three scientists measure the standard meter bar kept at the international bureau of standards (the definition of a meter). their measurements are 1.01 m, 0.99 m, and 1.00 m. are their measurements accurate, precise, or both? group of answer choices accurate but not precise neither accurate nor precise precise by not accurate accurate and precise

The correct options are B and C

Let us assume the amplitude of the two sinusoidal waves to be A1 and A2

Since, it is mentioned that the waves are identical, therefore let us assume A1=A2= a

The resultant wave of any two waves is given by the formula:

Resultant wave , R = [tex]\sqrt{A1^2+A2^2+2A1A2cos\alpha }[/tex]

where A1 and A2 are amplitudes of wave 1 and 2 and [tex]\alpha[/tex] is the angle between the waves

Now as per the formula, it is the the factor 2cos[tex]\alpha[/tex] that will decide that amplitude is greater than original or not

Hence we know that maximum value of cos [tex]\alpha[/tex] is when [tex]\alpha[/tex] is 0 degrees

Now it is known that value of cos[tex]\alpha[/tex] varies from 1 to 0 for o degrees to π/2

and the value varies from 0 to -1 for angle π/2 to π angle

Case 1: when [tex]\alpha[/tex]=0 degree

           Resultant wave R = [tex]\sqrt{A1^2+A2^2+2cos0A1A2}= \sqrt{2A^2+2A^2}=\sqrt{4A^2} =2A[/tex]

Case 2: When [tex]\alpha[/tex] is less than 90

let us consider [tex]\alpha = 45 degree[/tex]

 Resultant wave R =

[tex]\sqrt{A1^2+A2^2+2cos45A1A2}= \sqrt{2A^2+2A^2/2}=\sqrt{3A^2} =\sqrt{3} A[/tex]

case 3:

When [tex]\alpha[/tex] is less than 120

[tex]\sqrt{A1^2+A2^2+2cos120A1A2}= \sqrt{2A^2-2A^2/2}=A[/tex]

case 4: when [tex]\alpha[/tex] is less than 180 degrees

the value will be 0

Hence only option b and d are correct

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The distance at which the sound level is 100 dB is 30m.

Distance is a measurement of how far apart two objects or locations are. Distance in physics or common language can refer to a physical length or an estimate based on other factors (e.g. "two counties over"). |AB| is a symbol that can be used to represent the distance between two points. "Distance from A to B" and "Distance from B to A" are frequently used interchangeably. A distance function or metric is a technique to describe what it means for elements of some space to be "close to" or "far away" from each other in mathematics. It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and other social sciences.

Explanation:

We anticipate the radial distance to be 10 times greater, or 30 m, when the intensity is reduced by 20 dB, or by a factor of 102. A further 90 dB reduction might translate to an additional factor of 104.5 in terms of distance, or roughly 3030000m or 1000 miles. We measure sound intensity using the inverse square law and the decibel scale definition. According to the sound level definition,

β=10log[tex](\frac{1}{10^{-12}W/m^{2} } )[/tex]

We can compute the intensities corresponding to each of the levels mentioned as

[tex]I=[10^{\frac{\beta }{10} } ]10^{-12} W/m^{2}[/tex]

a. The power passing through any sphere around the source is

P=4π[tex]r^{2}[/tex]l

If we ignore absoption of sound by the medium,

conservation of energy requires that

[tex]r_{120} ^{2} I_{120} = r_{100}^{2} I_{100} =r_{10} ^{2} I_{10}[/tex]

then,[tex]r_{100} =r_{120} \sqrt{x} \frac{I_{120} }{I_{100} } =(3.00m)\sqrt{\frac{1\frac{W}{m^{2} } }{10^{-2}\frac{W}{m^{2} } } } =30 m[/tex]

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The work required to pump all the water over the top of the tank of radius 5 m and depth 2 m is 5.12 x 10^6 J.

The work required to pump the water over the top of the tank is equal to the gravitational potential energy of the water inside the tank.

The potential energy is given by the following equation,

U= mgh

Here, m is the mass of water present inside the tank.

We know that, Density( Mass/Volume

Hence, m= Density x volume

So, the equation becomes

U= ρ x V x g x h

Where V is the volume of hemispherical tank= 2/3π x r^3

Putting the given values in the above equation,

U= 1000 x 2/3 x 3.14 x 53 x 9.8 x 2 = 5.12 x 10^6 J

Hence, the work required to pump all the water over the top of a tank of radius 5 m and a depth of 2 m is 5.12 x 10^6 J.

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The Magnitude of force on the charged particle is -

F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k

We have a positively charged particle that moves through a region where both a uniform magnetic field and a uniform electric field exist.

We have to determine the total force on the moving particle.

The force exerted on a charged particle (q) moving with velocity (v) through an Electric field (E) and Magnetic field (B) is called Lorentz force. Mathematically -

|F| = qE + qv x B

According to the question, we have -

q = 3.20 × 10⁻¹⁹C

v = (2i + 3j - k) m/s

B = (2i + 4j + k) T

E = (4i - j - 2k) V

Now, using the formula to calculate Lorentz force -

F = q(4i - j - 2k) + q(2i + 3j - k) x (2i + 4j + k)

F = q(4i - j - 2k) + (2qi + 3qj - qk) x ((2i + 4j + k)

F = q(4i - j - 2k) + 0

F = q(4i - j - 2k)

F = (12.8 x 10⁻¹⁹C)i - (3.2 x 10⁻¹⁹C)j - (6.4 x 10⁻¹⁹C)k

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Answer:

i think a or b is the answer

Explanation:

i also don't know exactly

At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.

As a result, the manatee now becomes negatively buoyant and must rise to compensate.

When something has neutral buoyancy, it is not affected by the weight of anything above or below it.

This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.

Examples of things with neutral buoyancy include air balloons and swimming caps.

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(ii) The net displacement at a point on the string where the pulses cross is 0.2 m.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the ends are free.

There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.

Now, since A = 0.1 m

Then, 2A = 2(0.1) = 0.2 m

As a result, the net displacement at the string's intersection of two pulses is 0.2 m.

The correct option is (c).

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The frictional force is 11 N and the block’s acceleration is 0.14 m/s².

It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction, the lower the friction between the surfaces, and the higher coefficient of friction the higher the friction force between them.

For part (a):

Taking x component:

F(x) = F cosθ

Taking y component:

F(y) = -F sinθ

Applying Newton’s second law to the y-axis:

F(N) = 15 sin40 + (3.5)(9.8)

F(N) = 44 N

coefficient U = 0.25

f(k) = 11 N

For part (b):

Applying Newton’s second law to the x-axis:

a = ((15) cos40 - 11)/3.5

a = 0.14 m/s²

Thus, the frictional force is 11 N and the block’s acceleration is 0.14 m/s².

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The car given in the question is not traveling at a constant speed as the time interval in which it to cover the equal distance is not equal.

Speed is the physical quantity that measures the rate at which the position of a body is changing with respect to its surrounding. Its S.I. unit is meters per second. And its dimensional equation is [[tex]LT^{-1}[/tex]]

Given in the Question

Time to travel first meter =  5 seconds

Time to travel second meter =  8 seconds

The body is said to be moving with a constant speed if it travels an equal distance in equal intervals of time.

But in the above-given condition, the car travels 1m in 5 seconds but travels the next 1m in 8 seconds. Here the distance traveled is equal but the time interval in which both distances are covered is not equal.

Therefore, the car is not traveling at a constant speed.

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Answer:

YOUR ANSWER IS HERE....

The velocity of the horse as it travels through the track is 20 m/s.

Velocity can be defined as the ratio of distance or displacement to time.

To calculate the velocity of the the horse, we use the  formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the velocity of the horse as it travels through the track is 20 m/s.

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Answer:

A. 2s

Explanation:

time = distance ÷ speed

T = .2 ÷.1

T= 2

The magnitude of the electric field is 0 N/C.

We choose a Gaussian sphere of radius r > R concentric with the solid sphere.

Apply Gauss's law from Equation (1):

[tex]\Phi_{E} = \oint E\cdot dA = \frac{q_{in}}{\in_{0} }[/tex]

Since the electric field vector E is parallel to the area vector dA of the curved part the dot product can be the simple product EdA:

                                 [tex]\oint E\cdot dA = \frac{q_{in}}{\in_{0} }[/tex]

since the electric field is constant we can put E out of the integral:

                                [tex]E \oint dA = \frac{q_{in}}{\in_{0} }[/tex]

                                    [tex]EA = \frac{q_{in}}{\in_{0} }[/tex]

Substitute for A from Equation (2) and for [tex]q_{in}[/tex] from Equation (3)

recognizing that the enclosed charge by the Gaussian sphere is less than Q:

                              [tex]E(4\pi r^{2}) = \frac{pVgaussian}{\in_{0} }[/tex]

Substitute for V gaussian (volume of the Gaussian surface) from Equation (4):

                                          [tex]E(4\pi r^{2}) = \frac{\rho (\frac{4}{3} \pie r^{2})} {\in_{0} }[/tex]

                                           [tex]E = \frac{\rho r}{3\in_{0} }[/tex]

Where p is the charge per unit volume of the solid sphere which is equal to the total charge Q of the sphere divided by the volume V of the sphere :

                             [tex]E = \frac{(\frac{Q}{V} )r}{3\in_{0} }[/tex]

                                [tex]E = \frac{Qr}{(\frac{4}{3} \pi R^{3})3\in_{0} }[/tex]

                                [tex]E = \frac{Qr}{4\pi \in_{0}R^{3} }[/tex]

Substitute numerical values:

                                                  [tex]E = \frac{(26\times10^{-6})(0)}{4\pi(8.8542 \times10^{-12})(0.4)^{3}}[/tex]

                                 [tex]E = 0 N/C[/tex]

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The Big Bang Theory is an example of the universe originated from the explosion and expansion of all matter and energy

The Big Bang Theory is the way that astronomers explain how the universe began as a tiny, dense, fireball that exploded 13.8 billion years ago. It includes Albert Einstein's general theory of relativity along with standard theories of fundamental particles.

The theory was born of the statement that other galaxies are moving away from our own at countless speed in all directions, as if they had all been forced by an ancient explosive force.

The solar system is the gravitationally bound system of the sun, the objects that orbit it or travel around the sun. It consists of an average star (sun), the planets (Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune and Pluto) and their moons, dwarf planets and countless asteroids, comets, and other small icy objects.

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The number of molecules in the given volume is 5.33 x 10⁻¹² moles.

The number of molecules of the gas is calculated as follows;

PV = nRT

n = PV/RT

where;

1 torr = 133 Pa

1 x 10⁻¹⁰ torr =  ?

= 1.33 x 10⁻⁸ Pa

n = (1.33 x 10⁻⁸ x 1) / (8.314 x 300)

n = 5.33 x 10⁻¹² moles

Thus, the number of molecules in the given volume is 5.33 x 10⁻¹² moles.

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The content of matter in a body is called mass. Weight can be defined as the amount of force required to accelerate an object with mass, while volume is the space occupied by the mass.

On comparing with 1-kg block of solid iron, a 2-kg block of solid iron, mass is different for both the blocks.

So (a) mass cannot be the correct option.

According to this formula ,[tex]Density = \frac{Mass}{Volume}[/tex] , Density for both the blocks would be same, so volume will be different for both the blocks because of the different masses.

So (b) Volume cannot be the correct option.

Weight is mass dependent therefore

(c) weight cannot be the correct option

Since (a), (b), (c), are incorrect so (d) can not be the correct answer

Therefore on Comparing a 1-kg block of solid iron, with a 2-kg block of solid iron, (e) none of these would be same.

Correct option is (e)

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Answer:

The straight down arrow

Explanation:

Next time add a picture to also help those who would like to answer. :)

The acceleration of Mr. Henderson Porsche is 54545.45 mi/hr².

Velocity is the directional speed of an object, body, or particle in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

We know that acceleration of a body is Change in Velocity per unit time.

[tex]a=\frac{v-u}{t}[/tex]

Here ,

v is the Final Velocity,

u is the Initial Velocity and;

t is the time taken.

In the given question ,

The Porsche accelerated from 0 to 60 miles per hour in four seconds.

u = 0 mi/hr

v = 60 mi/hr

t = 4 sec

[tex]t=\frac{4}{3600}{~}hr\\[/tex]

[tex]t=\frac{1}{900} {~}hr[/tex]

t  = 0.0011 hr

Then,

[tex]a=\frac{v-u}{t}[/tex]

[tex]a=\frac{60-0}{0.0011}[/tex]

[tex]a=54545.45 {~}mi/hr^{2}[/tex]

Hence, the acceleration of the Porsche is 54545.45 mi/hr².

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Ricardo came up with the three different paper airplane designs. Ricardo plans to fly each paper airplane five times to see which design flies the furthest. Ricardo should calculate the aircraft's flight distance after each flight and record it.

Two of the most popular methods in agricultural surveying involve taking measurements of angles and distances with simple equipment. even when the equipment is simple. A high level of precision can be reached with perseverance and practice.

The primary method for measuring distance is (1) pace. The mileage counter. (3) taping or chaining four phases and (6) methods for electronic distance measurement, optical range finders (EDM).

It will be helpful to first examine the common units of distance (displacement). Common English units are as follows:

A foot is made up of 12 inches (in)

Yd (yard) equals 3 ft (ft)

The length of one rod is 16.5 feet and 5.5 yards (yd)

5280 feet, 1760 yards, and 320 rods make up a mile.

The units cancellation method is very helpful when converting between different units of measurement.

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(i) The largest mass will be of the object B.

(ii) The smallest mass will be of the object C.

(iii) The ratio of the mass of object A and b will be 3:5.

According to the Newton’s 2 law for the same force applied acceleration and mass will be in the inverse ratio .it means the more the acceleration the less will be the mass of the object for the same force applied. As the acceleration of the object B is less so its mass will be more and vice versa. And the ratio of the masses will be the inverse ratio of the acceleration of object.

Hence, the ratio will become inverse ratio of acceleration of both the object that is 3:5.

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The currents in the wires are in opposite directions.

If this flowing through the wire are in same direction then they the wire attract each other and if this flowing through the wire are opposite in direction then they the wire repel each other .

As it is given that a pair of wires repel each {other} which suggests that current inside the wires area unit in other means .

Hence current flowing through wires area unit opposite in direction.

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Answer: I don't know the right answer but it makes more sense for it to be balanced  

Explanation:

When an emission line of helium from a galaxy is shifted toward red, it means that the galaxy is moving away from the viewer and is denoted as option D.

This refers to the systems of stars and interstellar matter that make up the universe which are gravitationally bound together and are made up of four main components which are:

When an emission line of helium from a galaxy is shifted toward red, there is a displacement to a longer wavelengths and this alteration is referred to as a doppler shift.

Moving away from the view means that the galaxy will be viewed in the red spectrum of the visible light which is a part of the electromagnetic spectrum.

This is therefore the reason why option D was chosen as the most appropriate choice.

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The man moves across the ice with a velocity of -1 m/s.

Formula:

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Given:

After applying the law of linear momentum, we get the following value before the throw;

M₁ = Man's initial mass= 80kg,

U₁ = Initial velocity of Man = 0,

M₂= Initial mass of Book  = 4kg,

U₂= Initial velocity of Book = 0.

After the throw, the book's velocity will be

M₁ = Man final mass = 80kg,

V₁ = Man's final velocity = V.

M₂ = Final mass of Book = 4kg,

V₂ = Final velocity of Book = 20 m/s

After substituting the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)

Or, 0 = 80V + 80

Or, 80V = -80

Or, V = -80/80

V= -1m/s

[Note: The -ve sign shows the opposite direction]

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Answer:

48.9 m/s

Explanation:

I am ignoring air resistance in this:

horizontal velocity stays constant, so we need to find vertical velocity

v_0y = 0 m/s, t = 1.23s, a = 9.81 m/s^2 <- (g)

v_y = v_0y + at = 0 + 9.81 * 1.23 = 12.066 m/s

the magnitude v = sqrt(v_x ^ 2 + v_y ^2) = sqrt(47.4^2 + 12.066^2) = 48.9m/s

Answer:

V = 49.2 m/s

Explanation:

Given:

Vₓ  = 47.4 m/s

t = 1.23 s

___________

V - ?

Vy =  Voy + g·t = 0 + 9.8·1.23  ≈ 12,1 m/s

V = √( (Vx)² + (Vy)² ) = √ ( 47,7² + 12,1²) = 49.2 m/s

Answer: The diaphragm

Explanation:

The diaphragm is a thin dome-shaped muscle which separates the thoracic cavity (lungs and heart) from the abdominal cavity (intestines, stomach, liver, etc.)

The expansion of both will be the same. Then the correct option is C.

Thermal expansion, which often excludes phase transitions, is the propensity of matter to alter its form, area, volume, and concentration in response to a variation in heat.

The same metal is used to create two identically sized spheres, but only one is solid and the other is hollow. The same rate of warming is applied to the spheres.

The formula for the thermal expansion is given as,

[tex]\rm \alpha _L = \dfrac{1}{L} \cdot \dfrac{dL}{dT}[/tex]

[tex]\alpha_{L}[/tex] = thermal expansion

L = particular length measurement

dL = change in length

dT = change in temperature

If the material of the sphere is the same, then the coefficient of the expansion of the sphere is the same, then the expansion of both will be the same.

Both will expand at the same rate. Then, C is the right answer.

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The electric field on the axis of the uniformly charged ring at the center of the ring at 5.00cm is 2.41×〖10〗^7 N/C

Where a positive charge (q) is given, always note that the charges point away from the electric field. The expression used to calculate the electric field away from the center of the ring is given by the equation below,

E=(K_e×b)/(r^3×Q)

Where

E is Electric field

Ke is electric field constant

a  is radius of the charge q from the center of the circle

Q is electric charge = 75.0μC

The radius of the charge is a = 10cm= 0.1m

Distance from the electric field = 5cm = 0.05m

Ke is a constant given as  8.99×〖10〗^(9  ) Nm^2/c^2

E=(8.99×〖10〗^(9  ) Nm^2/c^2×0.05)/(〖0.1〗^3×75×〖10〗^(-6) )

E=2.41×〖10〗^7N/C

Therefore, the electric field away from the center of the ring is 2.41×〖10〗^7N/C away from the center of the ring

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The thing that happens when you push or pull a water tube is that the force makes the tube to speed up, slow down, or be in one place.

It is very hard when pulling  water and if a person need to consistently pull air out of the tube before water makes it to the pump, it is very  difficult and some pumps may or cannot do it.

In regards to pushing, when a person is pushing above the Center of Gravity, one is pushing the said object into the ground and thus is increasing the rate of friction.

If a person is pulling you are said to be pulling above the Center of Gravity and lowering friction.

So, The thing that happens when you push or pull a water tube is that the force makes the tube to speed up, slow down, or be in one place.

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The car’s velocity when it passed the checkpoint was of: 60 m/s

The formula and procedure we will use to solve this exercise is:

vi = [(2 *x)/ t] - vf

Where:

Information about the problem:

Applying the initial velocity formula we have:

vi = [(2 *x)/ t] - vf

vi = [(2 * 225m)/5 s ] - 30 m/s

vi = [(450 m)/5 s ] - 30 m/s

vi = 90 m/s - 30 m/s

vi = 60 m/s

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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the change in kinetic energy of the car is None of these

perfectly inelastic collision - It is the physical process. Of one object which strike against another without conserving the kinetic energy of to object.

m₁ = 1,500 kg  (mass of car)

v₁ =  4.00m/s     (velocity of car)

m₂= 50000kg    (mass of truck)

v₂ = 1.80m/s       (velocity of truck)

for perfectly elastic collision

[tex]v_{f}[/tex]=?

[tex]m_{1} .v_{1,i} + m_{2} .v_{2,i} =( m_{1} + m_{2} ).v_{f}[/tex]

1500*4 + 50000*1.80

= (1500 + 50000) [tex]v_{f}[/tex]

[tex]v_{f}[/tex] = 1.864 m/s

Initial kinetic energy is

K.E (i) = [tex]\frac{1}{2} m_{1} .v_{1,i} ^{2} + \frac{1}{2} m_{2} .v_{2,i}^{2}[/tex]

[tex]\frac{1}{2}[/tex]× [(1500*4²) +(50000)*(1.8)²

= 93000J

Final kinetic energy is  

K.E = [tex]\frac{1}{2}(m_{1} +m_{2} )v_{f}^{2}[/tex]

[tex]\frac{1}{2}[/tex]× ((1500+50000)*(1.864 )²

= 89476 J

Change in kinetic Energy

K.E = K.E (f) -  K.E (i)  

 = 89476 -93000

= -3524 J

the change in kinetic energy of the car is None of these

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