the width of a rectangle is 2 m less than the length. if the area of the rectangle is 48sq meters. what is the length and width ​

Answer:

The slope is -2

Step-by-step explanation:

Use the slope formula to find the slope mm.

m = − 2m = - 2

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Answer:

Where's the picture?

Step-by-step explanation:

Can't see it.

Answer:

55

Step-by-step explanation:

IHG = 123

IHS = x + 65

SHG = x + 78

IHG = IHS + SHG

123 = x + 65 + x + 78

123 = 2x + 143

123 - 143 = 2x

-20 = 2x

-10 = x

IHS = x + 65

IHS = - 10 + 65

IHS = 55

Answer:

[tex]Range: \{2,4, 3, -9\}[/tex]

Step-by-step explanation:

Given

The ordered pairs

Required

The range of the function

The range of a function is represented as:

[tex]Range = \{y_1,y_2,y_3,,,y_n\}[/tex]

i.e. we only write out the y values.

So, the given ordered pairs can be represented as

[tex](x,y) = \{(1,2), (-3,4), (3, 3), (0, -9)\}[/tex]

So, we have:

[tex]Range= \{2,4, 3, -9\}[/tex]

Answer: A. U.S. Landmarks to European Landmarks

Maria has 25 U.S. landmark postcards and 20 European landmark postcards. The ratio of U.S. landmarks to European landmarks can be written as 25:20 or as 25/20.

Alternatively, we can express the ratio as a fraction. If we divide the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we get 25/(25+20)=25/45

The last way we can express the ratio as a decimal. By dividing the number of U.S. landmark postcards by the total number of U.S. and European landmark postcards, we can find that the ratio of U.S. landmarks to European landmarks is 25/45 =0.555 or 55.5%

Step-by-step explanation:

Answer:

(-2,5), refer to the step-by-step. Feel free to comment any questions you may have!

Step-by-step explanation:

Given the system of equation, [tex]\left \{ {{x+6y=28} \atop {2x-3y=-19}} \right.[/tex], solve by elimination.

[tex]\left \{ {{-2(x+6y=28)} \atop {2x-3y=-19}} \right.[/tex] , multiply the top equation by -2.

We get,  [tex]\left \{ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex]

[tex]+ {{-2x-12y=-56} \atop {2x-3y=-19}} \right.[/tex], add the equations together.

We get, [tex]-15y=75[/tex], we just eliminated the variable, x, we can now solve this equation for y.

[tex]-15y=-75 = > y=\frac{-75}{-15}[/tex], [tex]y=\frac{75}{15} = > y=5[/tex]

We just found the value y, which is y=5. Now we can take this value and plug it into y for either of the two original equations and solve for x. I will take the top equation...

[tex]x+6y=28 = > x+6(5)=28 = > x+30=28[/tex], subtract the value, 30, from both sides. We get, [tex]x=-2[/tex].

We found the value x, x=-2.

Thus the solution to the given system of equations is (-2,5).

Answer:

(-2, 5)

Step-by-step explanation:

Given linear system of equations:

[tex]\begin{cases}x+6y=28\\2x-3y=-19\end{cases}[/tex]

To solve by the method of elimination, first multiply the first equation by -2:

[tex]\implies -2 (x+6y=28)[/tex]

[tex]\implies -2x-12y=-56[/tex]

Add this to the second equation to eliminate the term in x:

[tex]\begin{array}{lrcrcr}& 2x & - & 3y & = & -19\\+\vphantom{\dfrac12}&(-2x & - & 12y & = & -56\\\cline{2-6}&\vphantom{\dfrac12}&- & 15y & = &-75\end{array}[/tex]

Solve the expression for y:

[tex]\implies -15y=-75[/tex]

[tex]\implies y=5[/tex]

Substitute the found value of y into the expression for x and solve for x:

[tex]\implies x=28-6(5)[/tex]

[tex]\implies x=28-30[/tex]

[tex]\implies x=-2[/tex]

Check by substituting the found values of x and y into both equations.

Equation 1

[tex]\implies -2+6(5)=-2+30=28[/tex]

Equation 2

[tex]\implies 2(-2)-3(5)=-4-15=-19[/tex]

Hence proving that the solution (-2, 5) is true.

The formula needed to transform a quadratic polynomial or equation into a perfect square with an additional constant is known as the square formula. It is expressed as, [tex]ax^2 + bx + c = a(x + m)^2 + n[/tex], where, m and n are real numbers.

When a square is complete, a quadratic is written in the shape of a squared bracket, and if necessary, a constant is added. A good example is [tex]x^2 + 6x + 7[/tex] . First, let's note that [tex](x + 3)^2 = (x + 3)(x + 3) = x^2 + 6x + 9. x[/tex]  because this is two more than our expression.

The polynomial equations of degree two in one variable of type[tex]f(x) = ax^2 + bx + c = 0[/tex] and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f(x).

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The slope of the relation is 1/4

You should know that slope is the rate of change of y with respect to x.  slope is denoted by change in y over change in x

The table of values is given as:

x −2 −1 0 1 2

y −13 −9 −5 −1 3

The slope is calculated as:

Slope = y₂ - y₁/x₂ - x₁

So, we have

Slope = 2 - 1/3 + 1

Evaluate the like terms

Slope = 1/4

In conclusion, the slope of the relation is 1/4

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Answer:

3 more students

Step-by-step explanation:

6-3=3

How did you get that?

6 students live 2 miles away, while only 3 students live 3 miles away. To find the difference, subtract the two numbers.

Answer:

The table with (-3, 2), (0, 2), etc.

Every input has exactly one output.

Hope this helps :)

Answer:

∠FDA

Step-by-step explanation:

Angle FDA is vertical to angle EDG.

Picture shows vertical angles.

Answer:

it is a subset

Step-by-step explanation:

since elementsof these set{5,8} can found in {2,5,8}

Answer:

170 + 156.33 + 9.38 + 98.42 + 52.54= 486.67

1,445.26 - 486.67= 958.59

Faith has $958.59 left.

-1 on the left x-axis and 4 on the right y-axis.

Start at -2 on the y-axis, move up the y-axis six times, and you should arrive at 4. However, you must identify the first line in order to complete the puzzle.

Start at -2 on the y-axis, count up until it is on a corner of the graph, then move 4 up on the y-axis and once to the right, making the fraction 4/1.

Since you should be at 4, apply the formula rise/run 4/1 to ascend 6 on the y-axis.

step 1: ascend the y-axis six times.

Step 2: Use 4/1 to increase from the y-4 axis's by 1  to the right

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Answer:

Isosceles right triangle

Step-by-step explanation:

Step-by-step explanation:

Isosceles Right Triangle

Answer:

Step-by-step explanation:use a calculator

Answer:

Step-by-step explanation:

-29.8+33.2=3.4

Answer:

2 she draws it they are not real

Answer:

The width of the park should be 7.5 feet.

a. The exact volume, in cubic inches, of water flowing out of the pipe every second is 32π cubic inches.

b. The height, in inches, of the water in the tank after 5 minutes is 600 feet.

c. It will take 0.132 minutes to fill 75% of the tank

A cylinder is a three-dimensional solid object with two bases that are identically circular and are connected by a curving surface that is located at a specific height from the center.

Examples of cylinders are toilet paper rolls and cold beverage cans.

The volume of a cylinder is πr²h.

Curved surface area = 2πrh.

Total surface area = 2πr(h + r).

Given, Water flows at 2 feet per second through a pipe with a diameter of 8 inches so it is a cylindrical shape.

Therefore, The exact volume, in cubic inches, of water flowing out of the pipe every second is,

= π(4)²×2.

= 32π cubic inches.

The volume of the cylindrical tank is,

= π(7.5)²×6.

= 337.5π cubic inches.

The height, in inches, of the water in the tank after 5 minutes would be

= (32π×300)/π×16).

= 600 feet.

Now, 75% of 337.5π cubic inches is (0.75×337.5π) = 253.125π cubic inches.

Therefore the time required to fill 75% of the tank is,

= [(253.125π/32π)]/60 minutes.

= 7.91/60 minutes.

= 0.132 minutes.

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Answer:

- 3/x-1

Step-by-step explanation:

Answer:

[tex]-\frac{3}{x-1}[/tex]

Step-by-step explanation:

Factor the denominator and then combine fractions:

[tex]\frac{3}{(x-1)(x-2)} -\frac{3}{x-2}[/tex]

Find LCM (Least Common Multiple) of denominators:

LCM of (x-1)(x-2) and x-2 is (x-1)(x-2)

Adjust fractions based on LCM:

[tex]\frac{3}{(x-1)(x-2)} -\frac{3(x-1)}{(x-2)(x-1)}[/tex]

Denominators are now equal so you can subtract the fractions:

[tex]\frac{3-3(x-1)}{(x-1)(x-2)}[/tex]

Factor the numerator:

[tex]\frac{3(-x+2)}{(x-1)(x-2)}[/tex]

Cancel:

[tex]-\frac{3}{x-1}[/tex]

Answer:

[tex] \frac{1}{12} [/tex]

Step-by-step explanation:

Coin has 2 outcomes dice has 6 outcomes

A tail is 1/2 and a 3 is 1/6

So a tail and a 3 is 1/2 x 1/6

=1/12

Answer:

what's the question?

Step-by-step explanation:

Answer:

x = 71

Step-by-step explanation:

180 - 109 = 71

Answer:

844.5 calories.

Step-by-step explanation:

If a physically active adult weighing 170 pounds needs to consume about 2815 calories per day in order to maintain his or her weight, and a nutritionist recommends that no more than 30% of those calories should come from simple sugars, the maximum number of calories per day that should come from simple sugars is:

2815 calories * 30% = <<281530.01=844.5>>844.5 calories

So, the maximum number of calories per day that should come from simple sugars is 844.5 calories.

Answer

844.5

Step-by-step explanation:

80+100=180

180÷100=1.80

1.80×2815=844.5

Answer:

2 1/2 or 2.5

Step-by-step explanation:

I believe it's 1 1/2

Step-by-step explanation:

I think it's either 1/6 or 1/2

Hello there!

Answer:

16

Step-by-step explanation:

[tex] |x| = x \: \: \: if \: \: x \: \geqslant 0 \\ |x| = - x \: \: \: if \: \: \: x \: \leqslant 0[/tex]

-12 < 0 so |-12| = -(-12) = 12

4 > 0 so |4| = 4

|-12| + |4| = 12 + 4 = 16

Answer:

16

Step-by-step explanation:

Hello! This question is looking for the absolute value of integers. The absolute value is the distance the number has from zero. For example, -12 as twelve numbers away from zero, twelve away in the negative direction. The absolute value of -12, then, is just twelve. An easy way to remember this is to take away the negative sign when taking the absolute value, since an absolute value can never be negative. The absolute value sign is represented by a squarish bracket [ and ].

This question says to find the absolute value of each integer and then add the two. First we have [-12]. This is 12 away from zero, and we can take away the - sign from the asked integer and we get 12.

The second integer given is 4, and when we take the absolute value of 4, [+4], we get positive four. This is because four is four spaces away from zero on the number line.

Thus, we have +12 and +4 as are values to add since they are the absolute values and we can form this equation

12+4=16

Thus, the answer is 16.

Hope this helps! Remember the hint, when something has brackets like that or asks for the absolute value, take away a negative sign and make it positive! Have a great day!

Answer:

The answer is B

I hope you got it right!!!