Solve a triangle with a = 4. b = 5, and c = 7."
a. A=42.3°; B = 42.5⁰; C = 101.5⁰
b. A= 34.1°; B = 44.4°; C= 99.5⁰
C.
d.
OA
OB
C
OD
A = 34.1°: B=42.5°: C= 101.5°
A = 34.1°: B= 44.4°: C= 101.5°
Please select the best answer from the choices provided

Answer:

[tex]m = \frac{1 - ( - 7)}{9 - ( - 3)} = \frac{8}{12} = \frac{2}{3} [/tex]

B is the correct answer.

Approximately 2 tissues were used by each groom's guest at the wedding.

The calculation is as follows:

180 tissues ÷ 90 guests = 2 tissues per guest.

To determine how many tissues each groom's guest used, we need to find the average number of tissues per guest. We start by adding up the number of tissues used by the groom's guests, which is 180.

Then, we divide this total by the number of groom's guests, which is 90. This division gives us an average of 2 tissues per guest.

By dividing the total number of tissues used by the total number of guests, we can find the average number of tissues per guest. In this case, each groom's guest used approximately 2 tissues.

It's important to note that this calculation assumes an equal distribution of tissues among all the groom's guests.

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Answer:

There is one solution. The solution is 2, 18, 19.

Step-by-step explanation:

If you want me to show working tell me in the comments and I'll edit the answer

Answer:

A. (2, 18, -19)

Step-by-step explanation:

To solve:

Z is the most suitable variable to remove first

Add the first equation to the second equation: (this conveniently removes both y and z)

(x+y-z) + (4x-y+z) = 1+9

Simplify

5x = 10

Solve

x = 2

Multiply the second equation by 2 and minus it to the third equation: (Solve for y)

2(4x-y+z) - (x-3y+2z) = 2(9) - (-14)

Simplify

8x-2y+2z-x+3y-2z=18+14

7x+y=32

Substitute using x=2

7(2) + y = 32

y = 32 - 14

y = 18

Now substitute x and y for their respective values into Equation 1

2 + (-18) - z = 1

Simplify

-z = 19

z = -19

So :

x = 2, y = 18 , z = -19

Answer:

Step-by-step explanation:

To interchange Row 1 and Row 2 of the given matrix, the indicated row operation can be performed as follows:

Original matrix:

8 -2 1 7

2

9

4 5

1

4

-4 9

Interchanging Row 1 and Row 2:

2

8 -2 1 7

9

4 5

1

4

-4 9

The transformed matrix after interchanging Row 1 and Row 2 is:

2

8 -2 1 7

9

4 5

1

4

-4 9

Answer:

Step-by-step explanation:

its on satuday

The actual duration of eruption for x = 12.03 is 1.97 minutes, so the residual is 1.97 - 3.8431 = -1.8731 minutes.

The value of the linear correlation coefficient, also known as the Pearson correlation coefficient, measures the strength and direction of the linear relationship between two variables.

In this case, it represents the correlation between the time between eruptions and the duration of the eruption. To calculate the linear correlation coefficient, we can use the given data. The linear correlation coefficient is 0.8404.

The coefficient of determination, denoted as R-squared, represents the proportion of the variance in the dependent variable (duration of eruption) that can be explained by the independent variable (time between eruptions).

It is calculated by squaring the linear correlation coefficient. In this case, the coefficient of determination is 0.7055.

The regression line represents the best-fit line that approximates the relationship between the independent and dependent variables.

It can be expressed in the form of y = mx + b, where y represents the predicted duration of the eruption, x represents the time between eruptions, m represents the slope of the line, and b represents the y-intercept.

To determine the regression line, we can perform linear regression analysis using the given data. The regression line is y = 0.1608x + 1.8305.

The predicted duration of an eruption can be calculated by substituting the given time between eruptions value into the regression line equation. For x = 12.03 minutes, the predicted duration of an eruption is y = 0.1608 x 12.03 + 1.8305 = 3.8431 minutes.

The residual for x = 12.03 is the difference between the actual duration of eruption and the predicted duration. It can be calculated by subtracting the predicted value from the actual value. The actual duration of eruption for x = 12.03 is 1.97 minutes, so the residual is 1.97 - 3.8431 = -1.8731 minutes.

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The surface area and volume of the composite solid is are 1720ft² and 3563.33 ft³ respectively.

The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface area of the solid = lateral area of pyramid + surface area of cuboid

lateral area of pyramid = 4 × 1/2 bh

= 4 × 1/2 × 10× 12

= 120×2 = 240 ft²

Surface area of the cuboid = 2( 100+ 320+ 320)

= 2( 740)

= 1480 ft²

Surface area of the composite solid = 240 + 1480

= 1720 ft²

Volume of the composite solid = volume of cuboid + volume of pyramid

volume of cuboid = 10×10×32 = 3200ft²

volume of pyramid = 1/3base area × height

height of the pyramid is calculated as;

diagonal of base = √ 10²+10²

= √200

= 14.14

h² = 13²-7.07²

h² = 169 - 49.98

h² = 119.02

h = 10.9 ft

Volume of pyramid = 1/3 × 100 × 10.9

= 363.33 ft³

Volume of the composite solid = 3200+363.33

= 3563.33 ft³

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The correct answer is By finding the quotient of the bases to be one third and canceling common factors. Option D.

The Quotient of Powers Property states that when dividing two powers with the same base, you can subtract the exponents. In the given expression, we have three to the fourth power divided by nine.

To simplify this expression using the Quotient of Powers Property, we first need to recognize that nine can be written as three squared, since 3 multiplied by itself gives 9.

So, we have (3^4) / (3^2). According to the Quotient of Powers Property, we subtract the exponents: 4 - 2.

This gives us 3^(4-2), which simplifies to 3^2. Therefore, the expression three to the fourth power all over nine equals three squared.

It states that we find the quotient of the bases to be one third and cancel common factors. In this case, the bases are 3 and 3, and their quotient is indeed one third. Additionally, there are no common factors that can be canceled, as the expression does not contain any variables or additional terms.

Therefore, By finding the quotient of the bases to be one third and canceling common factors. accurately describes the steps involved in simplifying the expression using the Quotient of Powers Property.

We find the quotient of the bases (one third) and cancel common factors (which is not applicable in this case). Option D is correct.

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Note the complete question is

Explain how the Quotient of Powers Property was used to simplify this expression. (1 point)

Three to the fourth power all over nine equals three squared

A.) By simplifying 9 to 32 to make both powers base three and adding the exponents

B.) By simplifying 9 to 32 to make both powers base three and subtracting the exponents

C.) By finding the quotient of the bases to be one third and simplifying the expression

D.) By finding the quotient of the bases to be one third and cancelling common factors

The result of the row operation on the matrix is given as follows:

[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The matrix in this problem is defined as follows:

[tex]\left[\begin{array}{cccc}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The row operation is given as follows:

[tex]R_1 \rightarrow \frac{1}{2}R_1[/tex]

The meaning of the operation is that every element of the first row of the matrix is divided by two.

Hence the resulting matrix is given as follows:

[tex]\left[\begin{array}{cccc}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

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Answer:

35

Step-by-step explanation:

You can easily graph this in desmos for a visual understanding.

The slope of a line is received by (y2-y1)/(x2-x1). Assuming that Days is X and the cost is Y, we get (160-90)/(4-2), and it makes 70/2, which equates out to 35. Because the prices become more and more expensive, the slope is positive 35.

Answer:

The correct answer is a.

Step-by-step explanation:

The sequence is: 2 3 E 4 5 I 6 8 We can notice that there are numbers and letters alternating in the sequence. The numbers are increasing, and the letters seem to be vowels in alphabetical order. So, the next value should be a letter (vowel) after I, which is O. The correct answer is a.

Answer:

0

Step-by-step explanation:

[tex]\displaystyle \frac{F(b)-F(a)}{b-a}\\\\=\frac{F(\pi)-F(-\pi)}{\pi-(-\pi)}\\\\=\frac{\sin(4\pi)-\sin(-4\pi)}{2\pi}\\\\=\frac{0-0}{2\pi}\\\\=0[/tex]

Not sure how the correct answer is stated as 45/28, but the answer is definitely 0.

Answer:

Yes, a sinusoidal function is a great way to model temperatures over a 24-hour period because the pattern of temperature changes tends to be cyclic.

A sinusoidal function can be written in the general form:

D(t) = A sin(B(t - C)) + D

where:

- A is the amplitude (half the range of the temperature changes)

- B is the frequency of the cycle (which would be `2π/24` in this case because the temperature completes a full cycle every 24 hours)

- C is the horizontal shift (which is determined by the fact that the minimum temperature occurs at 6 AM)

- D is the vertical shift (which is the average of the maximum and minimum temperature)

Given the information you've provided, let's fill in the specifics:

- The high temperature for the day is 95 degrees.

- The low temperature is 75 degrees at 6 AM.

The amplitude, A, is half the range of temperature changes. It's the difference between the high and the low temperature divided by 2:

A = (95 - 75) / 2 = 10

The frequency, B, is `2π/24` because the temperature completes a full cycle every 24 hours.

The horizontal shift, C, is determined by the fact that the minimum temperature occurs at 6 AM. The sine function hits its minimum halfway through its period, so we want to shift the function to the right by 6 hours to make this happen. In our case, this means C = 6.

The vertical shift, D, is the average of the maximum and minimum temperature:

D = (95 + 75) / 2 = 85

So the equation for the temperature, D, in terms of t (the number of hours since midnight) is:

D(t) = 10 sin((2π/24) * (t - 6)) + 85

This equation represents a sinusoidal function that models the temperature over a day given the information provided.

Step-by-step explanation:

0.52913368398

màrk me brainliest

Answer:

[tex]\text{a.} \quad m\angle NLM=93^{\circ}[/tex]

[tex]\text{c.} \quad m\angle FHG=31^{\circ}[/tex]

Step-by-step explanation:

The inscribed angle in the given circle is ∠NLM.

The intercepted arc in the given circle is arc NM = 186°.

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc.

Therefore:

[tex]m\angle NLM=\dfrac{1}{2}\overset{\frown}{NM}[/tex]

[tex]m\angle NLM=\dfrac{1}{2} \cdot 186^{\circ}[/tex]

[tex]\boxed{m\angle NLM=93^{\circ}}[/tex]

[tex]\hrulefill[/tex]

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:

[tex]m\angle HFG=\dfrac{1}{2}\overset{\frown}{HG}[/tex]

[tex]m\angle HFG=\dfrac{1}{2}\cdot 118^{\circ}[/tex]

[tex]m\angle HFG=59^{\circ}[/tex]

As line segment FH passes through the center of the circle, FH is the diameter of the circle. Since the angle at the circumference in a semicircle is a right angle, then:

[tex]m\angle FGH = 90^{\circ}[/tex]

The interior angles of a triangle sum to 180°. Therefore:

[tex]m\angle FHG + m\angle HFG + m\angle FGH =180^{\circ}[/tex]

[tex]m\angle FHG + 59^{\circ} + 90^{\circ} =180^{\circ}[/tex]

[tex]m\angle FHG +149^{\circ} =180^{\circ}[/tex]

[tex]\boxed{m\angle FHG =31^{\circ}}[/tex]

The value of m<RQS as required to be determined in the task content is; 70°.

It follows from the task content that the measure of angle RQS is to be determined as required.

Recall, the measure of the central angle subtended by an arc is twice that which it subtends at any point on the circumference.

Therefore, m<RPS = 2 • m<RQS.

m<RQS = 140°/2

m<RQS = 70°.

Ultimately, the measure of angle RQS are; 70°.

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The scale factor used to create the image of polygon ABCD is 4.

To determine the scale factor, we need to compare the corresponding side lengths of the original polygon ABCD and the image polygon ABCD. Let's denote the scale factor as k.

Original polygon ABCD:

Side AB: length = 3 - 1 = 2

Side BC: length = -2 - (-1) = -1

Side CD: length = 1 - 3 = -2

Side DA: length = -2 - (-1) = -1

Image polygon ABCD:

Side AB: length = 12 - 4 = 8

Side BC: length = -3 - (-4) = 1

Side CD: length = 4 - 12 = -8

Side DA: length = -3 - (-4) = 1

Comparing the corresponding side lengths, we can set up the following equations:

k * 2 = 8 (for side AB)

k * (-1) = 1 (for side BC)

k * (-2) = -8 (for side CD)

k * (-1) = 1 (for side DA)

From the equations, we can see that k = 4 satisfies all of them.

Therefore, the scale factor used to create the image of polygon ABCD is 4.

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Answer:

[tex]x = 5.3 \: or \: 5 \frac{1}{3} [/tex]

Step-by-step explanation:

[tex]2 \times 2 + 3x - 20 = 0 \: \: \: \: \: \: 4 + 3x - 20 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:3x = 20 - 4 = 16 \: \: \: \: \: \: \: \: 3x = 16 \: \: divide \: both \: side \: by \: 3 = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 5.3[/tex]

The adjusted balance, considering the new account balance, payments/credits, new purchases, and finance charge, is $489.61.

To calculate the adjusted balance, we need to consider the new account balance, payments/credits, new purchases, and finance charges.

Starting with the new account balance of $435.92, we subtract the payments/credits of $68.50. This represents the amount that has been paid or credited to the account, reducing the balance.

Next, we add the new purchases of $118.49. These are additional charges made to the account, increasing the balance.

Finally, we add the finance charge of $3.70. This charge is typically applied as interest on the outstanding balance.

To calculate the adjusted balance, we can follow these steps:

Start with the new account balance: $435.92

Subtract the payments/credits: $435.92 - $68.50 = $367.42

Add the new purchases: $367.42 + $118.49 = $485.91

Add the finance charge: $485.91 + $3.70 = $489.61

Therefore, the amount of the adjusted balance is $489.61.

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Answer:

B. 0.65

Step-by-step explanation:

The closer the r value is to the number 1 or -1, the stronger the correlation.

For example:

0.99 > 0.01

-0.6 > 0.5

.43 < .76

.69 > .21

Please give brainliest and thanks!

Answer:

a) x² - x - 12 = 0

Step-by-step explanation:

We have equation A = equation B

⇒ x² - 9 = x + 3

⇒ x² - 9 - x - 3 = 0

⇒ x² - x - 12 = 0

Answer:

27)  34.29 in²

28)  If I get an A, then I studied for my final.

Step-by-step explanation:

To calculate the area of the trapezoid, we need to find its perpendicular height.

As the given diagram shows an isosceles trapezoid (since the non-parallel sides (the legs) are of equal length), we can use Pythagoras Theorem to calculate the perpendicular height.

Identify the right triangle formed by drawing the perpendicular height from the vertex of the bottom base to the top base (this has been done for you in the given diagram).

As the two base angles of an isosceles trapezoid are always congruent, the base of the right triangle is half the difference between the lengths of the parallel bases, which is (8 - 6)/2 = 1 inch.

The hypotenuse of the right triangle is the leg of the trapezoid, which is 5 inches.

Use Pythagoras Theorem to find the perpendicular height (the length of the other leg):

[tex]h^2+1^2=5^2[/tex]

[tex]h^2+1=25[/tex]

      [tex]h^2=24[/tex]

        [tex]h=\sqrt{24}[/tex]

        [tex]h=2\sqrt{6}[/tex]

Now we have found the height of the trapezoid, we can use the following formula to calculate its area:

[tex]\boxed{\begin{minipage}{7 cm}\underline{Area of a trapezoid}\\\\$A=\dfrac{1}{2}(a+b)h$\\\\where:\\ \phantom{ww}$\bullet$ $A$ is the area.\\ \phantom{ww}$\bullet$ $a$ and $b$ are the parallel sides (bases).\\\phantom{ww}$\bullet$ $h$ is the height.\\\end{minipage}}[/tex]

The values to substitute into the area formula are:

Substituting these values into the formula we get:

[tex]A=\dfrac{1}{2}(8+6) \cdot 2\sqrt{6}[/tex]

[tex]A=\dfrac{1}{2}(14) \cdot 2\sqrt{6}[/tex]

[tex]A=7\cdot 2\sqrt{6}[/tex]

[tex]A=14\sqrt{6}[/tex]

[tex]A=34.29\; \sf in^2\;(nearest\;hundredth)[/tex]

Therefore, the area of the isosceles trapezoid is 34.29 in², rounded to the nearest hundredth.

[tex]\hrulefill[/tex]

Given conditional statement:

The hypothesis is "I studied for my final", and the conclusion is "I will get an A".

The converse of a conditional statement involves switching the hypothesis ("if" part) and the conclusion ("then" part) of the original statement.

Therefore, the converse of the statement would be:

The function g(x) = 4x² - 28x + 49 can be rewritten as g(x) = 4(x - 7/2)² - 147 after completing the square.

To complete the square for the function g(x) = 4x² - 28x + 49, we follow these steps:

Step 1: Divide the coefficient of x by 2 and square the result.

  (Coefficient of x) / 2 = -28/2 = -14

  (-14)² = 196

Step 2: Add and subtract the value obtained in Step 1 inside the parentheses.

  g(x) = 4x² - 28x + 49

  = 4x² - 28x + 196 - 196 + 49

Step 3: Rearrange the terms and factor the perfect square trinomial.

  g(x) = (4x² - 28x + 196) - 196 + 49

  = 4(x² - 7x + 49) - 147

  = 4(x² - 7x + 49) - 147

Step 4: Write the perfect square trinomial as the square of a binomial.

  g(x) = 4(x - 7/2)² - 147

Therefore, the function g(x) = 4x² - 28x + 49 can be rewritten as g(x) = 4(x - 7/2)² - 147 after completing the square.

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The probable question may be:

Rewrite the function by completing the square.

g(x)=4x²-28x +49

g(x)= ____  (x+___ )²+____.

The values x = -5 and x = 3 make the second expression undefined. The correct answers are:

x = -5

x = 3

x= -3

To determine the values for which the given expressions are undefined, we need to find the values that make the denominators equal to zero.

First expression: [tex]\frac{3x}{(x^2 - 9)}[/tex]

For this expression, the denominator is (x^2 - 9). It will be undefined when the denominator equals zero:

x^2 - 9 = 0

Factoring the equation, we have:

(x - 3)(x + 3) = 0

Setting each factor equal to zero, we get:

x - 3 = 0 --> x = 3

x + 3 = 0 --> x = -3

So, the values x = 3 and x = -3 make the first expression undefined.

Second expression: [tex]\frac{(x + 4)}{(x^2 + 2x - 15)}[/tex]

For this expression, the denominator is (x^2 + 2x - 15). It will be undefined when the denominator equals zero:

x^2 + 2x - 15 = 0

Factoring the equation, we have:

(x + 5)(x - 3) = 0

Setting each factor equal to zero, we get:

x + 5 = 0 --> x = -5

x - 3 = 0 --> x = 3

So, The second expression is ambiguous because x = -5 and x = 3.

Consequently, the right responses are x = -5, x = 3 and x= -3.

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Answer:

550 gallons

Step-by-step explanation:

Let [tex]x[/tex] be the number of gallons for the 90% antifreeze solution and [tex]x+100[/tex] be the total number of gallons that will contain 80% antifreeze solution:

[tex]\displaystyle \frac{0.90x+0.25(100)}{x+100}=0.80\\\\0.90x+25=0.80x+80\\\\0.10x+25=80\\\\0.10x=55\\\\x=550[/tex]

Therefore, you would need 550 gallons of the 90% antifreeze solution.

Answer:

To find the length of AB using the segment addition postulate , we need to add the lengths of segments AC and CB.

AC + CB = AB

Substituting the given lengths:

2x-3 + 24 = 5x+6

Simplifying and solving for x:

21 = 3x

x = 7

Now that we know x, we can substitute it back into the expression for AB:

AB = 2x-3 + 24 = 2(7)-3 + 24 = 14-3+24 = 35

Therefore, the length of AB is 35.

Step-by-step explanation:

We conclude that there is no valid domain for the given function g(x, y) = sin^-1(x² + y² - 3). Thus, the concept of circles with radii does not apply in this case.

To determine the domain of the function g(x, y) = sin^-1(x² + y² - 3), we need to examine the range of the arcsine function. The arcsine function, [tex]sin^{(-1)[/tex](z), is defined for values of z between -1 and 1, inclusive. Therefore, for the given function, we have:

-1 ≤ x² + y² - 3 ≤ 1

Rearranging the inequality, we get:

-4 ≤ x² + y² ≤ -2

Now, let's analyze the inequalities separately:

x² + y² ≤ -2:

This inequality is not possible since the sum of squares of two non-negative numbers (x² and y²) cannot be negative. Therefore, there are no points that satisfy this inequality.

x² + y² ≤ -4:

Similarly, this inequality is also not possible since the sum of squares of two non-negative numbers cannot be less than or equal to -4. Therefore, there are no points that satisfy this inequality either.

Based on the analysis, we conclude that there is no valid domain for the given function g(x, y) = sin^-1(x² + y² - 3). Thus, the concept of circles with radii does not apply in this case.

It's important to note that the arcsine function has a restricted range of -π/2 to π/2, and for a valid domain, the input of the arcsine function must be within the range of -1 to 1. In this particular case, the given expression x² + y² - 3 exceeds the range of the arcsine function, resulting in no valid domain.

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The number of possible integral values of 'a' is 4 and the possible value of a are 1, 2, 5, and 10.

here we have to  find the number of possible integral values of 'a' that satisfy the given conditions, we need to compare the two inequalities:

x² - 6ax + 5a² <= 0

x² - 14x + 40 <= 0

Let's analyze each inequality separately:

x² - 6ax + 5a² <= 0

x² - 5ax -xa + 5a²<=0

(x - a)(x - 5a) <= 0

Case 1: (x - a) <= 0 and (x - 5a) <= 0

This implies a <= x <= 5a.

Case 2: (x - a) >= 0 and (x - 5a) >= 0

This implies x >= a and x >= 5a.

x² - 14x + 40 <= 0

x² - 10x-4x + 40 <= 0

(x - 4)(x - 10) <= 0

Case 3: (x - 4) <= 0 and (x - 10) <= 0

This implies 4 <= x <= 10.

Case 4: (x - 4) >= 0 and (x - 10) >= 0

This implies x >= 4 and x >= 10, which simplifies to x >= 10.

Case 1 (a <= x <= 5a) and Case 4 (x >= 10).

Since x >= 10, the lower bound of the intersection should be 10. We can substitute this value into the first inequality:

a <= 10 <= 5a

Dividing both sides by an (assuming a is positive), we get:

1 <= 10/a <= 5

To satisfy this condition, 'a' must be an integer divisor of 10. The integral values of 'a' that satisfy this condition are 1, 2, 5, and 10.

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Complete question:

if all the solutions of the inequality x² -6ax + 5a²<=0 are also the solutions of inequality x²- 14x + 40<=0 then find the number of possible integral values of a.

The question pertains to a quadratic inequality. A solution process could be carried out given the correct quadratic formula, although the initial inequality seems to contain a typo due to the lack of a comparison operator.

The question you asked is about finding the solution to quadratic inequality x^2-6ax+5a^2. In general, the solutions or roots for any quadratic equation can be calculated using the formula: -b ± √b² - 4ac / 2a. Therefore, you can potentially apply this formula to your inequality.

However, it appears that there might be a typo in your question, as an inequality should have a comparison operator (like <, >, ≤, or ≥). If the full equation was x^2-6ax+5a^2 ≤ 0 or ≥ 0, we could carry out the solution process with the given formula.

I would recommend reviewing the question to ensure that it's written correctly. Once you have the correct inequality, you can apply the quadratic formula and solve for your variable 'x'.

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