The heights of male seniors in high school closely follow a normal distribution N(µ,σ) = N(70.5,2.6) , where the units are inches. a) If we randomly sample the heights of five male seniors, what distribution should the sample mean follow? Give your answers to two decimal places.

Answer:

4 3 4 4 4 2 3 4 5 5 3.5 5

Just divide the number by 4

Sry if the list is kinda confusing

Answer:

6.02

Step-by-step explanation:

Answer:

................................

Answer:

10 to 15 (simplified: 2 to 3)

10/15 (simplified: 2/3)

10 : 15 (simplified: 2 to 3)

Answer:

f(x)=4−(x−7)

3

Let y=f(x)

So, x=f

−1

(y) ---- ( 1 )

y=f(x)

⇒ y=4−(x−7)

3

⇒ (x−7)

3

=4−y

⇒ x−7=

3

4−y

⇒ x=7+

3

4−y

⇒ f

−1

(y)=7+

3

4−y

.................. [ From ( 1 ) ]

∴ f

−1

(x)=7+

3

4−x

Answer:

f(5) = -6

Step-by-step explanation:

Problem

3.2x-1.7x+5.5=10

Steps:

1.5x + 5.5 = 10

1.5x X 10 + 5.5 X 10 = 10 X 10

15x + 55 - 55 = 100 - 55

15x = 45

15x/15 = 45/15

x = 3

Therefore questions ones answer is x = 3

Problem

3/4x-1/4x+14=3

Steps:

3/4x - 1/4x + 14 = 3

3/4x - 1/4x + 14 - 14 = 3 - 14

3/4x - 1/4x = -11

3/4x X 4 - 1/4x X 4 = -11 X 4

2x = -44

2x/2 = -44/2

x = -22

Therefore question two's answer is x = -22

Problem

3(2x+1)+x=-39

Steps:

7x + 3 = -39

7x + 3 - 3 = -39 - 3

7x = -42

7x/7 = -42/7

x = -6

Therefore question three's answer is  x = -6

Problem

m+4(2m-3)+-3

Steps:

= m + 4 (2m - 3) - 3

= m + 8m - 12 - 3

= 9m - 15

Therefore question four's answer is 9m - 15

Answer:

[tex]f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }[/tex]

Answer:

7x ³⁹¹

Step-by-step explanation:

1: "x3" was replaced by "x^3".

-3.6

Step-by-step explanation:

z/(-2) + -5 = -3.2 → times -2

z + 10 = 6.4

z = 6.4 - 10

z = -3.6

Step-by-step explanation:

Arithmetic Sequnce in our daily life

The knowledge of calculating the nth term of a sequence can be very helpful. Calculating loans, discounts, salary, savings are some of the use of arithmetic method. If I save P5 per day for 5 years, I can simply use arithmetic sequence to find how much I saved from day 1 to last. Salary increase can also be solved using arithmetic sequence. Below is an example.

Sample real life problem:

1. I earn P300 on the first day. After each succeeding day, I earn P2 more than the previous day. How much should I be able to earn after 30 days?

In this situation, I would use the arithmetic sequence formula which is:

an = a1 + (n - 1)d

an is the nth term

a1 is the first term

n is the term position

d is the common difference

Lets subsitute:

an = P300 + (30 - 1)P2

an = P358

I should earn P348 at the end of 30 days

Answer:

[tex]y = - \frac{2}{3} x + 1[/tex]

Step-by-step explanation:

2x +3y= 5

3y= -2x +5

Divide both sides by 3:

[tex]y = - \frac{2}{3} x + \frac{5}{3} [/tex]

[tex]y = - \frac{2}{3} x + 1 \frac{2}{3} [/tex]

Now that the equation is in the slope-intercept form (y= mx +c), the slope of the given line is the coefficient of x.

[tex]slope = - \frac{2}{3} [/tex]

Parallel lines have the same slope.

Slope of unknown line= -⅔

y= -⅔ +c

To find the value of c, substitute a pair of coordinates into the equation.

When x= 3, y= -1,

[tex] - 1 = - \frac{2}{3} (3) + c[/tex]

-1= -2 +c

c= -1 +2

c= 1

Thus, the equation of the line is y= -⅔x +1.

Answer:

Next, in 1630, the Puritans used the royal charter establishing the Massachusetts Bay Company to create a government in which “freemen”—white males who owned property and paid taxes and thus could take on the responsibility of governing—elected a governor and a single legislative body called the Great and General Court ...

Answer:

Questions and answers about the Massachusetts Bay Colony. The Puritans established a theocratic government with the franchise limited to church members.

Questions and answers about the Massachusetts Bay Colony. The Puritans established a theocratic government with the franchise limited to church members.Related Places: United States British Empire Massachusetts American colonies

Questions and answers about the Massachusetts Bay Colony. The Puritans established a theocratic government with the franchise limited to church members.Related Places: United States British Empire Massachusetts American coloniesRelated Topics: Western colonialism Puritanism theocracy “Bay Psalm Book”

Answer:

1. y = 3x - 1

2. y = -3x

3. y = 2x + 4

4. y = 2.5x - 4

5. y = 4x

6. y = -3/4x -0.25

7. uhhh two lines  since one definitlye doesn’t work

Step-by-step explanation: I couldn’t add more than 5 pics it’s the limit sadly.

B. The submarine is 125 feet below sea level.

Step-by-step explanation:

-124 feet because - (negative) means the submarine is 124 meters below sea level (masl).

Answer:

The elevation of a submarine with respect to sea level is displayed as - 125 feet. Which statement is correct?

A. The submarine is 125 feet above sea level.

B. The submarine is 125 feet below sea level.

C. The submarine is -125 feet above sea level.

D. The submarine is -125 feet below sea level.

Step-by-step explanation:

Answer:

x=135/13

Step-by-step explanation:

9/13 × 15 = x

9 × 15/13 = x

135/13 = x

x = 135/13

I hope this helps :)

Answer:

[tex]T(x)=\begin{cases}\frac{3x+1}{2} & x\text{ is odd} \\ \frac{x}{2} & x\text{ is even}\end{cases} \\ for \: instance \: start \: with \: 7 \: \\ which \: is \: an \: odd \: number \\ \frac{21 + 1}{2} = \frac{22}{2} = 11 \\ 11 \: is \: odd \\ \frac{11 + 1}{2} = 6\\ 6 \: is \: even \\ \frac{6}{2} = 3 \\ 3\: is \: odd \\ \frac{9 + 1}{2} = 5 \: \\ 5 \: is \: odd\\ \frac{15 + 1}{2} = 8 \\ 8 \: is \: even \\ \frac{8}{2} = 4 \\ 4 \: is \: even \\ \frac{4}{2} = 2 \: then \: 1 \\ [/tex]

Step-by-step explanation:

Can we connect to 1 for all numbers?

A general proof for a simple pattern seems almost impossible, probably a new branch of mathematics maybe needed to tackle this conjecture...

Answer:

19.5

Step-by-step explanation:

3r+(7+8)/(t-3)

3(4)+(15)/(5-3)

12+(15/2)

12+7.5

19.5

Answer:

2. 4y-2xy

Step-by-step explanation:

6y-2y(x+1)=6y-2xy-2y

=4y-2xy

Answer: Choice C

4/(3*sqrt(3))

which is the same as writing [tex]\frac{4}{3\sqrt{3}}[/tex]

==============================================================

Explanation:

We have the line [tex]\left(\sqrt{2}\right)x+y +2 = 0[/tex] in which points B and C are on this line. In other words, all of segment BC is on that line.

Point A is somewhere off that line as the diagram below indicates. We need to find the line through A that is perpendicular to the given line.

Recall that for any line of the standard form [tex]Px+Qy+R = 0\\\\[/tex], any perpendicular line will look like this: [tex]Qx-Py+S = 0\\\\[/tex]. Note the swap and sign change for the P,Q coefficients.

So anything perpendicular to [tex]\left(\sqrt{2}\right)x+y +2 = 0[/tex] will be of the form [tex]x-\left(\sqrt{2}\right)y+S = 0[/tex]. The sub-goal here is to find what S is equal to.

If you plugged in the origin point (x,y) = (0,0), then you should find that S = 0.

Therefore, the equation [tex]x-\left(\sqrt{2}\right)y = 0[/tex] is perpendicular to the given line and it passes through point A(0,0).

---------------------------

The reason why we computed that perpendicular line is to help determine the point D as shown in the diagram below. This point is at the intersection of the green perpendicular lines. This is at the base of the triangle such that BC is the base.

To find the location of point D, you need to solve this system of equations

[tex]\begin{cases}\left(\sqrt{2}\right)x+y +2 = 0\\\\x-\left(\sqrt{2}\right)y = 0\end{cases}[/tex]

Let's isolate x in the second equation

[tex]x-\left(\sqrt{2}\right)y = 0\\\\x=\left(\sqrt{2}\right)y\\\\[/tex]

Then substitute that into the other equation. Solve for y.

[tex]\left(\sqrt{2}\right)x+y +2 = 0\\\\\left(\sqrt{2}\right)*\left(\sqrt{2}\right)y+y +2 = 0\\\\2y+y +2 = 0\\\\3y +2 = 0\\\\3y = -2\\\\y = -2/3\\\\[/tex]

Now we can find x like so

[tex]x=\left(\sqrt{2}\right)y\\\\x=\left(\sqrt{2}\right)*(-2/3)\\\\x=\frac{-2\sqrt{2}}{3}\\\\[/tex]

The point D is located at the exact coordinates of

[tex]D=(x,y) = \left(\frac{-2\sqrt{2}}{3},\frac{-2}{3}\right)\\\\[/tex]

---------------------------

Next, we use the distance formula to compute the distance between point A and point D.

I'll use lowercase d to represent distance.

[tex]A = (x_1,y_1) = (0,0)\\\\D = (x_2,y_2) = \left(\frac{-2\sqrt{2}}{3},\frac{-2}{3}\right)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{\left(0-\left(\frac{-2\sqrt{2}}{3}\right)\right)^2 + \left(0-\left(\frac{-2}{3}\right)\right)^2}\\\\d = \sqrt{\left(\frac{2\sqrt{2}}{3}\right)^2 + \left(\frac{2}{3}\right)^2}\\\\d = \sqrt{\frac{8}{9} + \frac{4}{9}}\\\\d = \sqrt{\frac{12}{9}}\\\\d = \sqrt{\frac{4}{3}}\\\\d = \frac{\sqrt{4}}{\sqrt{3}}\\\\d = \frac{2}{\sqrt{3}}\\\\[/tex]

This represents the exact length of segment AD.

---------------------------

Since triangle ABC is equilateral, this means triangles ADB and ADC are identical mirrored copies of each other. Those two smaller triangles are equal in area and combine to form triangle ABC back again. Furthermore, they are right triangles. This last fact mentioned will allow us to use the pythagorean theorem like so

[tex]a^2+b^2 = c^2\\\\\left(\text{AD}\right)^2+\left(\text{DC}\right)^2=\left(\text{AC}\right)^2\\\\\left(\frac{2}{\sqrt{3}}\right)^2+\left(\frac{x}{2}\right)^2=\left(x\right)^2\\\\[/tex]

where x represents the lengths of AB, BC and AC.

After skipping a bit of steps, solving that said equation should lead to these two solutions

[tex]x = -\frac{4}{3}, \ x = \frac{4}{3}[/tex]

Because x is a side length, we ignore the negative solution.

---------------------------

We can now compute the area of triangle ABC

[tex]\text{area of triangle} = \frac{1}{2}*\text{base}*\text{height}\\\\\text{area of triangle ABC} = \frac{1}{2}*\text{BC}*\text{AD}\\\\\text{area of triangle ABC} = \frac{1}{2}*\frac{4}{3}*\frac{2}{\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{1*4*2}{2*3*\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{8}{6\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{4}{3\sqrt{3}}\\\\[/tex]

which points us to choice C as the final answer.

When writing this on a keyboard, we would write "4/(3*sqrt(3))" without quotes. The use of parenthesis is needed to ensure we divide by all of 3*sqrt(3). Otherwise, the computer might mistake it for [tex]\frac{4}{3}\sqrt{3}[/tex] which is entirely different.

Answer:

3102.12

Step-by-step explanation:

add the starting weight 788.52 plus the weight he gained 2.313.6

788.52 + 2.313.6 = 3102.12

Answer:

16.5 minutes

Step-by-step explanation:

2508/152 = 16.5

Check: 152 x 16.5 = 2508

9514 1404 393

Answer:

  (b)  Hiking 10 feet due north, then hiking 10 feet due south

Step-by-step explanation:

Any pair of numbers that totals zero will be a pair of opposites. The offered choices are ...

  +6 -4 = 2 . . . not zero

  +10 -10 = 0

  +2 -3 = -1 . . . not zero

  +5 -3 = 2 . . . not zero

Hiking 10 feet due north, then hiking 10 feet due south is a situation involving opposite numbers adding up to zero.

Answer:

[tex]216[/tex]

Step-by-step explanation:

Remember that [tex]a^{b}=a*a*a*a*... b~~times[/tex].

So, [tex]6^3=6*6*6=(6*6)*6=36*6=\boxed{216}[/tex]

Answer:

[tex]2x + 5 \geqslant 27 \\ = 2x \geqslant 27 - 5 \\ = 2x \geqslant 22 \\ = x \geqslant 22 \div 2 \\ x \geqslant 11 \\ x[11 \: \infty ) \\ thank \: you[/tex]

Step-by-step explanation:

Hope this help you

If this help you then mark me as a brainliest

Answer:

i don't know

im kinda silly lol lol lol lol lol lol lol lol lol

Answer:

Each book weighs 2.5 pounds.

Step-by-step explanation:

75/2.5 is 30.  Or you could also get the answer by 30* 2.5 which it would be 75. So, therefor, the answer is 2.5.

Answer:

2.5lb

Explanation:

In equation form the question is asking for x in

[tex]30(x) = 75[/tex]

Since multiplication is reversible (to be division), we can switch the equation up.

[tex]75[/tex] ÷ [tex]30 = x[/tex]

So the answer is

[tex]75[/tex] ÷ [tex]30 = 2.5[/tex]

Answer:

75

Step-by-step explanation:

15 is 20% of the total.

The total is x since it is unknown.

20% of the total = 15

20% of x = 15

0.2x = 15

Multiply both sides by 5.

x = 75

Answer:

Step-by-step explanation:

Suppose we decide to solve for y first.  y will then be in terms of x AND a real and an imaginary term:

48-5i=-4x+10yi

The goal here is to solve for y.  Adding 4x to both sides yields

48 - 5i + 4x = 10yi

and then we divide both sides by 10i to isolate the variable y:

48 - 5i + 4x

----------------- = y                 This result is "y in terms of the constant 48, the

      10i                               imaginary terms 5i and 10i, and the expression 4x.

We solve the original equation for x in a similar manner:

48-5i=-4x+10yi becomes 48 - 5i - 10yi = -4x, so that:

      -(48 - 5i - 10yi)

x = ------------------------

                 4

Next time, please specify which variable (x or y) you're solving for.  Thank you.