The volume of a cone is 36π in3

What is the volume of a cylinder with the same radius and height as this cone?

Answer:

The last option

Step-by-step explanation:

There are 42 species in the sample

the proportions are:

frogs = 18/42 = 3/7

lizards = 18/42 = 3/7

worms = 6/42 = 1/7

The number of frogs and lizards is the same and exceeds that of worms

The only option that meets these proportions is the last

Hope this helps

Answer:

h = 110°

Step-by-step explanation:

1) A pentagon has 5 sides that sum up to 540°. We know it is 540° because of this formula that is used to find the sum of the interior angles of any polygons. n is the number of sides.

= (n - 2) x 180

= (5 - 2) x 180

= 3 x 180

= 540°

2) We can now set up an equation.

70 + 100 + 120 + 140 + h = 540

430 + h = 540

h = 540 - 430

h = 110°

Answer:

All of it, ad 10%

Step-by-step explanation:

100% is all of it and 10% is 1/10 of it :]

Answer: So therefore your answer would be 7 3/4

Step-by-step explanation: Okay so sun's you are trying to increase the recipe by four times That means you need to do what the recipe calls for four times and times what the recipe calls for by four or how many times larger you want to make it. So first we would do 3/4 X 4 = 12/16 And then from there we need to simplify And for this I'm pretty for sure lol We are going to divide the top by three and then the bottom by four. So then it goes back to 3/4 and seven cups I'm pretty sure.

Answer:

T > 2.5

Explaination -

t > 2.5

t < 2.5

t > 0.4

t < 0.4

Here it is given that Gallegos burns 236 calories riding her bike each hour.

She wants to burn more than 590 calories riding her bike at the same rate.

Let the time required = t hours

So

236t > 590

⇒ t > 590/236

⇒ t > 2.5

Therefore, the answer is t > 2.5

Answer:

vertical

7x+x+20=180

8x=180-20

8x=160

x=160÷8

x=20°

Answer:

If you mean the base of the triange being 12 then the answer 24[tex]inch^{2}[/tex]

Step-by-step explanation:

[tex]A = \frac{h_{b}b }{2}[/tex]

so

[tex]A = \frac{(4) (12)}{2}[/tex]

=[tex]24inch^{2}[/tex]

Answer:

Step-by-step explanation:

The range = 2 = (greatest number in the set) - (lowest number in the set)

→ If we took x < 1 then the range would be 3 - x > 3 - 1 then 3 - x > 2 which is impossible ,therefore x could not be less than 1

→ If we took x > 3 then the range would be x - 1 > 3 - 1 then x - 1 > 2 which is impossible ,therefore x could not be higher than 3

1 ≤ x ≤ 3

then

x = 1 or x = 2 or x = 3

The table is a linear regression model, and the equation of the regression model is y = 0.24x + 0.77

See attachment for the required scatter plot

From the attached scatter plot, we can see that the points are almost on a straight line

Hence, the best model that fits the scatter plot is a linear model

Using a graphing calculator, we have the following calculation summary:

The regression equation is represented as:

y = bx + a

So, we have:

y = 0.23929x + 0.77143

Approximate

y = 0.24x + 0.77

Hence, the equation of the regression model is y = 0.24x + 0.77

Read more about regression models at:

https://brainly.com/question/13345245

#SPJ1

Answer:

annual = yearly

daily = everyday

so it's false

Step-by-step explanation:

daily compounding will pay more than yearly compounding because it happens daily.

it about it this way, some giving you interest daily versus yearly.

I hope these answer at least helps you

Good luck

Answer:

Answer: 4x+y=567, x+y=279, where x=96 and y=183.

Step-by-step explanation:

Answer:

21?

Step-by-step explanation:

just divide 105 by 5?

the full question wasn't here so I just guessed what u were trying to say

Given formula: [tex]\sf A_n= -4(2)^{n-1}[/tex]

simplify substitute the number of term by replacing n

Find first five terms:

[tex]\sf A_1= -4(2)^{1-1}[/tex]  ⇒  [tex]\sf A_1= -4[/tex]

[tex]\sf A_2= -4(2)^{2-1}[/tex]  ⇒  [tex]\sf A_2= -8[/tex]

[tex]\sf A_3= -4(2)^{3-1}[/tex]  ⇒  [tex]\sf A_3= -16[/tex]

[tex]\sf A_4= -4(2)^{4-1}[/tex]⇒  [tex]\sf A_4= -32[/tex]

[tex]\sf A_5= -4(2)^{5-1}[/tex]⇒  [tex]\sf A_5= -64[/tex]

Tenth term:

[tex]\sf A_{10}= -4(2)^{10-1}[/tex]   ⇒  [tex]\sf A_{10}= -2048[/tex]

Answer:

[tex]\sf a_1=-4\\a_2=-12\\a_3=-20\\a_4=-28\\a_5=-36\\a_{10}=-76[/tex]

Step-by-step explanation:

[tex]\textsf{Given sequence}: \sf a_n=-4(2n-1)[/tex]

This formula is for the nth term of the sequence.

Therefore, to find any term of the sequence, substitute the position of the term you wish to find as n.

For example, to find the 10th term, substitute n = 10 into the formula:

[tex]\begin{aligned}\sf a_{10} & =-4[2(10)-1)]\\ & = -4(20-1)\\ & = -4(19)\\ & = -76\end{aligned}[/tex]

To find the first 5 terms, substitute n = 1 through n = 5 into the formula:

[tex]\sf a_1=-4[2(1)-1]=-4(2-1)=-4(1)=-4[/tex]

[tex]\sf a_2=-4[2(2)-1]=-4(4-1)=-4(3)=-12[/tex]

[tex]\sf a_3=-4[2(3)-1]=-4(6-1)=-4(5)=-20[/tex]

[tex]\sf a_4=-4[2(4)-1]=-4(8-1)=-4(7)=-28[/tex]

[tex]\sf a_5=-4[2(5)-1]=-4(10-1)=-4(9)=-36[/tex]

Answer:

1 5/8 miles

Step-by-step explanation:

Min:

2+3=5, 3/8+1/8=4/8

5 4/8 miles

Jessica:

1+2=3, 5/8+2/8=7/8

3 7/8 miles

5 4/8- 3 7/8= 1 5/8 miles

Answer:

Equations II and IV

Step-by-step explanation:

See attached image.

Find the equation of the line in the form of y=mx+b, where m is the slope and b the y-intercept.  Pick any two points to calculate the Rise/Run, or slope, of the line, as shown.  The y-intercept, b, is the value of y when x=0.  Rearrange the resulting equation, as necessary, to see if it matches any of the options.  In option IV, I rearranged the answer, as it was easier to get it into the desired form of y=mx+b.

As shown, equations II and IV both match.

Answer:

The missing side length is 5.7

Step-by-step explanation:

Using the pythagoream theorem you can find the missing side length of a right triangle.

The formula is [tex]a^{2} + b^{2} = c^{2}[/tex] where a and b are the lengths of the triangle legs and c is the hypotenuse.

So yours would be:

[tex]7^{2} + x^{2} = 9^{2}[/tex]

Square the numbers:

[tex]49 + b^{2} = 81[/tex]

Isolate b:

[tex]b^{2} = 32[/tex]

Square root both sides:

[tex]b=\sqrt{32}[/tex]

Simplify:

[tex]\sqrt{32} = 5.7[/tex]

Answer And Step-by-step explanation:

1. b + 59 = 90

90 - 59 =b

⇒ b = 31

3. 29 + b = 90

90 - 29 = b

⇒ b = 61

5. 23 + b = 90

90 - 23 = b

⇒ b = 67

7. 32 + b = 90

90 - 32 = b

⇒ b = 58

18. 88 + b = 180

180 - 88 = 92

⇒ b = 92

20. 96 + b =180

180 - 96 = b

⇒ b = 84

22. 73 + b = 180

180 - 73 = b

⇒ b = 107

24. 91 + b = 180

180 - 91 = b

⇒ b = 89

Answer:

[tex]\cfrac{\left(x+8\right)\left(x-8\right)}{x^2+13}[/tex]

Step-by-step explanation:

[tex]\cfrac{x+8}{x+2}\cdot \cfrac{\left(x+2\right)\left(x-8\right)}{x^2+13}[/tex]

[tex]\cfrac{\left(x+8\right)\left(x+2\right)\left(x-8\right)}{\left(x+2\right)\left(x^2+13\right)}[/tex]

[tex]\cfrac{\left(x+8\right)\left(x-8\right)}{x^2+13}[/tex]

Answer:

A. (0,2) (4,2) (0,0)

b. (-2,0) (-2,-4) (0,0)

c. (0,2) (4,2) (0,0)

d. (0,2) (-4,2) (0,0)

These pointed are reflected into y-axis.

The drawing will take time to be drawn, that's why i only have written the points.

I hope my answer helps you.

Answer:

see below

Step-by-step explanation:

1.03  * x  = 92       x = prior percentage

92 / 1.03  = x = 89.32    

She HAD a 89.32 percentage score

   increasing this score   3%   reults in a score of 92

Answer:

2635.75 or 2635 3/4

used a calculator

Answer:

reggie made an error

the correct scale factor is 2/3

Step-by-step explanation:

we want to get from A to A', B to B', and ultimately C to C'

to get there, we must multiply each value in each point by the scale factor.

let's start out with reggie's scale factor. he multiplies each value in C by 3/2 to get to C'. we can try this out with one point, e.g. A

for A: 3/2 * (-12, -6) = (-18, -9). this is not A' = (-8, -4)! thus, 3/2 cannot be the scale factor

now, onto hillary's scale factor of 2/3

for A: 2/3 * (-12, -6) = (-8, -4). this is A'! thus, hillary is correct and reggie made an error

the correct scale factor is thus hillary's: 2/3

Answer:

70 - 5√10 ft²

Explanation:

Perimeter is the distance around a two-dimensional shape.

                       area of rectangle: length x width

Here given:

length: (3√2 + 4√5) ft

width: (-5√2 + 5√5) ft

Solve for perimeter:

length x width

(3√2 + 4√5) x (-5√2 + 5√5)

apply distributive method

(3√2)(-5√2) + (3√2)(5√5) + (4√5)(-5√2) + (4√5)(5√5)

multiply

-15(2) + 15√10 -20√10 + 20(5)

combine

-30 -5√10 + 100

simplify

70 - 5√10

[tex]y = \stackrel{\stackrel{m}{\downarrow }}{5}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

well, what's the equation of a line whose slope is 5 and passes through (-2 , -13) ?

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{-13})\qquad \qquad \stackrel{slope}{m}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-13)}=\stackrel{m}{5}(x-\stackrel{x_1}{(-2)})\implies y+13=5(x+2)[/tex]

Answer:

x=-19, y=-21

Step-by-step explanation:

[tex]\begin{bmatrix}x=y+2\\ 2y-3x=15\end{bmatrix}[/tex]

[tex]\mathrm{Substitute\:}x=y+2[/tex]

[tex]\begin{bmatrix}2y-3\left(y+2\right)=15\end{bmatrix}[/tex]

Simplify

[tex]\begin{bmatrix}-y-6=15\end{bmatrix}[/tex]

Isolate y for -y - 6 = 15: y = -21

[tex]\mathrm{For\:}x=y+2[/tex]

[tex]\mathrm{Substitute\:}y=-21[/tex]

[tex]x=-21+2[/tex]

Simplify

x=-19

[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]

[tex]x=-19,\:y=-21[/tex]

you can only solve this using simultaneouse solution. first, make x the subject in the second equation.2y-3x=15

In doing so x=-5+2/3y. You the multiply both equationby the co-efficient of x then you subtract the equations giving 1/3y=-7. hence y=-21.you then substitute the value for y into equation 1 where x=y+2 giving x=-19.

Answers A and B describe number 2

Answer:

A and B

Step-by-step explanation:

2 is a whole number (is not a fraction or decimal) and an integer is a positive or negative whole number, and irrational numbers never end or repeat.