Saul wants to bike 48 kilometers to taste some really good mangoes.
1. Write an equation that represents how many hours (t) the48km start text, k, m, end text trip will take if Saul bikes at a constant rate of r kilometers per hour.
2. How many hours will the48km48, end text trip take if Saul bikes at a constant rate of 20 kilometers per hour?
hours

a) The lowest cost per tiger is $2.74, according to Company C. (Divide the costs by how many stuffed animals there are; in this case, it's $41.10/15).

b) They would make $2.26 profit for each tiger sold.

You must divide the pricing by the anticipated number of sales to determine how much money customers must pay for each plush toy. For Company C, the calculation would be $41.10 divided by 15. You'll discover that Company C is the least expensive of all the companies when you do that.

By deducting $2.74 from $5, you can calculate their profit.

Although they had to spend $2.74 to purchase the plush animals, they are selling it for $5. $5 - $2.74 = $2.26

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Answer:

$507 958.20

Step-by-step explanation:

11 100 x   table value for 20 years , 8%

11,100 x 45.762 = $ 507,958.20

Answer:

14[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Make equivalent fractions with all the same denominator.  Let's us 12 as our common denominator

[tex]\frac{1}{3}[/tex] x [tex](\frac{4}{4})[/tex] = [tex]\frac{4}{12}[/tex]  Another name for [tex]\frac{4}{4}[/tex] is 1.  (4 divided by 4 is 1)  I am just making an equivalent fraction of [tex]\frac{1}{3}[/tex]

[tex]\frac{3}{4}[/tex] x [tex](\frac{3}{3})[/tex] = [tex]\frac{9}{12}[/tex] another name for [tex]\frac{3}{3}[/tex] is 1 (3 divided by 3 is 1)  I am just making an equivalent fraction of [tex]\frac{3}{4}[/tex].

Now that my denominators are all the same size I can see how many 12's I have.

6 [tex]\frac{4}{12}[/tex] + 4 [tex]\frac{9}{12}[/tex] + 3 [tex]\frac{7}{12}[/tex]  I can rearrange this to add all the whole numbers together and all of the fractions together.

6 + 4 + 3 = 13

[tex]\frac{4}{12}[/tex] + [tex]\frac{9}{12}[/tex] + [tex]\frac{7}{12}[/tex] = [tex]\frac{20}{12}[/tex]  I have 20 12ths.  every [tex]\frac{12}{12}[/tex] makes another whole, so

[tex]\frac{20}{12}[/tex]  1 whole with [tex]\frac{8}{12}[/tex] Left over.  If we put this all together, we have

13 + 1  + [tex]\frac{8}{12}[/tex]

14 [tex]\frac{8}{12}[/tex]  To simplify this.  I will divide [tex]\frac{8}{12}[/tex] ÷ [tex]\frac{4}{4}[/tex] = [tex]\frac{2}{3}[/tex].

the final answer is 14 [tex]\frac{2}{3}[/tex]

Answer:

For the first 15 minutes his average speed is 40 mph. He then stops for 25 minutes. He then completed the journey at an average speed of 45 mph. The total journey time is 1 hour.

Answer:

x = s/(1/q + 1/p)

Step-by-step explanation:

Solve for x:

x/p + x/q = s

Collect in terms of x:

x (1/q + 1/p) = s

Divide both sides by 1/q + 1/p:

Answer: x = s/(1/q + 1/p)

Answer:

The y-intercept is (0, 4/3) and the equation of is y = -1/6x + 4/3. if the y-coordinate of point c is 13, its x-coordinate is -70

The equation of a line in slope-intercept form is y = mx + b

where;

m is the slope

b is the y-intercept

Given the coordinate points (14, -1) and (2, 1)

Slope = 1-(-1)/2-14

Slope = 2/-12

Slope = -1/6

Determine the y-intercept

1 = -1/6(2) + b

1 = -1/3 + b

b = 1 + 1/3

b = 4/3

The given equation of the line is y = -1/6x + 4/3

For the y-intercept

y = -1/6(0) + 4/3

y = 4/3

Hence the y-intercept is (0, 4/3)

For the x-intercept

0 = -1/6(x) + 4/3

1/6x = 4/3

24x = 3

x = 1/8

Hence the x-intercept is (1/8, 0)

If the y-coordinate of point C is 13, hence;

y = -1/6x + 4/3

13 = -1/6x + 4/3

-1/6x = 13 - 4/3

-1/6x = 35/3

-1/2 x = 35

x = -70

The y-intercept is (0, 4/3) and the equation of is y = -1/6x + 4/3. if the y-coordinate of point c is 13, its x-coordinate is -70

The function represents a continuous function because it can be measured and not counted.

The domain is; x ≤ 19 gallons

The range is ; d(x) ≤ 323 miles

We are given the function that represents the distance d(x) in miles that the car can travel with x gallons of gasoline as;

d(x) = 17x

A) The Independent Variable is Number of gallons of gasoline used while the dependent variable is the distance that the car travels.

B) Discrete data is a numerical type of data that includes whole, concrete numbers with specific and fixed data values determined by counting. Continuous data includes complex numbers and varying data values measured over a particular time interval.

Thus, the situation represents a continuous function because it can be measured and not counted.

C) The domain is the set of all possible input values. You have 19 gallons and so the domain is; x ≤ 19 gallons

The range is the set of all possible output values. Thus, the range is;

d(x) ≤ (19 * 17)

d(x) ≤ 323 miles

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the recommended range of water consumption is defined by the compound inequality:

14.84  ≤  x ≤ 38.28

The water utility charges a fixed amount of $38 plus $1.28 per hundred cubic feet of water. So, if you consume x hundred cubic feet of water, the cost is given by the linear relation:

$38 + $1.28*x

Now, this needs to be between $57 and $87 (values included) so we can write the inequality:

$57 ≤  $38 + $1.28*x ≤ $87

Now we just need to solve this for x. If you subtract $38 in both sides you will get:

$57 - $38  ≤  $1.28*x ≤ $87 - $38

$19  ≤  $1.28*x ≤ $49

Now we divide by $1.28 so we get:

$19/$1.28  ≤  x ≤ $49/$1.28

14.84  ≤  x ≤ 38.28

So to be in the recommended range of water consumption, your water consumption x must be in the range:

[14.84, 38, 28]

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Answer:

16

Step-by-step explanation:

Difference means subtract

Let the two numbers be x and y

x-y = 6

Let y be the smaller number

2y = x+4

Using substitution

x = 6+y

2y = 6 +y +4

2y = y+10

Subtract y from each side

2y-y = y+10-y

y = 10

Now we need to find x

x-y = 6

x-10 = 6

Add 10 fo each side

x-10+10 =6+10

x = 16

Answer: -2√10

Step-by-step explanation:

-1√10 - 1√10 = -2√10.

Since they are like terms, you'd simply just collect the two together. Think of it as just doing -1 - 1 = -2 and adding the radical behind the two.

You'd also leave it as √10 because you're unable to break it down or simplify it further than that.

Hope I was able to help you out.

1. The number of people who carried a cell phone or a tablet is 128.

2. The probability that a person carries a cell phone or a tablet is 78.5%.

3. The number of people who carried neither a cell phone nor a tablet is 35.

4. The probability that a person carried neither a cell phone nor a tablet is 21.5%.

5. The number of people who carried a cell phone only is 43.

6. The probability that a person carried a cell phone only is 26.4%.

7. The number of people who carried a tablet but not a cell phone is 38.

8. The probability that a person carried a tablet but not a cell phone is 23.3%.

The sample size of the survey = 163

The number of persons who carried a cell phone = 90

The number of persons who carried a tablet computer = 81

The number of persons who carried both a cell phone and a tablet = 43

1. The number of people who carried a cell phone or a tablet is 128 (90 + 81 - 43).

2. The probability that a person carries a cell phone or a tablet is 78.5%. (128/163).

3. The number of people who carried neither a cell phone nor a tablet is 35 (163 - 128).

4. The probability that a person carried neither a cell phone nor a tablet is 21.5% (35/163).

5. The number of people who carried a cell phone only is 43.

6. The probability that a person carried a cell phone only is 26.4%(43/163).

7. The number of people who carried a tablet but not a cell phone is 38 (81 - 43).

8. The probability that a person carried a tablet but not a cell phone is 23.3% (38/163).

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1. How many people carried a cell phone or a tablet?

2. What is the probability that a person carries a cell phone or a tablet?

3. How many people carried neither a cell phone nor a tablet?

4. What is the probability that a person carried neither a cell phone nor a tablet?

5. How many people carried a cell phone only?

6. What is the probability that a person carried a cell phone only?

7. How many people carried a tablet but not a cell phone?

8. What is the probability that a person carried a tablet but not a cell phone?

Answer:

1,171 miles

Step-by-step explanation:

The trip is 1792 miles.

They have driven (58857 - 58236) miles of the trip so far (because the odometer change is equal to the distance driven).

(58857 - 58236) = 621

They still need to drive 1792 - 621 miles

1792 - 621 = 1171

So they have 1171 miles left until they complete the trip.

Answer:

42

Step-by-step explanation:

because its 42

The best estimation of the current of the jeans is $39.

Percentage is the value per hundredth.Fractions and decimas can be converted into percentage by multiplying them with 100.

According to the given question a pair of jeans was 31 dollars but due to an increase the price went up to 129% of what it was originally.

Let us assume that the new price of the jeans be x dollars.

So, 129% of 31 which is (129/100) is the new price.

∴ (129/100)×31 = x

1.29×31 = x.

x = 39.99 dollars.

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There are 2 pictures.

1. The equation 4x=7(x-3) is x=7.

2. Given ∠2≅∠4 and ∠2 and ∠3 are supplementary. we have proved ∠1≅∠3.

Given that,

There are 2 pictures.

1st picture is

We have to solve the given equation.

Equation is 4x=7(x-3)------> given

4x=7x-21 ---------> multiplying 7 to x and -3

4x-7x=-21

-3x=-21 --------> taking 7x to right side and subtracting 4x and 7x

x=-21/-3

x=7--------> taking -3 to left we get divided by 21, after division we got 7

Therefore, the equation 4x=7(x-3) is x=7.

2nd picture is

We have to prove the statement.

∠2≅∠4 --------> given

m ∠2=m ∠4 --------> angle congruence postulate

∠2 and ∠3 are supplementary ----------> given

m ∠2+m ∠3=180° ---------> Definition of supplementary angles

∠1 and ∠4 are supplementary ------> ∠2 ≅∠4 and ∠2 and ∠3 are supplementary then ∠2 and ∠1 also supplementary then ∠1 and ∠4 are supplementary.

m ∠1+m ∠4=180° --------> Definition of supplementary

m ∠1+m ∠4=m ∠2+m ∠3 ------> from step 4 we can write

m ∠1+m ∠4=m ∠4+m ∠3 -------> we know ∠2≅∠4

m ∠1=m ∠3 --------> ∠4 is remove from both sides.

∠1≅∠3 --------> definition of midpoint

Therefore, the statement is proved.

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The lengths can be used since it's more than the tightrope.

It should be noted that the the length of the tightrope is 15 feet long and the lengths given are 2,6 and 8 feet.

The addition of the lengths will be:

= 2 + 6 + 8

= 16 feet

Therefore, the lengths can be used since it's more than the tightrope. In this case, 26 feet is more than 15 feet.

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The lengths of AB and CD are 12 and 26.5 units

The given parameters are

AB = 2x + 3

BC = 21

CD = 7x - 5

AD = 11x + 10

The points are on line AD

So, we have

AD = AB + BC + CD

This gives

11x + 10 = 2x + 3 + 21 + 7x - 5

Evaluate the like terms

2x = 9

Divide by 2

x  = 4.5

Substitute x  = 4.5 in AB = 2x + 3 and CD = 7x - 5

AB = 2 * 4.5 + 3 = 12

CD = 7 * 4.5 - 5 = 26.5

Hence, the lengths of AB and CD are 12 and 26.5 units

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The correct answer is option c.

Jasmine gave a negative answer for distance.

The number line is the main visual base in statistics and we often want to look at two points on the number line and determine the distance between them. This is used to find the base of a rectangle or another figure that lies above the number line. By the end of this section, you will be able to determine the distance between any two points on a number line that comes from a statistics application.

The absolute value of 5 is 5, because it is 5 units away from 0. A negative number is a number that is less than zero. On a horizontal number line, negative numbers are usually shown to the left of 0. Two numbers are opposites if they are the same distance from 0 and on different sides of the number line.

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Therefore, the value for the algebraic expression 5 / 6 ( 1 / 2 (x) + 6 ) - 3x for x = 12 is -26.

Given algebraic expression is 5/6(1/2 (x) + 6 )-3x

As we know An algebraic expression in mathematics is an expression that consists of variables and constants, along with algebraic operations such as addition, subtraction, etc., and are made up of terms

Solve the expression for x = 12

To solve this algebraic expression we have to substitute the value of x = 12 in an expression as below

= 5 / 6 ( 1 / 2 (x) + 6 ) - 3x

Substitute the value of x in the given expression as below

= 5 / 6 ( 1 / 2 * 12 + 6 ) - 3 * 12

= 5 / 6 ( 6 + 6 )) - 36

= 5 / 6 ( 12 ) - 36

= 5 * 2 - 36

= 10 - 36

= -26

Therefore, the value  for the expression 5 / 6 ( 1 / 2 (x) + 6 ) - 3x for x = 12 is -26.

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[tex]\frac{3}{y}=18 \\ \\ 3=18y \\ \\ y=1/6 \\ \\ \implies y+2=\boxed{13/6}[/tex]

Answer: n=38/3

Step-by-step explanation:

4*(n-10)=(n-2)

4*(n-10)=n-2

4n-40=n-2

3n-40=-2

3n=38

n=38/3

The number n is four times as close to 10 as it is to 2 would be 38/3.

A number pattern is a pattern in a series of numbers that represents the common relationship between the numbers.

The equation form here;

4*(n-10)=(n-2)

4*(n-10)=n-2

4n-40=n-2

3n-40=-2

3n=38

n=38/3

Therefore, The number n is four times as close to 10 as it is to 2 would be 38/3.

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Part 1

∠FBA = 42° (alternate interior angles)

Part 2

∠FDC = 23° (linear pair)

∠BAD = 23° (alternate interior angles)

Part 3

∠AFBA = 115° (sum of angles in a triangle)

Answer:

139/200

Step-by-step explanation:

.695 can be represented as 695/1000. Divide the numerator and denominator by 5, you get 139/200.

Answer: 139/200

Step-by-step explanation:

I am guessing

Answer:

15(16+3) is the right answer

Step-by-step explanation:

mark me brainliest PLS

Answer:  E

Step-by-step explanation:

[tex]\frac{5}{6}(18x^{2} -3x)-\frac{6}{5} (5x^{3} -10x-30x^{2} )[/tex]

[tex]=\frac{5}{6}(18x^{2}) + \frac{5}{6} (-3x) - \frac{6}{5} (5x^{3} )-\frac{6}{5} (-10x)-\frac{6}{5} (-30x^{2} )[/tex]

[tex]= 15x^{2} -\frac{5}{2} x-6x^{3} +12x+36x^{2}[/tex]

[tex]=-6x^{3} + (15x^{2} +36x^{2} )+(-\frac{5}{2}x+12x)[/tex]

[tex]=-6x^{3} + 51x^{2} -\frac{5}{2}x+12x[/tex]

Therefore, the answer is E.

Answer: E.

Step-by-step explanation:

[tex]\displaystyle\\\frac{5}{6} (18x^2-3x)-\frac{6}{5} (5x^3-10x-30x^2)=\\\\\frac{5}{6}(18)(x^ 2)-\frac{5}{6} (3)(x)-\frac{6}{5} (5)(x^3)+\frac{6}{5}(10)(x)+\frac{6}{5} (30)(x^2)=\\\\ \frac{5*18}{6} x^2-\frac{5*3}{6}x -\frac{6*5}{5} x^3+\frac{6*10}{5}x+\frac{6*30}{5} x^2=\\\\5*3*x^2-\frac{5}{2} x-6x^3+6*2*x+6*6*x^2=\\\\15x^2-\frac{5}{2}x-6x^3+12x+36x^2=\\ -6x^3+51x^2-\frac{5}{2} x+12x[/tex]

Answer:

1/27 in^3.

Step-by-step explanation:

1/3 * 1/3 * 1/3

Answer:

x=1 and 4

suppose t=x1.5

We need to know about the perimeter of a rectangle to solve this problem.The length of the field is 131 yards and width is 46 yards.

The perimeter of a rectangle is the summation of it's length and breadth, the longer side of a rectangle is called length and the shorter side is called breadth. The perimeter of a rectangle is given by the formula 2(l+b) where l is the length of the rectangle and b is the breadth of the rectangle. In this question we have been told the perimeter of the rectangular field is 354 yards. The length of the field is 7 yards less than triple the width. Let the width of the field be x yard, then the length is

length=3x-7

Then perimeter in terms of x= 2(l+b)=2((3x-7)+x)=2(4x-7)=8x-14

8x-14=354

8x=368

x=46

Then breadth=46 yards

length =3x-7=138-7=131 yards

Therefore we found out the dimensions of the field to be, the length is 131 yards and breadth is 46 yards.

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