Shania has started a new job as an app developer. Her first task was to make an old designed for Android available on other platforms. which of the following would make her job easiest and fastest?

Types; 2 Auto body repair; 3 Auto glass repair; 4 See also; 5 References ... Independent automobile repair shops in the US may also achieve certification through manufacturer sponsored ...

Answer:

A computo is a box and it works really well if its good

Answer:

wat?

Explanation:

The question should be labeled in the psychology section, but what I assume the question means is some sort of paradoxical reverse psychology method of braincell loss. Even photosynthesis doesn't understand what it means. The question probably is what is the question, not that there's no help.

Hope this helps (a little)!

Answer:false

Explanation:

Bc

Answer:

what are you in third grade??

Explanation:

the answer is  the air pressure inside of the bottle reaches the same air pressure as outside of the bottle. K?? got it love???I hope soo

Answer:

the air pressure inside of the bottle reaches the same air pressure as outside of the bottle.

Explanation:

Answer:

$1,783,805

Explanation:

Okay, if we are going to answer thus question efficiently, we need to take time to understand each and every sentence in the question. Hence, from the question we have the following data or information and they are;

1. The initial deposit in which Juan deposited on his 26th birthday = $7500.

2. After the statement in [1] above, Juan decided to be depositing $1000 more than the one he deposited on his 26th birthday.

Therefore, we are given that there is 5% in the interest rate. Thus, after his thirty-fifth deposit he will have;

$7500[90.3203] + [5.516] × $1000 × 200.581] = $1,783,805

Answer:

ben black diyorum ve Iyi srdsler dilerim

#elmaliturta23

Answer:

The torque at the end of the beam is 2.5 Nm

Explanation:

Given;

length of beam, r = 0.5 m

applied force, F = 5 N

The torque at the end of the beam is given by;

τ = F x r

where;

τ  is the torque

F is applied force

r is length of the beam

τ = 5 x 0.5

τ = 2.5 Nm

Therefore, the torque at the end of the beam is 2.5 Nm

Answer:

actually, it was John Doe and Jane Doe, as they were created as testers on the exact same say when Roblox was created.

Explanation:

The first  player was builderman. Option C

The first player was one whose user handle was builderman.

However, the account was terminated. It was replaced with

‘Builderman’ is the account that belonged to the CEO and Co-Founder of , David Baszucki. He manages all of the admins.

When you make a new account, he's automatically your friend.

Note that ‘John Doe’ and ‘Jane Doe’ were two test accounts that were created by David.

The accounts were later rumored to hack others’

Learn about username at: https://brainly.com/question/28344005

#SPJ6

Answer:

The steady rate of heat transfer through the glass window is 707.317 watts.

Explanation:

A figure describing the problem is included below as attachment. From First Law of Thermodynamics we get that steady rate of heat transfer through the glass window is the sum of thermal conductive and convective heat rates, all measured in watts:

[tex]\dot Q_{total} = \dot Q_{cond} + \dot Q_{conv, in} + \dot Q_{conv, out}[/tex] (Eq. 1)

Given that window is represented as a flat element, we can expand (Eq. 1) as follows:

[tex]\dot Q_{total} = \frac{T_{i}-T_{o}}{R}[/tex] (Eq. 2)

Where:

[tex]T_{i}[/tex], [tex]T_{o}[/tex] - Indoor and outdoor temperatures, measured in Celsius.

[tex]R[/tex] - Overall thermal resistance, measured in Celsius per watt.

Now, we know that glass window is configurated in series and overall thermal resistance is:

[tex]R = R_{cond} + R_{conv, in}+R_{conv, out}[/tex] (Eq. 3)

Where:

[tex]R_{cond}[/tex] - Conductive thermal resistance, measured in Celsius per watt.

[tex]R_{conv, in}[/tex], [tex]R_{conv, out}[/tex] - Indoor and outdoor convective thermal resistances, measured in Celsius per watt.

And we expand the expression as follows:

[tex]R = \frac{l}{k\cdot w\cdot d} + \frac{1}{h_{i}\cdot w\cdot d} + \frac{1}{h_{i}\cdot w\cdot d}[/tex]

[tex]R = \frac{1}{w\cdot d}\cdot \left(\frac{l}{k}+\frac{1}{h_{i}}+\frac{1}{h_{o}} \right)[/tex] (Eq. 4)

Where:

[tex]w[/tex] - Width of the glass window, measured in meters.

[tex]d[/tex] - Length of the glass window, measured in meters.

[tex]l[/tex] - Thickness of the glass window, measured in meters.

[tex]k[/tex] - Thermal conductivity, measured in watts per meter-Celsius.

[tex]h_{i}[/tex], [tex]h_{o}[/tex] - Indoor and outdoor convection coefficients, measured in watts per square meter-Celsius.

If we know that [tex]w = 2.4\,m[/tex], [tex]d = 1.5\,m[/tex], [tex]l = 0.006\,m[/tex], [tex]k = 0.78\,\frac{W}{m\cdot ^{\circ}C}[/tex], [tex]h_{i} = 10\,\frac{W}{m^{2}\cdot ^{\circ}C}[/tex] and [tex]h_{o} = 25\,\frac{W}{m^{2}\cdot ^{\circ}C}[/tex], the overall thermal resistance is:

[tex]R = \left[\frac{1}{(2.4\,m)\cdot (1.5\,m)}\right] \cdot \left(\frac{0.006\,m}{0.78\,\frac{W}{m\cdot ^{\circ}C} }+\frac{1}{10\,\frac{W}{m^{2}\cdot ^{\circ}C} }+\frac{1}{25\,\frac{W}{m^{2}\cdot ^{\circ}C} } \right)[/tex]

[tex]R = 0.041\,\frac{^{\circ}C}{W}[/tex]

Now, we obtain the steady rate of heat transfer from (Eq. 2): ([tex]R = 0.041\,\frac{^{\circ}C}{W}[/tex], [tex]T_{i} = -5\,^{\circ}C[/tex], [tex]T_{o} = 24\,^{\circ}C[/tex])

[tex]\dot Q_{total} = \frac{24\,^{\circ}C-(-5\,^{\circ}C)}{0.041\,\frac{^{\circ}C}{W} }[/tex]

[tex]\dot Q_{total} = 707.317\,W[/tex]

The steady rate of heat transfer through the glass window is 707.317 watts.

Answer:

V= 90h cm³ where h is the height of the rectangular prism.

Explanation:

The formula for volume of a rectangular prism is ;

V=l*w*h  where;

V=volume in cm³

l= length of prism=10cm

w =width of the prism = 9 cm

Assume the height of the prism as h cm then the volume will be;

V= 10* 9*h

V= 90h cm³

when the value of height of the prism is given, substitute that value with h to get the actual volume of the prism.

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Answer:

the first one is the correct answer

Answer:

the first one would be correct

Explanation: