QUICKLY PLEASE: What is true about 1. 0 mol Ca and 1. 0 mol Mg? (3 points)

In the given chemical equation:

Fe(NO3)2 + Al → Fe + Al(NO3)3

Iron (Fe) is being reduced because it is gaining electrons and its oxidation state is decreasing from +2 to 0 (elemental state).

Aluminum (Al) is being oxidized because it is losing electrons and its oxidation state is increasing from 0 (elemental state) to +3.

Therefore, Fe(NO3)2 is the oxidizing agent, and Al is the reducing agent in this reaction.

The weight/volume percentage of sodium acetate in the solution is 4.6%.

The weight/volume percentage of sodium acetate in the solution can be calculated using the formula:
Weight/volume percentage = (Weight of solute ÷ Volume of solution) x 100%

In this case, the weight of sodium acetate is 13.8 grams and the volume of solution is 300 ml.

Therefore,
Weight/volume percentage = (13.8 g ÷ 300 ml) x 100%
Weight/volume percentage = 0.046 x 100%
Weight/volume percentage = 4.6%

Therefore, the weight/volume percentage of sodium acetate in the solution is 4.6%.

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The chemical energy referred to in the transfer from producers to consumers is the energy stored in the organic molecules synthesized by the producers during photosynthesis.

Producers, such as plants and algae, use energy from sunlight to convert carbon dioxide and water into glucose and other organic molecules through the process of photosynthesis. The energy from the sunlight is converted into chemical energy and stored in the organic molecules.

Consumers, such as herbivores and carnivores, obtain this stored chemical energy by consuming the organic molecules synthesized by the producers. The organic molecules are broken down during cellular respiration to release the stored chemical energy, which is used by the consumer to power its cellular processes.

Thus, the transfer of chemical energy from producers to consumers is a fundamental process in the food chain, and it is essential for the maintenance of life on earth.

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To accurately measure a very small volume of liquid like 0.03 ml, a micropipette would be the most appropriate measuring tool to use.

A micropipette is a laboratory instrument commonly used in biology, chemistry, and other related fields to accurately and precisely measure and transfer small volumes of liquids. It typically operates through a piston-driven air displacement system, allowing for very precise measurements in the microliter (μL) or even nanoliter (nL) range.

Micropipettes are commonly used in applications such as DNA sequencing, PCR, and protein assays, where precise and accurate liquid handling is essential for accurate results.

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The temperature when the thermometer reads a pressure of 800 mmHg is approximately 282.2 K (or 9.1 °C).

To solve this problem, we can use the ideal gas law:

PV = nRT

We can use this equation to calculate the temperature of the gas when the pressure is 800 mmHg.

First, we need to convert the pressures from mmHg to atm, since R is in units of L·atm/K·mol.

1 atm = 760 mmHg

780 mmHg = 1.026 atm

800 mmHg = 1.053 atm

Next, we can set up a ratio of the two pressures and temperatures:

P1/T1 = P2/T2

[tex](1.026 atm) / (273.15 K) = (1.053 atm) / T2[/tex]

Solving for T2, we get:

[tex]T2 = (1.053 atm) / (1.026 atm/273.15 K) \\T2 = 282.2 K[/tex]

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On a rock in coastal Maine, the fungus, the algae, and the bacteria make up part of an ecosystem.

An ecosystem consists of all the organisms and the physical environment with which they interact.

In the yellow scale lichen, the fungus provides protection, moisture, and nutrients for the algae. The algae carry out photosynthesis to produce food that is used by the fungus.

Ecosystem function is generally described as the capacity of natural processes and components to provide goods and services that satisfy human needs, either directly or indirectly.

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Answer:

107g

Explanation:

First convert the number of molecules to moles using avogadro's number.

There are 6.02 x 10^23 molecules in 1 mol.

3.8 x 10^24 molecules NH3 ÷ 6.02 x 10^23 molecules / mol

= 6.31 mol NH3

Now that we have moles of NH3 we can multiply it by NH3's molecular mass.

NH3 molecular mass = Mass of N + Mass of H x 3

14.007g/mol + 1.008g/mol * 3

= 17.031 g NH3/ mol

6.31 mol NH3 * 17.031 g NH3 / mol

= 107g NH3

First, we need to use stoichiometry to find out how many moles of hydrogen gas are produced. From the balanced chemical equation, we can see that for every 1 mole of zinc (Zn), 1 mole of hydrogen gas (H2) is produced. Therefore, if we have 20.0 mol of Zn, we will also produce 20.0 mol of H2.

Next, we can use the formula for the mass of a gas:

mass = molar mass x number of moles

The molar mass of hydrogen gas is approximately 2.02 g/mol. Therefore, the mass of 20.0 mol of hydrogen gas would be:

mass = 2.02 g/mol x 20.0 mol
mass = 40.4 g

So, 40.4 grams of hydrogen gas are produced when 20.0 mol of Zn are added to excess hydrochloric acid.

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At equilibrium, the concentrations of [tex]H_{3} O+, C_{6} H_{5}COO[/tex]-, and [tex]C_{6} H_{5}COO[/tex] in the solution will be 0.038 M, 0.038 M, and 0.012 M, respectively.

First, we can write the chemical equation for the dissociation of benzoic acid in water as follows:  [tex]C_{6}H5COOH + H_{2}O[/tex] ⇌[tex]C_{6}H_{5}COO- + H_{3}O[/tex]

The acid dissociation constant, Ka, is given as 6.3 × 10^-5.

[tex]Ka = [C_{6}H_{5}COO-][H_{3}O+] / [C_{6}H_{5}COOH][/tex]

We can assume that the initial concentration of [tex]C_{6}H_{5}COOH[/tex] is equal to its concentration at equilibrium, x. Thus, at equilibrium:

[tex][C_{6}H_{5}COOH] = x M \\[/tex]

[tex][C_{6}H_{5}COO-] = y M \\[/tex]

[tex][H_{3}O+] = y M\\[/tex]

Using the equilibrium expression and the given value of Ka, we can solve for the values of x and y:

[tex]Ka = [C_{6}H_{5}COO-][H_{3}O+] / [C_{6}H_{5}COOH]\\6.3 * 10^-5 = y^2 / x[/tex]

Since we know that the initial concentration of benzoic acid is 0.050 M, we can write: [tex]x + y = 0.050 M[/tex]

Now we have two equations and two unknowns. Solving for x and y:

[tex]x = 0.012 M\\y = 0.038 M[/tex]

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The volume of dichloromethane [tex](CH_2Cl_2)[/tex] produced when 149 liters of methane [tex](CH_4)[/tex] react according to the given reaction is approximately 6.224 x [tex]10^5 J/K*m^3[/tex].  

The volume of dichloromethane [tex](CH_2Cl_2)[/tex] produced when 149 liters of methane [tex](CH_4)[/tex] react according to the given reaction is not immediately apparent from the reaction stoichiometry.

The balanced equation for the reaction between methane  [tex](CH_4)[/tex] and carbon tetrachloride (CCl4) to form dichloromethane  [tex](CH_2Cl_2)[/tex] and carbon dioxide (CO2) is:

[tex](CH_4)[/tex] +  [tex]CO_2[/tex] →  [tex](CH_2Cl_2)[/tex] +  [tex]CO_2[/tex]

The balanced equation shows that 1 mole reacts with 1 mole of CCl4 to produce 1 mole of  [tex](CH_2Cl_2)[/tex] and 1 mole of  [tex]CO_2[/tex].

The volume of the gas can be calculated using the ideal gas law:

PV = nRT

To find the number of moles of gas, we can use the molecular masses of the reactants and products:

Molar mass of  [tex](CH_4)[/tex] = 16.04 g/mol

Molar mass of  [tex]CCl_4[/tex] = 89.9 g/mol

Molar mass of   [tex](CH_2Cl_2)[/tex] = 70.1 g/mol

Molar mass of  [tex]CO_2[/tex] = 44.01 g/mol

The number of moles of  [tex](CH_4)[/tex] can be calculated from the initial amount of gas:

149 L of CH4 = 149 x 16.04 g/mol = 2432 g

The number of moles of CCl4 can be calculated from the given volume:

149 L of  [tex](CH_4)[/tex] +  [tex]CCl_4[/tex] →   [tex](CH_2Cl_2)[/tex] +  [tex]CO_2[/tex]

The volume of the gas is given as 149 L, so the number of moles of  [tex]CCl_4[/tex] can be calculated as:

149 L = 149 x 89.9 g/mol = 13,277 g

The number of moles  can be calculated from the given volume and the desired amount of product

149 L of  [tex](CH_4)[/tex] + [tex]CCl_4[/tex] →   [tex](CH_2Cl_2)[/tex] + [tex]CO_2[/tex]

149 L of  [tex](CH_4)[/tex] + [tex]CCl_4[/tex] → 149 x 70.1 g/mol + 13,277 g x 1 mol/13.277 g = 43,691 g

V = nRT

V = 43,691 g x 8.314 J/mol·K = 364,617.5 J/K

1 J/K = 1/1000 L·K

Therefore, the volume of the gas is:

V = 364,617.5 J/K x (1/1000 L·K) = 3.646 x 10^4 L

substitute this value for V in the equation for the volume of  [tex](CH_2Cl_2)[/tex] :

PV = nRT

PV = 149 x 8.314 J/mol·K x (3.646 x [tex]10^4[/tex] L)

PV = 6.224 x   [tex]10^5 J/K*m^3[/tex].  

Therefore, The volume of dichloromethane [tex](CH_2Cl_2)[/tex] produced when 149 liters of methane [tex](CH_4)[/tex] react according to the given reaction is approximately 6.224 x [tex]10^5 J/K*m^3[/tex].  

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The ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.

To rank the solutions with the same molal concentration in decreasing order of their melting points, we need to consider their van't Hoff factor (i), which represents the number of particles a solute dissociates into when dissolved in water. The formula to calculate the effect of a solute on the melting point of a solution is ΔTf = Kf × m × i, where Kf is the cryoscopic constant of water, m is the molality, and i is the van't Hoff factor.

Here are the van't Hoff factors for each substance:

1. Calcium phosphate, Ca₃(PO₄)₂: This substance dissociates into 5 ions (3 Ca²⁺ + 2 PO₄³⁻), so i = 5.
2. Glucose, C₆H₁₂O₆: This substance is a molecular compound and does not dissociate into ions, so i = 1.
3. Sodium chloride, NaCl: This substance dissociates into 2 ions (Na⁺ + Cl⁻), so i = 2.
4. Magnesium chloride, MgCl₂: This substance dissociates into 3 ions (Mg²⁺ + 2 Cl⁻), so i = 3.

Using the van't Hoff factor, we can rank the solutions in decreasing order of their melting points:

1. Calcium phosphate, Ca₃(PO₄)₂ (i = 5)
2. Magnesium chloride, MgCl₂(i = 3)
3. Sodium chloride, NaCl (i = 2)
4. Glucose, C₆H₁₂O₆ (i = 1)

So, the ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.

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The pressure at the bottom of a lake is given as 2.35 atm, and we are asked to find the pressure of the water. Since water is the fluid in question, we can assume that it is incompressible and that its density is constant. To find the pressure of the water, we can use the following formula:

Pressure = Density x Acceleration due to gravity x Height

Here, the height refers to the depth of the lake, which we can assume to be the same as the height of the water column. The acceleration due to gravity is a constant, and the density of water is given as 0.21 g/L.

Substituting these values in the formula, we get:

Pressure = 0.21 g/L x 9.8 m/s^2 x Depth

Since the pressure at the bottom of the lake is given as 2.35 atm, we can convert this to SI units using the conversion factor:

1 atm = 101325 Pa

Therefore, 2.35 atm = 2.35 x 101325 Pa = 2.38 x 10^5 Pa

Substituting this value in the formula, we can solve for the depth:

2.38 x 10^5 Pa = 0.21 g/L x 9.8 m/s^2 x Depth

Depth = 114.7 m

Therefore, the pressure of the water at this depth is:

Pressure = 0.21 g/L x 9.8 m/s^2 x 114.7 m = 240.3 kPa

In conclusion, the pressure of the water at the bottom of the lake is 240.3 kPa. This is the pressure exerted by the water column due to its weight, and it is in addition to the atmospheric pressure. Understanding the pressure of fluids is important in many fields, such as hydrology, engineering, and physics.

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The concentration of the solution containing 25.0 g NaOH in 500 cm³ of water is approximately 1.25 M (moles per liter).

To find the concentration of a solution containing 25.0 g NaOH in 500 cm³ of water, follow these steps:

1. Convert grams of NaOH to moles. The molar mass of NaOH is approximately 40 g/mol (Na = 23 g/mol, O = 16 g/mol, H = 1 g/mol).

25.0 g NaOH × (1 mol NaOH / 40 g NaOH) ≈ 0.625 mol NaOH

2. Convert the volume of water from cm³ to liters (L).

500 cm³ × (1 L / 1000 cm³) = 0.5 L

3. Calculate the concentration of the solution in moles per liter (M).

Concentration = moles of solute/volume of solvent (in liters)
Concentration = 0.625 mol NaOH / 0.5 L ≈ 1.25 M

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The angle of a light beam affects the intensity and the amount of light reflected or transmitted through a process known as the "angle of incidence." When a light beam strikes a surface, the angle between the incoming light beam and the surface is called the angle of incidence. This angle plays a crucial role in determining the amount of light reflected or transmitted.

When the angle of incidence is small (light beam nearly perpendicular to the surface), more light is transmitted through the surface, and less is reflected. As the angle of incidence increases (light beam more parallel to the surface), the amount of light reflected also increases, while the intensity of the transmitted light decreases.

This phenomenon occurs due to the interaction of light with the surface material, which can either absorb, transmit, or reflect the incoming light, depending on the angle of incidence and the material's properties. The angle at which the light beam is incident on the surface also affects the intensity of the reflected light.

At a specific angle, called the "critical angle," the light beam is no longer transmitted but is entirely reflected, a phenomenon called "total internal reflection." The critical angle depends on the refractive indices of the two materials at the interface. When the angle of incidence is greater than the critical angle, all the light is reflected, and none is transmitted.

In summary, the angle of a light beam significantly influences the intensity and the amount of light reflected or transmitted by a surface. The angle of incidence determines the amount of light reflection, with a smaller angle leading to more transmission and a larger angle leading to increased reflection. The critical angle, in particular, plays a crucial role in determining the behavior of the light beam at the surface.

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The moles of hydrogen added to the balloon to give it a volume of 17.1 L were 8.8 mol.

Determine the initial ratio of moles to volume:
Initial moles of hydrogen = 2.6 mol
Initial volume of the balloon (V₁) = 3.9 L
Ratio of moles to volume: 2.6 mol / 3.9 L = 0.6667 mol/L

Final volume of the balloon (V₂) = 17.1 L

Calculate the final moles of hydrogen in the balloon using the initial ratio of moles to volume.
Final moles of hydrogen (H₂) = Ratio of moles to volume * V₂
Final moles of hydrogen (H₂) = 0.6667 mol/L * 17.1 L = 11.4 mol

The number of moles of hydrogen added thus are:
Moles of hydrogen added = Final moles of hydrogen - Initial moles of hydrogen
Moles of hydrogen added = 11.4 mol - 2.6 mol = 8.8 mol

So, 8.8 moles of hydrogen were added to the balloon to give it a volume of 17.1 L.

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If 44.0 grams of sodium reacts with 10.0 grams of chlorine gas, 54.0 grams of sodium chloride could potentially be formed in the reaction: 2 Na(s) + Cl₂(g) ⟶ 2 NaCl(s).


1. Calculate the moles of sodium and chlorine:
  - moles of Na = mass (g) / molar mass = 44.0 g / 22.99 g/mol = 1.91 mol
  - moles of Cl₂ = mass (g) / molar mass = 10.0 g / 70.90 g/mol = 0.141 mol

2. Determine the limiting reactant by dividing the moles of each reactant by their stoichiometric coefficients:
  - Na: 1.91 mol / 2 = 0.955
  - Cl₂: 0.141 mol / 1 = 0.141

3. Since the value for Cl₂ is lower, chlorine gas is the limiting reactant.

4. Calculate the moles of NaCl produced using the stoichiometry of the reaction:
  - moles of NaCl = moles of Cl₂ × (2 moles of NaCl / 1 mole of Cl₂) = 0.141 × 2 = 0.282 mol

5. Calculate the mass of NaCl produced:
  - mass of NaCl = moles × molar mass = 0.282 mol × 58.44 g/mol = 54.0 g

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0.008 moles of C₃H₇OH contains 1.44528 x 10^22 atoms of carbon.

To find the number of carbon atoms in 0.008 moles of C₃H₇OH, follow these steps:

1. Identify the number of carbon atoms in one molecule of C₃H₇OH. In this case, there are 3 carbon atoms.
2. Calculate the total number of molecules in 0.008 moles of C₃H₇OH by multiplying the number of moles by Avogadro's constant (6.022 x 10^23 molecules/mol).

0.008 moles * (6.022 x 10^23 molecules/mol) = 4.8176 x 10^21 molecules

3. Multiply the total number of molecules by the number of carbon atoms in each molecule to find the total number of carbon atoms:

4.8176 x 10^21 molecules * 3 carbon atoms/molecule = 1.44528 x 10^22 carbon atoms

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While balancing equation write the physical state of reactants and products as well as any reaction conditions.

Reactants are the substances that are present at the start of a chemical reaction. They are typically the substances that are used up during the reaction and are converted into different products. Reactants are usually written on the left side of a chemical equation, while the products are written on the right side. Reactants are essential components of any chemical reaction and are essential in order for the reaction to take place. Reactants are also known as substrates or starting materials.

Balancing the Following Equations:

1) CuSO4(s) + 2KI(aq) → Cu2I2(s) + K2SO4(aq) + I2(g)

2) 2NH3(g) + O2(g) → 2NO(g) + 2H2O(g)

3) 3Fe2O3(s) + 4CO(g) → 6Fe(s) + 3CO2(g)

4) Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)

5) 2Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + 2HNO3(aq)

6) CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)

7) 2MnO2(s) + 4HCl(aq) → 2MnCl2(aq) + 2H2O(l) + Cl2(g)

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The molality of the naphthalene solution in chloroform is approximately 0.551 mol/kg.

To calculate the molality of a solution of naphthalene dissolved in chloroform, we need to use the boiling point elevation formula: ΔTb = Kb * molality, where ΔTb is the change in boiling point, Kb is the boiling point elevation constant, and molality is the moles of solute per kilogram of solvent.

First, we need to find the change in boiling point (ΔTb) by subtracting the normal boiling point of chloroform from the given boiling point. The normal boiling point of chloroform is 61.2°C. Therefore, ΔTb = 63.2°C - 61.2°C = 2.0°C.

Next, we need to find the boiling point elevation constant (Kb) for chloroform. The Kb value for chloroform is 3.63 °C/kg/mol.

Now, we can use the boiling point elevation formula to solve for molality:
2.0°C = 3.63 °C/kg/mol * molality

Rearranging the equation and solving for molality, we get:
molality = 2.0°C / 3.63 °C/kg/mol = 0.551 mol/kg

Therefore, the molality of the naphthalene solution in chloroform is approximately 0.551 mol/kg.

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We need to dissolve 6.85 grams of sucrose in 2000 grams of water to make a 0.1 M solution.

To calculate the mass of sucrose needed to make a 0.1 molar solution in 2000 grams of water, we need to use the formula:

[tex]m = n *M * MW[/tex]

Step 1: Calculate the number of moles of sucrose needed

Molarity (M) = 0.1 mol/L

volume of solution = 2000 grams of water ÷ density of water = 2000 mL

We need to calculate the number of moles of sucrose that would be present in 2000 mL of a 0.1 M solution:

moles of solute (n) = [tex]M * V = 0.1 mol/L *2.0 L = 0.2 moles[/tex]

Step 2: Calculate the mass of sucrose needed

Molecular weight of sucrose is 342.3 g/mol.

We can use the formula:

[tex]m = n * M * MW \\m = 0.2 moles *0.1 mol/L * 342.3 g/mol = 6.85 g[/tex]

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We can use the ideal gas law to calculate the pressure of the bromine gas in the 1.5 L container. The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Since we know the temperature and the volume, we can rearrange the ideal gas law to solve for P, the pressure. We can use the pressure and volume from the first container to calculate the number of moles. Plugging in all of the known values, we get:

P1V1 = nRT

n = P1V1/RT

P2 = (P1V1/RT) * (V2/V1)

Using the values from the question, we get:

P2 = (1.20 atm * 2.65 L)/(0.08206 L·atm·mol-1·K-1 * 298 K) * (1.50 L/2.65 L)

This gives us a pressure of 1.04 atm in the 1.5 L container, which is equal to 1040 kPa.

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The computation in the question results in the production of 21 g of NF3.

Because it is the reactant that is totally consumed during the reaction, the limiting reactant specifies the maximum amount of product that can be created in a chemical process.

F2 molecular weight is 16.5 g/38 g/mol.

= 0.43 moles

N2 molecular weight is 16.5 g/28 g/mol.

= 0.59 moles

Now;

If 3 moles of F2 and 1 mole of N2 react,

N2 interacts with 0.59 moles at 0.59 * 3/1.

= 1.77 moles of F2

Thus F2 is the limiting reactant

2 moles of NF3 are created from 3 moles of F2.

When using 0.43 moles of F2, you get 0.43 * 2/3.

= 0.29 moles

NF3 mass generated is 0.29 moles * 71 g/mol.

= 21 g

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The volume of the gas in the truck tire is approximately 44.2 L.

The ideal gas law equation can be used to solve for the volume of the gas in the tire:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas.

Substituting the given values into the equation, we get:

(2.1 atm)(V) = (1.85 mol)(0.08206 L atm/mol K)(300 K)

Solving for V, we get:

V = (1.85 mol)(0.08206 L atm/mol K)(300 K)/(2.1 atm) ≈ 44.2 L

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The final pressure of the gas when the volume changes from 720 mL to 820 mL is approximately 1.22 atm.


To solve this problem, we can use Boyle's Law, which states that the product of the initial pressure and volume (P1V1) is equal to the product of the final pressure and volume (P2V2) for a gas at a constant temperature:

P1V1 = P2V2

Given the initial pressure (P1) is 1.4 atm and the initial volume (V1) is 720 mL, we need to find the final pressure (P2) when the volume (V2) changes to 820 mL. Rearrange the formula to solve for P2:

P2 = P1V1 / V2

Substitute the given values:

P2 = (1.4 atm × 720 mL) / 820 mL
P2 ≈ 1.22 atm

Therefore, the final pressure of the gas is approximately 1.22 atm.

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Explanation:

3120 j / (2000 g * (212-200 C) )  = .13 j /( g C)  

When reading an electron dot diagram, you can determine the number of valence electrons an atom has and use that information to predict how it will bond with other atoms. Atoms tend to form bonds in order to achieve a full outer shell of electrons, which is the most stable arrangement. By looking at the number of dots in the electron dot diagram, you can predict how many bonds an atom is likely to form and what types of atoms it will bond with.

To read an electron dot diagram, you first need to understand what it represents. An electron dot diagram, also known as a Lewis structure, shows the number of valence electrons that an atom has. Valence electrons are the electrons in the outermost energy level of an atom and are involved in chemical bonding.

The dot diagram shows the symbol for the element surrounded by dots representing the valence electrons. Each dot represents one electron, and the dots are placed around the symbol in pairs, with no more than two dots on each side.

For example, carbon has four valence electrons, so its electron dot diagram would show four dots surrounding the symbol for carbon. Nitrogen, on the other hand, has five valence electrons, so its electron dot diagram would show five dots.

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The Bohr equation for the hydrogen atom is given by:

E = -2.18 × 10^-18 J/n^2

where E is the energy of the electron, and n is the principal quantum number.

The lowest energy level or ground state of hydrogen is when n = 1. So, we can find the energy of the lowest excited state by setting n = 2 in the Bohr equation:

E = -2.18 × 10^-18 J/2^2 = -0.54 × 10^-18 J

The energy of the lowest excited state is the difference between the energy of the ground state and the energy of the excited state. So, we can find the energy of the lowest excited state by subtracting the energy of the ground state (n=1) from the energy of the excited state (n=2):

ΔE = E₂ - E₁ = (-0.54 × 10^-18 J) - (-2.18 × 10^-18 J) = 1.64 × 10^-18 J

Therefore, the energy of the lowest excited state of hydrogen is 1.64 × 10^-18 J, which is closest to option (b) 1.66 × 10^-18 J.

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