Ryan's friends have organized a treasure hunt. He is using the map below to find the clues. The position of the last clue, which
leads to the treasure, is located at point (-2,4).
6
+
2
2
-2
He figures that the treasure is 3 units either to the east or south of the location of the last clue. Which of these could be the
location of the treasure?
OA. point (1, 4) or point (-2, 1)
OB. point (-5, 4) or point (-2, 1)
OC. point (1, 1) or point (-5,7)
OD. point (1, 4) or point (-2,7)

Answer:

Danil received 147 euros

Step-by-step explanation:

Let, Danil,Gabriel and Hardly share some money of 3x:5x:9x ratio then,

From the question,

9x - 5x= 196

or, 4x= 196

or, x = 196/4

or, x = 49 euros

Again,Danil received 3x share of money

=3*49

=147 euros

Answer:

Step-by-step explanation:

Ratio = 3 : 5 : 9

Money received by  Danil = 3x  

Money received by Gabriel = 5x

Money received by Hadley = 9x

Difference in the amount between Gabriel and Hadley = 196 euros

9x - 5x = 196

       4x = 196

         x = 196/4

        x = 49

Money received by Danil = 3*49

                                           = € 147

Answer:

pounds and ounces

Randomly pick 25 fish from the entire pond and weigh each of them

Step-by-step explanation:

Centimeters, feet and inches measure length, not weight.

To find the average weight of fish living in a large pond, the scientist will randomly pick 25 fish from all over the pond. Next, each fish will be weighed. The weight of all 25 fish will be added and the total will be divided by 25. This will give you the average weight of a fish living in the large pond.

Answer:

14, 48 and 50

Step-by-step explanation:

Check the picture below, so hmm we know that much, and we can also more or less see that PR is the longest side, let's check the length of the other two sides

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ P(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad Q(\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ PQ=\sqrt{[3 - 6]^2 + [5 - 1]^2}\implies PQ=\sqrt{(-3)^2+4^2}\implies \boxed{PQ=5} \\\\[-0.35em] ~\dotfill\\\\ Q(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad R(\stackrel{x_2}{11}~,~\stackrel{y_2}{11})~\hfill QR=\sqrt{[11 - 3]^2 + [11 - 5]^2} \\\\\\ QR=\sqrt{8^2+6^2}\implies \boxed{QR=10}[/tex]

if that's true, the triangle is indeed a right-triangle, then hmmmm most likely using the pythagorean theorem PR² = PQ² + QR², let's check

[tex](\sqrt{125})^2~~ = ~~5^2~~ + ~~10^2\implies 125=25+100\implies 125=125~~\textit{\Large \checkmark}[/tex]

The fair interval illustrates a sample space

The interval that will make a fair decision is from 5 to 20

From the question, we understand that:

Since they choose odd and even integers, then the sample space must be divisible by the number of people (i.e 2 people)

The sample space (S) is calculated as:

S = Highest - Least + 1

S = 10 - 2 + 1 = 9

S = 15 - 3 + 1 = 13

S = 20 - 5 + 1 = 16

S = 25 - 5 + 1 = 21

Only 16 can be divisible by 2

Hence, the interval that will make a fair decision is from 5 to 20

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Answer:

17

Step-by-step explanation:

This flight makes a right triangle

The sides are 8 and 15. The hypotenuse isnt know and that is the answer.

8^2 + 15^2 = c^2

c^2 = 289

c = 17

The least amount of wrapping paper that Amy needs to wrap the present is 1936in².

Surface area is simply the amount of space covering the outside of a 3-dimensional object.

The surface area of a rectangular prism is expressed;

A = 2( wl + hl + hw )

Given the data in the question;

To determine the least amount of wrapping paper that Amy needs to wrap the present in the shape of a rectangular prism, we substitute our given values into the expression above.

A = 2( wl + hl + hw )

A = 2( (16in×20in) + (18in×20in) + (18in×16in) )

A = 2( 320in² + 360in² + 288in² )

A = 2( 968in² )

A = 1936in²

Therefore, the least amount of wrapping paper that Amy needs to wrap the present is 1936in².

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Answer:

1 dime

Step-by-step explanation:

didvide 1 pound by the weight or the dime to get the answer

The correct solution of the given quadratic equation was found using the formula.

The given equation is:

[tex]9x+2=8x^{2} +6x[/tex]

[tex]8x^{2} +6x-9x-2=0[/tex]

[tex]8x^{2} -3x-2=0[/tex]....(1)

An equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where [tex]a\neq 0[/tex].

We can solve equation (1) by the formula

[tex]x=\frac{-b+-\sqrt{b^{2} -4ac} }{2a}[/tex]

So, [tex]x=\frac{3+-\sqrt{(-3)^{2} -4(8)(-2)} }{2(8)}[/tex]

[tex]x=\frac{-3+-\sqrt{73} }{16}[/tex]

Hence, the correct solution of the given quadratic equation was found using the formula.

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Answer:

71.2

Step-by-step explanation:

PEMDAS is Parentheses, Exponent, Multiplication, Addition, Subtraction

This is just the order you do the operations.

First, Parentheses.

Second, Exponents,

Third, Multiplication or Division

Last, Addition or Subtraction

So, in 6 x (2.4 + 10.3) - 5

We first do parentheses which is

(2.4 + 10.3) = 12.7

Now we have,

6 x 12.7 - 5

The next thing is multiplication

6 x 12.7 = 76.2

Now we have,

76.2 - 5

Lastly subtract,

76.2 - 5 = 71.2

t=2 hrs-------so 2 hrs after the second plane leaves it will catch the first plane

CK

720+240*2=600*2

720+480=1200

1200=1200

The volume of the cone and pyramid are the same.

Formula for volume of cone = ⅓(144π × h)

Volume of cone = ⅓[πr² × height of cone)

Volume of triangular pyramid = ⅓[(½bh × height of pyramid)]

Also note the following:

Area of a circle = πr²

Area of a triangle = ½bh

Part A:

Area of circle 1 = πr² = π(12²) = 144π units²

Area of circle 2 = πr² = π(6²) = 36π units²

Area of circle 3 = πr² = π(3²) = 9π units²

Area of triangle 1 = ½(24)(12π) = 144π units²

Area of triangle 2 = ½(12)(6π) = 36π units²

Area of triangle 3 = ½(6)(3π) = 9π units²

Part B: Based on our results in part A, the volumes of the cone and pyramid, having the same height are the same.

Part C:

Volume of pyramid = ⅓(144π × h)

Using this measurement and our conclusion in part B:

Formula for the Volume of a cone = ⅓(144π × h)

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Answer:

30(2+1)

Step-by-step explanation:

Again, find common highest number. It is 30.

60/30 =2

30/30 = 1

so,

30(2+1)

The expression V − E + F is an illustration of the Euler's formula.

The expression V − E + F is always 2

The equation is given as:

V - E + F = 2

Where:

According to the Euler's formula, the relationship between V, E and F is:

V + F = 2 + E

Subtract E from both sides

V - E + F = 2

Hence, the expression V − E + F is always 2

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slope intercept form: y = mx + b    [ where m is slope and b is y-intercept ]

[tex]\dashrightarrow \ \sf9x + 3y = 27[/tex]

[tex]\dashrightarrow \ \sf 3y = 27 -9x[/tex]

[tex]\dashrightarrow \ \sf y = \dfrac{27 -9x}{3}[/tex]

[tex]\dashrightarrow \ \sf y = -3x + 9[/tex]

Here, the "slope is -3"  and  "y-intercept is 9"

Slope intercept form:-

Now convert

Cancel 3

Answer: 5/10 +5/10 =10/10 =1

Step-by-step explanation: I don't think this requires much explanation. Any number with same numerator and denominator equals 1.

When you get 10/10, the first and second box can be figures that sum up to be 10.

It can be 7 and 3, it can be 6 and 4

Answer:

The answer is 20

Step-by-step explanation:

There's two ways in which you can do this. The first one, and the simpliest one is finding the derivative of the equation P(x). After finding the derivative, set the dy/dx to be zero (so set the derivative to be zero). Then solve for x. This should give you the point at which there's no increase or decrease in the value of P, thus meaning the point at which its the maximum.

The second method is simply ploting a graph and finding the highest point.

They are exempt from income tax and we would get the income tax withheld as $340.

The person does not have another source of income, and there are no exceptions that are claimed by the person.

The withheld tax which is held every week can be calculated as;

Amount of income tax = 30 % of 1,166

Amount of income tax = $339.6

Amount of income tax = $340

Hence, they are exempt from income tax and we would get the income tax withheld as $340.

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Explanation:

A rhombus is a parallelogram in which the diagonals are mutual perpendicular bisectors. The coordinates of the vertices can be used to show ...

When both these conditions are met, the quadrilateral is a rhombus.

__

The diagonals will have the same midpoint (bisect each other) if the sum of the coordinates at the ends of one diagonal is the same as the sum of the end point coordinates of the other diagonal:

  A +C = B +D

  (3, 6) +(9, 6) = (6, 8) +(6, 4)

  (3+9, 6 +6) = (6 +6, 8 +4)

  (12, 12) = (12, 12) . . . . . . midpoints are the same; ABCD is a parallelogram

__

The diagonals will be perpendicular if the sum of the products of the coordinate differences of their end points is zero.

  AC⋅BD = (C -A)⋅(D -B) = (9 -3, 6 -6)⋅(6 -6, 4 -8)

  = (6, 0)⋅(0, -4) . . . . . end point differences; we want their dot-product

  = (6)(0) +(0)(-4) = 0 +0 = 0 . . . . diagonals are perpendicular

_____

Additional comment

The midpoints are computed as (A+C)/2 and (B+D)/2. We have multiplied each of them by 2 to simplify the arithmetic. Our resulting sums of (12, 12) must be divided by 2 to get the actual midpoint of the rhombus: (6, 6).

The notion of "dot product" is a vector notion. Two vectors are perpendicular when their dot product is zero. The dot product is the scalar sum of the products of corresponding coordinates.

Answer:

2x^2+10-3x

Step-by-step explanation:

start by multiplying numberes into the parentheses.

2x^2+10-3x-3+3

now combine like terms

2x^2+10-3x

Answer:

$24

Step-by-step explanation:

PRICE=$80

DISCOUNT=70٪ OF $80=(70/100)×80=70×80/100=$56

HENCE DISCOUNT=$56

NOW THE PRICE=$80-$56=$24

I HOPE IT HELPED YOU

Answer: 24

Step-by-step explanation:

Multiply the original price by how much is being discounted.

80 x .70 = 56

Subtract the answer from the original price.

80 - 56 = 24

The factor of the given polynomial are (3x^2-2)(x^2+5)

The polynomial

[tex]3x^4-2x^2+15x^2-10[/tex]

Factoring a polynomial is expressing the polynomial as a product.

The rearranged, grouped, and solved as follows

[tex]3x^4+15x^2-2x^2-10[/tex]

[tex]3x^4+15x^2-(2x^2+10)[/tex]

Factor out the common term

[tex]3x^2(x^2+5)-2(x^2+5)[/tex]

[tex](3x^2-2)(x^2+5)[/tex]

That is the third option is the correct option.

Therefore the factor of the given polynomial are  (3x^2-2)(x^2+5)

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The inequality of the expression is a greater than inequality, and the required inequality is 2x + y > 34

From the question, we have the following representations:

A field goal has 2 points, while a foul shot has 1 point.

So, the number of points in a game is:

Score = 2x + y

The team is behind by 34 points.

So, the team must attain above 34 points

This means that the score must be greater than 34.

So, the inequality is:

2x + y > 34

See attachment for the graph of the inequality

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The quotient of (3x⁴ - 4x² + 8x - 1) ÷ (x - 2) is 3x³ + 6x² + 8x + 24

It can be expressed as 3x³ + 6x² + 8x + 24  + 47 / x - 2

Quotients is the number obtained by dividing one number by another.  

The given expression is;

(3x⁴ - 4x² + 8x - 1) ÷ (x - 2)

Using synthetic division:

(3x⁴ - 4x² + 8x - 1) / (x - 2)  = 3x³ + 6x² + 8x + 24 remainder 47

3x⁴ - 4x² + 8x - 1 → Dividend

x - 2 → Divisor

3x³ + 6x² + 8x + 24 → Quotient

47 → Remainder

The quotient is;

[tex]\rm =\dfrac{3x^4-4x^2+8x-1}{x-2}\\\\=\dfrac{(3x^3 + 6x^2 + 8x + 24)(x-2)}{x-2}\\\\=3x^3 + 6x^2 + 8x + 24[/tex]

Therefore, the quotient of (3x⁴ - 4x² + 8x - 1) ÷ (x - 2) is 3x³ + 6x² + 8x + 24

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The quotient of (3x⁴ - 4x² + 8x - 1) ÷ (x - 2) would be 3x³ + 6x² + 8x + 24.

Quotients are the number that is obtained by dividing one number by another number.

The given expression

(3x⁴ - 4x² + 8x - 1) ÷ (x - 2)

(3x⁴ - 4x² + 8x - 1) / (x - 2)  = 3x³ + 6x² + 8x + 24

remainder is 47

Here,

3x⁴ - 4x² + 8x - 1 = Dividend

x - 2 = Divisor

3x³ + 6x² + 8x + 24 = Quotient

47 = Remainder

The quotient is;

(3x⁴ - 4x² + 8x - 1) / (x - 2)

(3x⁴ - 4x² + 8x +24) (x - 2) / (x - 2)

3x³ + 6x² + 8x + 24

Therefore, the quotient of (3x⁴ - 4x² + 8x - 1) ÷ (x - 2) is 3x³ + 6x² + 8x + 24

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