solve at least one question (30 points)

Answer:

The normal force the seat exerted on the driver is 125 N.

Explanation:

Given;

mass of the car, m = 2000 kg

speed of the car, u = 100 km/h = 27.78 m/s

radius of curvature of the hill, r = 100 m

mass of the driver, = 60 kg

The centripetal force of the driver at top of the hill is given as;

[tex]F_c = F_g - F_N[/tex]

where;

Fc is the centripetal force

[tex]F_g[/tex] is downward force due to weight of the driver

[tex]F_N[/tex] is upward or normal force on the drive

[tex]F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N[/tex]

Therefore, the normal force the seat exerted on the driver is 125 N.

The normal force exerted by the seat on the driver if the mass of the driver is 60 kg is of 125 N.

Given data:

The mass of car is, m' = 2000 kg.

The speed of car is, v = 100 km/h = 100 × 5/18 = 27.77 m/s.

The radius of curvature of path is, r = 100 m.

The mass of driver is, m = 60 kg.

In this case, the normal force on the driver is equal to the difference between weight of the driver and the centripetal force on the driver. Then the expression is given as,

[tex]N'= W - F\\\\N '= mg-\dfrac{mv^{2}}{r}[/tex]

Solving as,

[tex]N' = (60 \times 9.8)-\dfrac{60 \times 27.77^{2}}{100}\\\\N' = 125\;\rm N[/tex]

Thus, we can conclude that the normal force exerted by the seat on the driver if the mass of the driver is 60 kg is of 125 N.

Learn more about the centripetal force here:

https://brainly.com/question/14249440

Complete question is;

The cars in a soapbox derby have no engines; they simply coast downhill. Which of the following design criteria is best from a competitive point of view?

The car's wheels should;

A. have large moments of inertia

B. be massive

C. be hoop-like wheels rather than solid disks

D. have small moments of inertia

Answer:

D. The car's wheels should have small moments of inertia

Explanation:

They are simply cast downhill due to no engine and thus the solid wheels will have very small moments of inertia and will therefore accelerate at a faster rate.

Looking at the options, the correct one that corresponds to the description I just made is Option D.

The car's wheels should have small moments of inertia.

This is defined as the resistance of any physical object to a change in its velocity.

We told they were cast downhill due to no engine and the solid wheels having very small moments of inertia causing increase in acceleration depicts option D which was why it was chosen.

Read more about Inertia here https://brainly.com/question/1140505

Answer:

a) For an object with mass M, in a region with a gravitational acceleration g, is:

W = M*g

Then the weight is g times the mass of the object, this means that the weight is not always equal to the mass of the object, this first statement is false.

For example, in Earth the gravitational acceleration is 9.8m/s^2

Then there is no object in Earth with a weight equal to its mass.

b) The force of tension can be the force in a piece of string that is holding an object with mass M.

The force of tension will be always pointing in the direction to the "center" of the string, then it does not push, the tension force "pulls"

The statement is false.

c) we know that the weight is:

W = M*g

This is a force, that for an object that is in the air, will pull the object back to the ground.

Suppose that we also have that object attached to a string, and the object is in the air, now the object starts to fall due to its weight and we also pull down with the string, then the total force pulling down will be the weight plus the tension of the string, then we will have a force larger (in magnitude) than the weight, which means that the statement is false.

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

Answer:

Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer.  So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.

Explanation:

Answer:

0.06 m/s²

Explanation:

force= mass × acceleration

acceleration= force / mass

acceleration= 15/250= 0.06 m/s²

hope it helps! please mark me brainliest..

Have a good day ahead

The acceleration of the ball in the direction of the kick will be  600 m/[tex]s^{2}[/tex]

We have a Ball.

We have to determine the acceleration of the ball in the direction of the kick.

The product of mass and acceleration of a body is called force.

Force = Mass x Acceleration.

According to the question, we have -

Mass = 250 g = 0.025 Kg

Force = 15 N

Then, the acceleration of the ball in the direction of the kick will be -

F = m x a

a = F / m

a = 15 / 0.025 = 600 m/[tex]s^{2}[/tex]

Hence, the acceleration of the ball in the direction of the kick will be  600 m/[tex]s^{2}[/tex]

To solve more questions on Force, visit the link below-

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Answer:

1. 3 points

2. 6 points

3. goalkeeper

4. four quarters

5. eleven players

6. James Naismith

7. Duke nukem ( I'm not sure)

8. no

9. 1936

10. four

HOPE IT'S HELP :)

Answer:

Alpha particles carry a positive charge, beta particles carry a negative charge, and gamma rays are neutral. An alpha particle is made up of two protons and two neutrons bound together. Beta particles are high energy electrons. Gamma rays are waves of electromagnetic energy, or photons.

Answer: D. 40

Explanation:

Power = Force * Velocity

Force = 600N

Power needs to be converted to Watts:

= 24 * 1,000

= 24,000 W

24,000 = 600 * Velocity

Velocity = 24,000/600

= 40 m/s

Explanation:

Length of a string, l = 0.626 m

A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.

(a) The centripetal acceleration of the tennis ball is given by :

[tex]a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2[/tex]

(b) When r = 0.626 m and ω = 4.50 rev/s

Speed,

[tex]v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s[/tex]

When r = 1 m and ω = 4 rev/s

Speed,

[tex]v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s[/tex]

Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.

(c) [tex]a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2[/tex]

Hence, this is the required solution.

Answer:

the average reaction time is 0.25 seconds.

Answer:

B. The two sleds will move to the right.

Explanation:

I majored in physics

Answer:

b

Explanation:

Answer:

That isnt a question so no one will know the answer to what you are talking about. I suggest adding a sceenshot or picture of the question.

Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

To successfully answer the question given above, we must know the meaning of zero acceleration and negative acceleration respectively.

Zero acceleration simply means the object is not accelerating. This implies that velocity of the object is constant (i.e unchanged) with time.

Negative acceleration simply means the object is decelerating i.e coming to rest.

Now, let us answer the question given above.

From the question given above, the following data were obtained:

1. AB indicates that the particle is accelerating because the velocity increased from A to B with time.

2. BC indicates zero acceleration because the velocity of the Particle is constant (i.e unchanged) with time.

3. CD indicates that the object is coming to rest i.e decelerating (negative acceleration) because the velocity of the object decreased from C to D with time.

From the above illustrations, we can see that only option C gives the correct answer to the question.

Answer:

Option C. BC shows zero acceleration, and CD shows negative acceleration.

Explanation:

Answer:

1.52

Explanation:

Answer: 59.5 deg

Explanation:

I got it right on acellus ✅

Answer:

beta decay

Explanation:

the decay above is known as beta decay because give electron after it decay.

Answer: It’s definitely “Beta” friend!

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

Answer: D.

Explanation:

Answer:

i think the answer is b

Explanation:

playing sports often require both

Explanation:

i think C . it is twice the size of the object

Answer:

A. 9.8 m/s²

B. Zero

C. 6.125 m/s

D. 1.91 m

Explanation:

From the question given above, the following data were obtained:

Time (T) spent in the air = 1.25 s

A. Determination of the acceleration of the ball.

From the description given in question above, the motion of the tennis ball is motion under gravity. Hence, the ball will experience an acceleration due to gravity of 9.8 m/s²

B. Determination of the velocity at maximum height.

Maximum height is the greatest point reached by the tennis ball above the ground. At maximum height, the velocity of the tennis ball is zero since it has no further force to propel it upward.

C. Determination of the initial velocity of the ball.

We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:

Time (T) spent in the air = 1.25 s

Time (t) to reach the maximum height =?

T = 2t

1.25 = 2t

Divide both side by 2

t = 1.25 / 2

t = 0.625 s

Finally, we shall determine the initial velocity of the ball. This can be obtained as follow:

Time (t) to reach the maximum height = 0.625 s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) =?

v = u – gt (since the ball is going against gravity)

0 = u – (9.8 × 0.625)

0 = u – 6.125

Collect like terms

0 + 6.125 = u

u = 6.125 m/s

Thus, the initial velocity of the ball is 6.125 m/s

D. Determination of the maximum height.

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 (at maximum height)

Initial velocity (u) = 6.125 m/s

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 6.125² – (2 × 9.8 × h)

0 = 37.52 – 19.6h

Collect like terms

0 – 37.52 = – 19.6h

– 37.52 = – 19.6h

Divide both side by – 19.6

h = – 37.52 / – 19.6

h = 1.91 m

Thus, the maximum height reached by the ball is 1.91 m

Answer:

40m/s

Explanation:

144km/h

1km=1000m

1hr=3600secs

144×1000/3600=

40m/s

Answer:

When connected in parallel, the extension of both springs is the same, and the total elastic force will be equal to the sum of the forces in each spring: x=x1=x2,F=F1+F2. F=F1+F2,⇒kx=k1x1+k2x2=(k1+k2)x,⇒k=k1+k2.

Yes. The amount of stretch of a spring is proportional to the hanging mass.

According to Hooke's Law, the restoring force of the spring F is:

                   F = -kx

          k is the spring constant and x is the stretch of spring.

The restoring force F is in opposite direction of the weight of the hanging mass which is mg

                  ⇒ F = -mg

                     mg = -kx

                     x = mg/k

Hence x, the stretch of the spring is directly proportional to the hanging mass.

(i) If two springs are connected in parallel, their k- equialent is

                     [tex]k= k_{1}+k_{2}[/tex]

(ii) If two springs are connected in series, their k- equialent is

                    [tex]\frac{1}{k}=\frac{1}{k_{1} } +\frac{1}{k_{2} }[/tex]

Learn more about Hooke's Law:

https://brainly.com/question/2077015

Answer:

Mr. Dececco will not be happy

Explanation:

I'll give you a hint, the answer starts with the number 3. Use the kinematics equation of  [tex]delta\ x =v_{0}t+ \frac{1}{2}at^{2}[/tex]

Answer:

[tex]N_s : N_p = 20 : 1[/tex]

Explanation:

From the question we are told that

    The primary voltage is  [tex]V_p = 120 \ V[/tex]

     The secondary voltage is  [tex]V_s = 6 \ V[/tex]    

Generally from the transformer equation we have that

        [tex]\frac{V_p}{V_s} = \frac{N_p}{N_s}[/tex]

So

       [tex]\frac{120}{6} = \frac{N_p}{N_s}[/tex]

=>      [tex]\frac{N_p}{N_s} = 20[/tex]

Therefore the ratio of the number of turns in the secondary to the number of turns in the primary is  

       [tex]N_s : N_p = 20 : 1[/tex]

Answer:

Lens at a distance = 7.5 cm

Lens at a distance = 6.86 cm  (Approx)

Explanation:

Given:

Object distance u = 12 cm

a) Focal length = 20 cm

b) Focal length = 16 cm

Computation:

a. 1/v = 1/u + 1/f

1/v = 1/20 + 1/12

v = 7.5 cm

Lens at a distance = 7.5 cm

b.  1/v = 1/u + 1/f

1/v = 1/16 + 1/12

v = 6.86 cm  (Approx)

Lens at a distance = 6.86 cm  (Approx)

Answer:

Major, weight-bearing structures are the bones of the body that are strong and dense to be able to bear the weight of the body. The major, weight-bearing structures of cat and human skeletons are :

Human skeleton: The body weight of an individual is on his pelvic girdles that are attached to the bones of lower limbs. Thigh bones, leg bones, and bones of feet comprise lower limbs The lower limbs consist of the thigh, the leg, and the foot.

Cat skeleton:  cats are quadrupedal so it bears all the body weight on shoulders and legs that includes the Scapula and pelvis.

Answer:

a cold front i think

Explanation:

Answer:

0.40

Explanation:

a) Work done is expressed as

W = Force × distance

Given.

Force = 150N

Distance = 6.85m

Workdone = 150×6.85

Work done = 1027.5Joules

b) According to Newton's second law

\sumFx = ma

Fm - Ff = ma

Since speed is constant, acceleration us zero

Fm - Ff = 0

Fm = Ff = nR

Fm is the moving force

Ff is the frictional force

n is the coefficient of kinetic energy between the crate and rough surface

R is the reaction

From the formula;

Fm = nR

n = Fm/R

n = Fm/mg

n = 150/38(9.8)

n = 150/372.4

n = 0.40

Hence the coefficient of kinetic energy between the crate and rough surface is 0.40

Answer:

The ratio of the time period of the proton to the electron is 1835.16.

Explanation:

Given that,

Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T

We need to find the ratio between the time period of the proton Tp to the electron Te.

The time period in magnetic field is given by :

[tex]T=\dfrac{2\pi m}{qB}[/tex]

For proton, time period is :

[tex]T_P=\dfrac{2\pi m_P}{q_pB}\ ....(1)[/tex]

For an electron, the time period is :

[tex]T_e=\dfrac{2\pi m_e}{q_eB}\ ....(2)[/tex]

From equation (1) and (2) :

[tex]\dfrac{T_p}{T_e}=\dfrac{\dfrac{2\pi m_p}{q_pB}}{\dfrac{2\pi m_e}{q_eB}}\\\\As\ q_e=q_p\\\\\dfrac{T_p}{T_e}=\dfrac{m_p}{m_e}\\\\=\dfrac{1.67\times 10^{-27}}{9.1\times 10^{-31}}\\\\=1835.16[/tex]

So, the ratio of the time period of the proton to the electron is 1835.16.