The large rectangle below represents one whole. A large rectangle with 25 equal sections, 11 of which are shaded What percent is represented by the shaded area?

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

Answer: -6

Step-by-step explanation: I just took the test

Answer:

Quadratic function

Explanation:

It is not linear because the difference between y values is not constant.

([tex]10-5\neq 5-2[/tex] for example) In a linear function, the difference between y values would be constant.

Answer:

D

Step-by-step explanation:

Answer:

x = -5

Step-by-step explanation:

8x - 10 = 4x - 30

Subtract 4x from each side

8x-4x - 10 = 4x-4x - 30

4x -10 = -30

Add 10 to each side

4x-10+10 = -30+10

4x= -20

Divide by 4

4x/4 = -20/4

x = -5

Answer:

Step-by-step explanation:

6x-10x^2+3-(5x^2+3x-4)

when there is a - in front of an expression in (), change the sign of each term in the expression

6x-10x^2+3-5x^2-3x+4

now collect like terms

3x-10x^2+3-5x^2+4

3x-15x^2+3+4

3x-15x^2+7

now use the commutative property to reorder the terms

-15x^2+3x+7

=-15x^2+3x+7

Answer:

Model is

b = 115m + 65

The slope represents the amount of balance offset per month

Step-by-step explanation:

Here, we want to model an equation.

The equation to model will be in the form;

y = mx + c

we have the following points to consider

The points are in the form;

(number of months, balance)

(m , b)

So the points we have are;

(4,755) and (5,640)

So the slope will be ;

(y2 -y1)/(x2-x1) = (755-640)/(5-4) = 115

So the equation will be;

b = am + c

where a is the slope and c is the y intercept

we already have the slope

so equation becomes;

b = 115m + c

let’s get the y-intercept

we can get the y-intercept by any of the points;

That would be; let’s use (5,640)

640 = 5(115) + c

640 = 575 + c

c = 640 -575

c = 65

So the equation of the model is;

b = 115m + 65

The slope represents the balance per month

Answer:

in order to divide by a fraction, you need to multiply by its reciprocal instead, which would be 2 over 1 (2/1)

Step-by-step explanation:

in this case, 10 divided by 1/2 turns to 10 x 2/1

i tried my best, sorry if i couldnt help

Answer:

b

Step-by-step explanation:

Answer:

a) 18

b) 18 : 12

c)3  : 4

Step-by-step explanation:

a) 30 × [tex]\frac {60}{100}[/tex]

= 18 students walk to school

b)             No. of students                                       No. of students

            who walk to school               :                 who walk to school

                        18                               :                                 12

c)

18 : 12

=18/6 : 12/3

=3  : 4

Answer:

5, 12, 6, 4, 6, 5

Step-by-step explanation:

The nearest square root to 28 is 25, which is 5.

The nearest square root to 135 is 121, which is 12.

The nearest square root to 38.7 is 36, which is 6.

The nearest cubic root to 51 is 64, which is 4.

The nearest cubic root to 200 is 216, which is 6.

The nearest cubic root to 95 is 125, which is 5.

Answer:

Its a very complex solution but it x

=

0

,

3

√

14

2

Step-by-step explanation:

Answer:

The answer is Division property of equality

Step-by-step explanation:

Answer:

division property of equality

Step-by-step explanation:

Just took the test on edge

Answer:

$3045

Step-by-step explanation:

You need to find 13% of 3500, and subtract it from 3500.

13% of 3500 = 455

3500 - 455 = 3045

Answer:

8 quarters and 8 dimes

Step-by-step explanation:

Answer:

9 quarters 7 dimes they equal $2.95

Answer: x = 5

Step-by-step explanation:

Answer:

x = 1

Step-by-step explanation:

[tex] {x}^{2 } - {x}^{2} - 3x + 3 \\ - 3x + 3 \\ 3x = 3 \\ x = 1[/tex]

Answer:

Answer below

Step-by-step explanation:

2.08

2.082

2.8

2.82

√8 (it's 2.8284)

Answer:

let me know if im incorrect!

Step-by-step explanation:

2.082, 2.08, 2.8, 2.82, 8 squared (2.828)

Answer

Step-by-step explanation:

Answer:

thankk youu

Step-by-step explanation:

Answer:

4x³ + 3x² - 3x - 8

Step-by-step explanation:

Step 1: Write expression

(4x³ + 2x - 3) + (3x² - 5x - 5)

Step 2: Combine like terms

4x³ + 3x² - 3x - 8

Answer:

4x^3+3x^2-3x-8

Step-by-step explanation:

Use parentheses and combine like terms.

Answer:

c) 392

Step-by-step explanation:

Answer:

2/3

Step-by-step explanation:

10/15 can be divided by 5

66 degrees

Thing you have to know for these types of problems: The total measure of all angles is 180 degrees.

With that in mind, if we add 83 and 31, we get 114 degrees.

Now subtract from 180 and you will get 66 degrees.

Hope this helps, Please mark branliest if it did

Answer:

X=1/2, -2/5

Step-by-step explanation:

Solve the equation for X by finding a, b, and c of the quadratic then applying the quadratic formula.

Answer:

:) :) :) :) :) :) :0

Step-by-step explanation:

2/5 and 1/2

Answer:

Whats the question tho

Step-by-step explanation:

Answer:

The angle across the given measurements are the same. So there will be a 27 degrees across from the other 27 degrees. The straight line is 180 degrees, so do 180-27=153. The means the other 2 angles are 153 degrees. The other one is the same, but with different measurements. 180-35=145

Step-by-step explanation:

Let the angle adjacent to ∠27° be x .

[tex]∠x + 27 = 180° \: ( \: linear \: pair \: )[/tex]

[tex]x = 180 - 27 \\ ∠x = 153°[/tex]

Let the angle opposite to ∠27° be y .

[tex]∠y = ∠27° \: ( \: vertically \: opposite \: angles \: )[/tex]

Let the angle adjacent to ∠y ( 27°) be w .

[tex]w + ∠27° = 180° \: ( \: linear \: pair \: ) \\ w = 180 - 27 \\ ∠w = 153°[/tex]

Let the angle opposite to ∠35° be p .

[tex]∠p = ∠35° \: ( \: vertically \: opposite \: angles \: )[/tex]

Let the angle adjacent to ∠35° be a .

[tex]∠a + 35° =180 ° \: ( linear \: pair ) \\ a = 180 - 35 \\ ∠a = 145°[/tex]

Let the angle opposite to ∠35° be t .

[tex]∠t = 35° \: ( \: vertically \: opposite \: angles \: )[/tex]

Let the angle opposite to ∠145° be o .

[tex]∠o \: = 145° \: ( \: vertically \: opposite \: angles \: )[/tex]