Determine the liters of water formed when 6.97 L hydrogen react with an excess of oxygen. Please explain this so I can have a reference for when I don other questions.
2 H2(g) + 102 (g) → 2 H20 (l)
Answer:
it turns into icecream
Which type of plate boundary is represented at point A?
Answer:
You haven't put an image so that I can determine your answer
Explanation:
Answer:
Point A represents a location on a tectonic plate boundary. Plates X and Y represent major tectonic plates. The island of Crete; the Anatolian Plate, which is a minor tectonic plate; and the Hellenic Trench have been labeled. Arrows indicate the relative directions of plate motion.
Explanation:
naproxen (Aleve): 73.03%C, 6.13%H, and 20.84%O Express your answer as a chemical formula?
If the molecular weight is 230.26 g/mol carbon = 73.03% = 230.26*73.03/100 = 168.15/12 = 14 Carbons Hydrogen = 6.13% = 230.26*6.13/100 = 14/1 = 14 Hydrogens Oxigen = 20.84% = 230.26*20.84/100 = 47.98/16 = 3 Oxygens Hence the empirical formula is C14H14O3
What is a weight example?The International System for Units (SI) defines the newton as the unit of force, which is used to measure weight. For instance, a kilogram of matter weighs around 9.8 newtons on Earth's surface and around each as much on Moon.
How are weights determined?Weight, which is expressed in newtons, is a unit of measurement for the gravitational force acting on an object. The mass of a bird with a mass of 15 g changes with the strength of the gravity influence acting on it, and would differ significantly if it were measured, for instance, on the Moon rather than on Earth.
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Air currents transfer energy by the method of heat transfer called
Answer:
convection
Explanation:
What is the importance of CO2 and O2 in water?
The importance of the carbon dioxide, CO₂ and the oxygen O₂ in the water is they both are important for the aquatic animals and for the aquatic plant.
The CO₂ and O₂ are both important for the aquatic animals and also for the aquatic plants. the concentration of the oxygen in to the water is important for the aquatic animals that the dissolved oxygen for the respiration. the carbon dioxide will be more soluble in water than the oxygen in the water.
The carbon dioxide forms the carbonic acid in the water. the carbon dioxide is useful for the aquatic plants for the growth.
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Why the properties of elements are repeated after 2 8 18 and 32 elements?
The properties of the elements are repeated after 2 8 18 and 32 elements because these are the maximum number of the electrons that the four shells contains.
The electronic configuration of the elements in the periodic table are repeated because the maximum number of the electrons that the four shells can have are 2 8 18 and 32. the name of the four shells are K , L, M, N. The electronic configuration of the elements are repeated and due to this the properties of the elements are repeated.
Thus, the properties of the elements are increases because the electronic configuration are repeated in the periodic table.
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Elements whose properties are between those of metals and solid nonmetals are called:
metals
neutrons
metalloids
nonmetals
Answer:
mettaliods
Explanation:
It has the both property of metal and non metal so it is called mettaliod.
Answer:
metalloids
Explanation:
they are solid at roomtempreture and alloys with metals.
examples boron,silicon,arsenic,tellurium
Please help.. which kind of rock requires heat and pressure to form?
-Clastic rock
-Igneous rock
-metamorphic rock
-sedimentary rock
the answer I think is the metamorphic rock
Answer:
metamorphic
Explanation:
sedimentary rocks under heat and pressure form metamoephoc rocks
How many hydrogen atoms are in 1 mg of aspartame?
What is the percent of S K2S?
Answer:
29.07778262 (i don't know what you have to round to, but just be aware of rounding)
Explanation:
to answer this you have to convert both elements into grams, you do this by finding their atomic weight on a periodic table then multiplying it by how many moles of the molecule you have, k=39.098 and S=32.06, so you have to multiply k by two since you have two moles, so now you know that k2=78.196. then add the two amounts together to get the total weight of the compound, 110.256, now that you have that you can create a proportion to solve for the percent, the proportion is equal to the mass of one element, in this case S, over the total weight of the compound, 110.256. then divide [tex]\frac{32.06}{110.256}[/tex] =.290777... this is your percent in decimal form, so multiply by 100 to get you percentage.
if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest
The solubility of glucose (a type of sugar) is 133 g/1000mL. Would you expect a mixture made of 60 g of glucose in 500 mL of water to be saturated? Why or why not?
Answer:
yes
Explanation:
60/500 is less than 133/1000 meaning that the glucose will be able to disolve without a salute
What is the total number of moles contained in 115 grams
of C₂H5OH?
A. 1.00
B. 1.50
C. 2.50
D. 3.00
The total number of moles contained in 115 grams of C₂H5OH is 2.50 moles .
What is the term "mole"?The term "mole" refers to the quantity of a substance that has the same amount of subatomic particles (ions, molecules, or atoms) as there are carbon atoms.
Atomic weight of carbon(C)= 12 gm
Atomic weight of Hydrogen (H)=1 gm
Atomic weight of oxygen (o)=16 gm
∴Molecula weight of C2H5OH =(12×2 + 1×6 + 16×1) gm
24 + 6 + 16 gm = 46 gm
∴ 46 gm of C2H5OH contains 1 mole
1 gm of C2H5OH contain = 1/46 moles
115 gm of C2H5OH contains = 115×1/46 moles
⇒2.5 moles
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Molecular iodine, i2(g), dissociates into iodine atoms at 625 k with a first-order rate constant of 0. 271 s−1. Part a part complete what is the half-life for this reaction?
After solving the equation: The half-life for this reaction is 0.693/0.271 = 2.56 s.
What is reaction?Reaction is the response of a system to an external or internal stimulus. It is the way a person or object behaves in response to a change in their environment. Reactions can be physical, chemical, or psychological. Physical reactions involve changes in the body, such as muscle tension, sweating, or heart rate.
The half-life for this reaction is the time it takes for the concentration of molecular iodine to decrease by a factor of 2, or for half of the original amount of molecular iodine to react. This can be calculated using the equation:
T1/2 = 0.693/k
where k is the first-order rate constant.
Therefore, the half-life for this reaction is 0.693/0.271 = 2.56 s.
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A student dissolved 0.178 grams of a solid monoprotic acid in water and then titrated it. They then performed the same calculation as you just did in question 2 to find the moles and they found that 0.00685 moles were neutralized. What is the molar mass of the unknown acid that was dissolved? (Hint: What are the units for molar mass?)
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 25.98g/mol is the molar mass of the unknown acid that was dissolved.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.
Mathematically,
mole =given mass ÷ molar mass
Molar mass of unknown acid= ?
mass of unknown acid= 0.178 grams
moles of unknown acid= 0.00685 moles
Substituting the values in above formula we get
0.00685 = 0.178 ÷ molar mass
molar mass=25.98g/mol
Therefore, 25.98g/mol is the molar mass of the unknown acid that was dissolved.
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A reaction produces 4.93 L of oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield
When only 1 mol of oxygen was intended to be produced, a process instead yields 4.93 L of oxygen. The percent yield of the reaction is 493%.
Percent yield is a measure of how much of the desired product is produced in a chemical reaction. It is calculated by comparing the actual yield of a product to the theoretical yield, which is the amount of product that would be produced if the reaction were 100% efficient.
To calculate the percent yield, you can use the formula:
= percent yield
= (actual yield / theoretical yield) x 100%
The theoretical yield of a reaction is calculated by multiplying the number of moles of reactant used by the stoichiometry of the reaction. In this case, the reaction is supposed to produce 1 mol of oxygen, which is the theoretical yield. To calculate the actual yield, we can use the Ideal gas law PV = nRT, where P is the pressure, V is the volume, n is the number of mol. Since we know that V = 4.93 L, we can use this information to find n:
= n
= (PV) / RT
The actual yield is 4.93 L of O2 or 4.93 L of any gas at STP (Standard Temperature and Pressure) is equivalent to 4.93 moles of O2.
Then we can use this information to calculate the percent yield:
= percent yield
= (actual yield / theoretical yield) x 100%
= (4.93 moles O2 / 1 mole O2) x 100%
= 493%
So, the percent yield of the reaction is 493%.
It's important to note that a percent yield of greater than 100% is usually an indication of an error in the measurement or calculation of the actual yield, or it could be an indication that the theoretical yield is incorrect.
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What sources of error may have contributed to the percent yield not being 100 percent? Think about things that may have led to inaccurate measurements or where mass of the product could have been lost if this experiment was conducted in a physical laboratory
The product could have been lost if this experiment was conducted in a physical laboratory: Human Error, Incomplete Reaction, Inadequate Stirring, Impurities and Loss of Product.
What is product?Product is a tangible or intangible good that is produced for sale on the market.
1. Human Error: Inaccurate measurements or miscalculations during the experiment may have caused the percent yield not to be 100%.
2. Incomplete Reaction: Depending on the reaction conditions, it is possible that the reaction did not go to completion, leading to a lower percent yield than expected.
3. Inadequate Stirring: If the reactants were not adequately mixed during the experiment, some reactants may not have been able to properly react, resulting in a lower percent yield.
4. Impurities: If the reactants used in the experiment were impure, it could lead to a lower percent yield due to the presence of undesirable substances that can interfere with the reaction or are not involved in the reaction.
5. Loss of Product: If the experiment was conducted in a physical laboratory, it is possible that some of the product was lost during the experiment due to improper handling or other factors.
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Why do we use an excess of aldehyde in the aldol-dehydration reaction? O to form an enolate anion O to insure that the double aldol-dehydration takes place O to react with the free radicals
O to prevent air-oxidation
Option B, Using an excess of aldehyde in the aldol-dehydration reaction is done primarily to ensure complete conversion of the reactants to the desired product.
An excess of aldehyde is used to ensure that there is a sufficient concentration of the aldehyde present in order to form the enolate anion, which is the reactive intermediate in the aldol-dehydration reaction. To achieve high yield: Using an excess of aldehyde allows for the formation of multiple enolate anions, which increases the chances of a double aldol-dehydration reaction taking place, resulting in the formation of the desired product. Using an excess of aldehyde helps aldol-dehydration to prevent this by reducing the exposure of the aldehyde to air.
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if 87 grams of K2SO4 (molar mass 174 grams) is dissolved in enough water to make 250 milliliters of solution, what are the concentrations of the potassium and the sulfate ions ?
[K+ ] [SO4^2]
A. 0.020 M 0.020 M
B. 1.0 M 2.0 M
C. 2.0 M 1.0 M
D. 2.0 M 2.0 M
E. 4.0 M 2.0 M
If 87 grams of K₂SO₄ is dissolved in enough water to make 250 milliliters of solution, the concentrations of the potassium [K⁺] is 4 M and the sulfate ions [SO₄²⁻] is 2 M.
The molar mass of the K₂SO₄ = 174 g/mol
The mass of the K₂SO₄ = 87 g
the moles of the K₂SO₄ = 87 / 174
= 0.50 mol
moles of K⁺ = 0.50 × 2
= 1 mol
moles of SO₄²⁻ = 0.50 × 1
= 0.50
The concentration of [K⁺] = 1 / 0.250 = 4 M
The concentration of [SO₄²⁻] = 0.50 / 0.250 = 2 M
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Investigating Jessie's Claim
Identifying the Other Reactant
If the container was not empty when Jessie added the chlorine gas, then what could have been inside it? Below is an image
showing the reaction inside the container. There is also a table that lists some of the substances that Dr. Yung keeps in her lab.
The group of atoms that repeat to form each substance, as well as some of the properties of each substance, are included in the
table.
Procedure
1. Use the tokens and the information in the table to determine what the other reactant inside the container could have been.
2. Once you have identified the other reactant, answer the questions below.
mention three properties of alloys
help help help help help help help help help
Answer:
what do u need help with sir
Give a Question/Problem for Hot and Cold Compress Pillow.
Help mee plsss
THANK you!!!
Answer:
One problem that people may encounter when using a hot and cold compress pillow is that the pillow may not stay hot or cold for a long enough period of time. This can be frustrating for people who are using the pillow to alleviate muscle pain or reduce inflammation, as they may need to continually reheat or refreeze the pillow in order to maintain its therapeutic benefits. To solve this problem, people may need to find a pillow that is better at retaining heat or cold, or they may need to use additional heating or cooling elements (such as hot water bottles or ice packs) in conjunction with the pillow.
Explanation:
Consider the energy diagram below.
Which line indicates a higher reaction rate?
A because it has a lower activation energy.
B because it has a lower activation energy.
A because it’s Grxn is much lower
B because it’s Grxn is much lower
How can you deduce if a compound is optically active or not ?
Answer:
look for evidence that the molecules are chiral.
Explanation:
The instrument with which optically active compounds are studied is a polarimeter, shown in the figure below. Imagine a horizontal line that passes through the zero of a coordinate system.
Jerry designed a coat that he thinks could keep people dry during a thunderstorm. He created a prototype that looks just like his drawing. What should Jerry do next?
Answer:
The next step is prototype testing
Explanation:
The stages of the design process are;
1) Situation analysis
Paper based research is conducted on the situation to obtain the situation parameters
2) Brief writing
With the situation analysis developed above, the brief of the current situation is put down on paper
3) Problem research
The problem is researched and experimented on with the development of a paper based proof of the possible concept
4) Specification writing
The specifications of the problem are outlined
5) List the possible solutions
The possible solutions are brainstormed and listed
6) Preferred solution selection
The preferred solution is selected based on the constraints in the situation
7) Create working drawing/plan
The working design drawing of the selected solution or concept is completed and evaluated for applicability
8) Building of a prototype
The design is converted into a prototype which is a model of the actual solution
9) Testing of the prototype
The prototype is tested for functionality, for ability to work in the intended situation and/or in the intended system
10) Report writing
A report is made on the outcome of the tests for review before production
Therefore, after the prototype is created, stage 8, the next step is the testing of the prototype stage 9.
Problem that can be caued by both the complete and incomplete
combution of methane in a ga fire
Oxidation of methane to soot:
CH4(g)+O2(g)⟶C(s)+2H2O(g)
Among the hydrocarbons is methane, CH4(g). Only the elements carbon (C) and hydrogen (H) are present in the complex. When methane burns with too much oxygen, it produces water vapor and carbon dioxide gas CO2(g) (g). Complete combustion is defined as combustion with extra oxygen.
Methane can be partially oxidized into a variety of compounds when it is burned inefficiently, including CO, methanol, formic acid, formaldehyde, and higher hydrocarbons.
Carbon monoxide is an extremely toxic gas. It is invisible and odorless. Without anybody being aware of it, malfunctioning gas fireplaces or boilers can poison the air in a room by emitting carbon monoxide.
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The complete question is
Problems that can be caused by both the complete and incomplete
combustion of methane in a gas fire.
1. Ito ay binubuo ng apat na parte/bahag, isa na rito ang pinakamahalaga ang Lobo ng Usapan.
B. Tabloid
C. Komiks
A. Pahayagan
D. Aklat
Explain the energy transformation occurring in the image and how the law of conservation of energy is demonstrated here.
The limiting reactant, O2, forms 2.7 mol AI2O3. What mass of AI2O3 forms, knowing the molar mass of AI2O3 is 102 g/mol?
The limiting reactant, O₂, forms 2.7 mole Al₂O₃. Therefore, the mass of Al₂O₃ is 280 g.
What is mole ?The term mole (M) is defined as the amount of substance in a system which include as many elementary entities as there are atoms present in it. It is denoted by the symbol “mol”. The word mole is coming from the Latin word moles, which means “a mass”.
Molar Mass of Al₂O₃ = 101.96 g/mol
2.7 mole Al₂O₃ 101.96 g
------------------------ x -------------------
X 1 mole
= 280 g Al₂O₃
Thus, The limiting reactant, O₂, forms 2.7 mole Al₂O₃. Therefore, the mass of Al₂O₃ is 280 g.
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Draw the structure of the major organic product(s) of the following reaction.
excess Br2
excess OH
The major organic product of this reaction is 2-bromobutane, a saturated hydrocarbon with a bromine atom attached to the second carbon atom.
The major organic product is 2-bromobutane.
Structure:
CH3 CH2 CH2 CH2 Br
| | |
CH3 CH2 Br
1) The reaction begins with bromine reacting with the 2-methylpropane molecule to form the intermediate 2-bromo-2-methylpropane.
2) The intermediate then reacts with hydroxide ions to form the final product, 2-bromobutane.
3) The final product is a saturated hydrocarbon with a bromine atom attached to the second carbon atom.
The major organic product of this reaction is 2-bromobutane, a saturated hydrocarbon with a bromine atom attached to the second carbon atom.
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