There are 12 girls and 8 boys in Ms. Crabapple's class. If 25% of the girls and 25% of the boys are going on a field trip to a nuclear power plant, what percent of the entire class is going on the field trip?

Answers

Answer 1

Answer:

25%

Step-by-step explanation:

25% of 12 is 3

25% of 8 is 2

5 people out of 20 people

5/20 = 25%

Answer 2

25% percent of the entire class is going on the field trip

What is Percentage?

percentage, a relative value indicating hundredth parts of any quantity.

Given,

There are 12 girls and 8 boys in Ms. Crabapple's class.

The total number of students

12+8=20

25% of the girls and 25% of the boys are going on a field trip to a nuclear power plant,

25% of the girls =0.25×12=3

25% of the boys =0.25×8=2

So the total number of students went to field trip

3+2=5

So out of 20 student, 5 students went to the field trip.

Which means 25% of the entire class is going on the field trip

Hence, 25% percent of the entire class is going on the field trip

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Related Questions

find the point (x,y) on the curve where dy/dx = 0

Answers

a. By the chain rule,

[tex]\dfrac{dy}{dx} = \dfrac{dy}{dt}\cdot\dfrac{dt}{dx} = \dfrac{dy}{dt}\cdot\dfrac{1}{\frac{dx}{dt}}[/tex]

Given that [tex]y=e^t+e^{-t}[/tex] and [tex]x=e^{-t}[/tex], we have the derivatives

[tex]\dfrac{dy}{dt} = e^t -e^{-t}[/tex]

[tex]\dfrac{dx}{dt} = -e^{-t}[/tex]

and so

[tex]\dfrac{dy}{dx} = \dfrac{e^t - e^{-t}}{-e^{-t}} = 1-e^{2t}[/tex]

Set this equal to zero and solve for t :

[tex]1-e^{2t} = 0[/tex]

[tex]1 = e^{2t}[/tex]

[tex]\ln(1) = \ln\left(e^{2t}\right)[/tex]

[tex]0 = 2t \ln(e)[/tex]

[tex]0 = 2t[/tex]

[tex]t=0[/tex]

This value of t corresponds to x = e⁰ = 1 and y = e⁰ - 1/e⁰ = 1 - 1 = 0. So the only point on the curve where the derivative dy/dx is zero is (1, 0).

b. Compute the second derivative. Since dy/dx is a function of t, we'll momentarily replace it with f(t). By the chain rule,

[tex]\dfrac{d^2}{dx^2} = \dfrac d{dx} \dfrac{dy}{dx} = \dfrac{df}{dx} = \dfrac{df}{dt}\cdot\dfrac{dt}{dx} = \dfrac{df}{dt}\cdot\dfrac{1}{\frac{dx}{dt}}[/tex]

We have

[tex]\dfrac{df}{dt} = -2e^{2t}[/tex]

and we've already committed dx/dt. So

[tex]\dfrac{d^2}{dx^2} = \dfrac{-2e^{2t}}{-e^{-t}} = 2e^{3t} [/tex]

Substitute the first and second derivative into the differential equation:

[tex]\left(\dfrac{d^2y}{dx^2}\right)^2 + \dfrac{dy}{dx} - 1 = 0[/tex]

[tex]\left(2e^{3t}\right)^2 + (1-e^{2t}) - 1 = 0[/tex]

[tex]4e^{6t} -e^{2t}= 0[/tex]

[tex]e^{2t} (4e^{4t} - 1) = 0[/tex]

[tex]4e^{4t} - 1 = 0[/tex]

[tex]4e^{4t} = 1[/tex]

[tex]e^{4t} = \dfrac14[/tex]

[tex]\ln\left(e^{4t}\right) = \ln\left( \dfrac14\right)[/tex]

[tex]4t \ln(e) = -\ln(4)[/tex]

[tex]4t = -\ln(4)[/tex]

[tex]t = -\dfrac{\ln(4)}4[/tex]

Multiply (4-5i)(4+i)

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Answer:

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Answers

9514 1404 393

Answer:

  (b)  62°

Step-by-step explanation:

Let x represent the measure of the angle.

The complement is (90 -x).

The supplement is (180 -x).

The relationship between the supplement and the complement is ...

  (180 -x) = 6 +4(90 -x)

  180 -x = 6 +360 -4x

  3x = 186

  x = 62

The measure of the angle is 62°.

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Answer:

1.)

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

☆Answer :

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Answers

Can you give me some hint please

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2y = 70 -8x
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2) 2y = 8x -70
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Answers

Answer: 12

2 + 10

12

:)

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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I hope this helps! :)

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answers

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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