The triangle below has an area of 10 units squared.

The discriminant of  quadratic equation 3x^2 + 2x + 1 =0 is -8

We know that the standard form of quadratic equation is ax^2 + bx + c = 0, with a ≠ 0

The discriminant of quadratic equation ax^2 + bx + c = 0 is:

D = b^2 - 4ac

Comparing given quadratic equation 3x^2 + 2x + 1 =0 with ax^2 +bx + c = 0 we get,

a = 3, b = 2 and c = 1

So, the discriminant of given equation would be,

D = b^2 - 4ac

D = 2^2 - 4(3)(1)

D = 4 - 12

D = -8

Therefore, the discriminant is D = -8

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The factor of the given expression is -1 and 5/2 first we try to solve given expression as a quadratic equation then we make 2 terms equal to 0.

first, try to understand what is the factor of a quadratic equation.

A number or algebraic expression that evenly divides another number or expression—i.e., leaves no remainder—is referred to as a factor in mathematics. As an illustration, 3 and 6 are factors of 12 because 12 3 = 4 and 12 6 = 2, respectively. 1, 2, 4, and 12 are the other components that make up 12.

The roots of a quadratic equation are known as a factor. This means if we put the value of x to factor then the quadratic equation will become zero.

2x^2 - 3x - 5 = 2x^2 - (5-2)x - 5

3 can be written as 5-2.

2x^2 - 5x + 2x - 5

x(2x - 5) +1(2x-5)

(2x - 5)(x + 1)

So the factors is 2x -  5 = 0 or x  + 1 = 0.

2x - 5 = 0  , x = 5/2.

x + 1 = 0 , x = -1.

Given question is  incomplete complete  question here:

Which of the following is a factor of 2x^2 - 3x - 5?

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To make the sum X 3x² x 1, you must add -5x³ -2x² -6x -7 to 5x³ 2x² 6x 7.

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

These expressions are represented with the help of unknown variables, constants and coefficients. The combination of these three (as terms) is said to be an expression. It is to be noted that, unlike the algebraic equation, an algebraic expression has no sides or equal to sign.

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Answer:

D. Rotate triangle P 90° counter clockwise about point K, and then reflect it across a horizontal line through point K

A triangle is a three-sided polygon and each of its interior angles must add up to 180°; so each angle can have at most 180°.

A triangle is a three-sided polygon with three interior angles. According to the mathematical rule known as the “sum of interior angles”, the sum of the three interior angles of any triangle must always equal 180 degrees. Therefore, if the three angles of a triangle are A, B, and C, then A + B + C = 180. Since the sum of the three angles must equal 180 degrees, it means that each angle can have at most 180 degrees; none of the angles can be greater than 180 degrees. In other words, the maximum possible value of the angles in a triangle is 180 degrees, so the triangle can have only 180 degrees in total.

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The real and complex solutions of the polynomial equation are 2,-3i and 3i

Polynomial is an expression consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and positive-integer powers of variables

The given polynomial is x³-2x²+9x-18

Factor out x² from  x³-2x² which becomes  x²(x-2)

Factor out 9 from 9x-18 which becomes 9(x-2)

x³-2x²+9x-18

x²(x-2)+9(x-2)

Factor out common term x-2

( x²+9)(x-2)=0

x²+9=0

x=-3i and 3i

x-2=0

x=2

Hence, the real and complex solutions of the polynomial equation are 2,-3i and 3i

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For triangle ACE, if BD ∥AE , then BA/CB = DE/CD is proved.

For given triangle ACE,

BD || AE                             ...............(Given)

∠4 ≅ ∠1 and ∠3 ≅ ∠2      ..............(Corresponding Angles Postulates)

ΔACE ~ ΔBCD                  .............(Angle-Angle Similarity Postulate)

CA/CB = CE/CD                ............(Definition of similar triangles)

CA = CB + BA, CE = CD + DE           ..........(Segment Addition Postulate)

(CB + BA)/CB = (CD + DE)/CD   ..........(Substitution Property of Equality)

CB/CB + BA/CB = CD/CD + DE/CD  .........(Addition of Fractions)

1 + BA/CB = 1 + DE/CD                  .............(Siplification of fractions)

BA/CB = DE/CD                   ...............(Subtraction Property of equality)

Hence proved.

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Answer:

Hello There!!

Step-by-step explanation:

The answer is=>b.Salary.

hope this helps,have a great day!!

~Pinky~

In the given question, the form of payment is salary.

When someone is paid a certain amount of money for his/her work on a daily, weekly, monthly, or yearly basis is called salary.

Given, I'm getting paid a sum of $42000 per year.

It is not a commission. Because, I'm not getting paid any form of compensation here.

The paid amount is fixed here. Therefore, it is not a wage.

It is not a pension. Because, I'm not getting paid after the retirement.

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The constant of proportionality is 9 and equation of the proportion.

is y= 10x.

If the ratio of one variable to the other is constant, then there is a proportional relationship between the two variables. If x and y are in a proportional relationship, then the ratio of y to x is the constant of proportionality.

Given:

As, we know using the Constant of Proportionality

y = kx

or,  k = y/x  where k is Constant of Proportionality.

Then, from the table we have

k = 90/9

k= 10

Thus, y = kx

or, y= 10x

Hence, the equation of the proportion is y= 10x.

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Inequalities are mathematical expressions involving the symbols >, <, ≥ and ≤. To ‘solve’ an inequality means to find a range, or ranges, of values that an unknown x can take and still satisfy the inequality.

Suppose we want to solve the inequality x + 3 > 2.

We can solve this by subtracting 3 from both sides:

x + 3 > 2

x > −1

So the solution is x > −1. This means that any value of x greater than −1 satisfies x + 3 > 2.

Inequalities can be represented on a number line such as that shown in the image attached below. The solid line shows the range of values that x can take. We put an open circle at −1 to show that although the solid line goes from −1, x cannot actually equal −1.

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An equation in which the highest power of the variable is 1 is known as a linear equation. It is also termed a one-degree equation.

There are two types of linear equations, linear equations in one variable and linear equations in two variables. The standard form of a linear equation in one variable is Ax + B = 0. Where x = variable, A = coefficient and B = constant.

The standard form of a linear equation in two variables is Ax + By = C. Here, x and y are variables, A and B are coefficients and C is a constant.

A linear equation is an algebraic equation where each term has an exponent of 1 and when this equation is graphed, it always formed in a straight line. That is why it is named a 'linear equation'.

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The general solution is [tex]$$y=c_3 e^x+c_4 e^{-x}+\frac{1}{2} x \sinh x \text {. }$$[/tex]

Consider the following differential equation: y'' − y = cosh x

The given differential equation in the operator form will be: (D^2-1)y=coshx

The auxiliary equation of the corresponding homogeneous equation will be:

m^2-1 = 0

=>m^2=1

=>m=+1,-1

So, the complementary function will be [tex]y_c=c_1 e^x+c_2 e^{-x}.\alpha[/tex]

Now, let [tex]y_1=e^x, y_2=e^{-x}.[/tex]

Compute the Wronskian determinant:

[tex]$$\begin{aligned}W\left(y_1, y_2\right) & =\left|\begin{array}{ll}y_1 & y_2 \\y_1^{\prime} & y_2^{\prime}\end{array}\right| \\& =\left|\begin{array}{ll}e^x & e^{-x} \\e^x & -e^{-x}\end{array}\right| \\& =-e^x e^{-x}-e^x e^{-x} \\& =-2\end{aligned}$$[/tex]

Since the given differential equation is already in the form [tex]$y^{\prime \prime}+P(x) y^{\prime}+Q(x) y=f(x)$[/tex] (that is, the coefficient of y'' is 1 ),

So identify:

f(x)=cosh x

Then, calculate the values of u_1' and u_2', using formulas as follows:

[tex]$$\begin{aligned}u_1^{\prime} & =-\frac{y_2 f(x)}{W} & u_2^{\prime} & =\frac{y_1 f(x)}{W} \\& =-\frac{e^{-x} \cdot \cosh x}{-2} & & =\frac{e^x \cdot \cosh x}{-2} \\& =\frac{e^{-x} \cdot\left(\frac{e^x+e^{-x}}{2}\right)}{2} & \text { and } & =-\frac{e^x \cdot\left(\frac{e^x+e^{-x}}{2}\right)}{2} \\& =\frac{1}{4}\left(1+e^{-2 x}\right) & & =-\frac{1}{4}\left(e^{2 x}+1\right)\end{aligned}$$[/tex]

Integrate on both sides of u_1' and u_2' with respect to ' x', to get:

[tex]$$u_1=\frac{x}{4}-\frac{e^{-2 x}}{8} \text { and } u_2=-\frac{x}{4}-\frac{e^{2 x}}{8} .$$[/tex]

So, the particular solution is,

[tex]$$\begin{aligned}y_p & =u_1 y_1+u_2 y_2 \\& =\left(\frac{x}{4}-\frac{e^{-2 x}}{8}\right) e^x+\left(-\frac{x}{4}-\frac{e^{2 x}}{8}\right) e^{-x} \\& =\frac{1}{4} x\left(e^x-e^{-x}\right)-\frac{1}{8}\left(e^{-x}+e^x\right) \\& =\frac{1}{2} x \sinh x-\frac{1}{8}\left(e^{-x}+e^x\right)\end{aligned}$$[/tex]

Thus, the general solution of the given differential equation is,

[tex]$$\begin{aligned}y & =y_c+y_p \\& =c_1 e^x+c_2 e^{-x}+\frac{1}{2} x \sinh x-\frac{1}{8} e^{-x}-\frac{1}{8} e^x \\& =\left(c_1-\frac{1}{8}\right) e^x+\left(c_2-\frac{1}{8}\right) e^{-x}+\frac{1}{2} x \sinh x \\& =c_3 e^x+c_4 e^{-x}+\frac{1}{2} x \sinh x\end{aligned}$$[/tex]

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The area of a polygon with the given vertices is calculated by adding the areas of the individual triangles that make up the polygon.

A polygon is a closed figure in a plane consisting of a set of straight line segments connected end-to-end. The sides of a polygon are all of equal length, and the angles between them are all of equal measure. Polygons are one of the most fundamental shapes in geometry. They include triangles, squares, rectangles, hexagons, and many more.

The area of triangle WXZ is calculated as (1/2) × |XW × ZY|,

where XW is the vector from W to X and ZY is the vector from Z to Y.

In this example,

XW = (3, -2) and ZY = (-2, -4).

Therefore, the area of triangle

WXZ is (1/2) ×|(3, -2) × (-2, -4)| = (1/2) × 14 = 7.

The area of triangle XYA is calculated similarly,

where XY = (2, 3) and YA = (-2, -4).

Therefore, the area of triangle

XYA is (1/2) ×|(2, 3) ×(-2, -4)| = (1/2)× (-14) = -7.

The area of the polygon is calculated by adding the areas of the individual triangles, which in this example is 7 + (-7) = 0. Therefore, the area of the polygon with the given vertices is 0.

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Answer:

the answer is a

and the correct answer is letter C

Step-by-step explanation:

I don't know that is the answer

Answer:

3/8 of 24 is 9

9 are sharpened so 24-9=15

15 pencils are not sharpened.

Answer:

  2x +3y = 15  or  y = -2/3x +5

Step-by-step explanation:

You want the equation of the line with y-intercept 5 and x-intercept 7.5.

The intercept form equation can be written ...

  x/a +y/b = 1

where 'a' is the x-intercept and 'b' is the y-intercept.

The given intercepts of a=7.5 and b=5 mean we can write the equation as ...

  x/7.5 +y/5 = 1

Multiplying by 15 gives the standard-form equation ...

  2x +3y = 15

Solving for y gives the slope-intercept equation ...

  y = -2/3x +5

Answer:

[tex]\implies x = 1 \quad or -6 \\\\\implies f(x) = -3x^2-15x + 18 [/tex]

Step-by-step explanation:

Given :-

And we need to find out the zeroes of the quadratic function and we need to express it in Standard form. T

Function :-

[tex]\implies f(x)= -3(x-1)(x+6) [/tex]

[tex]\implies f(x)=0 \\\\\implies -3(x-1)(x+6)=0 \\\\\implies (x - 1 )(x+6) = 0 \\\\\implies x = 1 \quad or \quad -6 [/tex]

Therefore the zeroes are 1 and -6 .

Expressing in Standard form :-

The standard form of a quadratic equation is ,

[tex]\implies ax^2+bx + c = 0 [/tex]

And that of a quadratic function is ,

[tex]\implies f(x) = ax^2+bx + c [/tex]

Simplifying the equation :-

[tex]\implies f(x)= -3(x-1)(x+6)\\\\\implies f(x) = (-3x +3)(x+6) \\\\\implies f(x) = -3x(x+6)+3(x+6)\\\\\implies f(x) = -3x^2 -18x +3x + 18\\\\\implies f(x) = -3x^2-15x + 18 [/tex]

Hence the Standard form of the equation is -3x² - 15x + 18 .

Answer: You're correct

Step-by-step explanation:

All values on the dice are < 7, so 6/6 are less.

6/6 simplifies to 1, so that is also correct.

6/6 = 1 = 100%

0/6 is incorrect.

Answer:

You are 100% correct so dw abt it!

Step-by-step explanation:

I'm sorry

Answer:

Step-by-step explanation:

The amount of john would save 2900 rs

14500*1/5=2900

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To find the percentage increase of the slave population from 1800 to 1860, we can use the following formula:

What does math's % mean?

In essence, percentages are fractions with a 100 as the denominator. We place the percent symbol (%) next to the number to indicate that the number is a percentage. For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on a test (75/100).

percentage increase = (new value - original value) / original value x 100

We know that in 1800 the slave population was 893,602 and in 1860 the slave population was 1,953,760. So we can plug in these values into the formula:

percentage increase = (1,953,760 - 893,602) / 893,602 x 100

percentage increase = (1,060,158) / 893,602 x 100

percentage increase = 1.1885 x 100

percentage increase = 118.85

So, the slave population increased by 118.85% from 1800 to 1860.

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Direct variation is represented by this situation and she earn $900

if she works 12 hours.

Direct variation describes a relationship whereby one measure directly affects the other when the first one changes. This is completely opposed by inverse variation. Learn the definitions of direct and inverse variations in this article, along with some instances that have been solved.

When x is not equal to 0, y = kx is the equation that describes the linear function known as direct variation. An equation of the form xy = k, where x is not equal to zero and k is a nonzero real number constant, describes the nonlinear function known as inverse variation.

5 hours  = earns $ 375

1 hours = 375/5 = earns $ 75

12 hours  = 75  12 = earns $ 900

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Answer:

y = -1

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - (-1) / 6 - (-4)

0

y = 0x + b

-1 = 0(-4) + b

-1 = 0 + b

-1 = b

The correct answer is that we cannot conclude that being able to read is beneficial for them as there can be various cause and effect relation.

A research is conducted to collect information about a specific topic for the purpose of study. A group of population is asked to fill a survey form or answer questions based on the research topic.

This data is collected and analyzed to get the required result.

Here, in this question kindergarten students are the population from whom data is collected . Here, the conclusion is that having the ability to read and write from before only doesn't means they will have academic intelligence later.

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Answer:

C

Step-by-step explanation:

Start with the vertex. It is the lowest point. It is located at (-2,4)

The axis of symmetry is always the x value when the parabola opens upward or down ward. This parabola opens upward so it is x = - 2.

The answer is C

Answer:

x = 0.16

Step-by-step explanation:

Step 3:

Solve the equation for  x  by finding  a ,  b , and  c  of the quadratic then applying the quadratic formula.

[tex]x = - \frac{11 - \sqrt{185} }{16}[/tex]

Then, evaluate for x:

x = 0.16259190... which is about,

x = 0.16

Answer:

D

Step-by-step explanation:

9^2 + 40^2 = 41^2

Answer:

Mizuki is here to help!

115200 [tex]ft^3[/tex] is the volume of the building.

Step-by-step explanation:

120 x 20 x 48 =

2400 x 48 =

115200