Answer:
10+51+17=78
Step-by-step explanation:
Alright, so at first I just took a random number and kept on working it out until I got the exact answer as 78. Finally, i got the third number as 17. Now, i know the third number is 7 more than the first so I have to subtract 17 and 7, 17-7=10. So the first number is 10. Ok, now i know that the second number is 3 times the third number (17) so you should multiply, 17x3=51. 51 is the 2nd number.
1st number=10
2nd number=51
3rd number=17
Add them, 10+51+17=78.
Answer:
First number = 10Second number = 51Third number = 17Step-by-step explanation:
In the question we are given ,
Sum of three numbers is 78Third no. is 7 more than firstSecond no. is 3 times thirdSo , we are assuming that ,
Let first no. be xThird no. be x + 7 ( because in question it is given that third number is 7 more than the first number ) .Second no. be 3 ( x + 7 ) ( because in the question it is given that second no. is three times the third )We are finding the solution by adding all these term and equating it with 78 because sum of these three numbers is equal to 78 .
Here we go ,
[tex] \longrightarrow \: x + 3(x + 7) + x + 7 = 78[/tex]
Step 1 : Solving the bracket part :
[tex] \longrightarrow \: \blue{x }+ \blue{ 3x} + \red{21} + \blue{ x} + \red{7 }= 78[/tex]
Step 2 : Adding like terms :
[tex] \longrightarrow \:5x + 28 = 78[/tex]
Step 3 : Transposing 28 to right hand side :
[tex] \longrightarrow \:5x = \green{78} - \green{28}[/tex]
Step 4 : Subtracting 28 from 78 :
[tex] \longrightarrow \:5x = 50[/tex]
Step 5 : Transposing 5 to right hand side :
[tex] \longrightarrow \:x = \cancel \frac{50}{5} [/tex]
Step 6 ; Cancelling 50 with 5 :
[tex] \longrightarrow \: \purple{\boxed{x = 10}}[/tex]
Therefore value of ,
x [ first number ] = 103(x + 7 ) [ second number ] = 51x + 7 [ third number ] = 17Verification :
We are verifying our answer by adding the three numbers and it must be equal to 78 .
10 + 51 + 17 = 7861 + 17 = 7878 = 78L.H.S = R.H.SHence , Verified.Therefore , our answer is correct .
#Keep Learning15. Which three lengths could be the lengths of the sides of a triangle?
Step-by-step explanation:
11 cm, 6 cm, 17 cm
Answer::
11cm, 6cm, 17cm
step by step explanation:
the correct answer is 11cm 6cm and 17cm
because in a right angled triangle, the square of the hypothenus is equal to the square of the sum of the other two sides
hypothenus= 17cm other two sides=11cm and 6cm
If the percent of discount of an item is 25 percent and the sale price is $40 what is the original price
Answer:
$53.33
Step-by-step explanation:
40/1 - .25
40/.75 = $53.33
Can cubic units measure temperature?
Answer:
No because Temperature is measured in Kelvins
Step-by-step explanation:
Need help with khan geometry no link pls just answer
Angles ABC and CBD are complementary - they add up to 90°. This means
(4x + 52°) + (8x - 10°) = 90°
Solve for x :
12x + 42° = 90°
12x = 48°
x = 4°
It follows that angle CBD has measure
4 • 4° + 52° = 16° + 52° = 68°
What’s the area of the circle?
r= 4m
Answer:
50.3
Set A to the value of pi times the radius squared.
[tex]4^2 = 4 * 4 = 16\\\\A = \pi *r^2(4^2) = 50.26548245...[/tex]
Find the total balance of each investment account earning simple annual interest. A: $624 at 5% for 3 years
$93. 60
B: $4,120 at 7% for 18 months
$432. 60
C: $900 at 3. 1% for 6 months
D: $275 at 4. 8% for 8 years
$105. 60
Answer:
the answer is A because if the interest is equal to 624×5×3÷100 which would give us 93.60
but for the rest the when you solve it you won't get the same answer below it
a fishing tackle box is 13 inches long 6 inches wide and 2 1/2 inches high. what is the volume of the tackle box
Answer:
195 cubic inches
Step-by-step explanation:
A fishing tackle box is 13 inches long, 6 inches wide, and inches high. What is the volume of the tackle box? SOLUTION: The volume of the tackle box is 195 cubic inches.
What is the circumference of the following circle? or r=5
Answer: [tex]C=31.4[/tex]
Step-by-step explanation: When you are finding the circumference of a circle you use the formula
[tex]C=2\pi r[/tex]
[tex]C=2*3.14 *5[/tex]
[tex]C=31.4[/tex]
what is x if 1/4x = 9?
Answer:
x is 36
Step-by-step explanation:
the way to find out is 1/4 multiplied by what gives you 9. 9 divided by 1/4 is 36. 36 1/4's gives you 9.
Answer: 2
Step-by-step explanation:first u subtract 1-9=8then u divide 4/8=2 tell me if wrong
The mean of 4, 10, 3, 6, a, 9 and 10 is 7, find the value
of a
Answer:
The value of a is 7.
Step-by-step explanation:
To calculate mean, add all of the numbers in the set and divide by the number of terms in said set. There are 7 numbers in this set, so the equation can be set up as follows.
(4 + 10 + 3 + 6 + a + 9 + 10)/7 = 7
Simplify the terms on the top.
(42 + a)/7 = 7
Multiply both sides by 7.
42 + a = 49
Subtract both sides by 42.
a = 7.
Proof:
(4 + 10 + 3 + 6 + a + 9 + 10)/7 = 7
Substitute variable.
(4 + 10 + 3 + 6 + 7 + 9 + 10)/7 = 7
Add in the parenthesis.
49/7 = 7
Divide.
7 = 7.
Two angles are supplementary. The larger angle is 15 more than 10 times the smaller angle. FInd the measure of each angle.
[tex]\text{Larger angle} =x\\\\\text{Smaller angle} =y\\ \\\text{According to the condition,}\\\\x=10y+15\\\\\text{The two angles are supplementary, so their sum is}~ 180^{\circ} \\\\x+y=180\\\\\implies 10y+15 +y = 180\\\\\implies 11y = 180-15\\\\\implies 11y=165\\\\\implies y = \dfrac{165}{11}\\\\\implies y = 15\\\\\text{So,} ~x =180-15 = 165\\\\\text{Hence the larger angle is}~ 165^{\circ}~ \text{and the smaller angle is }15^{\circ}[/tex]
Twelve identical cylindrical pop cans are placed in a box. If sand fills the space between the pop cans and the cans and the sides of the box, what volume of sand is needed?
Answer:
Step-by-step explanation:
I don't see any information on dimensions of the cans or box, so I'll assume the question wants a general solution.
Three steps will result in the volume of sand required to fill the remaining space in the box.
1. Calculate the volume of a can using the equation for the volume of a cylinder: Vol = πr²h
2. Multiply the can volume by 12. This will give the total volume of the 12 cans in the box.
3. Calculate the volume of the box: Volume = (Base)(Width)(Height)
[Make sure the units are the same as those used in calculating the can volume. E.g., if the can is calculated with cm as the measue, the box dimensions must also be cm]
4. Subtract the volume of the12 cans (from step 2) from the volume of the box.
The result from 4 will be the volume of sand required to fill the box containing 12 cans.
I'm not clear why filling the box with sand is important, but perhaps it will absorb any soda released from cans broken when the heavy box is dropped by the person shocked that 12 cans of pop could be so heavy.
PLS I really need this a have 40 questions due tomorrow :( (please help anyone) 16 points
Please help! Easy for everyone but me for some reason.
What's the value of x? Show your work.
Answer:
x = 9
Step-by-step explanation:
using Pythagoras' identity in the right triangle
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
x² + 6² = ([tex]\sqrt{117}[/tex] )²
x² + 36 = 117 ( subtract 36 from both sides )
x² = 81 ( take square root of both sides )
x = [tex]\sqrt{81}[/tex] = 9
Helpppp I will mark brainliest
Problem 25
Point P has the x coordinate x = -5, while point Z has the x coordinate x = 5. This is a distance of 10 units on the number line. Segment PZ is 10 units long which is the base of the triangle.
The height of the triangle is 8 units because it's the vertical distance from R to segment PZ. Notice we go from x = 4 to x = -4. The base and height are always perpendicular to one another.
Area = (base*height)/2
Area = (10*8)/2
Area = 80/2
Area = 40
Answer: 40 square units==========================================================
Problem 26
I'm not sure about this one because the instructions mention a grid, but I don't see any grid lines here. I'm not sure if the grid lines are just really faint or if your teacher forgot to put them in.
Using the tree diagram below, what is the probability of getting tails and an even number?
hi the awnser us defiantly going to be that I 56
Step-by-step explanation:
edge
The sum of 5 times a number and 7 equals 8
Answer:
0.2
Step-by-step explanation:
the sum of 5 times 0.2 and 7 equals 8
The shorter leg of a right triangle has a measure of x + 5. The longer leg is one less than three times the length of the shorter leg. The hypotenuse is thirteen more than two times the shorter leg. The area of the triangle, A, is 2.5 times the magnitude of the perimeter.
Create a system of equations to model the situation above. Determine if there are any solutions, and, if possible, whether or not they are viable.
How many total possible solutions of the form (x, A) are there for this situation?
How many total viable solutions of the form (x, A) are there for this situation?
Answer:
Given:
[tex]\textsf{Shorter leg}=(x+5)[/tex][tex]\textsf{Longer leg}=3(x+5)-1[/tex][tex]\textsf{Hypotenuse}=2(x+5)+13[/tex][tex]\sf A=2.5P\quad \textsf{(where A is area and P is perimeter)}[/tex][tex]\begin{aligned} \textsf{Perimeter} & =\textsf{shorter leg + longer leg + hypotenuse}\\ & = (x+5)+[3(x+5)-1]+[2(x+5)+13]\\ & = x+5+3x+15-1+2x+10+13\\ & = 6x+42\end{aligned}[/tex]
[tex]\begin{aligned} \textsf{Area} & =\dfrac12\textsf{(shorter leg)(longer leg)}\\ & =\dfrac12(x+5)[3(x+5)-1]}\\ & =\dfrac12(x+5)(3x+14)\\ & = \dfrac12(3x^2+29x+70)\\ & = \dfrac32x^2+\dfrac{29}{2}x+35 \end{aligned}[/tex]
[tex]\begin{aligned} \textsf{Area} & =2.5 \sf (Perimeter)\\ \implies \dfrac32x^2+\dfrac{29}{2}x+35 & =\dfrac52(6x+42)\\ 3x^2+29x+70 & =5(6x+42)\\ 3x^2+29x+70 & =30x+210\\ 3x^2 -x-140 & =0\\ 3x^2-21x+20x-140 & =0\\ 3x(x-7)+20(x-7) &=0\\ (x-7)(3x+20)& =0\end{aligned}[/tex]
Therefore:
[tex](x-7)=0 \implies x=7[/tex]
[tex](3x+20)=0 \implies x=-\dfrac{20}{3}[/tex]
[tex]x=-\dfrac{20}{3}[/tex] is not a viable solution as when inputting this into the formula for the shorter leg, it gives a negative value:
[tex]\textsf{Shorter leg}=-\dfrac{20}{3}+5=-\dfrac53[/tex]
As distance cannot be negative, this is not a viable solution.
When x = 7:
[tex]\textsf{Shorter leg}=7+5=12[/tex]
[tex]\textsf{Longer leg}=3(7+5)-1=35[/tex]
[tex]\textsf{Hypotenuse}=2(x+5)+13=37[/tex]
[tex]\textsf{Perimeter}=6(7)+42=84[/tex]
[tex]\textsf{Area} & =\dfrac32(7)^2+\dfrac{29}{2}(7)+35=210[/tex]
Therefore, there is one viable solution. This solution in the form (x, A) is (7, 210)
x2 +9 x- 22,
Which graph shows the solution set of
20?
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Answer...
Ok done. Thank to me >:3
which is equivalent to 12
5x?
A. -12x + 5
B.
-5x + 12
C.
5.x 12
• D. 12x 5
Answer:
-5x+12
Step-by-step explanation:
12 -5x
We can use the communitive property of addition to change the order.
The minus sign stays with the 5x
-5x+12
From first principle, find the derivative of y=2x^3+x²+4x with respect to X
Answer:
[tex]derivative \: of \: y = 6 {x}^{2} + 2x + 4[/tex]
Step-by-step explanation:
we know that
[tex] \frac{d}{dx} {x}^{n} = n {x}^{n - 1} [/tex]
Now the derivative of y=2x³+x²+4x
[tex] \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} + {x}^{2} + 4x)[/tex]
[tex] \frac{dy}{dx} = \frac{d}{dx} (2 {x}^{3} ) + \frac{d}{dx}( {x}^{2} ) + \frac{d}{dx} (4x)[/tex]
[tex]\frac{dy}{dx} = 2(\frac{d}{dx} {x}^{3} ) + \frac{d}{dx} {x}^{2} + 4(\frac{d}{dx} x)[/tex]
here
[tex]\frac{d}{dx} {x}^{3} = 3 {x}^{2} [/tex]
[tex]\frac{d}{dx} {x}^{2} = 2x[/tex]
[tex]\frac{d}{dx} x = 1[/tex]
Now
[tex]\frac{dy}{dx} = 2(3 {x}^{2} ) + 2x + 4(1)[/tex]
[tex]\frac{dy}{dx} = 6 {x}^{2} + 2x + 4[/tex]
I hope it helped you
pls help what is the circumstance of a circle with a diameter of 8 feet? Use 3.14 for n
Answer:
D. 25.12 feet
Step-by-step explanation: C= r(pi)^2
Point P is located at (4, 6) on a coordinate plane. Point P will be reflected over the x-
axis. What will be the coordinates of the image of point P? What transformation was
performed on the given figure
1. (8,4)
2. (4-6)
3. (4,28)
4. (24,4)
Answer:
2.
Step-by-step explanation:
it's the reciprocal
so it's gonna reflect
What is the percent of increase from 26 to 91?
Answer:
250
Step-by-step explanation:
How to solve 3x - 1/2 = 8 1/2 please no links and do it step by step
Answer:
[tex]x=\frac{3}{2}[/tex]
Step-by-step explanation:
Step 1. Put each term in [tex]3x-\frac{1}{2}[/tex] over the common denominator 2.
[tex]\frac{6x}{2}-\frac{1}{2}[/tex]
Therefore we have [tex](\frac{6x}{2}-\frac{1}{2})=4[/tex]
Step 2.
Combine [tex]\frac{6x}{2}-\frac{1}{2}[/tex] into a single fraction.
[tex]\frac{6x-1}{2}[/tex]
Therefore we have [tex](\frac{1}{2}(6x-1))=4[/tex] or [tex]\frac{6x-1}{2}=4[/tex]
Step 3.
Multiply both sides by a constant to simplify the equation.
Multiply both sides of [tex]\frac{6x-1}{2}=4[/tex] by 2:
[tex]\frac{2*(6x-1)}{2}=4*2[/tex]
Step 4.
Cancel the common terms in the numerator and denominator of [tex]\frac{2*(6x-1)}{2}[/tex]
Then we get [tex]\frac{2}{2}*(6x-1)[/tex] which simplifies to [tex](6x-1)[/tex]
So all together we have [tex](6x-1)=2*4[/tex]
Step 5.
Multiply 2 and 4 together and remove the parenthesis.
[tex]6x-1=8[/tex]
Step 6.
Isolate terms with the variable x to the left hand side.
So add 1 to both sides:
[tex]6x+(1-1)=8+1[/tex]
Evaluate [tex]1-1=0[/tex] which cancels out
Step 7.
Add the like terms on the right side:
[tex]6x=9[/tex]
Step 8.
Divide both sides by a constant to simplify the equation.
Divide both sides of [tex]6x=9[/tex] by 6.
[tex]\frac{6x}{6} =\frac{9}{6}[/tex]
Any non-zero number divided by itself is 1.
[tex]x=\frac{9}{6}[/tex] which simplifies to [tex]x=\frac{3}{2}[/tex]
A right triangle has leg lengths of 9 units and 12 units. Write an equation that can be
used to determine the length of the hypotenuse, c .
The Pythagorean Theorem: [tex]a^2+b^2=c^2[/tex]
a and b are the two legs in a right trianglec is the hypotenuse (the longest side of a right triangle; opposite the 90° angle*keep in mind that this theorem applies only to right trianglesSolving the QuestionWe're given:
Legs = 9 units and 12 unitsHypotenuse = cPlug these measurements into the Pythagorean theorem:
[tex]a^2+b^2=c^2\\9^2+12^2=c^2[/tex]
⇒ Combine like terms:
[tex]81+144=c^2\\c^2=225[/tex]
Answer[tex]c^2=225[/tex]
What is the surface area
Answer:
144 is the surface area
Step-by-step explanation:
Multiply 5 x 8 for the 3 rectangles. You will get an answer of 40. 40 x 3 is 120. For the 2 triangles you multiply 6 x 4 divided by 2 times 2 which is 24 lol. 120 + 24 = 144.
Three points representing the corners of a rectangular garden are A (-7, 3), B (7, 3) and C (7, -3). How could you use the coordinate plane below to find the coordinates of the fourth corner, point D? What are the coordinates of the point?
Answer:
Point d's corrdinates are (-7, -3). You can use the coordinate grid to find it out by graphing the others first and then find the missing one based on the sides
Step-by-step explanation:
What is the area of a square enclosure that uses 320 meters of fencing?
Answer:
A = 6400 m²
Step-by-step explanation:
the sides s of a square are congruent , then
s = 320 ÷ 4 = 80 m
tahe area (A) of a square is calculated as
A = s² = 80² = 6400 m²
The required area of square, having side 80 meters, is 6400 square meters.
What is square ?A square is a quadrilateral with four equal sides and four equal angles that is a regular quadrilateral. The square's angles are at a straight angle or 90 degrees.
Given that,
The length of fencing enclosure a square = 320 meters,
Let the side of the square is a meter,
According to given condition, perimeter of square,
4a = 320
a = 80
Since, the area of square having side a, is a²
Area = a²
Area = (80²)
Area = 6400 square meters.
The area of square, having side 80, is 6400 square meters.
To learn more about Square on:
https://brainly.com/question/28776767
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(9×10^2)+(4×10^3)
give your anwser in standard form
Answer:
4.9 × [tex]10^3[/tex]
Step-by-step explanation:
Start by doing what is in the paranthesis from right to left.
[tex]9 * 10^2 = 900[/tex]
and
[tex]4 * 10^3 = 4000[/tex]
So if we add them we get:
[tex]900 + 4000 = 4900[/tex]
Now to put it into standard form we just put a decimal to the right of the first number and see how many times we need to move right in order to make the number. In this case it's 3 times so we tack on × [tex]10^3[/tex]
So our answer is:
[tex]4.9[/tex] × [tex]10^3[/tex]