Senior management of a consulting services firm is concerned about a growing decline in the firm's weekly number of billable hours. The firm expects each professional employee to spend at least 40 hours per week on work. In an effort to understand this problem better, management would like to estimate the standard deviation of the number of hours their employees spend on work-related activities in a typical week. Rather than reviewing the records of all the firm's full-time employees, the management randomly selected a sample of size 51 from the available frame. The sample mean and sample standard deviations were 48. 5 and 7. 5 hours, respectively. Construct a 88% confidence interval for the mean of the number of hours this firm's employees spend on work-related activities in a typical week. Place your LOWER limit, in hours, rounded to 1 decimal place, in the first blank. For example, 6. 7 would be a legitimate entry. ___ Place your UPPER limit, in hours, rounded to 1 decimal place, in the second blank. For example, 12. 3 would be a legitimate entry. ___

F(4) = 16 - 8 In(4) = 8 - 4 In(2)

So the global minimum value is F(2) ≈ -2.6137 and the global maximum value is F(1) = 1 (since F(4) is not greater than 1).

To find the global minimum and maximum of the continuous function F(x) = x^2 - 8 In(x) on the interval [1, 4], we need to find the critical points of the function and evaluate the function at those points and at the endpoints of the interval.

First, we take the derivative of the function:
F'(x) = 2x - 8/x

Setting F'(x) = 0, we get:
2x - 8/x = 0
Multiplying both sides by x, we get:
2x^2 - 8 = 0
Dividing both sides by 2, we get:
x^2 - 4 = 0
Factoring, we get:
(x + 2)(x - 2) = 0

So the critical points are x = -2 and x = 2. However, x = -2 is not in the interval [1, 4], so we only need to consider x = 2.

Now we evaluate the function at the critical point and the endpoints of the interval:
F(1) = 1 - 8 In(1) = 1
F(2) = 4 - 8 In(2) ≈ -2.6137
F(4) = 16 - 8 In(4) = 8 - 4 In(2)

So the global minimum value is F(2) ≈ -2.6137 and the global maximum value is F(1) = 1 (since F(4) is not greater than 1).

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With all of the edges 6 feet long, the total surface area of the greenhouse including the floor is approximately 98.39 ft².

To find the total surface area of Reina's greenhouse, we'll need to calculate the area of the equilateral triangular sides and the square base.

1. Equilateral triangular sides:
There are four congruent equilateral triangles with edges of 6 feet each. To find the area of one triangle, we can use the formula A = (s² * √3) / 4, where A is the area and s is the side length.

A = (6² * √3) / 4 = (36 * √3) / 4 = 9√3 square feet

Since there are four triangles, the total area of the triangular sides is 4 * 9√3 = 36√3 square feet.

2. Square base:
The base is a square with side lengths of 6 feet. To find the area, we can use the formula A = s².

A = 6² = 36 square feet

Now, let's add the area of the triangular sides and the square base

Total surface area = 36√3 + 36 ≈ 98.39 ft² (rounded to the nearest hundredth)

So, the total surface area of the greenhouse including the floor is approximately 98.39 ft².

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Using a calculator, we can evaluate ln 0.732 to four decimal places. The correct answer is option D, -0.4719.

The natural logarithm of a number is the logarithm to the base e (approximately 2.71828), and ln 0.732 is the natural logarithm of the number 0.732.

To find the value of ln 0.732, we simply input the number into the calculator and hit the ln key.

The result is approximately -0.4719, rounded to four decimal places. Therefore, the correct answer is D, -0.4719.

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The critical values are x = -4 and x = 2.

Given the function f(x) = (2-x)(x+4)^2, we need to find the critical values.

Critical values are the points where the derivative of the function is either zero or undefined.

Step 1: Find the derivative of f(x). f'(x) = d/dx((2-x)(x+4)^2)

Step 2: Apply the product rule, which states d(uv) = u*dv + v*du,

where u = (2-x) and v = (x+4)^2. f'(x) = (2-x)*d/dx((x+4)^2) + (x+4)^2*d/dx(2-x)

Step 3: Compute the individual derivatives. f'(x) = (2-x)*(2(x+4)) + (x+4)^2*(-1)

Step 4: Simplify the expression. f'(x) = -2(x+4)^2 + 4(x+4)(2-x)

Step 5: Set f'(x) equal to 0 and solve for x. 0 = -2(x+4)^2 + 4(x+4)(2-x)

Step 6: Factor out a common term. 0 = 2(x+4)[-1(x+4) + 2(2-x)]

Step 7: Solve for x. 0 = 2(x+4)(-x+2) x = -4, 2 The critical values are x = -4 and x = 2.

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The total number of outcomes for the compound event is m*n

option B.

The Fundamental Counting Principle states that if there are m ways to do one thing and n ways to do another thing, then there are m*n ways to do both things together.

This applies to compound events that consist of two or more independent events.

For example, suppose you have two dice and you want to know how many possible outcomes there are when you roll them. Each die has 6 possible outcomes, so by the Fundamental Counting Principle, the total number of outcomes for the compound event is 6*6 = 36.

So, for any two independent events with m and n outcomes, respectively, the total number of outcomes for the compound event is m*n.

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If there is no substrate present, the concentration of s would be 0.  The relative growth rate of biomass at time t, R, is related to the concentration of a substrate s at time t by the equation R(s) = cs / (k+s), where c and k are positive constants.

To find the relative growth rate of the biomass if there is no substrate present, we need to set the concentration of the substrate, s, to 0. Using the given equation, we can substitute 0 for s:

R(0) = c(0) / k + 0

R(0) = 0 / k

R(0) = 0

Therefore, the relative growth rate of the biomass would be 0 if there is no substrate present.
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Answer:For each figure, which pair of angles appears congruent? How could you check?

Figure 1

3 angles. Angle A B C opens to the right, angles D E F and G H L open up.

Figure 2

3 angles. Angles M Z Y and P B K open up, angle R S L opens to the right.

Figure 3

Identical circles. Circle V with central angle GVD opens to the right, circle J with central angle LJX  opens to the left and circle N with central angle CNE opens up.

Figure 4

A figure of 3 circles. H. B. E.

Step-by-step explanation:

Particular solution is: f(x) = (0.25/24) x⁹ - 6553.3333 x + 2

We need to integrate it twice. Integrating once gives us:

f'(x) = (0.25/3) x⁸ + C1

where C1 is the constant of integration. Using the initial condition f'(4) = 8, we can solve for C1:

8 = (0.25/3) 4⁸ + C1
C1 = 8 - (0.25/3) 4⁸
C1 = -6553.3333

Integrating again gives us:

f(x) = (0.25/24) x⁹ + C1 x + C2

where C2 is another constant of integration. Using the initial condition f(0) = 2, we can solve for C2:

2 = (0.25/24) 0⁹ + C1 0 + C2
C2 = 2

So the particular solution is:

f(x) = (0.25/24) x⁹ - 6553.3333 x + 2

Note that we did not need to use the second initial condition, f'(4) = 8, to find the particular solution. This is because it was already used to find the constant of integration C1.

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The solution to the system of equations shown above is the ordered pairs [-2, -9] and [3, -4].

In order to graph the solution to the given system of equations on a coordinate plane, we would use an online graphing calculator to plot the given system of equations and then take note of the point of intersection;

y = -x² + 2x - 1   ......equation 1.

2x - 2y = 14 ......equation 2.

Based on the graph shown in the image attached above, we can logically deduce that the solution to this system of equations is the point of intersection of the lines on the graph representing each of them, which is given by the ordered pairs (-2, -9) and (3, -4).

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The circumference of the brim of Arnold's hat is 37.68 inches.

What is circle?

A circle is a geometric shape that consists of all points in a plane that are equidistant from a fixed point called the center. It can also be defined as the set of points that are a fixed distance (called the radius) away from the center point. The distance around the circle is called its circumference, and the distance across the circle passing through the center is called its diameter.

The circumference of a circle can be calculated by the formula C = πd, where C is the circumference, π is the mathematical constant pi, and d is the diameter of the circle.

In this case, the diameter of the brim is 12 inches, so we can substitute that value into the formula:

C = πd

C = 3.14 x 12

C = 37.68

Therefore, the circumference of the brim of Arnold's hat is 37.68 inches.

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The quadratic function in vertex form is y = (8/9)(x - 5)^2 + 7

The vertex form of a quadratic function is given by:

y = a(x - h)^2 + k

where (h, k) is the vertex of the parabola.

In this case, we are given that the vertex is (5, 7), so we can write:

y = a(x - 5)^2 + 7

To find the value of a, we can use one of the points on the parabola.

Let's use the point (2, 15):

15 = a(2 - 5)^2 + 7

8 = 9a

a = 8/9

Substituting this value of a into the equation above, we get:

y = (8/9)(x - 5)^2 + 7

Therefore, the quadratic function in vertex form is y = (8/9)(x - 5)^2 + 7

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The value of the arc is approximately 14.3 cm.

We are given that;

The angle = 62, 20

Now,

To find the value of arc if angle is 82 degrees

Step 1: Convert the angle from degrees to radians

Angle in radians = Angle in degrees x π/180 Angle in radians = 82 x π/180 Angle in radians ≈ 1.43

Step 2: Multiply the angle by the radius

Arc length = Angle x Radius Arc length = 1.43 x 10 Arc length ≈ 14.3 cm

Therefore, by the arc length the answer will be approximately 14.3 cm.

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Mrs. Kwon used 107/8 yards of the total fabric length for Sun's and Jin's costume.

Firstly we will convert the mixed fraction to fraction. The length of fabric of Sun's costume = ((5×2)+1)/2

Length of fabric of Sun's costume = 11/2 yards

The length of fabric of Jin's costume = ((8×7)+7)/8

Length of fabric of Jin's costume = 63/8 yards

Total length of fabric used = Length of fabric of Sun's costume + Length of fabric of Jin's costume

Total length of fabric used = 11/2 + 63/8

Taking LCM we get-

Total length of fabric used = (11×4)+63/8

Multiply the values

Total length of fabric used = 44 + 63/8

Add the digits

Total length = 107/8 yards

Hence, she used 107/8 yards total fabric.

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The sum of the geometric series for the converging x values in the range -2 < x < 10 is 3. Hi! I'd be happy to help you find the sum of the given geometric series.

The geometric series converges if the common ratio, r, satisfies |r| < 1. In this case, the common ratio r is ((x-4)/6). Thus, we need to find the x values for which:

-1 < (x-4)/6 < 1

Multiplying all sides by 6, we get:

-6 < x-4 < 6

Adding 4 to all sides, we find the range of x:

-2 < x < 10

Now that we have the range for which the series converges, we can find the sum of the series. The sum of an infinite geometric series is given by the formula:

S = a / (1 - r)

Here, 'a' is the first term, which is (-1)^0 * ((x-4)/6)^0 = 1, and 'r' is ((x-4)/6). Plugging in the values, we get:

S = 1 / (1 - (x-4)/6)

Simplifying the denominator, we get:

S = 1 / (2/6) = 1 / (1/3) = 3

So, the sum of the geometric series for the converging x values in the range -2 < x < 10 is 3.

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Answer:

Step-by-step explanation:

Since it is x that is bound by 5≤x≤8, you should use the points (5,10) and (8,1), since a coordinate is written as (x,y).

Then, use the formula for slope, as the average rate of change means find the slope, [tex]\frac{y2-y1}{x2-x1}[/tex]

thus, plug in

[tex]\frac{1-10}{8-5}[/tex], and you get -9/3, or -3. :)

Answer:If the letters are 2 inches high in the sketch, and you want them to be 2 feet high in reality, that means you need to scale up the letters by a factor of 12 (since 1 foot = 12 inches).

So the new height of each letter will be:

2 inches/letter × 12 = 24 inches/letter

And the new length of the banner will be:

20 inches/banner × 12 = 240 inches/banner

To find out how much paper to buy, you need to know the width of the paper you'll be using. Let's say the paper is 36 inches wide (3 feet). In that case, you'll need to buy:

240 inches/banner ÷ 36 inches/roll = 6.67 rolls of paper

Since you can't buy a fraction of a roll of paper, you should round up to 7 rolls of paper to ensure you have enough.

Step-by-step explanation:

The standard deviation in the first sample was $20,00 and the standard deviation in the second sample is $18,000 so the agent's claim cannot be rejected at the 0.05 level of significance.

To test the agent's claim, we can perform a two-sample t-test with a significance level of 0.05. The null hypothesis is that there is no difference in the mean salaries of safeties and linebackers, while the alternative hypothesis is that there is a difference.

We can calculate the t-statistic using the formula:

t = (x1 - x2) / sqrt(s1²/n1 + s2²/n2)

where x1 and x2 are the sample means, s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.

Plugging in the given values, we get:

t = (501580 - 513360) / sqrt((20000²/15) + (18000²/15))

t = -1.2605

Using a t-distribution table with 28 degrees of freedom (15 + 15 - 2), we find that the critical value for a two-tailed test at a significance level of 0.05 is approximately ±2.048.

Since the absolute value of the calculated t-statistic (1.2605) is less than the critical value (2.048), we fail to reject the null hypothesis. Therefore, there is not enough evidence to conclude that there is a difference in the mean salaries of safeties and linebackers in the NFL.

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The required answers are  2.5 liters and  1.5 liters per minute.

Part A:

If we know that the pot has a capacity of 10 liters, we can use the equation y = 1.5x + 2.5 to determine how much soup was in the pot to start with, since at x = 0 minutes, no soup has been added yet.

Substituting x = 0 in the equation, we get:

y = 1.5(0) + 2.5

y = 2.5

Therefore, the pot had 2.5 liters of soup to start with.

Part B:

The equation y = 1.5x + 2.5 tells us how much soup is added to the pot in x minutes, so the rate at which the cook fills the pot can be found by taking the derivative of y with respect to x:

dy/dx = 1.5

Therefore, the rate at which the cook fills the pot is 1.5 liters per minute.

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(a) The first derivative of f is f'(x) = 3x² - 15.

(b) The second derivative of f is f''(x) = 6x.

(c) f is increasing on the interval (-∞, √5) and decreasing on the interval (√5, ∞).

(d) f is decreasing on the interval (-∞, √5) and increasing on the interval (√5, ∞).

(e) f is concave downward on the interval (-∞, 0) and concave upward on the interval (0, ∞).

(a) To find the first derivative of f, we differentiate each term of the function with respect to x using the power rule. Thus, f'(x) = 3x² - 15.

(b) To find the second derivative of f, we differentiate f'(x) with respect to x. Thus, f''(x) = 6x.

(c) To determine the intervals where f is increasing, we set f'(x) > 0 and solve for x. Thus, 3x² - 15 > 0, which simplifies to x² > 5. Therefore, x is in the interval (-∞, √5) or (√5, ∞). To determine which interval makes f increasing, we can test a point within each interval.

For example, when x = 0, f'(0) = -15, which is negative, so f is decreasing on (-∞, √5). When x = 10, f'(10) = 285, which is positive, so f is increasing on (√5, ∞). Thus, f is increasing on the interval (√5, ∞) and decreasing on the interval (-∞, √5).

(d) To determine the intervals where f is decreasing, we set f'(x) < 0 and solve for x. Thus, 3x² - 15 < 0, which simplifies to x² < 5. Therefore, x is in the interval (-∞, √5) or (√5, ∞). Again, we can test a point within each interval to determine which one makes f decreasing.

For example, when x = 0, f'(0) = -15, which is negative, so f is decreasing on (-∞, √5). When x = 10, f'(10) = 285, which is positive, so f is increasing on (√5, ∞). Thus, f is decreasing on the interval (-∞, √5) and increasing on the interval (√5, ∞).

(e) To determine the intervals of concavity, we examine the sign of the second derivative of f. If f''(x) > 0, then f is concave upward, and if f''(x) < 0, then f is concave downward. If f''(x) = 0, then the concavity changes. Thus, we set f''(x) > 0 and f''(x) < 0 and solve for x. We get f''(x) > 0 when x > 0 and f''(x) < 0 when x < 0.

Therefore, f is concave upward on (0, ∞) and concave downward on (-∞, 0).

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Hello, I am Alyssa Ann Verrett.

Put the numbers in order:

City A: {2, 3.5, 4, 4, 5, 5.5}

City B: {3.5, 4, 5, 5.5, 6, 6}

a)

The mean monthly rainfall amount for city A: 4 in;

The mean monthly rainfall amount for city B: 5 in;

b)

The MAD monthly rainfall amount for city A: 0.8 in;

The MAD monthly rainfall amount for city B: 0.8 in;

c)

The median monthly rainfall amount for city A: 4 in;

The median monthly rainfall amount for city A: 5.25 in;

Step-by-step explanation:

a) The general definition of mean of a set X is:

mean = (x₁ + x₂ + x₃ + ... xₙ)/n

For City a:

mean = (4+3.5+5+5.5+4+2)/6 = 4

For City b:

mean = (5+6+3.5+5.5+4+6)/6 = 5

b) The general definition of mean absolute deviation of a set X is:

MAD = (|x₁-mean| + |x₂-mean| + |x₃-mean| + ... + |xₙ-mean|)/n

For City a:

MAD = ( |4-4| + |3.5-4| + |5-4| + |5.5-4| + |4-4| + |2-4| )/6 = (0 + 0.5 + 1 + 1.5 + 0 + 2)/6 = 5/6 =0.8

For City b:

MAD = ( |5-5| + |6-5| + |3.5-5| + |5.5-5| + |4-5| + |6-5| )/6 = (0 + 1 + 1.5 + 0.5 + 1 + 1)/6 = 5/6 = 0.8

c) The general definition of median depends on the quantity of elements in the set X and it represents the middlemost value of the set:

When the quantity is odd:

median= x₍ₙ₊₁₎/₂

When the quantity is even:

median= (xₙ/₂ + x ₙ₊₂/₂) /2

For City A:

median = 2, 3.5, 4, 4, 5, 5.5 = (4 + 4) / 2 = 4

For City B:

median = 3.5, 4, 5, 5.5, 6, 6 = (5 + 5.5) / 2 = 5.25

The formula for calculating the amount of money in an account with continuous compounding is:

[tex]A = Pe^{(rt)}[/tex]

where A is the amount of money in the account, P is the principal (initial deposit), e is the mathematical constant e (approximately equal to 2.71828), r is the interest rate (expressed as a decimal), and t is the time (in years).

Plugging in the given values, we get:

A =[tex]40000 * e^{(0.025 * 8)[/tex]

Using a calculator, we find that [tex]e^{(0.025 * 8)[/tex] is approximately 1.2214, so:

A = 40000 * 1.2214 = $48,856.12

Therefore, the amount of money in the account after eight years with continuous compounding is $48,856.12.

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If a big sheet of white paper has a red dot in the center, the red dot is the  figure or object, and the white space is the ground or background.

In visual perception, the figure-ground relationship is the process by which our brains distinguish an object( the figure) from its surroundings( the ground).

This relationship is essential in our capability to fete and make sense of the visual world around us. The figure is the object of interest or focus, while the ground is the background against which it stands out.

The red dot becomes the focal point or center of attention, while the white space around it provides environment and contrast, making the dot more visible and commanding.

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The exact value of the double integral ∫∫D 2xy dA is 0.

To evaluate the double integral ∫∫D 2xy dA, where D is the region between the circles of radius 2 and 5 centered at the origin that lies in the first quadrant, we need to use polar coordinates.

In polar coordinates, the region D is defined by 2 ≤ r ≤ 5 and 0 ≤ θ ≤ π/2. The double integral can be expressed as:

∫∫D 2xy dA = ∫θ=0^(π/2) ∫r=[tex]2^5 2r^3[/tex] cosθ sinθ dr dθ

Solving the inner integral with respect to r, we get:

∫r=[tex]2^5[/tex] 2[tex]r^3[/tex] cosθ sinθ dr = [r^4 cosθ sinθ]_r=[tex]2^5 = 5^4[/tex] cosθ sinθ - [tex]2^4[/tex] cosθ sinθ

Substituting this result into the double integral expression and solving the remaining integral with respect to θ, we get:

∫∫D 2xy dA = ∫θ=0^(π/2) (5^4 cosθ sinθ - 2^4 cosθ sinθ) dθ

= [5^4/2 sin(2θ) - 2^4/2 sin(2θ)]_θ=0^(π/2)

= (5^4/2 - 2^4/2) sin(π) - 0

= (5^4/2 - 2^4/2) * 0

= 0

Therefore, the exact value of the double integral ∫∫D 2xy dA is 0.

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A finite minimal spanning set of a vector space V is a set S that satisfies the following properties:

In other words, S is the smallest set of vectors that can be used to generate V. If we remove any vector from S, the resulting set will not be able to generate V anymore.

The concept of a finite minimal spanning set is important in linear algebra, particularly in the context of basis and dimension. A basis is a linearly independent spanning set of a vector space V.

A finite minimal spanning set is also a basis of V. The dimension of a vector space is the number of vectors in any basis of V. Since a finite minimal spanning set is a basis, the dimension of V is equal to the number of vectors in S.

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Full Question: Let S be a finite minimal spanning set of a vector space V. That is, S has the property that if a vector is removed from S, then the new set will no longer span V. Prove that S must be a basis for V.

Let’s solve this system of equations. From the first equation, we have x = 6 + 2y. Substituting this into the second equation, we get 1/2(6 + 2y) + 3 = y. Solving for y, we get y = -6. Substituting this value of y into the first equation, we get x = 6 + 2(-6) = -6. So the solution to the system of equations is (x,y) = (-6,-6).

The features of function g(x) are: Domain of (4, ∞) Range of (8, ∞) X-intercept at (-4 + 1/256, 0) Y-intercept at (0, 10). Vertical asymptote of x=-4.

Since they enable us to convert an exponential equation into a logarithmic equation and vice versa, logarithmic functions are employed to solve equations involving exponents. They are also used in a variety of disciplines, including science, finance, and engineering.

The common logarithm, indicated by log, is the base that is most frequently used in logarithmic functions, and it is equal to 10. (x). The natural logarithm, indicated by ln, is provided through the use of another frequently used base, e. (x). The product rule, quotient rule, and power rule are among the characteristics of logarithmic functions that are similar to those of exponential functions.

When the function is transformed according to the given translation we have:

The domain of g(x) is (4, inf).

The vertical asymptote of f(x) is x=0, which corresponds to the y-axis.

The x-intercept is:

g(x) = f(x+4) + 8 = 0

f(x+4) = -8

[tex]2^{(f(x+4))} = 2^{(-8)}[/tex]

x+4 = 1/256

x = -4 + 1/256

Therefore, the x-intercept of g(x) is (-4 + 1/256, 0).

The y intercept is g(0) = f(4) + 8

= log∨2 4 + 8

= 2 + 8

= 10

Therefore, the y-intercept of g(x) is (0, 10).

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The repulsion between two negatively charged objects is an indication that the other object must be negatively charged. Thus, the correct answer is B: It has a negative charge.

This is due to the fact that like charges repel each other, while opposite charges attract each other. In this case, the negatively charged balloon repels the other balloon, indicating that the other balloon is also negatively charged. So, the correct answer is B).

The other options are incorrect. Option A is incorrect because both balloons cannot be positively charged as they would attract each other, not repel. Option C is incorrect because an uncharged object would not repel a negatively charged object. Option D is incorrect because a positively charged object would attract the negatively charged balloon, not repel it.

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No, I do not agree with Mayumi's conclusion that the quadrilateral RSTU cannot be a trapezoid just because the slopes of RU and ST are undefined.

RSTU is a trapezoid with  RU and ST are parallel and have the same x-coordinates.

A trapezoid is defined as a quadrilateral with at least one pair of parallel sides.

The fact that the slopes of RU and ST are undefined does not necessarily mean that they are not parallel.

As vertical lines have undefined slopes and are parallel to each other.

To determine if RSTU is a trapezoid,

Mayumi should check if any pair of opposite sides are parallel.

The slopes of the two pairs of opposite sides RS and TU, and RU and ST and check if they are equal.

Slope of RS = (4 - 3)/(1 - (-2))

                    = 1/3

Slope of TU = (1 - (-4))/(-2 - 1)

                    = -5/3

Slope of RU is undefined (vertical line)

Slope of ST is undefined (vertical line)

Since the slopes of RS and TU are not equal, they are not parallel.

The slopes of RU and ST are undefined does not give us any information about their parallelism.

Check at other properties of the quadrilateral to determine if they are parallel.

One property is the coordinates of the points.

If we draw the quadrilateral,  RS and TU are not parallel, but RU and ST are parallel and have the same x-coordinates.

Therefore, quadrilateral RSTU is a trapezoid with bases RS and TU, and legs RU and ST.

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In a rectangle, a diagonal forms a 36° angle with a side. To find the measure of the angle between the diagonals, which lies opposite to a shorter side, follow these steps:

1. Let's denote the angle between the diagonal and the shorter side as θ (which is given as 36°). Since the rectangle has four right angles (90°), the angle between the diagonal and the longer side can be found by subtracting θ from 90°: 90° - 36° = 54°.

2. Now, consider the right-angled triangle formed by the diagonal, shorter side, and longer side of the rectangle. The angle between the diagonal and the longer side is 54°, as calculated in step 1.

3. In a right-angled triangle, the sum of the other two angles (besides the right angle) must equal 90°. Thus, the angle opposite the shorter side in this triangle (let's call it α) can be calculated as: 90° - 54° = 36°.

4. Finally, the angle between the diagonals can be found by doubling α, as the diagonals bisect each other at a right angle: 2 * 36° = 72°.

Hence, the measure of the angle between the diagonals, which lies opposite to a shorter side, is 72°.

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