what’s the coefficients of the polynomials?
The numbers preceding a variable
Step-by-step explanation:The coefficients are the number before the variable.
Finding Coefficients
All variables are multiplied by some coefficient. Sometimes those coefficients are one or another number. Take the variable 5x. The coefficient is 5. Since 5 is the number that comes before the variable, it is the coefficient. Additionally, the variable x has a coefficient of 1 because x is multiplied by 1.
Polynomial Example
Every variable within a polynomial can have a unique variable. For example, 3x⁶+5x³+2x². The first coefficient is 3, then 5, then 2. Coefficients are simply the constants that a variable is multiplied by. It does not matter what the variable is or the exponent.
i really need help with someone who really understands pythagorean therom please help i will give away brainliest and a lot of points just please help me and can someone please stop reporting this question
Answer:
Perry would need to place his ladder 6.63 ft away from the base of the basketball hoop in order to reach the hoop.
Hope this helps!
Step-by-step explanation:
The Pythagorean theorem is [tex]a^{2} +b^{2} =c^{2}[/tex].
It is given that c is 12 and b is 10, so that would be:
[tex]c^{2} -b^{2} =a^{2}[/tex]
[tex]12^{2} -10^{2} =a^{2}[/tex]
144 - 100 = [tex]a^{2}[/tex]
44 = [tex]a^{2}[/tex]
a = [tex]\sqrt{44}[/tex]
a = 6.6332...
( c is the length of the ladder, b is the height of the hoop, and a is the distance between the ladder and the basketball hoop )
Several scientists decided to travel to South America each year beginning in 2001 and record the number of insect species they encountered on each trip. The table shows the values coding 2001 as 1, 2002 as 2, and so on. Find the model that best fits the data and identify its corresponding R2 value
The best-fitting model for the data and its corresponding R2 value need to be calculated.
How to model data?To find the model that best fits the data and its corresponding R2 value, we would need to perform linear regression analysis on the data. However, since the data table is not provided, we cannot provide an answer to this question.
Linear regression analysis is a statistical method used to model the relationship between two variables. In this case, the variables are the year and the number of insect species encountered on each trip. By analyzing the data, we can determine the equation of the line that best fits the data and the R2 value, which represents the proportion of the variance in the data that is accounted for by the model. A higher R2 value indicates a better fit between the model and the data.
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Veronica has a goal of saving $12,000 for a car. She is given $3000 by her grandfather to start a savings account, and she saves an additional $500 each month. Which equation can be used to find the number of months n it will take Veronica to save for the car?
Answer:
m= month 12k - 3500= 950 she needs to save for 2 in a half months to get her car
Step-by-step explanation:
Frets are small metal bars positioned across the neck of a guitar so that the guitar can produce notes of a
specific scale. To find the distance a fret should be placed from the bridge, multiply the
string length by 2 " where nis the number of notes higher than the string 's root note.
Determine where to place a fret to produce an A note on a C string (5 notes higher) that is 70 cm long. Round
your answer to the nearest hundredth.
a. 52. 44 cm
C. 58. 33 cm
b. 93. 44 cm
d. 74. 92 cm
To produce an A note on a C string (5 notes higher) that is 70 cm long we should place a fret at a distance of 74.92cm from bridge.
To find where to place the fret, we use the formula:
distance from bridge = (string length) x [tex]2^{(n/12)[/tex]
In this case, the string length is 70 cm and we want to produce an A note on a C string, which is 5 notes higher. So n = 5.
distance from bridge = [tex]70 * 2^{(5/12)[/tex]
Using a calculator, we get:
distance from bridge ≈ 74.92 cm
Therefore, the answer is d. 74.92 cm, rounded to the nearest hundredth.
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Homework 8: Problem 5 Previous Problem Problem List Next Problem (1 point) Find all points of intersection (r, θ) of the curves t = 6 cos(θ), r= 2 sin(θ). Note. In this problem the curves intersect at the pole and one other point. Only enter the answer for nonzero r in the form (r, θ) with θ measured in radians.
Point of intersection= Need find the area inclosed in the intersection of the two graphs. Area =
The two points of intersection are (0, θ) and (0.247, θ).
The area enclosed in the intersection of the two graphs is 7π/2 square units.
To find the points of intersection of the curves:
We need to solve for θ when t = 6 cos(θ) = r/3.
We can substitute r = 2 sin(θ) into this equation to get:
6 cos(θ) = 2 sin(θ)/3
18 cos(θ) = 2 sin(θ)
9 cos(θ) = sin(θ)
Squaring both sides and using the identity sin^2(θ) + cos^2(θ) = 1, we get:
81 cos^2(θ) = 1 - cos^2(θ)
82 cos^2(θ) = 1
cos(θ) = ±sqrt(1/82)
Since we know that the curves intersect at the pole (r = 0), we only need to consider the positive root of cos(θ) to find the other point of intersection.
We can use the equation r = 2 sin(θ) to find the value of r:
r = 2 sin(θ) = 2 cos(θ) sqrt(1 - cos^2(θ)) = 2 sqrt(1/82) ≈ 0.247
So the two points of intersection are (0, θ) and (0.247, θ) where cos(θ) = sqrt(1/82) and θ is measured in radians.
To find the area enclosed in the intersection of the two graphs:
We can use the formula for the area of a polar region:
A = 1/2 ∫(r²) dθ
Since we know that the curves intersect at the pole and at (0.247, θ), we can split the integral into two parts:
A = 1/2 ∫(0 to π/2)(2 sin(θ))² dθ + 1/2 ∫(π/2 to π)(6 cos(θ))² dθ
A = π/4 + 27π/4
A = 7π/2
So the area enclosed in the intersection of the two graphs is 7π/2 square units.
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This magic grid contains number sequences that increase in steps. What is the missing number? A 16 B 8 C 4 D 12 E 20
Answer:
12
Step-by-step explanation:
The numbers increase by 4 on each row.
A car with a mass of 1200 kg and traveling 40 m/s east runs into the back of a parked truck with a mass of 2000 kg. After the collision the car and truck do not stick together, but the car is stopped. If momentum is conserved, what would the velocity of the truck be after the collision?
The velocity of the truck after the collision would be 24 m/s east.
The law of conservation of momentum states that the momentum of a closed system remains constant if no external forces act on it. In this case, we can assume that the car and the truck form a closed system.
The momentum of an object is given by its mass multiplied by its velocity, p = mv. Initially, the momentum of the system is:
p_initial = m_car * v_car + m_truck * v_truck
where m_car and v_car are the mass and velocity of the car, and m_truck and v_truck are the mass and velocity of the truck.
After the collision, the car is stopped, so its velocity is 0. The momentum of the system after the collision is:
p_final = m_car * 0 + m_truck * v'_truck
where v'_truck is the velocity of the truck after the collision.
Since momentum is conserved, we can set p_initial equal to p_final:
m_car * v_car + m_truck * v_truck = m_truck * v'_truck
Solving for v'_truck, we get:
v'_truck = (m_car * v_car + m_truck * v_truck) / m_truck
Substituting the given values, we have:
v'_truck = (1200 kg * 40 m/s + 2000 kg * 0 m/s) / 2000 kg
v'_truck = 24 m/s east
Therefore, the velocity of the truck after the collision would be 24 m/s east.
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Which one is it please help thank you.
The students who attend Memorial High School have a wide variety of extra-curricular activities to choose from in the after-school program. Students are 38% likely to join the dance team; 18% likely to participate in the school play; 42% likely to join the yearbook club; and 64% likely to join the marching band. Many students choose to participate in multiple activities. Students have equal probabilities of being freshmen, sophomores, juniors, or seniors. If Event A = sophomore or junior, what is Event A'?
Event A' has a probability of 50% (25% for freshmen + 25% for seniors).
To determine Event A', we need to first identify what Event A represents. Event A is the probability that a student is a sophomore or junior. Since students have equal probabilities of being freshmen, sophomores, juniors, or seniors, the probability of Event A is 50% (25% for sophomores + 25% for juniors).
Event A' is the complement of Event A, which means it includes the other two grade levels not included in Event A, in this case, freshmen and seniors. Therefore, Event A' is the probability that a student is a freshman or a senior. Since students have equal probabilities of being in each grade level, Event A' also has a probability of 50% (25% for freshmen + 25% for seniors).
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o produto de dois números é 54 seu MMC é 18 Qual o MDC desse número?
Porfavor explique
Answer:
o MDC de 6 e 9 é 3.
O produto de dois números é 54 e o seu MMC é 18. Precisamos encontrar o MDC desses dois números.
Primeiro, encontramos os dois números cujo produto é 54: 6 e 9.
Então, fatoramos cada número em seus fatores primos: 6 = 2 x 3 e 9 = 3 x 3.
O MDC de 6 e 9 é o produto dos fatores primos comuns, elevados à menor potência. Neste caso, o único fator primo comum é 3, elevado à primeira potência.
Portanto, o MDC de 6 e 9 é 3.
A bookstore conducted a survey to see how many books their customers bought in a year. 100 customers were chosen at random. 30% of customers bought 3 books per year, 25% of customers bought 5 books per year, and 45% of customers bought 6 books per year. What was the average number of books bought per year?
Question 1 options:
4. 50
5. 75
4. 85
The average number of books bought per year by customers in the survey is approximately 4.85 books.
To find the average number of books bought per year, we need to calculate the mean of the data set. We can do this by using the formula:
Average = (Sum of all data points) / (Number of data points)
However, we do not have the actual number of data points. Instead, we have percentages. Therefore, we need to convert the percentages into actual numbers.
Out of 100 customers surveyed:
30% bought 3 books, which is equal to 30/100 x 100 = 30 customers
25% bought 5 books, which is equal to 25/100 x 100 = 25 customers
45% bought 6 books, which is equal to 45/100 x 100 = 45 customers
Now, we can calculate the average number of books bought per year using the formula mentioned earlier:
Average = (30 x 3) + (25 x 5) + (45 x 6) / (30 + 25 + 45)
Simplifying the above equation, we get:
Average = (90 + 125 + 270) / 100
Therefore, the average number of books bought per year is:
Average = 485/100
Average = 4.85 books per year (rounded to two decimal places)
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This is math and I need help.
The inequality that can be used to determine the number of outfits Jason can purchase while staying within his budget is 68.54 o ≤ 274.16.
Solving the inequality gives:
o ≤ 4
How to find the inequality ?The total cost of items that Jason spends on :
= 217. 34 + 36. 32 + 12. 18
= $ 265. 85
The amount that Jason has left from the $ 540 is:
= 540 - 265. 85
= $ 274. 16
If each outfit costs $ 68. 54 then the inequality that would help stay in budget is:
68.54 o ≤ 274.16
Solving this, gives:
o ≤ 274. 16 / 68.54
o ≤ 4
In conclusion, Jason can purchase up to 4 biking outfits while staying within his budget.
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A bridge is to be built across a small lake from a gazebo to a dock. The bearing from the gazebo to the dock is S 41° W. From a tree 100 meters from the gazebo, the bearings to the gazebo and the dock are S 74° E and S 28° E, respectively (see figure). Find the distance from the gazebo to the dock
The distance from the gazebo to the dock is approximately 120.45 meters.
The given problem can be solved using the concept of trigonometry.
let the distance from the gazebo to the dock be "d".
According to the question it is known that the bearing from the gazebo to the dock is S 41° W which means that the angle between the line from the gazebo to the dock and due south is 41°.
Hence the angle between the line from the gazebo to the tree and due south is =(74°-41°) =33°
Similarly, the angle between the line from the dock to the tree and due south is = 28°-x =28°-41°= -13°(As it is to the west of south).
Using the trigonometry law of sines we can write,
d/ sin(41°) = 100/ sin(33°)
d=(100/sin(33°))*sin(41°)
d= 120.45 meters
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(a) Find an equation of the tangent plane to the surface at the given point. z = x2 - y2, (5, 4, 9) X-5 (b) Find a set of symmetric equations for the normal line to the surface at the given point. Х y z 10 -8 -1 y - 4 Z - 9 10 -8 -1 Ox - 5 = y - 4 = Z - 9 X + 5 y + 4 Z +9 10 -8 -1 Ox + 5 = y + 4 = 2 + 9 =
z - 9 = 10(x - 5) - 8(y - 4) this is the equation of the tangent plane at the point (5, 4, 9). (x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1). These are the symmetric equations for the normal line to the surface at the given point.
(a) To find the equation of the tangent plane to the surface z = x^2 - y^2 at the point (5, 4, 9), we first need to find the partial derivatives with respect to x and y:
∂z/∂x = 2x
∂z/∂y = -2y
Now, we evaluate these at the given points (5, 4, 9):
∂z/∂x(5, 4) = 2(5) = 10
∂z/∂y(5, 4) = -2(4) = -8
Using the tangent plane equation:
z - z₀ = ∂z/∂x (x - x₀) + ∂z/∂y (y - y₀)
Plugging in the values:
z - 9 = 10(x - 5) - 8(y - 4)
This is the equation of the tangent plane at the point (5, 4, 9).
(b) The normal vector to the surface at the given point is given by the gradient vector (∂z/∂x, ∂z/∂y, -1) = (10, -8, -1). To find the symmetric equations for the normal line, we use the point-normal form:
(x - x₀)/a = (y - y₀)/b = (z - z₀)/c
Plugging in the point (5, 4, 9) and the normal vector components (10, -8, -1):
(x - 5)/10 = (y - 4)/(-8) = (z - 9)/(-1)
These are the symmetric equations for the normal line to the surface at the given point.
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A circle of radius 6 is centred at the origin, as shown.
The tangent to the circle at point P crosses the y-axis at (0, -14).
Work out the coordinates of point P.
Give any decimals in your answer to 1 d.p.
Answer:
P = (5.4, -2.6)
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{5 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]
As the given circle has a radius of 6 units and is centred at the origin, the equation of the circle is:
[tex]x^2+y^2=36[/tex]
The formula for the equation of the tangent line to a circle with the equation x² + y² = a² is:
[tex]\boxed{y = mx \pm a \sqrt{1+ m^2}}[/tex]
where:
m is the slope.a is the radius of the circle.To find the slope of the equation of the tangent line to the circle that passes through the point (0, -14), substitute a = 6, x = 0 and y = -14 into the formula and solve for m:
[tex]\implies -14 = m(0) \pm 6 \sqrt{1+ m^2}[/tex]
[tex]\implies -14 = \pm 6 \sqrt{1+ m^2}[/tex]
[tex]\implies \pm\dfrac{14}{6} =\sqrt{1+ m^2}[/tex]
[tex]\implies \left(\pm\dfrac{14}{6}\right)^2 =1+m^2[/tex]
[tex]\implies m^2= \left(\pm\dfrac{14}{6}\right)^2-1[/tex]
[tex]\implies m^2=\dfrac{40}{9}[/tex]
[tex]\implies \sqrt{m^2}= \sqrt{\dfrac{40}{9}}[/tex]
[tex]\implies m=\pm\sqrt{\dfrac{40}{9}}[/tex]
[tex]\implies m=\pm\dfrac{2\sqrt{10}}{3}[/tex]
The slope-intercept form of a straight line is y = mx + b, where m is the slope and b is the y-intercept.
As the slope of the given tangent line is positive, and the y-intercept is (0, -14), the equation of the tangent line is:
[tex]\boxed{y=\dfrac{2\sqrt{10}}{3}x-14}[/tex]
As point P is the point of intersection of the circle and the tangent line, substitute the tangent line into the equation of the circle and solve for x:
[tex]x^2+\left(\dfrac{2\sqrt{10}}{3}x-14\right)^2=36[/tex]
Expand the brackets:
[tex]x^2 +\dfrac{40}{9}x^2-\dfrac{56\sqrt{10}}{3}x+196=36[/tex]
Subtract 36 from both sides of the equation:
[tex]\dfrac{49}{9}x^2-\dfrac{56\sqrt{10}}{3}x+160=0[/tex]
Multiply both sides of the equation by 9:
[tex]49x^2-168\sqrt{10}x+1440=0[/tex]
Rewrite the equation in the form a² - 2ab + b²:
[tex](7x)^2-2 \cdot 7 \cdot 12\sqrt{10}x+(12\sqrt{10})^2=0[/tex]
Apply the Perfect Square formula: a² - 2ab + b² = (a - b)²
[tex](7x-12\sqrt{10})^2=0[/tex]
Solve for x:
[tex]7x-12\sqrt{10}=0[/tex]
[tex]7x=12\sqrt{10}[/tex]
[tex]x=\dfrac{12\sqrt{10}}{7}[/tex]
To find the y-coordinate of point P, substitute the found value of x into the equation of the tangent line:
[tex]y=\dfrac{2\sqrt{10}}{3}\left(\dfrac{12\sqrt{10}}{7}\right)-14[/tex]
[tex]y=\dfrac{2\sqrt{10}\cdot 12\sqrt{10}}{3\cdot 7}\right)-14[/tex]
[tex]y=\dfrac{240}{21}-14[/tex]
[tex]y=\dfrac{80}{7}-\dfrac{98}{7}[/tex]
[tex]y=-\dfrac{18}{7}[/tex]
Therefore, the exact coordinates of point P are:
[tex]\left(\dfrac{12\sqrt{10}}{7}, -\dfrac{18}{7}\right)[/tex]
The coordinates of point P to 1 decimal place are:
[tex](5.4, -2.6)[/tex]
Help how do I solve for x???
The value of x that makes line A and B parallel is 13.
What is the value of x?Two Angles are Supplementary when they add up to 180 degrees.
From the diagram:
Angle 1 = 9x + 24
Angle 2 = 3x
Angle 1 and angle 2 are supplementary as their sum equals 180 degrees making line A and B parallel.
Hence:
Angle 1 + Angle 2 = 180°
Plug in the values
9x + 24 + 3x = 180
Solve for x
Collect like terms
9x + 3x = 180 - 24
12x = 156
Divide both sides by 12
12x/12 = 156/12
x = 56/12
x = 13
Therefore, the value of x is 13.
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hich of the following lists the range and IQR for this data?
The range is 10, and the IQR is 14.
The range is 10, and the IQR is 13.
The range is 14, and the IQR is 13.
The range is 14, and the IQR is 10
Answer:
The range is 10, and the IQR is 13.
Step-by-step explanation:
The range is the difference between the maximum and minimum values in a dataset, and the interquartile range (IQR) is the difference between the third quartile (Q3) and the first quartile (Q1) of the dataset.
Since the range is the difference between the maximum and minimum values in the dataset, the range cannot be 14 and the IQR be 10, since 14 is greater than 10.
Therefore, the correct answer is:
The range is 10, and the IQR is 13.
HELP!! I need the answer to pass 10th grade and im stumped D:
AB is dilated by a scale factor of 3 to form A'B'. Point O, which lies on AB, is the center of dilation.
The slope of AB is 3. The slope of A'B' is 3. A'B' passes through point O.
What is dilation in mathematics?Dilation is a process of transformation used to resize an object.
The items are enlarged or shrunk through dilation. An image that retains the original shape is created by this alteration. The size of the form does differ, though.
By multiplying the x and y coordinates of the original figure by the scale factor, you may locate locations on the dilated image when a dilation in the coordinate plane has the origin as the center of dilation.
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The volume of this rectangular prism is 216 cubic inches. What is the value of L?
After leveling the sand box, the height of the sand box is 1.57 in
What is volume?Volume is defined as the space occupied within the boundaries of an object in three-dimensional space.
The volume of a cuboid is expressed as;
V = l × w × h
V = 30 × 20 × 5
V = 3000 in³
After leveling, the volume decreases by 1680 in³, therefore the new volume of the sand box is
3000-1680 = 1320
Therefore the new height of the sand is calculated as;
1320 = 30 × 28 × h
1320 = 840h
divide both sides by 840
h = 1320/840
h = 1.57 in
therefore the height of the remaining sand is 1.57
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3. Given f(x) = x² - 7x +13 and g(x) = x-2, solve f(x) = g(x) using the substitution method. Show your
work.
Answer:
The solutions for f(x) = g(x) are x = 5 and x = 3.
To solve f(x) = g(x) using substitution method, we need to substitute g(x) in place of x in the equation f(x) = x² - 7x + 13.
So, we have:
f(x) = g(x)
x² - 7x + 13 = x - 2 (Substituting g(x) = x - 2)
Now, we can solve for x by simplifying and solving the resulting quadratic equation:
x² - 8x + 15 = 0
Factoring the quadratic equation, we get:
(x - 5)(x - 3) = 0
So, x = 5 or x = 3.
Therefore, the solutions for f(x) = g(x) are x = 5 and x = 3.
To check, we can substitute each value back into the equations:
f(5) = 5² - 7(5) + 13 = 25 - 35 + 13 = 3
g(5) = 5 - 2 = 3
f(3) = 3² - 7(3) + 13 = 9 - 21 + 13 = 1
g(3) = 3 - 2 = 1
So, both solutions satisfy the original equation f(x) = g(x).
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The following selected transactions relate to investment activities of ornamental insulation corporation during 2021. the company buys debt securities, not intending to profit from short-term differences in price and not necessarily to hold debt securities to maturity, but to have them available for sale in years when circumstances warrant. ornamental’s fiscal year ends on december 31. no investments were held by ornamental on december 31, 2020.
mar. 31 acquired 6% distribution transformers corporation bonds costing $580,000 at face value.
sep. 1 acquired $1,170,000 of american instruments’ 8% bonds at face value.
sep. 30 received semiannual interest payment on the distribution transformers bonds.
oct. 2 sold the distribution transformers bonds for $623,000.
nov. 1 purchased $1,590,000 of m&d corporation 4% bonds at face value.
dec. 31 recorded any necessary adjusting entry(s) relating to the investments.
the market prices of the investments are:
american instruments bonds $1,102,000
m&d corporation bonds $1,670,000
(hint: interest must be accrued.)
required:
2. indicate any amounts that ornamental insulation would report in its 2021 income statement, 2021 statement of comprehensive income, and 12/31/2021 balance sheet as a result of these investments. include totals for net income, comprehensive income, and retained earnings as a result of these investments.
i am having trouble understanding the statement of comprehensive income for this.
i have net income: $102,2000
other comprehensive income:
reclassification adjustment: $43,000
gain on investments: $55,000
so this part equals (12,000)
than it wants me
Ornamental Insulation Corporation would report a net income of $1,022,000 and comprehensive income of $1,010,000 resulting from these investments in its 2021 financial statements.
How does Ornamental Insulation report its income, comprehensive income, and retained earnings for 2021 as a result of its investments?Ornamental Insulation Corporation would report the following amounts in its 2021 income statement, statement of comprehensive income, and balance sheet as a result of the investment activities:
Income Statement:Interest Income from American Instruments Bonds: $93,600 ($1,170,000 × 8%)
Gain on Sale of Distribution Transformers Bonds: $43,000 ($623,000 - $580,000)
Total Net Income: $136,600 ($93,600 + $43,000)
Statement of Comprehensive Income:Gain on Investments: $55,000 (This represents the gain on the sale of the distribution transformers bonds and is included in the comprehensive income section.)
Balance Sheet (as of December 31, 2021):
Investments:American Instruments Bonds: $1,102,000 (market value)
M&D Corporation Bonds: $1,670,000 (face value)
Accumulated Other Comprehensive Income: $55,000 (This represents the gain on investments and is included in the comprehensive income section.)
Retained Earnings: Increase of $136,600 (This represents the net income from the income statement.)
In summary, Ornamental Insulation Corporation would report a net income of $136,600, a comprehensive income of $55,000, and an increase in retained earnings of $136,600 as a result of these investments for the fiscal year 2021.
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Find the directional derivative of f(x, y, z) = 23 – x²y at the point (3,-1, -2) in the direction of the vector v=(-1,-4,-4).
The directional derivative of f(x, y, z) = z³ – x²y at the point (3,-1, -2) in the direction of the vector v=(-1,-4,-4) is -234/√33.
The function is f(x, y, z) = z³ – x²y
We have to find directional derivative at the point (3, -1, -2)
In the direction vector v = (-1, -4, -4)
The gradient of the function is
∇f(x, y, z) = ∂f/∂x [tex]\hat{i}[/tex] + ∂f/∂y [tex]\hat{j}[/tex] + ∂f/∂z [tex]\hat{k}[/tex]
∇f(x, y, z) = ∂/∂x(z³ – x²y) [tex]\hat{i}[/tex] + ∂/∂y(z³ – x²y) [tex]\hat{j}[/tex] + ∂/∂z(z³ – x²y) [tex]\hat{k}[/tex]
∇f(x, y, z) = -2xy[tex]\hat{i}[/tex] - x²y[tex]\hat{j}[/tex] + 3z²[tex]\hat{k}[/tex]
At the point (3, -1, 4).
∇f(3, -1, 4) = -2(3)(-1)[tex]\hat{i}[/tex] - (3)²(-1)[tex]\hat{j}[/tex] + 3(4)²[tex]\hat{k}[/tex]
∇f(3, -1, 4) = 6[tex]\hat{i}[/tex] + 9[tex]\hat{j}[/tex] + 48[tex]\hat{k}[/tex]
The length of the vector is
|v| = √[(-1)² + (-4)² + (-4)²]
|v| = √[1 + 16 + 16]
|v| = √33
To normalize the vector we have
n = (-√33/33, -4√33/33, -4√33/33)
The directional derivative is
∇f(x, y, z) · n = (6, 9, 48) · (-√33/33, -4√33/33, -4√33/33)
∇f(x, y, z) · n = -6√33/33 - 36√33/33 - 192√33/33
∇f(x, y, z) · n = (-6 - 36 - 192)√33/33
∇f(x, y, z) · n = -234√33/33
∇f(x, y, z) · n = -234/√33
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A maker of homemade candles makes a scatter plot to show data of the diameter of a candle and the total burn time of the candle. A line of best fit of this data is T = 6. 5d + 11. 8, where T is the total burn time, in hours, and d is the diameter of the candle, in inches. Approximately how long is the total burn time of a candle with a diameter of 0. 5 inch?
answers: A. 2 hours B. 5 hours
C. 10 hours D. 15 hours
Answer:
The given line of best fit is: T = 6.5d + 11.8
We can use this equation to estimate the total burn time for a candle with a diameter of 0.5 inches:
T = 6.5(0.5) + 11.8
T = 3.25 + 11.8
T = 15.05
So, according to the line of best fit, the total burn time of a candle with a diameter of 0.5 inch would be approximately 15.05 hours.
Therefore, the answer is D. 15 hours.
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Mrs. Carter baked a cake that was in the shape of a rectangular prism. The cake was 24 inches long, 15 inches wide and 3 inches high. She spread frosting on all four sides and the top. How many square inches of frosting did she use?
477 inches squared
594 inches squared
954 inches squared
1080 inches squared
Mrs. Carter used 954 square inches of frosting.
To find the surface area of the rectangular prism cake, we need to find the area of all six sides and then subtract the bottom since frosting was not applied to it.
The area of the top and bottom sides is 24 x 15 = 360 square inches each.
The area of the two side faces is 24 x 3 = 72 square inches each.
The area of the two end faces is 15 x 3 = 45 square inches each.
So, the total surface area of the cake is:
2(360) + 2(72) + 2(45) = 720 + 144 + 90 = 954 square inches.
Since frosting was applied to all sides, including the top, we use this surface area to find the amount of frosting used.
Therefore, Mrs. Carter used 954 square inches of frosting.
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Which number line shows the sum of -8, 4, and -2?
o
a +++++
-15
10
-5
0
5
10
15
b the
- 15
- 10
-5
0
15
10
15
o
chef
15
-10
5
0
5
10
15
o
d
-15
-10
0
5
110
15
Add the given numbers: -8 + 4 + (-2) = -6. So, the sum of -8, 4, and -2 is -6.
Which number line shows the sum of -8, 4, and -2?To represent -6 on a number line, we need to find its position relative to zero. Since -6 is negative, it will be located to the left of zero. We count 6 units to the left of zero on the number line to represent -6. Therefore, the number line that shows the sum of -8, 4, and -2 is:
o----+----+----+----+----+----+----+----+----+----o
-15 -10 -5 0 5 10 15 20 25 30
-6
So, the complete answer is:
The sum of -8, 4, and -2 is -6.
To represent -6 on a number line, locate 6 units to the left of zero.
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3. What is the range of the functiony = 3x + 1 for
the domain 2 ≤ x ≤ 67
6 ≤ y ≤ 18
sy≤2
7 ≤ y ≤ 19
1
5
sys 3
During a workout, Kelly spent 10½ minutes and burned a total of 504 calories. How many calories did she burn per minute?\
Answer:
48 calories per (each) minute.
Step-by- Step
=
The parabolas y=x^2 and y=-x^2-4x+6 are graphed below. What are they-values of the solutions to this system of equations
Answer:
y = 2.25
Step-by-step explanation:
The solutions are the points of intersection of the 2 graphs.
A meal program accepts online payments by the use of a credit card. for every payment processed, the person is charged a 2% processing fee.
if a person made a payment of $23.50, how much was the fee he or she paid?
The fee paid by the person for a $23.50 payment with a 2% processing fee is $0.47.
As the meal program accepts online payments by the use of a credit card. for every payment processed and the processing fee for the credit card payment is 2% of the payment amount. To calculate the fee if a person made a payment of $23.50, we can multiply the payment amount by 2% or 0.02.
Fee = 23.50 x 0.02 = $0.47
Therefore, the fee paid by the person for a $23.50 payment is $0.47.
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Si al triple de la edad que tengo, se quita mi edad aumentada en 8 años, tendría 36 años. ¿Qué edad tengo?
damePor lo tanto, la edad que tienes es de aproximante 14.67 años.
Si al triple de la edad que tengo, se quita mi edad aumentada en 8 años, tendría 36 años. ¿
Podemos plantear este problema como una ecuación algebraica. Si llamamos "x" a la edad que tienes, la ecuación sería:
3x - 8 = 36
Ahora, despejamos la variable "x" para encontrar su valor:
3x = 36 + 8
3x = 44
x = 44/3
.Este resultado nos indica que nuestra edad actual es de aproximadamente 14.67 años. Es importante tener en cuenta que la solución no es un número entero, lo cual puede parecer inusual para una edad, pero es una respuesta matemáticamente correcta según la ecuación planteada en el problema.
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