Suppose that you are taking a course where the total class grade is the weighted average of your homework, worksheets, quizzes and tests.
The homework is worth 15% of the course grade, worksheets are worth 20% of the course grade, the quizzes are worth 25% of the course grade, and tests are worth 40% of the course grade. To get a B in the course, you must have an overall average of at least 80%.

Your current grades in each category are:

Homework =
74
%, Worksheets =
76
%, and Quizzes =
77
%.

What is the minimum test average you need to get a B in the course?.

Your answer is:
% (Round to at least 1 decimal place)

Andy has $32 money left after spending $18 on school supplies and $47 on new clothes.

To find out how much money Andy has left, we need to start with the total amount of money he saved and then subtract the amount he spent on school supplies and new clothes.

The total amount Andy saved is:

$32 + $27 + $38 = $97

The amount Andy spent is:

$18 + $47 = $65

To find out how much money Andy has left, we can subtract the amount he spent from the amount he saved:

$97 - $65 = $32

So, after spending $18 on school supplies and $47 on new clothes, Andy is left with $32.

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Answer:

a) (1/2)(5)(CD) = 20 cm^2

5CD = 40, so CD = 8 cm

b) (1/2)(12)(8) = 48 cm^2

Using trigonometric identities when  cosθ = √2/2 and 3π/2 < θ < 2π

Trigonometric identities are mathematical equations that contain tigonometric ratios

Since cosθ = √2/2 and 3π/2 < θ < 2π, we desire to find sinθ and tanθ. We proceed as follows

a. To find sinθ, using the trigonometric identity

sin²θ = 1 - cos²θ

⇒ sinθ = ±√(1 - cos²θ)

So, substituting the value of cosθ into the equation, we have that

sinθ = ±√(1 - cos²θ)

sinθ = ±√(1 - (√2/2)²)

= ±√(1 - 2/4)

= ±√[(4 - 2)/4]

= ±√[2/4]

= ±√2/2

Since 3π/2 < θ < 2π, which is the fourth quadrant, we take the negative answer.

So, sinθ = -√2/2

b. To find tannθ, using the trigonometric identity

tan²θ = sec²θ - 1

⇒ tanθ = ±√(sec²θ - 1)

= ±√(1/cos²θ - 1)

So, substituting the value of cosθ into the equation, we have that

tanθ = ±√(1/cos²θ - 1)

tannθ = ±√(1/(√2/2)² - 1)

= ±√(1/2/4 - 1)

= ±√(4/2 - 1)

= ±√[2 - 1]

= ±√1

Since 3π/2 < θ < 2π, which is the fourth quadrant, we take the negative answer.

So, tanθ = -1

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log base 16, 32 can be written as log₂⁴ 2₅.

Evaluate with logₐx, write a and x as powers of same.

a) log₁₆ 64

= log₂⁴=2⁶

b) log₈₁ 27

= log₃⁴ 3³

c) log₁₆ 32

= log₂⁴ 2₅

d) log₂₇ 243

= log₃³ 3₅

Therefore, log base 16, 32 can be written as log₂⁴ 2₅.

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the cruising speed of the blue whale is approximately 3.16 meters per second.

What are  velocity?

a velocity is a unit of measurement for the Distance an object travels in a

the predetermined period of time. Here is a word equation that illustrates the connection between space, speed, and time: velocity is calculated by

dividing the total Distance traveled by the journey time.

In this case, we know the mass of the blue whale (m = 170,000 kg) and its kinetic energy (KE = 890,000 J), but we need to solve for its velocity (v).

Rearranging the formula, we get:

v = √(2 * KE / m)

Plugging in the values we know, we get:

v = √(2 * 890000 J / 170000 kg)

Simplifying this expression, we get:

v = √10 = 3.16 m/s

Therefore, the cruising speed of the blue whale is approximately 3.16 meters per second.

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In general, an antiderivative of a function f(x) is a function F(x) whose derivative is equal to f(x). The antiderivative of a polynomial function is obtained by adding one to the exponent of each term and dividing by the new exponent ⁵.

Caroline needs to fill the 1-quart pitcher four and a half times in order to fill all 3 pint glasses.

Since Caroline has 3 pint glasses to fill, she needs to use the 1-quart pitcher multiple times. Each time she fills the pitcher, she can pour it into 2 pint glasses

From this, we can say that Caroline needs to pour a total of 3 x 1.5 = 4.5 quarts of juice.

What is a Pitcher

Pitcher is a container with a spout and handle, used for holding and pouring liquids. It is typically used for serving beverages such as water, juice, milk, or iced tea. Pitchers can be made from a variety of materials, including glass, ceramic, metal, or plastic.

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The surface area of the pyramid is approximately 74.24 square inches.

What is a pyramid?

A pyramid is a three-dimensional geometric shape that has a polygonal base and triangular faces that meet at a single point called the apex. The most common type of pyramid is a square pyramid, which has a square base and four triangular faces.

To find the surface area of the pyramid, we need to find the area of each of the four triangular faces and the area of the square base, and then add them up.

The area of each triangular face can be found using the formula:

Area = (1/2) * base * height

where the base is one of the sides of the square base and the height is the slant height of the pyramid.

The slant height of the pyramid can be found using the Pythagorean theorem:

slant height² = height² + (1/2 * base)²

where the height is the height of the pyramid, which is given as 7 inches, and the base is 4 inches.

height = 7 in.

base = 4 in.

slant height² = 7² + (1/2 * 4)² = 49 + 4 = 53

slant height = √53 ≈ 7.28 in.

Now we can find the area of each triangular face:

Area = (1/2) * base * height = (1/2) * 4 * 7.28 ≈ 14.56 in^2

There are four triangular faces, so the total area of the triangular faces is:

4 * 14.56 = 58.24 in²

The area of the square base is:

Area = side² = 4² = 16 in²

Finally, we can find the surface area of the pyramid by adding up the area of the triangular faces and the area of the square base:

Surface Area = 58.24 + 16 = 74.24 in²

Therefore, the surface area of the pyramid is approximately 74.24 square inches.

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The estimated number of students per grade level in the state is between 66,700 and 112,800 students, with an estimated total of 580,450 students.

The anticipated number of students in line with grade level within the state is between:

(178.6 - 45.2) x 500 = 66,700 students

and

(178.6 + 45.2) x 500 = 112,800 students.

This is the range of values that we can be 95% confident includes the actual average number of students according to grade degree within the state, based on the sample of 500 high schools and the margin of mistakes of ±45.2.

To estimate the whole number of students according to grade level in the state, we can multiply the anticipated average with the aid of the total number of high schools:

3250 x 178.6 = 580,450 students

Consequently, the estimated number of students per grade level in the state is between 66,700 and 112,800 students, with an estimated total of 580,450 students.

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The area of the shaded shape is 62.5cm^2.

To find the area of the shaded shape, we need to break it down into simpler shapes that we can calculate the area of. From the image, we can see that the shape is composed of a rectangle and two right-angled triangles.

First, we need to find the dimensions of the rectangle. Since the shape has vertical and horizontal lines of symmetry passing through its center, we know that the rectangle is divided into four equal parts.

Therefore, the length of the rectangle is twice the length of one of the triangles, which is 5cm. So, the length of the rectangle is 2 x 5cm = 10cm. The width of the rectangle is also 5cm.

Next, we need to find the area of each of the triangles. We know that the base of each triangle is 5cm, and the height is half of the width of the rectangle, which is 2.5cm. Therefore, the area of each triangle is:

0.5 x base x height = 0.5 x 5cm x 2.5cm = 6.25cm^2

So, the total area of the two triangles is 2 x 6.25cm^2 = 12.5cm^2.

Finally, we can find the area of the shaded shape by adding the area of the rectangle and the area of the triangles:

Area = rectangle area + triangle area = 10cm x 5cm + 12.5cm^2 = 62.5cm^2.

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Since Q is the midpoint of NP, we know that NQ = QP. Similarly, we know that RS is the midpoint of OP, so we have RS = SO.

Let's label the length of QS as x. Then, we know that QR = 2x and SR = 3x.

To find the perimeter of triangle NOP, we need to find the lengths of NO, OP, and NP.

Using the Pythagorean Theorem, we can find that:

NO^2 = NQ^2 + OQ^2

NO^2 = (QP)^2 + (SO)^2

NO^2 = (x)^2 + (2x)^2

NO^2 = 5x^2

NO = x√5

Similarly, we can find that:

OP^2 = OQ^2 + PQ^2

OP^2 = (SO)^2 + (QP)^2

OP^2 = (3x)^2 + (x)^2

OP^2 = 10x^2

OP = x√10

Finally, we know that NP = NO + OP, so:

NP = x√5 + x√10

NP = x(√5 + √10)

To find the perimeter of NOP, we add up the three sides:

Perimeter of NOP = NO + OP + NP

Perimeter of NOP = x√5 + x√10 + x(√5 + √10)

Perimeter of NOP = x(2√5 + 2√10)

Perimeter of NOP = 2x(√5 + √10)

We can substitute the value we found for QS, which is x, to get:

Perimeter of NOP = 2(5 + 2√10)

Perimeter of NOP = 10 + 4√10

Therefore, the perimeter of triangle NOP is 10 + 4√10 units.

Answer: 64

Step-by-step explanation:

multiple all of them

Answer:

Step-by-step explanation:

After organizing the data, the researcher must present them so they can be understood by those who will benefit from reading the study. The most useful method of presenting the data is by constructing statistical charts and graphs. There are many different types of charts and graphs, and each one has a specific purpose.

This chapter explains how to organize data by constructing frequency distributions

and how to present the data by constructing charts and graphs. The charts and graphs

illustrated here are histograms, frequency polygons, ogives, pie graphs, Pareto charts,

and time series graphs. A graph that combines the characteristics of a frequency distribution and a histogram, called a stem and leaf plot, is also explained.

Section 2–2 Organizing Data 35

2–3

Objective

Organize data using

frequency

distributions.

1

2–2 Organizing Data

Suppose a researcher wished to do a study on the number of miles that the

employees of a large department store traveled to work each day. The researcher

first would have to collect the data by asking each employee the approximate distance the

store is from his or her home. When data are collected in original form, they are called

raw data. In this case, the data are

1 2 6 7 12 13 2 6 9 5

18 7 3 15 15 4 17 1 14 5

4 16 4 5 8 6 5 18 5 2

9 11 12 1 9 2 10 11 4 10

9 18 8 8 4 14 7 3 2 6

Since little information can be obtained from looking at raw data, the research

Answer:

c

Step-by-step explanation:

its ez

The distance from which the sprinkler can spread water is  4.37 feet

To determine the value, we need to know the area of the circle.

The formula for the area of a circle is expressed as;

A = πr²

Given that the parameters are;

Substitute the values, we have;

15 = 3.14r²

Divide both sides by the coefficient, we get;

r² = 4. 77

find the square root of both sides, we get;

r = 2. 19 feet

But note that the formula for diameter is given as;

Diameter = 2radius

Diameter = 2(2.19)

multiply the values

Diameter = 4.37 feet

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The average speed of the ferry is 54.54 miles per hour.

The expression for the average speed is given [tex]\frac{2d}{\frac{d}{50}+\frac{d}{60} }[/tex].

Now, the given expression can be solved as follows

2d÷ (6d/300 + 5d/300)

= 2d÷(11d/300)

= 2d×300/11d

= 600/11

= 54.54 miles per hour

Therefore, the average speed of the ferry is 54.54 miles per hour.

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To find the probability of winning the lottery game, we can use the formula for combinations:

nCk = n! / (k! * (n - k)!)

where n is the total number of choices (22 in this case) and k is the number of choices we make (6 in this case).

So, the number of possible combinations of six numbers from 22 is:

22C6 = 22! / (6! * 16!) = 13,983,816

Therefore, the probability of winning the lottery game is 1 in 13,983,816.

The expected value of playing the lottery game can be calculated as follows:

Expected value = (Probability of winning * Amount won) - (Probability of losing * Amount lost)

Expected value = (1/13,983,816 * $40,000) - (13,983,815/13,983,816 * $1)

Expected value = $0.5709

This means that on average, the player can expect to win about 57 cents per game played. However, it is important to note that this is just an average and the actual outcome of any single game can vary widely.

The true statement is that the difference between the maximum profit earned by the sandwich shop and the smoothie stand is $2,700. (option d).

To determine the maximum profit earned by each business, we need to find the vertex of each quadratic function. The vertex of a quadratic function of the form ax² + bx + c is given by the formula (-b/2a, f(-b/2a)), where f(-b/2a) is the maximum value of the function.

The equations for the two functions are:

f(x) = -500x² + 9000x + 7500 g(x) = -500x² + 7500x + 4200

To find the vertex of f(x), we need to first rewrite the function in standard form:

f(x) = -500(x² - 18x - 15)

Completing the square, we get:

f(x) = -500(x - 9)² + 12000

So the vertex of f(x) is (9, 12000), which represents the maximum profit earned by the sandwich shop.

Similarly, to find the vertex of g(x), we rewrite the function in standard form:

g(x) = -500(x² - 15x - 8.4)

Completing the square, we get:

g(x) = -500(x - 7.5)² + 14100

So the vertex of g(x) is (7.5, 14100), which represents the maximum profit earned by the smoothie stand.

Finally, we can calculate the difference between the maximum profits earned by both businesses as:

12000 - 14100 = -2700

Therefore, the correct answer is option (d).

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The evaluations are:

i. 11!  = 39916800

ii. 24! = 2.045 x 10^37

Expansion by factorial is a method of expanding a given number from 1 to the number given. An example is given thus;

5! = 5 x 4 x 3 x 2 x 1!

   = 120

To evaluate the given expressions;

a. 11! = 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1!

       = 39916800

Also,

b. 24! = 24 x 23 x 22 x 20 x ........ x 5 x 4 x 3 x 2 x 1!

          = 204484017332398 x 10 ^23

          = 2.045 x 10^37

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The calculated area of the triangle is 7.5 square inches

From the question, we have the following parameters that can be used in our computation:

The triangle with the following dimensions

base = 6 inches

height = 2.5 inches

Using the above as a guide, we have the following:

Area = 1/2 * base * height

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * 6 * 2.5

Evaluate

Area = 7.5

Hence, the area of the triangle is 7.5 square inches

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The resulting matrix after the product is given as follows:

[-32 4 20].

When a matrix is multiplied by a constant, we have that every element in the matrix is multiplied by the constant. Hence, the dimension of the matrix remains constant.

The parameters for this problem are given as follows:

Hence the products are:

Then the resulting matrix after the product is given as follows:

[-32 4 20].

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Mr. Mensah will pay 247.5 each month to the social security fund because 5.5% of 4500 is 247.5.

The total monthly salary of Mr. Mensah is 4500.

He is required to pay 5.5% of his salary into a social security fund.

Now, we have to find the amount he has to pay each month into the social security fund.

To find that, we need to find the value of 5.5 percent of 4500.

4500 ×5.5/100

45×5.5

247.5

Therefore, 5.5% of 4500 is 247.5.

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Answer:

logb28 ≈ 1.634.

Step-by-step explanation:

logb28 = (log428)/(log47)

We can then substitute the given values for logb4 and logb7:

logb28 = (log428)/(log47) = (log28)/(log24 + log27) = (log28)/(1.386 + 1.946)
1.386+1.946=3.332

logb28/3.332
logb28 ≈ 1.634.

Answer:

--------------------

Given:

Use the following identity to find [tex]log_b28[/tex]:

Apply the identity to the given:

There are 4 + 5 + 7 + 8 = 24 buttons in total.

After the cat knocks 2 buttons onto the floor, there are 22 buttons remaining on the table. The probability that the first button knocked onto the floor is blue or red can be calculated as follows:

P(blue or red) = P(blue) + P(red)

P(blue or red) = 4/24 + 5/24

P(blue or red) = 9/24

P(blue or red) = 3/8

Therefore, the probability that the button on the floor was blue or red is 3/8 or 0.375.Answer:

Step-by-step explanation:

Answer:

4x - 1 > 15

4x > 16

x > 4

The solution set is all numbers greater than 4.

If Jared uses two theorems together to make a conjecture about the sum of the interior angles of pentagons, Jared is using deductive reasoning. Correct option is B.

Deductive reasoning is a logical process in which a conclusion is reached by applying general principles or known information to specific situations. In this case, Jared is using two theorems, which are general principles that have been proven to be true, to make a conclusion about a specific situation, the sum of interior angles of pentagons.

The conclusion that Jared makes is a conjecture, which is a hypothesis or a tentative conclusion that is based on limited evidence or observation.

In contrast, inductive reasoning is a logical process in which a conclusion is reached based on a series of observations or specific instances. Inductive reasoning involves making generalizations based on specific observations, which can lead to a hypothesis or a theory.

Therefore, Jared's use of two theorems to make a conclusion is an example of deductive reasoning. Correct option is B.

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The calculated R2 value is 0.621, indicating that 62.1% of the variability in tumor growth can be explained by the linear regression model.

In statistics, the coefficient of determination, denoted by R2, is a measure of how well the regression line fits the data. It represents the proportion of the variance in the dependent variable (y) that is predictable from the independent variable (x).

To calculate R2, we use the formula R2 = SSR/SST, where SSR is the sum of squares of regression and SST is the total sum of squares.

From the given data, SSR = 568.5 and SST = 914.8. Thus, R2 = 568.5/914.8 = 0.621, rounded to three decimal places.

This means that 62.1% of the variability in the tumor growth can be explained by the linear regression model. The remaining 37.9% of the variability is unexplained and may be due to other factors not included in the model.

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The value of side c to the nearest tenth is 4.2.

The law of cosines signifies the relation between the lengths of sides of a triangle with respect to the cosine of its angle.

It is expressed as:

c² = a² + b² - ( 2ab × cosC )

From the diagram:

a = 7

b = 8

Angle C = 32 degrees

Plug these values into the above formula and solve for c.

c² = a² + b² - ( 2ab × cosC )

c = √( a² + b² - ( 2ab × cosC ) )

c = √( 7² + 8² - ( 2 × 7 × 8 × cos32 ) )

c = √( 49 + 64 - ( 112 × cos32 ) )

c = √( 113 - 94.98 )

c = √18.02

c = 4.2

Therefore, the value of c is 4.2.

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Answer:

Commutative property of addition: Changing the order of addends does not change the sum. For example, 4 + 2 = 2 + 4 4 + 2 = 2 + 4 4+2=2+44, plus, 2, equals, 2, plus, 4. Associative property of addition: Changing the grouping of addends does not change the sum

The solutions to f(x) = 0 on the interval [0, 2pi) are x = 0 and x = pi.

(a) For f(x) = 0

We set the function equal to zero and solve for x:

f(0) = sec²x - 1 = 0

sec² x = 1

Taking the square root of both sides, we get:

sec x = ±1

Recall that sec x = 1/cos x = cos⁻¹ x

Therefore

x = cos⁻¹ (1) = 0 (using calculator or table)

x = cos⁻¹(-1) = pi

Therefore, the solutions to f(x) = 0 on the interval [0, 2pi) are x = 0 and x = pi.

(b) For f(x) > 0

To get the positive values of x, we can start by factoring f(x):

f(x) = sec²x - 1 = (sec x + 1)(sec x - 1)

Since the square of the secant function is always positive, we have:

f(x) > 0 if and only if (sec x + 1)(sec x - 1) > 0

There are two cases to consider:

sec x + 1 > 0 and sec x - 1 > 0

sec x + 1 < 0 and sec x - 1 < 0

For case 1, we have:

sec x > -1 and sec x > 1

Since secant is always positive, we have sec x > 1.

For case 2, we have:

sec x < -1 and sec x < 1 (This is not possible)

(c) For f(x) < 0

By using the factored form of f(x) from part (b), we can find the values of x where f(x) is negative.

f(x) < 0 if and only if (sec x + 1)(sec x - 1) < 0

There are two cases to consider:

sec x + 1 > 0 and sec x - 1 < 0

sec x + 1 < 0 and sec x - 1 > 0

For case 1, we have:

sec x > 1 and sec x < -1 (not possible)

For case 2, we have:

sec x < -1 and sec x > 1

Since secant is always positive, this case is not possible either.

Therefore, there are no solutions to f(x) < 0 over the interval [0, 2pi).

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