Someone help me out eh?

Answer: [5 6 7]

Explanation: The np.arange takes in three parameters ->start,stop,step.

Hence, since we our range is 5 to 8, incrementing by 1 until we reach 8, giving us a list -> [5,6,7]

Answer:

user input loop

count variable

user input

Explanation:

these are you answers

Answer:

Chemicals

Explanation:

Answer:

Address space exhaustion

Explanation:

IPv6 (Internet Protocol version 6) was introduced in 1995. This model is faster and safer than the previous models due to the modifications done on it.

It was however introduced with the main aim of addressing space exhaustion. IPv4 addresses were already getting scarce and a new model had to be introduced to bridge the gap. IPv4 has billions of addresses however IPv6 has multiples of trillions addresses to take care of current and future needs.

Answer:

Sound waves are analogue and therefore they need to be converted into binary in order for a computer to be able to process them. To do this, the computer must convert the waveform into a numerical representation so that the waveform can be stored digitally. For this, we use an Analogue-to-Digital Convertor (ADC).

Explanation:

Answer:

Typecasting, or type conversion, is a method of changing an entity from one data type to another. It is used in computer programming to ensure variables are correctly processed by a function. An example of typecasting is converting an integer to a string.

mark me brainliesttb :))

Answer:

Here is some pseudocode that outlines the steps for creating a program that calculates overall final marks and outputs the necessary grades for a desired overall mark:

DEFINE a function called "calculate_final_mark"

INPUT: grades (list), weights (list), desired_mark (float)

CREATE a variable called "overall_mark" and set it to 0

FOR each grade and weight in the grades and weights lists:

 MULTIPLY the grade by the weight

 ADD the result to the overall_mark

IF overall_mark equals the desired_mark:

 OUTPUT "You have already achieved the desired mark."

ELSE:

 CREATE a variable called "needed_mark" and set it equal to the desired_mark minus the overall_mark

 OUTPUT "You need a" needed_mark "on your next assessment to achieve a" desired_mark "overall mark."

END the function

Here is the equivalent code in Python:

def calculate_final_mark(grades, weights, desired_mark):

 overall_mark = 0

 for grade, weight in zip(grades, weights):

   overall_mark += grade * weight

 if overall_mark == desired_mark:

   print("You have already achieved the desired mark.")

 else:

   needed_mark = desired_mark - overall_mark

   print(f"You need a {needed_mark} on your next assessment to achieve a {desired_mark} overall mark.")

Well nobody can guess my password, and if they were to brute-force hack me they have a 50% chance of finding my password.

Answer:

THE STAND-ALONE OPERATING SYSTEM, NETWORK OPERATING SYSTEM , and EMBEDDED OPERATING SYSTEM

Answer:

Server

Explanation:

Server is a central computer that enables authorized users to access networked resources.

Answer:

no

Explanation:

it just deletes the icon.

Answer:

Nope!

Explanation:

A shortcut doesn't replace or delete to original file, folder, app, etc.

Answer:

I know it

Explanation:

I will tell later

Answer:

The missing part of the code is:

for (i = 0; i < courseGrades.length; ++i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

       for (i = courseGrades.length-1; i >=0 ; --i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

Explanation:

This iterates through the array

for (i = 0; i < courseGrades.length; ++i) {

This prints each element of the array followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

This iterates through the array in reverse

       for (i = courseGrades.length-1; i >=0 ; --i) {

This prints each element of the array (reversed) followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

Answer:

Yes.

Explanation:

Check the jpeg below for the code.

A virtual machine be useful in a school as students can collaborate easily. Thus, option A is correct.

Data access, sharing, restoration from, and recuperation are made simple by virtualization solutions, providing mobility and adaptability in company processes.  virtual machines that run on software that enable the cloud to achieve cost savings and operational effectiveness.

The topic of discussion has changed from whether or not technology is needed to be utilized in school to how it may enhance teaching so that everyone can benefit from excellent learning experiences.

Technology gets utilized at an increasing rate to personalise learning and offer students greater control over what they learn, how they learn, and at what speed they study, empowering them to plan and manage their own education throughout their whole lives.

Therefore, option A is correct.

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Answer:

Explanation:

I believe the best process for this would be for the developer to create a class that has methods for opening up and reading all the data from each one of the sources. They should also add methods for easy manipulation, and writing to these files. This would allow the development team to easily reference this class and call the methods with a single line of code so that they can get and write the data from each individual source as needed. This design will also allow them to use all of these sources easily from any application by simply referencing the class and without having to change any code.

Answer:

Explanation:

.bnjuk

Answer:

def num_of_paths(maze):

   # Initialize the table with zeros

   n = len(maze)

   m = len(maze[0])

   table = [[0 for j in range(m)] for i in range(n)]

   # Fill in the first row

   for j in range(m):

       if maze[0][j] == 0:

           break

       table[0][j] = 1

   # Fill in the first column

   for i in range(n):

       if maze[i][0] == 0:

           break

       table[i][0] = 1

   # Fill in the rest of the table using dynamic programming

   for i in range(1, n):

       for j in range(1, m):

           if maze[i][j] == 0:

               table[i][j] = 0

           else:

               table[i][j] = table[i - 1][j] + table[i][j - 1]

   # Return the value in the bottom right corner of the table

   return table[n - 1][m - 1]

maze1 = ((1, 1, 1, 1, 1, 1, 1, 1, 0, 1),

(1, 0, 0, 1, 1, 1, 0, 0, 1, 1),

(0, 1, 1, 1, 0, 0, 1, 1, 1, 0),

(1, 1, 0, 1, 1, 1, 1, 0, 1, 1),

(0, 1, 0, 1, 0, 0, 1, 0, 1, 0),

(1, 0, 1, 1, 1, 1, 0, 1, 1, 1),

(1, 1, 0, 1, 0, 1, 0, 0, 1, 1),

(0, 1, 1, 1, 1, 1, 1, 1, 1, 0),

(1, 0, 1, 0, 0, 1, 1, 0, 1, 1),

(1, 0, 1, 1, 1, 0, 1, 0, 1, 0),

(1, 1, 0, 1, 0, 1, 0, 1, 1, 1))

maze2 = ((1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1),

(1, 1, 1, 1, 1, 1, 1, 1, 1))

maze3 = ((1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 1),

(1, 0, 1, 0),

(1, 0, 0, 1))

print(num_of_paths(maze1))

print(num_of_paths(maze2))

print(num_of_paths(maze3))

Answer:

here you go, if it helps ,do consider giving brainliest

Explanation:

#include<stdio.h>

int main(void)

{

  const int NUM_VALS = 4;

  int origList[4];

  int offsetAmount[4];

  int i = 0;

  origList[0] = 40;

  origList[1] = 50;

  origList[2] = 60;

  origList[3] = 70;

  offsetAmount[0] = 5;

  offsetAmount[1] = 7;

  offsetAmount[2] = 3;

  offsetAmount[3] = 0;

  // Prints the Sum of each element in the origList

  // with the corresponding value in the

  // offsetAmount.

  for (i = 0;i<NUM_VALS;i++)

  {

      origList[i] += offsetAmount[i];

      printf("%d ", origList[i]);

  }

  printf("\n");

  return 0;

}

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

while(str1[lenstr1] != '\0'){  lenstr1++;  }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Hello there!

def kilo_to_pounds(kilos):

____pounds = 2.204 * kilos

____return pounds

kilos = int(input())

print(kilo_to_pounds(kilos), 'lbs')

The program that takes a weight in kilograms as input, converts the weight to pounds, and then outputs the weight in pounds is in the explanation part.

The process of carrying out a specific computation through the design and construction of an executable computer programme is known as computer programming.

Here is the completed program in Python:

def kilo_to_pounds(kilos):

   pounds = kilos * 2.204

   return pounds

# Main program

kilo_input = float(input("Enter weight in kilograms: "))

pounds_output = kilo_to_pounds(kilo_input)

print("Weight in pounds: ", pounds_output)

Thus, the kilo_to_pounds function takes a weight in kilograms as input and converts it to pounds using the conversion factor of 2.204.

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Answer:

Insulated gloves because their made of synthetic rubber.

Explanation:

Answer:

n = int(input("How many numbers would you like to check? "))

divisible_count = 0

not_divisible_count = 0

for i in range(n):

   num = int(input("Enter a number: "))

   if num % 3 == 0:

       print(str(num) + " is divisible by 3")

       divisible_count += 1

   else:

       print(str(num) + " is not divisible by 3")

       not_divisible_count += 1

print("You checked " + str(n) + " numbers.")

print("Of those, " + str(divisible_count) + " were divisible by 3.")

print("And " + str(not_divisible_count) + " were not divisible by 3.")

Explanation:

You would run the program, it will ask the user to enter a number of integers, to check after that it will ask to enter numbers one by one, for each input, it will check if it's divisible by 3 or not, and keep counting how many were divisible or not divisible. After the loop ends, the program will output a summary of the total numbers checked, how many of them were divisible by 3 and how many were not.

You may further adjust it to match the requirement you need

You can download[tex]^{}[/tex] the answer here

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:

Architects plan, develop and implement building designs. They compile feasibility reports, determine environmental impact, create project proposals, estimate costs, determine timelines and oversee construction processes.

Explanation:

Answer:

an architect designs houses and how they will be made.

Explanation:

Answer:

Explanation:

#include <stdio.h>

void main()

{

   int  j, sum = 0;

   printf("The first 10 natural number is :\n");

   for (j = 1; j <= 10; j++)

   {

       sum = sum + j;

       printf("%d ",j);    

   }

   printf("\nThe Sum is : %d\n", sum);

}

The program illustrates the use of iterations

The most common iterations are the for loop and the while loop

The program in C, where comments are used to explain each line is as follows:

#include <stdio.h>

void main(){

   //This declares num, and initializes sum to 0

   int num, sum = 0;

   //The following iteration is repeated 10 times

   for (int i = 1; i <= 10; i++){

       scanf("%d ",&num);

       //This adds all user inputs

       sum = sum + num;

   }

   //This prints the sum

  printf("Sum: %d", sum);

}

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Answer:

1, 2, 3 and 5.

Explanation:

Answer:

a, b, c, e

Explanation:

cuz im smart

Answer:

Making their game accessible via the internet, with no need for a console

Explanation:

They made games like Farmville around this time