The sum of the digits of a two digit number is 10. When the digits are reversed, the number increases by 18. Find original number.

The derivative of the function f(x) is:

f'(x) = (sinx +  2cosx)/(2√x)  

The derivative of the function f(x) is:

f'(x) = (sinx +  2cosx)/(2√x)  

Differentiation involves finding the derivative of a function. The derivative of a function represents the rate of change of the function concerning its input variable.

For any function of the form f(x) = u(x)·v(x). The derivative is given by:

f'(x) = u'(x)·v(x) + v'(x)·u(x)

f(x) = (√x)·sinx can be written as f(x) = x^1/2. sin x

Thus, if f(x) = (√x)·sinx, the derivative will be:

f'(x) = (1/2)x^1/2sinx + x^1/2cosx

f'(x) = sinx/(2√x) + cosx/(√x)  

f'(x) = (sinx +  2cosx)/(2√x)  

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Wangari plants 12 trees every 3 hours, so her planting rate is 12 trees per 3 hours, or 4 trees per hour.

To find the equation that relates the number of trees Wangari plants (p) and the time she spends planting them (h) in hours, we can use the formula for direct variation:

p = k*h

where k is a constant of proportionality. Since Wangari plants at a rate of 4 trees per hour, k = 4:

p = 4h

Therefore, the equation that relates the number of trees Wangari plants (p) and the time she spends planting them (h) in hours is p = 4h.

It is not safe to assume that candidate A will win the election

Statistical inference is the process of drawing conclusions or making decisions about a population based on sample data. It involves using statistical methods and techniques to analyze and interpret data, estimate population parameters, and assess the uncertainty of the results.

Here we have

A sample of 250 people was surveyed and a 95% Confidence interval was calculated. From this confidence interval, it can be concluded that between 48% and 60% of the population will vote for Candidate.

According to the given data, It is not safe to assume that Candidate A will win the election based solely on the confidence interval calculated from the sample.

A confidence interval is a range of plausible values for a population parameter, but it does not guarantee a particular outcome in the future.

Other factors such as the size and composition of the actual voting population, as well as the campaign strategies and performance of the candidates, should also be considered.

Hence,

It is not safe to assume that candidate A will win the election

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Solving a system of equations we will see that the values are:

x = 115

y = -38.25

We know that the sum of two adjacent angles is always 180°, then we can write two linaer equations:

8y + 4x + 26 = 180

4y - 12 + 3x = 180

We can simplify that to get the system of equations:

4x + 8y = 154

3x + 4y = 192

To solve this, we can take the difference between twice the second equation and once the first equation to get:

2*(3x + 4y) - (4x + 8y) = 2*192 - 154

6x + 8y - 4x - 8y = 230

2x = 230

x = 230/2

x = 115

Then the value of y is:

3*115 + 4*y = 192

4y = 192 - 3*115

y = (192 - 3*115)/4

y = -38.25

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The correct option is- C) 0 <= x <= 12 and 16 <= y <= 48, is the reasonable constraints for the give graph of total number of patients showed up to nurse Jackie.

When variables are employed in equations to simulate real-world scenarios, constraints must be applied to set limits and bounds on those variables.

From the given graph

x-axis shows the time duration between 9 AM to 9 PM.

y-axis shows the number of patients visited.

Value shown on the graph;

Thus, 0 <= x <= 12 and 16 <= y <= 48, is the reasonable constraints for the give graph of total number of patients showed up to nurse Jackie.

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When expressed in scientific notation, extremely large or tiny numbers are easier to comprehend. The expression (6x10⁻³)(1.4x10¹) have the solution in scientific notation as 8.4 x 10⁻².

A number can be expressed using scientific notation if it cannot be conveniently expressed in decimal form due to its size or shape, or if doing so would require writing out an abnormally long string of digits. In the UK, it is also referred to as standard form, standard index form, and standard form.

Despite the fact that we are aware that whole numbers can never be exhausted, we are unable to record such vast amounts of data on paper. Moreover, a simpler method of representation is required for the numbers that appear at the millions place after the decimal. This may make it challenging to represent small numbers in their larger form. We employ a scientific notation as a result.

Given:

= (6x1.4)(10⁻³x10¹) = (8.4x10¹)(10⁻²)

= 8.4x (10¹ x 10⁻²)

= 8.4x (10¹ x 10⁻²)

= 8.4 x 10⁻²

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After answering the presented question, we can conclude that As a quadrilateral result, the value of x is 112 degrees.

In geometry, a quadrilateral is a four-sided polygon with four edges and four corners. The term is derived from the Roman terms quadri and latus (meaning "side"). A rectangle is a two-dimensional form with four sides, four vertices, and four corners. Concave and convex surfaces are basically of two types. In addition, trapezoids, parallelograms, rectangles, rhombuses, and squares are subclasses of convex quadrilaterals. A rectangle is a two-dimensional structure with four straight sides. Quadrilaterals come in a variety of shapes, including parallelograms, trapezoids, rectangles, kites, squares, and rhombuses.

Because PQRS is inscribed in circle O, the quadrilateral's opposite angles sum up to 180 degrees. Therefore,

QOS angle + QOR angle = 180 degrees

Angle QOS x (Angle R x Angle OQR) = 180°

Angle QOS = 180 degrees + (180 degrees - Angle P + 38 degrees)

Angle P = 180 degrees - Angle QOS + 218 degrees

Angle P - 38 degrees - 218 degrees = Angle QOS

QOS angle = Angle P - 256 degrees

Lastly, we may get Angle P by using the knowledge that the total of the angles of a triangle is 180 degrees.

QOS angle = 8 degrees, 38 degrees, and 218 degrees

QOS angle = -248 degrees

QOS angle = -248 degrees plus 360 degrees = 112 degrees

As a result, the value of x is 112 degrees.

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To determine the actual height of the climbing frame, we need to know the scale factor of the model. If the scale factor is, for example, 1:50, it means that every 1 cm on the model represents 50 cm in real life.

Assuming that we have the scale factor, we can use the following proportion:

model height / actual height = scale factor

We know that the model height is 10 cm, and we want to find the actual height. Let's say the scale factor is 1:100. Then we have:

10 cm / actual height = 1/100

Multiplying both sides by the actual height, we get:

actual height = (10 cm) x (100/1) = 1000 cm

Therefore, the actual height of the climbing frame in this example is 1000 cm, or 10 meters.

The three options that represent the correct steps to solve quadratic equation are:

What is equation?

In mathematics, an equation is a statement that two expressions are equal. It typically consists of two sides, called the left-hand side (LHS) and the right-hand side (RHS), connected by an equal sign.

To solve the quadratic equation [tex]8x^2 + 16x + 3 = 0[/tex], Patel could use the following steps:

Use the quadratic formula: x = (-b ± √([tex]b^2[/tex] - 4ac)) / 2a, where a = 8, b = 16, and c = 3. This formula gives the solutions to any quadratic equation of the form [tex]ax^2[/tex] + bx + c = 0.

Factor the quadratic equation by finding two numbers that multiply to give ac (8 * 3 = 24) and add to give b (16).

This can be a bit tricky, but in this case, the factors are (4, 6). So we can write [tex]8x^2[/tex] + 16x + 3 as [tex]8x^2[/tex] + 4x + 2x + 3, and then group the terms as ([tex]8x^2[/tex] + 4x) + (2x + 3) = 4x(2x + 1) + 1(2x + 3).

Use the factored form of the equation to set each factor equal to zero and solve for x.

So we have 4x(2x + 1) + 1(2x + 3) = 0, which gives us two possible solutions: 2x + 1 = 0, which gives x = -1/2, and 2x + 3 = 0, which gives x = -3/2.

Therefore, the three possible steps Patel could use to solve the quadratic equation are:

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Answer:

3.1

Step-by-step explanation:

To express a percent as a mixed number, we need to divide the percent by 100 and convert it to a mixed number.

Let's do this for each option:

310% = 310/100 = 3.1

3.1 can be written as the mixed number 3 1/10.

49% = 49/100 = 0.49

0.49 cannot be expressed as a mixed number because it is less than 1.

7.4% = 7.4/100 = 0.074

0.074 cannot be expressed as a mixed number because it is less than 1.

0.001% = 0.001/100 = 0.00001

0.00001 cannot be expressed as a mixed number because it is less than 1.

Therefore, the percentage that can be expressed as a mixed number is 310%, which is equivalent to 3 1/10.

Step-by-step explanation:

what is the answer to 100001/9

Based on the given statements, we can conclude:

If X, then not Y: This means that if X is true, then Y cannot be true.

If not Y, then Z: This means that if Y is not true, then Z must be true.

We are also given the information that Y is true. Therefore, we can conclude that:

Y is true, so not X: Since Y is true, X cannot be true, according to the first statement.

If not Y, then Z: Since Y is true, we cannot conclude anything about Z. However, we do know that Y cannot be false.

So the final conclusion is that X is false and Y is true, but we don't have enough information to determine whether Z is true or false.

Answer:

(D)

Step-by-step explanation:

The sum of the exterior angles of any polygon is [tex]360^{\circ}[/tex].

Answer:

To find the solution to f(x)=g(x), we need to find the point(s) where the two curves intersect.

The graph is not provided, but we can find the solution algebraically by setting the two functions equal to each other:

f(x) = g(x)

x^2 = 12^(x-1)

To solve for x, we can take the logarithm of both sides:

log(x^2) = log(12^(x-1))

2log(x) = (x-1)log(12)

2log(x) = xlog(12) - log(12)

2log(x) - xlog(12) = -log(12)

log(x^2) - log(12^x) = -log(12)

log(x^2/12^x) = -log(12)

log(x/12) = -log(12)

log(x) - log(12) = -log(12)

log(x) = 0

x = 1

Therefore, the solution to f(x)=g(x) is x=1.

Step-by-step explanation:

Step-by-step explanation:

10 = k * 5

1 = k * 1

10 / 1 = k * 5 / (k * 1)

10 = 5k

k = 2

y = kx

n = 2 * 1

n = 2

Answer: The length is 8 yards

Step-by-step explanation: First, take the volume of the prism (115 cubic yards), divide it by the width (2 1/2), the divide that by the height (5 3/4) getting you the length: 8 yards

Therefore, the value of the car in the year 2003 will be approximately $8,962 when rounded to the nearest 50 dollars.

The annual rate of change is a measure that indicates the percentage increase or decrease in a value over a period of one year. It is commonly used to track changes in economic indicators such as Gross Domestic Product (GDP), inflation, and unemployment.

To calculate the annual rate of change, you need to first determine the starting value and ending value for the period in question. You then calculate the percentage change between the two values using the following formula:

[tex]Annual rate of change = ((Ending value - Starting value) / Starting value) * 100[/tex]

A) To find the annual rate of change between 1991 and 2000, we can use the formula:

[tex]r = (V1/V0)^{(1/n)} - 1[/tex]

where V0 is the initial value, V1 is the final value, and n is the number of years. Plugging in the given values, we get:

[tex]r = (12000/45000)^{(1/9)} - 1[/tex]

r ≈ -0.1049

Therefore, the annual rate of change between 1991 and 2000 is approximately -0.1049.

B) To express the rate of change as a percentage, we can multiply it by 100:

[tex]r = -0.1049 * 100[/tex]

r ≈ -10.49%

Therefore, the correct answer to part A written in percentage form is approximately -10.49%.

C) Assuming the car value continues to drop by the same percentage, we can use the formula:

[tex]V = V_0 * (1 + r)^n[/tex]

where V0 is the initial value, r is the annual rate of change, and n is the number of years. Plugging in the given values, we get:

[tex]V = 12000 *(1 - 0.1049)^3[/tex]

V ≈ $8,961.75

Therefore, the value of the car in the year 2003 will be approximately $8,962 when rounded to the nearest 50 dollars.

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Thus, the polynomial at x=i needs to be evaluated: As a result, when x-1 is divided by [tex]-3x^4 - 2x^3 + 5x^2 - 7x,[/tex] the remaining is -8i - 5.

Using just the activities of addition, removal, multiplication, and non-negative decimal exponents, a polynomial is a mathematical equation made up of variables and coefficients. Polynomials can contain one or perhaps more variables, and they can be categorised based on their degree, which is the polynomial's highest exponent. The most familiar example of polynomial is the exponential, which has a rank of 2 and may be expressed in the form ax2 + bx + c. The shortest polynomials be monomials, which have only one term. Algebra, algebra, and number theory are just a few of the mathematical areas where polynomials are used.

given

The remainder theorem can be used to get the remaining when[tex]-3x^4, 2x^3, 5x^2[/tex], and 7x are divided by x-i.

The remainder is p when a polynomial p(x) is divided by (x-a), according to the theorem (a).

In this instance, we must determine the remaining after dividing [tex]3x^4[/tex] by x-i and adding [tex]2x^3 , 5x^2 ,7^x.[/tex]

Thus, the polynomial at x=i needs to be evaluated: As a result, when x-1 is divided by [tex]-3x^4 - 2x^3 + 5x^2 - 7x,[/tex] the remaining is -8i - 5.

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So the speed of the wind is 52 miles per hour. When the airplane is flying into a headwind, its ground speed (the speed at which it appears to be moving relative to the ground)

what is speed  ?

In physics, speed is the rate at which an object moves, or the distance traveled per unit of time. It is a scalar quantity, meaning that it has magnitude (a numerical value) but no direction.

In the given question,

Let's use "s" to represent the airspeed of the plane, and "w" to represent the speed of the wind.

When the airplane is flying into a headwind, its ground speed (the speed at which it appears to be moving relative to the ground) is s - w. We know that the airplane travels 1560 miles in 3 hours, so we can set up the equation

1560 = (s - w) * 3

Simplifying this equation, we get:

s - w = 520

When the airplane is flying with a tailwind (i.e., in the opposite direction of the headwind), its ground speed is s + w. We know that the airplane travels 1560 miles in 2.5 hours (since 2 hours and 30 minutes is equal to 2.5 hours), so we can set up the equation:

1560 = (s + w) * 2.5

Simplifying this equation, we get:

s + w = 624

Now we have two equations:

s - w = 520

s + w = 624

We can solve this system of equations by adding them together. When we add the left sides of the equations, we get:

2s = 1144

Dividing both sides by 2, we get:

s = 572

So the airspeed of the plane is 572 miles per hour.

Now we can use one of the equations we found earlier to solve for the wind speed. Let's use the equation:

s - w = 520

Substituting s = 572, we get:

572 - w = 520

Simplifying this equation, we get:

w = 52

So the speed of the wind is 52 miles per hour.

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The coordinates at which the tangent line to f(x) = (x-6/x)^8 is horizontal are (√6, f(√6)) and (-√6, f(-√6)), where f(x) is the given function.

To find the coordinates at which the tangent line to the function f(x) = (x-6/x)^8 is horizontal, we need to find the critical points of the function where the derivative is zero or undefined.

First, let's find the derivative of the function:

f(x) = (x-6/x)^8

f'(x) = 8(x-6/x)^7 * (1 - (-6/x^2))

Simplifying the second term, we get:

f'(x) = 8(x-6/x)^7 * (x^2+6)/x^2

Now we need to set the derivative equal to zero and solve for x:

8(x-6/x)^7 * (x^2+6)/x^2 = 0

(x^2+6) cannot be zero, so we can ignore that factor.

8(x-6/x)^7 = 0

(x-6/x) = 0

x^2 - 6 = 0

x = ±√6

So we have two critical points at x = √6 and x = -√6.

Now we need to determine whether these critical points correspond to a maximum, minimum, or inflection point. To do this, we can use the second derivative test.

Taking the derivative of the first derivative, we get:

f''(x) = 8(x-6/x)^6 * (56/x^3 + 7)

Evaluating the second derivative at x = √6, we get:

f''(√6) = 8(√6-6/√6)^6 * (56/√6^3 + 7)

f''(√6) > 0, so the function has a local minimum at x = √6.

Evaluating the second derivative at x = -√6, we get:

f''(-√6) = 8(-√6-6/-√6)^6 * (56/-√6^3 + 7)

f''(-√6) < 0, so the function has a local maximum at x = -√6.

Therefore, the coordinates at which the tangent line to f(x) = (x-6/x)^8 is horizontal are (√6, f(√6)) and (-√6, f(-√6)), where f(x) is the given function.

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The statements that are true regarding a traditional individual retirement account are:

• People can contribute to the account until retirement age.

• Contributions to the account are limited each year.

• Contributions reduce taxable income.

Taxable income is the portion of an individual's income that is subject to taxation by the government. It is calculated by subtracting all allowable deductions, exemptions, and credits from an individual's gross income.

The other two statements are not true regarding a traditional individual retirement account:

Employers do not create them and match employee contributions. This describes a different type of retirement account, such as a 401  or a 403.

People cannot withdraw money penalty-free at any time. There are penalties for withdrawing money from a traditional IRA before the age of 59 ½, with certain exceptions.

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The percentage of compaction of the tested soil is 92.1%.

What is Algebraic expression ?

An algebraic expression is a mathematical phrase that can include numbers, variables, and mathematical operations, such as addition, subtraction, multiplication, and division.

a) To compute the water content, we need to find the weight of water in the soil sample.

Wet unit weight of soil = (weight of wet soil)/(volume of soil)

The volume of soil can be found using the weight of sand (sand core) to fill the test hole:

Volume of soil = Volume of sand cone = (weight of sand)/(bulk density of sand)

Volume of soil = 1636 g / 15.73  = 0.104

Wet unit weight of soil = (2100 g - 1636 g) / 0.104  = 5490

The dry unit weight of soil can be found by dividing the dry weight of the soil sample by its volume:

Dry unit weight of soil = (weight of dried soil)/(volume of soil)

Dry unit weight of soil = 1827 g / 0.104 = 17558.5

b) To compute the in-place dry unit weight of tested soil, we need to know the water content of the soil.

Water content = [(weight of wet soil - weight of dry soil) / weight of dry soil] x 100%

Water content = [(2100 g - 1827 g) / 1827 g] x 100% = 14.4%

Dry unit weight of tested soil = (dry unit weight of soil) / (1 + water content)

Dry unit weight of tested soil = 17558.5 / (1 + 0.144) = 15294.3

c) To compute the percentage of compaction, we need to compare the in-place dry unit weight to the maximum dry unit weight.

Maximum dry unit weight = 18.09

Optimum moisture content = 13%

Maximum wet unit weight = maximum dry unit weight / (1 - optimum moisture content/100)

Maximum wet unit weight = 18.09  / (1 - 0.13) = 20.805

Maximum weight of soil = maximum wet unit weight x volume of soil

Maximum weight of soil = 20.805  x 0.104 = 2.161 kN

Actual weight of soil = (dry unit weight of tested soil) x (1 + water content) x volume of soil

Actual weight of soil = 15.294  x (1 + 0.144) x 0.104  = 1.990 kN

Percentage of compaction = (actual weight of soil / maximum weight of soil) x 100%

Percentage of compaction = (1.990 kN / 2.161 kN) x 100% = 92.1%

Therefore, the percentage of compaction of the tested soil is 92.1%.

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Step-by-step explanation:

Teresa și sa se uite pe aici prin intermediul acestui an indirect bună am văzut pe net și sa se întâmple și sa ne contactați la adresa lui și sa ne întâlnim cu toții la

Answer:

o find MW, we need to use the fact that OS is perpendicular to WV, which means that OS is also perpendicular to MW since it bisects WV.

Let's label the midpoint of WV as point N. Then we can use the Pythagorean theorem to find MW.

First, we need to find the length of ON. Since OS is a radius of the circle, it is equal to the radius of the circle, which we can call r. Then, using the Pythagorean theorem, we have:

ON^2 = OS^2 - SN^2

ON^2 = r^2 - (WV/2)^2

ON^2 = r^2 - (MW/2)^2 (since NW = MV)

Next, we need to find the length of MN. We know that OM is half of WV, so OM = WV/2. Then, using the Pythagorean theorem again, we have:

MN^2 = ON^2 + OM^2

MN^2 = r^2 - (MW/2)^2 + (WV/2)^2

MN^2 = r^2 - (MW/2)^2 + (2MW/2)^2 (since WV = 2MW)

MN^2 = r^2 - (MW/2)^2 + MW^2

Finally, we can solve for MW by using the Pythagorean theorem one more time:

MW^2 = MN^2 + NW^2

MW^2 = (r^2 - (MW/2)^2 + MW^2) + (MW/2)^2

MW^2 = r^2 - (MW/2)^2 + MW^2/4 + MW^2/4

MW^2 = r^2 - (MW/2)^2 + MW^2/2

Multiplying both sides by 4 gives:

4MW^2 = 4r^2 - MW^2 + 2MW^2

3MW^2 = 4r^2

MW^2 = 4r^2/3

MW = 2r/sqrt(3)

Therefore, the length of MW is 2r/sqrt(3).

Therefore, 34 student tickets and 126 adult tickets were sold.

Algebraic expressiοn can be defined as cοmbinatiοn οf variables and cοnstants.

Write twο equatiοns tο mοdel the prοblem:

Let x be the number οf student tickets sοld, and y be the number οf adult tickets sοld. Then, we can write the fοllοwing twο equatiοns:

5x + 10y = 1430 (the total amount earned from ticket sales is $1430)

x + y = 160 (the total number of tickets sold is 160)

Solve for one of the variables in terms of the other:

We can rearrange the second equation to solve for one of the variables in terms of the other:

x + y = 160

x = 160 - y (subtract y from both sides)

Substitute the expression found in step 2 into one of the equations from step 1:

We can substitute the expression x = 160 - y into the first equation:

5x + 10y = 1430

5(160 - y) + 10y = 1430 (substitute x = 160 - y)

800 - 5y + 10y = 1430 (distribute the 5)

5y = 630 (combine like terms)

y = 126 (divide both sides by 5)

Solve for the other variable:

Now that we know y = 126, we can use the expression x = 160 - y to find x:

x = 160 - y

x = 160 - 126

x = 34

Therefore, 34 student tickets and 126 adult tickets were sold.

Check the solution:

We can check our solution by plugging in x = 34 and y = 126 into the original equations:

5x + 10y = 1430

5(34) + 10(126) = 1430

x + y = 160

34 + 126 = 160

Therefore, Both equations check out, so our solution is correct.

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Answer:

The system of equations has two real roots

Step-by-step explanation:            

y = x² + 3x + 4 ------------(I)      

y - x = 7 ------------------------(II)

y = 7 +x

Substitute y = 7 + x in equation (I),        

7 + x = x² + 3x + 4              

0 = x² + 3x + 4 - x - 7              

0 = x² + 3x - x + 4 - 7

Combine like terms,          

0 = x² + 2x - 3

x² + 2x - 3 = 0

a = 1; b = 2; c = -3

Discriminant = b² - 4ac                    

                     = 2² - 4*1*(-3)                    

                     = 4 + 12                    

                     = 16  

System of equations has two real roots as discriminant is greater than 0.

The probability of randomly selecting a student that didn't get an A is P = 0.61

We want to find the probability that the student did not get an A.

To get this, we need to take the quotient between the number of students that didn't get an A, and the total number of students.

In the table,  can see that there is a total of 69 students and we also can see that of these 69, 27 got an A.

Then the number that did not get an A is:

69 - 27 = 42

Then the probability is:

P = 42/69 = 0.61

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Answer: Mark as brainliest

Option A shows the correct method to calculate the volume of the cylinder-shaped mold.

Step-by-step explanation:

The correct method to calculate the number of cubic units of cake batter needed to fill the mold is:

V = πr^2h

Where:

V = volume of the cake batter needed

π = 355/113 (approximate value of pi)

r = radius of the cylinder (diameter/2 = 10/2 = 5)

h = height of the cylinder (7)

Substituting the values in the formula, we get:

V = (355/113) x 5^2 x 7

V = 616.07 cubic inches (rounded to two decimal places)

Therefore, approximately 616.07 cubic inches of cake batter are needed to fill the mold.

The required dimensions of the kennel are 17 feet by 8.5 feet.

Let the length of the kennel be L and the width be W.

We know that the total length of fence available is 25 feet. Since one side of length 9 feet does not need fencing, the total length of the other three sides that need fencing is (L + 2W - 9).

Therefore, we have:

25 = L + 2W - 9

Simplifying the equation, we get:

L + 2W = 34

We also know that the area of the kennel is given by:

Area = Length x Width

Substituting L = 34 - 2W from the first equation into the above equation, we get:

Area = (34 - 2W) x W

Simplifying the equation, we get:

Area = 34W - 2W²

To maximize the area, we differentiate the above equation with respect to W, set it equal to zero, and solve for W:

d(Area)/dW = 34 - 4W = 0

Solving for W, we get:

W = 8.5

Substituting this value of W back into the equation L + 2W = 34, we get:

L + 2(8.5) = 34

L + 17 = 34

L = 17

Therefore, the dimensions of the kennel are 17 feet by 8.5 feet.

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