The assembly consists of two 10mm diameter rods a-b and c-d, a 20 mm diameter rod e-f and a rigid bar h; point g is located at mid-distance between points e and f. all rods are made of copper with e = 101 gpa. if the magnitude of one force p is 10 kn, determine reactions at points a, c, and f.

The graphs are identified as follows

1. the domain is option G

2. the range is option E

3. the domain is option D

4. the range is option C

In coordinate geometry, the domain and range are concepts used to describe the set of possible inputs (x-values) and outputs (y-values) of a function, respectively.

The domain of a function is the set of all possible x-values for which the function is defined. In other words, it is the set of all values that can be plugged into the function and produce a meaningful output.

The range of a function is the set of all possible y-values that the function can take on as x varies over its domain. In other words, it is the set of all values that the function can output.

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The length of the base of the given triangle can be simplified as 2√2/5 feet, which is equivalent to √8/5 feet.

We are given that the area of the triangle is (2/25) * 252 square feet.

Let the length of the base be x. Then, the height of the triangle can be expressed as (2/5)x, since the base divides the triangle into two equal parts.

The area of the triangle is given by the formula A = (1/2)bh, where b is the length of the base and h is the height of the triangle.

Substituting the given values, we get:

(1/2)x(2/5)x = (2/25)*252

Simplifying this equation, we get:

(1/5)x²= 20.16

Multiplying both sides by 5, we get:

x² = 100.8

Taking the square root of both sides, we get:

x =√(100.8)

Simplifying this expression, we get:

Therefore, the length of the base is √(4.032) feet, which can be expressed as a fraction in simplest form as 2√(2)/5 feet.

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The toys approach each other at the distance of  630 cm.

To solve the problem, we can use the Pythagorean theorem.

Let the distance between the tugboat and the sail ship be d, and

let t be the time in seconds since they started moving.

Then we have:

Distance traveled by the tugboat (in cm) = 5t

Distance traveled by the sail ship (in cm) = 7t/sqrt(2)

Using the Pythagorean theorem, we have:

d² = (5t)² + (7t/(\sqrt(2)))²

d² = 25t² + 24.5t²

d² = 49.5t²

d = \sqrt(49.5)t

To find how closely the two toys approach each other, we need to find the minimum value of d.

This occurs when t is maximized, which happens when the toys are closest to each other.

The sail ship travels a distance of 8\sqrt(2) meters in the Northeast direction, which is equivalent to 800\sqrt(2) cm. Therefore, the time taken for the sail ship to travel this distance is:

t = (800\sqrt(2) cm) / (7 cm/(\sqrt(2))) = 200\sqrt(2) seconds

Substituting this value of t in the equation for d, we get:

d = \sqrt(49.5)(200\sqrt(2)) = 630 cm (corrected)

Therefore, the minimum distance between the two toys is 630 cm.

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If a rectangular piece of cardboard with dimensions 5 inches by 8 inches is used to make the curved side of a cylinder-shaped container, the greatest volume the cylinder can hold is 80/π cubic inches.

To find the greatest volume the cylinder can hold, we need to determine the dimensions of the cylinder that can be made from the given cardboard.

First, we need to calculate the circumference of the cylinder using the length of the cardboard, which will be the height of the cylinder. The length of the cardboard is 8 inches, so the circumference of the cylinder will be 8 inches.

The circumference of a cylinder is given by the formula C = 2πr, where r is the radius of the cylinder.

Therefore, 8 = 2πr, or r = 4/π inches.

Next, we need to determine the length of the curved side of the cylinder, which is given by the formula L = 2πr.

So, L = 2π(4/π) = 8 inches.

Finally, we can calculate the volume of the cylinder using the formula V = πr²h, where h is the height of the cylinder, which is 5 inches.

V = π(4/π)²(5) = 80/π cubic inches.

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Answer: 35 + 25 + 50 / 2 = 85

Step-by-step explanation: You would have to add them all together and then divide them by 2.

Manuel can type 68 words in two minutes at a rate of 34 words per minute.

Given that; Manuel types at a rate of 34 words per minute.

To determine how many words Manuel can type in two minutes, we simply need to multiply his typing rate by the number of minutes he is typing.

Since Manuel is typing for two minutes

Hence;

Number of words = Typing rate × Time

Plugging in the values we have from the problem.

Number of words = 34 words/minute × 2 minutes

Simplifying

Number of words = 34 words × 2

Number of words = 68 words

Therefore, he can type 68 words in two minutes.

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None of the provided answer choices are correct, as the correct answer should be 41 lb.

To find the total weight of the box and the presents, you simply add the weights together:

Box weight: 14 lb
Present 1 weight: 15 lb
Present 2 weight: 12 lb

Total weight = 14 lb + 15 lb + 12 lb = 41 lb

None of the provided answer choices are correct, as the correct answer should be 41 lb.

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The table that have a constant of proportionality between y and x of 12 is the first table

From the question, we have the following parameters that can be used in our computation:

The table of values

From the first table of values, we have the following readings

(x, y) = (1/2, 6), (2, 24) and (10, 120)

Using the above as a guide, we have the following:

The constant of proportionality between y and x in the graph is

k = y/x

Substitute the known values in the above equation, so, we have the following representation

k = 6/(1/2) = 24/2 = 120/10

Evaluate

k = 12 = 12 = 12

Hence, the constant of proportionality between y and x in the first table is 12

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Complete question

Which table has a constant of proportionality between y and x of 12?

x          1/2               2             10

y           6                24          120

x          1/4               3             12

y           3                60          144

x          1/3               6             9

y           4                78          117

Part A: The equation for the amount of air still needed is: y = 14,137.17 - 1600X

Part B: The total amount of air still needed to fill the ball after 4 minutes is 8,937.17 cubic inches.

Part C: It takes approximately 8.84 minutes to pump up the ball to its maximum volume.

Part A:

The formula for the volume of a sphere is 4/3πr³, where r is the radius. Since the maximum diameter of the exercise ball is 30 inches, its radius is 15 inches. Therefore, the maximum volume of the ball is:

4/3π(15)³ = 14,137.17 cubic inches

Let's let y represent the amount of air still needed to fill the ball to its maximum volume, and X represent the number of minutes the pump has been running. We know that the pump is filling the ball at a rate of 1600 cubic inches per minute. Therefore, the equation for the amount of air still needed is:

y = 14,137.17 - 1600X

Part B:

After 4 minutes, the pump has filled the ball with:

1600 x 4 = 6400 cubic inches

Using the equation from Part A, we can find the amount of air still needed after 4 minutes:

y = 14,137.17 - 1600(4) = 8,937.17 cubic inches

Therefore, the total amount of air still needed to fill the ball after 4 minutes is 8,937.17 cubic inches.

Part C:

To find the estimated number of minutes it takes to pump up the ball to its maximum volume, we can set the equation from Part A equal to 0 (since y represents the amount of air still needed):

0 = 14,137.17 - 1600X

Solving for X, we get:

X = 8.84

Therefore, it takes approximately 8.84 minutes to pump up the ball to its maximum volume.

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Check the picture below.

Answer:

C (12)

Step-by-step explanation:

Answer:

250+25d= P

Step-by-step explanation:

How to say it aloud: "$250 plus 25 times miles ran is equal to total amount earned"

250 is a fixed amount that is apart of the equation. In order to get a correct total at the end, $250 must be added to 25d.

25d stands for $25 times the amount of miles ran, which according to the word problem is represented by d. The reason we multiply 25 times d is because Marcus is getting $25 for every mile he runs. At the end of his run, we need to multiply $25 by those miles.

The reason everything equals P is because according to the word problem, P is the amount of money earned.

I hope that makes sense.

Answer:

0 hrs 32 mins

Step-by-step explanation:

The system of equation is 7.71 feet, under the condition the area of a rug is 108 square feet and the length it it’s diagonal is 14 feet.

Now to solve this problem, we can use the formula for the area of a rectangle which is A = L x W . Therefore, we can write the equation 108 = L x W

Now the length of the diagonal is 14 feet. We can use this information to write another equation using the Pythagorean theorem which states that for any right triangle with legs of length a and  b  and hypotenuse of length c ,
a² + b² = c²
Since a rectangle is made up of two right triangles, we can use this theorem to find the length and width of the rectangle.

Let us assume the length of the rug L and the width of the rug  W

L²+ W² = 14²

We have two equations with two unknowns

108 = L x W
L² + W² = 14²

We can solve for one variable in terms of another using substitution. From the first equation,

W = 108 / L

Substituting this into the second equation gives:


L² + (108 / L)² = 14²
L² - 196L² + 11664 = 0


This is a quadratic equation in terms of  L². We can solve for L²  


L² = (196 ± √(196² - 4 x 11664)) / 2
L² = (196 ± √(38416)) / 2
L² = (196 ± 196) / 2


Taking the positive root gives:

L² = 196

So:

L = √(196) = 14

Substituting this back into one of our original equations gives:

W = 108 / L
= 108 / 14
≈ 7.71

Therefore, the length of the rug is 14 feet and its width is approximately 7.71 feet.
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The probability of  P(Ski) is 7 / 30, P(Snowboard) is 13 / 30,P(Ski & Snowboard) is 2/15 and P(ski or snowboard) is  8/15.

1. Probability of a student skiing (P(Ski)):
  P(Ski) = number of students who ski / total number of students = 28 / 120 = 7 / 30

2. Probability of a student snowboarding (P(Snowboard)):
  P(Snowboard) = number of students who snowboard / total number of students = 52 / 120 = 13 / 30

3. Probability of a student skiing and snowboarding (P(Ski & Snowboard)):
  P(Ski & Snowboard) = number of students who ski and snowboard / total number of students = 16 / 120 = 4 / 30

=2/15

4.Probability(ski or snowboard) = (7/30) + (13/30) - (2/15)

P(ski or snowboard) = 8/15
Therefore, the probabilities are:

P(ski) = 7/30

P(snowboard) = 13/30

P(ski and snowboard) = 2/15

P(ski or snowboard) = 8/15

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To evaluate the given integral using cylindrical coordinates, we need to first express the given solid E and the differential volume element dv in terms of cylindrical coordinates.

In cylindrical coordinates, the paraboloid z = 1 – x^2 - y^2 can be expressed as z = 1 – r^2, where r is the distance from the z-axis and θ is the angle made with the positive x-axis. Since the solid E lies in the first octant, we have 0 ≤ r ≤ √(1-z), 0 ≤ θ ≤ π/2, and 0 ≤ z ≤ 1 – r^2.

The differential volume element dv in cylindrical coordinates is given by dv = r dz dr dθ.

Substituting these expressions in the given integral, we get:

SITE . 742 + x^2 dv = ∫∫∫E (742 + r^2) r dz dr dθ

= ∫θ=0π/2 ∫r=0√(1-z) ∫z=0^(1-r^2) (742 + r^2) r dz dr dθ

= ∫θ=0π/2 ∫r=0√(1-z) [(742r + r^3/3) - (742r^3/3 + r^5/5)] dr dθ

= ∫θ=0π/2 ∫z=0^1 [247/3(1-z)^(3/2) - 185/6(1-z)^(5/2)] dz dθ

= ∫θ=0π/2 [98/15 - 185/21] dθ

= ∫θ=0π/2 [56/315] dθ

= [28/315]π

Therefore, the value of the given integral using cylindrical coordinates is [28/315]π.

To evaluate the given integral using cylindrical coordinates, we need to express the function and limits of integration in terms of cylindrical coordinates (r, θ, z). The conversion between Cartesian and cylindrical coordinates is given by:

x = r*cos(θ)
y = r*sin(θ)
z = z

The given function in the problem is z = 1 - x^2 - y^2. Substituting the expressions for x and y in terms of cylindrical coordinates, we get:

z = 1 - r^2(cos^2(θ) + sin^2(θ))
z = 1 - r^2

Now, we need to find the limits of integration for r, θ, and z. Since E is the solid in the first octant, the limits for θ are 0 to π/2. For r, the limits are 0 to √(1 - z), and for z, the limits are 0 to 1. Then, the integral becomes:

∫(0 to π/2) ∫(0 to √(1 - z)) ∫(0 to 1) (742 + r^2cos^2(θ) + r^2sin^2(θ)) * r dz dr dθ

Solve this triple integral to find the volume of the solid E.

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The total surface area of the cone is 44π cm², where π represents the mathematical constant pi.

We have,

To find the total surface area of a cone, we need to calculate the lateral surface area (denoted by L) and the base area (denoted by B), and then sum them.

The lateral surface area of a cone is given by L = πrℓ, where r is the radius of the base and ℓ is the slant height.

The base area is given by B = πr², where r is the radius of the base.

Given the dimensions:

Radius of the base (r) = 4 cm

Slant height (ℓ) = 7 cm

We can calculate the lateral surface area as L = π(4)(7) = 28π cm².

The base area can be calculated as B = π(4^2) = 16π cm².

Now, to find the total surface area (SA), we sum the lateral surface area and the base area:

SA = L + B = 28π + 16π = 44π cm².

Therefore,

The total surface area of the cone is 44π cm², where π represents the mathematical constant pi.

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The perimeter of the 8 feet by 6 feet rectangular garden is 28 feet.

We will need to install chicken wire along this entire length to satisfy the customer's requirements. Good luck with your project!

To find the perimeter of a rectangular garden, you can use the formula:

Perimeter = 2(Length + Width). In this case, the garden measures 8 feet by 6 feet,

so the length is 8 feet and the width is 6 feet.
Add the length and width.
8 feet + 6 feet = 14 feet
Multiply the sum by 2.
2(14 feet) = 28 feet.
The perimeter of the rectangular garden is 28 feet.

As a contractor, you will need to install chicken wire along this entire 28 feet of the garden's perimeter to meet the customer's request.
Remember to choose the appropriate type of chicken wire, considering factors such as durability, mesh size, and material (e.g., galvanized steel or plastic).

Additionally, we may need to install supporting posts at regular intervals to ensure the stability and effectiveness of the chicken wire fence.

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we can see that there is no stem value of 4 and therefore no department store with 49 pairs of glasses.

To find the largest number of pairs of glasses at any one department store, we need to examine the stem-and-leaf plot provided.

The stem-and-leaf plot shows the number of pairs of glasses at each store, with the first digit (the stem) indicating the tens place and the second digit (the leaf) indicating the ones place.

Looking at the plot, we can see that the largest stem is 4, which corresponds to the number 40. The largest leaf for stem 4 is 8, which corresponds to the number 48. Therefore, the largest number of pairs of glasses at any one department store is 48.

We can also verify this by scanning through the leaves in the plot and looking for the largest value. The largest leaf value is 9, which corresponds to the number 49. However, we can see that there is no stem value of 4 and therefore no department store with 49 pairs of glasses.

The largest number of pairs of glasses at any one department store is indeed 48.

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The quadratic function in vertex form that passes through the point (1, -3) is: f(x) = (x - 1)²  - 3

What is vertex form?

Vertex form is a way of expressing a quadratic function of the form:

f(x) = a(x - h)² + k

where (h, k) is the vertex of the parabola, and a is a constant that determines the shape and direction of the parabola.

The quadratic function in vertex form is given by:

f(x) = a(x - h)²  + k

where (h, k) is the vertex of the parabola.

We are given the point (1, -3), which lies on the parabola. This means that:

f(1) = -3

Substituting x = 1 into the vertex form of the equation, we get:

f(1) = a(1 - h)²  + k

-3 = a(1 - h)²  + k

Since we don't know the value of h or a, we can't solve for k directly. However, we can use the vertex form of the equation to find the values of h and k.

The vertex of the parabola is the point (h, k). Since the parabola passes through the point (1, -3), we know that the vertex lies on the axis of symmetry, which is the vertical line x = 1.

Therefore, the x-coordinate of the vertex is h = 1. Substituting this into the equation above, we get:

-3 = a(1 - 1)²  + k

-3 = a(0) + k

k = -3

Now that we know the value of k, we can substitute it back into the equation above and solve for a:

-3 = a(1 - h)²  + k

-3 = a(1 - 1)²  + (-3)

-3 = a(0) - 3

a = 1

Therefore, the quadratic function in vertex form that passes through the point (1, -3) is:

f(x) = (x - 1)²  - 3

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The maximum and minimum values for given function f(x, y) = 5x² + 5y² subject to xy = 1 are both 10. The extreme values of f(x, y, z) = x + 2y; x + y + z = 6, y² + z² = 4 subject to both constraints are 7 and -4.

We can use Lagrange multipliers to find the maximum and minimum values of f(x, y) subject to the constraint xy = 1.

First, we set up the Lagrange function

L(x, y, λ) = 5x² + 5y² + λ(xy - 1)

Then, we take partial derivatives of L with respect to x, y, and λ and set them equal to 0

∂L/∂x = 10x + λy = 0

∂L/∂y = 10y + λx = 0

∂L/∂λ = xy - 1 = 0

Solving these equations simultaneously, we get

x = ±√2, y = ±√2, λ = ±5/2√2

We also need to check the boundary points where xy = 1, which are (1, 1) and (-1, -1). We evaluate f at these points and compare them to the values we get from the Lagrange multipliers.

f(√2, √2) = 10, f(-√2, -√2) = 10

f(1, 1) = 10, f(-1, -1) = 10

So the maximum and minimum values of f(x, y) subject to xy = 1 are both 10.

We can use Lagrange multipliers to find the extreme values of f(x, y, z) subject to both constraints.

First, we set up the Lagrange function

L(x, y, z, λ, μ) = x + 2y + λ(x + y + z - 6) + μ(y² + z² - 4)

Then, we take partial derivatives of L with respect to x, y, z, λ, and μ and set them equal to 0

∂L/∂x = 1 + λ = 0

∂L/∂y = 2 + λ + 2μy = 0

∂L/∂z = λ + 2μz = 0

∂L/∂λ = x + y + z - 6 = 0

∂L/∂μ = y² + z² - 4 = 0

Solving these equations simultaneously, we get

x = -1, y = 2, z = 3, λ = -1, μ = -1/2

x = 3, y = -2, z = -1, λ = -1, μ = -1/2

We also need to check the boundary points where either x + y + z = 6 or y² + z² = 4. These points are (0, 2, 2), (0, -2, -2), (4, 1, 1), and (4, -1, -1). We evaluate f at these points and compare them to the values we get from the Lagrange multipliers.

f(-1, 2, 3) = 7, f(3, -2, -1) = -1

f(0, 2, 2) = 4, f(0, -2, -2) = -4

f(4, 1, 1) = 6, f(4, -1, -1) = 2

So the maximum value of f subject to both constraints is 7, which occurs at (-1, 2, 3), and the minimum value of f subject to both constraints is -4, which occurs at (0, -2, -2).

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1)  The domain of Y = 3x⁴ + 4x³ is (-∞, ∞).

2) The x-intercepts are (0, 0) and (-4/3, 0) and the y-intercept is (0, 0)

3)  The horizontal asymptote is y = infinity.

4) Function does not exhibit any symmetry with respect to the y-axis or origin.

5)  The critical points are x = 0 and x = -1.

6)  The critical points are x = 0 and x = -1.

7) The function is concave down on the interval (-∞, -2/3) and concave up on the intervals (-2/3, 0) and (0, ∞).

1) The domain of a polynomial function is all real numbers, so the domain of Y = 3x⁴ + 4x³ is (-∞, ∞).

2) To find the x-intercepts, we set Y equal to zero and solve for x:

0 = 3x⁴ + 4x³

0 = x³(3x + 4)

x = 0 or x = -4/3

Therefore, the x-intercepts are (0, 0) and (-4/3, 0).

To find the y-intercept, we set x equal to zero and solve for Y:

Y = 3(0)⁴ + 4(0)³

Y = 0

Therefore, the y-intercept is (0, 0).

3) Polynomial functions do not have vertical asymptotes. However, as x approaches positive or negative infinity, the function approaches infinity. Therefore, the horizontal asymptote is y = infinity.

4) The function Y = 3x⁴ + 4x³ is neither even nor odd. Therefore, it does not exhibit any symmetry with respect to the y-axis or origin.

5) To find the critical points, we take the first derivative of Y and set it equal to zero:

Y' = 12x³ + 12x²

0 = 12x²(x + 1)

Therefore, the critical points are x = 0 and x = -1.

6) To determine whether the critical points are maxima or minima, we take the second derivative of Y and evaluate it at each critical point:

Y'' = 36x² + 24x

At x = 0, Y'' = 0, which means that the second derivative test is inconclusive. To determine whether x = 0 is a maxima or minima, we look at the sign of the first derivative to the left and right of the critical point. We find that Y' is negative to the left of x = 0 and positive to the right, so x = 0 is a local minimum.

At x = -1, Y'' = 12, which is positive. Therefore, x = -1 is a local minimum.

7) To determine the concavity of the function, we look at the sign of the second derivative:

Y'' = 36x² + 24x

When Y'' > 0, the function is concave up, and when Y'' < 0, the function is concave down.

At x < -2/3, Y'' is negative, so the function is concave down.

At -2/3 < x < 0, Y'' is positive, so the function is concave up.

At x > 0, Y'' is positive, so the function is concave up.

Therefore, the function is concave down on the interval (-∞, -2/3) and concave up on the intervals (-2/3, 0) and (0, ∞).

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The width of the rectangle is approximately 5.39 meters.

Let's denote the width of the rectangle by x. According to the problem, the length of the rectangle is 4 meters more than the width, which means that the length can be represented as x+4.

The formula for the area of a rectangle is A = length x width. In this case, we know that the area of the rectangle is 77 square meters, so we can set up the following equation:

77 = (x+4)x

Expanding the brackets, we get:

77 = x² + 4x

Rearranging this equation into standard quadratic form, we get:

x² + 4x - 77 = 0

To solve for x, we can use the quadratic formula:

[tex]x = \frac{(-b ± sqrt(b^2 - 4ac))}{ 2a}[/tex]

Plugging in the values for a, b, and c, we get:

[tex]x = \frac{(-4 ± sqrt(4^2 - 4(1)(-77)))}{ 2(1)}[/tex]

Simplifying this expression, we get:

[tex]x = \frac{(-4 ± sqrt(336)} { 2}[/tex]

[tex]x = \frac{(-4 ± 4sqrt(21))}{ 2}[/tex]

x = -2 ± 2[tex]\sqrt{(21)}[/tex]

Since the width of a rectangle cannot be negative, we discard the negative solution and get:

x = -2 ± 2[tex]\sqrt{(21)}[/tex]

Therefore, the width of the rectangle is approximately 5.39 meters (rounded to two decimal places).

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The solution to the system of differential equations x' = y - x + t and y' = y with initial conditions x(0) = 9 and y(0) = 4 is x(t) = 10e^t - t - 1 and y(t) = 9e^t - 5t - 5.To find this solution, we first solve for y in the second equation:y' - y = 0y(t) = Ce^tNext, we substitute this expression for y into the first equation and solve for x:x' = Ce^t - x + tx' + x = Ce^t + tMultiplying both sides by e^t, we get:(e^t x)' = Ce^2t + te^tIntegrating both sides:e^t x(t) = (C/2)e^2t + te^t + DUsing the initial condition x(0) = 9, we get:D = 9Using the expression for y(t) and the initial condition y(0) = 4, we get:C = 5Substituting these values into the equation for x(t), we get:x(t) = 10e^t - t - 1Finally, we substitute the expression for y(t) into the given initial condition y(0) = 4 and solve for the constant C:C = 9 - 5tSubstituting this expression for C into the equation for y(t), we get:y(t) = 9e^t - 5t - 5

For more similar questions on topic Vectors in 2D is a sub-topic in linear algebra that deals with the study of vectors in two-dimensional space. In two-dimensional space, vectors are represented as ordered pairs of real numbers and can be used to describe quantities such as displacement, velocity, and force. The magnitude and direction of a vector can be calculated using trigonometry, and vectors can be added, subtracted, and multiplied by scalars using the rules of vector algebra.

In the context of the given problem, we are asked to find two unit vectors in 2D that make an angle of 45 degrees with a given vector 6i + 5j, where i and j are the unit vectors in the x and y directions, respectively. To solve this problem, we need to use the properties of vectors and trigonometry to find the appropriate unit vectors that satisfy the given conditions. The solution to this problem involves finding the components of the given vector, calculating the angle between this vector and the x-axis, and using this angle to construct the desired unit vectors.

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The solution to the system of differential equations is:
x(t) = 5 e^(t/2) - 4 e^(3t/2)
y(t) = 4

To solve this system of differential equations, we can use Laplace transforms. Taking the Laplace transform of both sides of each equation, we get:

sX(s) - x(0) = Y(s) - X(s) + T Y(s)
sY(s) - y(0) = Y(s)

Substituting in the initial conditions x(0) = 9 and y(0) = 4, we can solve for X(s) and Y(s):

X(s) = (s + 1)/(s^2 - s - T)
Y(s) = 4/s

To find x(t) and y(t), we need to inverse Laplace transform these expressions. We can use partial fractions to simplify the expression for X(s):

X(s) = A/(s - r1) + B/(s - r2)

where r1 and r2 are the roots of the denominator s^2 - s - T, given by:

r1 = (1 - sqrt(1 + 4T))/2
r2 = (1 + sqrt(1 + 4T))/2

Solving for A and B, we get:

A = (r2 + 1)/(r2 - r1)
B = -(r1 + 1)/(r2 - r1)

Substituting these values back into the expression for X(s), we get:

X(s) = (r2 + 1)/(r2 - r1)/(s - r1) - (r1 + 1)/(r2 - r1)/(s - r2)

Taking the inverse Laplace transform of this expression, we get:

x(t) = (r2 + 1)/(r2 - r1) e^(r1 t) - (r1 + 1)/(r2 - r1) e^(r2 t)

Substituting in the values for r1 and r2, we get:

x(t) = 5 e^(t/2) - 4 e^(3t/2)

Similarly, taking the inverse Laplace transform of Y(s) = 4/s, we get:

y(t) = 4

Therefore, the solution to the system of differential equations is:

x(t) = 5 e^(t/2) - 4 e^(3t/2)
y(t) = 4

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60 ≤ 1.36x + 34 ≤ 85; To stay within the range, the usage should be between 19.1 and 37.5 HCF.

The correct compound inequality to represent the scenario is:

60 ≤ 1.36x + 34 ≤ 85

To solve for x, we need to isolate it in the middle of the inequality:

60 - 34 ≤ 1.36x ≤ 85 - 34

26 ≤ 1.36x ≤ 51

Finally, we divide by 1.36 to isolate x:

19.12 ≤ x ≤ 37.5

Therefore, the recommended range of water consumption is between 19.1 and 37.5 HCF. The answer is (D) 60 ≤ 1.36x + 34 ≤ 85; To stay within the range, the usage should be between 19.1 and 37.5 HCF.

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complete question

To conserve water, many communities have developed water restrictions. The water utility charges a fee of $34, plus an additional $1.36 per hundred cubic feet (HCF) of water. The recommended monthly bill for a household is between $60 and $85 dollars per month. If x represents the water usage in HCF in a household, write a compound inequality to represent the scenario and then determine the recommended range of water consumption. (Round your answer to one decimal place.)

60 ≤ 1.36x − 34 ≤ 85; To stay within the range, the usage should be between 69.1 and 87.5 HCF.

60 ≤ 1.36x − 34 ≤ 85; To stay within the range, the usage should be between 44.1 and 87.5 HCF.

60 ≤ 1.36x + 34 ≤ 85; To stay within the range, the usage should be between 37.5 and 44.1 HCF.

60 ≤ 1.36x + 34 ≤ 85; To stay within the range, the usage should be between 19.1 and 37.5 HCF.

In a circle with radius 6 and angle intercepts an arc of length 3π , the angle in radians in simplest form is π/2.

In a circle, the length of an arc is proportional to the angle that it intercepts. The ratio of the arc length to the circumference of the circle is equal to the ratio of the angle in radians to 2π. Thus, we can write:

(arc length) / (circumference) = (angle) / (2π)

In this problem, we are given that the circle has a radius of 6 and that the arc length is 3π. We can use the formula for the circumference of a circle, which is C = 2πr, to find the circumference of this circle:

C = 2πr = 2π(6) = 12π

Now we can use the formula above to find the angle in radians:

(3π) / (12π) = (angle) / (2π)

Simplifying this equation, we get:

angle = (3π * 2π) / 12π = 1/2 * π

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Diego selling raffle tickets for $1.75 per ticket and she earned for 50 tickets is $87.50.

When a purchase, appropriation, requisition, or direct engagement with the customer occurs at the point of sale, the seller or supplier of the products or services completes a transaction. Title (property or ownership) of the object is transferred, and a price is settled, meaning a price is agreed upon for which the ownership of the item will transfer.

We can calculate how much money Diego would make if he sold each quantity of raffle tickets for $1.75 each using Excel's multiplication function. It is possible to create a table with the number of tickets sold in one column and the money taken in the other.

Diego would receive $17.50, for instance, if he sold 10 tickets (10 x $1.75). If he sold 20 tickets, he would earn $35 (20 x $1.75), and so on. Using Excel's fill handle, you can quickly fill the table with the totals for each sold ticket.

The table would look like this:

Number of Tickets Sold | Amount of Money Earned

•----------------------------------|---------------------------------------•

   10                                |    $17.50

   20                               |    $35.00

   30                               |    $52.50

   40                               |    $70.00

   50                               |    $87.50

By using the multiplication function in Excel, we can quickly calculate the amount of money Diego would earn for any number of raffle tickets sold at $1.75 per ticket.

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The value 78 inches best describes the tallest player on the Bulldogs baseball team. This height is an outlier within the data set and may affect statistical analyses.

The Bulldogs, a baseball team, consists of nine starting players with varying heights. Their heights are as follows: 72 in, 71 in, 78 in, 70 in, 72 in, 72 in, 73 in, 70 in, and 72 in. To describe the data, we can analyze the presence of the 78 in height value.

In this case, the value 78 in represents the tallest player on the team. When examining this data set, it is important to understand how this value affects the overall distribution of heights among the players. One way to determine this is by calculating the mean, median, and mode of the height data.

The mean (average) height for the team is 71.22 inches, and the median (middle) value is 72 inches. The mode (most frequent) height is also 72 inches. The value 78 inches is above the mean and median values, indicating that it is an outlier, or a value that is significantly different from the majority of the other data points.

In conclusion, the value 78 inches best describes the tallest player on the Bulldogs baseball team. This height is an outlier within the data set and may affect statistical analyses. However, it provides valuable information about the diversity of heights among the starting players on the team.

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The correct expression that is equal to 4.6 is option c. [1.6 + (3 × 4)] – (2 ÷ 2)

Let's evaluate each expressions using the BODMAS rule of mathematics,

a. 1.6 + (3 × 4) – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

b. 1.6 + 3 × 4 – 2 ÷ 2

= 1.6 + 12 - 1

= 12.6

c. [1.6 + (3 × 4)] – (2 ÷ 2)

= [1.6 + 12] - 1

= 12.6

d. (1.6 + 3) × (4 – 2) ÷ 2

= 4.6 × 2 ÷ 2

= 4.6

BODMAS is an acronym used to remember the order of operations in mathematics: Brackets, Orders, Division, Multiplication, Addition, Subtraction. It is used to perform calculations in the correct order to obtain the correct result. Therefore, the correct answer is (c).

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Complete question - Which expression is equal to 4.6?

a. 1.6 + (3 × 4) – 2 ÷ 2

b. 1.6 + 3 × 4 – 2 ÷ 2

c. [1.6 + (3 × 4)] – (2 ÷ 2)

d. (1.6 + 3) × (4 – 2) ÷ 2

Answer:

a + s = 21.7

7a = 6s - 0.8

Step-by-step explanation:

I just used pattern recognition in my head and stuff i dont know how to explain

The instant when the radar gun is used, the rate at which the distance between the two cars is changing is g'(t) = 7968t + 368/5 kilometers per hour.

Let's break down the problem. We have two cars, one traveling south at 112 km/h and another traveling west at 96 km/h. The police car is stationed at an intersection and the two cars are at different points relative to the intersection. The first car is 4/5 kilometer north of the intersection while the second car is 2/5 kilometer east of the intersection.

Let's call this distance "d". Using the Pythagorean theorem, we can write:

d² = (4/5)² + (2/5)² d² = 16/25 + 4/25 d² = 20/25 d = sqrt(20)/5 d = 2sqrt(5)/5 kilometers

Now, we need to find the rate at which the distance between the two cars is changing. This is equivalent to finding the derivative of the distance with respect to time. Let's call this rate "r".

To find "r", we need to use the chain rule. The distance between the two cars is a function of time, so we can write:

d = f(t)

where t is time. We can then write:

r = d'(t) = f'(t)

where d'(t) and f'(t) denote the derivatives of d and f with respect to time, respectively.

To find f'(t), we need to express d in terms of t. We know that the first car is traveling at a constant speed of 112 km/h due south. Let's call the position of the first car "x" and the time "t". Then we have:

x = -112t

The negative sign indicates that the car is moving south. Similarly, we can express the position of the second car in terms of time. Let's call the position of the second car "y". Then we have:

y = 96t

The positive sign indicates that the car is moving west.

Now, we can use these expressions to find the distance between the two cars as a function of time. Let's call this function "g(t)". Then we have:

g(t) = √((x + 4/5)² + (y - 2/5)²) g(t) = √((-112t + 4/5)² + (96t - 2/5)²)

To find g'(t), we need to use the chain rule. We have:

g'(t) = (1/2)(x + 4/5)'(x + 4/5)'' + (y - 2/5)'x(y - 2/5)''

where the primes denote derivatives with respect to time. We can simplify this expression by noting that x' = -112 and y' = 96. We also have x'' = y'' = 0, since the speeds of the two cars are constant.

Substituting these values, we get:

g'(t) = -112x(-112t + 4/5)/√((-112t + 4/5)² + (96t - 2/5)²) + 96x(96t - 2/5)/√((-112t + 4/5)² + (96t - 2/5)²)

Simplifying this expression, we get:

g'(t) = (-112x(-112t + 4/5) + 96x(96t - 2/5))/√((-112t + 4/5)² + (96t - 2/5)²)

We can further simplify this expression by multiplying out the terms in the numerator:

g'(t) = (-12544t + 560/5 + 9216t - 192/5)/√((-112t + 4/5)² + (96t - 2/5)²)

g'(t) = (7968t + 368/5)/√((-112t + 4/5)² + (96t - 2/5)²)

g'(t) = 7968t + 368/5

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Complete Question:

A car is traveling at 112 km/h due south at a point 4/5 kilometer north of an intersection_ police, the car Is traveling at 96 km/h due west to at point 2/5 kilometer due cust of the same intersection. At that instant; the radar in the police car measures the rate at which the distance between the two cars [ changing: What does the radar gun register?