Two objects are a distance of 1.7 x 103 meters apart. One object has a mass of 3 x 107 kg and the other has a mass of 6 x 108. Determine the gravitational force between the objects.

This question involves the concepts of the law of conservation of energy and specific heat capacity.

This collector can deliver "7.96 x 10⁻⁴ m³/min" of water at an output temperature of 60°C.

According to the law of conservation of energy:

Solar Energy = Energy Required to raise the temperature of the water

Solar Power = Energy Required to raise the temperature of the water

[tex]IA=\frac{mC\Delta T}{t}\\\\\frac{m}{t}=\frac{IA}{C\Delta}[/tex]

where,

[tex]\frac{m}{t}[/tex] = mass flow rate = ?

I = solar radiation = 660 W/m²

A = Area = 3.8 m²

ΔT = change in temperature = 60°C - 15°C = 45°C

C = specific heat capacity = 4200 J/kg.°C

Therefore,

[tex]\frac{m}{t}=\frac{(660\ W/m^2)(3.8\ m^2)}{(4200\ J/kg.^oC)(45^oC)}\\\\\frac{m}{t}=(0.0133\ kg/s)(\frac{60\ s}{1\ min})\\\\\frac{m}{t}=0.796\ kg/min[/tex]

Now, the volume flow rate will be:

[tex]\frac{V}{t}=\frac{(\frac{m}{t})}{(density\ of\ water)}=\frac{(0.796\ kg/min)}{(1000\ kg/m^3)}\\\\\frac{V}{t}=7.96\ x\ 10^{-4}\ m^3/min[/tex]

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The attached picture explains the law of conservation of energy.

W = 25 J

Explanation:

Work done on an object is defined as

[tex]W = Fd = (10\:\text{N})(2.5\:\text{m}) = 25\:\text{J}[/tex]

The magnitude of the load L on the crane before the collapse is 3211.81 N

To determine the magnitude of the load on the crane (L), we will need to make use of the equilibrium conditions of the torque.

It is always an ideal process to list out all the parameters given as this will let you understand how you can determine the answer to the question from the given parameters.

From the given information;

From the question;

the angle at which the crane is positioned can be determined by taking the tangent of the angle θ. i.e.

[tex]\mathbf{tan \ \theta = \dfrac{h}{d-s}}[/tex]

[tex]\mathbf{\theta = tan^{-1} \Big ( \dfrac{h}{d-s} \Big )}[/tex]

[tex]\mathbf{\theta = tan^{-1} \Big ( \dfrac{2.070 }{5.580 - 0.522} \Big )}[/tex]

[tex]\mathbf{\theta =22.26^0}[/tex]

Consider the equilibrium conditions of the torques with respect to the magnitude of the load at point P.

∴

[tex]\mathbf{Tsin \theta (d-s) - W_L (d-x) -(Mg) (\dfrac{d}{2}) = 0}[/tex]

By making the magnitude of the load [tex]\mathbf{W_L}[/tex] the subject of the formula, we have:

[tex]\mathbf{W_L = \dfrac{Tsin \theta (d-x) -(Mg) (\dfrac{d}{2})}{ (d-s) } }[/tex]

[tex]\mathbf{W_L = \dfrac{(11650 )sin (22.26) (5.580-1.350) -(88.50\times 9.81) (\dfrac{5.580}{2})}{ (5.580-0.522) } }[/tex]

[tex]\mathbf{W_L = 3211.81 \ N }[/tex]

Therefore, we can conclude that the magnitude of the load is 3211.81 N

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Hi there!

[tex]\large\boxed{E_{total} = 8.0 \text{ J}}[/tex]

For a mass undergoing SHM, the total energy of the system is given as:

[tex]ME = \frac{1}{2}kA^2[/tex]

Where:

k = Spring constant (N/m)

A = amplitude (m)

There is no quantity of mass in the equation, so the total mechanical energy of the system is NOT impacted by the object's mass.

Thus, the energy of the system will still be 8.0 J.

Answer:

23

Explanation:

3x-4

Answer: A , D & F

Explanation:

Answer:

Explanation:

conservation of momentum during the collision

0.035(214) + 0.15(0) = 0.185v

v = 40.486 m/s

The kinetic energy after impact will convert to gravity potential energy

(ignoring air resistance)

mgh = ½mv²

     h = v²/2g

     h = 40.486² / (2(9.8))

     h = 83.6303...

     h = 84 m

Answer:

Explanation:

In the vertical analysis assuming launch from ground level.

0 = 0 + (41.3sinθ)(5.1) + ½(-9.8)5.1²

(41.3sinθ)(5.1) = ½(9.8)5.1²

(41.3sinθ) = ½(9.8)5.1

sinθ = ½(9.8)5.1/41.3

sinθ = 0.60508...

θ = 37.235°

vx = 41.3cos37.235

vx = 32.881452...

vx = 32.9 m/s

Answer:

None of these elements.

Answer:

A) -31.2 rad/s

B) 28.1 rad/s^2

Explanation:

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

Answer:

Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.

Explanation:

Answer:

What is the average force of collision?

Explanation:

The velocity of the combined mass after impact is found by conservation of momentum

0.480(75) + 0.240(0) = (0.480 + 0.240)v

v = 50 m/s

An impulse results in a change of momentum

FΔt = mΔv

F = mΔv/Δt

for the pigeon

F = 0.240(50 - 0)/0.015

F = 800 N

for the falcon

F = 0.480(50 - 75)/0.015

F = -800 N

The final speed(v) of the Peregrine falcons and pigeon is 50 m/s

The objective of this question is to determine the final speed(v) of the Peregrine falcons and pigeon

From the information given:

According to the conservation of momentum, we can say that the totality of momentum before and after the collision is the same. As such;

[tex]\mathbf{m_fv_f = (m_f+m_p) v}[/tex]

[tex]\mathbf{480 g \times 75 m/s = (480 + 240) \ g \times v}[/tex]

[tex]\mathbf{v = \dfrac{480 g \times 75 m/s}{(480 + 240) \ g}}[/tex]

[tex]\mathbf{v = \dfrac{36000 \ m/s}{ 720}}[/tex]

v = 50 m/s

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Answer:

not sure i need points

Explanation:

Answer:

it would decrease

Explanation:

f=1/T

Answer:

we know that

s=vt

given

v=5.4 m/s

t=12 s

s=5.4 m/s*12 s=64.8m

Explanation:

Hope this helps:)

Answer:

D

Explanation:

Process of elimnination + it's the only one that makes sense

An object will begin moving from rest when acted upon by forces that are greater in one direction than in any other direction. Hence, Option (D) is correct.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

When  forces that are greater in one direction than in any other direction, resultant will be  unbalanced forces.  Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.

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#SPJ2

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between the 2 objects.

the distance is now quadrupled.

Fgravitynew = G*(mass1*mass2)/(4D)² =

= G*(mass1*mass2)/(16D²) =

= (G*(mass1*mass2)/D²) / 16 = Fgravity/16

the new gravitational force will be 179/16 = 11.1875 units

The impulse the floor exert on the box is 116 kgm/s.

The given parameters;

The final velocity of the box when it dropped to the floor is calculated as follows;

[tex]\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 1.1} \\\\v = 4.64 \ m/s[/tex]

The impulse the floor exert on the box is calculated as follows;

the impulse the floor exert on the box is equal to change in momentum of the book

[tex]J = \Delta P\\\\J = \Delta Mv\\\\J = M(v_f - v_0)\\\\J = 25(4.64 - 0)\\\\J = 116 \ kgm/s[/tex]

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Answer:

a battery, wires, and a switch.

Explanation:

All circuits include?

Use the meter stick to measure your height to the level of your eyes, then use trigonometry ratio formula to calculate the height from your eyes' level and above of the statue of liberty with angle of elevation, then, add the two heights.

If you are standing at a known distance from the statue of liberty, a meter stick can be used to measure your known distance away from the statue of liberty.

To determine its height using only a meter stick, the angle at which you look at the peak of statue of liberty must be measured or known. The height of the statue of liberty can be calculated if you know the angle of elevation at which you look at the peak of the statue, and the availability of the meter stick.

Use the meter stick to measure your height to the level of your eyes, then use trigonometry ratio formula to calculate the height from your eyes' level and above of the statue of liberty. That is,

Tan Ф = opposite / adjacent

Tan Ф = H/d

H = d x TanФ

Where

H = calculated height from the eyes level and above

Ф = angle of elevation

d = known distance away from the statue

Let h = Your measured height of your body to the eyes level

Then,

The height of the statue of liberty = H + h

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The moment of inertia of the wheel is 4.27 kg.m²

The kinematics equation explains the variables associated and related of motion.

From the information given, applying the kinematic equation of motion to determine the acceleration of the block, we have:

[tex]\mathbf{y = ut + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = (0)t + \dfrac{1}{2}at^2}[/tex]

[tex]\mathbf{y = \dfrac{1}{2}at^2}[/tex]

Making acceleration (a) the subject, we have:

[tex]\mathbf{a = \dfrac{2y}{t^2}}[/tex]

where;

[tex]\mathbf{a = \dfrac{2\times 1.5 }{2.0^2}}[/tex]

a = 0.75 m/s²

The angular acceleration of the wheel can be estimated by the formula:

[tex]\mathbf{\alpha = \dfrac{a}{r}}[/tex]

[tex]\mathbf{\alpha = \dfrac{0.75 \ m/s^2}{0.40 \ m}}[/tex]

[tex]\mathbf{\alpha = 1.875 \ rad/s^2}[/tex]

Finally, the torque acting on the wheel is:

[tex]\mathbf{\tau = I \alpha}[/tex]

[tex]\mathbf{Tr = I \alpha}[/tex]

where;

∴

[tex]\mathbf{I =\dfrac{T\times r}{\alpha} }[/tex]

[tex]\mathbf{I =\dfrac{20 \ N\times 0.40 \ m}{1.875 \ rad/s^2} }[/tex]

I = 4.27 kg.m²

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Answer:

do it got a picture

on the edge

Explanation:

The energy in the system is given by the initial potential energy at the point 1.

The linear velocity at point 3, is approximately 33.59 m/s.

Reasons:

The parameters are;

Height at point 1, h₁ = 83 m

Radius of the ring = 8 cm

Mass of the ring, M = 8 kg

Height at point 2, h₂ = 32 m

At point 2, we have;

Change in potential energy = Kinetic energy

Which gives;

(83 - 32) × 9.81 × 8 = 0.5 × 8 × v² + 0.5 × 8 × 0.08² × (v/0.08)²

Which gives;

v ≈ 22.37 m/s

At point 3, the rotational kinetic energy remains constant while the

translational kinetic energy increases as follows;

K.E. at point 3 = Initial kinetic energy + Change in potential energy

Which gives;

K.E. at point 3 = 0.5 × 8 × v₃³ ≈ 0.5×8×22.37² + 32×9.81×8

[tex]v_3^2 = \dfrac{0.5 \times 8 \times 22.37^2 + 32 \times 9.81 \times 8}{0.5 \times 8} = 1128.15[/tex]

v₃ ≈ √(1128.15) ≈ 33.59

The linear velocity at point 3, v₃ ≈ 33.59 m/s

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The probable question parameters as obtained from a similar question online are;

Height at point 1, h₁ = 83 m

Radius of the ring = 8 cm

Mass of the ring, M = 8 kg

Height at point 2, h₂ = 32 m

Answer:

F12 = G M1 M2 / R12^2

F12' = G M1 M2 / R12'^2

F12' / F12 = R12'^2 / R12^2 = (1/3)^2

F12' = 1/9 F12

The new force is 1/9 the of the old force

Answer:

What is kinetic friction?

Kinetic friction is defined as a force that acts between moving surfaces. A body moving on the surface experiences a force in the opposite direction of its movement.

What causes it?

When the mass is not moving, the object experiences static friction. The friction increases as the applied force increases until the block moves. After the block moves, it experiences kinetic friction, which is less than the maximum static friction.

What does it generate?

When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into thermal energy (that is, it converts work to heat). This property can have dramatic consequences, as illustrated by the use of friction created by rubbing pieces of wood together to start a fire.

Hi there!

We know that:

U (Gravitational Potential Energy) = mgh

Where:

g = acceleration due to gravity (m/s²)

m = mass (kg)

h = height/displacement (m)

Plug in the values:

U = 3 × 9.8 × 14 = 412 J

Answer:

.192 kg x m^2

Explanation:

I= mass of a times radius of a squared + mass of b times radius of b squared +...

I= .6 kg x .4m^2 + .6 kg x .4m^2

= .192 kg x m^2

Hope this helps :)