The length of DE in centimetres is 12 .
The following proportion can be established as follow:
AB / DE = BC / EF = AC / DF
Therefore,
let's find DE as follows;
AB / DE = BC / EF
4 / DE = 3 / 9
cross multiply
9 × 4 = 3DE
divide both sides by 3
DE = 36 / 3
DE = 12 cm
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What is the approximate area of sector BAC given that 0 ~ 4.71 radians?
A. 117.75m2 or B. 1962.5m2
Answer:
1962.5 m^2
Step-by-step explanation:
area of the entire circle = pi (50^2)
subtract the large area
pi 50^2 - 4.71 /2pi pi 50^2 =
Find AB and
BC of this isosceles
triangle.
Answer:
AB = 23, BC = 13
Step-by-step explanation:
[tex]5x - 7 = 23[/tex]
[tex]5x = 30[/tex]
[tex]x = 6[/tex]
AB = 23, BC = 3(6) - 5 = 18 - 5 = 13
on a blueprint, the bedroom wall is 6 in long. the scale factor is 1 to 24. what is the length of the actual wall?
A. 144 inches
B. 4 inches
C. 24 inches
D. 6 inches
Answer:
A
Hope This Helps! :)
Answer:
B. 4 inches
Step-by-step explanation:
(24)(1) / 6 = 4
Find the variation and an equation of variation where y varies inversely as x and y= 0.4 when x= 0.8
Hi!
The words "y varies inversely as x" automatically means we can write:
[tex]y=\cfrac{k}{x}[/tex]
Note that this is a fraction because it said "inversely". If it had said "jointly" or "directly", it would have been [tex]y=kx[/tex].
Now, we plug in the given values to solve for k.
We are given:
[tex]y = 0.4[/tex]
[tex]x = 0.8[/tex]
Plug those in and we have:
[tex]0.4=\cfrac{k}{0.8}[/tex]
Multiply both sides by [tex]0.8[/tex]:
[tex]0.32=k[/tex]
Now, with the value of [tex]k[/tex] solved for, we put it back into the original equation, and that's your answer:
[tex]y=\cfrac{0.32}{x}[/tex]
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Sarah is hiking on a trail near her home. She traveled 5 miles before stopping for a break. After the break, Sarah plans on increasing her speed to 3 miles per hour. Which equation models the total distance, D, Sarah travels after hiking for an additional h hours?
Answer:
D=3h+5
Step-by-step explanation:
Given: The rate of increasing speed = 3 miles per hour
The distance she traveled before stopping = 5 miles
Let h represents the number of additional hours for hiking.
Then the equation that models the total distance 'D' Sarah travels after hiking for an additional h hours is given by :-
D=3h+5
Answer:
D = 3h + 5
Step-by-step explanation:
cyrus lives 8 miles due south of adriana. adriana lives 21 miles due west of Jane. jane lives 14 miles due south of madisyn.
the shortest distance between cyrus' house and janes house is:
The shortest distance between Adriana’s house and Madisyn’s house is:
Answer:
Step-by-step explanation:
from Cyrus' to Jane's , the distance is D= [tex]\sqrt{8^{2} +21^{2} }[/tex] = 22.47 mi
from Adriana's to Madisyn's , the dist. is D =[tex]\sqrt{21^{2} +14^{2} }[/tex] = 25.24 mi
A castle entrance has walls that can be modeled by the equation StartFraction x squared Over 10 squared EndFraction minus StartFraction y squared Over 30 squared EndFraction = 1 with units in feet. How wide is the entrance where the walls are closest together?
10 ft
20 ft
30 ft
60 ft
Answer:
20
Step-by-step explanation:
What is the difference between the mean and the median of the following set of numbers {7, 28, 9, 11, 5}
Answer:
Mean - 12
Median - 9
Mean - Median = 3
Step-by-step explanation:
math
Mr. Emmer gave a test in his chemistry class. The scores were normally distributed with a mean of 82 and a standard deviation of 4. What percent of students would you expect to score between 82 and 90?
Answer:
95.45%
Step-by-step explanation:
Honestly I looked it up I hope it helps though and best of luck! : )
Answer:
47.5% I just took it
Can someone please help me with this
Answer:
(x = 0, y = 0) and (x = 3, y = 0)
Step-by-step explanation:
Let's test out each pair by substituting the values into the inequalities.
Case 1: x = 0, y = 0
0 <= 6
0 < 6
It works!
Case 2: x = -5, y = -15
-15 <= 10 + 6 = 16
-5 + 15 = 10 < 6
It doesn't work.
Case 3: x = 4, y = -2
-2 <= -8 + 6 = -2
4 + 2 = 6 < 6
It doesn't work.
Case 4: x = 3, y = 0
0 <= -6 + 6 = 0
3 < 6
It works!
Case 5: x = 10, y = 0
0 <= -20 + 6 = -14
From here we can already see that it doesn't work
Case 1 and 4 work!
Use the diagram above to answer the questions.
a. What are the coordinates of point N? (1 pt.)
b.
Use the Pythagorean Theorem to find the length of
segment PQ. (2 pts)
Answer:
a. (53, 12)
b. I couldn't find this without making a graph myself, hopefully someone will find it or you can figure it out for yourself using the answer I did provide.
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
Answer:
5.
Step-by-step explanation:
Have you heard of something called reading?
The two triangles below have proportional side lengths. Solve for x.
Answer:
90
Step-by-step explanation:
x/15=66/11
x/15=6
multiply by 15 on both sides to get the variable by itself
x=90
If an object is thrown upward from a 100-foot-high platform with an initial velocity of 64 feet
per second, then its height in feet is given by h(t) = -16t2 + 64t + 100 where t is time in
seconds. What is the maximum height reached by the object?
Answer:
164 ft
Step-by-step explanation:
The TIME of maximum height (this is a dome shaped parabola)
will be given by t = -b/2a = - 64 / (2)(-16) = 2 sec
Putting in t = 2 into the equation will give the max height
-16 (2^2) + 64(2) + 100 = max = 164 ft
If the complement of the angle a is B and the supplement of the angle B is 4a, then find the measure of the angle B
[tex] \alpha + \beta = 90[/tex]
[tex] \beta + 4 \alpha = 180[/tex]
Multiply the upper system by -1:[tex] - \alpha - \beta = - 90[/tex]
[tex] \beta + 4 \alpha = 180[/tex]
Add the systems:[tex]3 \alpha = 90[/tex]
[tex] \alpha = 30[/tex]
[tex] \beta = 90 - \alpha = 90 - 30 = 60[/tex]
[tex]( \alpha = 30) < = > ( \beta = 60)[/tex]
What is the best choice for r (the correlation coefficient)?
(A) r=0
B) r = -0.35
r = -0.6
(D) r = -0.90
Millions
Answer:
B) r = -0.35
Step-by-step explanation:
Correct me if I'm wrong
155.5-5.5∙20.7 help me with this
Answer:
41.65
Step-by-step explanation:
First do 5.5*20.7 because of PEMDAS or GERMDAS which is basically saying the order of how to solve expressions/equations
5.5*20.7=113.85
Then subtract 113.85 from 155.5
155.5-113.85=41.65
Help and you get brainliest
Answer:
1.a) 90 1.b) 32
Step-by-step explanation:
1.) 1^2 + 2^3 + 3^4
Squared means how much times to multiply the same number.
So, 1^2= 1x1=1
2^3=2x2x2=8
3^4=3x3x3x3=81.
So, 81+8+1=90
2. 4^2=4x4=16+2^4=2x2x2x2=16
16+16=32
Please mark me brainliest :)
solve the one in the middle asking for f'(10)
From the definition, we have
[tex]\displaystyle f'(10) = \lim_{x\to0} \frac{f(x) - f(10)}{x - 10}[/tex]
With [tex]f(x)=\sqrt{x-1}[/tex], we get [tex]f(10)=\sqrt{10-1}=\sqrt9=3[/tex]. So the limit we want to compute is
[tex]\displaystyle f'(10) = \lim_{x\to0} \frac{\sqrt{x-1} - 3}{x - 10}[/tex]
Rationalize the numerator by multiplying by its conjugate:
[tex]\displaystyle \frac{\sqrt{x-1} - 3}{x - 10} \times \frac{\sqrt{x-1}+3}{\sqrt{x-1}+3} = \frac{\left(\sqrt{x-1}\right)^2-3^2}{(x-10)\left(\sqrt{x-1}+3\right)} = \frac{x-10}{(x-10)\left(\sqrt{x-1}+3\right)}[/tex]
x is approaching 10, which is to say x ≠ 10, so we can cancel the factors of x - 10 and remove the discontinuity.
Then we're left with
[tex]\displaystyle f'(10) = \lim_{x\to0} \frac1{\sqrt{x-1}+3} = \frac1{\sqrt{10-1}+3} = \frac1{\sqrt9+3} = \frac1{3+3} = \boxed{\frac16}[/tex]
evaluated by direct substitution, which we can do since the limand is continuous.
asap, help me with 17 and 18.
Answer:
17. 125 ft^2
18. 9.4 in^2
Step-by-step explanation:
Both 17 and 18 are similar. You split that it into pieces.
Area of Rectangle/Square: Area = Length * Width
Area of a Triangle: Area = 1/2 * Base * Height.
17.
Area Rectangle:
Area = Length * Width
Area = 10 ft * 6 ft = 60 ft^2
Area Triangle:
Area = 1/2 * Base * Height
Area = 1/2 * 10 ft * 13 ft = 65 ft^2
Total Area = 60 ft^2 + 65 ft^2 = 125 ft^2
18.
Area Rectangle:
Area = Length * Width
Area = 2.7 in * 2 in = 5.4 in^2
Area Triangle:
Area = 1/2 * Base * Height
Area = 1/2 * 2 in * 4.4 ft = 4.4 ft^2
Total Area = 5.4 ft^2 + 4.4 ft^2 = 9.4 ft^2
In which number does the digit 6 have a value that is 10 times as great as the value of the digit 6 in 283,691?
360,281
486,732
573,674
678,832
HELP GUYS PLEASE!!!!!!!!
Answer:
B. 486,732
__________________________________________________________
SolveTo solve digit problems, multiply the value of the digit example: tens place, hundreds place by 10 to get to the next digit, and then you will have your answer.
[tex]600 * 10 = 6,000~-- > ~thousands~place[/tex]
Therefore, the answer would be B. because it has a 6 in the thousands place.
__________________________________________________________
Questions?Ask in comments.
486,732 is the number in which the digit 6 have a value that is 10 times as great as the value of the digit 6 in 283,691. Option B is correct.
To find the number in which the digit 6 has a value that is 10 times as great as the value of the digit 6 in 283,691, we need to compare the place values of the digit 6 in both numbers.
In the number 283,691:
The 6 is in the hundreds place.
Now let us multiply this place with 10.
100×10 = 1000.
Find the number in which the digit is in 1000 place.
In the number 486732, the 6 is in 1000 place.
Hence, Option B is correct. 486,732 is the number in which the digit 6 have a value that is 10 times as great as the value of the digit 6 in 283,691.
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Pls pls pls help me po:)
PRECAL:
Having trouble on this review, need some help.
1. As you can tell from the function definition and plot, there's a discontinuity at x = -2. But in the limit from either side of x = -2, f(x) is approaching the value at the empty circle:
[tex]\displaystyle \lim_{x\to-2}f(x) = \lim_{x\to-2}(x-2) = -2-2 = \boxed{-4}[/tex]
Basically, since x is approaching -2, we are talking about values of x such x ≠ 2. Then we can compute the limit by taking the expression from the definition of f(x) using that x ≠ 2.
2. f(x) is continuous at x = -1, so the limit can be computed directly again:
[tex]\displaystyle \lim_{x\to-1} f(x) = \lim_{x\to-1}(x-2) = -1-2=\boxed{-3}[/tex]
3. Using the same reasoning as in (1), the limit would be the value of f(x) at the empty circle in the graph. So
[tex]\displaystyle \lim_{x\to-2}f(x) = \boxed{-1}[/tex]
4. Your answer is correct; the limit doesn't exist because there is a jump discontinuity. f(x) approaches two different values depending on which direction x is approaching 2.
5. It's a bit difficult to see, but it looks like x is approaching 2 from above/from the right, in which case
[tex]\displaystyle \lim_{x\to2^+}f(x) = \boxed{0}[/tex]
When x approaches 2 from above, we assume x > 2. And according to the plot, we have f(x) = 0 whenever x > 2.
6. It should be rather clear from the plot that
[tex]\displaystyle \lim_{x\to0}f(x) = \lim_{x\to0}(\sin(x)+3) = \sin(0) + 3 = \boxed{3}[/tex]
because sin(x) + 3 is continuous at x = 0. On the other hand, the limit at infinity doesn't exist because sin(x) oscillates between -1 and 1 forever, never landing on a single finite value.
For 7-8, divide through each term by the largest power of x in the expression:
7. Divide through by x². Every remaining rational term will converge to 0.
[tex]\displaystyle \lim_{x\to\infty}\frac{x^2+x-12}{2x^2-5x-3} = \lim_{x\to\infty}\frac{1+\frac1x-\frac{12}{x^2}}{2-\frac5x-\frac3{x^2}}=\boxed{\frac12}[/tex]
8. Divide through by x² again:
[tex]\displaystyle \lim_{x\to-\infty}\frac{x+3}{x^2+x-12} = \lim_{x\to-\infty}\frac{\frac1x+\frac3{x^2}}{1+\frac1x-\frac{12}{x^2}} = \frac01 = \boxed{0}[/tex]
9. Factorize the numerator and denominator. Then bearing in mind that "x is approaching 6" means x ≠ 6, we can cancel a factor of x - 6:
[tex]\displaystyle \lim_{x\to6}\frac{2x^2-12x}{x^2-4x-12}=\lim_{x\to6}\frac{2x(x-6)}{(x+2)(x-6)} = \lim_{x\to6}\frac{2x}{x+2} = \frac{2\times6}{6+2}=\boxed{\frac32}[/tex]
10. Factorize the numerator and simplify:
[tex]\dfrac{-2x^2+2}{x+1} = -2 \times \dfrac{x^2-1}{x+1} = -2 \times \dfrac{(x+1)(x-1)}{x+1} = -2(x-1) = -2x+2[/tex]
where the last equality holds because x is approaching +∞, so we can assume x ≠ -1. Then the limit is
[tex]\displaystyle \lim_{x\to\infty} \frac{-2x^2+2}{x+1} = \lim_{x\to\infty} (-2x+2) = \boxed{-\infty}[/tex]
What is the answer to the question 7 1/3 - 3 2/3 =
Answer:
11/3
Step-by-step explanation:
convert the 7 1/3 to 22/3 then convert the 3 2/3 to 11/3 and subtract.
Please help me answer this
Answer:
The answer is B
Step-by-step explanation:
Btw if its wrong im sorry
Bella’s car payment is $321.00 a month for a five year period. What will she have paid for her car when she has paid her finals payment????
Thank you so much !!
Answer:
$19,260
Step-by-step explanation:
1 year = 12 months
5 × 12 = 60
5 years = 60 months
$321 × 60 = $19,260
Find the dimensions and solve for the volume.
What is the volume of this prism?
Length: ? Cm
Width: 5 cm
Height: 2 cm
Volume: ? Cm
3
Length is not given or any diagram hasn't been attached.
Length to be taken as x
L=xB=5H=2Now
Volume:-
V=LBHV=5(2)xV=10x cm³If $a = 4$, $b = 2$, and $c = -5$, then what is the value of $\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}$?
Answer is not 13 or 31.
[tex]\sqrt[3]{4 a^4 b^5} = \sqrt[3]{4 \times 4^4 \times 2^5} = \sqrt[3]{(4\times 2)^5} = \sqrt[3]{(2^2\times2)^5} = \sqrt[3]{(2^3)^5} = \sqrt[3]{2^{15}} = \sqrt[3]{(2^5)^3} = 2^5 = 32[/tex]
[tex]\dfrac{a-c}{(b+c)^2} = \dfrac{4-(-5)}{(2+(-5))^2} = \dfrac{4+5}{(2-5)^2} = \dfrac9{(-3)^2} = \dfrac99 = 1[/tex]
Then the expression evaluates to 32 + 1 = 33.
The value of the expression
[tex]$\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2}$[/tex]
is 33 when $a = 4$, $b = 2$, and $c = -5$.
How did we get the values?Let's substitute the given values into the expression and calculate the result:
Given:
$a = 4$
$b = 2$
$c = -5$
Substituting the values:
[tex]$\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2} = \sqrt[3]{4(4)^4(2)^5} + \dfrac{4 - (-5)}{(2+(-5))^2}$[/tex]
Calculating the values within the cube root:
[tex]$\sqrt[3]{4(4)^4(2)^5} = \sqrt[3]{4 \cdot 256 \cdot 32} = \sqrt[3]{32768} = 32$[/tex]
Calculating the values within the fraction:
[tex]$\dfrac{4 - (-5)}{(2+(-5))^2} = \dfrac{4 + 5}{(-3)^2} = \dfrac{9}{9} = 1$[/tex]
Now we can substitute the calculated values back into the expression:
[tex]$\sqrt[3]{4a^4b^5} + \dfrac{a - c}{(b+c)^2} = 32 + 1 = 33$[/tex]
Therefore, the value of
[tex]\sqrt[3]{4a^4b^5} + \frac{a - c}{(b+c)^2} \: is \: 33 \: when \: a = 4, \: b = 2, and \: c = -5[/tex]
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describe a set of transformations that would map triangle FGH onto F'G'H
Answer:
Describe a set of transformations that would map triangle FGH onto F'G'H
Step-by-step explanation:
For the given angle measure, find the measure of a supplementary angle and the measure of a complementary angle. 27
Answer:
A complementary angle is 63 degrees and supplementary angle is 153 degrees.
Step-by-step explanation:
Complementary angle:
A complementary angle adds up to 90 degrees, so you have to subtract 27 from 90. 90-27=63
Supplementary angle:
A supplementary angle adds up to 180 degrees, so you have to subtract 27 from 180. 180-27=153