The shoe sizes of a group of middle school girls are shown.


If a shoe size of 9 is added to the data, how does the median change?
The median stays 6.75.
The median increases to 6.75.
The median stays 7.
The median increases to 7.

a. The probability that the top-selling Red and Voss tire wears out before 60,000 miles can be found by calculating the Z-score and using a standard normal distribution table. The Z-score formula is: Z = (X - μ) / σ, where X is the distance (60,000 miles), μ is the mean (71,000 miles), and σ is the standard deviation (5,000 miles).

Z = (60,000 - 71,000) / 5,000 = -11,000 / 5,000 = -2.2. Using a standard normal distribution table, the probability is approximately 0.0139 or 1.39%.

b. To find the probability that a tire lasts more than 81,000 miles, calculate the Z-score: Z = (81,000 - 71,000) / 5,000 = 10,000 / 5,000 = 2. Using the standard normal distribution table, the probability of a Z-score less than 2 is approximately 0.9772. Since we want the probability of the tire lasting more than 81,000 miles, we need to find the complement: 1 - 0.9772 = 0.0228 or 2.28%.

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Answer: Let's say the total number of students surveyed is "x".

We know that 65% of the students surveyed said their favorite color was red, which means that 325 students said their favorite color was red.

We can set up a proportion to solve for "x":

65/100 = 325/x

To solve for "x", we can cross-multiply:

65x = 32500

Dividing both sides by 65, we get:

x = 500

Therefore, Hakeem surveyed 500 students in total.

Step-by-step explanation:

The equation Y=8.35x represents a proportional relationship between Y and x.

What is proportion?

In mathematics, two quantities are said to be proportional if they vary in a way that can be expressed as a ratio or fraction. Specifically, if two quantities x and y are proportional, this means that as x increases or decreases, y also increases or decreases by the same factor.

The equation Y=8.35x represents a proportional relationship between Y and x.

In a proportional relationship, when one variable (x) increases or decreases, the other variable (Y) changes by a constant factor. This constant factor is known as the constant of proportionality.

In the given equation, Y and x are directly proportional to each other, with a constant of proportionality of 8.35. This means that if x is multiplied by any factor, Y will also be multiplied by the same factor. For example, if x is doubled, Y will also be doubled (since 2 times 8.35 is 16.7).

Therefore, the equation Y=8.35x represents a proportional relationship between Y and x.

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Therefore, the value of tan N rounded to the nearest hundredth is approximately 0.85.

A triangle is a basic geometrical shape that is formed by connecting three non-collinear points in a plane using straight line segments. The three points are called the vertices of the triangle, and the line segments connecting them are called the sides. The angles formed between the sides of a triangle are also an important characteristic of the triangle. Triangles come in many different shapes and sizes, and they have many interesting properties and applications in mathematics, science, engineering, and other fields.

Since the opposite side of angle N is √67 and the adjacent side is √92, we can use the following formula for tangent:

tan(N) = opposite / adjacent

tan(N) = √67 / √92

We can simplify this expression by rationalizing the denominator:

tan(N) = (√67 / √92) * (√92 / √92)

tan(N) = √(67*92) / 92

tan(N) = √6164 / 92

tan(N) = 78.43 / 92

tan(N) ≈ 0.85 (rounded to the nearest hundredth)

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45% is greater than 40%

4. The transformation by Mrs. Selcer of the function f(x) = x² to create g(x) = 6·x², is a vertical stretch of the function f(x), therefore;

The transformation of a function is a function that results in a variation in the graph of the parent function.

The rules for the transformation of a function indicates that a transformation of a function f(x) to a·f(x), transform the coordinates of the points of f(x) as follows;

(x, y) → (x, a·y)

Therefore;

The transformation is a vertical stretch when a > 1

The transformation is a horizontal compression when a < 1

Since f(x) = x², and g(x) = 6·x², we get;

g(x) = 6·f(x)

Therefore, comparing, we get; a = 6 > 1, which indicates that the function is vertically stretched.

Therefore, Jane is correct.

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John should sell the jeans for ₱20,500 to gain a profit of 6%

if the cost price of a product is more than the selling price, but a profit may be made if the cost price of the product is lower than the price at which it is being sold. Loss percentage= Loss/CP x 100.

Given:

Selling price of jeans with a loss of 44% = ₱10,800

Profit percentage required = 6%

Let the cost price of the jeans be 'x'

Mathematical sentence:

According to the given information, we can write the following equation:

Selling price with loss of 44% = Cost price (1 - Loss %)

⇒ 10800 = x(1 - 0.44)

⇒ x = 10800 / 0.56

⇒ x = 19371.43

To find the selling price with a profit of 6%, we can use the following formula:

Selling price with profit % = Cost price (1 + Profit %)

Substituting the values, we get:

Selling price with profit of 6% = 19371.43(1 + 0.06)

⇒ Selling price with profit of 6% = 20500

Therefore, John should sell the jeans for 20,500 to gain a profit of 6%.

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The height of the pile is increasing at a rate of approximately 0.056 feet per minute when the pile is 12 feet high.

We are given that sand is falling off at a rate of 14 cubic feet per minute, and the diameter of the base of the cone is approximately three times the altitude. Let h be the height of the pile at a given time t, then we can write the volume of the cone as V = (1/3)πr^2h, where r is the radius of the base of the cone. Since the diameter is three times the altitude, we have r = 3h/2.

Taking the derivative of the volume with respect to time, we get dV/dt = (1/3)π(9h^2/4)(dh/dt). Plugging in the given values, we get:

14 = (1/3)π(9h^2/4)(dh/dt)

Simplifying, we get:

dh/dt = 56/(3πh^2)

When the height of the pile is 12 feet, the rate of change of the height of the pile is:

dh/dt = 56/(3π(12)^2) ≈ 0.056 ft/min.

Therefore, the height of the pile is changing at a rate of approximately 0.056 ft/min when the pile is 12 feet high.

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Answer:

y = 200·1.15^t The required function is y=1.047t + 199.12

Step-by-step explanation:

The ratio from one year to the next is 1.15, so the balance is a geometric sequence. Since t starts at zero, we can write the balance (y) after t years as ...

 y = initial value · (common ratio)^t

 y = 200·1.15^tThe given table shows the balance of a money market account over time.

Time (t)     Balance(y)

0  200

1  210

2  220.5

3  231.53

4  243.1

5  255.26

The function that represents the balance y(in dollars) after t years is linear regression line, because the value of y increased linearly.

The linear regression function is defined as

Where,

Put the values from the below table in the above formulas.

The value of b is 11.047 and the value of a is 199.12. Here, the variable is t.

Therefore the required function is the anser up top

The area of the rectangle has a width of 5 1/3 yards long and 2 1/6 yards wide is 104/9 square yards or 11.56 square yards.

When calculating a rectangle's area, we multiply the length by the breadth of the rectangle.

A mixed fraction is one that is expressed by its quotient and remainder.

Area = length * breadth

Given: Length = [tex]5 \frac{1}{3}[/tex] yards

           breadth = [tex]2 \frac{1}{6}[/tex] yards

First, we need to convert a mixed number into the improper fraction

[tex]5 \frac{1}{3}[/tex] = [tex]\frac{(5*3) + 1}{3}[/tex] = [tex]\frac{16}{3}[/tex]

[tex]2 \frac{1}{6} = \frac{(2*6) +1}{6} =\frac{13}{6}[/tex]

Therefore the area of the rectangle = Length * width

= [tex]\frac{16}{3} * \frac{13}{6}[/tex]

=[tex]\frac{104}{9}[/tex]

=[tex]\frac{104}{9} yards^{2}[/tex]

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Complete question:

The rectangle has [tex]5\frac{1}{3}[/tex] yards long and [tex]2 \frac{1}{6} \\[/tex] yards wide. What’s the area

Answer:

its b

Step-by-step exiplanation:

Answer:

The width of the jewelry store is 33 feet.

Step-by-step explanation:

To solve the problem, we can use the formula for the perimeter of a rectangle, which is P = 2L + 2W where P is the perimeter, L is the length, and W is the width. Substituting the given values, we get 186 = 2(60) + 2W. Simplifying the right side, we get 186 = 120 + 2W. Subtracting 120 from both sides, we get 66 = 2W. Dividing both sides by 2, we get W = 33.

Therefore, the width of the jewelry store is 33 feet.

The estimated relationship may not hold for all levels of TV advertising, and there may be non-linearities or interactions with other variables that should be taken into account in a more sophisticated model.

What is the interpretation of this relationship?

To develop an estimated regression equation to estimate weekly gross revenue with the amount of television advertising as the independent variable, we would need a dataset that includes information on both variables. Assuming we have such a dataset, we could use linear regression to estimate the relationship between the two variables.

The estimated regression equation would take the form:

Weekly Gross Revenue = [tex]b_0 + b_1[/tex]×Amount of TV Advertising + error

where [tex]b_0[/tex] is the intercept (the value of weekly gross revenue when the amount of TV advertising is zero), [tex]b_1[/tex] is the slope (the estimated increase in weekly gross revenue associated with a one unit increase in TV advertising), and error represents the random variation in the relationship between the two variables that is not explained by the model.

The interpretation of the relationship between weekly gross revenue and amount of TV advertising would depend on the sign and magnitude of the slope coefficient

[tex](b_1)[/tex]. If [tex]b_1[/tex] is positive, it would suggest that an increase in TV advertising is associated with an increase in weekly gross revenue. The magnitude of [tex]b_1[/tex] would indicate the strength of this relationship - a larger positive value of[tex]b_1[/tex] would indicate a stronger relationship between TV advertising and weekly gross revenue.

If [tex]b_1[/tex] is negative, it would suggest that an increase in TV advertising is associated with a decrease in weekly gross revenue. This could occur if the advertising is perceived as irritating or offensive to viewers, leading them to avoid the advertised product or service.

It is important to note that correlation does not imply causation, and there may be other factors that affect weekly gross revenue that are not captured in the model.

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Answer:

  17/6√3

Step-by-step explanation:

You want the simplified form of 9·sin(60°) -5/√3.

  [tex]9\sin(60^\circ)-\dfrac{5}{\sqrt{3}}=9\cdot\dfrac{\sqrt{3}}{2}-\dfrac{5\sqrt{3}}{\sqrt{3}\cdot\sqrt{3}}= \dfrac{3\cdot9\sqrt{3}}{3\cdot2}-\dfrac{2\cdot5\sqrt{3}}{2\cdot3}\\\\=\dfrac{(27-10)\sqrt{3}}{6}=\boxed{\dfrac{17}{6}\sqrt{3}}[/tex]

Answer:

(C). 45.2

Step-by-step explanation:

The sampling method described in the question is called "quota sampling."

Quota sampling is a non-probability sampling technique in which researchers select participants based on pre-determined quotas or characteristics, such as age or gender. In this case, the researchers are selecting participants between the ages of 20 and 40.

However, this method may not be representative of the entire population as it does not guarantee that all subgroups within the population have an equal chance of being selected. Therefore, the results may be biased and not accurately reflect the opinions of the entire population.

Therefore, it is important to consider the limitations of quota sampling when interpreting the results

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a) The null and alternative hypothesis are defined as

[tex]H_0 : p = 0.80 [/tex]

[tex]H_a : p > 0.80[/tex]

So, right choice is option (iii) here.

b) The test statistic value is equals to the 1.25.

c) The p-value of distribution is equals to the 0.1056. So, option(b) is right one here.

d) Conclusion: a fail to reject the null hypothesis, that is p = 0.80. So, there is no evidence to support the claim.

The claim about the population proportion that the proportion is more than 80% is tested under the null and the alternative hypothesis at the 5% level of significance. To calculate the P-value and the test statistic value, we will use Z-test. . We have a random sample of 100 people. So, sample size, n = 100

Number of people who favored candidate from the sample = 85

level of significance, [tex] \alpha[/tex]

= 0.05

Population proportion, [tex] \hat p[/tex]

= 85% = 0.85

a) The null hypothesis is,

[tex]H_0 : p = 0.80[/tex]

The alternative hypothesis is,

[tex]H_a : p>0.80[/tex]

(Right-Tailed)

Therefore, Option (iii) is correct.

b)Now, we determine the z statistic value : z-test statistic is defiend as:

[tex]z= \frac{\hat p−p}{\sqrt{\frac{p(1−p)}{n}}}[/tex]

=> [tex]z = \frac{0.85 - 0.80}{\sqrt{\frac{0.80(1 - 0.80)}{100}}}[/tex]

=> z = 0.05/0.04 = 1.25

so, Z-statistic value is 1.25.

c) Using the Z-distribution table, the value of P( z = 1.25 ) is 0.1056.

d) As we see, p-value (0.1056) > 0.05, so we fail to reject the null hypothesis. There is no evidence to reject null hypothesis.

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Complete question:

a random sample of 100 people was taken. eighty-five of the people in the sample favored candidate a. we are interested in determining whether or not the proportion of the population in favor of candidate a is significantly more than 80%.

a) The correct set of hypothesis for this problem is I)H0:p=0.85 and

HA:p>0.85

ii. H0:p>0.80 and

HA:p=0.80

iii.) H0:p=0.80 and

HA:p>0.80

iv.) H0:p=0.80 and HA:p≥0.80

b) find out the Z-statistic value?

c)the p-value is ? group of answer choices 0.2112 0.05 0.1056 0.025

d) What is your conclusion?

The largest lampshade Hillary can wrap laces around has an estimated diameter of [tex]14.32[/tex] inches.

The better measure across the edge of the circle is its diameter. The radius of a circle is the farthest from to any place on the edge. The diameter and radius are inversely proportional, or 2r=d2 r=d.

For instance, if a circle has a circumference of 25 cm, its diameter is 25 cm/, or 7.96 cm. For instance, calculate the square root of 12cm2 if that is the circle's area. Hence, the circle's diameter becomes 1.95 x 2 Equals 3.90 cm.

[tex]C = 2pir[/tex]

where [tex]C[/tex] is the circumference, π (pi) is a mathematical constant approximately equal to [tex]3.14[/tex], and r is the radius of the circle.

We can do this by rearranging the formula for the circumference:

[tex]C = 2pir[/tex]

[tex]r = C / (2pi)[/tex]

We are given that Hilary has [tex]45[/tex] inches of lace, which is the circumference of the circle.

[tex]r = 45 / (2pi) =7.16 inches[/tex]

Finally, we can find the diameter of the circle by doubling the radius:

[tex]d = 2r = 14.32 inches[/tex]

Therefore, the approximate diameter of the largest lampshade Hilary can put lace around is [tex]14.32[/tex] inches.

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The expected number of tosses until either a head comes up or four tails are obtained is 7/4

Let X be the random variable representing the number of tosses until either a head comes up or four tails are obtained.

Let's consider the first toss. There are two possible outcomes: heads or tails. If a head comes up on the first toss, then we stop and X = 1. If a tail comes up, we need to continue tossing until we get four tails in a row or a head.

Let Y be the random variable representing the number of additional tosses needed if the first toss is a tail. There are two possible outcomes for the second toss: heads or tails. If a head comes up, we stop and X = 2. If a tail comes up, we need to continue tossing until we get three tails in a row or a head.

Similarly, we can define Z as the random variable representing the number of additional tosses needed if the first two tosses are tails. There are two possible outcomes for the third toss: heads or tails. If a head comes up, we stop and X = 3. If a tail comes up, we need to continue tossing until we get two tails in a row or a head.

Finally, let W be the random variable representing the number of additional tosses needed if the first three tosses are tails. There are two possible outcomes for the fourth toss: heads or tails. If a head comes up, we stop and X = 4. If a tail comes up, we need to continue tossing until we get four tails in a row.

We can write X in terms of Y, Z, and W as follows

X = 1 + Y if the first toss is heads

X = 1 + 1 + Z if the first two tosses are tails and the third toss is heads

X = 1 + 1 + 1 + W if the first three tosses are tails and the fourth toss is heads

X = 1 + 1 + 1 + 1 if the first four tosses are tails

Now, we need to compute the expected values of Y, Z, and W.

If the first toss is a tail, the probability of getting another tail on the second toss is 1/2, and the probability of getting a head is also 1/2. Therefore,

E[Y] = 1/2(1) + 1/2(1 + Z)

If the first two tosses are tails, the probability of getting another tail on the third toss is 1/2, and the probability of getting a head is also 1/2. Therefore,

E[Z] = 1/2(1) + 1/2(1 + W)

If the first three tosses are tails, the probability of getting another tail on the fourth toss is 1/2, and the probability of getting a head is also 1/2. Therefore,

E[W] = 1/2(1) + 1/2(4)

Note that the expected value of W is 2, not 3, because if we get three tails in a row, we stop and X = 4.

Putting it all together, we have:

E[X] = 1/2(1) + 1/2(1 + E[Z])

= 1/2(1) + 1/2(1 + 1/2(1) + 1/2(1 + E[W]))

= 1/2(1) + 1/2(1 + 1/2(1) + 1/2(1 + 2))

= 7/4

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Step-by-step explanation:

To find the price of one tire patch, you could use the equation:

4x = 22.2 + 1.9

which simplifies to:

4x = 24.1

Then divide both sides by 4 to isolate x:

x = 6.025

So the equation that applies here is:

4x = 22.2 + 1.9

We can start by rearranging the equation 5 sin x + 4 cos x = 0 by dividing both sides by cos(x):

5

sin

⁡

�

cos

⁡

�

+

4

=

0

5

cosx

sinx

​

+4=0

Recall that $\frac{\sin x}{\cos x} = \tan x$. So we can substitute this in:

5

tan

⁡

�

+

4

=

0

5tanx+4=0

Now we can solve for $\tan x$:

\begin{align*}

5 \tan x + 4 &= 0 \

5 \tan x &= -4 \

\tan x &= \frac{-4}{5}

\end{align*}

Therefore, the value of $\tan x$ is $\boxed{\frac{-4}{5}}$.

Polynomial expressions of [tex]2^{nd}[/tex] degree with one unknown (only [tex]x[/tex]) have [tex]2[/tex] roots. We use the formula below to determine these roots;

This formula is valid for equations of the form [tex]ax^2+bx+c[/tex]. We can convert the equation given in the question into this format to get the result;

Hence, the value of [tex]a[/tex]: [tex]8[/tex],

the value of [tex]b[/tex]: [tex]16[/tex],

the value of [tex]c[/tex]: [tex]3[/tex].

Now, we can find the roots of this equation by using this formula;

Answer:

30% of students do not plan to attend college.

mean temperature=sum of all the temperatures to the total number of temperatures:

Mean temperature = (71 + 75 + 74 + 80 + 83 + 86 + 90 + 85 + 81 + 80) / 10

Mean temperature = 805 / 10

Mean temperature = 80.5°F

Therefore, the mean temperature for the next 10 days is 80.5 degrees Fahrenheit.

The mean temperature in Fahrenheit for the next 10 days is 79.5.

The mean temperature in Fahrenheit for the next 10 days can be calculated as follows;

Add all the given temperatures together:

71 + 75 + 74 + 80 + 83 + 86 + 90 + 85 + 81 + 80 = 795

Divide the sum obtained by the total number of temperatures, which is 10: 795 ÷ 10 = 79.5.

Therefore, the mean temperature in Fahrenheit for the next 10 days is 79.5.

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With only two hours left, it's important to stay focused and work efficiently. Take breaks as needed to avoid burnout, but don't procrastinate or get distracted by other tasks.

Hi there! I'd be happy to help you with your math on your profile. Could you please provide me with more specific information about the assignment? What topics does it cover and what kind of problems do you need help with? It's difficult to provide a comprehensive answer without more information.

In the meantime, I can offer some general tips for tackling math problems. First, read the problem carefully and make sure you understand what it's asking. Look for key words or phrases that indicate what type of problem it is. Next, identify the relevant formulas or concepts that you'll need to solve the problem. If you're unsure, check your textbook or notes for guidance.

As you work through the problem, be sure to show your work and label each step clearly. This will help you avoid mistakes and make it easier to check your work later. If you get stuck, don't be afraid to ask for help from a teacher or tutor.
Good luck, and let me know if you have any more specific questions or concerns!

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The greatest power of "p" in this situation is 4, which is the coefficient of p4. Consequently, the polynomial has a degree of 4.

Polynomials are algebraic expressions that consist of variables and coefficients. Variables are also sometimes called indeterminates.

This equation is provided:

1) [tex]$2p^{4}+p^{3}$[/tex]

The greatest power of the polynomial's variable "p" must be identified to categorize this polynomial by degree.

Therefore, the polynomial [tex]$2p^{4}+p^{3}$[/tex] is a polynomial of the fourth degree.

2) [tex]$2x^{2}$[/tex]

The greatest power of the polynomial's variable "x" must be identified to categorize this polynomial by degree.

The greatest power of "x" in this situation is 2, which is the coefficient of . Consequently, the polynomial has a degree of 2.

Therefore, the polynomial [tex]2x^2[/tex] is a polynomial of the second degree.

3) [tex]$-5n^{4}+10n-10$[/tex]

The greatest power of the polynomial's variable "n" must be identified to categorize this polynomial by degree.

The greatest power of "n" in this situation is 4, which is the coefficient of . Consequently, the polynomial has a degree of 4.

Therefore, the polynomial [tex]n^4[/tex] is a polynomial of the fourth degree.

4) 6n

The greatest power of the polynomial's variable "n" must be identified to categorize this polynomial by degree.

The greatest power of "n" in this situation is 1, which is the coefficient of [tex]n^1[/tex]. Consequently, the polynomial has a degree of 1.

Therefore, the polynomial [tex]n^1[/tex] is a polynomial of one degree.

5) -6

The greatest power of the polynomial's variable "n" must be identified to categorize this polynomial by degree.

The polynomial in this instance doesn't have a component. It has a value of 6 and is a constant word. A constant word is thought to have a degree of zero.

Therefore, equation 6 is a zero-degree polynomial.

6) [tex]$x^{3}-3$[/tex]

The greatest power of the polynomial's variable "x" must be identified to categorize this polynomial by degree.

The greatest power of "x" in this situation is 3, which is the coefficient of . Consequently, the polynomial has a degree of 3.

Therefore, the polynomial [tex]x^3[/tex] is a polynomial of the third degree.

7) [tex]$2n^{5}$[/tex]

The greatest power of the polynomial's variable "n" must be identified to categorize this polynomial by degree.

The greatest power of "n" in this situation is 5, which is the coefficient of . Consequently, the polynomial has a degree of 5.

Therefore, the polynomial [tex]n^5[/tex] is a polynomial of the fifth degree.

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