two objects have an electrical attractive force between them. how far apart would they have to be separated to make the attractive force one hundred times weaker?

A force of 1 pounds is required to hold a spring stretched 0.1 feet beyond its natural length. The work done in stretching the spring from its natural length to 0.9 feet beyond its natural length is 4.05 lb*ft.

To calculate the work done in stretching the spring, we can use Hooke's Law and the work formula for a spring. Hooke's Law states that the force (F) required to stretch a spring is proportional to its displacement (x) from its natural length, represented as F = kx, where k is the spring constant.

From the given information, 1 pound of force is required to stretch the spring 0.1 feet. Therefore, we can find the spring constant k:

1 lb = k * 0.1 ft
k = 10 lb/ft

Now we can use the work formula for a spring: W = (1/2)kx^2, where W is the work done and x is the displacement from the natural length. In this case, we are stretching the spring 0.9 feet:

W = (1/2)(10 lb/ft)(0.9 ft)^2

W = 4.05 lb*ft

So, the work done is 4.05 lb*ft.

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Oort cloud comets have orbits that gradually degrade over time, pushing them nearer to the sun every year. A is the right answer.

The word comet is derived from the Greek letter o (kometes), which indicates "long-haired." The typical observational test for distinguishing between a comet and an asteroid in a freshly discovered object is, in fact, the presence of the brilliant coma.

Comets are solar system-orbiting icy balls of rock, gas, and dust. They resemble a small town in size when frozen. A comet's path brings it in close proximity to the Sun, which causes it to heat up and eject gases and dust into a massive blazing head bigger than most planets.

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The focal length of the concave mirror can be determined by measuring the distance between the focal point and the surface of the mirror using the ruler tool available in the video.

The given video explains how to determine the focal length of a concave mirror using white lines and a ruler tool. The point where the white lines cross will be the focal point. Follow the below steps to determine the focal length of concave mirror:Step 1: Use the white lines to trace the beam at various times. Drag and rotate the white lines until they align along the reflected beam for at least two locations of the incident light. Don't use points near the edge of the mirror, as there is some distortion there.Step 2: Determine the focal point of the concave mirror using the white lines.Step 3: Measure the distance between the focal point and the surface of the mirror using the ruler tool.Step 4: The distance between the focal point and the surface of the mirror will be the focal length of the concave mirror. The focal length of concave mirror 1 is around 8.5 cm.

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The work done on the 1550 kg elevator car by its cable to lift it 38.5 m at constant speed, considering an average friction force of 145 N, is 591,494.25 J.

To calculate the work done on the elevator car, we need to consider both the force due to gravity and the friction force.

Step 1: Calculate the force due to gravity
Force due to gravity (F_gravity) = mass * acceleration due to gravity
F_gravity = 1550 kg * 9.81 m/s^2
F_gravity = 15,205.5 N

Step 2: Calculate the net force
Net force (F_net) = F_gravity + friction force
F_net = 15,205.5 N + 145 N
F_net = 15,350.5 N

Step 3: Calculate the work done
Work done (W) = F_net * distance
W = 15,350.5 N * 38.5 m
W = 591,494.25 J
The work done on the 1550 kg elevator car by its cable to lift it 38.5 m at constant speed, considering an average friction force of 145 N, is 591,494.25 J.

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The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

When an object is put in front of a plane mirror, this is the distance between the image that results and the focus.

To calculate the image distance, we use the formula below.

Formula:

1/f = 1/u+1/v Equation 1

Where:

f = Focal length of the mirror

v = Image distance

u = object distance

From the question,

Given:

f = 0.45 m

u = 0.25 m

Equation 1 can be changed to reflect these numbers to determine the image distance.

1/0.45 = 1/0.25 + 1/v

2.22 = 4+1/v

1/v = 2.22-4

1/v = -1.78

v = 1/(-1.78)

v = -0.56 m

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Answer:

 c d

Explanation:

The forces that acts on a moving car are majorly driving force, reactionary force, frictional force, gravitational force, and the air resistance.

A multiple set of forces acts on ant object, when it is in motion, lets see each of them clearly.

Driving force: This is the force generated by the car's engine that propels the car forward.

Friction force: This force acts opposite to the car's direction of motion and is caused by the interaction between the car's tires and the road surface.

Air resistance/drag force: This is the force that opposes the car's motion as it moves through the air.

Gravitational force: This force pulls the car down towards the Earth.

Centripetal force: This force acts on the car when it moves in a circular path, and is directed towards the center of the circle.

Normal force: This force is exerted on the car by the ground, perpendicular to the surface of the road.

Therefore, these mentioned forces interact in complex ways to determine the car's motion, and can be influenced by factors such as the car's speed, mass, and shape, as well as the road surface and external conditions like wind and temperature.

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The complete question is :

Draw the labelled sketch of a system of forces acting on a moving car and explain it.

In the previous problem, if your system's power use under load is 125 watts, and your electricity cost was 15 cents per kwh (kilowatt hour), the cost of power for running the system for a month under continuous load would be $16.38.

A watt is a unit of power in the International System of Units (SI). One watt is equal to one joule per second (J/s), or one ampere of electrical current with a potential difference of one volt (A⋅V).  Electricity is the set of physical phenomena related to the presence and motion of matter that has the property of electric charge. It is associated with charged particles, including electrons, protons, and ions, and the electromagnetic fields that interact with them. Penny is a monetary unit of the United States, worth one cent. It's the smallest denomination of currency in the US, with the exception of the half-cent that was previously used.

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When we compare the kinetic energy distributions for heavy vs. light particles at the same temperature, we observe that the kinetic energy distributions are the same.

The molecules of gas have kinetic energy, which is dependent on the velocity of the particles that make up the gas. The heavier particles move slower and have less kinetic energy, while the lighter particles move faster and have more kinetic energy.

This relationship is governed by the equation:

KE = 0.5 mv²

Where,KE: Kinetic energy, M: Mass, V: Velocity

Since temperature is a measure of the average kinetic energy of particles, we can say that two samples of gas at the same temperature will have the same average kinetic energy of their particles.

Although the particles in the sample are of different sizes, they will have the same average kinetic energy.

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The linear speed of the boulder's center of mass is 33.6 meters per second.

When a boulder of mass 20 kg and radius 4.8 meters is rolling down an incline without slipping and its angular speed is 7 radians per second, the linear speed of the boulder's center of mass can be calculated using the formula:

V = rω

where,

V is the linear speed of the boulder's center of mass,

r is the radius of the boulder, and

ω is the angular speed of the boulder.

The radius of the boulder, r = 4.8 meters, the angular speed of the boulder, ω = 7 radians per second.

Substitute the given values in the formula, V = rω= 4.8 x 7= 33.6 meters per second.

So, the linear speed is 33.6 meters per second.

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For the vertical and horizontal spring scenario, the energy remains constant for the system: block ceiling (spring), and earth The correct answer is (option c).
For the block on a table with a horizontal spring scenario and considering friction, the energy does not remain constant for any of the given systems. The correct answer is option f.

For the first scenario with the vertical spring, the energy of the system remains constant between the initial and final states since the system is conservative.

At the highest position, the block has gravitational potential energy, and at the equilibrium position, the block has only kinetic energy. The total mechanical energy of the system remains constant, neglecting any energy losses due to friction or air resistance. Therefore option c is correct

For the second scenario with the horizontal spring, the energy of the system does not remain constant between the initial and final states since there is friction between the block and the table.

The system is not conservative, and some energy is lost due to friction. Therefore, the energy of the system decreases between the initial and final states, and none of the options given accurately describes the system.  Therefore option f is correct.

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When the balloon rises high above earth to a point where the atmospheric pressure is 0.340 atm and its volume increases to 5.00 x 10³ m³, the temperature of the atmosphere at this higher altitude is approximately 255.1 K.

Using the combined gas law, we can determine the temperature at the higher altitude. The combined gas law is:

(P₁ × V₁) / T₁ = (P₂ × V₂) / T₂

Given:
P₁ = 1.000 atm (ground level pressure)
V₁ = 2.00 x 10³ m³ (ground level volume)
T₁ = 27°C + 273.15 (convert to Kelvin) = 300.15 K (ground level temperature)
P₂ = 0.340 atm (higher altitude pressure)
V₂ = 5.00 x 10³ m³ (higher altitude volume)

We want to find T₂, the higher altitude temperature:

(1.000 atm × 2.00 x 10³ m³) / 300.15 K = (0.340 atm × 5.00 x 10³ m³) / T₂

Solving for T₂:

T₂ = (0.340 atm × 5.00 x 10³ m³) × 300.15 K / (1.000 atm × 2.00 x 10³ m³)
T₂ ≈ 255.1 K

So, the temperature of the atmosphere at the higher altitude is approximately 255.1 K.

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It would take approximately 15129 helium-filled balloons to lift a person with a mass of 72 kg, assuming each balloon is spherical with a diameter of 36 cm.

First, let's calculate the volume of each helium-filled balloon:

radius (r) = 18 cm = 0.18 m (since the diameter is given as 36 cm)

volume of a sphere (V) = (4/3)πr^3

V = (4/3)π(0.18)^3

V ≈ 0.00387 m^3

Next, let's calculate the weight of the displaced air by each balloon:

density of air (ρ) = 1.2 kg/m^3 (at sea level and room temperature)

weight of displaced air (F) = ρVg

F = 1.2 * 0.00387 * 9.81

F ≈ 0.0467 N

Now, let's calculate the weight of the person:

weight of person (W) = mass * g

W = 72 * 9.81

W ≈ 706.3 N

Finally, we can calculate the number of balloons needed to lift the person:

number of balloons = (W / F) + 1

The extra balloon is added to account for the weight of the balloons themselves. Substituting the values, we get:

number of balloons = (706.3 / 0.0467) + 1

number of balloons ≈ 15129

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The telescope uses a reflecting design with a concave primary mirror and a secondary mirror.

The telescope you are noticing utilizes a reflecting telescope, which shines light utilizing a sunken essential mirror situated at the lower part of the telescope. The light emission enters the telescope through a little opening in the essential mirror, which mirrors the light to an optional mirror situated close to the highest point of the telescope.

The optional mirror then, at that point, mirrors the light to an eyepiece situated along the edge of the telescope, which permits the spectator to see the picture shaped by the essential mirror. This kind of telescope is known as a Newtonian reflector, named after Sir Isaac Newton who imagined this plan in the seventeenth 100 years.

Reflecting telescopes enjoy upper hands over refracting telescopes, for example, being liberated from chromatic abnormality, and the capacity to create bigger gaps without a similar degree of cost and intricacy.

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Resolvemos las ecuaciones simultáneamente para obtener v0. En este caso, podemos encontrar que la velocidad inicial (v0) que se comunicó a la pelota en el golpe es aproximadamente 16,35 m/s.

Para determinar la velocidad inicial (v0) de la pelota en el golpe de pelota vasca, podemos utilizar la ecuación de la trayectoria parabólica. En este caso, conocemos la altura inicial (0,8 m), la distancia horizontal (10 m) y la altura final en la pared (4,2 m) cuando la pelota golpea el frontis. También sabemos que el ángulo con respecto a la horizontal es de 60º.

Primero, descomponemos la velocidad inicial en sus componentes horizontal y vertical:
v0x = v0 * cos(60º)
v0y = v0 * sen(60º)

Luego, utilizamos la ecuación de la trayectoria parabólica para la altura en función del tiempo:
y(t) = 0,8 + v0y * t - (1/2) * g * t^2
4,2 = 0,8 + v0 * sen(60º) * t - (1/2) * 9,8 * t^2

Además, usamos la ecuación para la distancia horizontal:
x(t) = 10 = v0 * cos(60º) * t

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The falling of the rock will follow the principle of conservation of energy.

Before the rock falls, all the energy is stored as potential energy. The kinetic energy increases as the rock falls because its speed increases. The potential energy decreases as the rock falls because its position relative to the ground decreases.

Thus, the total energy remains constant.

When the rock falls, it gains kinetic energy due to its motion, and loses potential energy due to its decrease in height. However, the total energy of the system (rock, cliff, and Earth) remains constant because energy is conserved. This is known as the conservation of energy principle.

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The statement which is false about the terrestrial planets is : "despite being the closest planet to the sun, some parts of mercury have a surface temperature far below the freezing point of water."

Mercury is the closest planet to the Sun, which means that it receives a large amount of solar radiation. However, the planet's lack of atmosphere and slow rotation result in extreme temperature variations between its day and night sides. During its daytime, temperatures can reach up to 430 °C (800 °F), which is hot enough to melt lead.

However, as Mercury rotates away from the sun and enters its nighttime, its surface cools rapidly. Due to the lack of an atmosphere to hold in heat, the planet's nighttime temperatures can drop to as low as -173 °C (-280 °F). These extreme temperature variations make it difficult for any potential life to survive on Mercury.

Despite these extreme temperature variations, some parts of Mercury do not get cold enough to freeze water. Water freezes at 0 °C (32 °F), and the lowest temperature ever recorded on Mercury was around -183 °C (-297 °F). Therefore, while some parts of Mercury can get very cold, it never gets cold enough to freeze water is the correct option.

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In order to conserve momentum, Paula has a greater speed after the push-off since she is less massive than Ricardo.

Momentum is the product of the mass of a moving object and its velocity. It's a vector quantity since it has both magnitude and direction. In a closed system, the total momentum before and after a collision or explosion is always conserved. This implies that the total momentum before and after a collision or explosion is always the same. The momentum of each object might, however, differ before and after a collision or explosion. The greater the mass of an object, the greater its momentum. The greater the velocity of an object, the greater its momentum. So, to conserve momentum, Paula has a greater speed after the push-off since she is less massive than Ricardo.

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Rounded to the nearest whole number, the refracted angle is 16 degrees.

Using Snell's Law, we can calculate the refracted angle. Snell's Law states that n1 * sin(θ1) = n2 * sin(θ2), where n1 and n2 are the indices of refraction, and θ1 and θ2 are the incident and refracted angles, respectively.

Given:
n1 = 2.1
θ1 = 61 degrees
n2 = 7.5

We need to find θ2.

2.1 * sin(61) = 7.5 * sin(θ2)

To find θ2, we can rearrange the equation:

sin(θ2) = (2.1 * sin(61)) / 7.5

Now, find the inverse sine (arc sin) to get θ2:

θ2 = arc sin[(2.1 * sin(61)) / 7.5]

θ2 ≈ 15.58 degrees

Rounded to the nearest whole number, the refracted angle is 16 degrees.

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Oxygen gas is an example of matter because it has mass and occupies space. The correct option is A.

Matter can exist in various forms such as solids, liquids, gases, and plasma, and can be composed of atoms or molecules. The properties of matter, such as its density, temperature, and pressure, can be studied through the use of various physical and chemical processes.

Matter is composed of tiny particles called atoms, which consist of a nucleus containing positively charged protons and uncharged neutrons, surrounded by negatively charged electrons. The arrangement of these particles in matter determines its physical and chemical properties. These interactions play a critical role in many physical phenomena, including the behavior of materials under different conditions, the formation and evolution of stars and galaxies, and the behavior of subatomic particles.

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The Pan-STARRS telescopes can detect potential killer asteroids colliding with Earth up to a few weeks in advance.

The Panoramic Survey Telescope and Rapid Response System (Pan-STARRS) is a system of telescopes used for wide-field astronomical surveys, including asteroid detection. The system is capable of detecting near-Earth asteroids (NEAs) and potentially hazardous asteroids (PHAs) with diameters larger than 140 meters up to several decades in advance of their potential impact with Earth.

The exact time frame for detection depends on the size, trajectory, and reflectivity of the asteroid, as well as the observation frequency of the telescope system. However, the Pan-STARRS system provides an important tool for identifying potentially hazardous asteroids and informing future efforts for mitigation and prevention of catastrophic asteroid impacts.

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Answer:

S = 1/2 a t^2       where S is distance traveled

ω = 1/2 α t^2      corresponding angular acceleration

ω2 / ω1 = t2^2 / t1^2 = 3       ω2 = 3 * ω1          given

t2 = 3^1/2 t1^1/2 = 1.73 t1

N = f * t      where f is the frequency and N the number of revolutions

If f is 3 times as large then ω  is also 3 times as large

N2 / N1 = ω2 / ω1 = 3

Then N2 = 1.73 N1      or time for blade to cone to rest

It would take 1.73 revolutions if the angular speed was 3 ω1

The blade of the power mower will take 3 revolutions to come to a stop when the initial angular velocity is three times the original value (v₃ = 3 v₁) and the same constant acceleration is applied.

To solve the problem, we can use the formula for the angular velocity of an object undergoing constant angular acceleration:

ω = ω₀ + αt

where ω is the final angular velocity, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time interval.

We know that the blade is stopped within 1 revolution when the initial angular velocity is v₁. Therefore, we can write:

2π = (ω - v₁) / α

Solving for α, we get:

α = (ω - v₁) / (2π)

When the initial angular velocity is increased to three times the original value, the initial angular velocity becomes v₃ = 3 v₁. Using the same formula, we can write:

3(2π) = (ω - 3v₁) / α

Solving for α using the value we obtained earlier, we get:

α = (ω - v₁) / (2π) = (3ω - 3v₁) / (6π)

Simplifying the equation, we get:

ω = (5/3)v₁

Substituting this value in the formula we obtained earlier, we can find the time it takes for the blade to stop:

3(2π) = (ω - 3v₁) / α

Substituting ω = (5/3)v₁ and α = (3ω - 3v₁) / (6π), we get:

t = 9π / (5(3ω - 3v₁))

Substituting the value of ω, we get:

t = 3π / (5v₁)

Therefore, it will take 3 revolutions for the blade to stop.

The complete question is:

The blade of a power mower starts with an initial angular velocity of v₁ and is stopped within 1 revolution by a safety device. If the initial angular velocity is increased to three times the original value (v₃ = 3 v₁), and the same constant acceleration is applied, how many revolutions will it take for the blade to come to a stop?

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Answer:

Explanation:

Making parallax measurements from Pluto would offer several advantages over Earth:

Advantages:

Disadvantages:

The advantage of making parallax measurements from Pluto is that it provides a much larger baseline for the measurements, which would increase the accuracy of the measurements. However, the disadvantage is that Pluto's orbit is highly elliptical, which could make the measurements more difficult and less precise.

Parallax is a method used by astronomers to measure distances to nearby stars. It involves measuring the apparent shift in position of a star relative to distant background stars as the Earth orbits around the Sun. This shift is caused by the observer's change in position relative to the star. By measuring the angle of this shift, astronomers can calculate the distance to the star.

If parallax measurements were made from Pluto, the distance between the observer and the star would be much greater than if the measurements were made from Earth. This larger baseline would result in a greater angle of shift, which would increase the accuracy of the measurements.

However, Pluto's highly elliptical orbit could make the measurements more challenging because the distance between Pluto and the star would change over time. This would require careful timing of the measurements to ensure accuracy. Additionally, Pluto's distance from Earth could make it more difficult to transmit the data back to Earth.

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The maximum speed at which a car can round a curve of 25 m radius on a level road if the coefficient of friction between the tires and the road is 0.3 is approximately 8.58 m/s.

When a car is moving around a curve, there are two forces acting on it: the force of friction between the tires and the road, and the force of gravity pulling the car towards the center of the curve. In order for the car to safely stay on the road, the force of friction must be greater than or equal to the force of gravity.

We can use the formula for maximum speed in a circular motion, which is, v = √(μrg)

where, v = maximum speed, g = acceleration due to gravity = 9.81 m/s^2, r = radius of the curve, μ = coefficient of friction.

Substituting the given values, we get:

v = √(0.3 x 25 x 9.81)

v = √73.725

v ≈ 8.58 m/s

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The law of universal gravitation says that each physical object attracts every other entity with a force directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The greater the mass of an object, the greater the gravitational force it exerts on other objects, and the closer two objects are to each other, the stronger the gravitational force between them.

In the case of the solar system, the sun is the largest object and therefore exerts the greatest gravitational force on all the planets and other objects within its orbit. The planets, in turn, also exert gravitational forces on each other, which can affect their orbits and positions within the solar system.

Therefore, if the size of the sun were to be manipulated, it would affect the gravitational forces on the planets and their orbits. Similarly, if the positions of the planets were to be manipulated, it would also affect the gravitational forces and their positions within the solar system.

As for a hypothesis, it could be that if the size of the sun were to increase, the gravitational forces on the planets would also increase, which could cause changes in their orbits and potentially lead to collisions or other catastrophic events.

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No, heating the ground alone is not enough to prevent a tornado from forming.

A tornado is a violent and dangerous weather phenomenon characterized by a rapidly rotating column of air that extends from a thunderstorm cloud to the ground. Tornadoes typically form when there are strong wind shears present in the atmosphere, which causes the air to start rotating horizontally.

Heating the ground may contribute to instability, but it is just one of many factors that can contribute to the formation of a tornado.

Furthermore, even if the ground were heated, it would not necessarily have a significant impact on the other necessary atmospheric conditions. In fact, sometimes hot and humid conditions near the ground can contribute to the development of thunderstorms and potentially tornadoes.

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False. The linear velocity of the coin remains constant because the angular velocity of the disk is constant and the coin rotates without sliding.

The distance from the location of the coin to the center of the disk does not affect the linear velocity of the coin.

The linear velocity of the coin is equal to the product of the angular velocity of the disk and the distance from the center of the disk to the location of the coin.

However, since the angular velocity of the disk is constant, the linear velocity of the coin is also constant, regardless of its distance from the center.

This can be explained by the fact that all points on the rotating disk undergo the same angular displacement in the same amount of time, which results in a constant angular velocity.

As a result, the linear velocity of the coin does not increase in magnitude as its distance from the center of the disk increases.

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If the mass of the objects increases, then the gravitational force between them will also increase, as it is directly proportional to the mass of the objects involved.

The law of universal gravitation is a physical law that describes the attraction between two masses. It states that every particle in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The equation for this law is F = G(m1m2/d²), where F is the force of attraction, G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between them. As the masses of the objects increase, the gravitational force between them also increases, assuming that the distance between them remains constant.

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This potential energy will convert to Kinetic energy (KE) at maximum speed:
KE = 0.5 * m * v^2, where m is the mass of the block (0.1 kg) and v is the maximum speed.

(a) To find the maximum speed of the block, we can use the conservation of energy principle. When the block is pulled to a distance of 0.5 m, it has potential energy which will convert to kinetic energy when released.

Potential energy (PE) = 0.5 * k * x^2, where k is the spring constant (40 N/m) and x is the distance (0.5 m)
PE = 0.5 * 40 * (0.5)^2 = 5 J

This potential energy will convert to kinetic energy (KE) at maximum speed:
KE = 0.5 * m * v^2, where m is the mass of the block (0.1 kg) and v is the maximum speed.

Equating the potential energy and kinetic energy:
5 J = 0.5 * 0.1 * v^2
v^2 = 100
v = 10 m/s

(b) To find the frequency of the oscillations, we can use the formula:
f = (1 / 2π) * √(k / m), where f is the frequency, k is the spring constant, and m is the mass.
f = (1 / 2π) * √(40 / 0.1) = 1 Hz

(c) When the spring is flipped vertically and attached to the ground, the natural length of the spring will change due to the force of gravity acting on the block. However, since the question does not provide enough information to calculate the new length, we cannot provide a specific value.

(d) The frequency of oscillations of the vertical spring-block oscillator will be slightly lower compared to when it was placed horizontally. This is because, in the vertical position, the weight of the block acts against the spring force, which effectively increases the mass of the system, resulting in a lower frequency of oscillations.

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The initial temperature of the hot glass prism was 81.2°C.

A transparent object having two triangular ends and three rectangular sides is known as glass prism.

As we know, Q = mcΔT

Q is heat transferred, m is the of the water, c is specific heat capacity of water, ΔT is change in temperature of the water.

Assuming no heat is lost to the surroundings, heat lost by hot glass prism is equal to heat gained by the water:

Q_lost = Q_gained

Heat lost by the hot glass prism can be calculated as: Q_lost = mcΔT

m is mass of the glass prism and ΔT is difference between initial temperature of prism (T_i) and final temperature of the water (25°C).

Heat gained by the water can be calculated as: Q_gained = mcΔT

m is mass of the water and c is specific heat capacity of water.

mcΔT = mcΔT_g

T_i = (ΔT_g / ΔT) x 25°C

Heat transferred from the glass prism to water is: Q = mcΔT = 100 g x 0.664 J/(g °C) x (25°C - T_i)

ΔT_g = T_i - T_hot = - (25°C - T_i)

100 g x 0.664 J/(g °C) x (25°C - T_i) = 300 g x 4.184 J/(g °C) x (25°C - 22°C)

T_i = 81.2°C

Therefore,  initial temperature of the hot glass prism was 81.2°C.

To know more about glass prism, refer

https://brainly.com/question/3891897

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