:

I4(-3)+5| +8(-3)

|-12+5| -24

7-24 = -17

60 bottles required.

For hemispherical bowl:

[tex]\sf volume: \dfrac{2}{3} \pi r^3[/tex]                         [diameter: 30 cm, radius: 15 cm]

[tex]\rightarrow \sf volume: \dfrac{2}{3} \pi (15)^3[/tex]

[tex]\rightarrow \sf volume: 2250\pi \ cm^3[/tex]

For each cylindrical bottles:

[tex]\sf volume: \pi r^2h[/tex]                          ["r" is 2.5 cm, "h" is 6 cm]

[tex]\rightarrow \sf volume: \pi (2.5)^2(6)[/tex]

[tex]\rightarrow \sf volume: 37.5 \pi \ cm^3[/tex]

So number of required bottles: