Question 8, 1.2.35-PS
Part 1 of 5
iew an example
HW Score: 44.44%, 4
O Points: 0 of 1
- Scatterplots and Graphs
K
If a ball is thrown into the air at 96 feet per second from the top of a 109-foot-tall building, its height can be modeled by the function S=109+961-162, where S is in feet and t is in seconds.
Complete parts a through e below.
a. Graph this function for t representing 0 to 8 seconds and S representing 0 to 300 feet. Choose the correct graph below.

Question 8, 1.2.35-PSPart 1 Of 5iew An ExampleHW Score: 44.44%, 4O Points: 0 Of 1- Scatterplots And GraphsKIf

Answers

Answer 1

The quadratic function in this problem is represented by Graph C.

What is the quadratic function for this problem?

The quadratic function for the projectile height after t seconds is given by:

S(t) = 109 + 96t - 16t²

From this, we have that:

Due to the negative coefficient of t², it is a concave down parabola, which remoces option d.The initial height is of 109 feet, which removes option b.The initial velocity is positive, which means that the parabola has increasing height for a while before decaying, which removes option A.

Thus, the quadratic function in this problem is represented by Graph C.

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Related Questions

A5.1 m long ladder is leaning against a
wall. The wall stands perpendicular to the
ground. The base of the ladder is 1.8 m
away from the wall.
Work out the size of the acute angle that
the ladder makes with the ground.
Give your answer in degrees to 1 d.p.

Answers

The acute angle the ladder makes with the ground is 69.3 degrees.

How to find the acute angles formed from the right triangle ?

The ladder is 5.1 m and it is leaning against a wall.

The wall is perpendicular to the ground.

This means the ground forms 90 degrees with the wall.

This situation forms a right angle triangle.

Therefore, the acute angle the ladder forms with the ground can be found as follows:

Using trigonometric ratios,

cos ∅ = adjacent / hypotenuse

where

∅ = acute angle

Therefore,

adjacent side = 1.8 m

hypotenuse side = 5.1 m

Hence,

cos ∅ = 1.8 / 5.1

∅ = cos⁻¹ 0.35294117647

∅ = 69.3326835065

∅ = 69.3°

Therefore, the acute angle the ladder makes with the ground is 69.3 degrees.

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NEED OF IMMEDIATE HELP

Answers

It is biased because there is over 100 answers there on the graph..If he asked 100 workers then there should only be 100 not 150…

Answer:

There are no sampling errors, as all numbers add up to 100, however, there is a bias, as the highest number is 52 for movies, and the person who conducted the survey was a movie theater manager to his own customers.

the weight of an organ in adult male has a bell shaped distribution with a mean of 300 grams and a standard deviation of 25 grams. Use the empirical rule to determine the following:
a.) About 95% of organs will be between what weights?
b.) What percentage of organs weighs between 225 grams and 375 grams?
c.) What percentage of organs weighs less than 225 grams or more than 275 grams?
d.) what percentage of organs weighs between 275 grams and 275 grams?

Answers

Using the Empirical Rule, it is found that:

a) About 95% of the organs will be between 250 and 350 grams.

b) 99.7% of organs weighs between 225 grams and 375 grams.

c) 84.15% of organs weighs less than 225 grams or more than 275 grams.

d) 0% of organs weight exactly 275 grams.

What does the Empirical Rule state?

It states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.Approximately 95% of the measures are within 2 standard deviations of  the mean.Approximately 99.7% of the measures are within 3 standard deviations of the mean.

95% of the weights are within 2 standard deviations of the mean, hence:

300 - 2 x 25 = 250 grams.300 + 2 x 25 = 350 grams.

About 95% of the organs will be between 250 and 350 grams.

For item b, the amounts are within 3 standard deviations of the mean, hence:

99.7% of organs weighs between 225 grams and 375 grams.

For item c, considering the symmetry of the normal distribution, we have that:

0.5 x 0.003 = 0.15% weigh less than 225 grams.0.5 x 68% + 50% = 84% weight more than 275 grams.

Hence:

84.15% of organs weighs less than 225 grams or more than 275 grams.

For item d, considering that the normal distribution is continuous, the percentage of an exact value is 0, hence:

0% of organs weight exactly 275 grams.

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Chloe reads 7 pages of a mystery book in 9 minutes. What is her average reading rate in pages per
minute?

Answers

Answer:

1.25

Step-by-step explanation:

you have to take the 9 pages and divide by 7 and then divide that by 60 and u get 1.25

HELPPPOOOOMEEEEEEW PLEASE

Answers

Answer: 124 degrees

Step-by-step explanation:

JKL=YKL+JKY

10x+14=6x-6+64

10x+14=6x+58

4x+14=58

4x=44

x=11

JKL=10x+14

JKL=10(11)+14

JKL=110+14

JKL=124 degrees

please help with this one! ASAP

Answers

Answer: 699 m^2

Step-by-step explanation:

A manufacturer estimates his marginal cost and revenue at various levels of output to be the following. If fixed cost is 500, estimate, using the Simpsons rule, the total profit or loss of producing 100 units is Blank 1. Fill in the blank, read surrounding text.
GHC


q (units)

0

20

40

60

80

100

120

MC

260

250

240

200

240

250

270

MR

410

350

300

250

270

250

300

Answers

If the fixed cost is GHC500, the total profit or loss of producing 100 units is GHC 0.

What is the profit when MC = MR?

When the marginal cost (MC) equals the marginal revenue (MR), the company breaks even, and from that point, profit maximization starts.

When MR is more than MC, the tendency is for the firm to produce more and earn more profit, and when MR is less than MC, the firm produces fewer as it incurs losses.

The profit maximization level occurs where the MR and the MC are equal.

Data and Calculations:

Total revenue = fixed cost + variable cost (MR x Units)

Total revenue = 500 + (100 x 250)

Total revenue = 500 + 25,000

Total revenue = GHC 25,500

Total profit or loss at 100 units = GHC0 (GHC25,500 - GHC25,500)

GHC

q (units)     0     20     40     60       80     100      120

MC        260  250   240   200    240     250     270

MR         410  350   300   250    270     250     300

Thus, if the fixed cost is GHC500, the total profit or loss of producing 100 units is GHC 0.

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A cube-shaped box has a side length of 6n³ centimeters. Amelia has several cube-shaped blocks with a side length of 2n centimeters that she needs to store in the box. what is the volume of one block? what is the volume of the box​

Answers

The volume of blocks is 8n³ cm³ and volume of box is 216 n⁹ cm³.

According to the question we have been given that the

  side length of the cube shaped box = 6n³ cm

  side length of the cube shaped blocks = 2n cm

We need to find the volume of the box and the blocks.

The formula for the volume of cube is

                      V = (s)³ cubic units.

     where, s = side length of the cube

Now putting the required values in the above formula we get

  volume of box = (6n³)³ cm³

                         = 216 n⁹ cm³  

 volume of the blocks = (2n)³ cm³

                                   = 8n³ cm³

Hence the volume of blocks is 8n³ cm³ and volume of box is

216 n⁹ cm³.

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At the arcade, Ryan, Sara, and Tim played video racing games, pinball, and air hockey. Ryan spent $6 for 6 racing games, 2 pinball games, and 1 game of air hockey. Sara spent $12 for 3 racing games, 4 pinball games, and 5 games of air hockey. Tim spent $12.25 for 2 racing games, 7 pinball games, and 4 games of air hockey. How much did each of the games cost?

Answers

Answer: Racing $.50

Pinball $.75

Air Hockey $1.50

7 grade

1. Andrea walked 1/2 miles in 1/3 of an hour at a constant speed. What was that speed?

A. 1 miles per hour

B.1.25 miles per hour

C.1.5 miles per hour

D.2.5 miles per hour

Answers

Answer:

C

Step-by-step explanation:

0.5 of a mile in 20 minutes

60/20=3

0.5*3=1.5

Correct answer is C

At the movie theatre, child admission is 5.50 and adult admission is 9.20. On Monday, three times as many adult tickets as child tickets were sold, for a total sales of 662.00 . How many child tickets were sold that day?

Answers

Answer is 20 child tickets

Step by step

Let child tickets be “C”
Let adult tickets be “A”

We know
Adult tickets = 3 Child tickets
Equation 1
A = 3C

We know C = 5.50 and A = 9.20 and the total is 662

Equation 2
5.50C + 9.20A = 662

Substitute equation 1 value of A into the equation and solve

5.50C + (9.20)(3C) = 662

5.50C + 27.60C = 662

33.10C = 662

Divide both sides by 33.10 to solve for C

33.10 /33.10 C = 662

C = 20

20 child tickets sold

We can solve for adult tickets and check our work

Equation 1
A = 3C
Substitute C value into equation

A = (3)(20)

Adult tickets = 60

We know C = 5.50 and A = 9.20 and the total is 662

5.50C + 9.20A = 662

(5.50)(20) + (9.20)(60) = 662

110 + 552 = 662

662 = 662

We are correct they equal
Problem solved!!



Evaluate-nx + x when x = 2.

Answers

Answer:

-2n + 2

Step-by-step explanation:

They give you the X value which is 2

All you do is substitute

-2n + 2

Hope this helped

If Cindy shoots a ball at a basket 40 times
and scores 15 times, what is the
experimental probability of Cindy scoring?

Answers

Experimental probability of Cindy scoring=0.375

Probability:

Probability is always a number between 0 and 1, where 0 means an event is impossible and 1 means an event is certain.

The probabilities in a probability model must sum to 1.

When the outcomes of an experiment are all equally likely, we can find the probability of an event by dividing the number of outcomes in the event by the total number of outcomes in the sample space for the experiment.

To find the probability of the union of two events, we add the probabilities of the two events and subtract the probability that both events occur simultaneously.

To find the probability of the union of two mutually exclusive events, we add the probabilities of each of the events.

The probability of the complement of an event is the difference between 1 and the probability that the event occurs.

In some probability problems, we need to use permutations and combinations to find the number of elements in events and sample spaces.

Formula :

probability of an event with equally likely outcomes : [tex]\frac{n( experimental-event )}{n(total no. of event )}[/tex]

Given :

Total no. of event =Cindy shoots a ball at a basket 40 times

experimental event = 15 times

[tex]P(E)= \frac{15}{40} \\P(E)=\frac{3}{8} \\P(E)= 0.375\\[/tex]

experimental probability of Cindy scoring=0.375

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Which of the following expressions is equivalent to 9x-27

Answers

Answer:

3

Step-by-step explanation:

9x-27=0

+27. +27

9x=27

x=3

Eli runs a distance of 3 miles in 2/5 of an hour. jess runs a distance of 4/5 mile in 1/10 of an hour. who had the faster speed

Answers

Jess had a faster speed of 8 miles/hour

Given:

3 miles in 2/5 hour

4/5 miles in 1/10 hour

To find the quotient, we must switch to the inverse approach,

where 2/5 becomes 5/2 and 1/10 becomes 10/1.

For Eli:

A distance of 3 miles is covered in 2/5 of an hour.

3 miles equals 2/5*1

3 miles equals 2/5 hour

The inverse amount is multiplied as

3*5/2 miles = 1 hour.

7.5 miles

Eli moves at a 7.5 mph speed.

For Jess:

1/10 of a mile is covered in 4/5miles.

1/10 * 1 hour times 4/5 miles

1/10 hour equals 4/5 miles.

The inverse number is multiplied as follows: 4/5 * 10/1 = 1 hour.

40 miles at a speed of 5 miles per hour.

1 hour Equals 8 miles

Jess's speed is 8 miles per hour.

Hence, Jess had a faster speed of 8 miles per hour

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Leah is training to run half marathon Her goal For training is to run 20 miles a week. she ran 3 1/2 Miles on Monday 4. 3/4 miles on Tuesday 5 miles on Wednesday And 4 miles On Thursday. how Many Miles will She Need to run On Friday In Order to meet her goal?

Answers

The number of miles she should run on Friday is 2 3/4 miles.

Given that, Leah is training to run a half marathon her goal training is to run 20 miles a week. she ran 3 1/2 miles on Monday 4 3/4 miles on Tuesday 5 miles on Wednesday and 4 miles on Thursday.

We need to find how many miles will she need to run on Friday in order to meet her goal.

How to add mixed fractions?

Follow these steps to add mixed fractions:

Add the whole numbers together. Find the lowest common denominator (LCD) of both fractions. The LCD is the lowest number that is evenly divisible by both numbers.Convert the fractions to have the LCD as their denominator.Once you have a common denominator, the fractions can be added by simply adding the numerators.

Now, the number of miles she ran together from Monday to Thursday

=3 1/2 + 4 3/4 + 5 + 4 =(3+4+5+4)(1/2 + 3/4)

=16 (2/4 + 3/4)

=16 5/4

=17 1/4

Remaining miles = 20-17 1/4

=20-69/4

=(80-69)/4

=11/4

=2 3/4

Therefore, the number of miles she should run on Friday is 2 3/4 miles.

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Please Help Me! Will be brainlest


E=-7g^4+3g^2h^2-11h^4

F=6g^4-13g^2h^2+8h^4

E+F=

Answers

The addition of the given expression "E = - 7g⁴ + 3g²h² - 11g⁴" and "F = 6g⁴ - 13g²h² + 8h⁴" is "- g⁴ - 10g²h² - 3g⁴"

Exponent

E = - 7g⁴ + 3g²h² - 11g⁴

F = 6g⁴ - 13g²h² + 8h⁴

E + F = (- 7g⁴ + 3g²h² - 11g⁴) + (6g⁴ - 13g²h² + 8h⁴)

= - 7g⁴ + 3g²h² - 11g⁴ + 6g⁴ - 13g²h² + 8h⁴

collect like terms

= -7g⁴ + 6g⁴ + 3g²h² - 13g²h² - 11g⁴ + 8h⁴

evaluate

= - g⁴ - 10g²h² - 3g⁴

Therefore, the addition of the given expression "E = - 7g⁴ + 3g²h² - 11g⁴" and "F = 6g⁴ - 13g²h² + 8h⁴" is "- g⁴ - 10g²h² - 3g⁴"

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Decide what values of the variable cannot possibly be solutions for the equation. Do not solve.

Answers

By inspecting the denominator, the values of x cannot be solutions of the rational equation are x₁ = - 3 and x₂ = 2.  

What values does lead to an indetermination in a rational equation?

A rational equation is an expression of the P(x) / Q(x), where P(x) and Q(x) are the equations of the numerator and the denominator functions. The rational equation becomes undefined for all x-values such that Q(x) = 0. Then, we must look up for all values of x such that:

x² + x - 6 = 0

x² + [3 + (- 2)] · x - 6 = 0

x² - 2 · x + 3 · x - 6 = 0

x · (x - 2) + 3 · (x - 2) = 0

(x + 3) · (x - 2) = 0

x₁ = - 3 ∨ x₂ = 2

The values of x cannot be solutions of the rational equation are x₁ = - 3 and x₂ = 2.  

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7th- grade question
7. Billy cut the grass for 3/5 of an hour on Monday and 3/10 of an hour on
Tuesday. What fraction of an hour did he spend cutting grass for the two
days?
A. 1/5
B. 2/5
C. 5/10
D. 9/10

Answers

Answer:

The answer is c because if you multiply 3/5 and 3/10 by doing butterfligt

Cyndee wants to invest $50,000. Her financial planner advises her to invest in three types of accounts: one paying 3%, one
paying 5%, and one paying 6% simple interest per year. Cyndee wants to put twice as much in the lowest-yielding, least-risky
account as in the highest-yielding account. How much should she invest in each account to achieve a total annual return of
$2120?

Answers

Answer:

$25,333.33 at 3%$12000 at 5%$12,666.67 at 6%

Step-by-step explanation:

Cyndee invests $50,000 in accounts earning 3%, 5%, and 6% annually, for a total annual return of $2120. She puts twice as much in the first account as in the third. You want to know the amount invested in each account.

Setup

Let x represent the amount invested in the third account. Then 2x is the amount invested in the first account, and (50000 -3x) is the amount invested in the second account. The total return is ...

  0.03(2x) +0.05(50000 -3x) +0.06(x) = 2120

Solution

Simplifying the equation gives ...

  -0.03x +2500 = 2120

  380 = 0.03x . . . . . . . . . . add 0.03x-2120

  12,666 2/3 = x . . . . . . . divide by 0.03

  2x = 25,333 1/3

  50000 -3x = 12,000

Cyndee should invest 25,333.33 at 3%, $12,000 at 5%, and $12,666.67 at 6%.

center at (2, -2) and twice the area of the circle (x, -7)² + (y, -7)² =7​

Answers

Answer:

[tex](x-2)^2+(y+2)^2=14[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where:

(a, b) is the center of the circle.r is the radius of the circle.

Given equation:

[tex](x-7)^2+(y-7)^2=7[/tex]

Therefore:

center = (7, 7)radius = √7

Area of a circle

[tex]\sf A=\pi r^2[/tex]

where:

r is the radius.

Therefore, the area of a circle with radius √7 is:

[tex]\implies \sf Area=\pi \left(\sqrt{7}\right)^2=7 \pi\:\:square\:units[/tex]

Therefore, a circle with twice the area would be:

[tex]\implies \sf Area = 2 \cdot 7 \pi = 14 \pi \:\: square\:units[/tex]

Therefore, its radius would be:

[tex]\begin{aligned}\implies \sf \pi r^2 & = \sf14 \pi\\\sf r^2 & = \sf 14\\\sf r & = \sf \sqrt{14}\end{aligned}[/tex]

So the equation of a circle with a center at (2, -2) and a radius of √14 is:

[tex]\implies (x-2)^2+(y-(-2))^2=\left(\sqrt{14}\right)^2[/tex]

[tex]\implies (x-2)^2+(y+2)^2=14[/tex]

Simplify the expressions:
−8y³ x 5y8

Answers

When multiplying terms with exponents, the exponents add up. Exponents 3 and 8 wii equal 11.

I hope this helps.

Hi! Your answer is 11. When multiplying terms with exponents, the exponents add up.

Step-by-step explanation:

You want to multiply the terms with the exponents. You should get 3 and 8, add those up and you will get 11.

Hope this helps! Have a good day :)

Multiply.
9/4 ⋅ 14

A. 23/4
B. 28
C. 63/2
D. I don't know.

Answers

Answer:

C. 63/2

Step-by-step explanation:

[tex] \frac{9}{4} \times 14 \\ = \frac{9}{4} \times \frac{14}{1} \\ = \frac{9 \times 7}{2} = \frac{63}{2} \\ please \: if \: found \: helpful \: rate \: brainliest.[/tex]

The answer is 63/2

I got 100% on the test

I hope this helps!

Proof that this answer is correct and not fake

How many different​ 10-letter words​ (real or​ imaginary) can be formed from the following​ letters? E, T, A, R, N, I, T, C, F, R Question content area bottom Part 1 enter your response here ​ten-letter words​ (real or​ imaginary) can be formed with the given letters.

Answers

Answer:

10! or 3628800 words

=============================

Given 10 letters and we are looking for the number of 10-letter words.

This is about the permutation of 10:

[tex]_{10}P_{10} = 10! = 3628800[/tex]

Kiara and Donovon attend different middle schools. They both went to their schools’ winter carnivals. Kiara paid a $5 entrance fee and bought several tickets costing $0.75 each for games and rides. Donovon paid a $7 entrance fee and bought several tickets costing $0.50 each for games and rides. How many tickets, , must Kiara and Donovan each buy in order for the cost of attending their school carnivals to be the same?

Answers

Using linear functions, it is found that they have to buy 8 tickets for the costs to be the same.

What is a linear function?

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

For the functions in this problem, we consider that:

The entrance fee is the intercept.The cost for carnivals(games/rides) is the slope.

Hence the cost functions for Kiara and Donovon are given, respectively, by:

K(x) = 5 + 0.75x.D(x) = 7 + 0.5x.

The costs will be the same when:

K(x) = D(x)

5 + 0.75x = 7 + 0.5x.

0.25x = 2

x = 2/0.25

x = 8.

They have to buy 8 tickets for the costs to be the same.

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Add (4) and (−15) if right i will give brainliest

−11

−19

19

11

Answers

-11 is the answer to this question

Answer:-11

Step-by-step explanation:

-15 + 4 = -11

Answer this question please

Answers

'less than' corresponds to the < symbol, so the inequality is x<1.2. However, the weight cannot be negative or zero, so the inequality is 0<x<1.2.

In interval notation, this is (0, 1.2).

4x = y + 3
8x - 3= 2y
Graph the system

Answers

the lines are parellel

The sum of a daughter and mother's age is 55. The age of the daughter is the
mother's age reversed. Find the age of the daughter if the age of the mother is
greater than 40 years.

Answers

The daughter is 14. And the mother is 41

HELP MEEEEE OUTTTT PLEASEEE

Answers

Hope this helped
check the image below for working

Answer:

other answer is right

Step-by-step explanation:

just answering so they can get brainliest:)

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They have followed me ever since. The magnificent creatures appeared in storybooks I read in the library, paintings I saw in museums, movies I watched in the theater, and the dreams I had in my sleep. By the time I was thirteen, one question consumed me. I wanted to know if dragons ever existed, so I set out on a quest for facts.2As I started my research, I discovered many skeptics. Scientists presented evidence to show why dragons could notand did notexist. They explained that it would be impossible for dragons to fly because they would be too big. They laughed at the idea of dragons breathing fire. They pointed out that no other animal has ever done this. They said that if dragons had lived, someone would have found remains somewhere in the world. No bones about it, there were plenty of logical explanations. It would have been easy for me to accept that the only place dragons ever existed was in the imaginations of those who believed.3I could have given up, but I thought about my grandmother. She always told me that "people who believe that science is the answer to everything are missing out on everything else." With her words in mind, I searched some more. There were many facts that hinted that dragons may not be fictional. I noticed that cultures across the world all described dragons in similar ways. This was odd because they had no way to communicate with each other. I found dragons mentioned in more than just stories. They appeared in old legal papers, in the travel logs of Marco Polo, and in the Bible. I saw that the Chinese calendar uses a different animal each year. Dragons are included along with eleven real animals. I began to believe it was a real possibility that all of these people were talking about a creature that actually existed.4With renewed hope that there was some truth to the legends, I looked for new research. I found that some experts disagreed with popular arguments against dragons. They suggested that a dragon could have four stomachs like a cow. If it created stomach gases like birds, it might create enough to lift itself off the ground. This would give it the ability to fly. If it forced out air when diving toward the earth, it might release gases which could ignite into flame. When the animal died, the stomachs would release strong acids that would dissolve its dead body over time. Biologists backed up these ideas with sketches and models based on known animals. Not everyone agreed with these ideas, but many of the things we accept about dinosaurs and other extinct species started the same way.5I doubt we will ever truly know whether dragons existed. There may always be two sides to the fiery debate. Some will say the stories come from active imaginations. Some will believe with all their hearts that the legendary creatures roamed our ancient world. I don't know for certain which side to believe, but the sound and fury of a night like this makes me smile. It rekindles my childhood dreams and keeps the exciting possibility alive.Which sentence from paragraph 4 makes an explicit statement without offering any implicit suggestions? your class nominates one student to attend student government association meetings on behalf of the class and report back on what was discusseda, direct democracyb, representative democracy Read the paragraph from the section "Shellfish."Lower pH values occur naturally on the West Coast during upwelling events, but recent observations indicate that CO2 originating from human activities is contributing to seasonal aragonite undersaturation. Scientists suspect that low pH may be a factor in the oysters' reproductive failure. More research is needed to disentangle potential acidification effects from other risk factors. Nonetheless, acidification is a potential factor in the current crisis to the multi-million-dollar oyster industry. The potential role of ocean acidification is encouraging new collaborations and accelerated research on ocean acidification and its biological impacts.Which of the following can be inferred from the selection above?AHuman activities are the primary cause of the aragonite undersaturation during upwelling events.BWhile some marine organisms are harmed by ocean acidification, others are helped by the lower pH levels in the ocean.CCollaborators are more motivated to study ocean acidification because of the economical impact it has on the oyster industry.DOcean acidification is not to blame for the oysters' reproductive failure because lower pH values are natural during upwelling events. can someone help me please