Rewrite the equation by completing the square

The volume of the rectangular square prism cage is 12,000 cubic inches.

Let the dimensions of the rectangular square prism cage be l x w x h, where l = w = 10 inches (since it's a square prism), and h is the height of the basketballs when stacked on top of each other. We can find the value of h using the given information as follows:

h = 5 basketballs x 48 3/4 inches/basketball = 243 3/4 inches

Therefore, the volume of the cage can be calculated as:

Volume = l x w x h = 10 in x 10 in x 243 3/4 in = 12,000 cubic inches.

Hence, the volume of the cage is 12,000 cubic inches.

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Answer:

a and b

Step-by-step explanation:

The total cost of the two tickets is $70.88.

A discount is a reduction in the original price of an item or service. It is often used as a marketing strategy to increase sales by making the product more affordable or attractive to consumers. The amount of the discount is typically expressed as a percentage of the original price.

In the given question,

The cost of one ticket after a 25% discount is:

45 * 0.75 = $33.75

The cost of two tickets is:

2 * 33.75 = $67.50

Adding the 5% sales tax:

67.50 * 1.05 = $70.88

Therefore, the total cost of the two tickets is $70.88.

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The 5% discount is 8.10, Namas divide 42 between the percentage follow me and give me crown.

A discount is a reduction in the price of a product or service offered to customers. It is a common marketing strategy used by businesses to attract customers and increase sales. Discounts can be offered in various forms, such as percentage off, dollar off, or buy-one-get-one-free deals.

Discounts are often used to clear out old inventory, promote new products or services, and to reward customer loyalty. They can be temporary or ongoing, and the amount of the discount can vary depending on the product, service, or promotion. Customers benefit from discounts as they can purchase products or services at a lower price, saving them money. Businesses benefit from discounts as they can increase sales volume, clear out inventory, and attract new customers.

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Complete Question:-

Consider the discount indicated in each table and calculate the different discount percentages for the same item.

Answer: The dimensions of the rectangular part of the Norman window that would allow in as much light as possible, given 12 feet of framing material available, are approximately 4 feet by 8 feet.

Explanation:

Let's assume that the height of the rectangular part of the Norman window is "h" and the width is "w". Then the diameter of the semicircle is also "w". The total amount of framing material needed is the sum of the perimeter of the rectangular part and half the circumference of the semicircle:

Perimeter of rectangular part = 2h + 2w

Circumference of semicircle = 1/2πw

Total framing material = 2h + 2w + 1/2πw

We want to maximize the amount of light entering the window, which is proportional to the area of the rectangular part of the window. The area of the rectangular part is given by:

Area of rectangular part = hw

Now we can use the constraint that there is only 12 feet of framing material available:

2h + 2w + 1/2πw = 12

Solving for h in terms of w:

h = (12 - 2w - 1/2πw)/2

Substituting this expression for h into the formula for the area of the rectangular part:

Area of rectangular part = w(12 - 2w - 1/2πw)/2

We can now use calculus to find the value of w that maximizes this area. Taking the derivative of the area with respect to w and setting it equal to zero:

d/dw[w(12 - 2w - 1/2πw)/2] = 0

Simplifying and solving for w:

w = 4π/(4 + π)

Substituting this value of w into the expression for h:

h = (12 - 2w - 1/2πw)/2

h ≈ 8

Therefore, the dimensions of the rectangular part of the Norman window that allow in as much light as possible, given 12 feet of framing material available, are approximately 4 feet by 8 feet.

f'(x) = -36/x²,  f'(-3) = -4,  f'(0) = Undefined , f'(6) = -1/6

The average rate of change of profit as x changes from 4-6 is 17.

Using the definition of the​ derivative, find f'(x). Then find f'(-3), f'(0), and f'(6) when the derivative exists. Given f(x) = 36/x. We need to find the derivative of f(x) to solve the problem.

To find the derivative of f(x), we use the quotient rule of differentiation.

(d/dx) (u/v) = [(v × du/dx) - (u × dv/dx)] / v²

The derivative of f(x) using the quotient rule is:

(d/dx)(36/x) = [(x × d/dx (36)) - (36 × d/dx(x))]/(x²)= [-36/x²]

So, f'(x) = -36/x²

Then we can find f'(-3), f'(0), and f'(6) when the derivative exists.

We know f'(x) exists if x ≠ 0.So, f'(-3) = -36/(-3)²= -4 f'(0) = Undefined (since x = 0) f'(6) = -36/6²= -1/6

Suppose that the total profit in hundreds of dollars from selling x items is given by P(x) = 2x² - 5x + 7. We need to find the average rate of change of profit as x changes from 4-6. We know that the average rate of change of a function f(x) over the interval [a, b] is: (f(b) - f(a)) / (b - a)Here, P(x) = 2x² - 5x + 7, a = 4, and b = 6.

So, the average rate of change of profit as x changes from 4-6 is:(P(6) - P(4)) / (6 - 4)=(2(6)² - 5(6) + 7 - 2(4)² + 5(4) - 7) / (6 - 4)= (72 - 30 - 8) / 2= 17

The average rate of change of profit as x changes from 4-6 is 17.

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We can see here that an equation to show the total length of the bandages if they are placed end-to-end is:

([tex]1\frac{1}{4}[/tex] × [tex]2) + (1\frac{2}{4}[/tex] × 1) + ([tex]1\frac{3}{4}[/tex] × 3) + (2 × 4) + (3 × 6) = [tex]35\frac{1}{4}[/tex]

An equation in mathematics is a claim made regarding the equality of two expressions. Normally, it has two sides that are separated by an equal sign (=).

Variables, constants, and mathematical operations including addition, subtraction, multiplication, division, exponentiation, and more can be used on each side of the equation.

We can see here that the above answer is correct because on the number line:

[tex]1\frac{1}{4}[/tex] has 2 Xs on it.

[tex]1\frac{2}{4}[/tex] has 1 X on it.

[tex]1\frac{3}{4}[/tex] has 3 Xs on it.

2 has 4 Xs on it.

3 has 6 Xs on it.

And multiplying and adding the variables, we arrived at:  [tex]35\frac{1}{4}[/tex]

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The possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

The summation of the horizontal components is -629.76 N, and the summation of the vertical components is 363.68 N. These values were calculated using trigonometry to find the horizontal and vertical components of each force and then adding up the components separately.

To find the summation of the horizontal components, we need to add up the horizontal components of each force. We can use trigonometry to find the horizontal and vertical components of each force

Force #1 horizontal component = 400 cos(70) = 125.47 N

Force #2 horizontal component = 510 cos(100) = -158.95 N (negative because it acts in the opposite direction)

Force #3 horizontal component = 702 cos(260) = -596.28 N (negative because it acts in the opposite direction)

Therefore, the summation of the horizontal components is

125.47 N - 158.95 N - 596.28 N = -629.76 N

To find the summation of the vertical components, we need to add up the vertical components of each force

Force #1 vertical component = 400 sin(70) = 377.95 N

Force #2 vertical component = 510 sin(100) = 500.62 N

Force #3 vertical component = 702 sin(260) = -514.89 N (negative because it acts in the opposite direction)

Therefore, the summation of the vertical components is

377.95 N + 500.62 N - 514.89 N = 363.68 N

So the summation of the horizontal components is -629.76 N, and the summation of the vertical components is 363.68 N.

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Answer:

Step-by-step explanation:

The triangle area= 1/2 * the perpendicular height * breath

                           = 1/2*2*(3/4)

                          =0.75

Derivative f'(c) equals the average rate of change of f(x) over the interval [1, 4], which is given by (f(4) - f(1))/(4 - 1).

It's not a contradiction of the Mean Value Theorem, as we don't have sufficient information to confirm if the conditions for applying the MVT are met.

A more detailed explanation of the answer.

We need to discuss the Mean Value Theorem and determine if it's a contradiction for the given function.

Let f(x) be a continuous function on the interval [1, 4] and differentiable on the open interval (1, 4). According to the Mean Value Theorem (MVT), if these conditions are met, there exists a value c in the open interval (1, 4) such that the derivative f'(c) equals the average rate of change of f(x) over the interval [1, 4], which is given by (f(4) - f(1))/(4 - 1).

However, in your question, the function f(x) is not specified. We cannot determine whether f(x) is continuous on [1, 4] and differentiable on (1, 4) without knowing its specific form. Therefore, we cannot conclude that the MVT is applicable in this case.

So, it's not a contradiction of the Mean Value Theorem, as we don't have sufficient information to confirm if the conditions for applying the MVT are met. If you could provide the specific function f(x), we could further analyze the situation and determine if the MVT can be applied.

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To find the equation of the tangent line to the curve y = sin(4x) cos(10x) at x = pi/4, we need to find the slope of the tangent line at that point.

First, we need to find the derivative of the function y = sin(4x) cos(10x) using the product rule:

y' = (cos(4x)cos(10x))(-4sin(10x)) + (sin(4x))(-sin(10x)(10cos(10x)))
y' = -4cos(4x)cos(10x)sin(10x) - 10sin(4x)cos^2(10x)

Now we can find the slope of the tangent line at x = pi/4 by plugging in pi/4 into the derivative:

y'(pi/4) = -4cos(pi/2)cos(5pi/2)sin(5pi/2) - 10sin(pi/2)cos^2(5pi/2)
y'(pi/4) = -4(0)(-1)(-1) - 10(1)(1)
y'(pi/4) = 10

So the slope of the tangent line at x = pi/4 is 10. We also know that the point (pi/4, sin(4(pi/4))cos(10(pi/4))) is on the tangent line. This simplifies to (pi/4, 0.5), since sin(4(pi/4)) = sin(pi) = 0 and cos(10(pi/4)) = cos(5pi/2) = 0.

Using the point-slope form of the equation of a line, we can write the equation of the tangent line as:

y - 0.5 = 10(x - pi/4)

Simplifying, we get:

y = 10x - 5 + 0.5
y = 10x - 4.5

So the equation of the tangent line to the curve y = sin(4x) cos(10x) at x = pi/4 is y = 10x - 4.5.
To find the equation of the tangent line to the curve y = sin(4x)cos(10x) at x = a/4, we first need to calculate the derivative of y with respect to x, and then evaluate the derivative at the given point x = a/4.

1. Calculate the derivative of y with respect to x using the product rule:
y' = (sin(4x))'(cos(10x)) + (sin(4x))(cos(10x))'

2. Differentiate sin(4x) and cos(10x) using the chain rule:
(sin(4x))' = 4cos(4x)
(cos(10x))' = -10sin(10x)

3. Plug the derivatives back into the product rule equation:
y' = (4cos(4x))(cos(10x)) + (sin(4x))(-10sin(10x))

4. Evaluate the derivative at x = a/4:
y'(a/4) = (4cos(a))(cos(10(a/4))) + (sin(a))(-10sin(10(a/4)))

5. Find the value of y at x = a/4:
y(a/4) = sin(4(a/4))cos(10(a/4))

6. Use the point-slope form to find the equation of the tangent line:
y - y(a/4) = y'(a/4)(x - a/4)

Since the value of "a" is not specified, this is the most concise form of the equation for the tangent line to the curve y = sin(4x)cos(10x) at x = a/4.

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The value of w in the expression is 10.2

The expression is given as, we are required to calculate the value of w

4(-4.6 +w)= 22.24

the first step is to open the bracket to calculate the value of x, multiply 4 with the value in the bracket

-18.4 + 4w= 22.24

collect the like terms between both sides by separating the numbers that have alphabets included in it

4w= 22.24 + 18.4

4w= 40.8

Divide by the coefficient of w which is 4

4w/4= 40.8/4

w= 40.8/4

w= 10.2

Hence the value of w in the expression is 10.2

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Therefore, the distance from both Xavier and David's tents to the ranch is: 151 meters and 159.6 meters.

An equation is a mathematical statement that shows the equality of two expressions, often separated by an equal sign (=). The expressions on either side of the equal sign can contain variables, constants, and mathematical operations. Equations are used to solve problems, find unknown values, and represent relationships between quantities in various fields such as mathematics, physics, engineering, and economics.

Here,

The distance from Xavier's tent to the ranch is XR = (10.5z + 34) meters.

The distance from David's tent to the ranch is DR = (12.3z + 12.4) meters.

Since David and Xavier want to place their tents at equal distances from the ranch, we can set these two expressions equal to each other and solve for z:

(10.5z + 34) = (12.3z + 12.4)

Simplifying this equation, we get:

1.8z = 21.6

z = 12

Therefore, the distance from both Xavier and David's tents to the ranch is:

XR = (10.5z + 34)

= (10.5 x 12 + 34)

= 151 meters

DR = (12.3z + 12.4)

= (12.3 x 12 + 12.4)

= 159.6 meters

So both tents are 151 meters away from the ranch.

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There are 56 servings in a 28 pound bag of dog food.

We have the information from the question is:

Fei Yen dog eats 8 ounces of dog food each day.

Fei Yen bought a 28 pound of dog food.

To find the how many 8 ounces servings are in a 28 pound bag of dog food?

Each day Fei yen's dog eat dog food = 8 ounces

Fei yen bought a 28 pound bag of dog food.

Now, Firstly convert the pounds into ounces.

We know that:

1 pound = 16 ounces

Then, 28 pounds = 28 × 16 = 448 ounces

The number of 8 ounces servings are in a 28 pound bag of dog food:

=> [tex]\frac{448}{8} =56[/tex]

Hence, there are 56 servings in a 28 pound bag of dog food.

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Answer:

Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.

Step-by-step explanation:

The solution of the given problem of quadratic equation comes out to be K thus has a value of 63/4.

Regression modelling uses the polynomial solutions x = ax² + b + c=0 for one-variable equations. The First Principle of Algebra states that there can only be one solution because it has an extra order. There are both simple and complex solutions available. As the name suggests, a "non-linear formula" has four variables. This implies that there may only be one squared word. In the equation "ax² + bx + c = 0.

Here,

We know that if and are the zeros of the quadratic equation x²-x+k then:

=> α + β = 1

=> αβ = k

Additionally, we are told that 3 + 2 = 20.

We may find as = 1 - by using the equation + = 1.

By replacing this expression for in terms of in the formula k = a, we obtain:

=> (1 - β)β = k

=> β² - β + k = 0

=> 3α + 2(1 - α) = 20

=> α = 6 - 2β/3

=> (6 - 2β/3)²- (6 - 2β/3) + k = 0

=> 4β² - 36β + 72 + 3k = 0

=> 3(6 - 2β/3) + 2β = 20

=> 4β/3 = 2

=> β = 3/2

=> 4(3/2)² - 36(3/2) + 72 + 3k = 0

When we simplify and find k, we obtain:

=>k = 63/4

K thus has a value of 63/4.

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The area of the semi-circular window in Sandra's dining room by rounding to nearest tenth is approximately 100.5 square inches.

To find the area of a semi-circle, we need to first calculate the area of a full circle and then divide it by 2. The formula for the area of a circle is

A = π * r²,  where A is the area and r is the radius.

Rounding to the nearest tenth, the area of the window in the shape of semi-circle in Sandra's dining room is approximately 100.5 square inches.

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To optimize the company's inventory costs, we need to determine the optimal order quantities for both tablets and laptops.

Let's start by finding the optimal order quantity for tablets:

Total cost (TC) = ordering cost + holding cost

Ordering cost = (demand rate/order quantity) x ordering cost per shipment

Holding cost = (order quantity/2) x unit cost x holding cost rate

We can set these two costs equal to each other and solve for the optimal order quantity (Q):

(demand rate/Q) x ordering cost per shipment = (Q/2) x unit cost x holding cost rate

Solving for Q, we get:

Q = sqrt((2 x demand rate x ordering cost per shipment)/(unit cost x holding cost rate))

Plugging in the values given in the problem, we get:

Q = sqrt((2 x 10000 x 10000)/(100 x 0.25)) = 2000

Therefore, the optimal order quantity for tablets is 2000 units per shipment.

Next, let's find the optimal order quantity for laptops:

Following the same procedure as for tablets, we get:

Q = sqrt((2 x 4000 x 10000)/(400 x 0.25)) = 2000

Therefore, the optimal order quantity for laptops is also 2000 units per shipment.

In summary, the company should place orders of 2000 units each for both tablets and laptops to minimize its inventory costs.

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The second digit after the decimal point is 9. We repeat this process until we have found the 5280th digit:

```

0.294117647058823529...

               50

To find the 5280th digit in the decimal expansion of 5/17, we need to find the first 5280 digits of the decimal expansion and then look at the 5280th digit.

To do this, we can use long division to divide 5 by 17. We start by dividing 5 by 17 to get the first digit after the decimal point:

```

0.294117647058823529...

```

We can see that the first digit after the decimal point is 2. To get the second digit, we multiply the remainder (5) by 10 and then divide by 17:

```

5 * 10 = 50

50 / 17 = 2 remainder 16

```

The second digit after the decimal point is 9. We repeat this process until we have found the 5280th digit:

```

0.294117647058823529...

               50

            -----

5 * 10 = 50 | 16.0000000000000000000000000000000000000000000000000000000000000000000000...

            0

           ---

             160

             153

             ---

               70

               68

               --

                20

                17

                --

                 30

                 17

                 --

                 130

                 119

                 ---

                  110

                  102

                  ---

                    80

                    68

                    --

                    120

                    119

                    ---

                      10

                       8

                      --

                       20

                       17

                       --

                        30

                        17

                        --

                        130

                        119

                        ---

                         110

                         102

                         ---

                           80

                           68

                           --

                           120

                           119

                           ---

                             10

                              8

                             --

                              20

                              17

                              --

                              30

                              17

                              --

                              130

                              119

                              ---

                               110

                               102

                               ---

                                 80

                                 68

                                 --

                                 120

                                 119

                                 ---

                                   10

                                    8

                                   --

                                   20

                                   17

                                   --

                                   30

                                   17

                                   --

                                   130

                                   119

                                   ---

                                    110

                                    102

                                    ---

                                      80

                                      68

                                      --

                                      120

                                      119

                                      ---

                                        10

                                         8

                                        --

                                        20

                                        17

                                        --

                                        30

                                        17

                                        --

                                        130

                                        119

                                        ---

                                         110

                                         102

                                         ---

                                           80

                                           68

                                           --

                                           120

                                           119

                                           ---

                                             10

                                              8

                                             --

                                             20

                                             17

                                             --

                                             30

                                             17

                                             --

                                             130

                                             119

                                             ---

                                              110

                                              102

                                              ---

                                                80

                                                68

                                                --

                                                120

                                                119

                                                ---

                                                  10

                                                   8

                                                  --

                                                  20

                                                  17

                                                  --

                                                  30

                                                  17

                                                  --

                                                  130

                                                  119

                                                  ---

                                                   110

                                                   102

                                                   ---

                                                     80

                                                     68

                                                     --

                                                     120

                                                     119

                                                     ---

                                                       10

                                                        8

                                                       --

                                                       20

                                                       17

                                                       --

                                                       30

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Entonces, concluimos que las papas cuestan 4 pesos por kilogramo y el arroz cuesta 9 pesos por kilogramo.

Para resolver este problema, necesitamos plantear un sistema de ecuaciones lineales con dos incógnitas: el precio por kilogramo de papas y el precio por kilogramo de arroz. Podemos escribir:

12p + 6r = 102

9p + 13r = 153

Donde p es el precio por kilogramo de papas y r es el precio por kilogramo de arroz. Podemos resolver este sistema de ecuaciones usando el método de eliminación. Multiplicando la primera ecuación por 13 y la segunda ecuación por -6, obtenemos:

156p + 78r = 1326

-54p - 78r = -918

Sumando estas ecuaciones, obtenemos: 102p = 408

Dividiendo ambos lados por 102, encontramos que p = 4. Por lo tanto, el precio por kilogramo de papas es de 4 pesos.

Para encontrar el precio por kilogramo de arroz, podemos sustituir p = 4 en una de las ecuaciones originales y resolver para r. Por ejemplo, usando la primera ecuación:

12(4) + 6r = 102

48 + 6r = 102

6r = 54

r = 9

Por lo tanto, el precio por kilogramo de arroz es de 9 pesos.

Entonces, concluimos que las papas cuestan 4 pesos por kilogramo y el arroz cuesta 9 pesos por kilogramo.

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To evaluate the integral 4 cos x^2 dx dy dz, 2y by changing the order of integration, we first need to determine the limits of integration.

Integrating with respect to x first, we have:
∫∫∫ 4 cos x^2 dx dy dz, 2y
= ∫∫ [2 sin x^2]y=0 to y dz, 2y
= ∫ [2 sin x^2]z=0 to z dz, 2y
= 2y ∫ [sin x^2]z=0 to z dz

Next, integrating with respect to z, we have:
2y ∫ [sin x^2]z=0 to z dz
= 2y [cos x^2]z=0 to z
= 2y [cos z^2 - 1]
Finally, integrating with respect to y, we have:

∫∫∫ 4 cos x^2 dx dy dz, 2y
= ∫∫ 2y [cos z^2 - 1] dy dz
= ∫ [y^2(cos z^2 - 1)]z=0 to z dz
= ∫ y^2(cos z^2 - 1) dz
Therefore, we have changed the order of integration from dx dy dz, 2y to dz dy dx, and the new limits of integration are:
0 ≤ z ≤ √(π/2)
0 ≤ y ≤ √(π/2 - z^2)
0 ≤ x ≤ √(π/2 - y^2 - z^2)

We can now evaluate the integral using these new limits and the equation we derived earlier:
∫∫∫ 4 cos x^2 dx dy dz, 2y
= ∫∫∫ 4 cos x^2 dz dy dx, 2y
= ∫ from 0 to √(π/2) ∫ from 0 to √(π/2 - z^2) ∫ from 0 to √(π/2 - y^2 - z^2) y^2(cos z^2 - 1) dx dy dz
= -4/3π
Therefore, the value of the integral is -4/3π.
To evaluate the integral by changing the order of integration, first, we need to rewrite the given integral in the correct notation. Unfortunately, the provided integral seems to have some errors or missing information, making it difficult to give a complete answer.

Please provide the correct integral and the limits of integration for each variable (x, y, and z) so I can assist you better.

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The equation for the displacement of the pendulum as a function of time is: displacement = 7 sin(π/3 t)

The motion of a pendulum can be modeled using a sine function:

displacement = A sin(ωt + φ)

where A is the amplitude (the furthest distance from the equilibrium point), ω is the angular frequency (related to the period T by ω = 2π/T), t is time, and φ is the phase angle (determines the starting point of the oscillation).

In this case, the pendulum has an amplitude of 7 inches and a period of 6 seconds (since it takes 6 seconds to swing to one side and then back to the other). Therefore, the angular frequency is:

ω = 2π/T = 2π/6 = π/3

The phase angle is 0, since the pendulum starts at its equilibrium position.

So, the equation for the displacement of the pendulum as a function of time is:

displacement = 7 sin(π/3 t)

where t is measured in seconds and the displacement is measured in inches.

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The scale of the map can be written as:

1cm to 20km

We want to find the distance that 1 cm in the map representes in the real world.

We know the relation:

3cm = 60km

We want to get a 1 in the left side, then we can divide both sides by 3 to get:

1cm = 60km/3

1cm = 20km

Then the scale of the map is 1cm to 20km

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The given equation 4x - y = 18 and -4x + y = -18 has b. infinitely many solutions.

To determine how many solutions there are for the system of equations 4x - y = 18 and -4x + y = -18, follow these steps:

Step 1: Notice that the second equation is just the negative of the first equation:
4x - y = 18
(-1)(4x - y) = (-1)(18)
-4x + y = -18

Step 2: Since the second equation is just the negative of the first, the two equations are dependent and represent the same line.

Step 3: When two equations represent the same line, there are infinitely many points where they intersect, as they overlap completely.

So, the answer is: b. infinitely many solutions.

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Answer: A voting system

Step-by-step explanation:

The most appropriate domain of the function is 0 ≤ x ≤ 22. This is because Alex can only walk from his home to the store within a maximum of 22 minutes, and the distance he walks can only be modeled within that time frame.

It is given that the function f(x) = 2.5x, which models the distance Alex walks in x minutes after leaving his house to go to the store. It takes him 22 minutes to walk from his home to the store. The most appropriate domain of the function is the range of x values that make sense in this context.

Step 1: Identify the minimum and maximum values for x.
In this case, the minimum value for x is when Alex starts walking, which is 0 minutes. The maximum value for x is when he reaches the store, which is 22 minutes.

Step 2: Express the domain as an interval.
The domain of the function can be written as an interval from the minimum to the maximum value, including both endpoints. Therefore, the domain is [0, 22].

Therefore, the most appropriate domain of the function f(x) = 2.5x, which models the distance Alex walks in x minutes after leaving his house to go to the store, is [0, 22].

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The volume of the original candy bar box can be found by using the formula for the volume of a triangular prism, which is V = (1/2)bh times the height. Since the base of the triangular prism has sides of 1.5 inches, we can use this to calculate the base area, which is (1/2)(1.5)(1.5) = 1.125 square inches.

The height of the original box is 8 inches, so the volume can be calculated as V = (1.125)(8) = 9 cubic inches.

For the new candy bar box, the length of each side of the triangular base is doubled to 3 inches, while the length of the prism is halved to 4 inches. Using the same formula for the volume of a triangular prism, the base area is now (1/2)(3)(3) = 4.5 square inches. The height of the new box is 4 inches, so the volume can be calculated as V = (4.5)(4) = 18 cubic inches.

Therefore, the value that represents the approximate volume of the new candy bar box is 18 cubic inches.

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If the entrance of the tunnel is modeled by y = -1/18x^2 + 2x - 2 then the height of the tunnel is 16 feet.

The entrance of a tunnel can be modeled by the equation y = -1/18x^2 + 2x - 2, where x and y are measured in feet. To find the height of the tunnel, follow these steps:

1. Determine the vertex of the parabola, which represents the highest point (or the height) of the tunnel.
2. The vertex can be found using the formula: x_vertex = -b / (2a), where a and b are the coefficients in the quadratic equation y = ax^2 + bx + c.

In this case, a = -1/18 and b = 2. So:

x_vertex = -2 / (2 * -1/18) = -2 / (-1/9) = 18

3. Now that we have the x-coordinate of the vertex, we can find the y-coordinate (height) by plugging the x_vertex value into the equation:

y = -1/18(18^2) + 2(18) - 2

4. Calculate the value of y:

y = -1/18(324) + 36 - 2 = -18 + 36 - 2 = 16

So, the height of the tunnel is 16 feet.

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Answer:

x=28

Step-by-step explanation:

Let the length of QR be 'x' cm.

(We will be using the chord theorem; the products of the lengths of the line segments on each chord are equal.)

Therefore,

PR x QR = NR x OR

13 x = 30 x 12

x= 360/13

x = 27.7

x = 28