Si se impulsa un bloque con una velocidad de 15m/s sobre el piso sin rozamiento mostrado. Determinar la altura “h” que alcanzará, no existe rozamiento.
PORFAAA AYUDA URGENTE

La altura máxima alcanzada por el bloque es de 14.471 metros.

En esta pregunta asumimos que la altura inicial del bloque es igual a tres metros por encima del la altura de referencia y la altura final puede ser determinada mediante el principio de conservación de la energía, en cuyo caso, la suma de la energía cinética traslacional inicial ([tex]K[/tex]) y la energía potencial gravitacional inicial ([tex]U_{o}[/tex]), ambos en joules, es igual a la energía potencial gravitacional final ([tex]U_{f}[/tex]), en joules. Matemáticamente hablando, tenemos la siguiente expresión:

[tex]U_{o}+K = U_{f}[/tex]

[tex]m\cdot g\cdot z_{o} + \frac{1}{2}\cdot m\cdot v^{2} = m\cdot g \cdot z_{f}[/tex] (1)

Donde:

A continuación, despejamos la altura final del bloque:

[tex]z_{f} = z_{o}+\frac{1}{2}\cdot \frac{v^{2}}{g}[/tex] (2)

Si sabemos que [tex]z_{o} = 3\,m[/tex], [tex]v = 15\,\frac{m}{s}[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces la altura máxima alcanzada por el bloque es:

[tex]z_{f} = 3\,m + \frac{1}{2}\cdot \left[\frac{\left(15\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} } \right][/tex]

[tex]z_{f} = 14.471\,m[/tex]

La altura máxima alcanzada por el bloque es de 14.471 metros.

Invitamos cordialmente a ver esta pregunta sobre el principio de conservación de la energía: https://brainly.com/question/19561287

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