Answer: 478,412
Step-by-step explanation:
In order to do this just take 2 million and subtract the number of chips you wanted to take away. For example, it'd be 2,000,00 - 1,521,588 which leaves you with 478,412.
-0.8 as a fraction!
Please explain I have to go in like 5 minutes!
Answer:
4/5 divide 100 by the denominator in this case 5 get 20 as the unit percent and multiply by the numerator to get 80% which is 8/10 as a fraction.
What is 18/100 written as a decimal?
[tex]0.18[/tex]
is the decimal point
12. Suppose a computer manufacturer has the total cost function C(x) = 65x +3500 and the total revenue function
R(x) = 365x, where x represents the number of computers produced and sold. What is the profit on 326 items?
a. $86,500
b. $101,300
c. $94,300
d. $1,238,800
$143.680
Cost is 65x + 3500 where x is = 326.
65(326) + 3500
21,190 + 3500 = $24,690 is the cost.
Revenue is 365x where x is 326.
365(326) = $118,990
Now we subtract the two:
118,990 - 24,690 = $94,300
This means that the answer is C) $94,300.
I hope this helps! :)
Can you help please?
Answer:
Step-by-step explanation:
A set of stickers contains 4 shamrocks for every 6 rainbows. Which choice contains an equivalent ratio of shamrocks to rainbows?
shamrocks : rainbows
1. 2 : 4
2. 6 : 9
3. 1 : 3
4. 8 : 18
A square piece of paper has a perimeter of 36 cm. What is the area of a square piece of paper with twice that perimeter? *
323 sq.cm
324 sq.cm
81 sq.cm
---------------------
( perimeter = l+ b )
(area = l × w )
(l= length)
(b= breadth )
(w= width)
Answer:
Area= 18 x 18=324 sq.cm
Step-by-step explanation:
p=36 x2=72 (as it is twice that of the original paper)
since it is a square, length of 1 side = 72/4= 18
so, the area = l x l= 18 x 18= 324 sq.cm
Answer:
Area= 18 x 18=324 sq.cm
Step-by-step explanation:
p=36 x2=72 (as it is twice that of the original paper)
Since it is a square, length of 1 side = 72/4= 18
Therefore, the area = l x l= 18 x 18= 324 sq.cm
Hope this helps :)
How do I do this math !
Answer:
The equation of a straight line is always
[tex]y=mx+b[/tex]
The constant m always refers to the slope, and the constant b always refers to the y-intercept.
Simply substitute the numbers in:
[tex]y=-\frac{1}{2}x+3[/tex]
There's your equation!
A truck is carrying
10^3
bushels of apples,
10^2
bushels of grapes, and
10^1
bushels of oranges. Each bushel of apples weighs 32 pounds, each bushel of grapes weighs 25 pounds, and each bushel of oranges weighs 42 pounds. What is the total weight of the fruit in pounds?
A.
3,592 pounds
B.
5,742 pounds
C.
32,299 pounds
D.
34,920 pounds
[tex]\begin{cases} \stackrel{apples}{10^3}\\ \stackrel{grapes}{10^2}\\ \stackrel{oranges}{10^1} \end{cases}\qquad \begin{cases} \stackrel{lbs}{32}\\ \stackrel{lbs}{25}\\ \stackrel{lbs}{42} \end{cases}\qquad \begin{array}{rllll} 10^3\cdot 32\\ 10^2\cdot 25\\ +\qquad 10\cdot 42\\\cline{1-1} 34920&lbs \end{array}[/tex]
Please please help !
Answer:
Unsure but it might be -8/3
Step-by-step explanation:
If AD = 12 and BD = 14, what is CD?
Write your answer as a whole number or as a decimal rounded to the nearest hundredth.
a. 7
b. 10.29
C. 12.54
d. 16.33
Answer: D. 16.33
Step-by-step explanation:
Choose the correct answer below
Answer: B.
Step-by-step explanation:
brainliest me
Ms. April likes for the twenty students in her
class to have a carton of milk each day at break
time. She sends three of her students down to
the cafeteria to ask for the cartons of milk, but
she likes to mix things up a bit and wants to
send a different group of students down every
day. Will she have enough different groups of
three students in her class of twenty students to
send a different group every day of the school year? (There are 180 days in the school year)
Answer:
Ms. April will not have enough students.
Step-by-step explanation:
This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.
Answer:
Ms. April will not have enough students.
Step-by-step explanation:
This is because 180 days of the year divided by 3 students per day = 60 students per year. The class only has 20 students, therefore, there is not enough students needed to collect milk.
Question 19
A game consists of black and white pieces. The number of black pieces is 5 more than 3 times the white pieces. Seven white and 15 black pieces are removed each round. After several rounds, there are 3 white and 56 black pieces left. How many pieces were there in the beginning?
A. 52
B. 158
C. 210
D. 213
E. 218
Answer:
D. 213Step-by-step explanation:
The number of black pieces is 5 more than 3 times the white pieces:
b = 3w + 5Let the number of rounds is x.
Initial number of white nd black pieces:
w = 7x + 3b = 15x + 56Substitute the values of b and w into first equation and find the value of x:
15x + 56 = 3(7x + 3) + 515x + 56 = 21x + 146x = 42x = 7Find the number of pieces:
w = 7*7 + 3 = 52b = 3*52 + 5 = 161w + b = 52 + 161 = 213Correct choice is D
Answer:
A game consists of black and white pieces. The number of black pieces is 5 more than 3 times the white pieces. Seven white and 15 black pieces are removed each round. After several rounds, there are 3 white and 56 black pieces left. How many pieces were there in the beginning?
A. 52
B. 158
C. 210
D. 213
E. 218
What is the average number of 20 14 28 18
Step-by-step explanation:
Avg = 20 + 14 + 28 + 18 /4
Avg = 80/4 = 20
Denise is going on a road trip with some friends. For the first leg of their trip, they drive on the highway for 2.5 hours before taking an exit. If they maintain a steady pace of 64 miles per hour, how far do they drive on the highway?
Answer:
160
Step-by-step explanation:
We know that [tex]\left \{ {{t=2.5} \atop {v=64}} \right.[/tex]
Formulate and substitute: [tex]d=2.5[/tex]×[tex]64[/tex]
Calculate the product or quotient: [tex]160[/tex]
Answer: [tex]160[/tex]
Abby has $32 to spend on party supplies. After buying 9 packs of noisemakers, she has $20 left.
How much did each pack of noisemakers cost?
A
$0.75
B
$1.15
C
$1.33
D
$12.00
Answer:
$1.33
Step-by-step explanation:
32-20 = 12
12/9 = $1.33
Please help me :/!!!!
Answer:
(3, 9)
Step-by-step explanation:
Set 3x and 2x+3 equal to each other forming an equation in x.
3x=2x+3
Solve for x.
x=3
Substitute the given value of x into the equation y=3x.
y=3x3
Solve for y.
y=9
(x, y) = (3, 9)
Hope this helps :)
The average of max's three tests is an 84 what must he get on a fourth test to raise his average to an 87
Answer:
He must get a 96% on the fourth test to raise his average to an 87
A car was valued at 380,000 in the year 2014. By 2019, the value had depreciated to 110,000. If the cars value continues to drop by the same percentage,what will it be worth by 2017?
Please help thanks and Godbless
Answer:
160000
Step-by-step explanation:
4. 8 is what percent of 18?
Answer:
the answer is 26.6666667 and when rounded off is 26.7
is 1/4 to the 0 power bigger then 1
Answer:
1/4 to the 0 power is equal to 1. Therefore, it is not bigger than 1
work out the value of 35-3×9
you must remember to do the bidmas or bodmas in those type of question
First you must try to do multiplie this question 3×9 = 27
than subtract
35-27 =8
8 is final answer
Answer:
8
Step-by-step explanation:
35-3×9=35-27
=8
Hope this helps!!!
solve for x in equation !! ?
Pretty sure the answer is d
Use substitution to determine which value of x makes the equation x– 5 = 7.4 true
x=2.4
X= 6.9
X= 7.9
X = 12.4
HELPPPP
Step-by-step explanation:
I'm not sure if I'm using substitution method but I guess it's x = 12.4
Can someone help with question #4 please
Answer:
4,0 is the right ok I am a professor
Given log_73≈0.5646 and log_716≈1.4248, evaluate the expressions. Please show work using given values.
Answer:
(a) [tex]\log_72 \approx 0.3562[/tex]
(b) [tex]\log_7(\frac{147}{16} ) = 2[/tex]
Step-by-step explanation:
For the point a:
For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex]
16 can be re-write as [tex]2^4[/tex]. Then you have:
[tex]\log_72^4[/tex]
Using the power property of the logarithm we have:
[tex]\log_ba^c = c\log_ba[/tex]
[tex]\log_72^4 = 4\log_72[/tex]
And this expression is equal to:
[tex]4\log_72 \approx 1.4248\\\log_72\approx \frac{1.4248}{4} \approx 0.3562\\[/tex]
For the point b:
For this problem we use the information of [tex]\log_716 \approx 1.4248[/tex] and [tex]\log_73 \approx 0.5646[/tex]
The first is use the quotient property in the given log.
[tex]\log_c\frac{a}{b} = \log_ca-\log_cb[/tex]
[tex]\log_7\frac{147}{16} = \log_7147 -\log_716[/tex]
We already know the value of [tex]\log_716[/tex] then we have to calculate the value of [tex]\log_7147[/tex].
So we factorize the number 147 in [tex]3 \cdot 7 \cdot 7[/tex] (for factorize the number start with the smaller prime and check if the remainder is 0, it is then is a primer factor of the number).
Now re-write [tex]\log_7147[/tex] as [tex]\log_73 \cdot 7^2[/tex] and by the product property get:
[tex]\log_bmn = \log_b m +\log_b n\\\log_73 \cdot 49 = \log_7 3 +\log_7 49 = 0.5646 + 2 = 2.5646[/tex]
Know replace each value in the subtraction and get the result:
[tex]\log_7147 -\log_716 = 2.5646 - 0.5646 = 2[/tex]
100 pointer question here
Answer:
See attached
Expressions matching the properties
The associative property:
a + b = b + aab = baThe commutative property:
a + (b + c) = (a + b) + cDistributive property:
a(b + c) = ab + acHELP ME OUT PLEASE
PLS SEND PICTURE OF WHAT TO DO
Use the data to create a scatter plot.
Answer:
(2,5)
(3,8)
(4,13)
(5,12)
(6,18)
(7,20)
Plug those into the scatter plot graph
Step-by-step explanation:
The left side is the x axis and the right side is the y axis
at does the point (2, 1.5) represent in this context?
In what context? Do you mean calculus If you are talking about graphing on a graph plane it would be the two accelerates on the x axis so (left or right) and then the 1.5 accelerates on the y axis so 1.5 on the y axis would be one and halfway to the 2 mark on the y axis so in the middle of 1 to 2 on the y axis the y axis goes (up and down)
Due tomorrow answer using steps
[tex]\\ \sf\longmapsto (5x^3+5x^2+5)-(6x^3-6x^2+8x-5)[/tex]
[tex]\\ \sf\longmapsto 5x^3+5x^2+5-6x^3+6x^2-8x+5[/tex]
[tex]\\ \sf\longmapsto 5x^3-6x^3+5x^2+6x^2-8x+5+5[/tex]
[tex]\\ \sf\longmapsto -x^3+11x^2-8x+10[/tex]
[tex]\\ \sf\longmapsto x^3-11x^2+8x-10[/tex]
[tex]\large \boldsymbol{} \longmapsto (5x^3+5x^2+5) -(6x^3-6x^2+8x-5 ) \\\\\\ \longmapsto5x^3+5x^2+5-6x^3+6x^2-8x+5 \\\\\\ \longmapsto 5x^3-6x^3+5x^2+6x^2-8x+5+5 \\\\\\ \longmapsto \boxed{ - x^3+11x^2-8x+10}[/tex]