Select the locations on the number line to plot the points 1, 4, and −3.

Select The Locations On The Number Line To Plot The Points 1, 4, And 3.

Answers

Answer 1

The locations of the points on the number line are:

point 1: 1 step to the right of 0.

point 4: 4 steps to the right of 0.

point -3:  3 steps to the left of 0

How to select the locations on the number line to plot points?

A number lines is an horizontal straight line in which the integers are placed in equal intervals.

All positive numbers on the number line are on the right side of zero while the negative numbers are on the left side of zero.

To locate 1: starting from 0, count 1 step to the right.

To locate 4: starting from 0, count 4 steps to the right.

To locate -3: starting from 0, count 3 steps to the left.

Check the attached image to see the points.

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Select The Locations On The Number Line To Plot The Points 1, 4, And 3.

Related Questions

By which number 4704 must be divided so as to obtain a perfect square​

Answers

Answer:

6 the last one

Step-by-step explanation:

4704/6=784

784 squared is 28

making it a perfect square unlike the rest which have excess numbers after the decimal

Answer:

6

Step-by-step explanation:

WHEN YOU DIVIDE 4704 BY 6 YOU GET 784

IN ORDER TO GE THE PERFECT SQUARE YOU HAVE TO FIND THE LCM O 4704

y to the -3 power
pls help!!!!!!!!!

Answers

Answer:

any number goes down 3 places

Step-by-step explanation:

EX:10 to the power of -3 = 0.001

If f(x)=2x^3−x^2−16x+15 and f(−3)=0, list all of the zeros from least to greatest

x=
x=
x=

Answers

The roots from smallest to greatest are -3, 1, and 5/2 or (2 1/2).

brainliest
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Answers

3/7 because you divide both by 11 :)

Solve this inequality for x.

Answers

Answer:

A.  x ≥ 21[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

81 - 1[tex]\frac{1}{5}[/tex] x ≤ 55

-1[tex]\frac{1}{5}[/tex] x ≤ 55-81

-[tex]\frac{6}{5 }[/tex] x ≤ -26

x ≥ -26(-[tex]\frac{5}{6}[/tex])       **flip the inequality when you divide by a negative number

x ≥ 21[tex]\frac{2}{3}[/tex]

Equations of Exponential Functions

Given the following equations of an exponential function
R = 10.5(0.535)t
determine the decay rate.

a. 0.535%
b. 10.5%
c. 50%
d. 46.5%

Please select the best answer from the choices provided

Answers

Answer:

D. 46.5%

Step-by-step explanation:

I calculated it logically

A pizza shop sold 18 medium pizzas. The number of large pizzas sold was 3 times as many as the number of medium pizzas sold. How many pizzas did the pizza shop sell altogether?

Answers

Answer:

18 × 3 = 54

18 + 54 = 72

Therefore, the answer is 72.

18x3 +18 = 54+ 18 = 72. 72 pizzas were sold

factorise y^6 - 64 as possible

Answers

Answer:

Step-by-step explanation:

Observe that [tex]y^6-64=y^6-2^6.[/tex]

And you factor out using this expression:

[tex](a^6-b^6)=(a-b)(a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5)[/tex]

Take a=y and b=2.

Answer:

(y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)

Step-by-step explanation:

[tex]y^{6}[/tex] - 64 ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

[tex]y^{6}[/tex] - 64

= (y² )³ - 4³

= (y² - 4)([tex]y^{4}[/tex] + 4y + 16) ← note y² - 4 is a difference of squares

= (y - 2)(y + 2)([tex]y^{4}[/tex] + 4y + 16)

Please help I was sick and missed out on class thank you.

Answers

Answer: slope=-5 and y-intercept=1

Step-by-step explanation:

The equation given is in slope-intercept form. Slope-intercept for is y=mx+b, where m is slope and b is y-intercept.

This gives m=-5 and b=1.

Random samples of students at ​four-year colleges were interviewed several times since . Of the students who reported ​, the percentage who reported bingeing at least three times within the past two weeks was ​% of students in and of students in a. Estimate the difference between the proportions in and ​, and interpret. b. Find the standard error for this difference. Interpret it. c. Define the two relevant population parameters to compare in the context of this exercise. d. Construct and interpret a ​% confidence interval to estimate the true difference. e. State the assumptions for the confidence interval in part d to be valid.

Answers

Answer:

Step-by-step explanation:

Of The Students Who Repo Drinking Alcohol, The Percentage Who Reported Random samples of students at 112 four-year colleges were interviewed  who reported bingeing at least three times within the past two weeks was 42.5% of Estimate the difference between the proportions in 2007 and 1998, and interpret.

Restrictions must be indicated for rational functions involving a denominator because__________
is not defined​

Answers

Answer:

rational expressions

hope I helped! :)

Ignore the blue dots they are wrong

Answers

Answer:

1. true

2. false

3. false

4. true

1.true. 2.false. 3.false. 4.true.

Help please look at picture no links!!

Answers

Answer:

66

Step-by-step explanation:

[tex]1)\ \frac{28.9}{3.14} = 9.2[/tex]

[tex]2)\ \frac{9.2}{2} = 4.6[/tex]

[tex]3)\ 4.6^2 * 3.14 = 21.16 * 3.14 = 66.4[/tex]

What is the value of x?

sin49°=cosx

Answers

Answer : x=41 degrees

PLEASE someone help

Answers

7????

Step-by-step explanation:

Use the graph of the function,

f(x)=x-1/x^2+5x+6

to identify the function's
vertical asymptotes.

a. x=-1, x= 6
b. x=1, x=-6
c. x=-2, x=-3
d. X= 2, x= 3

Answers

Answer:

c.    x = -2  or x = -3

Step-by-step explanation:

The vertical asymptotes occur where the denominator = 0.  That happens when the f(x) is undefined.  So,

x^2 + 5x + 6 = 0

(x + 2)(x + 3) = 0

x = -2  or x = -3

Evaluate -3x³-4x for x = -1.
A)-1
B)7
C)1

Answers

Answer:

B) 7

Step-by-step explanation:

-3x³-4x =

-3(-1)³-4(-1) =

-3(-1)+4=

3+4 =7

Explain the cyclin-dependent regulation
cell cycle

Answers

Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.

hope this helps!

Answer:

Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.

Step-by-step explanation:

If m = 2, n = 3 and p = 0; then what is the value of 4mp + 3n​

Answers

Answer: The answer is 9.

Answer:

9

Step-by-step explanation:

4mp + 3n

Given:

m = 2

n = 3

p = 0

Work:

4mp + 3n

4(2)(0) + 3(3)

0 + 9

9

Which expression is equivalent to -51 - (-60)−51−(−60)minus, 51, minus, left parenthesis, minus, 60, right parenthesis?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
-60+(-51)−60+(−51)minus, 60, plus, left parenthesis, minus, 51, right parenthesis

(Choice B)
B
60+5160+5160, plus, 51

(Choice C)
C
51-6051−6051, minus, 60

(Choice D)
D
-51+60−51+60minus, 51, plus, 60

Answers

Answer:

it's B.

Step-by-step explanation:

Answer:

its c

Step-by-step explanation:

Hydrocodone bitartrate is used as a cough suppressant. After the drug is fully absorbed, the quantity of drug in the body decreases at a rate proportional to the amount left in the body, with constant of proportionality k. Suppose that the half-life of hydrocodone bitartrate in the body is 3.9 hours, and that the oral dose taken is 9 mg.
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
c) Use the half-life to find the constant of proportionality k.
d) How much of the 9 mg dose is still in the body after 12 hours?

Answers

Answer:

a. dQ/dt = -kQ

b. [tex]Q = 9e^{-kt}[/tex]

c. k = 0.178

d. Q = 1.063 mg

Step-by-step explanation:

a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.

Let Q be the quantity of drug left in the body.

Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then

-dQ/dt ∝ Q

-dQ/dt = kQ

dQ/dt = -kQ

This is the required differential equation.

b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.

with t = 0, Q(0) = 9 mg

dQ/dt = -kQ

separating the variables, we have

dQ/Q = -kdt

Integrating we have

∫dQ/Q = ∫-kdt

㏑Q = -kt + c

[tex]Q = e^{-kt + c}\\Q = e^{-kt}e^{c}\\Q = Ae^{-kt} (A = e^{c})[/tex]

when t = 0, Q = 9

[tex]Q = Ae^{-kt} \\9 = Ae^{-k0}\\9 = Ae^{0}\\9 = A\\A = 9[/tex]

So, [tex]Q = 9e^{-kt}[/tex]

c) Use the half-life to find the constant of proportionality k.

At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours

So,

[tex]Q = 9e^{-kt}\\4.5 = 9e^{-kX3.9}\\\frac{4.5}{9} = e^{-kX3.9}\\\frac{1}{2} = e^{-3.9k}\\[/tex]

taking natural logarithm of both sides, we have

[tex]ln\frac{1}{2} = ln(e^{-3.9k})\\\\-ln2 = -3.9k\\k = -ln2/-3,9 \\k = -0.693/-3.9\\k = 0.178[/tex]

d) How much of the 9 mg dose is still in the body after 12 hours?

Since k = 0.178,

[tex]Q = 9e^{-0.178t}[/tex]

when t = 12 hours,

[tex]Q = 9e^{-0.178t}\\Q = 9e^{-0.178X12}\\Q = 9e^{-2.136}\\Q = 9 X 0.1181\\Q = 1.063 mg[/tex]

To find the next number in the sequence: 7, 10, 13, 16, ____ you would need to do which of the following?

Answers

The number after 16 is 19. You add 3 each time .

Answer:

19. Add

Step-by-step explanation:

10 - 7 =

13 - 10 =

16 - 13 =

16 + 3 =


The greatest value of 7x would be?

Answers

Answer: 70

Step-by-step explanation:

the correct answer is 70

Factor the expression y^2+8x+12

Answers

Answer: y^2+8x+12

Step-by-step explanation:

Does anyone know how to solve this?

Answers

Answer:

The right answer is C ( π/2)

Lisette wrote the following algebraic expression to represent “4 times as large as the product of w and 11.”

Answers

The translation of the sentence "4 times as large as the product of w and 11" to an expression is 44w

How to translate the algebraic sentence to an expression

From the question, we have the following parameters that can be used in our computation:

“4 times as large as the product of w and 11.”

The number is represented with w

So, the statement remains unchanged as follows

“4 times as large as the product of w and 11.”

4 times as large means 4 *

So, we have the following representation

4 times as large as the product of w and 11 ⇒ 4 * the product of w and 11.

the product of means that we multiply

4 times as large as the product of w and 11 ⇒ 4 * w * 11

Evaluate the products

This gives

4 times as large as the product of w and 11 ⇒ 44w

Hence, the expression is 44w

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BC is the diameter of the semicircle. The area of rectangle ABCD is 20 and the length of line AB is 5.What is the area of the semicircle?

Answers

Answer:

2[tex]\pi[/tex] [tex]units^{2}[/tex]

Step-by-step explanation:

BC is equal to 4 because 5*4=20.

The radius is 2. The equation for the area of a circle is [tex]\pi r^2[/tex].

Therefore, if we plug in 2 we will get [tex]4\pi[/tex].

But then we divide by 2 to get 2[tex]\pi[/tex] [tex]units^{2}[/tex] as our answer.

Hope this helped! :)

what is the trigonometric ratio for cos n ​

Answers

Answer: 12/13, i think

Step-by-step explanation:

-3x-6+(-1)
i will give brainliest !

Answers

Answer:

-3x-7

Step-by-step explanation:

Let's simplify step-by-step.

−3x−6−1

=−3x+−6+−1

Combine Like Terms:

=−3x+−6+−1

=(−3x)+(−6+−1)

=−3x+−7

Answer:

=−3x−7

if you do on the side like how i did it helps if u need help finding if the final answer is a positive or a negative when doing questions like this :)

I need to know the first and last one

Answers

The lines FE and GH are parallel to each orther.

What is congruent of the triangle?

The shapes maintain their equality regardless of how they are turned, flipped, or rotated before being cut out and stacked. We'll see that they'll be placed entirely on top of one another and will superimpose one another. Due to their identical radius and ability to be positioned directly on top of one another, the following circles are considered to be congruent.

Any two figures can be perfectly positioned over one another to demonstrate their congruence. The relationship between two figures that are said to be congruent is described using the word "congruence."

Given that

ΔPEI = ΔGHI

here ∠pie = ∠gih

PI =HI

GI=EI

So both triangles are congruent

So the FE║GH.

Hence the lines FE and GH are parallel to each orther.

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