Remember to convert the measurements to the same unit. Once you have the volume of the rock, express it in cubic centimeters (cm³) since the water level rise was given in centimeters.
To find the volume of the rock, we can use the concept of displacement. When the rock is submerged in the container, it displaces a certain amount of water equal to its own volume.
Given that the water level rises by 0.5 cm when the rock is submerged, we know that the volume of the rock is equal to the volume of water displaced, which can be calculated using the formula:
Volume of rock = Volume of water displaced
The volume of water displaced can be calculated using the formula:
Volume of water displaced = length × width × height
Since the shape of the container is a rectangular solid, the length, width, and height are already given. We can substitute the values into the formula to find the volume of the rock.
To know more about volume visit:-
https://brainly.com/question/28058531
#SPJ11
Question 4 A book of mass m is taken to a heighth with a constant speed. A rock of mass 2m is taken to the same height also at a constant speed. The rock rises to this height twice as fast as the book. The work the gravitational force does on the rock is one quarter of the the work done on the book one half of the work done on the book twice the work done on the book four times the work done on the book the same as the work done on the book
The work done by the gravitational force on the rock is four times the work done on the book.
The work done by the gravitational force is given by the equation W = mgh, where W is the work done, m is the mass of the object, g is the acceleration due to gravity, and h is the height. Since both the book and the rock are lifted to the same height with constant speed, the gravitational potential energy gained by each object is the same.
Let's assume the work done on the book is W_book. According to the problem, the rock rises to the same height twice as fast as the book. Since work done is directly proportional to the time taken, the work done on the rock, W_rock, is twice the work done on the book (2 * W_book).
Learn more about gravitational force click here: brainly.com/question/32609171
#SPJ11
At what separation is the electrostatic force between a +14 uC point charge and a +54 uC point charge equal in magnitude to 3.1 N? (In m)
The separation at which the electrostatic force between a +14 uC point charge and a +54 uC point charge is equal in magnitude to 3.1 N is approximately 0.32 meters.
To calculate this, we can use Coulomb's law, which states that the electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.Mathematically, Coulomb's law can be expressed as: F = k * |q1 * q2| / r^2 where F is the electrostatic force, k is the electrostatic constant (k = 8.99 x 10^9 N*m^2/C^2), q1 and q2 are the charges of the two point charges, and r is the separation between them.
In this case, we have q1 = +14 uC = +14 x 10^-6 C and q2 = +54 uC = +54 x 10^-6 C. We are given that the magnitude of the electrostatic force is 3.1 N. By rearranging Coulomb's law, we can solve for the separation:
r = sqrt(k * |q1 * q2| / F)
Substituting the given values, we find:
r = sqrt((8.99 x 10^9 N*m^2/C^2) * |(14 x 10^-6 C) * (54 x 10^-6 C)| / (3.1 N))
Calculating this expression gives us a separation of approximately 0.32 meters.
To learn more about electrostatic force click here : brainly.com/question/9774180
#SPJ11
Numerical Response #2 A 400 g mass is hung vertically from the lower end of a spring. The spring stretches 0.200 m. The value of the spring constant is _____N/m.6. A node is where two or more waves produce A. destructive interference with no displacement B. destructive interference with maximum amplitude C. constructive interference with maximum amplitude D. constructive interference with no displacement
The value of the spring constant is determined by the mass and the amount the spring stretches. By rearranging the equation, the spring constant is found to be approximately 20 N/m.
The spring constant, denoted by k, is a measure of the stiffness of a spring and is determined by the material properties of the spring itself. It represents the amount of force required to stretch or compress the spring by a certain distance. Hooke's Law relates the force exerted by the spring (F) to the displacement of the spring (x) from its equilibrium position:
F = kx
In this scenario, a 400 g mass is hung vertically from the lower end of the spring, causing it to stretch by 0.200 m. To determine the spring constant, we need to convert the mass to kilograms by dividing it by 1000:
mass = 400 g = 0.400 kg
Now we can rearrange Hooke's Law to solve for the spring constant:
k = F / x
Substituting the values we have:
k = (0.400 kg * 9.8 m/s^2) / 0.200 m
Calculating this expression gives us:
k ≈ 19.6 N/m
Rounding to the nearest significant figure, we can say that the value of the spring constant is approximately 20 N/m.
Learn more about Spring constant here ; brainly.com/question/14159361
#SPJ11
The tension in a ligament in the human knee is approximately proportional to the extension of the ligament, if the extension is not too
large. If a particular ligament has an
effective spring constant of 159 N/mm as it is stretched, what is the tension in this ligament when it is
stretched by 0.720 cm?
The pressure in a ligament in the mortal knee is roughly commensurable to the extension of the ligament if the extension isn't toolarge.However, the pressure in this ligament when it's stretched by 0, If a particular ligament has an effective spring constant of 159 N/ mm as it's stretched.720 cm is 115.68N.
Hooke's law is a law that states that the force F demanded to extend or compress a spring by some distance X scales linearly with respect to that distance.
That's F = kx Where F is the force applied, k is the spring constant, and x is the extension or contraction of the spring. Pressure is defined as the force transmitted through a rope, string, line, or any other analogous object when it's pulled tense by forces acting on its ends. Pressure, like any other force, can be represented in newtons( N).
For this problem, the extension x = 0.720 cm = 0.0720 cm = 0.0720/ 10 = 0.00720 m, and the spring constant k = 159 N/ mm = 159 N/ 1000 mm = 0.159 N/ mm = 0.159 N/m.
Using Hooke's law F = kx = (0.159 N/ m) ×(0.00720 m) = 0.001145 N ≈115.68N.
The tension in the ligament when itstretched by 0.720 cm is 115.68N.
#SPJ11
Learn more about spring constant and tension https://brainly.com/question/14670501
Problem#14(Please Show Work 30 points) (a) A pendulum is set up so that its bob (a thin copper disk) swings between the poles of a permanent magnet as shown in Figure 22.63. What is the magnitude and direction of the magnetic force on the bob at the lowest point in its path, if it has a positive 0.250 μC charge and is released from a height of 40.0 cm above its lowest point? The magnetic field strength is 2.50 T. (b) What is the acceleration of the bob at the bottom of its swing if its mass is 35.0 grams and it is hung from a flexible string? Be certain to include a free-body diagram as part of your analysis.
(a) To find the magnitude and direction of the magnetic force on the bob of the pendulum at the lowest point in its path, we can use the equation for the magnetic force on a charged particle moving through a magnetic field:
F = qvB sinθ
where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
In this case, the bob of the pendulum has a charge of +0.250 μC (or 0.250 × 10^-6 C) and is released from a height of 40.0 cm (or 0.40 m) above its lowest point. The magnetic field strength (B) is 2.50 T.
At the lowest point, the velocity of the bob is purely horizontal and perpendicular to the magnetic field. Therefore, the angle θ between the velocity vector and the magnetic field vector is 90 degrees.
Substituting the given values into the formula:
F = (0.250 × 10^-6 C) * v * (2.50 T) * sin(90 degrees)
Since sin(90 degrees) = 1, the equation simplifies to:
F = (0.250 × 10^-6 C) * v * (2.50 T)
We need to determine the velocity of the bob at the lowest point. To do that, we can use the conservation of mechanical energy. At the release point, all the potential energy is converted into kinetic energy:
mgh = (1/2)mv²
where m is the mass of the bob, g is the acceleration due to gravity, h is the release height, and v is the velocity at the lowest point.
Given that the mass (m) of the bob is 35.0 grams (or 0.035 kg), the release height (h) is 40.0 cm (or 0.40 m), and the acceleration due to gravity (g) is 9.8 m/s², we can solve for v:
(0.035 kg)(9.8 m/s²)(0.40 m) = (1/2)(0.035 kg)v²
v² = (0.035 kg)(9.8 m/s²)(0.80 m)
v² = 0.2744 m²/s²
v ≈ 0.523 m/s
Substituting the value of v into the equation for F:
F = (0.250 × 10^-6 C) * (0.523 m/s) * (2.50 T)
F ≈ 3.28 × 10^-7 N
Therefore, the magnitude of the magnetic force on the bob at the lowest point is approximately 3.28 × 10^-7 N, and the direction of the force is perpendicular to both the velocity vector and the magnetic field vector.
(b) To find the acceleration of the bob at the bottom of its swing, we need to analyze the forces acting on the bob using a free-body diagram.
The forces acting on the bob are the tension in the string (T) and the gravitational force (mg).
At the bottom of the swing, the tension in the string provides the centripetal force to keep the bob moving in a circular path. Therefore, the tension (T) is equal to the centripetal force:
T = m * a_c
where m is the mass of the bob and a_c is the centripetal acceleration.
The gravitational force (mg) acts vertically downward. At the bottom of the swing, it does not contribute to the acceleration along.
To know more about Acceleration, click here:
brainly.com/question/2303856
#SPJ11
Two empty soda cans are placed upright on a frictionless table, where the cans are separated by several centimetres. Predict the motions of the cans when you blow air through
the gap between the cans using a straw. Explain this in 80 words.
When air is blown through the gap between the two upright soda cans using a straw, the cans will move away from each other. This is due to the principle of action and reaction.
The air blown through the gap creates a stream of fast-moving air molecules that exert a force on the inner surfaces of the cans. According to Newton's third law of motion, the cans will experience an equal and opposite force, causing them to move in opposite directions away from each other.
To know more about Newton's third law of motion refer here
https://brainly.com/question/974124#
#SPJ11
7. A bar magnet passes through a circular loop of wire as shown below. At the instant that the middle of the magnet passes through the loop, the induced current (as seen from the coil # 2) is A counte
The passage of a bar magnet through a circular loop of wire induces a current in the wire.
At the instant that the middle of the magnet passes through the loop, the induced current is a counterclockwise direction in coil #2.
This phenomenon is known as electromagnetic induction and is described by Faraday's Law. When a magnetic field changes in intensity or moves relative to a conductor (such as a wire), it induces an electromotive force (EMF) in the conductor, which in turn creates an electric current. In this case, as the bar magnet passes through the circular loop of wire, the magnetic field changes, which induces a current in the wire.
This induced current follows Lenz's Law, which states that the direction of the induced current is always in such a direction as to oppose the change that produced it. In this case, as the north pole of the bar magnet enters the loop, it creates a magnetic field pointing upwards through the loop. Therefore, the induced current creates a magnetic field in the opposite direction (downwards) to oppose the change. This corresponds to a counterclockwise induced current in coil #2.
As the bar magnet continues to pass through the loop, the magnetic field changes again, and the induced current will change accordingly. Once the bar magnet exits the loop, the induced current will stop. This phenomenon has numerous applications in everyday life, including electromagnetic induction used in power plants to generate electricity
To learn more about emf click brainly.com/question/30083242
#SPJ11
A400 ohm resistor is connected in series with a 0.35 H inductor and AC-source. The potential difference across the resistor is VR-6.8 cos (680rad/s)t a) What is the circuit current at t-1.6s? t in Volts. b) Determine the inductive reactance of the inductor? c) What is the voltage across the inductor (V₁) at t=3.2s? J₁ = 2
In this series circuit, a 400-ohm resistor is connected with a 0.35 H inductor and an AC source.
The potential difference across the resistor is given by VR = 6.8 cos(680 rad/s)t. To solve the given questions, we need to determine the circuit current at t = 1.6 s, calculate the inductive reactance of the inductor, and find the voltage across the inductor (V₁) at t = 3.2 s.
a) To find the circuit current at t = 1.6 s, we can use Ohm's law. The potential difference across the resistor is VR = 6.8 cos(680 rad/s)(1.6 s). Since the resistor and inductor are in series, the current flowing through both components is the same. Therefore, the circuit current at t = 1.6 s is I = VR / R, where R is the resistance value of 400 ohms.
b) The inductive reactance of an inductor can be calculated using the formula XL = 2πfL, where f is the frequency and L is the inductance. In this case, the frequency is given by ω = 680 rad/s. Thus, the inductive reactance of the 0.35 H inductor is XL = 2π(680)(0.35).
c) To determine the voltage across the inductor (V₁) at t = 3.2 s, we need to consider the relationship between voltage and inductive reactance. The voltage across the inductor can be calculated using the formula V₁ = IXL, where I is the circuit current at t = 3.2 s, and XL is the inductive reactance determined in part (b).
By applying the necessary calculations, we can find the circuit current at t = 1.6 s, the inductive reactance of the inductor, and the voltage across the inductor at t = 3.2 s using the given information.
Learn more about resistor here: brainly.com/question/30672175
#SPJ11
A boy kicks a soccer ball from the ground, giving it an initial velocity of 34 m/s at some unknown angle. The ball reaches a maximum height of 19m above the ground. Use energy to determine the velocity?
the velocity of the soccer ball is approximately 27.29 m/s.To determine the velocity of the soccer ball, The total energy is the sum of the kinetic energy (0.5mv²) and the potential energy (mgh). Since the initial kinetic energy is zero, we can equate the potential energy at the maximum height to the total energy at the ground level. Solving for v, we get:
0.5mv² + mgh = mgh
0.5v² = 2gh
v² = 4gh
v = √(4gh)
Given that g is approximately 9.8 m/s² and h is 19m, we can substitute these values:
v = √(4 * 9.8 * 19) = √(745.6) ≈ 27.29 m/s
Therefore, the velocity of the soccer ball is approximately 27.29 m/s.
To learn more about energy click on:brainly.com/question/1932868
#SPJ11
A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.553rev/s. What is its angular velocity (in rev/s) after a 16 kg child gets onto it by grabbing its outer edge? The child is initially at rest.
The angular velocity (in rev/s) after a 16 kg child gets onto it by grabbing its outer edge will be 2.30 rads per sec.
How to calculate the angular velocityTo calculate the angular velocity, we will begin by noting the measurements given to us which are:
Mass of merry-go-round = 120 kg
Radius = 1.80 m
Rotating angular velocity = 0.553 rev/s
Mass of child = 16 kg
We will then apply the velocity formula:
[tex]Wf = \frac{Mmrm^{2} /2.Wb}{Mmrm^{2} /2 + Mcrc^{2} }[/tex]
Factoring in the figures, we will then have
120(1.8)²/2. 3.14 ÷ 20(1.8)²/2 + 22(1.8)²
= 2.3 rad/secs.
Learn more about angular velocity here:
https://brainly.com/question/29566139
#SPJ4
Consider two objects of masses m₁= 8.775 kg and m₂ = 4.944 kg. The first mass (m₂) is traveling along the negative y-axis at 48.38 km/hr and strikes the second stationary mass m₂, locking the two masses together. What is the velocity of the first mass before the collision? What is the velocity of the second mass before the collision? What is the final velocity of the two masses? What is the total initial kinetic energy of the two masses? What is the total final kinetic energy of the two masses? How much of the mechanical energy is lost due to this collision?
The initial velocity of the second mass (m₂) is 0 as it is stationary. To find the initial velocity of the first mass (m₁), we will use the equation for kinetic energy.Kinetic energy = 1/2 mv²where m is the mass of the object and v is its velocity.
The kinetic energy of the first mass can be found by converting its velocity from km/hr to m/s.Kinetic energy = 1/2 (8.775 kg) (48.38 km/hr)² = 1/2 (8.775 kg) (13.44 m/s)² = 797.54 JSo the total initial kinetic energy of the two masses is the sum of the kinetic energies of the individual masses: 797.54 J + 0 J = 797.54 JThe final velocity of the two masses can be found using the law of conservation of momentum.
According to the law of conservation of momentum, the momentum before the collision is equal to the momentum after the collision.m₁v₁ + m₂v₂ = (m₁ + m₂)vfwhere m₁ is the mass of the first object, v₁ is its velocity before the collision, m₂ is the mass of the second object, v₂ is its velocity before the collision, vf is the final velocity of both objects after the collision.
Since the second mass is stationary before the collision, its velocity is 0.m₁v₁ = (m₁ + m₂)vf - m₂v₂Substituting the given values in the above equation and solving for v₁, we get:v₁ = [(m₁ + m₂)vf - m₂v₂]/m₁= [(8.775 kg + 4.944 kg)(0 m/s) - 4.944 kg (0 m/s)]/8.775 kg = 0 m/sSo the initial velocity of the first mass is 0 m/s.
The momentum of the system after the collision is:momentum = (m₁ + m₂)vfThe total final kinetic energy of the system can be found using the equation:final kinetic energy = 1/2 (m₁ + m₂) vf²Substituting the given values in the above equation, we get:final kinetic energy = 1/2 (8.775 kg + 4.944 kg) (0.9707 m/s)² = 25.28 JThe mechanical energy lost due to this collision is the difference between the initial kinetic energy and the final kinetic energy:energy lost = 797.54 J - 25.28 J = 772.26 JThus, the mechanical energy lost due to this collision is 772.26 J.
Initial velocity of the first mass = 0 m/sInitial velocity of the second mass = 0 m/sFinal velocity of the two masses = 0.9707 m/sTotal initial kinetic energy of the two masses = 797.54 JTotal final kinetic energy of the two masses = 25.28 JEnergy lost due to this collision = 772.26 J.
To know about velocity visit:
https://brainly.com/question/30559316
#SPJ11
An electron moves north at a velocity of 9.8 x 104 m/s and has a
magnetic force of 5.6x10 -18 N west exerted on it. If the magnetic
field points upward, what is the magnitude of the magnetic
field.
i
The magnitude of the magnetic field is 3.5x[tex]10^-5[/tex] Tesla. To determine the magnitude of the magnetic field, we can use the formula for the magnetic force experienced by a moving charged particle in a magnetic field:
F = qvB sin(θ)
where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and θ is the angle between the velocity vector and the magnetic field vector.
In this case, we are given the magnetic force (F = 5.6x10^-18 N), the velocity of the electron (v = 9.8x10^4 m/s), and the direction of the magnetic force (west). We need to find the magnitude of the magnetic field (B).
Since the force is perpendicular to the velocity, the angle θ between the velocity vector and the magnetic field vector is 90 degrees. Therefore, sin(θ) = 1.
B = F / (qv)
B = (5.6x[tex]10^-18[/tex]N) / (1.6x1[tex]0^-19[/tex] C x 9.8x[tex]10^4[/tex] m/s)
B = 3.5x[tex]10^-5[/tex] T
Therefore, the magnitude of the magnetic field is 3.5x[tex]10^-5[/tex]Tesla.
Learn more about magnetic field here:
https://brainly.com/question/19542022
#SPJ11
What happens to the deflection of the galvanometer needle (due to moving the magnet) when you increase the area of the coils? ( original 50%, increase it to 70 % or 80%). Explain.
We can see that when you increase the area of the coils in a galvanometer, the deflection of the galvanometer needle will generally increase as well. This is because the increase in coil area leads to an increase in the magnetic field strength produced by the coils when a current flows through them.
What is galvanometer?A galvanometer is a device used to detect and measure small electric currents. It consists of a coil of wire wound around a movable spindle, a permanent magnet, and a pointer or needle attached to the spindle.
When an electric current passes through the coil, it creates a magnetic field that interacts with the magnetic field of the permanent magnet, causing the spindle to rotate and the pointer to deflect.
Learn more about galvanometer on https://brainly.com/question/16553202
#SPJ4
The sound intensity 300.0 m from a wailing tornado siren is 0.10 W/m². What is the sound intensity level 50.0 m from the siren?
The sound intensity level at a distance of 50.0 m from the siren is approximately 1.33 W/m², calculated using the inverse square law for sound propagation and the formula for sound intensity level.
To calculate the sound intensity level at a distance of 50.0 m from the siren, we can start by using the inverse square law for sound propagation:
I₁/I₂ = (r₂/r₁)²
Where I₁ and I₂ are the sound intensities at distances r₁ and r₂, respectively. We are given that the sound intensity at a distance of 300.0 m is 0.10 W/m².
So, plugging in the values:
0.10 W/m² / I₂ = (50.0 m / 300.0 m)²
Simplifying:
I₂ = 0.10 W/m² / ((50.0 m / 300.0 m)²)
= 0.10 W/m² / (0.1667)²
= 0.10 W/m² / 0.02778
≈ 3.60 W/m²
Now, to determine the sound intensity level (L), we can use the formula:
L = 10 log₁₀ (I/I₀)
Where I is the sound intensity and I₀ is the reference intensity, typically 10^(-12) W/m².
Using the given sound intensity of 3.60 W/m²:
L = 10 log₁₀ (3.60 / 10^(-12))
= 10 log₁₀ (3.60) + 10 log₁₀ (10^12)
≈ 10 log₁₀ (3.60) + 120
≈ 10 (0.556) + 120
≈ 5.56 + 120
≈ 125.56 dB
Therefore, the sound intensity level at a distance of 50.0 m from the siren is approximately 125.56 dB.
To learn more about sound intensity, click here: https://brainly.com/question/32194259
#SPJ11
A car of mass 1374 kg accelerates from rest to 15.2 m/s in 5.40 s. How much force was required to do this?
The force required to accelerate the car from rest to 15.2 m/s in 5.40 s is approximately 3858.5 N.
To calculate the force required to accelerate the car, we can use Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and acceleration:
F = m * a
Where:
F is the force (what we're trying to find)m is the mass of the car (1374 kg)a is the acceleration of the car (which can be calculated using the formula Δv / Δt, where Δv is the change in velocity and Δt is the change in time)Given that the car starts from rest (initial velocity, v₀ = 0) and reaches a final velocity of 15.2 m/s in 5.40 s, we can calculate the acceleration:
Δv = v - v₀ = 15.2 m/s - 0 m/s = 15.2 m/s
Δt = 5.40 s
a = Δv / Δt = 15.2 m/s / 5.40 s
Now, let's calculate the force:
F = (1374 kg) * (15.2 m/s / 5.40 s)
F ≈ 3858.5 N
Therefore, the force required to accelerate the car from rest to 15.2 m/s in 5.40 s is approximately 3858.5 Newtons.
To learn more about Newton's second law of motion, Visit:
https://brainly.com/question/2009830
#SPJ11
A 957-g empty iron kettle is put on a stove. How much heat. in joules. must it absorb to raise its temperature from 15.0°C to 37.0°C? (The specific heat for iron is 113 cal/kg•C°, 1 cal = 4.190 J) 10,900 J 9950 J 2380 J 16,700 J A monatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.02 m2 to 0.14 m3. The final pressure of the gas is 140 kPa. The ideal gas constant is R = 8.314 J/mol · K. The change in the internal (thermal) energy of the gas is closest to 0.00 kJ. -38 kJ. -19 kJ. 19 kJ. 38 kJ.
1. The heat absorbed by the iron kettle is approximately 10,900 J.
2. The change in the internal energy of the gas is closest to 0.00 kJ.
1. To calculate the heat absorbed by the iron kettle, we can use the formula:
Q = m × c × ΔT
where Q is the heat, m is the mass of the iron kettle, c is the specific heat of iron, and ΔT is the change in temperature.
Given:
m = 957 g = 0.957 kg (converting to kilograms)
c = 113 cal/kg·°C = 113 × 4.190 J/kg·°C (converting to joules)
ΔT = (37.0°C - 15.0°C)
Substituting the values into the formula:
Q = 0.957 kg × (113 × 4.190 J/kg·°C) × (37.0°C - 15.0°C)
Q ≈ 10900 J
Therefore, the heat absorbed by the iron kettle is approximately 10900 J.
2. For an isothermal process, the change in internal (thermal) energy of the gas is zero. Therefore, the change in internal energy is closest to 0.00 kJ.
Therefore, the answer is 0.00 kJ.
Read more on internal energy here:https://brainly.com/question/31951981
#SPJ11
Find the total surface area of the washer, rounded to one
decimal place, for x = 14 mm and y = 24 mm. Hint: Think of the
washer as a cylinder through which a hole has been drilled.
The total surface area of the washer, considering the outer and inner cylinders, is approximately 1051.4 mm². The outer cylinder contributes to the surface area while the inner cylinder, representing the hole, does not affect it.
To find the total surface area of the washer, we need to calculate the surface area of the outer cylinder and subtract the surface area of the inner cylinder.
The surface area of a cylinder is given by the formula:
[tex]A_{cylinder[/tex]= 2πrh
where r is the radius of the cylinder's base and h is the height of the cylinder.
In this case, the washer can be seen as a cylinder with a hole drilled through it, so we need to calculate the surface areas of both the outer and inner cylinders.
Let's calculate the total surface area of the washer:
Calculate the surface area of the outer cylinder:
Given x = 14 mm, the radius of the outer cylinder ( [tex]r_{outer[/tex] ) is half of x, so [tex]r_{outer[/tex] = x/2 = 14/2 = 7 mm.
The height of the outer cylinder ([tex]h_{outer[/tex]) is y = 24 mm.
[tex]A_{outer_{cylinder[/tex] = 2π [tex]r_{outer[/tex][tex]h_{outer[/tex] = 2π(7)(24) ≈ 1051.4 mm² (rounded to one decimal place).
Calculate the surface area of the inner cylinder:
Given the inner radius (r_inner) is 7 mm less than the outer radius, so r_inner = r_outer - 7 = 7 - 7 = 0 mm (since the inner hole has no radius).
The height of the inner cylinder ([tex]h_{inner[/tex]) is the same as the outer cylinder, y = 24 mm.
[tex]A_{inner_{cylinder[/tex] = 2π [tex]r_{inner[/tex] [tex]h_{inner[/tex] = 2π(0)(24) = 0 mm².
Subtract the surface area of the inner cylinder from the surface area of the outer cylinder to get the total surface area of the washer:
Total surface area = [tex]A_{outer_{cylinder[/tex] - [tex]A_{inner_{cylinder[/tex] = 1051.4 - 0 = 1051.4 mm².
Therefore, the total surface area of the washer, rounded to one decimal place, is approximately 1051.4 mm².
Learn more about Surface area
brainly.com/question/29298005
#SPJ11
Using your knowledge of kinetic molecular theory and methods of transfer of heat, explain what happens when a person puts their hand down on a very hot stove top. Also explain how they may have had a warning that the stovetop would be hot before their hand touched the stove.
When a person puts their hand down on a very hot stove top, the heat energy is transferred from the stove top to the person's hand. Kinetic molecular theory explains that the temperature of a substance is related to the average kinetic energy of the particles that make up that substance. In the case of the stove top, the heat causes the particles to vibrate faster and move farther apart, which results in an increase in temperature.
The transfer of heat occurs by three methods, namely conduction, convection, and radiation. In this case, the heat is transferred through conduction. Conduction is the transfer of heat energy through a substance or between substances that are in contact. When the person's hand touches the stove top, the heat energy is transferred from the stove top to the person's hand through conduction.
Before touching the stove, the person may have had a warning that the stove top would be hot. This is because of the transfer of heat through radiation. Radiation is the transfer of heat energy through electromagnetic waves. The stove top, which is at a higher temperature than the surrounding air, emits heat energy in the form of radiation. The person may have felt the heat radiating from the stove top, indicating that the stove top was hot and that it should not be touched.
Learn more about the kinetic molecular theory: https://brainly.com/question/134712
#SPJ11
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1,200 kg and is approaching at 7.74 m/s due south. The second car has a mass of 805 kg and is
approaching at 15.7 m/s due west.
Calculate the final velocity (magnitude and direction) of the cars.
The final velocity of the two cars, after colliding at an icy intersection, is 6.51 m/s at an angle of 309 degrees from the south.
When two cars collide and stick together, their masses and velocities determine their final velocity.
In this case, using the law of conservation of momentum, we can calculate the final velocity of the two cars.
The initial momentum of the first car is (1200 kg)(7.74 m/s) = 9292.8 kgm/s south.
The initial momentum of the second car is (805 kg)(15.7 m/s) = 12648.5 kgm/s west.
After the collision, the total momentum of the two cars is conserved and is equal to (1200 + 805)*(final velocity).
Solving for the final velocity, we get a magnitude of 6.51 m/s.
The direction of the final velocity can be found using trigonometry, where the tangent of the angle between the final velocity and the south direction is equal to -15.7/7.74.
This gives us an angle of 309 degrees from the south.
Therefore, the final velocity of the two cars is 6.51 m/s at an angle of 309 degrees from the south.
Learn more about Velocity from the given link:
https://brainly.com/question/18084516
#SPJ11
Gravity is an inverse-square force like electricity and magnetism. If lighter weight moose has a weight of 3640 N on Earth's surface (approximately 6.37 · 10^6 m from Earth's center), what will the moose's weight due to Earth in newtons be at the Moon's orbital radius (approximately 3.84 · 10^8 m from Earth's center) to two significant digits?
To two significant digits, the weight of the moose due to Earth at the Moon's orbital radius would be approximately 60 N.
To calculate the weight of the moose due to Earth at the Moon's orbital radius, we need to consider the inverse-square relationship of gravity and apply it to the given distances.
Given:
Weight of the moose on Earth's surface = 3640 N
Distance from Earth's center at Earth's surface (r1) = 6.37 × 10^6 m
Distance from Earth's center at Moon's orbital radius (r2) = 3.84 × 10^8 m
The gravitational force between two objects is given by the equation F = (G * m1 * m2) / r^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.
To find the weight of the moose at the Moon's orbital radius, we need to calculate the force at that distance using the inverse-square relationship.
First, we calculate the ratio of the distances squared:
(r2/r1)^2 = (3.84 × 10^8 m / 6.37 × 10^6 m)^2
Next, we calculate the weight at the Moon's orbital radius:
Weight at Moon's orbital radius = Weight on Earth's surface * (r1^2 / r2^2)
Substituting the given values:
Weight at Moon's orbital radius ≈ 3640 N * (6.37 × 10^6 m)^2 / (3.84 × 10^8 m)^2
Calculating the weight at the Moon's orbital radius:
Weight at Moon's orbital radius ≈ 60 N
To learn more about gravitational force: https://brainly.com/question/32609171
#SPJ11
21 of 37 Attempt Many expressions in special relativity contain the gamma (Y) factor. 1 Y= V1 - 02/22 In the equation, v is the speed of some object or reference frame and c is the speed of light. Find the numerical value of y for each of the listed speeds. v = 0. incorrect V = 0.450c. Y incorrect 0.990, Y Incorrect retel renants how the value of y depends on speed.
The value of γ (gamma) increases as the speed (v) approaches the speed of light (c).
The correct expression for the gamma factor (γ) in special relativity is:
γ = 1 / √(1 - (v^2 / c^2))
For the given speeds:
1. v = 0: γ = 1 / √(1 - (0^2 / c^2)) = 1 / √(1 - 0) = 1
2. v = 0.450c: γ = 1 / √(1 - (0.450c)^2 / c^2) = 1 / √(1 - 0.2025) = 1 / √(0.7975) ≈ 1.112
The value of γ depends on the speed (v) relative to the speed of light (c). As the speed approaches the speed of light (c), the value of γ increases, indicating greater time dilation and relativistic effects.
Read more about gamma factor here: https://brainly.com/question/32882386
#SPJ11
The 1700-turn coil in a dc motor has an area per turn of 2.3 x 10-2 m^2. The design for the motor specifes that the magnitude of the
maximum torque is 2.1 N-m when the coil is placed in a 0.16-T magnetic feld. What is the current in the coil?
The current in the coil is 3.73 A.
Area per turn of coil, A/t = 2.3 × 10^-2 m²
Number of turns of the coil, N = 1700
Maximum torque, T = 2.1 N-m
Magnetic field, B = 0.16 T
We know that the torque on a coil is given by the formula:
T = NABI Sinθ
where,
N = Number of turns
A = Area per turn of the coil
B = Magnetic field
I = Current in the coil
θ = Angle between A and B
And I can be expressed as:
I = (T/NA) / BISinθ
Now, we need to calculate I. So let's calculate the required parameters.
Torque on the coil:
T = 2.1 N-m
Number of turns of the coil:
N = 1700
Area per turn of the coil:
A/t = 2.3 × 10^-2 m²
Magnetic field:
B = 0.16 T
I = (T/NA) / BISinθ
⇒ I = T / (NABISinθ)
Here, Sinθ = 1 (because θ = 90°)
∴ I = T / (NAB)
Putting the values of T, N, A, and B, we get:
I = (2.1 N-m) / [(1700)(2.3 × 10^-2 m²)(0.16 T)]
≈ 3.73 A
Therefore, the current in the coil is 3.73 A.
To learn more about coil, refer below:
https://brainly.com/question/12000391
#SPJ11
Simple Rotational Variables Problem Points:40 The angular position of a point on the rim of a rotating wheel is given by 0 = 2.2t + 4.2t² + 1.9t3, where 0 is in radians if t is given in seconds. What is the angular speed at t = 3.0 s? 95.7rad/s Submit Answer Incorrect. Tries 1/40 Previous Tries What is the angular speed at t = 5.0 s? 353.5rad/s Submit Answer What is the Incorrect. Tries 2/40 Previous Tries average angular acceleration for the time interval that begins at t = 3.0 s and ends at t = 5.0 s? Submit Answer Tries 0/40 What is the instantaneous acceleration at t = 5.0 s? Submit Answer Tries 0/40 Post Discussion Send Feedback
The angular position of a point on the rim of a rotating wheel is given by θ = 2.2t + 4.2t² + 1.9t³, θ where is in radians if t is given in seconds.
The angular speed at t = 3.0 s is 78.7 rad/s.
The angular speed at t = 5.0 s is 186.7 rad/s.
The average angular acceleration for the time interval that begins at t = 3.0 s and ends at t = 5.0 s is 54.0 rad/s².
The instantaneous acceleration at t = 5.0 s is 65.4 rad/s².
To find the angular speed at t = 3.0 s, we need to differentiate the given equation for angular position (θ) with respect to time (t):
ω = dθ/dt
Given that the equation for angular position is θ = 2.2t + 4.2t² + 1.9t³, we can differentiate it to find the angular speed:
ω = dθ/dt = 2.2 + 8.4t + 5.7t²
Now we can substitute t = 3.0 s into the equation to find the angular speed at t = 3.0 s:
ω = 2.2 + 8.4(3.0) + 5.7(3.0)²
= 2.2 + 25.2 + 51.3
= 78.7 rad/s
Therefore, the angular speed at t = 3.0 s is 78.7 rad/s.
To find the average angular acceleration for the time interval from t = 3.0 s to t = 5.0 s, we can use the formula:
Average angular acceleration (αₐ) = (ω₂ - ω₁) / (t₂ - t₁)
Given that t₁ = 3.0 s, t₂ = 5.0 s, and ω₁ = 78.7 rad/s (from the previous calculation), we need to find ω₂ at t = 5.0 s. Following the same process as before, we differentiate the equation for angular position:
ω = 2.2 + 8.4t + 5.7t²
ω₂ = 2.2 + 8.4(5.0) + 5.7(5.0)²
= 2.2 + 42 + 142.5
= 186.7 rad/s
Substituting the values into the average angular acceleration formula:
αₐ = (ω₂ - ω₁) / (t₂ - t₁)
= (186.7 - 78.7) / (5.0 - 3.0)
= 108.0 / 2.0
= 54.0 rad/s²
Therefore, the average angular acceleration for the time interval from t = 3.0 s to t = 5.0 s is 54.0 rad/s².
Finally, to find the instantaneous acceleration at t = 5.0 s, we need to differentiate the angular speed equation:
ω = 2.2 + 8.4t + 5.7t²
Differentiating with respect to time:
α = dω/dt = 8.4 + 11.4t
Substituting t = 5.0 s:
α = 8.4 + 11.4(5.0)
= 8.4 + 57
= 65.4 rad/s²
Therefore, the instantaneous acceleration at t = 5.0 s is 65.4 rad/s².
To know more about angular position here
https://brainly.com/question/31604955
#SPJ4
The angular position of a point on the rim of a rotating wheel is given by θ = 2.2t + 4.2t² + 1.9t³, θ where is in radians if t is given in seconds. What is the angular speed at t = 3.0 s? What is the angular speed at t = 5.0 s? What is the average angular acceleration for the time interval that begins at t = 3.0 s and ends at t = 5.0 s? What is the instantaneous acceleration at t = 5.0 s?
The angular speed at t = 3.0 s can be found by taking the derivative of the given equation with respect to time and evaluating it at t = 3.0 s. Differentiating the equation [tex]0 = 2.2t + 4.2t^2 + 1.9t^3[/tex] with respect to t gives us the angular speed as the coefficient of the first-order term.
By differentiating the equation, we obtain [tex]0 = 2.2 + 8.4t + 5.7t^2[/tex]. Substituting t = 3.0 s into the equation, we can find the angular speed at t = 3.0 s.
The average angular acceleration for the time interval that begins at t = 3.0 s and ends at t = 5.0 s can be calculated by finding the change in angular speed over the given time interval and dividing it by the duration of the interval.
To find the instantaneous acceleration at t = 5.0 s, we need to take the derivative of the angular speed equation with respect to time and evaluate it at t = 5.0 s. The derivative of the angular speed equation will give us the angular acceleration at any given time.
To learn more about Angular Speed
brainly.com/question/29058152
#SPJ11
Question 5 of 7 > The largest tendon in the body, the Achilles tendon, connects the calf muscle to the heel bone of the foot. This tendon is typically 15.0 cm long, 5.00 mm in diameter, and has a Young's modulus of 1.65 x 10° Pa. If an athlete has stretched the tendon to a length of 16.1 cm. what is the tension T, in newtons, in the tendon?
Young's modulus is the constant that shows the ratio of stress to strain for a material that is being stretched or compressed. The formula for stress is.
The original length of the tendon is L1 = 15.0 cm The stretched length of the tendon is L2 = 16.1 cm The diameter of the tendon is d = 5.00 mm = 0.0050 m Young's modulus is Y = 1.65 x 1010 Pa To find the tension T in the tendon, we need to calculate the change in length and stress.
Change in length of tendonΔL[tex]= L2 - L1ΔL = 16.1 cm - 15.0 cmΔL = 1.1 \\[/tex]cm Now, we convert the change in length to meters,ΔL = 1.1 cm x 1 m/100 cmΔL = 0.011 m Stress on tendon Stress = Force/Area In this case, we are given the diameter of the tendon.
To know more about constant visit:
https://brainly.com/question/31730278
#SPJ11
T
A 19 0-kg child descends a slide 1,80 m high and reaches the bottom with a speed of 1.25 m/s Part A How much thermal energy due to friction was generated in this process? Express your answer to three significant figures and include the appropriate units.
The thermal energy generated due to friction in this process is approximately 3,195 J.
To calculate the thermal energy generated due to friction, we need to consider the change in potential energy and kinetic energy of the child.
The change in potential energy (ΔPE) of the child can be calculated using the formula:
ΔPE = mgh
where:
m is the mass of the child (190 kg),
g is the acceleration due to gravity (approximately 9.8 m/s²),
and h is the height of the slide (1.80 m).
ΔPE = (190 kg) × (9.8 m/s²) × (1.80 m)
ΔPE ≈ 3,343.2 J
The change in kinetic energy (ΔKE) of the child can be calculated using the formula:
ΔKE = (1/2)mv²
where:
m is the mass of the child (190 kg),
and v is the final velocity of the child (1.25 m/s).
ΔKE = (1/2) × (190 kg) × (1.25 m/s)²
ΔKE ≈ 148.4 J
The thermal energy due to friction can be calculated by subtracting the change in kinetic energy from the change in potential energy:
Thermal energy = ΔPE - ΔKE
Thermal energy = 3,343.2 J - 148.4 J
Thermal energy ≈ 3,194.8 J
Therefore, the thermal energy generated due to friction in this process is approximately 3,194.8 Joules (J).
Read more on Thermal energy here: https://brainly.com/question/19666326
#SPJ11
A skilled archer tries to hit an apple from the ground with an arrow. At the same time, as he fires, the apple falls freely. If the velocity of the arrow is <97,27,0> m/s, height of the apple is (200,100,0) and arrow starts from (-200,0,0)> m, calculate the time when the arrow will hit the apple and visualize it as a simulation. Create an arrow and apple as defined (you can add more objects as well). Define a loop to update the speeds and positions (for both apple and arrow) including the effect of gravity. Plot the graph (Position Vs Time)
The time when the arrow will hit the falling apple can be calculated by simulating the motion of both objects. Given the velocity of the arrow as <97,27,0> m/s, the initial position of the arrow as (-200,0,0) m, and the initial position of the apple as (200,100,0) m.
We can update the speeds and positions of both objects using a loop that incorporates the effect of gravity. By plotting the graph of position versus time, we can visually determine the time at which the arrow hits the apple.
To simulate the motion of the arrow and the falling apple, we need to update their speeds and positions over time. We can do this by incorporating the effect of gravity on both objects. Assuming the acceleration due to gravity is -9.8 m/s^2 (taking downward as the negative direction), we can use the following equations of motion:
Arrow:
Velocity of the arrow: v_arrow = <97, 27, 0> m/s
Initial position of the arrow: p_arrow = <-200, 0, 0> m
Apple:
Initial velocity of the apple: v_apple = <0, 0, 0> m/s
Initial position of the apple: p_apple = <200, 100, 0> m
Using a loop, we can update the positions and speeds of the arrow and the apple by considering the effect of gravity on their vertical components. The horizontal components of the velocities remain constant.
By tracking the positions of the arrow and the apple over time, we can plot a graph of their vertical positions versus time. The time at which the arrow and the apple intersect on the graph corresponds to the time when the arrow hits the apple.
Learn more about acceleration:
brainly.com/question/2303856
#SPJ11
A 17 kg curling stone traveling at 12.5 m/s [E] collides with another stone of the same mass. The collision is a glancing one. If the second stone is now traveling at 1.5 m/s [E25°N], calculate the velocity of the first stone after collision. 13 m/s [E6.8°S] 26 m/s [E18°N] 7.0 m/s [E1.4°N] 11 m/s [E3.3°S]
To solve this problem, we can analyze the conservation of momentum and the conservation of kinetic energy during the collision.
Let's break down the initial and final velocities of the stones into their x and y components for easier calculations. For the initial velocity of the first stone, we have:
Initial velocity of stone 1: v1 = 12.5 m/s [E]
Initial velocity of stone 2: v2 = 0 m/s [E]
The final velocity of the second stone is given as:
Final velocity of stone 2: vf2 = 1.5 m/s [E25°N]
To find the final velocity of the first stone (vf1), we need to calculate its x and y components separately. Let's assume the final velocity of the first stone has components vx1 and vy1.
Using the conservation of momentum, we know that the total momentum before the collision is equal to the total momentum after the collision. Since the masses of the stones are the same, we can write the equation:
(m1 * v1) + (m2 * v2) = (m1 * vx1) + (m2 * vf2)
Substituting the known values, we have:
(17 kg * 12.5 m/s) + (17 kg * 0 m/s) = (17 kg * vx1) + (17 kg * 1.5 m/s)
Simplifying the equation:
212.5 kg·m/s = 17 kg * vx1 + 25.5 kg·m/s
212.5 kg·m/s - 25.5 kg·m/s = 17 kg * vx1
187 kg·m/s = 17 kg * vx1
Dividing both sides by 17 kg:
vx1 = 11 m/s [E]
Now, we can use the conservation of kinetic energy to find the y-component of the final velocity of the first stone. Since the collision is glancing, the kinetic energy in the y-direction is conserved. We have:
(1/2) * m1 * v1^2 = (1/2) * m1 * vy1^2
Substituting the values:
(1/2) * 17 kg * (12.5 m/s)^2 = (1/2) * 17 kg * vy1^2
156.25 J = 8.5 kg * vy1^2
Dividing both sides by 8.5 kg:
vy1^2 = 18.3824
Taking the square root:
vy1 ≈ 4.286 m/s
Now we have the x and y components of the final velocity of the first stone. We can calculate the magnitude and direction using trigonometry:
Magnitude of vf1 = sqrt(vx1^2 + vy1^2) ≈ sqrt((11 m/s)^2 + (4.286 m/s)^2) ≈ 11.952 m/s
Direction of vf1 = atan(vy1 / vx1) ≈ atan(4.286 m/s / 11 m/s) ≈ atan(0.3896) ≈ 21.8°
The final velocity of the first stone after the collision is approximately 11.952 m/s [E21.8°N].
Among the given options, the closest value is 11 m/s [E3.3°S].
Learn more about momentum here
brainly.com/question/24030570
#SPJ11
A gas undergoes two processes. In the first, the volume remains constant at 0.190 m³ and the pressure increases from 3.00×105 Pa to 6.00×10^5 Pa. The second process is a compression to a volume of 0.130 m³ at a constant pressure of 6.00×10^5 . Find the total work done by the gas during both processes. Express your answer in joules.
A gas undergoes two processes as follows :In the first process: The volume is constant at 0.190 m³The initial pressure, P₁ = 3.00×10⁵ Pa The final pressure, P₂ = 6.00×10⁵ PaIn the second process: The pressure is constant at 6.00×10⁵ Pa The initial volume, V₁ = 0.190 m³The final volume, V₂ = 0.130 m³To
find the total by the gas during both processes, we use the formula for work done in an isobaric process, and then add the work done in an isovolumetric process to it. Work done in isobaric process[tex]: W = PΔV = P(V₂ - V₁)W₁ = PΔV₁ = P₁(V₂ - V₁)W₁ = 3.00×10⁵ Pa × (0.130 m³ - 0.190 m³)W₁ = -9.0 × 10⁴ J[/tex] (Negative sign indicates work done by gas)Work done in is ovolumetric process: W₂ = 0 (As there is no change in volume, ΔV = 0)Therefore, the total work done by the gas during both processes is: [tex]W = W₁ + W₂W = -9.0 × 10⁴ J + 0 = -9.0 × 10⁴[/tex]J (Negative sign indicates work done by gas)Hence, the total work done by the gas during both processes is -9.0 × 10⁴ J.
To know more about constant visit:
brainly.com/question/31730278
#SPJ11
Identify the statements which could be tested by an objective experiment or observation. -People with green eyes are on average taller than people with blue eyes. -Daily meditation lowers blood pressure. -Somewhere in the universe there is an alien civilization of bird-like beings that have achieved interstellar space travel. -The best candies are made of chocolate. God allows civilizations to collapse when he becomes displeased with them. -The stock market performs better in months when the number of sunspots on the Sun's surface increase. -The most athletic individuals have an astrological sign of Capricorn, Aquarius, Pisces, Cancer or Leo. Asteroid A has 4.0 times the mass and 1.5 times the velocity of Asteroid B. If Asteroid B has a kinetic energy of 2,900,000 J then what is the kinetic energy of Asteroid A?
The statements that could be tested by an objective experiment or observation are "people with green eyes are on average taller than people with blue eyes", "daily meditation lowers blood pressure", and "the stock market performs better in months when the number of sunspots on the Sun's surface increase". The kinetic energy of Asteroid A is 4.5 J.
These statements lend themselves to empirical investigation through data collection, statistical analysis, and observation. By conducting controlled experiments, collecting relevant data, and analyzing the results, researchers can provide objective evidence to support or refute these claims.
The kinetic energy of Asteroid A is calculated by using the formula for kinetic energy:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Mass of Asteroid B (mB) = 1
Velocity of Asteroid B (vB) = 1
Kinetic energy of Asteroid B (KEB) = 2,900,000 J
Mass of Asteroid A (mA) = 4.0 * mB = 4.0
Velocity of Asteroid A (vA) = 1.5 * vB = 1.5
Substituting the values into the formula:
KEA = (1/2) * mA * vA^2
= (1/2) * 4.0 * (1.5)^2
= (1/2) * 4.0 * 2.25
= 4.5 J
Therefore, the kinetic energy of Asteroid A is 4.5 J.
To know more about kinetic energy, refer to the link :
https://brainly.com/question/22174271#
#SPJ11
The wave functions of two sinusoidal
waves y1 and y2 travelling to the right
are given by: y1 = 0.02 sin 0.5mx - 10ttt)
and y2 = 0.02 sin(0.5mx - 10mt + T/3), where x and y are in meters and t is in seconds. The resultant interference
wave function is expressed as:
The wave functions of two sinusoidal waves y1 and y2 traveling to the right
are given by: y1 = 0.02 sin 0.5mx - 10ttt) and y2 = 0.02 sin(0.5mx - 10mt + T/3), where x and y are in meters and t is in seconds. the resultant interference wave function is given by:y = 0.02 sin(0.5mx - 10tt + T/3) + 0.02 sin(0.5mx - 10mt)
To determine the resultant interference wave function, we can add the two given wave functions, y1 and y2.
The given wave functions are:
y1 = 0.02 sin(0.5mx - 10tt)
y2 = 0.02 sin(0.5mx - 10mt + T/3)
To find the resultant interference wave function, we add y1 and y2:
y = y1 + y2
= 0.02 sin(0.5mx - 10tt) + 0.02 sin(0.5mx - 10mt + T/3)
Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can rewrite the resultant wave function:
y = 0.02 [sin(0.5mx - 10tt)cos(T/3) + cos(0.5mx - 10tt)sin(T/3)] + 0.02 sin(0.5mx - 10mt
Simplifying further, we have:
y = 0.02 [sin(0.5mx - 10tt + T/3)] + 0.02 sin(0.5mx - 10mt)
Therefore, the resultant interference wave function is given by:
y = 0.02 sin(0.5mx - 10tt + T/3) + 0.02 sin(0.5mx - 10mt)
To learn more about sinusoidal waves visit: https://brainly.com/question/28517936
#SPJ11