Sam had 5 fish. She ate 2 how many did she have left

Answer:

2[tex]\pi[/tex] [tex]units^{2}[/tex]

Step-by-step explanation:

BC is equal to 4 because 5*4=20.

The radius is 2. The equation for the area of a circle is [tex]\pi r^2[/tex].

Therefore, if we plug in 2 we will get [tex]4\pi[/tex].

But then we divide by 2 to get 2[tex]\pi[/tex] [tex]units^{2}[/tex] as our answer.

Hope this helped! :)

Answer:

any number goes down 3 places

Step-by-step explanation:

EX:10 to the power of -3 = 0.001

The translation of the sentence "4 times as large as the product of w and 11" to an expression is 44w

From the question, we have the following parameters that can be used in our computation:

“4 times as large as the product of w and 11.”

The number is represented with w

So, the statement remains unchanged as follows

“4 times as large as the product of w and 11.”

4 times as large means 4 *

So, we have the following representation

4 times as large as the product of w and 11 ⇒ 4 * the product of w and 11.

the product of means that we multiply

4 times as large as the product of w and 11 ⇒ 4 * w * 11

Evaluate the products

This gives

4 times as large as the product of w and 11 ⇒ 44w

Hence, the expression is 44w

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Answer: y^2+8x+12

Step-by-step explanation:

Answer:

a. dQ/dt = -kQ

b. [tex]Q = 9e^{-kt}[/tex]

c. k = 0.178

d. Q = 1.063 mg

Step-by-step explanation:

a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.

Let Q be the quantity of drug left in the body.

Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then

-dQ/dt ∝ Q

-dQ/dt = kQ

dQ/dt = -kQ

This is the required differential equation.

b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.

with t = 0, Q(0) = 9 mg

dQ/dt = -kQ

separating the variables, we have

dQ/Q = -kdt

Integrating we have

∫dQ/Q = ∫-kdt

㏑Q = -kt + c

[tex]Q = e^{-kt + c}\\Q = e^{-kt}e^{c}\\Q = Ae^{-kt} (A = e^{c})[/tex]

when t = 0, Q = 9

[tex]Q = Ae^{-kt} \\9 = Ae^{-k0}\\9 = Ae^{0}\\9 = A\\A = 9[/tex]

So, [tex]Q = 9e^{-kt}[/tex]

c) Use the half-life to find the constant of proportionality k.

At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours

So,

[tex]Q = 9e^{-kt}\\4.5 = 9e^{-kX3.9}\\\frac{4.5}{9} = e^{-kX3.9}\\\frac{1}{2} = e^{-3.9k}\\[/tex]

taking natural logarithm of both sides, we have

[tex]ln\frac{1}{2} = ln(e^{-3.9k})\\\\-ln2 = -3.9k\\k = -ln2/-3,9 \\k = -0.693/-3.9\\k = 0.178[/tex]

d) How much of the 9 mg dose is still in the body after 12 hours?

Since k = 0.178,

[tex]Q = 9e^{-0.178t}[/tex]

when t = 12 hours,

[tex]Q = 9e^{-0.178t}\\Q = 9e^{-0.178X12}\\Q = 9e^{-2.136}\\Q = 9 X 0.1181\\Q = 1.063 mg[/tex]

The roots from smallest to greatest are -3, 1, and 5/2 or (2 1/2).

Answer:

-3x-7

Step-by-step explanation:

Let's simplify step-by-step.

−3x−6−1

=−3x+−6+−1

Combine Like Terms:

=−3x+−6+−1

=(−3x)+(−6+−1)

=−3x+−7

Answer:

=−3x−7

Answer:

66

Step-by-step explanation:

[tex]1)\ \frac{28.9}{3.14} = 9.2[/tex]

[tex]2)\ \frac{9.2}{2} = 4.6[/tex]

[tex]3)\ 4.6^2 * 3.14 = 21.16 * 3.14 = 66.4[/tex]

Answer:

The right answer is C ( π/2)

7????

Step-by-step explanation:

Answer:

Step-by-step explanation:

Observe that [tex]y^6-64=y^6-2^6.[/tex]

And you factor out using this expression:

[tex](a^6-b^6)=(a-b)(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5)[/tex]

Take a=y and b=2.

Answer:

(y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)

Step-by-step explanation:

[tex]y^{6}[/tex] - 64 ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

[tex]y^{6}[/tex] - 64

= (y² )³ - 4³

= (y² - 4)([tex]y^{4}[/tex] + 4y + 16) ← note y² - 4 is a difference of squares

= (y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)

Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.

hope this helps!

Answer:

Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.

Step-by-step explanation:

Answer:

A.  x ≥ 21[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

81 - 1[tex]\frac{1}{5}[/tex] x ≤ 55

-1[tex]\frac{1}{5}[/tex] x ≤ 55-81

-[tex]\frac{6}{5 }[/tex] x ≤ -26

x ≥ -26(-[tex]\frac{5}{6}[/tex])       **flip the inequality when you divide by a negative number

x ≥ 21[tex]\frac{2}{3}[/tex]

Answer:

Step-by-step explanation:

Of The Students Who Repo Drinking Alcohol, The Percentage Who Reported Random samples of students at 112 four-year colleges were interviewed  who reported bingeing at least three times within the past two weeks was 42.5% of Estimate the difference between the proportions in 2007 and 1998, and interpret.

answer:

-4

explanation:

when reflected the a will be at -2 in the third quadrant, when moved 2 units to the left you get the y coordinate of -4

hope this helped!

Answer:

it's B.

Step-by-step explanation:

Answer:

its c

Step-by-step explanation:

Answer:

c.    x = -2  or x = -3

Step-by-step explanation:

The vertical asymptotes occur where the denominator = 0.  That happens when the f(x) is undefined.  So,

x^2 + 5x + 6 = 0

(x + 2)(x + 3) = 0

x = -2  or x = -3

Answer:

B) 7

Step-by-step explanation:

-3x³-4x =

-3(-1)³-4(-1) =

-3(-1)+4=

3+4 =7

The lines FE and GH are parallel to each orther.

What is congruent of the triangle?

The shapes maintain their equality regardless of how they are turned, flipped, or rotated before being cut out and stacked. We'll see that they'll be placed entirely on top of one another and will superimpose one another. Due to their identical radius and ability to be positioned directly on top of one another, the following circles are considered to be congruent.

Any two figures can be perfectly positioned over one another to demonstrate their congruence. The relationship between two figures that are said to be congruent is described using the word "congruence."

Given that

ΔPEI = ΔGHI

here ∠pie = ∠gih

PI =HI

GI=EI

So both triangles are congruent

So the FE║GH.

Hence the lines FE and GH are parallel to each orther.

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Answer:

6 the last one

Step-by-step explanation:

4704/6=784

784 squared is 28

making it a perfect square unlike the rest which have excess numbers after the decimal

Answer:

6

Step-by-step explanation:

WHEN YOU DIVIDE 4704 BY 6 YOU GET 784

IN ORDER TO GE THE PERFECT SQUARE YOU HAVE TO FIND THE LCM O 4704

Answer: 12/13, i think

Step-by-step explanation:

Answer:

D. 46.5%

Step-by-step explanation:

I calculated it logically

Answer:

18 × 3 = 54

18 + 54 = 72

Therefore, the answer is 72.

Answer: slope=-5 and y-intercept=1

Step-by-step explanation:

The equation given is in slope-intercept form. Slope-intercept for is y=mx+b, where m is slope and b is y-intercept.

This gives m=-5 and b=1.

Answer: The answer is 9.

Answer:

9

Step-by-step explanation:

4mp + 3n

Given:

m = 2

n = 3

p = 0

Work:

4mp + 3n

4(2)(0) + 3(3)

0 + 9

9

Answer:

19. Add

Step-by-step explanation:

10 - 7 =

13 - 10 =

16 - 13 =

16 + 3 =

Answer:

1. true

2. false

3. false

4. true

Answer:

rational expressions

hope I helped! :)