To understand electrical currents we need to understand

In order to hit the target, the archer should aim the arrow so that it follows a parabolic trajectory.

The archer should aim the arrow slightly higher than the target, so that the arrow will arc downward and reach the target. Additionally, the archer should take into account other factors such as wind speed and direction, as these can affect the trajectory of the arrow.

The parabolic trajectory is a curve created when an object is thrown or shot in the air at an angle, then follows the path of a parabola. The parabolic trajectory allows for the object to travel in an arc and reach a certain distance, such as a target.

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Answer:

-3.2m

Explanation:

To find the distance of the 25N weight from the pivot, we can use the concept of moments. The moment of a force is the product of the force and the perpendicular distance from the pivot to the line of action of the force.

The total moment about the pivot due to the weights on side A is:

Moment_A = (10N * 4m) + (30N * 2m) = 80Nm

The moment of the 25N weight on side B must be equal and opposite to the total moment of the weights on side A, so we can set up the following equation:

Moment_B = -80Nm

We can solve for the distance of the 25N weight from the pivot by rearranging the equation to solve for x:

x = Moment_B / 25N = -80Nm / 25N = -3.2m

So the distance of the 25N weight from the pivot is -3.2m. This means that the weight is 3.2m to the left of the pivot, since the pivot is taken as the origin for the purpose of calculating moments.

Answer:

See explanation

Explanation:

The question is incomplete, as the required parameters are missing. The general solution to this is as follows;

First, get the mass (m) and the acceleration (a) of the sled

So, the force (f) to stop the sled is:

[tex]f = ma[/tex] ---- Newton 2nd law

However, the force to stop the sled will be in the opposite direction of the sled.

So:

[tex]f =-ma[/tex]

Assume that:

[tex]m \to 5kg[/tex]

[tex]a \to 6m/s^2[/tex]

The required force is:

[tex]f =-ma[/tex]

[tex]f =-5kg * 6m/s^2[/tex]

[tex]f = -30N[/tex]

The required work applied to a 1000 kg car when it is pushed 1000 m up along a 10- degree incline at a constant velocity is calculated to be 4.6 × 10⁶ J.

Given that,

Mass m = 1000 kg

Displacement d = Δx = 1000 m

Angle of inclination θ = 10°

Coefficient of friction μ = 0.3

The equation for work done is known to be,

W = F × d

We must divide the force of gravity into its component parts and examine the side acting in the x-direction in order to calculate the force of gravity in that direction.

F gx direction = F g sinθ = mg sinθ

The force of friction is directly related to  μ times the normal force.  The normal force in this situation is equivalent to the y component of the force of gravity.

F gy direction = F g cosθ = mg cosθ

We know force of friction, Ff = μ FN

FN = F gy direction

Ff = μ mg cosθ

We know that our force applied must balance both of these forces,

F applied = mg sinθ + μ mg cosθ

As, W = F × d = (mg sinθ + μ mg cosθ) d = ( 1000× 9.8 sin10° + 0.3 × 1000× 9.8 cos10°) 1000 = (9800 sin10° + 2940 cos10°) 1000 = (0.17 × 9800 + 0.985 × 2940) 1000 = (1666 + 2895.9) 1000 = 4561.9 × 10³ J = 4.6 × 10⁶ J

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Answer:

 In places of hot climate, it is advised that the outer walls of house be painted white because white color does not absorb any heat radiation from the sun which keep inside cool even if there is hot climate outside the house.

The statement is false. The capacitor doesn't charge Q exponentially decays to zero when the RELAY is thrown to position N.O.

As a capacitor charges, its voltage also rise.

V = Q/C

where Q = charge, V = voltage and C = capacitance

If the circuit contains a battery, a resistor and a capacitor all connected in series, then the following are true.

The battery voltage is fixed. And the capacitor voltage is rising. This clearly means that the current through the resistor is dropping.

I = (Vbatt - Vcap)/R

Since the current is dropping, then the rate at which charge is deposited on one plate and removed from the other one continuously drops.

So the charging of the capacitor also slows down because of the rising voltage.

But here the rise in the voltage is slowing down because of the rate of charges that are accumulating and leaving continuously is slowing down.

The slower rise in voltage causes a further slowing in the rate of charge movement which further slows down the rise in voltage which causes an even slower rate of charge movement.

A capacitor is referred as an electrical device which stores electrical charge when it is connected across the source of potential difference.

The total charge that the capacitor can be stored when it is placed across a potential V is given by

Q=CV

where C is the capacitance of the capacitor.

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Answer:

30 m/s

Explanation:

Answer:

The speed is equal to Distance divided by Time.

The SI Unit of Speed is m/s or meters per second.

V = S/T

= 750/25

= 30 m/s

The total change in momentum of the mass is calculated to be 80.16 kg m/s.

Given that,

Force F = 10 N

Mass m = 6 kg

Time t = 8 sec

"Newton's second law states that F = m a."

Making 'a' as subject,

a = F/m = 10/6 = 1.67 m/s²

From the equations of motion, let us calculate velocity.

v = u + a t

v = 0 + 1.67 × 8 = 13.36 m/s

Δp = m(v - u) = 6 × ( 13.36 - 0) = 80.16 kg m/s

Thus, the change of momentum is 80.16 kg m/s.

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According to the question, the sofa and carpet have a static friction coefficient of 10.519.

Static friction is defined as a force that maintains an object at rest. when someone tries to move a stationary thing across a platform without actually moving their body or the platform they were moving the object across, they face resistance.

Given:

Wight of sofa = 117 kg

Force= 109N

weight = mass × acceleration due to gravity 117 × 9.8 = 1146.6

the mass is given in kilograms, but work in newtons, thus we multiplied the mass by 9.8

acceleration = Zero

force = resistance

substitute force with 109N and resistance with 1146.6× μ

109 = 1146.6 × μ

μ = 1146.6/109

μ = 10.519

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Answer:

all of the above are correct

Torque increases with distance because torque is defined as the force acting on an object multiplied by the distance from the axis of rotation. The farther the force is applied from the axis of rotation, the greater the torque will be.

To understand this, imagine a lever with a weight on the end of it. If the weight is placed closer to the pivot point of the lever, it will take less force to lift the weight than if the weight is placed farther away from the pivot point. This is because the farther the weight is from the pivot point, the greater the torque will be. The same is true for any object that is being rotated around an axis - the farther the force is applied from the axis of rotation, the greater the torque will be.

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Answer: B

Explanation:

Free fall -> constant acceleration of g = 9.81ms-1

Constant acceleration -> velocity increases at a constant rate (increases proportionally with time)

Math behind it:

* Velocity is the integration of acceleration, likewise acceleration is the differentiation of velocity. Integrating a constant value gives linearly increasing function in terms of x. (integrating with respect to x)

Hence, graph B shows the trend that velocity increases at a constant rate.

Graph A - Velocity decreases linearly

Graph C - Also decreases nonlinearly

Graph D - Not possible scenario. Velocity approaches infinity.

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

We have

[tex]a = \frac{6}{12} = \frac{1}{2} = 0.5 \\ [/tex]

We have the final answer as

Hope this helps you

True: In newton's second law, F = ma, the mass m is a gravitational mass.

What is Newton's second law?

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In equation form this can be written as F = ma, where F is the net force applied,

m is the mass of the object, and a is the acceleration of the object. This law explains that the larger the force applied, the greater the acceleration of the object.

Also, the larger the mass of the object, the lower the acceleration when the same force is applied to the object.

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Electric force is the attraction or repelling force that exists between any two charged objects. Newton's laws of motion, which apply to all forces, describe how a force acts and what it does to the target body.

Mutual interactions between two charges produce electrical forces. When there are three or more charges present, the cumulative effects of each charge's interactions with the other charges produce the electric force acting on a single charge.

2.40 x 1043 times more powerful than the gravitational force is the electric force between these electrons. Or, to put it another way, gravity is only about a trillion trillion trillion trillion times as strong as electricity.

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Answer:

9/10

Explanation:

The force of gravity between two objects is equal to their respective masses multiplied by two. If one of the items triples in mass, the gravitational pull between them will also triple.

The force of gravity between two objects is multiplied by two when their masses are each doubled, and so on. Since an object's kinetic energy is exactly proportional to its mass, it will double along with the object's mass. The force of gravity between two objects is equal to their respective masses multiplied by two. If one of the items triples in mass, the gravitational pull between them will also triple.

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The time taken can be calculated by the equation: t = -RC ln(15/50)

To determine how long after closing the switch s the potential across each capacitor will be reduced to 15.0 V, we need to know the initial potential across the capacitors, the capacitance value and the resistance in the circuit.

When a switch is closed, the potential across a capacitor decreases exponentially with time according to the equation:

V(t) = V0e^(-t/RC)

Where V0 is the initial potential across the capacitor, t is time, R is the resistance in the circuit, and C is the capacitance.

In this case, the initial potential across each capacitor is 50.0 V, and the resistance in the circuit is 80 ohms.

To find the capacitance value we need to know that the capacitors are parallely connected, which means that the total capacitance is the sum of the individual capacitances:

Ctotal = C1 + C2

Once we have the capacitance value, we can find the time constant RC:

RC = R / Ctotal

Now we can use the equation above to find the time it takes for the potential to decay to a certain percentage of the initial value.

For example, if we want to find the time it takes for the potential to decay to 15.0 V (30% of the initial value), we can use the following equation:

15.0 V = 50.0 Ve^(-t/RC)

and we can solve for t:

t = -RC ln(15/50)

It's worth noting that this is an estimation and that in real world situations the resistance and capacitance values are also affected by other factors such as leakage current or parasitic capacitances.

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Answer:

since, Pressure=Force/Area

then,Area=Force/Pressure

or,Area=20000/1000

:.Area=20 m²

The magnitude of the net force on the object is 8 N. This is because the force of gravity, which is 17 N, is being opposed by the force of air resistance, which is 9 N. Therefore, the net force is 17 N - 9 N = 8 N.

Force is a push or pull on an object that is caused by an interaction between two objects. It has both magnitude, which is the strength of the interaction, and direction, which is the direction in which the force is being applied.

Net force is the sum of all the forces acting on an object. It is calculated by adding up all the forces that are acting on the object, taking into account their directions. This can be used to calculate the acceleration of an object, as the greater the net force, the greater the acceleration.

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Answer:

wool

Explanation:

Wool comes from sheep.  Rayon, candles (the paraffin type) and petrochemicals all come from petroleum.

Answer:

A)    E = 1 N * d = 1 Newton-Meter = 1 Joule

P(ower) = E / t = 1 N-m / t = 1 Joule / sec = 1 W

The cables and machinery used to transport electric energy from the supplying utility to the wiring system of the premises served are referred to as "service" in the NEC. The Service Point is the location where the customer's premises wiring starts and the utility supply terminates.

Drop in service. between the service point and the utility's electrical supply infrastructure, the overhead conductors.

Service conductors are the wires that run from the service point to the method of terminating the service (service equipment, not meter). For both above (service drop) and subterranean, service conductors would include service-entrance conductors (service lateral).

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Answer:

a. Thus, the tension in the cord causes no change in angular momentum.

b. 0.112 N

c. -0.048 J

Explanation:

a) Explain if the tension force causes the change of angular momentum.

A centripetal force F initially acts on the block to keep at at a radius of 0.5 m and speed of 0.9 m/s.

When the cord is pulled, the tension causes a change in the centripetal force to a new value at a radius of 0.23 m.

But since the force is applied in the radial direction and not perpendicular to the radius, there is no torque applied (since torque τ = rFsinθ and θ = 0 thus τ = rFsin0 = 0)and thus, there is tangential acceleration α (since α = τ/I where I = rotational inertia of block)and thus no change in angular speed ω (since α = Δω/Δt, α = 0 ⇒ Δω/Δt ⇒ Δω = 0).

Since there is a no change in angular speed, there is thus no change in angular momentum.

Thus, the tension in the cord causes no change in angular momentum.

b) What is the tension in the cord in the final situation when the block moving in a circle with smaller radius.

The centripetal force in the cord is equal to the tension at the smaller radius.

We find the angular speed of the block from v = rω where v = initial tangential speed of block at r = 0.5 m = 0.9 m/s and r = 0.5 m.

So, ω = v/r = 0.9 m/s ÷ 0.5 m = 1.8 rad/s

The centripetal force at radius r = 0.23 m is F = mrω² where m = mass of block = 0.150 kg, r = distance = 0.23 m and ω = angular speed = 1.8 rad/s

So, F = 0.150 kg × 0.23 m × (1.8 rad/s)²

F = 0.150 kg × 0.23 m × 3.24 rad²/s²

F = 0.11178 kgmrad²/s²

F ≅ 0.112 N

c) How much work was done by the person who pulled on the cord

From work-kinetic energy principles, the work done by the tension equals the kinetic energy change of the block.

ΔK = W

1/2m(v₂² - v₁²) = W where m = mass of block = 0.150 kg, v₁ = initial speed of block = 0.9 m/s, v₂ = final speed of block distance r = 0.23 m,

Since the tangential speed v ∝ r the radial distance,

v₂/v₁ = r₂/r₁

v₂ = (r₂/r₁)v₁

= 0.23 m × 0.9 m/s ÷ 0.5m

= 0.207 m²/s ÷ 0.5 m

= 0.414 m/s

So, W = 1/2m(v₂² - v₁²)

W = 1/2 × 0.150 kg((0.414 m/s)² - (0.9 m/s)²)

W = 1/2 × 0.150 kg((0.1714 m/s)² - (0.81 m/s)²)

W = 1/2 × 0.150 kg((-0.6386 m²/s²)

W = 1/2 × -0.09579 kgm²/s²)

W = -0.0479 kgm²/s²

W = -0.0479 J

W ≅ -0.048 J

Answer: [tex]2520[/tex]¢

Explanation:

Given

Company charges [tex]10[/tex]¢ per cubic inch

The dimension of the box is [tex]9\ in.\times 7\ in.\times 4\ in.[/tex]

The volume of the box is

[tex]V=9\times 7\times 4\\V=252\ in.^3[/tex]

Therefore cost associated with it is

[tex]\Rightarrow C=10\times 252\\\Rightarrow C=2520[/tex]

Thus, the cost is [tex]2520[/tex]¢.

Answer:

25.20

Explanation:

The velocity of an object can change even if the speed of the object remains constant.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

In physics, an object's initial position is its starting point for motion, and its final position is where it comes to rest.

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The potential difference,  acting over a distance of 2.5 cm is 1.4*10^-12V.

The potential actually grows as you get farther away from the charge, becoming less negative as you get closer to it and eventually reaching zero. The potential for both positive and negative charges is zero at infinite distances from the charge.

The energy that a body has because of its location or deformation is known as potential energy. Both the body's bulk and the height to which it is lifted play a role.

Given:

Distance (d) = 2.5cm = 0.025 m

For an electron,

[tex]m= 9.109*10^-31kg[/tex]

[tex]q=1.602*10^-19C[/tex]

We isolate the electric field:

[tex]E=\frac{mg}{q}[/tex]

[tex]g=9.8 m/s^2[/tex]

[tex]E=\frac{(9.109*10^-31kg)(9.8m/s^2)}{1.602*`10^-19C}[/tex]

[tex]E=5.5723*10^-11V/m[/tex]

Electric potential,

[tex]E=\frac{V}{d}[/tex]

[tex]V=Ed[/tex]

[tex]V= (5.5723*10^-11V/m)(0.025m)[/tex]

[tex]V=1.4*10^-12V[/tex]

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A mole sample of an ideal gas is gently cooled at constant temperature 320 K.

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Answer:

Work = Work out

Work in = 5 N * d     where d is the distance the handle travels

Work out = 50 N * 7 m = 350 Joules

d = 50 N * 7m / 5 N = 70 m

This is the distance traveled by the force of 5 N

A man lifts a bucket of water from a well that is 7 meters deep. The bucket and water together weigh 50 Newtons. He turns the crank handle with a force of 5 Newtons. The effort force is 70 Newtons.

If a force is applied for a machine to move or change the position of the object is known as Effort force.

The effort force formula can be described as,

Fe = Fl. dl / de

Fe is effort force (N, lb)

Fl is load force (N, lb) (note that weight is a force)

dl is distance from load force to fulcrum (m, ft)

de is distance from effort force to fulcrum (m, ft)

Here, the given data to find the effort force is,

Fl =50 Newtons

dl = 7 meters

de = 5 Newtons.

Substituting all the values, we get,

Fe = 350/5

Fe = 70 Newtons.

Thus, the effort force is 70 Newtons.

Hence, Option A is the correct answer.

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The correct option is A, After the switch is closed, the top plate of the capacitor eventually becomes positively charged.

A capacitor is a passive device that stores electrical energy in an electric field. It consists of two conducting plates separated by an insulating material such as air, paper, mica, ceramic, or plastic. When a voltage is applied across the two plates, the electric field created between them stores the energy in the form of an electrostatic potential.

When the voltage is removed, the charge stored in the capacitor is slowly discharged, releasing the energy. Capacitors are used in a wide range of applications, from power supplies and signal processing to motor control, filtering, and energy storage. They are also used to smooth out short-term fluctuations in voltage or current and are key components in many types of electronic circuits.

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