Answer:
Use the formula to determine the contact area of each tire with the road.
Area divided by force yields pressure, as the equation suggests.
The weight of the car, which is 1500 kg, exerts a force on an area where pressure is at 2.2 x 10^5 Pa.
Supported by all four tires, we must first determine the total force.
Weight of car is 1500 kg multiplied by 9.8m/s^2 equals =14700 N, also known as total force.
Equally sharing the load, four tires are responsible for supporting the vehicle.
Each tire carries a force that equals the total force divided by 4, which is equivalent to 3675 N as calculated from a total force of 14700 N.
Each tire's contact area with the road can now be calculated.
3675 N divided by 2.2 x 10^5 Pa equals the area. This area can also be described as force divided by pressure.
Approximately 16.7 cm^2 or 1.67 x 10^-2 m^2 is the designated area.
The contact area between the road and each tire measures exactly 16.7 cm^2.
The current in a circuit is 0.50 A. The circuit has two resistors connected in series: one is 110 Ω and the other is 130 Ω. What is the voltage in the circuit?
Answer:
120 V
Explanation:
Given:
I (total) = 0,5 A
R1 = 110 Ω
R2 = 130 Ω
Find: V (total) - ?
The resistors are connected in series
That means, the current in the circuit is the same for every resistor:
I (total) = I1 = I2
Now, we need to find the voltage in each resistor:
V1 = I × R1
V1 = 0,5 × 110 = 55 V
V2 = I × R2
V2 = 0,5 × 130 = 65 V
Now, since the connection is in series, in order to find the total voltage in the circuit, we have to add the voltages of the resistors:
V (total) = V1 + V2
V (total) = 55 + 65 = 120 V
A horizontal force of 25 N is exerted on a box (mass 10 kg), as shown in the diagram. The box accelerates at 2.0 m.s-2. What is the magnitude of the frictional force acting between the box and the floor?
Answer:
the magnitude of the frictional force acting between the box and the floor is 5 N.
Explanation:
At the point 0, there are 2 point sources, emitting the same constant sound power,
with intensity in inversely proportional to the square of the distance from the source. At the point A, the sound level intensity is [tex]20dB[/tex]
(a) What is the sound level intensity at A of one source?
(b) What is the number of sources that we have to add at A so that the sound level intensity at the midpoint M of OA is [tex]30dB[/tex]?
The number of sources that we have to add at A so that the sound level intensity at M is doubled is 2.
(a) Let the distance of point A from one source be x. Then the distance from the other source is (OA - x), where OA is the distance between the two sources. The sound intensity at point A due to one source is proportional to 1/x^2. So, if the sound power of one source is P, then the sound intensity at A due to one source is given by I = P/(4πx^2), where 4πx^2 is the surface area of a sphere with radius x.
The sound level intensity is defined as L = 10log(I/I0), where I0 is a reference intensity (I0 = 10^-12 W/m^2). Since there are two sources, the total sound intensity at A is twice the sound intensity due to one source, i.e., I_total = 2I = 2P/(4πx^2). Therefore, the sound level intensity at A is L = 10log(2P/(4πx^2I0)) = 10log(2P/(4πI0)) - 20log(x).
(b) Let the distance of point M from one source be y. Then the distance from the other source is (OM - y), where OM is the distance between O and M. The sound intensity at M due to one source is proportional to 1/y^2. So, if the sound power of one source is P, then the sound intensity at M due to one source is given by I = P/(4πy^2), where 4πy^2 is the surface area of a sphere with radius y.
The sound level intensity at M due to one source is L_M = 10log(I/I0) = 10log(P/(4πy^2I0)).
Since the sound intensity is inversely proportional to the square of the distance, the sound intensity at A due to one source is four times the sound intensity at M due to one source. Therefore, I_A = 4I = 4P/(4πy^2), and the sound level intensity at A due to one source is L_A = 10log(I_A/I0) = 10log(P/(πy^2I0)).
We want the total sound level intensity at M due to all sources to be L_M = L_A + 10log2, where 10log2 is the sound level intensity increase due to adding a second source. Therefore, we have:
10log(P/(4πy^2I0)) + 10log2 = 10log(P/(πy^2I0))
10log2 = 10log(4/π)
log2 = log(4/π)
2 = 4/π
π = 2
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4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?
Answer:
a = 3.02 m/s^2
h
Explanation:
we know that centripetal acceleration (a) is
[tex] \frac{v {}^{2} }{r} = a[/tex]
since v = rω, we can substitute it into the equation, which now gives us the centripetal acceleration in terms of angular velocity and radius (check image).
now we use the values given and find the answer
6. Construct a new physical equations having in terms of G, C and h dimensions of length where G is universal gravitational constant, c is the speed of light and I is planck's Constant.
Basic values of mass in the existing program are c1/2 G-12 h1/2 if the speed of light (c), newtonian constant (G), and Planck's parameter (h) are taken as the fundamental units.
What is the G equivalent of the principle of the universal gravitational equation?According to the Universal Gravitation Equation, G is equal to 6.673 x 10-11 N m2/kg2. Everything because of how a fruit falls from a tree to the reason the moon rotates around the earth may be explained by the Universal Gravitational Law.
What does the formula for the universal law of gravity mean?This rule states that the distance is proportional to the product of the mass of the two objects. The Universal Law of Force of gravity is summed up by the following gravitational force equation: FG = (G.m1.
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WHAT IS QUANTUM PHYSICS
hi!
Answer:
Quantum physics is the study of matter and energy at the most fundamental level. It aims to uncover the properties and behaviors of the very building blocks of nature.
If astronomers were to find they have made a mistake and our solar system is actually 7.2 (rather than 8.2) kpc from the center of the galaxy, but the orbital velocity of the sun is still 240 km/s, what is the minimum mass of the galaxy?
Assuming a circular orbit for the Sun, we can use the equation:
v^2 = GM/r
where v is the orbital velocity of the Sun, r is the distance from the center of the galaxy, G is the gravitational constant, and M is the mass of the galaxy.
We can solve for M:
M = v^2 * r / G
Using the given values of v = 240 km/s and r = 7.2 kpc = 7.2 * 3.086e+19 m, and G = 6.6743e-11 N m^2/kg^2, we get:
M = (240000 m/s)^2 * 7.2 * 3.086e+19 m / 6.6743e-11 N m^2/kg^2
M = 1.47e+42 kg
Therefore, the minimum mass of the galaxy, if the distance of the solar system from the center is actually 7.2 kpc, is approximately 1.47 x 10^42 kg.
what is the mechanica advantage of alever then can lift 100 Newton with an input force of 20 Newton
Answer:
Explanation:
To calculate the mechanical advantage of a lever, we use the formula:
Mechanical Advantage = Output Force / Input Force
In this case, the output force is 100 Newton and the input force is 20 Newton, so:
Mechanical Advantage = 100 N / 20 N
Mechanical Advantage = 5
Therefore, the mechanical advantage of the lever is 5. This means that for every 1 Newton of input force applied to the lever, the lever will produce 5 Newtons of output force. So, in this case, an input force of 20 Newtons applied to the lever would produce an output force of 100 Newtons.
A metal weigh 20N in air, 12N in water, and 14N in Kerosene. Cal the the Relative density of (a) Metal (b) kerosene
The relative density of kerosene is 0.006, or 6 kg/m³.
A metal block that weighs 60 tonnes in the air and 40 tonnes beneath water, what is its density?1 Response. Employ the Archimedes' Principle to your advantage: the buoyant force of a fluid is equal to the apparent loss of weight in water and is also equal to the weight of the displaced fluid. Weight of the displaced water equals 60 - 40 N, or the apparent loss in weight of the metal block. Water displacement mass is calculated as 20 / 9.8 = 2.04 kg.
Buoyant force = Weight of the displaced water = 20 N - 12 N = 8 N
Volume of water displaced = Buoyant force / Density of water = 8 N / 9.8 m/s² = 0.8163 kg
Density of metal = Weight of metal in air / Volume of metal = 20 N / (density of air x volume of metal)
Density of metal = 20 N / 0.8163 kg = 24.5 kg/m³
Buoyant force = Weight of the displaced kerosene = 20 N - 14 N = 6 N
Volume of kerosene displaced = Buoyant force / Density of kerosene = 6 N / 9.8 m/s² = 0.6122 kg
Density of kerosene = Mass of kerosene / Volume of kerosene displaced = 14 N / 0.6122 kg = 22.86 kg/m³
Relative density of kerosene = Density of kerosene / Density of water = 22.86 kg/m³ / 1000 kg/m³ = 0.006, or 6 kg/m³.
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Remember the steps that the American Heart Association recommends for saying no to cigarettes. Which one of these will you use if you are faced with peer pressure to smoke? Which one of these will you use if you are faced with peer pressure to drink or take drugs? Explain the method you will use and why you chose it.
Answer: just say no and never talk to that person again.
Explanation:
because that is what i would do to prevent drugs and/or nicotine to enter my body.
MS-PS2-1, MS-PS2-2: Newton...
16
Distance (m)
Distance vs. Time
B
120
Time (sec.)
A
B
Which car is faster, A or B? Choose the statement that BEST fits the graph.
Car A is faster than B because A's speed is 120 m/s.
Car B is faster than A because B's speed is 90 m/s.
Car A is faster than B because A's speed is 20 m/s and B is 15 m/s.
D) Car B is faster than A because B's motion is accelerating and A is constant speed.
The statement that best fits the graph is: D) Car B is faster than A because B's motion is accelerating and A is constant speed.
Which car is faster, A or B?From the graph, we can see that the distance traveled by both cars increases over time. However, the slope of the distance-time graph for car B is steeper than that of car A. This means that car B covers more distance in the same amount of time as car A, indicating that car B is traveling faster than car A.
Furthermore, we can see that the speed-time graph for car B is a straight line with a positive slope, indicating that its speed is increasing over time. On the other hand, the speed-time graph for car A is a horizontal line, indicating that its speed is constant.
Therefore, we can conclude that car B is faster than car A because car B's motion is accelerating, while car A is moving at a constant speed.
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Find the position of the center of mass of the system of the sun and Jupiter. (Since Jupiter is more massive than the rest of the planets combined, this is essentially the position of the center of mass of the solar system.)
it's only beyond the surface of the sun! There is a barycenter throughout our entire solar system. All of the planets in the solar system, including the sun, center of mass.
Is the Sun more massive than the solar system as a whole?The sun is significantly more massive than Earth and has a radius that is likewise much greater. The mass of the sun is more than 333,000 times more than the mass of the Earth and makes up nearly all of the solar system's mass (99.8%).
How much more does the Sun compare to Jupiter?The Sun is 1000 times more than Jupiter, the solar system's most planet , but Jupiter is still 1000 times less than it.
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I need help with this ty
Answer:
4 & 2
Explanation:
If you plug in experimental values into the formula for kinetic energy, you will see the relationship.
1.
[tex]\frac{1}{2}(2 kg)(2 m/s)^{2} = 4 kg * m^{2} /s^{2} \\\\\frac{1}{2}(8 kg)(2m/s)^{2} = 16 kg * m^{2} /s^{2}\\\\\frac{16}{4} = 4[/tex]
2.
[tex]\frac{1}{2}(6 kg)(2m/s)^{2} = 12 kg * m^{2} /s^{2} \\\\\frac{1}{2}(3 kg)(2 m/s)^{2} = 6 kg * m^{2}/s^{2}\\ \\\frac{12}{6} = 2[/tex]
Jonathan and Jane are sitting in a sleigh that is at rest on frictionless ice. Jonathan's weight is 800 N
, Jane's weight is 600 N
, and that of the sleigh is 1000 N
. They see a poisonous spider on the floor of the sleigh and immediately jump off. Jonathan jumps to the left with a velocity (relative to the ice) of 5.00 m/s
at 30.0∘
above the horizontal, and Jane jumps to the right at 7.00 m/s
at 36.9∘
above the horizontal (relative to the ice).
1) Calculate the magnitude of the sleigh's horizontal velocity after they jump out?
2) What is the direction of the sleigh's horizontal velocity after they jump out?
Since the positive x-direction was established to be to the right, the sleigh's velocity is in this direction (the positive x-direction).
Calculation-The whole horizontal momentum is conserved since there is no external force operating on the system (the sleigh plus Jonathan and Jane) in the horizontal direction.
Let's say that the positive x-direction is to the right and the positive y-direction is up. Then, we may divide Jonathan and Jane's velocities into their x- and y-components as follows:
vx1 = 5.00 cos 30.0° = 4.33 m/s and vy1 = 5.00 sin 30.0° = 2.50 m/s are the speeds of Jonathan.
Jane's speed is given by the formulas vx2 = 7.00 cos 36.9° = 5.61 m/s and vy2 = 7.00 sin 36.9° = 4.16 m/s.
The sleigh is initially at rest, hence there is no initial total momentum in the x-direction. The total x-direction momentum after Jonathan and Jane jumps out is:
px = (−800 N)(−4.33 m/s) + (600 N)(5.61 m/s) = 6430 N·s
The final momentum in the x-direction is:
p'x = (1000 N + 800 N + 600 N)vx'
where vx' is the final velocity of the sleigh in the x-direction.
Therefore, we can solve for xv:
vx' = px / (1000 N + 800 N + 600 N) = 6430 N·s / 2400 N = 2.68 m/s
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What is the charge of an electric field 0.40 m away from a
source charge of 3.00 x 10-5C?
The electric field 0.40 m away from a source charge of 3.00 x 10^-5 C is 1.69 x 10^6 N/C, directed away from the source charge.
How to find the chargeThe electric field created by a point charge at a distance r from the charge is given by the equation:
E = kQ/r^2
where
E is the electric field in N/C,
k is Coulomb's constant (9.0 x 10^9 N m^2/C^2),
Q is the source charge in Coulombs, and
r is the distance from the source charge in meters.
Substituting the given values into the equation, we get:
E = (9.0 x 10^9 ) x (3.0 x 10^-5) / (0.40)^2
E = 1.69 x 10^6 N/C
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A 10,000 kg freight car is rolling along a track at 3.00m.s.Calculate the time needed for a force of 1000N for stop the car
It takes 0.3 seconds for a force of 1000 N to halt a 10,000 kg goods car moving at 3.00 m/s along a track.
Calculate the time needed for a force of 1000N for stop the carWe must first establish the car's starting kinetic energy in order to calculate the time required to stop the vehicle:
Kinetic Energy (KE) is equal to half of mass times speed, or 10,000 kg times 3.00 m/s.
KE = 45,000 J
Then, we may use the designed with the intent, which asserts that an object's change in kinetic energy equals the jobs performed by an external force: Work equals Force x Distance x Change in KE.
The gain in kinetic energy is equal to the starting kinetic energy because the car is coming to a stop: KE Change = -45,000 J
As a result, the external force's work is: Work equals force times distance, or -45,000 J.
When we solve for distance, we obtain: Work / Force = -45,000 J / 1000 N Distance
Location = -45 m
Because the force is against the direction of the car's motion, you'll see that the range is negative.
Finally, we can calculate the travel time using the kine model for uniformly accelerated motion: Distance is equal to 1/2*acceleration*time2. Time is calculated as sqrt(2 * Distance / Acceleration) as well as sqrt(2 * 45 m / (1000 N / 10,000 kg)).
time equals sqrt(0.09 s2/kg).
time = 0.3 s
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QUICK ANSWER Rainbows are caused by the refraction of visible wavelengths of light. TRUE OR FALSE
Answer:
true it is refraction of visible
The following conversion equivalents are given:
1 m 100 cm 1 in = 2.54 cm 1 ft = 12 in
A bin has a volume of 1.5 m3. The volume of the bin, in ft3, is closest to:
Answer:52.972ft^3
Explanation:
It is unit conversion based and for a volume of a bin from cubic meter to cubic foot as we know 1 meter =3.281 foot.
where volume=1.5m^3
multiply 1.5*(3.281)^3 ft^3
v=52.972 ft^3
The lightweight wheel on a road bike has a moment of inertia of 0.097 kg⋅m2
. A mechanic, checking the alignment of the wheel, gives it a quick spin; it completes 5 rotations in 2.2 s. To bring the wheel to rest, the mechanic gently applies the disk brakes, which squeeze pads against a metal disk connected to the wheel. The pads touch the disk 7.1 cm from the axle, and the wheel slows down and stops in 1.2 s.
What is the magnitude of the friction force on the disk?
the magnitude of the friction force on the disk is approximately 1.16 N.
We can use the conservation of energy to find the friction force on the disk. The initial kinetic energy of the wheel is equal to the work done by the friction force on the disk:
K_i = W_friction
The initial kinetic energy of the wheel can be found from its moment of inertia and angular velocity:
K_i = (1/2) I [tex]ω^2[/tex]
where I is the moment of inertia, ω is the angular velocity, and the factor of 1/2 comes from the rotational kinetic energy formula.
The final kinetic energy of the wheel is zero, since it comes to a stop. The work done by the friction force can be found from the distance over which it acts:
W_friction = F_friction d
where F_friction is the friction force and d is the distance over which the pads act on the disk. We can find the distance from the angular displacement of the wheel:
θ = ω t
where θ is the angle through which the wheel rotates, t is the time for the wheel to come to a stop, and the factor of 1/2π converts from rotations to radians. The distance over which the pads act is then:
d = r θ = 0.071 m × (5/2π) ≈ 0.562 m
Now we can put everything together:
K_i = W_friction
(1/2) I [tex]ω^2[/tex] = F_friction d
We can solve for the friction force:
F_friction = (1/2) I [tex]ω^2[/tex] / d
Plugging in the given values:
F_friction = (1/2) ×[tex]0.097 kg⋅m^2[/tex] × [tex](5/2.2π rad/s)^2[/tex] / 0.562 m ≈ 1.16 N
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Consider a converging lens with focal length 9.56 cm. The distance between an object and
a real image of the object created by the lens is 59.6 cm. Find the distance between the
object and the lens if the lens is closer to the object than it is to the image. Answer in cm
The object's distance from the lens is 11.4 cm.
Calculation-The thin lens equation can be used to determine how a converging lens's object distance (p), image distance (q), and focal length (f) relate to one another:
1/p + 1/q = 1/f
where p denotes the distance to the object, q is the distance to the picture, and f is the focal length.
Let's solve for the object distance using the thin lens equation:
1/p + 1/59.6 = 1/9.56
Combining both sides with p59.69.56 results in:
59.69.56 + p9.56 = p*59.6
Adding and subtracting:
570.176 + 9.56p = 59.6p
50.04p = 570.176
p = 11.4 cm
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QUICK ANSWER Fiber optic cables utilize internal reflection to transmit signals. TRUE OR FALSE
PLS MRK ME BRAINLIEST
Answer:
True
Explanation:
optical fibre consists of core and cladding. The signal is converted to light using transducers. The light travels across the cable undergoing multiple internal reflections. At the other end the light is converted back to Signal using transducers.
Answer: True
Explanation: Optical fiber uses the optical principle of "total internal reflection" to capture the light transmitted in an optical fiber and confine the light to the core of the fiber.
If I get this wrong im sorry
31. IP Point charges +4.1 µC and -2.2 μC are placed on the x axis at (11 m, 0) and (-11 m, 0), respectively. (a) Sketch the electric potential on the x axis for this system. (b) Your sketch should show one point on the x axis between the two charges where the potential vanishes. Is this point closer to the +4.1-C charge or closer to the -2.2-µC charge? Explain. (c) Find the point referred to in part (b).
Explanation:
let at a distance x from the c
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.70 cm. If the potential difference across the plates was 24.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.
the magnitude of the electric field in the region between the plates is 1.44 × [tex]10^6[/tex]V/m.
The electric field between the plates of the CRT can be calculated using the formula:
E = V/d
where E is the electric field, V is the potential difference across the plates, and d is the distance between the plates.
Substituting the given values, we get:
E = 24.5 kV / 0.017 m
Converting kV to V and simplifying, we get:
E = 24.5 × [tex]10^3[/tex]V / 0.017 m
E = 1.44 × [tex]10^6[/tex] V/m
An electric field is a force field created by a charged object or collection of charged objects that exerts a force on other charged objects within its vicinity. The electric field is a vector quantity and is measured in units of volts per meter (V/m).
The electric field at a point in space is defined as the force per unit charge acting on a positive test charge placed at that point. The direction of the electric field is given by the direction of the force that would be experienced by a positive test charge placed at that point.
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The Earth surface temperature is around 270 K and emissivity of 0.8, while space has temperature of around 2K. What is the net power radiated by the Earth in free space?
The net power radiated by the Earth in free space is approximately
1.2 x 10^ 17 W watts.
How to find the power radiatedTo calculate the net power radiated by the Earth in free space, we can use the Stefan-Boltzmann Law:
Power = σ * A * ε * (T^4 - T0^4)
where:
σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4)
A is the surface area of the Earth (4πR^2, where R is the radius of the Earth)
ε is the emissivity of the Earth (0.8)
T is the temperature of the Earth surface (270 K)
T0 is the temperature of space (2 K)
Plugging in the values, we get:
Power = 5.67 x 10^-8 * 4πR^2 * 0.8 * (270^4 - 2^4)
The radius of the Earth is approximately 6.37 x 10^6 m, so:
Power = 5.67 x 10^-8 * 4π(6.37 x 10^6)^2 * 0.8 * (270^4 - 2^4)
Power ≈ 1.193 x 10^ 17 W
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A truck accelerates uniformly from rest to 18.5 m/s in 5.7 s along a level stretch of road. Determine the average power (in W) required to accelerate the truck for the following values of the weight (ignore friction). (a)
The average power required to accelerate the truck with a weight of 20,000 N is approximately 116,930.68 W.
The average power required to accelerate an object is given by the formula:
Power = Work / Time
where Work is the change in kinetic energy of the object and Time is the time interval over which the change in kinetic energy occurs.
The change in kinetic energy of the truck is given by:
ΔK = 1/2 * m *[tex]v^2[/tex]
where m is the mass of the truck and v is its final velocity.
Since the truck starts from rest, its initial kinetic energy is zero, so the work done on the truck is equal to its change in kinetic energy. Therefore, the average power required to accelerate the truck is:
Power = Work / Time = ΔK / Time
Substituting the given values, we get:
(a) For weight w = 10,000 N (approximately 1,020 kg):
m = w / g = 10000 N / [tex]9.81 m/s^2[/tex] = 1019.3 kg
ΔK =[tex]1/2 * m * v^2[/tex] = 1/2 * 1019.3 kg * [tex](18.5 m/s)^2[/tex]= 333,036.6 J
Power = ΔK / Time = 333036.6 J / 5.7 s ≈ 58,426.84 W
Therefore, the average power required to accelerate the truck with a weight of 10,000 N is approximately 58,426.84 W.
Note: g is the acceleration due to gravity, which is approximately 9.81 [tex]m/s^2.[/tex]
(b) For weight w = 20,000 N (approximately 2,040 kg):
m = w / g = 20000 N / 9.81 m/s^2 = 2041.2 kg
ΔK = 1/2 * m *[tex]v^2[/tex] = 1/2 * 2041.2 kg * [tex](18.5 m/s)^2[/tex]= 666,073.3 J
Power = ΔK / Time = 666073.3 J / 5.7 s ≈ 116,930.68 W.
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a person that just start driving a car is called
Answer:
A person who drives a car for themselves, generally taking themselves back and forth to work or errands, is generally referred to as a driver.
Need help with this
Explanation:
See image for definitions....look at the units and fill the blanks appropriatly
A student decides to devise a new temperature scale with the freezing and boiling points at 0° X and
70° X. What Celsius temperature would correspond to a temperature of 35° X?
O 50
O 35
O 90
O 70
Answer:
To convert temperature from the new scale (X) to Celsius, we simply subtract 0 from the value in X and then multiply the resulting number by a factor of 100/70. This gives us the Celsius temperature.
For 35° X, we can use the formula as follows:
C = (35 - 0) * (100/70)
C = 35 * 1.4286
C = 50°C
Therefore, the correct answer is option A, which is 50.
A car slows down from -27.7m/s to -10.9m/s while undergoing a displacement of -105. What was the acceleration? (Unit=m/s^2)
The acceleration of the car was 6.88 [tex]m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.
To find the acceleration of the car, we can use the following formula:
acceleration = (final velocity - initial velocity) / time
However, we are not given the time it took for the car to undergo the displacement. To find the time, we can use the following formula:
displacement = (final velocity + initial velocity) / 2 * time
Solving for time, we get:
time = displacement / ((final velocity + initial velocity) / 2)
Plugging in the given values, we get:
time = [tex]-105 / ((-10.9 - 27.7) / 2) = 2.29 s[/tex]
Now that we have the time, we can use the first formula to find the acceleration:
acceleration = [tex](-10.9 - (-27.7)) / 2.29 = 6.88 m/s^2[/tex]
Therefore, the acceleration of the car was [tex]6.88 m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.
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Q37. A major source of heat loss from a house in cold weather is through the windows. Calculate the rate of heat flow through a glass window 2.0m x 1.5m in area and 3.2mm thick, it the temperatures at the inner and outer surfaces are 15.00C and 14.0°C
The rate of heat flow through the window is approximately 84.38 W.
To calculate the rate of heat flow through a glass window
The rate of heat flow through the window can be calculated using the formula:
Q = (kA (T1 - T2))/d
Where
Q is the rate of heat flowk is the thermal conductivity of the glassA is the area of the windowT1 is the temperature at the inner surfaceT2 is the temperature at the outer surfaced is the thickness of the glassWe first need to convert the temperatures to Kelvin, since temperature differences must be in Kelvin in this formula:
T1 = 15.0°C + 273.15 = 288.15 K
T2 = 14.0°C + 273.15 = 287.15 K
The thermal conductivity of glass can vary depending on the type of glass, but a typical value is around k = 0.9 W/(m·K) for plate glass.
Substituting the given values into the formula, we get:
Q = (0.9 W/(m·K) x 2.0 m x 1.5 m x (288.15 K - 287.15 K))/0.0032 m
Simplifying this expression, we get:
Q ≈ 84.38 W
Therefore, the rate of heat flow through the window is approximately 84.38 W.
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